A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.

An obstruction is just ahead on the shoulder. Your front wheel leaves the roadway at a high speed. You countersteer when the front tire touches the roadway.

Countersteer is usually done by the cyclists and motorcyclists to turn at higher speeds. It is advisable to be done only on the race tracks. This is because the two wheels do not follow the same path during turning and it may affect other vehicles on normal roads. The rider must be leaned in the direction of turn in order to complete the turn. As the front wheel leaves at a higher speed, countersteering is done when the front wheel touches the ground.

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Answer: Find the right angle degree and then you will find ow to do the rest.

Answer: The rods both have the same charge therefore they repel each other.  The force of repulsion creates a downward force on the balance pan and therefore the balance registers a higher reading.

The test section's pressure is lower than the ambient pressure.

In the physical sciences, pressure is defined as the perpendicular force per unit area or the stress at a particular location within a confined fluid.

Given,

Diameter of Test section, d₂ = 0.5m

Area, A₂ = π/4d₂² = π/4×0.5² = 0.19635m²

Now, At Inlet,

Po = 101325Pa

To = 288 k

s = 122 kg/m³

(a) Using Bernoulli Theorem, i'n Test Section,

Po = [tex]P_{t}[/tex] +1/2γ [tex]v_{t^{2} }[/tex]

101325 = [tex]P_{t}[/tex] + ½ (1.22) (200) ²

[tex]P_{t}[/tex] = 76925 Pa

[[tex]v_{t}[/tex] = 200m/s]

Now,

Static Temperature, [tex]T_{t}[/tex]

[tex]T_{0}[/tex] = [tex]T_{t}[/tex] +v²/2[tex]c_{p}[/tex]

288 = [tex]T_{t}[/tex] +200²/2×1005

[tex]T_{t}[/tex] = 268.09k.

Thus,

[tex]M_{t}[/tex] = [tex]v_{t}[/tex]/[tex]\sqrt{\nu RT_{t} }[/tex]

[tex]M_{t}[/tex] = 200/1.4×287×268

[tex]M_{t}[/tex]= 0.609

The test section's pressure is lower than the ambient pressure.

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The beat frequency is always equal to the difference in frequency between the two notes that interact to create the beats.

First wave frequency 5Hz

Second wave frequency 227Hz

Beat frequency 〰️222Hz.

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342.5 N of force must she exert to stay on if she is 0.891 m from its center while 22.0 kg child is riding a playground merry-go-round that is rotating at 40.0 rev/min

Since we are given the mas of the child  which is  22.0 kg and the number of revolutions which is 40.0 rev/min   which will be  :

n=2*3.14 *40.0 /60  = 4.18 radians/s

and the distance from the center is  0.891 m( r). The formula we are referring to calculates the centripetal force :

F= m(n)²* r

=22(4.18)²*0.891

= 342.49 = 342.5 N

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If there is a 1.0% minimum energy uncertainty in the photons, the pulse's minimum duration is  1.6313×10⁻¹⁴ seconds.

There are two approaches to determine a photon's energy: E = h f can be used if the photon's frequency is known. This equation is referred to as Planck's equation because Max Planck proposed it. Using the formula E = h c, the photon's energy can be determined if its wavelength is known.

energy of the laser = h × c/λ

where h=Planck's constant-6.626×10⁻³⁴

c-speed of light = 3×10⁻⁸ m/s

λ = wavelength = 615 nm-615×10⁻⁹ m

energy = E = 6.626×10⁻³⁴×3×10⁸/(615×10⁻⁹) = 3.2322×10⁻¹⁹ J

then uncertainty in energy = 0.01×E = 3.2322×10⁻²¹ J

from Heisenberg uncertainty principle:

uncertainty in energy × uncertainty in time > h/(4× π)

==> uncertainty in time >6.626×10⁻³⁴/(4× π×3.2322×10⁻²¹)=1.6313×10⁻¹⁴

so minimum duration of the pulse is 1.6313×10⁻¹⁴ seconds.

To know more about If there is a 1.0% minimum energy uncertainty in the photons, the pulse's minimum duration is  1.6313×10⁻¹⁴ seconds.

There are two approaches to determine a photon's energy: E = h f can be used if the photon's frequency is known. This equation is referred to as Planck's equation because Max Planck proposed it. Using the formula E = h c, the photon's energy can be determined if its wavelength is known.

energy of the laser=h × c/λ

where h=Planck's constant-6.626×10⁻³⁴

c-speed of light = 3×10⁻⁸ m/s

λ = wavelength = 615 nm-615×10⁻⁹ m

energy = E = 6.626×10⁻³⁴×3×10⁸/(615×10⁻⁹) = 3.2322×10⁻¹⁹ J

then uncertainty in energy = 0.01×E = 3.2322×10⁻²¹ J

from Heisenberg uncertainty principle:

uncertainty in energy × uncertainty in time > h/(4× π)

==> uncertainty in time >6.626×10⁻³⁴/(4× π×3.2322×10⁻²¹)=1.6313×10⁻¹⁴

so minimum duration of the pulse is 1.6313×10⁻¹⁴ seconds.

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The acceleration is going to be down the ramp as the cars roll up it and it's the same direction. In all 3 cases.

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

According to Newton's Second Law, the amount of an object's acceleration is the combined result of two causes :

A linear acceleration is the acceleration of the car in the direction it is moving, and it causes the passengers to feel a force pushing them back into their seats.

The acceleration that is used when changing direction is referred to as radial acceleration, and the reaction that the passengers feel is a centrifugal force.

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This is also known as the cut and weight method for determining the average thickness of plastic sheets.

The calculator below uses the formula (volume) x (density) = (weight) to calculate the theoretical thickness of a plastic film. "Film" is generally less than 1 mm thick, so the unit is μm. (If it is 1 mm or more, it is called a "sheet.") Generally, the micrometer method (JIS-C-2151) is used. Using a micrometer, measure the specified number of specified points in the width direction and length direction of the film. Film thickness has a significant impact on coating quality and cost. Measuring it and knowing which gauge to use is routine for every coater. Film thickness plays an important role in product quality, process control, and cost control and can be measured by various instruments.

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Heating of gas leads to change in kinetic energy of the gas.

As the temperature of the system increases, the molecules in it begin to move faster, and the speed of the particles is directly proportional to the kinetic energy.

Kinetic energy is the energy possessed by the gaseous particles while they are in motion.

Mathematically, KE = (1/2)mv^2,

where KE is kinetic energy, m is mass, and v is velocity.

When the temperature of a gas increases but the pressure remains the same, the volume of the gas increases, which means that the molecules must cover more space in the same amount of time by moving faster.

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The statement that is true regarding a distance vs. time graph is option A: The graph should show distance on the vertical axis.

How far an object has come in a certain amount of time is displayed on a distance-time graph. Time is represented on the X-axis and Distance is plotted on the Y-axis (left) (bottom).

On a distance-time graph, an object's motion is indicated by a sloping line. The slope or gradient of the line in a distance-time graph is equal to the object's speed. The object is travelling more quickly the steeper the line is (and the bigger the gradient).

Note that the distance-time graph shows the relationship between distance and time by plotting distance on the y-axis and time on the x-axis.

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Answer:

(Question) Which quantity is scalar?

(Answer) Energy

(Question) Which option describes a vector quantity?

(Answer) It has magnitude, units, and direction.

(Question) A sailboat ends up 7 miles to the west of a pier. Which statement is true about this situation?

(Answer) It describes displacement, which is a vector quantity.

(Question) Which statement is true regarding a distance vs. time graph?

(Answer) The graph should show distance on the vertical axis.

(Question) On a distance vs. time graph for an object, a line segment that is sloping upward indicates

(Answer) motion in the positive direction.

Explanation:

just finished the quick check UwU

The image is formed at the distance 50/3 from the concave mirror .

The reflective surface of a concave mirror is curved inward and away from the light source. Concave mirrors focus light inward to a single focal point. In contrast to convex mirrors, the image formed by a concave mirror changes depending on the distance between the object and the mirror.

Given ,

In concave lens

focal length f =+25

object distance  u =20cm

Using lens formula, we have

1/f=1/v-1/u

1/25=1/v-1/20

1/v=1/20-1/25=2-1/25 =1/25

v = 25 cm

Now, for concave mirror, we have

Focal length, f= R/2=25/2 = 12.5 cm

Object distance, u=+(25−50) cm= -25 cm

Using mirror formula, we have

1/f=1/v + 1/u

1/v = 1/12.5 - 1/-25 = 5-2/50 = 3/50

v = +50/3

Therefore the image is formed at the distance 50/3 from the concave mirror

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The final speed of the astronaut at the space station is 0.36 m/s and the direction will be opposite to the direction of the tool kit thrown.

The mass of the astronaut = 80 kg

The mass of the tool kit = 15 kg

The speed of the space station = 1.25 m/s

The speed of the tool kit threw = 6 m/s

The final speed of the astronaut can be found using the conservation of momentum formula,

           [tex]\displaystyle m_{1}v_{f1} + m_{2}v_{f2} = m_{1}v_{i1} + m_{2}v_{i2}[/tex]

where m₁ is the mass of the astronaut

           m₂ is the mass of the tool kit

           [tex]\displaystyle v_{i1}[/tex] and [tex]\displaystyle v_{i2}[/tex] is the speed of the space station

           [tex]\displaystyle v_{f1}[/tex] is the speed of the astronaut after throwing the toolkit

Let us substitute the known values in the above equation, we get

              (80 x [tex]\displaystyle v_{f1}[/tex]) + (15 x 6) = (80 x 1.25) + (15 x 1.25)

                     (80 x [tex]\displaystyle v_{f1}[/tex]) + 90 = 100 + 18.75

                              80 x [tex]\displaystyle v_{f1}[/tex]   = 118.75 - 90

                                80 x [tex]\displaystyle v_{f1}[/tex] = 28.75

                                        [tex]\displaystyle v_{f1}[/tex] = 28.75 / 80

                                              = 0.36 m/s

Therefore, the final speed of the astronaut is 0.36 m/s

By newton's third law, for every action, there will be an equal and opposite reaction. Thus, the direction of the astronaut's direction will be against the direction of the tool kit thrown.

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The statement that is true about the situation where the sailboat ends up 7 miles to the west is that it describes displacement, which is a vector quantity (option A).

Displacement is the vector quantity which denotes distance with a directional component. This means that displacement is distance with direction.

On the other hand, distance is the amount of space between two points, usually geographical points, usually (but not necessarily) measured along a straight line. It is a scalar quantity, meaning that it has no direction.

This serves as the major difference between both terms: Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

According to this question, a sailboat ends up 7 miles to the west of a pier. This means that the magnitude is 7 while the direction is west of the pier, hence, it depicts displacement.

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The goalie slides on the frictionless ice at a speed of 0.076 m/s.

collision energy equals collision momentum

An object's momentum will vary as a result of a force applied for a specific length of time. In other words, an uneven force an object regardless of whether it is speeding up or slowin accelerates g down. When a force exerted against an object's motion slows it down.

The puck weighs 0.111 kg in terms of mass.

Hockey puck velocity is 55 meters per second.

Goalkeeper weight: 80 kg

Goalkeeper's speed is 0 meters per second.

Following the rule of linear momentum conservation, (0.111 kg 55 m/s) + (80 kg 0 m/s) = (0.111 kg + 80 kg) V V = (6.105 / 80.111) = 0.076 m/s (0.111 kg 55 m/s) + (0.111 kg + 80 kg) V = 0.076 m/s

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The frequency and energy of a photo of each of the colors indicated above are calculated using the formula for the frequency of light and the formula for energy in relation to Planck's constant.

In this case, the formula for energy and frequency is given as follows:

E = Hv

Where

E - Energy (in eV)

h - Planck's constant (4.1357 x 10⁻15 eVs)

v-frequency (in Hz)

v = c/λ

Where,

v - frequency (Hz)

c - speed of light (3x 10⁸) ms⁻¹

λ - wavelength (in meters)

The energy of the photon for Red light is given as follows:

E = (4.6 x 10¹⁴) (4.1357 x 10⁻¹⁵)

E = 1.902 eV

Frequency is given as:

v = [3×10⁸ms−¹] /[650x×10⁻¹⁹m]

v = 4.6 x 10¹⁴Hz

For Green light:

Energy is given as:
E = (5.4 x 10¹⁴) (4.1357 x 10⁻¹⁵)

E = 2.234 eV

Frequency is given as:
v = [3×10⁸ms−¹] /[550x×10⁻¹⁹m]

v = 5.4 x 10¹⁴Hz

For Blue light:

Energy is given as:
E = (6.6 x 10¹⁴) (4.1357 x 10⁻¹⁵)

E = 2.729 eV

Frequency is given as:
v = [3×10⁸ms−¹] /[450x×10⁻¹⁹m]

v = 6.6 x 10¹⁴Hz

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The potential difference across a 19m long, 2.0mm diameter copper wire carrying a 7.6A current is 676 V.

The resistance of the wire is given by R = ρ L/A

where ρ is the resistivity of copper (ρ = 1.72E-8 Ωm) and L is the length of the wire (19m). So,

R = 1.72E-8 * 2.0E-3/7.6E3

= 912 Ω.

Assuming that no other circuit elements are present, the potential difference across this wire will be equal to the voltage drop across that resistor:

V = IR = 912 * 7.6E3

= 676 V

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The distance between the moth and its image in the mirror is equal to the distance between the moth and your eyes, which is equal to 43.7 centimeters.

The distance from the moth to its image is 16.4 cm, which is equal to 48.8 cm, because it's a plane mirror. So, if you want to know how far away from you the moth looks like it is, just subtract 48.8 cm (the distance between your eyes) from 16.4 cm (the distance between you and the moth).

The angle between these two objects is 48 degrees,

so S = 1/2  2  sin(48)

= 0.958 meters.

Moth + Mirror (dist1) + Me (dist2) = 48 * 0.958 = 43.7 centimeters

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Answer: D

Explanation:

a. The acceleration of the system is 0.21 m/s^{2}

b. The equation of the force of friction is -

tension force - force of friction = unknown mass x its acceleration and force of friction is equal to product of coefficient of friction and                    normal force acting on unknown mass .

c.  Newton's second law of motion applies when there are unbalanced forces acting on an object. According to the second law, the mass and the net force acting on the object both affect how quickly an object is accelerating . An object's acceleration is directly proportional to the net force applied and inversely proportional to the object's mass. An object's acceleration increases as the amount of force exerted on it does. A decreasing acceleration is caused by an increase in an object's mass.

The unknown mass is nearly equal to 30 kg .

What is acceleration ?

the rate at which the speed and direction of a moving object vary over time is termed as acceleration . An object going straight ahead  when it accelerates or decelerates,  is said accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

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Roller balder will have 28,665 J gravitational potential energy at the top of a hill that is 45.0 meters high

gravitation potential energy = m*g*h

mass = 65 kg

g = 9.8 [tex]m/s^{2}[/tex]

h = 45 m

gravitation potential energy  = 65 * 9.8 * 45 = 28,665 J

Roller balder will have 28,665 J gravitational potential energy at the top of a hill that is 45.0 meters high

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The velocity of the car at point E which is  10 m is determined as 24.2 m/s.

The final velocity of the coaster car is calculated by applying the principle of conservation of energy.

total kinetic energy of the coaster = total potential energy of the coaster

K.E = P.E

-¹/₂mv₁² + ¹/₂mv₂² = -mgh

-v₁² + v₂² = -2gh

v₂² = v₁² - 2gh

where;

The given parameters include;

v₂² = v₁² - 2gh

v₂² = (28²) - (2 x 9.8 x 10)

v₂² = 588

v₂ = √588

v₂ = 24.2 m/s

Thus, the final velocity of the coaster car at the given height will be smaller than the initial velocity due to effect of gravity.

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Answer: We are unable to see the word bank please update it with a more clear bank word image.

The period of a 3.00kg object moving in a simple harmonic motion is 5.02s

Simple harmonic motion is a system where the object oscillates around the equilibrium position.

Based on the theorem, there are some formulas:

x(t) = A.cos t (ωt+∅)

x max = A

v max = Aω

a max = Aω²

ω = 2π/T = 2πf

From the question, we got some informations:

m = 3.00kg

v max = 4.00 m/s

a max = 5.00 m/s²

T = ?

We will use the formula for a max and v max to find the value of ω:

v max = Aω

v max = 4.00 m/s

Aω = 4.00 m/s ...(i)

a max = Aω²

5.00 = v max (ω)

5.00 = 4.00ω

ω = 1.25 rad/s ..(ii)

Next, we will use the Period formula:

ω = 2π/T

1.25 = 2π/T

T = 1.6π s

T = 5.02s

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It is important to look ahead during a swoop toward other jumpers in freefall because you want to be able to see where they are going, and what they are doing.

If you don't look ahead, you may not be able to avoid them correctly. Looking ahead also helps you keep an eye on your parachute and where it is about other jumpers.

Looking ahead during a swoop toward other jumpers in freefall is important because it allows you to assess the situation and make sure that you aren't going to collide with another jumper. If you don't look ahead, you might not realize that there are people above but be ensure that you aren't colliding to avoid a collision.

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Answer:

Explanation:

Given:

V₀ = 2 m/s

V = 20 m/s

Δt = 12 s

__________

a - ?

The acceleration of the van:

a = ΔV / Δt = (V - V₀) / Δt

a = (20 - 2) / 12 = 18 / 12 ≈ 1.5 m/s²

Flow doesn't depends on absolute values of P1 and P2

Flow doesn't depends on absolute values of P1 and P2 but flow depends on pressure difference between top and bottom of each sides. This conclude that whenever  { P2-P4 = P1-P3 } flow will be stop.

after some time, difference in pressure across either components is

{  P​​​​​​(Top) - P​​​​(bottom) }

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The fraction of the original kinetic energy of the bullet appears as mechanical energy in the system of block-spring-bullet is 0.72 m.

Amplitude=0.72 m

KE of system=0.5*(1.8+0.06)*8.7^2=70.39 j

Conservation of momentum

0.06*270=(1.8+0.06)*v

v=8.7 m/s

conservation energy

0.5*(1.8+0.06)*8.7^2=0.5*220*x^2+(1.8+0.06)*9.81*x

x=0.72 m

Amplitude=0.72 m

Original KE of bullet = 0.5*0.06*270^2=2187j

KE of system = 0.5*(1.8+0.06)*8.7^2=70.39 j

Amplitude in physics is stated to be the maximum displacement or distance that is moved by a factor on a body that is vibrating or wave measured from its equilibrium role.

As the pendulum swings through its equilibrium point (straight down), it swings to a maximum distance away from the center.

The amplitude of a wave is related to the amount of energy it includes. An excessive amplitude wave consists of a massive amount of power; a low amplitude wave consists of a small quantity of strength. Amplitude and intensity are associated, but not equal.

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The energy output from the car is 15125 J and the input energy is given 50000 J. Thus, the efficiency of the car is 30.25 %.

The efficiency of an engine is the ratio of its energy output to the energy input multiplied by 100. The efficiency of a heat engine can be found similarly using the input heat and output heat.

Given the mass of the car is 1000 Kg and it is accelerated to 5.5 m/s. Therefore the kinetic energy output is is calculated as follows:

KE = 1/2 mv²

     = 1/2  1000 kg × (5.5 m/s)²

     =  15125 J

The input energy is 50000 J. Therefore, the energy efficiency is :

efficiency = output energy / input energy × 100

                = ( 15125 J/ 50000J ) × 100

                = 30.25 %

Hence, the energy efficiency of the car is 30.25 %.

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The greater amount of energy is transferred during the first case and the difference in energies is: 84 × 10³ J

Internal energy refers to all energy within a particular system, including the kinetic energy of molecules and the energy stored in chemical bonds between molecules. The interaction of heat, work, and internal energy involves the transfer and conversion of energy whenever a change is made to the system.

The amount of heat (Q) gained or lost from the sample can be calculated using the formula Q = mcΔT. where m is the mass, c is the specific heat, and ΔT is the temperature change.

For the first case:

Q = mcΔT

Q = mc(T₁ - T₂)

m = 1 kg or 1000 g

c =  4.2 J g⁻¹/°C

T₁ = 10 °C

T₂ = -15 °C

Q₁ = 1000 × 4.2 × (10 -(-15))

Q₁ = 105 × 10³ J

For the second case:

Q = mcΔT

Q = mc(T₂ - T₁)

m = 1 kg or 1000 g

c =  4.2 J g⁻¹/°C

T₁ = 60 °C

T₂ = 65 °C

Q₂ = 1000 × 4.2 × (65 - 60)

Q₂ = 21 × 10³ J

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