Answer:
15√3
Step-by-step explanation:
after grouping and adding them to get 15√9
then you apply Surds
ill give brainliest
Directions: Factor the following trinomials containing negative numbers. Follow the rules for operations with signed numbers to identify the correct binomial factors.
1. x2 + 6x - 7
2. x2 - 5x + 6
3. x2 - 6x - 7
4. x2 + 5x - 6
5. x2 + x - 12
6. x2 - 2x - 8
7. x2 - 4x - 5
8. x2 + 2x - 3
9. x2 - 16
10. x2 - x - 12
11. x2 -9x + 18
12. x2 -5x - 14
13. x2 - 7x + 10
14. x2 -11x + 24
15. x2 - x - 30
The aim of factorization to obtain the common factors that are present in the expression.
What are factors?When we factorize an expression, the aim is to obtain the common factors that are present in the expression.
Now we have trinomials numbered 1 - 15. Trinomial is an expression that is made up of three terms. Quadratic expressions are mostly found to appear as trinomial
The binomial factors that are associated with each are shown in the factorized expressions below. The binomials contain two terms in each bracket.
Given the trinomials, the correct binomial factors are;
(x−1)(x+7) (x−2)(x−3)(x+1)(x−7) (x−1)(x+6)(x−3)(x+4)(x+2)(x−4)(x+1)(x−5)(x−1)(x+3) (x+4)(x−4)(x+3)(x−4)(x−3)(x−6)(x+2)(x−7)(x−2)(x−5) (x−3)(x−8) (x+5)(x−6)Learn more about factorization:https://brainly.com/question/19386208
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The controller of MingWare Ceramics Inc. wishes to prepare a cost of goods sold budget for September. The controller assembled the following information for constructing the cost of goods sold budget: Direct materials: Enamel Paint Porcelain Total Total direct materials purchases budgeted for September $35,870 $7,530 $139,890 $183,290 Estimated inventory, September 1 1,730 4,150 6,920 12,800 Desired inventory, September 30 2,980 2,710 7,150 12,840 Direct labor cost: Kiln Department Decorating Department Total Total direct labor cost budgeted for September $51,550 $149,500 $201,050 Finished goods inventories: Dish Bowl Figurine Total Estimated inventory, September 1 $5,810 $3,310 $2,730 $11,850 Desired inventory, September 30 3,720 4,590 4,360 12,670 Work in process inventories: Estimated inventory, September 1 $3,540 Desired inventory, September 30 1,980 Budgeted factory overhead costs for September: Indirect factory wages $80,400 Depreciation of plant and equipment 10,550 Power and light 5,110 Indirect materials 3,390 Total 99,450 Use the preceding information to prepare a cost of goods sold budget for September. For those boxes in which you must enter subtracted or negative numbers use a minus sign. MingWare Ceramics Inc. Cost of Goods Sold Budget For the Month Ending September 30 Finished goods inventory, September 1 $Finished goods inventory, September 1 Direct labor $Direct labor Direct materials: $- Select - - Select - $- Select - - Select - $- Select - Direct labor fill in the blank 15 - Select - - Select - $- Select - Work in process inventory, September 30 fill in the blank 22 - Select - $- Select - - Select - $- Select - 4,100
The preparation of the Cost of Goods Sold Budget for MingWare Ceramics Inc. in September is as follows:
Cost of Goods Sold Budget:Beginning inventory of finished goods $11,850
Cost of goods manufactured 485,310
Ending inventory of finished goods (12,670)
Cost of Goods Sold $484,490
What is the cost of goods sold budget?The cost of goods sold budget sums the costs of the beginning inventory of finished goods with the cost of goods manufactured and subtracts the ending inventory of finished goods.
The cost of goods sold budget is based on the cost of goods manufactured budget.
Data and Calculations:Direct materials: Enamel Paint Porcelain Total
Total direct materials purchases
budgeted for September $35,870 $7,530 $139,890 $183,290
Estimated inventory, September 1 1,730 4,150 6,920 12,800 Desired inventory, September 30 (2,980) (2,710) (7,150) (12,840)
Materials used in production $183,250
Direct labor cost: Kiln Department Decorating Department Total
Total direct labor cost
budgeted for September $51,550 $149,500 $201,050
Finished goods inventories: Dish Bowl Figurine Total
Estimated inventory, September 1 $5,810 $3,310 $2,730 $11,850
Desired inventory, September 30 3,720 4,590 4,360 12,670
Cost of goods manufactured budget:Work in process inventories:
Estimated inventory, September 1 $3,540
Direct materials used in production $183,250
Direct labor costs $201,050
Total factory overhead costs $99,450
Desired inventory, September 30 (1,980)
Cost of goods manufactured $485,310
Budgeted factory overhead costs for September:Indirect factory wages $80,400
Depreciation of plant and equipment 10,550
Power and light 5,110
Indirect materials 3,390
Total 99,450
Thus, to prepare the cost of goods sold, as above, MingWare Ceramics, requires to determine the cost of goods manufactured for September.
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Find the value of y.
answer choices
A. 118
B. 32.5
C. 65
D. 130
The value of 'y' is 32. 5 degrees . Option B
How to determine the valueIt is important to note that If two chords intersect inside a circle,
The measure of the angle formed is half the sum of the measure of the arcs intercepted by the angle and its vertical angle
From the diagram, it is shown that the both the chords at 'y' and the angle '65' intersect in the circle
We then have that;
[tex]y = 65[/tex] × [tex]\frac{1}{2}[/tex]
[tex]y = 65[/tex] × [tex]0. 5[/tex]
y = 32. 5 degrees
We can see that the value of 'y' in the given figure is 32. 5 degrees which is half the angle at the vertex of the intersecting chords.
Thus, the value of 'y' is 32. 5 degrees . Option B
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Underwood Company is preparing its annual profit plan. As part of its analysis of the profitability of individual products, the controller estimates the amount of manufacturing overhead that should be assigned to each of the two product lines from the information given below. Wall Mirrors Specialty Windows Total units produced 30 30 Total number of material moves 7 18 Direct labor hours per unit 145 145 Budgeted material-handling costs are $30,000. The material-handling cost per wall mirror under activity-based costing is:
The material-handling cost per wall mirror under activity-based costing is $280
What is activity-based costing?
Activity-based costing involves absorbing overheads based on cost drivers which directly impact the incurrence of the overhead, in this case, material moves determine the amount of material-handling costs to be incurred, hence, material-handing overheads would be absorbed into the two products based on material moves, which is the appropriate cost driver.
There 25 materials move in both divisions (i.e. 7+18=25)
Material-handling cost per material move=Budgeted material-handling costs /total material moves
Budgeted material-handling costs =$30,000
Material-handling cost per material move=$30,000/25
Material-handling cost per material move=$1,200
Total material-handing costs for wall mirror=number of material moves for wall mirror*Material-handling cost per material move
Total material-handing costs for wall mirror=7*$120
Total material-handing costs for wall mirror=$8,400
material-handling cost per wall mirror=Total material-handing costs for wall mirror/number of wall mirrors
material-handling cost per wall mirror=$8,400/30
material-handling cost per wall mirror=$280
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Find a formula for the nth term in this arithmetic sequence first term -2 common difference an=
27. Identify the domain of the set (6,2), (-1,-5), (4,4), (9, 2) and tell if the relation is a function.
O {-1, 4, 6, 9); not a function
O {-5, 2, 4}; a function
O {-1,4,6,9}; a function
O {-5, 2, 4); not a function
Answer:
the third one
Step-by-step explanation:
it is function that contain four domain
DIRE NEED OF HELP, pleaseee help
(not a lot of points sorry)
Answer:
C. Subtract 4 from both sides.
Step-by-step explanation:
You need the equation in the form x² + ax + b = 0 to then either try factoring or use the quadratic formula.
In order to achieve that, you need to first:
Subtract 4 from both sides.
(Subtracting rational coefficients-Mixed numbers)
Simplify by combining like terms:
1/3k - 8 3/4k
[?] ?
_k
?
Answer:
-8 5/12
Step-by-step explanation:
find the area of a triangular shaped land having the length of three sides 20,34 M and 42 respectively in metre square Anna and ropani
Step-by-step explanation:
if I understand you correctly, then the 3 sides are
a = 20 m
b = 34 m
c = 42 m
under this assumption the best is to use Heron's Formula to get the area :
s = (a + b + c)/2
area = sqrt(s(s - a)(s - b)(s - c))
in our case
s = (20 + 34 + 42)/2 = 96/2 = 48
area = sqrt(48(48-20)(48-34)(48-42)) =
= sqrt(48×28×14×6) = sqrt(112,896) =
= 336 m²
Answer:
sorry i didnt know this D: <3
Step-by-step explanation:
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
If you do in fact mean [tex]f(1)=f(6)=0[/tex] (as opposed to one of these being the derivative of [tex]f[/tex] at some point), then integrating twice gives
[tex]f''(x) = -\dfrac1{x^2}[/tex]
[tex]f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1[/tex]
[tex]f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2[/tex]
From the initial conditions, we find
[tex]f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0[/tex]
[tex]f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)[/tex]
Eliminating [tex]C_2[/tex], we get
[tex](C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))[/tex]
[tex]-5C_1 = \ln(6)[/tex]
[tex]C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)[/tex]
Then
[tex]\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}[/tex]
Hey guys I need some help with #11 so if anyone could help that would be great THANK YOU!!
ONE HUNDRED LOTTERY TICKETS ARE SOLD FOR $5.00 EACH. ONE PRIZE OF $300
WILL BE AWARDED. STEVE PURCHASES ONE TICKET. FIND HIS EXPECTATION.
please help me im begging you help me i beg u :(
A line with slope
-1/3
passes through the point (-4, 4).
Find the coordinates of another point on the line.
Answer:
(0, 8/3) = y-intercept
Step-by-step explanation:
I chose to find the y-intercept since it is easy to find with the given information.
The equation for a line is y = mx + b
To find the y-intercept, we must plug in the info we have and solve for b:
4 = -1/3 (-4) + b
4 = -4/3 + b
8/3 = b
To find a point on the line, you also could have added -1 to 4 and 3 to -4 since slope means rise/run or change in y/change in x:
(y - 1) / (x + 3) = (4 - 1) / (-4 + 3) = (3, -1) (flip since it's the y and x coordinate) = (-1, 3)
a population of bobcats increase by 5% per year if the population is currently 40 in how many years will the population reach 80 round your answer to the nearest tenth. The population will reach 80 in about _____years
[tex]\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & 80\\ P=\textit{initial amount}\dotfill &40\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years \end{cases} \\\\\\ 80=40(1 + 0.05)^{t}\implies \cfrac{80}{40}=1.05^t\implies 2=1.05^t\implies \log(2)=\log(1.05^t) \\\\\\ \log(2)=t\log(1.05)\implies \cfrac{\log(2)}{\log(1.05)}=t\implies 14.2\approx t[/tex]
Ten students from a school appear in one or more subjects for an inter school quiz competition as shown in the table given below. General Knowledge Math Science Acel Barek Carlin Acton Bay Acton Anael Max Anael Max Kai Kai Carl Anael Dario Dario Carlin Barek Let G represents the set of students appearing for General Knowledge, M represents the set of students appearing for Math, and S represents the set of students appearing for Science. Find G n M and G u S .
The computation shows that:
G n M = Anael and Max
G u S = Acel, Action, Anael, Max, Carl, Dario, Catlin, Kai, and Barek.
How to illustrate the information?From the information, ten students from a school appear in one or more subjects for an inter school quiz competition as shown in the table.
The subjects include general Knowledge Math Science.
Therefore, G represents the set of students appearing for General Knowledge, M represents the set of students appearing for Math, and S represents the set of students appearing for Science. The intersection is illustrated above.
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Suppose follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of so that the following is true.
Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.
Answer:
c = 2.25
Step-by-step explanation:
The normal distribution function is symmetrical, so the area not in the central zone is split evenly between the lower and upper tails.
SolutionWe can find -c from ...
P(x < -c) = (1 - 0.9756)/2 . . . . . the area in the lower tail
The calculator tells us -c = -2.25.
c = 2.25
A cylinder has radius of 4 inches and height 10inches.There’s a small cylinder inside the previous cylinder of radius of 2 inches with the same height and same centre.What is total surface area?
The surface area of the cylinder is 48π inches².
How to find the Surface area of a cylinder?Surface area of a cylinder = 2πr(r + h)
where
r = radiush = heightTherefore,
Surface area of the smaller cylinder = 2 × π × 2(2 + 10)
Surface area of the smaller cylinder = 4π(12)
Surface area of the smaller cylinder = 48π
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Manufacturers of tires report that car tires should be able to last an average of 50,000 miles. A new tire company produces a different type of tread and tests 100 randomly selected tires. This sample of 100 tires lasted an average of 51,500 miles. Assuming the new type of tread does not improve the mileage of the tire, 200 sample means were simulated and displayed on the dotplot.
Using the dotplot and the sample mean mileage, is there convincing evidence that the new type of tread improves the mileage of the tire?
Yes, because a mean mileage of 51,500 or more occurred only 14 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
Yes, because a mean mileage of 51,500 or less occurred 186 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
No, because a mean mileage of 51,500 or less occurred 186 out of 200 times, the mean mileage is not statistically significant. There is not convincing evidence the new type of tire tread improves mileage of the tire.
No, because a mean mileage of 51,500 or more occurred 14 out of 200 times, the mean mileage is not statistically significant. There is not convincing evidence the new type of tire tread improves mileage of the tire.
There is convincing evidence the new type of tire tread improves mileage of the tire.
How to interpret the mean mileage?The given parameter is:
Average = 50000 miles
New average = 51500 miles
The dot plot is added as an attachment
From the dot plot, we can see that the mean value of 51500 or more occurred 14 times out of the 200 samples
So, the conclusion is that: (a) Yes, because a mean mileage of 51,500 or more occurred only 14 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
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Two trains leave towns 664 miles apart at the same time and travel toward each other. One train travels 16 mih faster than the other. If they meet in 4 hours, what is the rate of each train?
Answer:
I think that I am right. One train is traveling at 75 mph and the other train is traveling at 91 mph
Step-by-step explanation:
can you answer this question
Based on the given entries that Jonathan Shaw owes and owns, the Balance Sheet can be drawn below.
What is Jonathan Shaw's balance sheet?The assets will go to the right side of the sheet and the liabilities and equity will go to the left.
Jon's Shop of Gifts Balance Sheet
Assets Liabilities
Cash $2,556 Bank loan $19,000
Accounts Receivable: $450 Accounts Payable - $900
R. Gregory Ceramic supply
Accounts Receivable: $1,860 Accounts Payable - $2,900
R. Gregory Jose's Art Co.
Supplies $1,000 Total liabilities $22,800
Furniture $10,300 Equity
Equipment $20,000 Jonathan Shaw capital $51,166
Automobiles $37,800 Total equity $51,166
Total assets $73,966 Total liabilities and $73,966
equity
The equity can be found as:
= Assets - liabilities
= 73,966 - 22,800
= $51,166
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It takes Natalie's mother 20 minutes to drive to work. She works 6 miles away.
If she drives the same speed to pick up Natalie at a friend's house that is 14 miles
away, about how long will the drive take?
A 8.7 minutes
B 2.4 minutes
C 45.7 minutes
D 705 minutes
Answer:
B. 45.7
Step-by-step explanation:
20/6=3.33
3.33*14=46.62
46.62 is closest to 45.7
Therefore, 45.7 is the best answer.
There are three novels on Sam's reading table: Light, Zami, and Money.
. On his next trip, he can choose to take some, none, or all of these novels. In the braces below, list all the possible sets of novels that Sam can take.
Write each set in your list in roster form. If there is more than one set in your list, separate them with commas. If you need the empty set in your list, use the symbol Ø.
The subsets of the set of novels is given as follows:
{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.
How to find the subsets of a set?Suppose we have a set with cardinality n, that is, with n elements. This set will have 2^n subsets, which are all the possible combinations with the elements of the set, including the empty set.
In this problem, the novels are given as follows:
Light, Zami, and Money.
Hence the possible subsets are given as follows:
{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.
With is the list that is asked for this problem, which are the subsets of the set of novels.
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Given the following function, find f(-5), f(0), and f(3).
f(x) = x^2+5
Answer:
f(-5) = 30
f(0) = 5
f(3) = 14
Step-by-step explanation:
=> f(x) = x²+5
for , f(-5) = (-5)² +5
=> 25 +5
=> 30
for , f(0) = (0)² +5
=> 5
for , f(3) = (3)² + 5
=> 9 + 5
=> 14
Evaluate each expression if A=2
B=-3. C=-1. D=4
2d-a/b
Answer:
2 × 4 - 2 / -3
8-2/-3
6/-3
-2
i need help with these 2
Answer:
Step-by-step explanation: Hey for the second one I got y = -3/4x -0.5 I'm not sure if its correct though sorry if not
ill try my best to explain my solution though
1. From the parallel equation (3x + 4y = 12) all we need to do is find the slope
So the easiest way to do so is to put the said equation in y-intercept form
y=mx +b
m= slope
b= y intercept
so 1. 3x + 4y = 12
=
4y = 12-3x
divide that by 4 to get only y
y=3-3/4x
-3/4 is our slope
y=-3/4x+b
than we have a point -2, -2
if we put -2 for y
-2=-3/4x+b
and then we put our -2 for x
-2 = -3/4 * -2 + b
=
-2 = -1.5 +b
b=-0.5
Answer : y=-3/4x-0.5
which expression gives the value of QR?
a. 67 sin 80 degrees over sin 52 degrees
b. 67 sin 52 degrees over sin 80 degrees
c. 51 tan 52 degrees
d. 51 sin 80 degrees over cos 52 degrees
Answer:
B
Step-by-step explanation:
using the Sine Rule in Δ QRS
[tex]\frac{QR}{sinS}[/tex] = [tex]\frac{RS}{sinQ}[/tex] ( substitute values )
[tex]\frac{QR}{sin52}[/tex] = [tex]\frac{67}{sin80}[/tex] ( cross- multiply )
QR × sin80° = 67 × sin52° ( divide both sides by sin80° )
QR = [tex]\frac{67sin52}{sin80}[/tex]
Based on the family the graph below belongs to, which equation could represent the graph?
Considering the asymptotes of the function, the equation that represents the graph is:
[tex]y = \frac{1}{x + 2} + 3[/tex]
What are the asymptotes of a function f(x)?The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.This function, from the graph, has a vertical asymptote at x = -2, hence the denominator is given by:[tex]y = \frac{1}{x + 2} + 3[/tex]
x + 2, as x + 2 = 0 -> x = -2.
The horizontal asymptote is of y = 3, hence:
[tex]\lim_{x \rightarrow \infty} f(x) = 3[/tex]
Which means that the function is described by the following rule:
[tex]y = \frac{1}{x + 2} + 3[/tex]
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find derivative of y= sin x sin 3x
The derivative of y= sin x sin 3x is [tex]$=3 \cos x-3 \cos 3 x$[/tex]
What is a derivative?Futures contracts, options contracts, and credit default swaps are typical types of derivatives. Beyond this, a sizable number of derivative contracts satisfy the requirements of a wide range of counterparties.To find the derivative of y= sin x sin 3x:
[tex]$y=3 \sin (x)-\sin (3 x)$[/tex]
[tex]$y^{\prime}=3 \cos x-[\cos (3 x) \cdot 3]$[/tex]
[tex]$y^{\prime}=3(\cos x-\cos 3 x)$[/tex]
[tex]\frac{dx}{dy} =3 cosx - 3 cos x[/tex]
Differentiate [tex]sin 3x[/tex] using the chain rule
Given [tex]y=f^{'} (g(x))*g^{'}[/tex]←chain rule
y=[tex]y=3 sin x-sin 3x[/tex]
[tex]\frac{dx}{dy} =3 cos x - cos 3x*\frac{d}{dx} (3x)[/tex]
[tex]=3cosx-3cos3x[/tex]
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On Wednesday, the temperature changes -3
∘
each hour for 10 hours. If the temperature was 12
∘
to begin with on Wednesday, what was the temperature after the 10 hours.
Answer:
-24 would be the temperature
Answer:
-24 BECAUSE I did all the math.
