The Ksp of a substance is the equilibrium constant for the reaction between the dissolved ions and the undissolved solid. In this case, the equation is M₂+(aq) + 2OH-(aq) ↔ M(OH)₂(s).
Knowing the volume of HCl required for the titration (25.10 mL) and the molarity of the HCl (0.173 M), the concentration of M₂+ and OH- ions in the saturated solution can be calculated. The Ksp can then be calculated using the concentration of M₂+ and OH- ions in the solution.
The Ksp can be expressed as Ksp = [M₂+][OH]⁻². To calculate the Ksp, the molarity of the HCl solution is multiplied by the volume used in the titration (25.10 mL) to get the moles of HCl used (4.35 x 10⁻³mol). This number is then divided by the volume of the saturated solution (28.5 mL) to get the concentration of M₂+ (1.53 x 10-2 M) and OH- (3.06 x 10⁻² M).
Finally, the Ksp can be calculated using the concentrations of M₂+ and OH- ions: Ksp = [1.53 x 10⁻²][3.06 x 10⁻²]2 = 4.94 x 10⁻⁵. Thus, the Ksp for this alkaline earth hydroxide is 4.94 x 10-5.
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What is the atomic theory of matter?
The atomic theory of matter states that all matter, whether an element, a compound or a mixture is composed of small particles called atoms.
What is atomic theory?The atomic theory is any of the several theories that explain the structure of the atom, and of subatomic particles.
The atomic theory of matter, first postulated by John Dalton, seeks to explain the nature of matter-the materials of which the Universe, all galaxies, solar systems and Earth are formed.
The components of the atomic theory are as follows;
All matter is made of very tiny particles called atoms.Atoms are indivisible particles, which cannot be created or destroyed in a chemical reactionAtoms of a given element are identical in mass and chemical propertiesAtoms of different elements have different masses and chemical propertiesAtoms combine in the ratio of small whole numbers to form compoundsThe relative number and kinds of atoms are constant in a given compoundLearn more about atomic theory at: https://brainly.com/question/28853813
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According to the general procedure of Experiment A2b, 213 mg of (E)-stilbene (180. 25 g/mol) was reacted with 435 mg of pyridinium bromide perbromide (319. 82 g/mol) to afford 342 mg of meso-stilbene dibromide (340. 05 g/mol) as a white solid. Calculate the percent yield for this reaction. Enter your answer as digits only (no units), using the proper number of significant figures
The percent yield for the given reaction is 85.29%.
The percent yield for this reaction can be calculated using the formula:
percent yield = (actual yield / theoretical yield) x 100
The theoretical yield can be calculated based on the stoichiometry of the reaction. From the equation given, we know that 1 mole of (E)-stilbene reacts with 1 mole of pyridinium bromide perbromide to produce 1 mole of meso-stilbene dibromide.
First, let's calculate the number of moles of (E)-stilbene:
213 mg (E)-stilbene x 1 g/1000 mg x 1 mol/180.25 g = 0.00118 mol (E)-stilbene
Next, let's calculate the number of moles of pyridinium bromide perbromide:
435 mg pyridinium bromide perbromide x 1 g/1000 mg x 1 mol/319.82 g = 0.00136 mol pyridinium bromide perbromide
Since the stoichiometry is 1:1, the number of moles of meso-stilbene dibromide produced is also 0.00118 mol.
Finally, let's calculate the theoretical yield in grams:
theoretical yield = 0.00118 mol x 340.05 g/mol = 0.401 g
Now we can calculate the percent yield:
percent yield = (0.342 mg / 0.401 g) x 100 = 85.29%
Therefore, the percent yield for this reaction is 85.29%.
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What law describes what happens when a steel drum that is heated collapses when put under cold water?
Boyles' Law
Ideal Gas Law
Charles' Law
Gay-Lussac's Law
The law describes what happens when a steel drum that is heated collapses when put under cold water is Gay-Lussac's Law Option d
What is Gay-Lussac's Law?Gay-Lussac's Law, is called the Law of Combining Volumes.
It is a gas law that specifes the connection between a gas volume and temperature under constant pressure.
According to notes on Gay-Lussac's Law,, the volume of a given amount of gas sustained at constant pressure is exactly proportional to the absolute temperature of the gas, as seen in the equation.
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The following reaction occurs when a burner on a gas stove is lit:
CH4(g) + 2O2(g) ⇄ CO2(g) + 2H20(g)
Evaluate the following statements and select the correct grouping. True statements are marked with a T, and false statements are marked with an F.
The system cannot reach equilibrium because it is not a closed system.
Increasing the concentration of the CH4 will increase the production of CO2 and water.
Increasing the temperature of the flame will increase the production of CO2 and water.
Adding CO2 will increase the volume of methane and oxygen
If you apply 1,200 Newtons of force to an object and move it 8 meters, how much work do you do on the object?
To calculate the work done on an object, we use the formula:
Work = Force × Distance × cos(theta)
where "Force" is the magnitude of the force applied, "Distance" is the distance over which the force is applied, and "theta" is the angle between the force and the direction of motion.
In this case, the force is 1,200 Newtons, the distance is 8 meters, and we'll assume the angle between the force and direction of motion is 0 degrees (meaning the force is applied in the same direction as the object is moving). Therefore:
Work = 1,200 N × 8 m × cos(0°)
Work = 9,600 J
So, you do 9,600 joules of work on the object.
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A 3. 00 g mass of compound X was added to 50. 0 g of water
and it is found that the freezing point has decreased by 1. 25 °C.
What is the molar mass of X if it has a van't Hoff factor of 3?
g/mol (Kf of water = 1. 86 K. Kg/mol)
Your answer should be rounded to three significant figures. Do not include units
in your answer.
When a 3.00 g mass of compound X is added to 50.0 g of water, a new mixture is formed. This mixture is a combination of two substances, the compound X and water. A compound is a substance formed when two or more different elements combine chemically in a fixed ratio. In this case, compound X is the result of the combination of two or more elements.
The addition of compound X to water results in the formation of a solution. A solution is a homogeneous mixture of two or more substances, in which the components are uniformly distributed. The compound X dissolves in the water to form a homogeneous mixture.
The mass of the resulting mixture is the sum of the mass of compound X and the mass of water. Therefore, the mass of the resulting mixture is 53.00 g (3.00 g + 50.00 g).
Water is a common solvent for many compounds, including compound X. Water molecules have a polar nature, which enables them to dissolve polar and ionic compounds, such as salts and acids. The dissolution of compound X in water is a result of the polar nature of water molecules.
In summary, the addition of a 3.00 g mass of compound X to 50.00 g of water results in the formation of a homogeneous mixture. The resulting mixture has a mass of 53.00 g, which is the sum of the mass of compound X and the mass of water. Water is a common solvent for many compounds, including compound X, and its polar nature enables it to dissolve many polar and ionic compounds.
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How many liters would be in 7.65 moles of a gas!
7.65 moles of gas at STP would occupy a volume of approximately 171.36 liters.
To find out how many liters are in 7.65 moles of a gas, you will need to use the Ideal Gas Law equation, which is:
PV = nRT
In this equation:
P = pressure of the gas
V = volume of the gas in liters
n = number of moles of the gas
R = ideal gas constant (0.0821 L atm/mol K)
T = temperature in Kelvin
However, since we are not given the values for pressure (P) and temperature (T), we cannot calculate the exact volume (V) in liters for 7.65 moles of a gas.
If we assume standard temperature and pressure (STP) conditions, which are 0°C (273.15 K) and 1 atm, we can use the molar volume of a gas at STP, which is 22.4 liters/mol.
To calculate the volume in liters at STP, you can use the following formula:
V = n × molar volume at STP
Now, plug in the values:
V = 7.65 moles × 22.4 liters/mol
V ≈ 171.36 liters
So, under STP conditions, 7.65 moles of gas would be approximately 171.36 liters.
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A quantity of gas is at a temperature of 20°C, a pressure of 760 torr and occupies a volume of 2. 00 L. If the pressure is changed to 730 torr, what will be the new volume? Assume that there is no temperature change
The new volume of the gas, assuming constant temperature and a change in pressure from 760 torr to 730 torr, is 2.09 L.
Using the Boyle's Law equation,
P₁V₁ = P₂V₂,
where P is pressure and V is volume, we can solve for V₂ by plugging in the given values in the equation:
(760 torr)(2.00 L) = (730 torr)(V₂)
Solving for V₂, we get:
V₂ = (760 torr)(2.00 L) / (730 torr) = 2.09 L
Therefore, the new volume of the gas is 2.09 L.
This result makes sense because according to Boyle's Law, as pressure decreases, volume increases proportionally, assuming a constant temperature.
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Which term names the result of two or more atoms combining chemically?.
The term that names the result of two or more atoms combining chemically is a molecule.
A molecule is formed when two or more atoms combine chemically by sharing electrons in a covalent bond.
This bonding occurs when atoms have unpaired electrons in their outermost shell, and they share these electrons to complete their valence shells. In a covalent bond, the electrons are shared between atoms, rather than being transferred, as in an ionic bond.
Molecules can be formed between atoms of the same element or different elements, depending on the chemical properties of the atoms.
For example, two oxygen atoms can combine to form an oxygen molecule (O2), while a hydrogen atom can combine with an oxygen atom to form a water molecule (H2O).
Molecules are the building blocks of all substances in the universe. They are responsible for the chemical and physical properties of substances, such as their melting and boiling points, solubility, and reactivity.
Understanding the formation and behavior of molecules is essential for understanding chemistry and the world around us.
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How many moles of HCl can be made from 6.15 mol H₂ and an excess of Cl₂?
(Remember to write and balance the chemical equation before calculating your answer)
The number of moles of the HCl that can be made from the 6.15 mol H₂ and the excess of the Cl₂ is 12.3 mol.
The balanced chemical equation is :
H₂ + Cl₂ ---> 2HCl
The number of moles of H₂ = 6.15 mol
The number of moles of any substance = mass / molar mass
The 1 mole of H₂ produces the 2 moles of HCl
The molar ratio in between the H₂ and the HCl is 1 : 2
The number of moles of HCl = 2 × 6.15 mol
The number of moles of HCl = 12.3 mol
Therefore, the total number of moles of HCl produces in the reaction is 12.3 moles.
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Katja plans an experiment that measures the temperature of different colors of paper placed in sunlight. her hypothesis is that if black, blue, yellow, red, and white sheets of paper are exposed to white light, then the black sheet of paper will increase the most in temperature. katja will place a sheet of each color of paper of the same size and thickness in the same location for the same amount of time. why will katja use different colors of paper in her experiment?
Katja is using different colors of paper in her experiment to test her hypothesis that the black sheet of paper will increase the most in temperature when exposed to white light.
Each color of paper will absorb different wavelengths of light, and the amount of energy absorbed will depend on the color of the paper. Black paper will absorb all wavelengths of light and therefore absorb the most energy, leading to an increase in temperature.
On the other hand, white paper will reflect all wavelengths of light and absorb the least amount of energy, leading to a smaller increase in temperature compared to black paper.
By testing multiple colors of paper, Katja can compare the temperature increases of each color and determine which color absorbs the most energy and which absorbs the least. This will provide her with more data to support her hypothesis and better understand the relationship between color and the absorption of energy from light.
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Question 25 of 25
what is indicated by the prefixes cis-and trans-?
a. the size of the molecule
b. the location of the methyl group
c. the type of stereoisomer
d. the type of alkane
The prefixes cis- and trans- are used to describe stereoisomers, which are molecules that have the same molecular formula and connectivity but differ in their spatial arrangement. The correct answer is option c.
Specifically, they are used to describe molecules that have a carbon-carbon double bond or a ring structure.
Cis- and trans- indicate the type of stereoisomer, specifically geometric isomers. Cis- is used to describe molecules in which the two groups attached to the carbons of the double bond are on the same side, while trans- is used to describe molecules in which the two groups are on opposite sides of the double bond.
For example, in the molecule [tex]2-butene[/tex], there are two possible arrangements of the methyl ([tex]CH3[/tex]) and hydrogen (H) groups around the carbon-carbon double bond. If the two methyl groups are on the same side of the double bond, the molecule is called [tex]cis-2-butene[/tex]. If the two methyl groups are on opposite sides of the double bond, the molecule is called [tex]trans-2-butene[/tex].
The correct answer is option c.
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The state of matter which has no definite shape or volume is calledAsolidBliquidCgasDwater
Answer: C. Gas
Explanation:
A gas is a state of matter that has no definite shape or volume, and its particles are usually far apart and moving quickly in random directions.
1.
What is the boiling point of a solution prepared by dissolving 2. 50 g of biphenyl (C12 H10)
in 85. 0 g of benzene. The molecular weight of biphenyl is 154 g.
The boiling point of the solution is 80.58 °C, which is prepared by dissolving 2. 50 g of biphenyl (C₁₂ H₁₀).
To determine the boiling point of the solution, we need to use the equation;
Δ[tex]T_b}[/tex] = [tex]K_{b}[/tex] x m
Where ΔTb is boiling point elevation, is molal boiling point elevation constant, and m is molality of the solution.
First, we to calculate the molality of the solution;
moles of biphenyl =2.50 g / 154 g/mol
= 0.0162 mol
mass of benzene = 85.0 g
moles of benzene = 85.0 g / 78.11 g/mol
= 1.088 mol
molality = moles of solute/mass of solvent (in kg)
molality = 0.0162 mol / 0.085 kg
= 0.19 mol/kg
Next, we need to look up the molal boiling point elevation constant ([tex]K_{b}[/tex]) for benzene. The value of [tex]K_{b}[/tex] for benzene is 2.53 °C/m.
Finally, we alculate the boiling point elevation;
Δ[tex]T_b}[/tex] = [tex]K_{b}[/tex] x m
Δ[tex]T_b}[/tex] = 2.53 °C/m x 0.19 mol/kg
= 0.481 °C
The boiling point elevation (Δ[tex]T_b}[/tex]) is the difference between the boiling point of the solution and the boiling point of the pure solvent. The boiling point of pure benzene is 80.1 °C. Therefore, the boiling point of the solution will be;
Boiling point of solution = 80.1 °C + 0.481 °C
= 80.58 °C
So, the boiling point of the solution is 80.58 °C.
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Calculate the heat energy transferred to 2. 3g of copper, which has a specific heat of 0. 385 J/g·°C, that is heated from 23. 0°C to 174. 0°C. (Enter the answer rounded to two decimal places with a space between the number and unit, ex. : 145. 23 J)
The heat energy transferred to the copper can be calculated using the formula:
Q = m × c × ΔT
where Q is the heat energy transferred, m is the mass of the copper, c is the specific heat capacity of copper, and ΔT is the change in temperature.
Substituting the given values:
m = 2.3 g
c = 0.385 J/g·°C
ΔT = 174.0°C - 23.0°C = 151.0°C
Q = 2.3 g × 0.385 J/g·°C × 151.0°C = 131.38 J
Therefore, the heat energy transferred to 2.3 g of copper is 131.38 J.
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What is the mass in grams of 0.30 mol of nahco3?
The mass in grams of 0.30 mol of NaHCO3 can be calculated using the molar mass of NaHCO3, which is 84.01 g/mol.
To do this, we simply multiply the number of moles by the molar mass. Therefore:
Mass in grams = Number of moles x Molar mass
Mass in grams = 0.30 mol x 84.01 g/mol
Mass in grams = 25.203 g
Therefore, the mass in grams of 0.30 mol of NaHCO3 is 25.203 g.
We first need to understand the concept of molar mass. Molar mass is defined as the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms present in a molecule.
In the case of NaHCO3, the molar mass is calculated by adding the atomic masses of sodium (Na), hydrogen (H), carbon (C), and oxygen (O), which gives us a total of 84.01 g/mol.
When we are given the number of moles of a substance, we can easily convert it to its mass in grams using the formula Mass in grams = Number of moles x Molar mass. This formula helps us to convert the amount of a substance in moles to its corresponding mass in grams.
In conclusion, the mass in grams of 0.30 mol of NaHCO3 is 25.203 g. This calculation was done by multiplying the number of moles of NaHCO3 by its molar mass. Molar mass is a key concept in chemistry, and it allows us to convert between the number of moles of a substance and its mass in grams.
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Calculate the poh of a 3.14x10-5 m hisolution.
poh = (round to 2 decimal places)
The pOH of the 3.14x10^-5 M solution is approximately 9.50 (rounded to 2 decimal places).
To calculate the pOH of a 3.14x10^-5 M solution, first find the pH using the formula:
pH = -log10[H+]
Where [H+] represents the concentration of hydrogen ions in the solution. In this case, the concentration is 3.14x10^-5 M. Then, calculate the pOH using the relationship between pH and pOH:
pH + pOH = 14
First, find the pH:
pH = -log10(3.14x10^-5) ≈ 4.50
Now, calculate the pOH:
pOH = 14 - pH = 14 - 4.50 ≈ 9.50
So, the pOH of the 3.14x10^-5 M solution is approximately 9.50 (rounded to 2 decimal places).
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Find the volume of 53.5 g of O2 at 30.1°C and 110.0 kPa. Round to the nearest tenth.
The volume of 53.5 g of O₂ at 30.1°C and 110.0 kPa is 1 m³ approximately
The Charles Law: What is it explained?According to Charles' Law, while pressure is maintained constant, the volume of a given amount of gas varies in direct proportion to the absolute temperature of the gas. The Kelvin scale is used to measure temperature to determine the absolute temperature.
To find the volume of a gas, we can use the Ideal Gas Law:
PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the universal gas constant, and T is the temperature of the gas in Kelvin.
First, we need to convert the given temperature of 30.1°C to Kelvin:
T = 30.1°C + 273.15 = 303.25 K
Next, we need to determine the number of moles of O₂ present. We can use the molar mass of O₂ to convert from grams to moles:
molar mass of O₂ = 32.00 g/mol
moles of O₂ = 53.5 g / 32.00 g/mol = 1.671875 mol
Now we can rearrange the Ideal Gas Law to solve for V:
V = nRT / P
V = 1.671875 × 8.3145 × 303.25 /110 k × 1000 Pa / kPa
V = 0.062878 m³
Finally, we round the answer to the nearest tenth: (rounded to one decimal place) V = 1 m³
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Can someone please help with this Thermochemical Equation
The balanced thermochemical equation for the combustion of methane gas is:
Calculate much heat is released when 4.5 moles of methane gas undergo a combustion reaction.
The heat that is released by 4.5 moles of methane gas is 4005 kJ.
What is combustion?The chemical reaction of combustion involves the breaking of chemical bonds in the fuel molecules, followed by the recombination of atoms with oxygen to form new molecules such as carbon dioxide, water vapor, and other combustion products.
We know that the balanced reaction equation have been shown in the image that is attached here.
As such we have that;
1 mole of methane gas produces 890 kJ of heat
4.5 moles of methane gas would produce 4.5 * 890/1
= 4005 kJ
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A 0. 225L solution of H2CO3 is neutralized by 0. 0880L of a 1. 22 M Fe(OH)3 solution. What is the concentration of the H2CO3 solution?
The concentration of the H₂CO₃ solution is 0.162 M.
To solve this problem, we can use the balanced chemical equation for the neutralization reaction between H₂CO₃ and Fe(OH)₃:
2 Fe(OH)₃ + 3 H₂CO₃ → Fe₂(CO₃)+ 6 H₂O
From the balanced equation, we can see that the mole ratio between Fe(OH)3 and H₂CO₃ is 2:3. We can use this information along with the volume and concentration of the Fe(OH)₃ solution to calculate the number of moles of H₂CO₃:
Moles of Fe(OH)₃ = volume x concentration = 0.0880 L x 1.22 M = 0.10776 moles
Moles of H₂CO₃= (2/3) x moles of Fe(OH)₃ = (2/3) x 0.10776 moles = 0.07184 moles
Now, we can calculate the concentration of the H₂CO₃ solution using the volume of the solution provided: concentration = moles / volume = 0.07184 moles / 0.225 L = 0.162 M
Therefore, the molarity of the H₂CO₃ solution has been determined to be 0.162 M.
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Neon leaks out of a container in 15. 0 minutes. The same amount of an unknown gas will leak out in 21. 2 minutes under identical conditions. What is this unknown gas? *
The unknown gas is likely methane. The unknown gas leaks out of a container in 21.2 minutes, while Neon leaks out in 15.0 minutes under identical conditions.
To identify the unknown gas, we can use Graham's law of effusion. This law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, this can be expressed as:
Rate1 / Rate2 = √(M2 / M1)
In this case, Rate1 is the rate of effusion of Neon, and Rate2 is the rate of effusion of the unknown gas. M1 is the molar mass of Neon, and M2 is the molar mass of the unknown gas.
First, let's find the ratio of the rates of effusion:
Rate1 / Rate2 = 15.0 minutes / 21.2 minutes = 0.7075
Next, we'll substitute this ratio and the molar mass of Neon (20.18 g/mol) into Graham's law equation:
0.7075 = √(M2 / 20.18)
Now, square both sides of the equation:
0.5006 = M2 / 20.18
Finally, solve for M2 (the molar mass of the unknown gas):
M2 = 0.5006 * 20.18 = 10.10 g/mol
The unknown gas has a molar mass of approximately 10.10 g/mol, which closely matches the molar mass of methane (CH4) at 16.04 g/mol. Therefore, the unknown gas is likely methane.
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What set of coefficients will balance the chemical equation below:
___NH3 (g) + ___O2 (g) ___H2O (l) + ___NO (g)
What set of coefficients will balance the chemical equation below:
___NH3 (g) + ___O2 (g) ___H2O (l) + ___NO (g)
A. 4,5,6,4
B. 2,3,1,1
C. 1,3,3,1
D. 4,3,1,4
A. 4,5,6,4 set of coefficients will balance the chemical equation below
4NH3 (g) + 5O2 (g) 6H2O (l) + 4NO (g)
What are the balancing coefficients?The coefficients necessary to balance a chemical equation are known as stoichiometric coefficients. These are crucial as they link the quantities of reactants consumed and the products produced. Because they are used to determine the equilibrium constants, the coefficients have a connection to them.
The coefficients, which may be modified to make the equation balanced, show how many of each substance is present during the reaction.
Given the amount of bonds each has, it makes reasonable that H2O has a bond order of 2, whereas NH3 has a bond order of 3.
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The half life period of a radioactive element is 20. 0 weeks. After 80. 0
weeks, one gram of the element will reduce to
a 0. 0895 g
b 0. 0925 g
с 0,0625 g
d 0. 0325 g
The remaining amount of the radioactive element, after 80.0 weeks with a half-life of 20.0 weeks, is 0.0625 grams. Thus, the correct answer is с) 0.0625 g.
To solve the problem, we need to calculate the remaining amount of the radioactive element after 80.0 weeks, given a half-life of 20.0 weeks.
We can use the formula: [tex]\text{Remaining amount} = \text{Initial amount} \times \left(\frac{1}{2}\right)^{\frac{\text{time elapsed}}{\text{half-life}}}[/tex]
Plugging in the values, we get:
[tex]\text{Remaining amount} = \text{Initial amount} \times \left(\frac{1}{2}\right)^{\left(\frac{80.0 \text{ weeks}}{20.0 \text{ weeks}}\right)}[/tex]
Simplifying the exponent, we have:
[tex]\text{Remaining amount} = \text{Initial amount} \times \left(\frac{1}{2}\right)^{\frac{\text{elapsed time}}{\text{half-life}}}[/tex]
Calculating[tex]\left(\frac{1}{2}\right)^4[/tex], we get:
[tex]\text{Remaining amount} = 1 , \text{gram} \times \frac{1}{16}[/tex]
Therefore, the remaining amount of the element after 80.0 weeks is 1/16 gram, which is equal to (c) 0.0625 grams.
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A 0. 50 L can of gas is at a pressure of 20. 0 kPa. If the can is run over by a garbage truck and flattened to a volume of 0. 010 L, what is the pressure in kPa?
The pressure inside the flattened can is 1000 kPₐ .
To solve this problem using the Ideal Gas Law formula and the given information. The terms involved in this question are pressure, volume, and the Ideal Gas Law (PV = nRT).
Here's the step-by-step explanation:
1. The initial state of the gas is given as: P₁ = 20.0 kPₐ and V₁ = 0.50 L.
2. The final state of the gas after being flattened is given as: V₂ = 0.010 L.
3. We need to find the final pressure, P₂.
4. Since the problem doesn't involve any changes in temperature or the amount of gas, we can use Boyle's Law, which is a simplified version of the Ideal Gas Law for constant temperature and amount of gas. Boyle's Law states that P₁V₁ = P₂V₂.
5. Plug in the given values: (20.0 kPₐ)(0.50 L) = P2(0.010 L).
6. Solve for P₂: P₂ = (20.0 kPₐ )(0.50 L) / 0.010 L = 1000 kPₐ .
The pressure inside the flattened can is 1000 kPₐ .
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Potassium superoxide (ko2, 71.10 g/mol) can be used to generate oxygen gas. what mass of o2 (32.00 g/mol) can be formed if 500.0 g ko2 reacts with excess h2o? (write the answer to one decimal place)
225.0 g
168.8 g
675.1 g
375.0 g
56.26 g
When 500 gm of KO2 reacts with excess H2O, 112.6 gm of O2 can be formed.
In order to determine the mass of O2 formed from the reaction of KO2 with excess H2O, we'll need to use stoichiometry. First, let's write down the balanced chemical equation:
2 KO2 + 2 H2O → 2 KOH + H2O2 + O2
Now, let's follow these steps:
1. Convert the given mass of KO2 (500.0 g) to moles using its molar mass (71.10 g/mol):
(500.0 g KO2) × (1 mol KO2 / 71.10 g KO2) = 7.03 mol KO2
2. From the balanced equation, we can see that 2 moles of KO2 produce 1 mole of O2. So, we'll convert the moles of KO2 to moles of O2:
(7.03 mol KO2) × (1 mol O2 / 2 mol KO2) = 3.52 mol O2
3. Convert the moles of O2 to mass using its molar mass (32.00 g/mol):
(3.52 mol O2) × (32.00 g O2 / 1 mol O2) = 112.6 g O2
Therefore, when 500.0 g of KO2 reacts with excess H2O, 112.6 g of O2 can be formed.
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HELP CHEMISTRY!! What does the hump in the middle of each energy diagram represent? (exothermic & endothermic diagrams)
Answer:
Activation Energy
Explanation:
I know you dont need this
ENDOTHERMIC
During this chemical reaction energy is absorbed. In the chemistry lab, this would be indicated by a decrease in temperature or if the reaction took place in a test tube, the test tube would feel colder to the touch. Reactions like this one absorb energy because
The reactants have less potential energy than the products
Reactions like this one absorb energy because the reactants have more potential energy than the products, option C is correct.
In exothermic reactions, the products have less potential energy than the reactants. The difference in potential energy between the reactants and products is the energy released during the reaction. This energy is usually released in the form of heat, which causes an increase in temperature.
The reaction releases energy because the products are more stable than the reactants, which means that less energy is required to maintain their chemical bonds. This extra energy is released during the reaction, resulting in a net release of energy, option C is correct.
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The complete question is:
During this chemical reaction energy is released. In the chemistry lab, this would be indicated by an increase in temperature or, if the reaction took place in a test tube, the test tube would feel warmer to the touch. Reactions like this one absorb energy because
A) the reaction requires activation energy.
B) the reactants have less potential energy than the products.
C) the reactants have more potential energy than the products.
D) the mass of the products is greater than the mass of the reactants.
Explain with words how the parent nucleus changes in alpha decay?
Which nutrient helps in the repair of tissue
Protein is the main nutrient that helps in the repair of tissue. Protein provides the amino acids that the body needs to build and repair cells and tissues. Other nutrients that aid in tissue repair include carbohydrates, fats, vitamins, and minerals.
If your end product is 200. 0 g KMnO4 how much KOH did you start with?
Both Scientist A and Scientist B achieved same yield of KMnO₄, indicating they obtained the maximum possible amount based on the starting materials and reaction conditions. The percent yield for Scientist A is approximately 100% and for Scientist B, it is also approximately 100%
To solve these problems, let's go step by step:
1. If the end product is 1.5 moles of KMnO₄, according to the balanced chemical equation:
2 MnO₂ + 4 KOH + O₂ -> 2 KMnO₄ + 2 KOH + H₂
We can see that the stoichiometric ratio between KMnO₄ and MnO₂ is 2:2. Therefore, the number of moles of MnO₂ used in the reaction would be 1.5 moles.
2. To determine how much KOH was used when the end product is 200.0 g of KMnO₄:
Again, using the balanced chemical equation, we can see that the stoichiometric ratio between KMnO₄ and KOH is 2:4. Therefore, the number of moles of KOH used would be twice the number of moles of KMnO₄.
Given that the molar mass of KMnO₄ is approximately 158.034 g/mol, we can calculate the number of moles of KMnO₄:
moles of KMnO₄ = mass of KMnO₄ / molar mass of KMnO₄
moles of KMnO₄ = 200.0 g / 158.034 g/mol
moles of KMnO₄ ≈ 1.265 mol
Since the stoichiometric ratio is 2:4, the number of moles of KOH would be twice that:
moles of KOH = 2 * moles of KMnO₄
moles of KOH = 2 * 1.265 mol
moles of KOH ≈ 2.53 mol
3. To determine the theoretical yield of potassium permanganate when starting with 500 g of MnO₂:
Again, using the balanced chemical equation, we can see that the stoichiometric ratio between MnO₂ and KMnO₄ is 2:2. Therefore, the molar ratio is 1:1.
Given that the molar mass of MnO₂ is approximately 86.9375 g/mol, we can calculate the number of moles of MnO₂:
moles of MnO₂ = mass of MnO₂ / molar mass of MnO₂
moles of MnO₂ = 500 g / 86.9375 g/mol
moles of MnO₂ ≈ 5.75 mol
Since the stoichiometric ratio is 1:1, the theoretical yield of KMnO₄ would be equal to the number of moles of MnO₂:
Theoretical yield of KMnO₄ = moles of MnO₂
Theoretical yield of KMnO₄ ≈ 5.75 mol
4. To calculate the percent yield for Scientist A and Scientist B, we need the actual yields of KMnO₄ produced by each scientist. Let's assume Scientist A produces 83.67 g of KMnO₄ and Scientist B produces 81.35 g of KMnO₄.
Percent yield = (actual yield / theoretical yield) * 100
Percent yield for Scientist A = (83.67 g / (2 * 83.67 g)) * 100 ≈ 100%
Percent yield for Scientist B = (81.35 g / (2 * 81.35 g)) * 100 ≈ 100%
5. Both Scientist A and Scientist B achieved 100% yield, indicating that they obtained the maximum possible amount of KMnO₄ based on the starting amount
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Complete question :
If your end product is 1.5 moles of KMnO4. how many moles of manganese oxide were used in the reaction? The equation for the production of potassium permanganate is as follows: 2 MnO2+ 4 KOH + O2- 2 KMnO4 + 2 KOH + H2 You must show all work to receive full credit If your end product is 200.0 g KMnO4 how much KOH did you start with? The equation for the production of potassium permanganate is as follows: 2 MnO2+ 4 KOH + O2+ 2 KMnO4 + 2 KOH + H2 You must show all work to receive full credit. A company manufacturing KMnO, wants to obtain the highest yield possible Two of their research scientists are working on a technique to increase the yield Both scientists started with 500 g of manganese oxide What is the theoretical yield of potassium permanganate when starting with 500 g MnO2? The equation for the production of potassium permanganate is as follows 2 MnO2+ 4 KOH + 02 - 2 KMnO, +2 KOH + H2 You must show all work to receive tul credit Scientist A produces 83.67 g KMnO4 while Scientist B produces 81.35 g KMnO4 What is the percent yield for Scientist A? What is the percent yield for Scientist B? You must show all work to receive full credit. The equation for the production of potassium permanganate is as follows: 2 MnO2+ 4 KOH + O2-2 KMnO4+2 KOH + H2 of the two scientists' results, whose would you present to the boss as an example of the product your company manufacturers? Justify your answer with evidence and scientific reasoning BIETE
