To identify the unknown metal ion that produces an orange color in a flame test, you could perform several tests like; Flame Coloration Test, Confirmatory Tests, Spectroscopic Analysis, pH and Solubility Tests, and Comparison with Known Samples.
Perform flame tests with known metal ions that are known to produce an orange color in a flame e.g., sodium, calcium, lithium, etc. Observe the color of the flame produced by the unknown metal ion and compare it to the reference flame colors.
Once you have narrowed down the possibilities based on the flame color, you could perform additional confirmatory tests to further identify the unknown metal ion.
Also, we use spectroscopic techniques, such as atomic absorption spectroscopy (AAS) or emission spectroscopy, to analyze the unknown solution and determine the concentration and identity of the metal ions present.
You could perform pH and solubility tests on the unknown solution to determine its acidity or basicity and observe any characteristic changes in color or precipitation.
If you have access to known samples of metal ions with similar flame colors, you could compare the unknown solution with these known samples using various tests, such as chemical reactions, spectroscopic analysis, or physical properties, to determine similarities or differences that may help in identifying the unknown metal ion.
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what is the equation for finding energy of an electron. how is the quantum number (n.. increases as you go away from the nuclus), related to the energy
The equation for finding the energy of an electron is given by the following formula:
E = -13.6 eV * (Z^2 / n^2)
where E is the energy of the electron, Z is the atomic number of the element, and n is the principal quantum number, which increases as you go away from the nucleus.
As the principal quantum number (n) increases, the electron is located further away from the nucleus. This means that the electron is in a higher energy level, and the energy of the electron is less negative, which indicates that it requires less energy to remove the electron from the atom. In other words, as n increases, the energy of the electron becomes less negative and closer to zero.
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atrazine is a type of herbicide that has a half-life of 224 days in wetland soils. after 448 days, the persistence of atrazine will be
The atrazine is the type of the herbicide which has the half-life of the 224 days in the wetland soils. After the 448 days, the persistence of the atrazine will be 1/4 of the original amount.
The Atrazine is the chlorinated triazine systemic of the herbicide which is used to the selectively control of the annual grasses and the broadleaf weeds before it will emerge.
The Persistence with the symbol as P is the chemical property and this is refers to the chemical's degradation rate of the one or the more environmental compartment with the symbol as S.
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according to the bronsted-lowry definition, what acts as the acid when the reaction below proceeds in the forward direction?
Bronsted-Lowry acid is a compound that donates a proton.
In the Bronsted-Lowry theory, proton transport between chemical species is used to characterise acid-base interactions.
This theory is also known as the proton theory of acids and bases, which states that any compound that can transfer a proton to another compound is an acid, and the compound that accepts the proton is a base.
Because it makes up the nucleus of a hydrogen atom, a proton is a nuclear particle with a unit positive electrical charge; it is denoted by the symbol H+.
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do open systems like the oven allow energy to enter and leave?
Open systems allow energy and matter (stuff) to enter and leave the system. A pan on the stove is an open system because water can evaporate or be poured in, and heat can enter the pan if the stove is turned on, and leave the pan also.
-NO2 and halides are electron __________ (withdrawing/ donating) groups. When they are near the carboxyl group of a carboxylic acid, they __________ (increase/decrease acidity). -NH2 and -OCH3 are _______ groups and they _______ acidity.
-NO2 and halides are electron withdrawing groups. When they are near the carboxyl group of a carboxylic acid, they increase acidity. -NH2 and -OCH3 are electron-donating groups, and they decrease acidity.
Electron withdrawing groups have tendency to take the electrons away from the given compound or atom.They carry out +I or +M effect in organic chemistry. Examples of electron donating groups are toulene, halides , carbonyl , nitro groups, etc. Electron donating groups have tendency to donate electrons to the atom or compound. They carry out -I and -M effect in organic chemistry. Examples of electron withdrawing groups are carboxyl group, cyanide group, etc.
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CH3COOC5H11 Draw this structure it is an ester
The structure of Ester:
[tex]CH_3CH_2CH_2CH_2CH_2-C-O-CH_2CH_3[/tex]
I
[tex]CH_3[/tex]
An alcohol and a carboxylic acid react to form an ester, a type of chemical molecule. Esters are often used in a variety of common items including plastics, flavorings and fragrances. They often have a pleasant fruity or floral scent, which is what gives many fruits their distinctive aroma.
An alkyl group (R) is attached to one oxygen atom and a carbonyl group (C = O) is attached to another oxygen atom to form an ester structure. Alkyl or aryl groups can form alkyl groups.
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what are 2 types of adaptation
Answer:
Physiological adaptations are how the animal's body functions on the inside. This includes changes in the cells, chemicals, and processes inside an animal's body. Behavioral adaptations are how an animal acts. This includes actions like hibernating and communicating.
Explanation:
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Soluble ionic compounds, acids, and molecular bases all produce ions in solution. An ionic compound will _________ in aqueous solution, breaking apart into its component ions. Acids and molecular bases will _______ in water, producing ions even though they are molecular compounds.
Answer:Dissociate, Ionize
Explanation:
An ionic compound will dissociate in aqueous solution, breaking apart into its component ions. This process is called ionization, and it occurs because water molecules surround and interact with the ions, separating them from each other and allowing them to move freely in solution.
Acids and molecular bases will ionize in water, producing ions even though they are molecular compounds. When an acid dissolves in water, it donates a hydrogen ion (H+) to the water molecule, forming a hydronium ion (H3O+). Similarly, when a molecular base dissolves in water, it accepts a hydrogen ion from the water molecule, forming a hydroxide ion (OH-). These ions then move freely in solution and can participate in chemical reactions.
A sample contains Ba3(PO4)2, CdS, AgCl, NH4Cl, and ZnS. Identify the precipitate after the addition of 6 M HCl.
A) Ba3(PO4)2
B) CuS
C) AgCl
D) NH4Cl
E) NiS
After the addition of 6 M HCl to the sample containing [tex]Ba_{3}(PO_{4})_{2}[/tex], CdS, AgCl, [tex]NH_{4}Cl[/tex], and ZnS, the precipitate that forms is C) AgCl
AgCl precipitate is formed in the following manner-
1. When you add 6 M HCl, it will react with the compounds present in the sample.
2. HCl will not react with [tex]Ba_{3}(PO_{4})_{2}[/tex] as it is insoluble in acidic solutions.
3. HCl will dissolve CdS, [tex]NH_{4}Cl[/tex], and ZnS by forming their soluble chloride salts ([tex]CdCl_{2}[/tex], [tex]NH_{4}Cl[/tex], and [tex]ZnCl_{2}[/tex]).
4. HCl will react with AgCl, but it won't dissolve it. Instead, it will form a precipitate due to its low solubility in water.
So, the precipitate after the addition of 6 M HCl is AgCl (Option C).
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A liquid with a specific hear of 1.9 J/gC has 4750 J of energy added to it. The
temperature changed from 20 degrees C to 30 degrees C, what is the mass of the
liquid?
The mass of the liquid is 250 grams.
To find the mass of the liquid
We can use the following formula to determine the liquid's mass:
Q = mcΔT
Where
m is the liquid's mass Q is the heat energy absorbed by the liquidC stands for the liquid's specific heat capacityT stands for temperature changeWhen provided, Q = 4750 J, c = 1.9 J/g°C, and T = (10°C - 30°C)°C. To find m, we can rearrange the equations as follows:
m = Q / (c × ΔT)
We obtain the following by substituting the values:
m = 4750 J / (1.9 J/g°C 10°C)
m = 250 grams
Therefore, the mass of the liquid is 250 grams.
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Identify the strongest acid.
A) HIO4
B) HIO3
C) HIO2
D) HIO
E) Not enough information is given.
The strongest acid among the given options is A) HIO4 (per-iodic acid).
This is due to its highest oxidation state and greatest electronegativity, which allow it to donate a proton more readily, making it a stronger acid.
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A chemist adds 3.0 g sodium nitrate to 1.0 l water and stirs. the resulting solution is clear and colorless. he adds another 1.0 g sodium nitrate and stirs. the solution remains clear and colorless. what was true of the original solution he made?
The original solution made by the chemist was saturated.
The fact that the solution remained clear and colorless even after adding an additional 1.0 g of sodium nitrate indicates that the solution could still dissolve more sodium nitrate. This suggests that the solution was not yet saturated after the initial addition of 3.0 g sodium nitrate, and therefore the chemist added more sodium nitrate to reach saturation.
When the chemist first added 3.0 g of sodium nitrate to 1.0 L of water and the solution became clear and colorless, it indicated that the sodium nitrate completely dissolved in the water. When he added another 1.0 g of sodium nitrate and the solution still remained clear and colorless, it means that the solution was able to dissolve more solute. This characteristic is typical of an unsaturated solution, which is a solution that contains less solute than its saturation point at a given temperature and pressure.
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Calculate the pH of a 0.200 M NaCN solution. The Ka for HCN is 4.9 × 10^-10.
A) 3.87
B) 11.31
C) 2.69
D) 10.13
The pH of a 0.200 M NaCN solution is 11.31.
To calculate the pH of a 0.200 M NaCN solution, we must first find the concentration of CN- ions and the concentration of HCN. Since NaCN dissociates completely in water, the concentration of CN- ions is 0.200 M. The Ka for HCN is 4.9 × 10^-10.
Next, we need to set up an ICE (Initial, Change, Equilibrium) table to determine the change in concentration of HCN and CN- ions:
HCN + H2O ↔ H3O+ + CN-
I: 0 - - 0.200 M
C: +x - +x -x
E: x - x 0.200-x
Ka = [H3O+][CN-]/[HCN] = (x)(0.200-x)/x = 4.9 × 10^-10
Assuming that x is small compared to 0.200, we can simplify the equation to:
x(0.200) = 4.9 × 10^-10
x = 2.45 × 10^-9
Since x represents the concentration of H3O+ ions, we can now calculate the pH using the formula:
pH = -log10[H3O+]
pH = -log10(2.45 × 10^-9)
pH ≈ 11.31
The pH of the 0.200 M NaCN solution is approximately 11.31.
Therefore, the correct answer is B) 11.31.
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malathion is a common insecticide with a half-life in the environment of 1 day. if 100 grams of malathion are released into the environment, about how much will remain after 4 days?
After 4 days, about 6.25 grams of malathion will remain in the environment.
To determine how much malathion will remain after 4 days given its half-life of 1 day and an initial amount of 100 grams, you can follow these steps:
1. Understand that the half-life is the time it takes for the substance to decrease by half.
2. Since the half-life of malathion is 1 day, this means that after 1 day, half of the initial amount will remain.
3. After each subsequent day, the amount of malathion will continue to decrease by half.
Now, let's calculate how much malathion will remain after 4 days:
Day 1: 100 grams / 2 = 50 grams remaining
Day 2: 50 grams / 2 = 25 grams remaining
Day 3: 25 grams / 2 = 12.5 grams remaining
Day 4: 12.5 grams / 2 = 6.25 grams remaining
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What is the dependent variable of what is the effect of day length on plant growth
Answer:
Dependent variables are the variables that will be measured after they are changed by an independent variable. In this case, you will be measuring plant growth. This makes plant growth the dependent variable.
before determining the limiting reactant, you must convert all values from grams to _______. also, look over example on CHM review page 131
Before determining the limiting reactant, you must convert all values from grams to moles. This is because the balanced chemical equation gives the mole ratios of the reactants and products, not the gram ratios. Converting to moles allows for a more accurate comparison of the amounts of each reactant.
To determine the limiting reactant in a chemical reaction, you need to compare the amounts of reactants used and see which one runs out first. These amounts are usually given in grams, but in order to compare them, they must first be converted to moles. This is because the stoichiometry of the reaction, which describes the ratio of reactants and products, is based on molar ratios, not mass ratios.
To convert grams to moles, you need to use the molar mass of the substance, which is the mass of one mole of the substance. This can be found by adding up the atomic masses of all the atoms in the molecule. Once you have the molar mass, you can divide the given mass by the molar mass to get the number of moles.
After converting all the given masses to moles, you can then use the stoichiometry of the reaction to determine which reactant is limiting. The limiting reactant is the one that is completely used up first, and once it is used up, the reaction stops. The other reactant is in excess and will have some amount left over after the reaction is complete.
It is important to convert all values to moles before determining the limiting reactant in order to compare the amounts of reactants on an equal basis and to use the stoichiometry of the reaction correctly. The example on page 131 of the CHM review may provide additional context and practice on this concept.
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First to answer gets brainliest, please and thank you.
Answer:
It would take 21.8 mL of 1.75 M beryllium nitrate solution to produce 5.4 g of aluminum nitrate
Explanation:
Using the balanced chemical equation and the molar mass of aluminum nitrate provided, we can calculate the amount of aluminum nitrate produced from the given mass:
1 mole of aluminum nitrate (Al(NO3)3) has a mass of 213.01 g.
So, 5.4 g of Al(NO3)3 is equivalent to (5.4 g) / (213.01 g/mol) = 0.0254 mol.
From the balanced chemical equation, we can see that 3 moles of beryllium nitrate (Be(NO3)2) produce 2 moles of aluminum nitrate. So, the amount of beryllium nitrate needed to produce 0.0254 mol of aluminum nitrate is:
(0.0254 mol Al(NO3)3) x (3 mol Be(NO3)2 / 2 mol Al(NO3)3) = 0.0381 mol Be(NO3)2
Now we can use the concentration and the amount of beryllium nitrate to calculate the volume of the solution required:
0.0381 mol of Be(NO3)2 is present in (0.0381 mol) / (1.75 mol/L) = 0.0218 L = 21.8 mL of 1.75 M beryllium nitrate solution.
Therefore, it would take 21.8 mL of 1.75 M beryllium nitrate solution to produce 5.4 g of aluminum nitrate, assuming the reaction proceeds to completion.
additions to the carbonyl groups of aldehydes or ketones generally consist of a. protonation of the carbonyl carbon. b. nucleophilic attack on the carbonyl group. c. protonation of the nucleophile. d. electrophilic attack on the carbonyl group.
When it comes to additions to the carbonyl groups of aldehydes or ketones, the most common mechanisms involve either protonation of the carbonyl carbon or nucleophilic attack on the carbonyl group. Protonation of the carbonyl carbon occurs when a proton is added to the carbon atom of the carbonyl group, making it more electrophilic and allowing for easier nucleophilic attack. This mechanism is often seen in acid-catalyzed reactions.
On the other hand, nucleophilic attack on the carbonyl group involves a nucleophile (an electron-rich species) attacking the carbonyl carbon, leading to the formation of a new bond and the creation of an intermediate species. This mechanism is often seen in base-catalyzed reactions.
It is important to note that both aldehydes and ketones can undergo these mechanisms, although the reactivity may differ slightly between the two. Additionally, protonation of the nucleophile and electrophilic attack on the carbonyl group are less common mechanisms in these types of reactions.
Overall, understanding these mechanisms and their differences is crucial in predicting and understanding the outcomes of various reactions involving aldehydes and ketones.
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Which type(s) of molecular interactions determine a molecule's melting range?- Hydrogen bonding- Dipole-dipole- Van der Waals- All of the above
All of the above types of molecular interactions can determine a molecule's melting range.
Hydrogen bonding is one of the strongest intermolecular forces, and is based on the electrostatic attraction between the partial positive charge of a hydrogen atom and the partial negative charge of an oxygen or nitrogen atom.
Dipole-dipole interactions are also electrostatic in nature, and are the attractive force between two molecules with opposite charges. Van der Waals interactions are weaker than hydrogen bonding and dipole-dipole interactions, but they are still important in determining the melting range of a molecule.
These interactions are based on the attraction between slightly positive and slightly negative regions of two different molecules. All of these interactions work together to determine the melting point of a molecule, as the stronger the intermolecular forces are, the higher the melting point will be.
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A hard water sample contains 8.5×10−3 % Ca by mass (in the form of Ca2+ ions).
How much water (in grams) contains 1.2 g of Ca? (1.2 g of Ca is the recommended daily allowance of calcium for those between 19 and 24 years old.)
m of H2O=______g
3.527 g of water contains 1.2 g of calcium, which is the recommended daily allowance of calcium for those between 19 and 24 years old.
In order to answer this question, we must first calculate the mass of calcium in 8.5 × 10³ % of a given mass of water. Since calcium is present in the form of Ca⁺² ions, 8.5 × 10⁻³ % of a given mass of water is equal to 8.5 × 10⁻³ grams of Ca⁺² ions.
We can then multiply this mass of Ca⁺²+ by the molar mass of calcium (40.08 g/mol) to calculate the mass of calcium in 8.5 × 10⁻³ % of a given mass of water. This mass is equal to 0.34064 g.
Now, in order to calculate the mass of water that contains 1.2 g of Ca, we must divide 1.2 g of Ca by 0.34064 g of Ca in 8.5 × 10⁻³ % of a given mass of water. This calculation yields a mass of water of 3.527 g.
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This is due tomorrow and my teacher thinks I did it but really I have no idea and I’m too lazy to try and look up answers
Name - Function
A. Brainstem Control center, regulates vital functions such as breathing, heart rate, and blood pressure.B. Cerebrum Higher processes such as thought, memory, and emotion.C. Cerebellum Physical coordination and balance.What does the brain control?The brain regulates a variety of bodily processes, such as movement, sensation, thinking, emotion, and behavior.
Activity and Part of the brain it involves are:
a. Testing a hamburger - Sensory cortex in the parietal lobe
b. Artistic ability - Right hemisphere of the cerebrum
c. Kicking a soccer ball - Motor cortex in the frontal lobe
d. Rate of breathing - Medulla oblongata in the brainstem
e. Tying your shoes - Cerebellum
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Which compound do you expect to be miscible with octane (C8H18)?Which compound do you expect to be miscible with octane ?NH3CH3OHH2OCBr4
Out of the given compounds, the compound that is most likely to be miscible with octane is CH₃OH (methanol) due to its similar polarity.
Methanol has a polar hydroxyl group (-OH) that can participate in hydrogen bonding, but it also has a nonpolar methyl group that makes it partially nonpolar. This partial nonpolarity allows methanol to dissolve in nonpolar solvents like octane.
NH₃ (ammonia) is a polar compound due to its ability to form hydrogen bonds with water molecules. It is unlikely to be miscible with octane because the two compounds have very different polarities.
H₂O (water) is a highly polar compound due to its ability to form hydrogen bonds. It is unlikely to be miscible with octane because of their differences in polarity.
CBr₄ (carbon tetrabromide) is a nonpolar compound, but it is not likely to be miscible with octane due to the large size of its molecules and high molecular weight.
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Which of the following is a condition of the ideal gas law? The gas molecules...
Group of answer choices
must move in a random fashion
must interact with each other
must be moving at a slow speed
must adhere to the container wall
The condition of the ideal gas law is that the gas molecules must move in a random fashion.
The condition of the ideal gas law is that the gas molecules must move in a random fashion. This means that the molecules move in a chaotic manner with no set pattern or direction, constantly colliding with each other and the walls of their container.
This assumption is based on the kinetic theory of gases, which assumes that gases are made up of small particles (molecules or atoms) that are in constant motion.
The ideal gas law is a mathematical relationship between the pressure, volume, temperature, and number of particles of a gas. It is based on several assumptions, including that the gas molecules are in constant motion, that they occupy no volume, and that they do not interact with each other except through elastic collisions.
Therefore, if the gas molecules do not move in a random fashion, this assumption would not hold, and the ideal gas law would not accurately describe the behavior of the gas.
The other options, such as the gas molecules interacting with each other or adhering to the container wall, are not conditions of the ideal gas law, but rather factors that can affect the behavior of real gases under certain conditions.
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design a synthesis of 4,4-dimethyl-2-cyclohexenone from any acyclic compounds.
Synthesize 4,4-dimethyl-2-cyclohexenone from propanal via Grignard reaction and Barton-Kellogg cyclization.
How to synthesize 4,4-dimethyl-2-cyclohexenone?To synthesize 4,4-dimethyl-2-cyclohexenone from acyclic compounds, we can use the following synthetic route:
The first step involves the synthesis of 4,4-dimethyl-2-pentanone from the reaction of propanal with isobutylmagnesium bromide. The Grignard reagent will add to the carbonyl group of propanal to give a secondary alcohol. This is then oxidized to the ketone using a mild oxidizing agent like PCC (pyridinium chlorochromate).The second step involves the synthesis of 4,4-dimethyl-2-cyclohexenone from 4,4-dimethyl-2-pentanone via a modified Barton-Kellogg reaction. First, 4,4-dimethyl-2-pentanone is treated with sodium hydroxide to generate the enolate ion, which is then reacted with iodine to give the iodinated enolate. This iodinated enolate is then treated with 1,4-diazabicyclo[2.2.2]octane (DABCO) in the presence of a copper catalyst to cyclize and form the cyclohexenone product.Overall synthesis:
Propanal --> (Grignard reaction) --> 4,4-dimethyl-2-pentanol --> (oxidation with PCC) --> 4,4-dimethyl-2-pentanone --> (enolate formation, iodination, cyclization) --> 4,4-dimethyl-2-cyclohexenone.
Synthesis of 4,4-dimethyl-2-pentanone:
Propanal is reacted with isobutylmagnesium bromide to form 2-methyl-2-(2-methylpropyl)propan-1-ol. This secondary alcohol is then oxidized to the corresponding ketone using PCC.
Synthesis of 4,4-dimethyl-2-cyclohexenone:4,4-dimethyl-2-pentanone is treated with sodium hydroxide to generate the corresponding enolate ion. The enolate is then reacted with iodine to give the iodinated enolate. This iodinated enolate is then treated with DABCO in the presence of a copper catalyst to form the cyclohexenone product via cyclization.
Overall, this synthetic route involves two key reactions: the Grignard reaction and the modified Barton-Kellogg reaction. These reactions are widely used in organic synthesis and can be adapted to other synthetic routes as well.Learn more about synthesize
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Does the stripe on a diode indicate the anode or cathode?
Yes, the stripe on a diode indicates the cathode. The cathode is the negative terminal of the diode, and the anode is the positive terminal. T
The stripe on the diode is typically located near the cathode end, and it is used to indicate the polarity of the diode.
The stripe on a diode indicates the cathode, not the anode. When looking at a diode, the stripe is present on the cathode side, which is the negative terminal. The anode, on the other hand, is the positive terminal without the stripe. In a circuit, the diode allows current to flow in one direction, from the anode to the cathode, when it's forward-biased, and blocks the current when it's reverse-biased.
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Answer the following 2 questions on assaying:
Describe what equipment you would find in an assay office and what the equipment was used for.
List 3 interesting things you learned about furnaces.
what is the sum of the coefficients when the following equation is balanced using the lowest, whole numbered coefficients?
The sum of coefficients, when an equation is balanced using the lowest, whole numbered coefficients, is called the balanced equation.
When balancing a chemical equation, the coefficients in front of the reactants and products are adjusted to ensure that the same number of each type of atom appears on both sides of the equation. The coefficients must be whole numbers, and the lowest possible set of coefficients should be used. The sum of these coefficients gives us the balanced equation, which represents the chemical reaction that is taking place. The sum of the coefficients is important because it tells us how many molecules of each substance are involved in the reaction.
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First to answer gets brainliest, please and thank you. If you can say why you chose each step, it would be appreciated.
The concept molarity is used here to determine the milliliters of NaOH required. The term molarity is an important method which is used to calculate the concentration of a solution. Here the volume is 0.95 mL.
Molarity is defined as the number of moles of the solute dissolved per liter of the solution. It is usually expressed in mol / L and it is represented as 'M'.
The equation used to calculate molarity is:
M = Number of moles of the solute / Volume of solution in liters
Number of moles = Given mass / Molar mass = 44.00 / 22.99 = 1.91
Volume = n / M = 1.91 / 2.00 = 0.95 mL
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the element which makes up the framework of organic compounds and which cycles through all ecosystems is
The element which makes up the framework of organic compounds and cycles through all ecosystems is carbon.
Carbon is an essential element that forms the backbone of organic compounds, including proteins, carbohydrates, lipids, and nucleic acids. It is present in all living organisms and cycles through the environment via the carbon cycle. Carbon dioxide is absorbed by plants during photosynthesis and is incorporated into organic molecules that are passed on to other organisms through the food chain.
When organisms respire or decompose, carbon is released back into the atmosphere or soil, where it can be taken up by plants once again. This continuous cycle of carbon is vital for the sustainability of all ecosystems.
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85.2 grams of slovent are mixed with 320. gram solute. what is the mass percent?
The mass percent of the solute in the solution is 78.92%.
The mass of the solution is the sum of the mass of the solute and the mass of the solvent.
In this case, the mass of the solvent is given as 85.2 grams, and the mass of the solute is 320 grams. Therefore, the mass of the solution is:
Mass of solution = Mass of solvent + Mass of solute
Mass of solution = 85.2 grams + 320 grams
Mass of solution = 405.2 grams
Now, we can calculate the mass percent of the solute in the solution:
Mass percent = (Mass of solute / Mass of solution) x 100%
Mass percent = (320 grams / 405.2 grams) x 100% = 78.92%
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