3. Write "T" for true statements and "F" for false statements:
a. Protozoa are multi cellular animals.
b. Vacuoles are larger in plant cell.
c. Body of mammals is covered with feathers.
d. There is a pair of antenna on the head of a cockroach.
e. Birds have hollow and air filled bones.

Answers

Answer 1

Answer:

F

T

F

T

T

Explanation:

Thanks for this oppurtunity


Related Questions

A train started its journey at 9:00. Its average speed between
9:00 and 13:00 was 80 km/h. It travelled 1/5 of its journey by
13:00. If the train was required to arrive at the destination at
21:00, what average speed must the train travel at for the rest
of the journey?

Answers

Answer:

Explanation:

In the four hours before 13:00 the train traveled 4(80) = 320 km.

It needs to travel another 4(320) = 1280 km in the next 21:00 - 13:00 = 8 hrs.

1280 / 8 = 160 km/hr

We can define average speed as:

s = (distance traveled)/(time it takes)

Using this, we will find that the average speed at which the train must travel the rest of the journey is 160km/h.

Here the given information is:

The train starts its journey at 9:00

The average speed between 9:00 and 13:00 was 80km/h, and it travels 1/5 of the journey by 13:00.

Then, if we define D as the total distance of the whole journey, in that lapse of 4 hours the train traveled 1/5 of D, or just D/5.

Then we can write the average speed as:

[tex]80km/h = \frac{(D/5)}{4h}[/tex]

[tex]80km/h*4h = D/5[/tex]

[tex]320km = D/5[/tex]

[tex]5*320km = D = 1,600km[/tex]

This means that the total distance of the journey is 1,600km

And at this time (13:00) the train already traveled 320km, so the distance left is:

[tex]d = 1,600km - 320km = 1,280km[/tex]

And we know that the train needs to finish the journey at 21:00

The time between 13:00 and 21:00 is 8 hours.

So the train needs to travel a distance of 1,280km in 8 hours, then the average speed that the train needs is:

[tex]s = (1,280km)/8h = 160 km/h[/tex]

s = 160km/h

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Which is an accurate statement about a magnetic field's direction?

The magnetic field goes from the north pole to the south pole.
The magnetic field goes from the south pole to the north pole.
The direction of the magnetic field depends on the strength of the field.
The magnetic field depends on if the magnet is man made or natural

Answers

The direction of a magnetic field can be accurately described as flowing from the north pole to the south pole,

What is a magnetic dipole?

When considering the idea of a magnetic dipole, it involves having two magnetic poles that possess equal strength but differ in polarity. This particular configuration results in the creation of a magnetic field that flows from the north to south pole. The magnitude of this field is determined by the size of the magnetic dipole moment, which serves as a distinctive quality of the magnet.

Which is an accurate statement about a magnetic field's direction?

The idea of a magnetic field pertains to a specific region in space that can exert magnetic force on either a magnet or a charged particle in motion. The orientation of the magnetic field lines indicates the direction of the force that would affect any magnetic object within the field. It's important to note that these lines always form closed loops, originating from the north pole of the magnet and extending through surrounding space before ultimately returning to enter at its south pole. This implies that without fail, magnetic field lines travel from north to south pole, with this directional flow being reliant on the magnet's magnetic dipole moment.

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A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other.

What is most likely the phase of the substance?

gas
liquid
solid and gas
liquid and solid

Answers

The answer would be liquid and solid

Liquid substance has the most likely phase.

What is solid, liquid and gas and how they relate to the phase?

Solid:

In the solids, the particles are arranged orderly and closely packed.The attractive forces between particles are very strong.Particles also gets vibrate about a fixed point.The spaces between the particles are extremely small.

Liquid:

In the liquids, the particles arranged randomly but closer than gas and they are also closely packed but further apart than solids.The attractive forces between particles are strong but less than solids.Particles slide or roll over one on the another randomly.There will have some spaces but lesser than gas.

Gas:

The particles in the gases are random, far apart from one another.The attractive forces are very weak.There will be no regular movement.The movement will also be freely done.

Hence, the correct answer is Option B, liquid.

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2. Determine the units of the quantity described by each of the following
combinations of units:

a. kg (m/s) (1/s)
b. (kg/s) (m/s)
c. (kg/s) (m/s)
d. (kg/s) (m/s)

Answers

We have that the unit of the quantities are described

a.kg (m/s) (1/s)=Newton  

b. (kg/s) (m/s^2)=Newton

c. (kg/s) (m/s)^2=Newton  

d. (kg/s) (m/s)​=Newton

From the question we are give the units  

a.kg (m/s) (1/s)  

b. (kg/s) (m/s^2)  

c. (kg/s) (m/s)^2  

d. (kg/s) (m/s)​

a)  

Generally  

kg (m/s) (1/s) is Represented as Newton  

Where Newton is the unit Force and Weight

b)  

Generally  

(kg/s) (m/s) is the unit representation of Newton  

Therefore  

Newton

c)  

kg/s) (m/s) is the unit representation of Newton  

Therefore  

Newton

d)

Generally  

(kg/s) (m/s) is the unit representation of Newton  

Therefore  

Newton

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How many mm is 97.25cm?

Answers

Answer:

972.5 mm

Explanation:

Since there are 10 millimeters in one centimeter, we move the decimal place to the right once to convert from cm to mm.

The answer is 972.5 mm since all you need is to time it by ten

The length of a plate as measured with a ruler is 24.74 cm. The breadth as measured with a Vernier caliper is 6.78 cm. Calculate the are of the plate with exact significant figures.

Answers

The area of the plate is 167.78 centimeters.

The area of the plate can be calculated with the equation of the area of a rectangle:

[tex] A = l*w [/tex]   (1)      

Where:

l: is the length = 24.74 cm

w: is the width = 6.78 cm

By entering the above values into equation (1) we can find the area.

[tex] A = 24.74 cm*6.78 cm = 167.74 cm [/tex]

Therefore, the area of the plate is 167.78 centimeters.

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A fertilized human egg cannot grow into a crocodile duck or fish because

Answers

Answer:

A fertilized human egg cannot grow into a crocodile, duck or fish specifically because of: genetic code. is a stage in reproduction whereby an egg and a sperm fuse to create a single cell.

Explanation:

Because of ; Genetic Code

please help meeee its for physics....

Answers

Nothing accelerates a Projectile Horizontally during Motion...

Consequently

Horizontal Acceleration is Always Zero.

The Horizontal Velocity is always Constant too.

Only the vertical Velocity changes by -9.8ms-².

If this is so...

∆x = v'∆t + ½(0)(∆t)²

∆x = v't.

I'd go with Option D.

The pressure of a liquid is given by P = pgh. Calculate the pressure (in SI unit) if the
density of water, p is 1 g cm-, the acceleration due to gravity, g is 10 m s?, and the
height of water, h is 50 cm.

Answers

Answer:

5000 Pa

Explanation:

First collect the data you've been given already and make sure to convert into the right units;

Density = 1 g/cm³ ...... 1000 Kg/

acceleration due to gravity = 10 m/

Height = 50 cm......0.5 m

after collecting the data, use the formula to solve

pressure = pgh

= 1000 × 10 × 0.5

= 5000 Pa

hope this helps

A particle initially located at the origin has an acceleration of a=3jm/s^2 and an initial velocity of Vi=5im/s.

(a)the vector position and velocity at any time t

Answers

Given the particle's acceleration is

[tex]\vec a(t) = \left(3\dfrac{\rm m}{\mathrm s^2}\right)\vec\jmath[/tex]

with initial velocity

[tex]\vec v(0) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath[/tex]

and starting at the origin, so that

[tex]\vec r(0) = \vec 0[/tex]

you can compute the velocity and position functions by applying the fundamental theorem of calculus:

[tex]\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u)\,\mathrm du[/tex]

[tex]\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u)\,\mathrm du[/tex]

We have

• velocity at time t :

[tex]\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \displaystyle \int_0^t \left(3\dfrac{\rm m}{\mathrm s^2}\right)\,\vec\jmath\,\mathrm du \\\\ \vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath \\\\ \boxed{\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath}[/tex]

• position at time t :

[tex]\vec r(t) = \displaystyle \int_0^t \left(\left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)u\,\vec\jmath\right) \,\mathrm du \\\\ \boxed{\vec r(t) = \left(5\dfrac{\rm m}{\rm s}\right)t\,\vec\imath + \frac12 \left(3\frac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath}[/tex]

What is the displacement of a car traveling 14 km North on I985 then 20 km South on I985?

Answers

Displacement = (14-20) Km = -6 Km

The displacement of a car is -6 Km South

11. Approximatrly how many kelvins are equal to 60°F?
a. 439
b. 212
c. 902
d. 289

Answers

D, that’s the answer

I dont know dont know dont know

Answers

Answer:

what you need help on exactly?

Explanation:

Farah wants to move a 40.0kg rable. She applies a force of 520N. Under these conditions, the table initially moves with an acceleration of 4.50 m/s^2 Calculate the friction force on the table

Answers

Answer:

340 Newtons of friction force

Explanation:

4.50 m/s² = 520N of Fn - ?N of Ff ÷ 40 Kg or [tex]\frac{520-x}{40}[/tex] = 4.50

40* 520 - x/40 = 4.50 *40

520-x = 180

520-x/520 = 180/520

x=340 N of Ff

can someone help me this question ​

Answers

Answer:

Volume of wood is 68-50 = 18 cm³

Explanation:

Hope it helps you

3(8+2)
----------
4^2-1

Answers

1. First you do the parentheses which is 8+2=10
2. 10 times 30
3. 4^2= 16 then you subtract it from 1 = 15
Answer: 30/15=2

Calculate the force applied if 200 Pascal pressure is exerted over the area of 0.2m². With explanation.​

Answers

Force applied will be equal to 40 Newtons .

Answer:

F=40N

Explanation:

As

P=[tex]\frac{F}{A}[/tex]   and

F=P*A

Putting the values

F=200*0.2

F=40N

What is the displacement from 0 to 35.5 seconds

Answers

Answer:

12

cause the is no longer erra

The following are dimensions of various physical parameters that will be discussed later on in the text. Here [L], [T], and [M] denote, respectively, dimensions of length, time, and mass.

Dimension Dimension
Distance (x) [L] Acceleration (a) [L]/[T]2
Time (t) [T] Force (F) [M][L]/[T]2
Mass (m) [M] Energy (E) [M][L]2/[T]2
Speed (v) [L]/[T]

Which of the following equations are dimensionally correct?

a. F = ma
b. x = 2 at2
c. E = 1/2 max
d. E = max
e. F = ?Fx/m

Answers

Dimentional analysis is very important in physics, because it allows finding errors in equations. We find that the following true equations

a) F= m a

b) x = 2 a t²

c) E = [tex]\frac{1}{2} }\ m \ a \ x[/tex]

d) E = m a x

The fundamental units in mechanics are;

the length [L] whose unit is the meter

The time [T] that has the second as a unit

The mass [M] with fundamental unit the kilogram (kg)

all other quantities are derived from these three fundamental units, for example velocity is

     v = x / t

we replace the units

     [v] = [L] / [T]

so the units of velocity are the distance between time.

This exercise uses the units of various quantities and asks to find if the equations are dimensionally correct.

Let's substitute the units in each expression

a) F = m a

    [M] [L] / [[T] ² = [M] [L] / [T] ²

the two sides of the expression are equal therefore the equation is correct

b) x = 2 a t²

scalar quantities have no units

    [L] = [L] / [T] ² [T] ²

    [L] = [L]

the two sides are equal, therefore the equation is correct

c) E = ½ m a x

    [M] [L] ² [T] ² = [M] [L] [T] ² [L]

    [M] [L] ² [T] ² = [M] [L] ² [T] ²

the two sides are equal the equation is correct

d) E = m a x

since scalar quantities have no units, this expression is equivalent to the expression in part c, therefore it is correct

e) F = F x / m

    [M] [L] / [T] ² = [M] [L] / [T] ² [L] / [M]

    [M] [L] / [T] ² = [L] ² / [T] ²

the two sides are different so the equation is false

In the dimensional analysis we find that expressions are true a, b, c, d  and we see that the expression e is false

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Define measurement What problems might me face it measurement systems were not established? (1+2=3) ​

Answers

Answer:

The process of comparing unknown quantities with known quantities is called measurement .

If it measurement system were not established ,then there may create lots of problem such as: unequal measure ,anyone can get more ,or anyone can get less mass ,so on .

HELP PLS. the length of a wall in a class is measured by a class 6 student and his teacher using their hand span the readings obtained by the student is 52 hand spans the reading obtained by his teacher will be _______ (assume there are no errors in the measurement

Answers

Answer:

48

Explanation:

because teachers hand will be bigger than a student's hand. That's why teacher's hand acquire less surface area

A stretched rubber band has _________energy

Answers

Answer:

A stretched rubber band has potential energy

Answer:

elastic potential energy

Explanation:

The temperature at which water leaves the boiler is?

Answers

Answer:

The average setting for a gas-powered hot water boiler is 180°F. This provides the appropriate level needed for most cold weather temperatures. If you can raise the temperature manually, do not set it any higher than 210°F (which is often the limit), and try to remain down at 190°F if you need the extra heat.

what’s the correct answer

Answers

According to 1st equation of motion :

[tex]\boxed{ \boxed{v = u + at}}[/tex]

where,

v = final velocityu = initial velocity a = acceleration t = time

let's solve for t

[tex] \hookrightarrow \: 17.63 = 0 + 2.13t[/tex]

[tex] \hookrightarrow \: t = \dfrac{17.63}{2.13} [/tex]

[tex] \hookrightarrow \: t = 8.276 \approx 8.28\: \: sec[/tex]

Any two importance of measurement

Answers

Answer:

to sell and to buy

Explanation:

measurement is a comparison between unknown quantity with a known quantity

how physical science can be truth?

Answers

Because it is physically true day really know that by just knowing it very well

two mass, m and 2m approach each along a Path a right angle to each Other after collision they Stick together and move off at 2m/s at angle 37degree to Original direction of the mass m What where the initial speed of the two Particles ​

Answers

Answer:

m1 v1 = x-component of momentum   (towards origin)

m2 v2 = y-component of momentum  (towards origin where they collide)

m3 V cos 37 = m1 v1

m3 V sin 37 = m2 v2    components of momentum after collision

sin 37 / cos 37 = 2 v2/ v1

v2/ v1  = 1/2 * tan 37 = 1/2 * .754 = .377   for the ratio of speeds

Using m3 V cos 37 = m1 v1

3 * 2 cos 37 = 1 * v1

v1 = 4.79 m/s

m3 V sin 37 = m2 v2

v2 = 6 * sin 37 / 2 = 1.81 m/2

v2 / v1 = 1.81 / 4.79 = .378      same as ratio found above

Write a formular to show force experienced by charge in magnetic field.​

Answers

Answer:

[tex]{ \boxed{ \sf{F = Bev}}}[/tex]

Explanation:

F » Force

B » Magnetic flux density

e » magnitude of charge

v » voltage

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1. Escribe V, si la afirmación es verdadera o F, si es falsa. Justifica tu respuesta.
1)Un rayo de luz es una línea imaginaria que se traza en dirección perpendicular a la onda.
2)Una onda reflejada es aquella que viaja por el mismo medio de la onda incidente después de alcanzar la frontera entre dos medios.
3) La normal es una recta perpendicular a la línea que divide los dos medios.
4)En los espejos planos el ángulo de incidencia es igual al ángulo de reflexión.
5)En los espejos convexos la luz incide por la parte interna de la superficie esférica.
6)El foco está a una distancia equivalente al doble del radio de curvatura de un espejo esférico.
7)En un espejo esférico una imagen derecha es aquella que está por encima del eje óptico.

Answers

Las leyes de la óptica geométrica, permite encontrar los enunciados verdaderos son:

 1. Un rayo es una línea perpendicular a los frentes de onda.

 2. La onda incidente y reflejada van en el mismo medio

 3. La normal es perpendicular a la superficie que divide el medio.

 4. El espejo el ángulo de incidencia y refracción son iguales

Se le pide que diga si la afirmación es verdadera o falsa.

1) Un rayo de luz es una línea imaginaria que se dibuja perpendicular a la onda.

La luz está compuesta por infinitos frentes de onda, para simplificar la notación se dibuja un plano a través de todos los frentes de onda con la misma fase y la línea normal a esta se llama rayo; es el equivalente matemático de la norma definida para un plano

 

la declaración es verdadera

2) Una onda reflejada es aquella que viaja por el mismo medio que la onda incidente después de alcanzar el límite entre dos medios.  

Cuando la onda interactúa con el medio a medida que se refleja o se transmite, la onda reflejada está en el mismo medio de incidencia.

la declaración es verdadera

3) La normal es una línea perpendicular a la línea que divide las dos medias.

En óptica es habitual describir los fenómenos con respecto a una línea perpendicular al plano de incidencia de la onda electromagnética, esta línea se denomina Normal.

 

La afirmación es verdadera

 

4) En espejos planos, el ángulo de incidencia es igual al ángulo de reflexión.

La ley de la reflexión establece que el ángulo de incidencia es igual al ángulo de reflexión. En los espejos cumplen esta ley

la declaración es verdadera

5) En los espejos convexos la luz incide en el interior de la superficie esférica.

En un espejo convexo, el radio de curvatura va hacia la parte interior de la esfera, los rayos incidentes comienzan en la parte exterior del espejo.

la afirmación es falsa

 

          [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

Donde f es la distancia focal, p y q son la distancia al objeto y la imagen, respectivamente

En este caso la distancia al objeto es infinita,  por lo cual  la distancia focal es igual a la distancia a la imagen

          f = q

El foco está a una distancia igual al mitad radio de curvatura de un espejo esférico.

La distancia focal es la distancia donde se forma la imagen cuando el objeto está en el infinito, si usamos la ecuación del constructor

        f = q = R / 2

donde la distancia focal es el radio de curvatura sobre dos

la afirmación es falsa

7) En un espejo esférico, una imagen derecha es aquella que está por encima del eje óptico.

En óptica, la imagen puede ser vertical o invertida. Por convención el objeto se dibuja hacia arriba con respecto al eje óptico, si la imagen también está hacia arriba se llama derecha y si está hacia abajo se llama invertida

En un espejo esférico es invertida

la afirmación es Falsa

Usando las leyes de la óptica geométrica podemos encontrar si los enunciados son verdaderos o no.

las afirmaciones verdaderas son: 1,2,3,4

las declaraciones falsas son: 4,6,7

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Grive reasons The units of force and pressure are called derived units. an​

Answers

How ??

Force:-

We know

According to newtons second law

[tex]\boxed{\sf Force=Mass\times Acceleration}[/tex]

[tex]\\ \sf\longmapsto Force=kgm/s^2[/tex]

We don't use it

[tex]\\ \sf\longmapsto Force=Newton(N)[/tex]

Hence its a derived unit.

Pressure:-

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{N}{m^2}[/tex]

[tex]\\ \sf\longmapsto Pressure=Pascal(Pa)[/tex]

Hence its a derived unit

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