2)Point C is reflected across a b such that in maps and to point D. Point C and D are then connected to form CD. Which of the following must be true? A)CD bisects ABB)AB=CD C)CD is parallel to ABD) CD is perpendicular to AB
Answers
Point C is reflected across a line AB such that it maps to point D.
Points C and D are then connected to form a line CD.
Let us draw a figure to better understand the problem
As you can see from the above figure,
We have reflected the point C across the line AB and the reflected point is mapped to point D.
Then we connected the point C to point D using the red color to form line CD.
The line CD is perpendicular to line AB.
All other options depend on the exact scenario which means they may or may not be true.
But we can be sure about option D that it must always be true.
Therefore, option D is the correct answer.
Related Questions
A car rental agency charges $175 per week plus $0.20 per mile to rent a car. How many miles can you travel in one week for $295?
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Answer:
600 miles
Step-by-step explanation:
295$ - 175$ = 120$. 120$ divided by 20 cents equals 600.
felicia borrowed $12,000 from her bank at a monthly interest rate of 5%. if she paid back the loan after 3 months, how much interest is she going to pay? how much money will she pay back to her bank?
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felicia borrowed $12,000 from her bank at a monthly interest rate of 5%. if she paid back the loan after 3 months, how much interest is she going to pay? how much money will she pay back to her bank?
we have that
the interest for each month is
0.05*12,000=$600
after 3 months
total interest is 3*$600=$1,800
she going to pay $1,800
Part b
12,000-1,800=$10,200
Find all the angles in the interval 0 to 360 degrees that satisfy the following condition. Round theanswer to the nearest hundredth of a degree.sin(x) = 5/14
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Given the expression:
[tex]\sin (x)=\frac{5}{14}[/tex]to find the angle, we use the invers sine function to get x:
[tex]\begin{gathered} \sin (x)=\frac{5}{14} \\ \Rightarrow x=\sin ^{-1}(\frac{5}{14})=20.92 \\ x=20.92 \end{gathered}[/tex]therefore, the angle x = 20.92°
What is the length of the missing leg? If anyone to help it would be much appreciated
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In the given right triangle
Applying the Pythagorean Theorem
[tex]73^2=b^2+55^2[/tex]Solve for b
[tex]\begin{gathered} b^2=73^2-55^2 \\ b^2=2,304 \\ b=48\text{ in} \end{gathered}[/tex]Gregory had $7.32 he put $3.50 in the bank how much did he have left to spend
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Answers
$3.82
Explanation
If Gregory had $7.32 he put $3.50 in the bank, the the amount left to spend is ($7.32 - $3.50) = $3.82
Question in picture answer please
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The expression in the image is:
a*(a + b + b) = a² + 2ab
So the correct option is the bottom left one.
Which expression is on the diagram?
The diagram is a rectangle that can be divided into smaller rectangles. We know that the area of the large rectangle will be equal to the sum of the areas of the smaller rectangles, then we can write:
area of the larger rectangle = a*(a + b + b)
While the addition of the areas of the smaller figures gives:
sum of areas: a² + a*b + a*b = a² + 2ab
Then the expression in the image is:
a*(a + b + b) = a² + 2ab
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Rotate point A(3,5) 270° counterclockwise around the origin
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the given point is A(3,5)
when we rotate a point (x,y) around origin counterclockwise then its coordinates becomes (y,-x)
so point A(3,5) will be changed into A'(5,-3).
so new coordinate of the point will be A'(5,-3)
4. What is the value of c in the quadratic equation 2m² + m +3 = 0?A.OB. 1C. 2D. 3
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GIven a quadratic equation in standard form, we have
[tex]\begin{gathered} ax^2+bx+c=0 \\ \text{where} \\ a,b,\text{ and }c\text{ are the coefficients of the terms} \end{gathered}[/tex]c represents the coefficient of the constant in the quadratic equation.
Given the equation 2m² + m +3 = 0
what amount of time in months is necessary for a principal of $6,000 to produce $550 and interest at 10%?
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the compound interest formula is given by
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]where A is the amount you will have, P is the principal, r is the annual interest rate, n is the amount of times the interest is compounded per time period, and t is the amount of time.
In our case, we need to find the time t. Then, by moving the Principal to the left hand side, we get
[tex]\frac{A}{P}=(1+\frac{r}{n})^{nt}[/tex]By applying natural logarithm on both sides, we get
[tex]\ln (\frac{A}{P})=nt\cdot ln(1+\frac{r}{n})[/tex]now, we can isolate t as
[tex]t=\frac{\ln (\frac{A}{P})}{n\ln (1+\frac{r}{n})}[/tex]Now, we can substitute our given values into this expression. It yields,
[tex]t=\frac{\ln (\frac{6550}{6000})}{12\ln (1+\frac{0.1}{12})}[/tex]which gives
[tex]t=\frac{0.0877}{12(0.0083)}[/tex]then, the time (in years) is
[tex]t=0.88\text{ years}[/tex]Now, we must convert this result in months. Since 1 year has 12 months, we have
[tex]\begin{gathered} t=0.88\times12 \\ t=10.56\text{ months} \end{gathered}[/tex]that is, the answer is 10.56 months
Five thousand tickets are sold at $1 each for a charity raffle. Tickets will be drawn at random and monetary prizes awarded as follows: 1 prize of$500; 3 prizes of $100, 5 prizes of$20, and 20 prizes of $5. What is the expected value of this raffle if you buy 1 ticket?
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As per the unitary method, the expected value of this raffle if you buy 1 ticket is $ 0.25.
Unitary method:
Basically, the word unitary refers to a single or an individual unit.
Therefore, this method aims at determining values in relation to a single unit.
Given,
Here we have that five thousand tickets are sold at $ 1 each for a charity raffle, and tickets are to be drawn at random and monetary prizes awarded as follows:
1 prize of $ 500,
3 prizes of $ 200,
5 prizes of $ 10, and
20 prizes of $ 5,
And here we need to determine what is the expected value of this raffle if you buy 1 ticket.
As per the given details, let us consider X be the expected value then we have written it as the equation like the following,
(500 + 3 x 200 + 5 x 10 + 20 x 5) / 5000 = X
When we simplify it then we get,
(500 + 600 + 50 + 100) / 5000 = X
After the addition operation we get the value,
1250/5000 = X
Then the value of X can be written as,
0.25 = X
Therefore, the expected value of this raffle per ticket is $ 0.25.
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8X squared +4x-112=0
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8x² + 4x - 112 = 0
To solve this equation, we can use the quadratic formula, as follows:
[tex]\begin{gathered} x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_{1,2}=\frac{-4\pm\sqrt[]{4^2-4\cdot8\cdot(-112)}}{2\cdot8} \\ x_{1,2}=\frac{-4\pm\sqrt[]{16+3584^{}}}{16} \\ x_{1,2}=\frac{-4\pm\sqrt[]{3600^{}}}{16} \\ x_1=\frac{-4+60}{16}=3.5 \\ x_2=\frac{-4-60}{16}=-4 \end{gathered}[/tex]A rectangular board is 1200 millimeters long and 800 millimeters wide. What is the area of the board in square meters? Do not round your answer. Be sure to include the correct unit in your answer.
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Given:
shape: rectangle
length: 1200 mm
width: 800 mm
Find: area in square meters
Solution:
First, let's convert the given dimensions to meters.
Conversion rule is 1 m = 1000mm. Let's convert the length first.
[tex]1200\operatorname{mm}\times\frac{1m}{1000\operatorname{mm}}=1.2m[/tex]Length = 1.2 meters
Now, let's convert the width.
[tex]800\operatorname{mm}\times\frac{1m}{1000\operatorname{mm}}=0.8m[/tex]Width = 0.8 meters
Now that we are done converting the dimensions of the board to meters, let's solve for the area. The formula is:
[tex]Area=length\times width\text{ }[/tex]Let's plug in the converted dimensions to the formula.
[tex]Area=1.2m\times0.8m=0.96m^2\text{ }[/tex]Therefore, the area of the board is 0.96 square meters.
Options for the first box: 9.51, 9.75, 9.67, 9.59Options for the second box: 9.91, 9.99, 9.75, 9.83
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We know that
• The mean is 9.75 meters per second.
,• The standard deviation is 0.08 meters per second.
According to the empirical rule, 95% of the data falls into 2 standard deviations below and above the mean, so we just have to subtract and add the standard deviation twice.
[tex]\begin{gathered} \bar{x}+2\sigma \\ \bar{x}-2\sigma \end{gathered}[/tex]Using the given information, we have
[tex]\begin{gathered} 9.75+2(0.08)=9.75+0.16=9.91 \\ 9.75-2(0.08)=9.75-0.16=9.59 \end{gathered}[/tex]Therefore, her next measurement will fall between the values of 9.59 and 9.91 meters per second.[tex]9.59Write a function $g$ whose graph represents the indicated transformation of the graph of f the equation f(x)=x+2 translated 2 units to the right is g(x)=
Answers
The function g(x) whose graph represents the indicated transformation of the graph of the equation f(x) = x+2 translated 2 units to the right is g(x) = x
Here the function is
f(x) = x+2
It is translated 2 units to the right
A translation defined as the movement of the graph either horizontally or vertically. In translation the shape or the size of the graph will not change only the location of the graph changes
Then the equation will be
f(x-2) = (x-2)+2
= x-2+2
= x
Hence, the function g(x) whose graph represents the indicated transformation of the graph of the equation f(x) = x+2 translated 2 units to the right is g(x) = x
The complete question is
Write a function g(x) whose graph represents the indicated transformation of the graph of f the equation f(x)=x+2 translated 2 units to the right.
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A group of 45 people attened a ball game.There were twice as many children as adults in the group, Set up a system of equations that represents the numbers of adults and children who attened the game and solve the system to find the number of children who were in the groupe as many children as adults in the group. set up a system of equations that represents the number of adults and children who attened the game and solve the system to find the number of children who were in the group
Answers
A system of equations representing the number of adults and children attending the game is x + 2x = 45, and the number of children who were in the group is 30.
What is an equation?An equation is a mathematical statement showing that two mathematical expressions are equal or equivalent.
Equations are represented using the equation sign (=).
The total number of people who attended the game = 45
Let the number of children, who were twice as many as adults, C = 2x
Let the number of adults, who attended the game, A = x
Therefore, the total number of attendees, T = x + 2x = 45
x + 2x = 45
3x = 45
x = 15
C = 2x
= 2(15)
= 30
Check:
x + 2x = 45
Substitute x with 15
15 + 2(15) = 45
15 + 30 = 45
45 = 45
Thus, from the system of equations, we can conclude that 30 children attended the game, which is twice the number of adults.
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y = 5
2x − 4y = –10
( _ , _ )
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PLUG 5 IN THE PLACE OF Y AND SOLVE FOR X
[tex]2x - 4(5) = - 10 \\ 2x - 20 = - 10 \\ 2x = - 10 + 20 \\ 2x = 10 \\ \frac{2x}{2} = \frac{10}{2} \\ x = 5[/tex]
SINCE WE FOUND THAT x=5
we have the pair
(5,5)
Can you please help draw this loci?The locus of point in the interior of the square ABCD AND ALSO equidistant from its side AB and BC is diagonal BD.
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First let's draw the square ABCD:
The point is interior to the square, and also is equidistant from the sides AB and BC.
Drawing all the points that follow these rules in green, we have:
So this loci is represented by the diagonal BD of the square. All the points of this diagonal are equidistant to the sides AB and BC.
The length between the bases on a baseball field is 90ft. A scale drawing shows the distance between the based as 2 1/2 inches. One inch on this drawing equals how many ft?
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SOLUTION:
Step 1:
In this question, we have the following:
The length between the bases on a baseball field is 90ft.
A scale drawing shows the distance between the bases is 2 1/2 inches.
One inch on this drawing equals how many ft?
Step 2:
[tex]\begin{gathered} \text{90 f}eet\text{ =2 }\frac{1}{2}\text{ inches} \\ y\text{ f}eet\text{ = 1 inch} \end{gathered}[/tex]Cross-multiply, we have that:
[tex]\begin{gathered} 2\frac{1}{2}\text{ x y = 9}0\text{ x 1} \\ \frac{5}{2}y=90 \\ \text{Divide both sides by }\frac{5}{2},\text{ we have that:} \\ y\text{ = 90 x }\frac{2}{5} \\ y\text{ =}\frac{180}{5} \\ y\text{ =36} \end{gathered}[/tex]CONCLUSION:
One inch on this drawing equals 36 feet
Answer the following The sign of a is : a. positive B .Zero C.Negative The value of h is given by h The value of k is given by k
Answers
Since the function is concave up, the leading coefficient a must be positive.
Then: The sing of a is positive
The function is expressed in its canonical form, where h and k are the x and y coordinates of the vertex, respectively.
We can check in the graph that the vertex coordinates are (-5,-4).
Therefore, we have:
The value of h is given by h = -5
The value of k is given by k = -4
3 Find the co-ordinates of the point at which the gradient of the curve with equation y = 3x² has gradient 18.
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The co-ordinates of the point at which the gradient of the curve y = 3x² is 18 are (3, 27).
Here we are given the equation of a curve as- y = 3x²
The gradient of a curve can be found out by differentiating it with respect to the independent variable. Thus, the gradient here will be dy/dx.
dy/dx = 6x
Thus the gradient of the curve is 6x.
Further, we are given that the gradient value is 18. thus, the value of x at gradient = 18 will be-
6x = 18
x = 18/6
x = 3
Substituting this in the equation of the curve, we can find the value of y as follows-
y = 3*3²
y = 3*9
y = 27
Thus, the co-ordinates of the point at which the gradient of the curve y = 3x² is 18 are (3, 27).
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I want to learn mathematics
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Answer:
take math class and watch stuff on kai academy
Answer:
use maths watch and get smart
Can find the correct answer
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Answer:
∠ QOR = 35°
Step-by-step explanation:
from the diagram
∠ POQ + ∠ QOR = ∠ POR , that is
24° + ∠ QOR = 59° ( subtract 24° from both sides )
∠ QOR = 35°
I need help this is geometry 
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Answer: 6 a: 1=30 2=44, 3=106 4=30
Step-by-step explanation:
well, 3 is the opposite of 106 so they are equal, 2 is the opposite of 44 so they are equal, then you can just take the straight line and subtract the ones around it from 180 to find the 1 or 4, so 180-106, then 74-44=30. then because 1 and 4 are on opposite sides, they are equal. Sorry for not having enough times for all problems, but to help with 6 and 7, just remember that opposites are equal (you can use in 6b and 7a) and the if they make a straight line they make 180 degrees (use in 7b)
Which of the following expressions are perfect-square trinomials? Check all of the boxes that apply.
x²-16x-64
4x2 +12x+9
x+20x+100
x² + 4x + 16
Answers
Answer:
The second and the third one
Step-by-step explanation:
4x^2 + 12x + 9 = (2x + 3)^2
x^2 + 20x + 100 = (x + 10)^2
OlialSlideAfrange Tools Add-ons HelpLast edit was 30 minutes ago२D PresentBackgroundLayoutThemeTransition56716. The Garcias are on their way to the beach. They are traveling ata rate of 30 miles per hour. Use the ordered pairs to graph thedistance traveled over time.Distance (miles)306090120150Time (hours)12345A15012090Distance (miles)60300Time (hours)GO ONGO ON
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it is given that gracias travels 30 miles with speed of 30 miles per hour in a hour,
so (1 , 30)
the x cordinate is representing the time and y cordinate is representing the distance
so all the coordinates will be
(2, 60) & (3, 90) & (4, 120) & (5, 150)
mark these point on the graph
then draw the line that will meet these point.
Factor xy+qr-xr-qy using grouping method
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We are given the following expression:
[tex]xy+qr-xr-qy[/tex]We will associate the terms that have common factors, like this:
[tex](xy-xr)+(qr-qy)[/tex]Now we take the common factor for each of the parenthesis:
[tex]x(y-r)+q(r-y)[/tex]Since each parenthesis has a common factor but with inverted signs, we will take -1 as a common factor in the second parenthesis, we get:
[tex]x(y-r)-q(y-r)[/tex]Now we can take "y-r" as a common factor for the entire expression:
[tex](y-r)(x-q)[/tex]And thus we have factored the expression.
May I please get help describing each? I have tried multiple times to get each of them are
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Definitions:
Perpendicular bisector: A line that bisects (split into two equal parts) a line segment at a right angle (90°)
Angle bisector: A line that bisects a angle.
Median of a triangle: Line segment drawn from a vertex to the middpoint of the opposite side to the vertex.
Altitude of a triangle: Perpendicular segment form a vertex of a triangle to the opposite side.
a) With the given information you can describe FI as:
Median of triangle FGH:Line segment drawn from a vertex (F) to the middpoint of the opposite side to the vertex (GH). The two marks in red indicates that the segments have the same measure (then the point I is the middpoint of the side GH.
Theres is not indication of a perpendicular angle, or a bisection of the angle. Then you can not describe FI as any of the other options.
Match the vocabulary to the proper definition?1.)two-way frequency table2.)categorical variable3.)marginal frequencies4.)joint frequencies-----------------Definitions:----------------()entries in the TOTAL row and TOTAL column of a two-way frequency table()entries in the body of a two-way frequency table () variables that take on values that are names or labels. The color of a ball, gender, or year in school (freshman, sophomore, junior, senior) are examples of categorical variables ()a useful tool for examining relationships between categorical variables
Answers
1. Two-way frequency table
entries in the body of a two-way frequency table
2. Categorical variable
variables that take on values that are names or labels. The color of a ball, gender, or year in school (freshman, sophomore, junior, senior) are examples of categorical variables
3. Marginal frequencies
entries in the TOTAL row and TOTAL column of a two-way frequency table
4. Joint frequencies
a useful tool for examining relationships between categorical variables
At a movie premiere the movie co-workers were asked whether they liked it or did not like it .of the 20 adult asked 15 of them said they liked it a 50 teenagers asked 32% said they liked it .Fill in the blank below to make a statement the most reasonable possible.At the movie premiere ____ moviegoers enjoyed the Movie more because only ___% did not like the movie where is ___% of the ___ moviegoers did not like the movie.
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Answer:
At the movie premiere, adult moviegoers enjoyed the movie more because only 25% did not like the movie whereas 68% of the teenager moviegoers did not like the movie.
First, let us get the percentage of adults that liked the movie.
It is said that 15 out of 20 adults liked the movie. We can get the percentage by dividing the number of adults who liked the movie by the total number of adults.
[tex]\frac{\text{ number of adults who liked the movie }}{\text{ total number of adults }}=\frac{15}{20}\times100=75\%[/tex]We will then find out the percentage of adults and teenagers that did not like the movie by subtracting the percentage that liked the movie from 100%
Adults who did not like the movie:
[tex]100\%-75\%=25\%[/tex]Teenagers who did not like the movie:
[tex]100\%-32\%=68\%[/tex]Here, we can conclude that:
At the movie premiere, adult moviegoers enjoyed the movie more because only 25% did not like the movie whereas 68% of the teenager moviegoers did not like the movie.
can you tell me in steps how to solve this quadratic formula problem?It's for an essay
