500 N of force on a large box for 45 seconds, but it does not move.
How much work is being done?
What is the power?

Answer:

4870 N

Explanation:

Since he is not accelerating

  the force is equal to his weight    mg  = 487 * 10 = 4870 N

Answer:

Approximately [tex]1.9\times 10^{4}\; {\rm N}[/tex] (rounded up) assuming that [tex]g = (-9.81)\; {\rm N \cdot kg^{-1}}[/tex] (downwards.)

Explanation:

The car is accelerating at a constant [tex]a = 0.60\; {\rm m\cdot s^{-2}}[/tex] (positive since the car is accelerating upwards.) Hence, the net force on this car will be:

[tex]\begin{aligned}F_{\text{net}} &= m\, a \\ &= 1800\; {\rm kg} \times 0.60\; {\rm m\cdot s^{-2}} \\ &= 1080\; {\rm N}\end{aligned}[/tex].

Note that since net force points in the same direction as acceleration (upwards,) [tex]F_{\text{net}}[/tex] is also positive.

The main forces on this car are:

With a mass of [tex]m = 1800\; {\rm kg}[/tex], the weight on this car will be [tex]m\, g = 1800\; {\rm kg} \times (-9.81)\; {\rm N \cdot kg} = (-17658)\; {\rm N}[/tex] (negative since weight points downwards to the ground.)

The net force on this car is the sum of the external forces:

[tex]F_{\text{net}} = F(\text{tension}) + m\, g[/tex].

It is shown that [tex]F_{\text{net}} = 1080\; {\rm N}[/tex] while [tex]m\, g = (-17658)\; {\rm N}[/tex]. Substitute both values into the equation and solve for [tex]F(\text{tension})[/tex]:

[tex]1080\; {\rm N} = F(\text{tension}) + (-17658)\; {\rm N}[/tex].

[tex]\begin{aligned}F(\text{tension}) &= 1080\; {\rm N} + 17658\; {\rm N} \approx 1.9\times 10^{4}\; {\rm N} \end{aligned}[/tex] (rounded up.)

(a) To generate a 1 T magnetic field inside the solenoid, we need 7.96 x 10⁶ turns.

(b) If we had an iron core inside the solenoid with relative permeability of 64,000, the number of  turns would be 124 turns.

The number of turns of the solenoid is determined by applying the following equation for magnetic field strength at the center of the solenoid.

B = μnI

where;

n = B/ μI

N/L = B/μI

N = (BL)/μI

where;

n = (1 x 0.01) / (4π x 10⁻⁷  x 0.001)

n = 7.96 x 10⁶ turns

If we had an iron core inside the solenoid with relative permeability of 64,000, the number of turns would be calculated as;

N = (BL)/(μI x μr)

where;

N = (1 x 0.01) / (4π x 10⁻⁷  x 0.001 x 64,000)

N = 124 turns

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In class, one sophisticated and expensive demonstration the class would see in where I lift the table, so the speed of the book at the bottom of the table is 2.55 m/s. Hence, option C is correct.

A force that acts across sliding surfaces is referred to it as kinetic friction. A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' kinetic friction will determine how much force is applied.

According to the given data in the question,

mgh - (μmg cosθ)s = 1/2 mv²

v²/2 = (9.8)(1.27)(sin 39.7) - (0.49)(9.8)(1.27)(cos 39.7)

v = 2.55 m/s.

Therefore, the speed of the book will be equal to 2.55 m/s.

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I hate to leave you answer less, but there isn't even a question here to answer.

The characteristics of the surfaces in contact determine the coefficient of static frictional force. It doesn't depend on how big the surfaces are. Depending on the fluid gradient in velocity between fluid layers.

It speaks of the friction force of a fluid in motion. A fluid with high viscosity resists motion due of high internal stress created by its molecular structure. In cold conditions, low-viscosity oils help the motor begin more quickly by reducing friction between engine components. Elevated oils, on the other hand, retain the strength and thickness of the film.

Measurements of viscosity are utilized in the grocery business to increase productivity and cost effectiveness. It has an effect on how quickly a substance moves through a pipe, what it takes to set or dry, and also how quickly the fluid is dispensed into packaging.

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Answer:

  2 m/s²

Explanation:

You want the acceleration produced by a force on 14 kg if that same force produces an acceleration of 7 m/s² when acting on a mass of 4 kg.

For the same force, the acceleration is inversely proportional to the mass. In this problem, the mass increases from 4 kg to 14 kg, a factor of 14/4 = 7/2.

The acceleration will change by a factor that is the inverse of this: 2/7.

  acceleration of 14 kg = (7 m/s²) × (2/7) = 2 m/s²

The period of the ball's motion is 0.142 s and the frequency of the motion is 7 Hz.

The period of the ball's motion is calculated by applying the following kinematic equation as shown below.

v = 2πr/T

ωr = 2πr/T

ω = 2π/T

T = 2π/ω

where;

The angular speed of the ball = 7 rev/s = 7 rev/s  x 2π rad/rev = 14π rad/s

T = 2π/14π

T = 1/7 s = 0.142 s

The frequency of the ball's motion is the inverse of the period of the motion and can be calculated as follows;

f = 1/T

f = (1) / (1/7) = 7 Hz

Thus, the period of the ball's motion is determined from the angular speed of the ball while the frequency of the ball's motion is the reciprocal of the period of the motion.

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The energy needed by a stove to transfer heat completely to 1 g of liquid water fro 1 °C to 25 °C is 100.37 J.

Energy is the ability or the capacity to do work.

To calculate the  amount of energy, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The energy required is 100.37 J.

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Taking into account the definition of calorimetry, the energy that a stove must transfer to completely heat 1 g of liquid water from 1 °C to 25 °C is 100.416 J.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When heat added or removed from a substance causes a temperature change in it without affecting its molecular structure, it is called sensible heat.

So, the expression that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the definition of calorimetry:

Q = 4.184 J/gC× 1 g× 24 C

Solving:

Q= 100.416 J

Finally, the energy needed is 100.416 J.

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You may find out an object's total displacement—or how far it is from its point of origin—by using the football player's total displacement, d=46.10yd,definite integral of velocity function of an item.

It's common for people to believe that distance & displacement are really just different labels for the same thing. Displacement and distance are different ideas, though. The overall distance traveled by an object during its voyage will be more than the displacement between those two points if it changes direction.

In terms of its density and volume, the displaced fluid's mass can be stated as m = V. W = mg, where g is the acceleration due to gravity, is the weight of the fluid that has been displaced. As a result, W = Vg can be used to indicate the weight of the displaced fluid.

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Answer:

KE + PE = constant       conservation of energy

At 50 m   KE = zero and PE = m g h

PE = 700 kg* 9.80 m/s^2 * 50 m = 343,000 Joules

PE + KE = 343,000 J

At point R

PE = 343,000 J - 1/2 * 700 kg * 400 m^2 / s^2 = 203,000 J

m g h = 203,000 J       at point R

h = 203,000 J / (700 kg * 9.80 m/s^2 = 29.6 m    height of point R

Check:

343,000 = 700 * 9.80 * 29.6 + 350 * 400 = 343,000    

Adding PE and KE at point R

The electric motor will lift the 131 kg bundle of shingles at a height of 14 m.

Gravitational potential energy is the energy exhibited by an object because of a change in its position in the presence gravitational field.

The gravitational potential energy of an object at height h from the surface of the earth is given by:

[tex]U = mgh,[/tex]                  where m is the mass of the object.

Given, the power of the electric motor, P = 1.5 KW, and time, t - 12 s

Power = Work/ time

Work = Power × time

Work = 1500 ×12 = 18000 J

Given, the mass of the object, m= 131 Kg

The gravitational potential energy, U = 18000J

The height of the bundle of shingles can be determined as:

18000 = 131 ×9.8 ×H

H = 14 m

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Your question was incomplete most probably complete question was,

An electric motor is used to hoist building supplies from the ground to the roof of a building. How much work can the motor do in 12 seconds if its power output is 1.5 kW. How high can it lift a 131 kg bundle of shingles in that time?

Explanation:

According to newton's second law.

The acceleration of the car would be 10 m/s² if the force (10 N) on it is doubled.

We know that the acceleration of an object can be calculated using the formula ⇒ a = F/m (i)

Here, the force experienced by the car is ⇒ F = 10 N

If this force is doubled we would have ⇒ 2×10 ⇒ 20 N (ii)

The mass of the car is ⇒ m = 2 kg (iii)

Now, putting the values of the doubled force and mass (ii and iii) in (i), we get ⇒ a = 20/2

a = 10 m/s²

Therefore, the car has an acceleration of 10 m/s² when the force on it is doubled.

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Option -a is correct. The two objects' respective masses and distances from one another.

In other words, a line connecting the two masses is where the force vectors we could depict on each mass lie. When two objects pull on one another due to gravity, this is always true. The lines of those attractional forces run between the centers of mass of the two objects.

Any particle of matter in the universe will gravitate toward any other with a force that varies directly as the product of the masses and inversely as the square of the distance between them, according to Newton's law of gravitation.

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The number of complete cycles the rotating mirror goes through before the angular velocity gets to zero is approximately 1166.8 revs

Angular velocity is the ratio of the angle turned to the time taken.

The kinematic equation for angular velocity are presented as follows;

ω = ω₀ + α·t

θ = θ₀ + ω₀·t + 0.5·α·t²

Where;

θ₀ = The initial angle turned = 0

ω₀ = The initial angular velocity of the mirrors = 115 rad/s clockwise

α = The angular acceleration = (115  - (-115))rad/s/(85 s) = -46/17 m/s²

t = The duration of the motion;

When the angular velocity, ω is zero, we get;

0 = 115 - 46/17·t

t = 85/2

Which indicates;

θ = 0 + 115× (85/2) + 0.5×(46/17) ×(85/2)² = 7331.25

θ = 7331.25 radians

θ = 7331.25/(2×π) ≈ 1166.8 rev

The mirrors would have turned through approximately 1166.8 revolutions when the angular gets to zero

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The amount of work that the force does as the particle crosses the 21.0 J. Work done refers to the amount of energy used by a force that move an object.

A force's output is defined as the product of the force's component acting in the displacement's direction and its magnitude. Formula. The following formula can be used to determine work: multiply force by distance traveled inside the direction of force. W = F × d.

A force is said to have completed its work when it exerts itself on an object and the object really moves in the direction of the applied force. A product of the force as well as the object's displacement in the force's direction is the work that the force produces.

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Answer:

Explanation:

The work is numerically equal to the area of ​​the figure lying under the graph of the function.

(a)

A₁ = (1/2)·80·6 = 240 J

(b)

A₂ = (1/2)·40·3 = 60 J

(c)

A = A₁ + A₂ = 240 + 60 = 300 J

Examples of following forces mentioned -

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Answer:

30 . 7 m

Explanation:

It takes 2.5 seconds for the rock to fall the vertical height

d = 1/2 a t^2

d = 1/2 ( 9.81)(2.5^2) = 30.7 m

Astronomers refer to as retrograde motion of the planets to an apparent movement of the planets westward from night to night.

The retrograde movement or the retrogradation of the planets is the apparent movement that a planet makes in the opposite direction to the other bodies that make up the system where it is.

This movement is actually an optical illusion that occurs due to the difference in speed between the different planets, looking as if one of them were moving backwards from east to west.

Therefore, we can confirm that the correct answer is option D. apparent movement of the planets westward from night to night.

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It is evident from Isaac Newton's equation for universal gravitation that ANY TWO masses will act as an easily calculable attractive force on one another. Cavendish proved that this was accurate (for masses that he gathered in his shed).

The Cavendish experiment was the first to accurately determine the gravitational constant and the force of gravity between masses in a laboratory setting. Cavendish's work does not directly mention the gravitational constant due to the unit norms in use at the time. Instead, the outcome was initially stated as Earth's specific gravity, or alternatively, as Earth's mass. The first precise values for these geophysical constants came from his experiment.

Thus, by measuring the universal  gravitational constant though experiment,  Cavendish's experiment makes easy to calculate gravitational attraction force for minute objects also.

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In arrangement B) , mirrors are placed mutually perpendicular to each other .

A retroreflector is a device or surface that reflects radiation back to its source with minimum scattering.

When two mirrors are placed perpendicular to each other , and if a  light ray that strikes an object consisting of two mutually perpendicular reflective surfaces is reflected back exactly parallel to the direction to the source it came from.

out of all arrangements , it can be observed that in arrangement B) , mirrors are placed mutually perpendicular to each other .

hence , correct option will be

option B

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The change in gravitational potential energy stored in 16 Jule.

What is gravitational potential energy?

In classical mechanics, of the  gravtitational potential at in a  location is equal to the work per unit mass that's would be needed to Move an object to that locations from a fixed references  location. It is analogous to the electric potential with the mass playing the role of charge.

Sol-As per the given question ∆PE = mgh

M= skg

g= 4m/s^2

∆h = 2m

∆PE = 2m×4m×2m

= 16 Joules.

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If the speed is constant, then there is no acceleration. The area beneath the acceleration graph for a certain time period  equals the change in velocity during that time period.

Acceleration is zero when the velocity is constant. The area under the acceleration graph for a period of time is equal to the change in velocity for that period. There can be no area beneath the acceleration graph in this instance because the velocity does not change.

During a specific motion, the acceleration will not change, as indicated by the word constant. These curves are used to determine the value of only variable velocity if the item experiences this kind of acceleration, as the graph presented will be linear along with slope.

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The best graph to use if I want to compare the price of six different cars would be a bar graph

A bar graph is a graphical representation of the given data . It uses bars that extend to different heights to depict value .

Bar graphs are used to compare different type of things between different groups or to see changes over a period of time. Hence , bar graph will fits the best if one want to compare the price of six different cars .

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The gas is a matter as it has mass and occupies space which is evident from the fact that it weighed less.

Anything that occupies space and has mass is matter.

When the gas was shot out of the can, the can weighed less. This simply means that gas has mass.

Since the gas has mass and does occupy space, so, this shows that gas is matter.

Everything around is made up of matter. There are different types of matter like solids, liquids, and gas. These three are the primary forms of matter. Two other forms are also discovered which are Plasma and Bose-Einstein Condensate.

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Answer:

Yes.

Friction is the force which resists the motion of an Object. Measured in Newtons.

formula = F=ma, where f is the force, m is the mass and a is the acceleration