A 10 kg object is on a movable platform. Rank the size of the normal force acting on the object from largest to smallest.
a) The object is at rest and the platform is not moving

b) the object is at rest on the stationary platform and there is a downward force of 10N applied to the top of the object while it remains stationary

c) the object is at rest on the stationary platform and there is an upward force of 10N applied to the top of the object while it remains stationary

d) the platform is accelerating the object upward at 1.5 m/s^2

e) the platform is accelerating the object downward at 0.5 m/s^2

Answer:

13.02 m/s

Explanation:

First, convert the units of kilometer and hours into meter and second. This can be done by multiplying 150 with 1000 since a kilometer equals 1000 meters. This’ll get us the new unit of 150,000 meters.

Then convert 3.2 hours to second by firstly multiplying 3.2 with 60. This’ll get us with 192 minutes since an hour equals 60 minutes. Then multiply 192 by another 60 because a minute equals to 60 seconds. You’ll obtain the new unit of 11520 seconds.

Next, we can now apply the basic velocity formula which is:

[tex]\displaystyle \vec v = \dfrac{\vec s}{t}[/tex]

Where [tex]\vec v[/tex] is velocity, [tex]\vec s[/tex] is displacement and [tex]t[/tex] is time. In this scenario, assume that the car travels in linear path - this means that the displacement equals to distance. Therefore, from the information we have, we can conclude that:

Apply in the formula to find velocity:

[tex]\displaystyle {\vec v = \dfrac{150000}{11520}}\\\\\displaystyle{\vec v \approx 13.02 \ \, \sf{m/s}}[/tex]

Therefore, our velocity is approximately 13.02 m/s

answer -

7 m/s^2

Explanation:

it goes 7m/s 14 / 2 = 7

The Maximum tangential speed the ball can have would be = 5.3m/s.

A tangential speed is defined as the speed of an object that has an angular velocity with respect to an instantaneous velocity.

The formula used to calculate the maximum tension;

T = mv²/r

Where T = Maximum tension = 132.3N

M = mass= 4kg

r = radius = 0.86m

V= tangential speed = x

Make v the subject of formula;

V = √Tr/m

V = √ 132.3 × 0.86/4

V = √113.778/4

V= √28.4445

V = 5.3 m/s.

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Complete question:

An athlete swings a 4.00 kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.860 m at an angular speed of 0.660 rev/s. If the maximum tension the rope can withstand before breaking is 132.3 N, what is the maximum tangential speed the ball can have?

Convection is the method which occurs in a refrigerator

Convection is used in a refrigerator's system to remove heat from the freezer and refrigeration compartments and send it outside the appliance. The process of convection involves the transfer of heat through the movement of material, typically a gas or a liquid.

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The acceleration of the sled of combined mass 62.5 kg is 1.018 m/s².

Acceleration is the rate of change of velocity.

To calculate the acceleration of the sled, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the acceleration of the sled is 1.018 m/s².

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The time taken for the bowling ball to stop, given that a force of 38 N was applied is 0.55 s

We'll begin by obtaining the deceleration of the ball. This can be obtained as follow:

Force (F) = mass (m) × deceleration (a)

F = ma

Divide both sides by m

a = F /m

a = 38 / 6.9

a = -5.5 m/s²

Finally, we shall determine the time. This is shown below:

a = (v – u) / t

-5.5 = (0 – 3) / t

-5.5 = -3 / t

Cross multiply

-5.5 × t = -3

Divide both sides by -5.5

t = -3 / -5.5

t = 0.55 s

Thus, we can say that the time required is 0.55 s

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Answer:

The first one is the right answer

Explanation:

This is because a period is only completed when there is the completion of only one oscillation

26.83 Newton Force is the resultant of the two forces. ​

F1= 12 N

F2=24 N

resultant force= [tex]F_r= \sqrt{F_1^2+F_2^2+2F_1F_2cos \alpha}[/tex]

angle=90°

[tex]F_r= \sqrt{(12)^2+(24)^2+2(12)(24)(cos 90)}[/tex]

[tex]{:[=\sqrt(144+576+0)],[=\sqrt720],[=26.83N][/tex]

The resultant force is the total force acting on the object or body along with the direction of the body. The resultant force is 0 when the object is at rest or traveling at the same speed as the object. Given that each force is acting in the same direction, their aggregate force ought to be equal.

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The greatest energy or the greatest extension from its equilibrium positions is equal to 0.12 J.

Mechanical energy is the sum of potential energy and kinetic energy that is used to do work. Mechanical energy defines the energy of a system because of its motion or position.

The total mechanical energy is conserved as we know the energy can neither be created nor destroyed. The mechanical energy of a system can only be changed from one form to another whenever the forces used to do work are conservative in nature.

The energy is stored in the form of potential energy in a compressed string.  If the elastic potential energy is changed into kinetic energy as it is used to accelerate the mass.

The total mechanical energy required to compress the spring is the maximum amount of elastic potential energy stored in the spring. The greatest energy of the spring will be at the maximum displacement. Therefore, the spring will have the greatest potential energy at equilibrium positions equal to 0.12 J.

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Answer:

Explanation:

Mass of disk = 0.14 kgSpring constant = 155 N/mLength = 4 cmWe need to calculate the speed Using energy conservationWhere, k = spring constantx = compressed lengthm = mass of the discPut the value into the formulaHence, The speed with which the disk slides across the surface is 1.33095 m/s.

Answer:

B

Explanation:

If you try the experiment yourself, You will see that a hot piece of metal has and sustains that thermal energy until that piece of metal eventually cools off.

On the other hand, it takes a while for the cold piece of metal to heat up. So, therefore, it does not contain thermal energy for that long period until it is thoroughly heated up.

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The correct statement about the right ascension is "it is 3 hours to the east of zero hours right ascension.

option C is the correct answer

The right ascension of stars is the astronomical equivalent of longitude.

Right ascension is also the angular distance of the star measured eastward from the first point of Aries, also called the Vernal Equinox.

In other words, the right ascension describes how far a star is displaced from a given point towards the eastward direction along the longitude.

Lines of longitude runs from east to west. But the right ascension runs towards the east.

Thus, the correct statement describing the right ascension would measure it towards the east.

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Answer:

A. The maximum is 8cm. B. 5 pieces of wire.

Explanation:

To find each pieces' length we need to find what can divide both wires = 8cm

A. The maximum is 8cm.

The amount of pieces = 16m/8m = 2 pieces and 24m/8m = 3 pieces. 2 pieces + 3 pieces = 5 pieces of wire.

B. 5 pieces of wire.

Jovian planets are less dense than terrestrial planets.

The Jovian planets lack solid surfaces, in contrast to the terrestrial planets that make up our inner solar system—Mercury, Venus, Earth, and Mars. They are made mostly of hydrogen and helium instead, with minute amounts of other gases like methane, ammonia, water, and others in their atmospheres.

Terrestrial planets formed from metal and rock-based planetesimals, but they were ultimately too small to hold much of the solar nebula's rich hydrogen and helium gas. The Jovian planets, on the other hand, originated distant from the Sun where there were abundant ices and rocks.

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According to the given statement The ball's velocity just before it stopped was  8.0 m/s.

The correct option is B.

The rate at which velocity and speed change over time is referred to as acceleration. When anything moves faster or slower, it is said to be accelerating or decelerating in a straight line. Even if the speed remains constant, moving in a circle quickens because the direction is always changing.

A increase in an object's orientation or speed is referred to as acceleration. Acceleration is the term for the pace at which speed changes. Don't forget that velocity is made up of two components: direction and speed.

The definition of acceleration comes first

a = v[tex]_f[/tex] - v[tex]_o[/tex] /t

2 = v[tex]_f[/tex]- 0/4

v[tex]_f[/tex]= 8 m/s

After 4 seconds, the ball will be moving at a speed of 8 m/s.

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Using a free body diagram to explain the situation,  the acceleration of the block decreased because of force of friction acting in opposite direction reducing the net force on the block and consequently the acceleration of the block.

The net force on an object is the sum of all the forces acting on an object.

According to Newton's second law of motion, the net force on an object is directly proportional to the product of mass and acceleration of the object.

F(net) = ma

F - Ff = ma

where;

In the absence of friction force, the maximum acceleration of the block is calculated as;

a = F/m

a = 40 N / 10 kg

a = 4 m/s²

In the presence of friction force, the net force will decrease and the acceleration of the block will decrease as well.

In free body diagram (FBD) this can be represented as;

F →       Ф     ← Ff

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Statement is accurate C. You would weight more on planet A because the distance between you and the planet's of center of gravity would be smaller.

You would weigh less on planet A due to a closer proximity to the planet's center of gravity, which is the statement that best represents your weight on each planet.

According to Newton's rule of universal gravitation, "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them,"

Given that weight is a function of both mass and gravity, objects on planets with stronger gravitational pull will have heavier masses.

The weight will be lighter since there is less space between the individual and the planet's center.

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A race car is traveling in a uniform circular motion around a race track, the radial acceleration of the car when the velocity is doubled and the radius of the circle is halved will increase by a factor of 8 (Option D)

To arrive at the above conclusion, we must recall that radial acceleration is defined by:

Ac = v²/r; where

Ac - is the magnitude of radial acceleration

v -  is the linear or tangential speed

r - is the radius of the circular path

A′c -  is the new magnitude of the radial acceleration.

Given that the linear velocity is duplicated and simultaneously the radius is split in two, then the new radial acceleration increases by a factor of 8, according to the following calculation:

A'c = (2v²)/(0.5r)

= 4v²/(0.5r)

= 8 · (v²/r)

= 8 · Ac

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Full Question:

A race car is traveling in a uniform circular motion around a race track what happens to the radial acceleration of the car if the velocity is doubled and the radius of the circle is halfed?

A. It remains the same.

B. It increases by a factor of 2.

C. It increases by a factor of 4.

D. It increases by a factor of 8.

E. It decreases by a factor of 2.

If N placed one of these on top of item M, the acceleration when M is dragged by a force od 20 N is 10 m/s. N weighs 2 kg, but M is 4 kg in weight.

The correct answer is D

Acceleration is the rate at which the direction and speed of a moving object change over time. Anything is said to be accelerated when it goes straighter and faster or slower. Therefore, even though the speed is constant, travel on a circle increases due to the constant change in direction.

Slow acceleration can be dangerous as well as unpleasant, especially when entering a busy state road when you must accelerate rapidly to avoid being rear-ended. When you are moving slowly up a slope while driving, acceleration can sometimes be a hassle.

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The options that correctly identifies the missing terms, in order of their

appearance in the sentences are as follows:

The initial horizontal velocity of the box dropped from the airplane is equal to the horizontal velocity of the airplane.

The velocity of the airplane is 50 m/s

Hence, the horizontal velocity of the box is also 50m/s.

The box falls freely under the effect of gravity. Hence, the acceleration in the vertical direction will be equal to the acceleration due to gravity.

The time taken by the box to reach the ground is calculated  from the formula below as follows:

t = √(2h/g)

where;

t is the time taken to reach the ground

h is the vertical height above the ground = 40 m

g is the acceleration due to gravity = 9.8 m/s²

t = √(2 * 40 / 9.8)

t = 2.86 seconds

The horizontal distance traveled by the box = 2.86 s * 50 m/s

The horizontal distance traveled by the box = 143 m

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The wavelength of the wave is 3m and the speed of the wave is  15 m/s

We define a wave as a disturbance that occurs along a medium and leads to the transference of energy from one point to another. As we can see the energy in this case is transferred along the length of the string. We know that the wavelength is the distance between the two successive crests or troughs.

Now we know that the distance between the two successive crests as we can see is the wavelength of the wave and this is shown the length that have been designated as d and we thus have the wavelength as 3m.

Again we have;

v = λf

v = speed of the wave

f = frequency of the wave

λ = wavelength of the wave

Then;

v = 3 m * 5 Hz

= 15 m/s

Thus the wave speed is obtained as 15 m/s.

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Answer:

yes

Explanation:

Because doubting is thinking something is

wrong

The distance of this star in kilometers is equal to 5.64 × 10¹⁸ kilometers. Also, the distance of this star in light-years is equal to 626.67 light-years.

Mathematically, the inverse square law for light can be used for calculating its luminosity at a distance by using this mathematical expression:

d = √(L/4πF)

Where:

Substituting the given parameters into the formula, we have;

Distance in kilometers, d = √(6.0 × 10²⁶/4 × 3.142 × 1.5 × 10⁻¹²)

Distance in kilometers, d = √(6.0 × 10²⁶/1.885 × 10⁻¹¹)

Distance in kilometers, d = √3.183 × 10³⁷

Distance in kilometers, d = 5.64 × 10¹⁸ kilometers.

For the distance in light-years, we would divide the distance in kilometers by 9.0 × 10⁻¹⁵:

Distance in light-years = 5.64 × 10¹⁸/9.0 × 10¹⁵

Distance in light-years = 626.67 light-years.

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Answer: 14.41*10^2 m/s

Explanation:

let, V be the escape velocity of the moon.

M be the mass of the earth.

r be the distance between the moon and the earth.

G be the universal gravitational constant.

And G = 6.67428*10^-11 m^3kg^-1 s^-2

here, given in the question that

The earth has a mass of 5.98*10^24 kg.

so, M = 5.98*10^24 kg.

And the distance from the earth to the moon is 3.84*10^8 m.

so, r = 3.84*10^8 m.

now, we know,

V = √2GM/r

V = √(2 * 6.67428*10^-11* 5.98 * 10^24 )/ 3.84*10^8

V = √79.82*10^13/3.84*10^8

V = √20.78*10^5

V = 14.41*10^2 m/s

The net force on the electron is F = 1X10-13 N.

The mass of the electron is m = 1X10-30 kg.

The distance covered by an electron is S = 10 cm.

The acceleration of an electron can be calculated as:

F = ma

a = F/m

Substitute the values in the above expression.

[tex]a = (\frac{1 * 10^{-13}N }{1* 10^{-30kg} } ) \\[/tex]

a = [tex]1*[/tex][tex]10^{-17} m/s^{2}[/tex]

Thus. the acceleration of the electron is. [tex]a = 1*10^{-17} m/s^{2}[/tex]

The expression of time taken by the electron is given by,

S = ut + [tex]\frac{1}{2} at^{2}[/tex]

Here, u is the electron's initial velocity, whose value is zero because the electron is initially at rest.

Substitute the values in the above expression.

(10cm x 1m/100cm) = 0 x t + 1/2 x (1 x [tex]10^{17}[/tex] m/s²) x t²

(0.1m) x 2 = (1 x [tex]10^{17}[/tex] m/s²)x t²

[tex]t = \sqrt{\frac{0.2m}{(1*10^{17} m/s^{2} )} }[/tex]

t = 1.414 x [tex]10^{-9}[/tex]s

Thus, the time taken by the electrons to be accelerated from rest is t = 1.414 x [tex]10^{-9}[/tex]s

Electrons are accelerated from rest by a potential difference of V volts. The speed of individual electrons in metal wires is typically millions of kilometers per hour. In contrast, drift velocities are typically only a few meters per hour, while signal velocities are 100 million to 1 billion kilometers per hour.

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a. The plane traveled 2626.60 km north

b. The plane traveled 2323.81 km west

Since the airplane is traveling 835 km/h in a direction 41.5 ∘ west of north, weresolve it into its component velocity vector.

So, its velocity, V = -(835 km/hsin41.5°)i + (835 km/hcos41.5°)j

= -(835 km/h × 0.6626)i + (835 km/h × 0.7490)j

=  -(553.29 km/h)i + (625.38 km/h)j

Now the speed of the plane in the north direction is the j component which is 625.38 km/h.

Since the plane traveled 4.20 h, The distance travelled is d = speed × time = 625.38 km/h × 4.20 h

= 2626.60 km

So, the plane traveled 2626.60 km north

Also, the speed of the plane in the west direction is the i component which is 553.29 km/h.

Since the plane traveled 4.20 h, The distance travelled is d = speed × time = 553.29 km/h × 4.20 h

= 2323.81 km

So, the plane traveled 2323.81 km west

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The total equivalent resistance of the circuit which consists of 4 resistors ( 1202, 180, 320 and 3802 ) connected in series is 50.1 KΩ

Resistance of resistor,

Total equivalent resistance, R = R1 + R2 + R3 + R4

R = 12000 + 18 + 32 + 38000

R = 50.1 KΩ

Equivalent resistance is a another way of indicating total resistance. The equivalent resistance will be of a single resistor that replaces the total network without altering any effect on the system.

Therefore, the total equivalent resistance of a series circuit consists of 4 resistors connected in series: 1202, 180, 320, and a 3802 is 50.1 KΩ

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The maximum height reached by the cylinder at the given initial velocity is 0.2 m.

The maximum height travelled by the cylinder is calculated by applying the following kinematic equation as shown below.

v² = u² - 2gh

where;

At maximum height, the final velocity of the cylinder = 0

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (2²) / (2 x 9.8)

h = 0.2 m

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Answer:

A.0

Explanation: