[tex]\boxed{\sf K.E=\dfrac{1}{2}mv^2}[/tex]
[tex]\\ \sf\longmapsto 18750=\dfrac{1}{2}2100v^2[/tex]
[tex]\\ \sf\longmapsto 18750=1050v^2[/tex]
[tex]\\ \sf\longmapsto v^2=\dfrac{18750}{1050}[/tex]
[tex]\\ \sf\longmapsto v^2=17.85m^2[/tex]
[tex]\\ \sf\longmapsto v=\sqrt{17.85}[/tex]
[tex]\\ \sf\longmapsto v=4.1m/s[/tex]
1. A car travels a distance of 200 m in 4 seconds. What is the velocity of the car?
Answer:
50m/s
Explanation:
here;
distance travelled(s): 200m
time taken(t): 4s
now
velocity(v): s/t
= 200/4
Velocity: 50m/s#
a constant force acting on a body of mass 4kg changes its velocity from 2m/s to 4m/s in 4s. what is the force?
Answer:
2 Newton
Explanation:
from newton second law
F = ma
as we have the mass equals 4 kg
we need to get the acceleration which will be change in velocity over change in time
a = ∆V/∆t = (4-2)/4 = 0.5
so F = 4 * 0.5 = 2
Answer:2N
Explanation:
It takes Stu, a slimy slug, 20 minutes to travel from his favorite bush to the local trash can (a trip of 30 meters), how far can he travel in 1 hour (60 minutes)?
Answer:
It take him 1 hour to travel 90 meters
Explanation:
Answer:
90 m
Explanation:
30 ÷ 20 = 1.5 m/min x 60 min = 90 m
When is the car exceeding a 10 km/hr speed limit?
If the car travels a distance greater than 10 km in one hour or less than one hour, it has exceeded the speed limit.
The given parameter:
speed limit = 10 km/hour
To find:
when the car will exceed the speed limitSpeed is defined as the total distance traveled divided by the total time taken for the journey.
[tex]speed = \frac{distance}{time}[/tex]
If the car travels any distance greater than 10 km in 1 hour or less than 1 hour, it has exceeded the speed limit of 10 km/hr.
For example, let's say the distance traveled by the car in one hour is 11 km. The speed of the car is 11 km/hr which is greater than the speed limit.
Thus, we can conclude that if the car travels a distance greater than 10 km in one hour or less than one hour, it has exceeded the speed limit.
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The speed of an object undergoing constant acceleration increases from 8.0 meters per second to 16.0 meters per second in 10. seconds. How far does the object travel during the 10. seconds?
Answer:
[tex] \boxed{d = 120\: meters} [/tex]
Explanation:
Given:
[tex] v_{0} [/tex] = 8.0 m/s[tex] v [/tex] = 16.0 m/s[tex] t [/tex] = 10 seconds[tex] d [/tex] = ?We can use this equation with the variables given to solve:
[tex] d \: = \frac{t \: (v + v_{0})}{2}[/tex] →
[tex] d \: = \frac{(10s) \: ((16.0 \: m/s) + (8.0 \: m/s))}{2} [/tex] →
[tex] d \: = \frac{(10s) \: (24 \: m/s)}{2} [/tex] →
[tex] d \: = \frac{(10 \: s \: • \: 24 \: m/s)}{2} [/tex] →
[tex] d \: = \frac{240 \: m}{2} [/tex] →
[tex] d \: = 120 \: m [/tex]
The distance traveled by the object in 10 seconds is 120 meters.
Given to us,
Final velocity of the object, [tex]v= 16\ meter/sec[/tex]
Initial velocity of the object, [tex]u= 8\ meter/sec[/tex]
Time for traveling, [tex]t= 10\ sec[/tex]
Using the first equation of motion, we can find out acceleration of the object [tex]a[/tex],
[tex]v=u+at\\16=8+a\times 10\\a= 0.8\ meter/sec^2[/tex]
Now using the second equation of motion and putting the value of [tex]a[/tex],
The distance[tex](S)[/tex] traveled by the object ,
[tex]\begin{aligned}S&= ut+\frac{1}{2}at^2\\&= 8\times 10+ \frac{1}{2}\times 0.8\times 10^2\\&= 120\ meters \\\end{aligned}[/tex]
Hence,The distance traveled by the object in 10 seconds is 120 meters.
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What is electrical energy
Answer:
Electric is produce by water it is very helpful in our life
¿Qué cantidad de calor absorbió una masa de 4 g de cinc al pasar de 20 °C a
180 °C?
(amount of heat)Q = ? , (Mass) m= 4 g , ΔT = T f - T i = 180 c° - 20 °c = 160 °c ,
Ce = 0.093 cal/g. °c
Q = m C ΔT
Q = 4 g × 0.093 cal/g.c° × ( 180 °c- 20 °c )
Q= 4×0.093 × 160
Q = 59.52 cal
I hope I helped you^_^
Choose the correct term to complete each blank.
It is (Harder/easier) to push an empty wheelbarrow than one filled with dirt. Because the dirt-filled wheelbarrow has more (Force/Speed/Mass) than the empty one, it requires more (Force/Inertia/Acceleration) to push at the same speed. A wheelbarrow containing grass clippings will require (More/Less/The Same) force to push at the same speed than a dirt-filled one because the grass clippings have less mass than dirt. Either wheelbarrow will require more force to push it uphill than downhill due to the effect of
(Friction/Inertia)
Explanation:
It is (Harder/easier) to push an empty wheelbarrow than one filled with dirt. Because the dirt-filled wheelbarrow has more (Force/Speed/Mass) than the empty one, it requires more (Force/Inertia/Acceleration) to push at the same speed. A wheelbarrow containing grass clippings will require (More/Less/The Same) force to push at the same speed than a dirt-filled one because the grass clippings have less mass than dirt. Either wheelbarrow will require more force to push it uphill than downhill due to the effect of (Friction/Inertia)
URGENT // PHYSICS
Match each measurement with the correct example.
distance
[ Choose ]
displacement
[ Choose ]
speed
[ Choose ]
velocity
[ Choose ]
acceleration due to gravity on Earth
[ Choose ]
net force
[ Choose ]
weight
[ Choose ]
acceleration
[ Choose ]
Choices :
75 m/s upwards ; 22 Newtons to the left ; 2 m/s^2 9.8 m/s^2 or 9.81 m/s^2 ; 128 m/s^2 West ; 14 meters ; 45 mph ; 125 kilometers South ; 14 newtons down
distance- 14 meters
displacement- 125 kilometers South
speed- 45 mph
velocity- 75 m/s upwards
acceleration due to gravity on the earth- 9.8 m/s^2
net force- 22 Newtons to the left
weight- 14 Newtons down
acceleration- 128 m/s^2 West
Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.
What is Velocity?Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.
Velocity → 75 m/s upwards
Velocity is the ratio of displacement and time, therefore, it has magnitude as well as direction.
Net force → 22 Newtons to the left
Force is measured in Newton and can be in any direction
Acceleration due to gravity on Earth → 9.8 m/s^2 or 9.81 m/s^2
It is the general value of Acceleration due to gravity on Earth.
Acceleration → 128 m/s^2 West
Acceleration is measured in meters per second square.
Distance → 14 meters
Distance is measured in meters, feet, cm, km, etc.
Speed → 45 mph
Speed is the ratio of distance and time.
Displacement → 125 kilometers South
Displacement has magnitude and direction both.
Weight → 14 newtons down
Weight is also a force but it is in the downward direction.
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Suppose your friend mistakes a yardstick for a meter stick and measures the length of an intersection in your neighborhood. Is this error random or systematic? Which of these types of errors affect precision or accuracy?
How do you find the uncertainty of a meter stick?
Thus, L =5 . 7 cm measured with a meter stick implies an uncertainty of 0.05 cm. A common rule of thumb is to take one-half the unit of the last decimal place in a measurement to obtain the uncertainty
A car has a velocity of 10m/s.it now accelerated to 1m for 0.25min.find d distance travelled
Answer:
the answer is 13.33 m/s²
) A jeep starts from the state of rest. If its velocity becomes 60 km/hr in 5 minutes, (i) What is the acceleration of the jeep? (ii) What is the distance covered by the jeep? (Ans: 0.056 m/s", 2500 m)
Answer:
Ans: a=0.056ms^-2 S=2500m
Explanation:
vi=0ms^-1
vf=60km/hr= [tex]\frac{60*1000}{3600}[/tex]=16.6ms-1
a=[tex]\frac{vf-vi}{t}[/tex]
=[tex]\frac{16.6-o}{5*60}[/tex]
a=0.056ms^-2S=?S=vit+[tex]\frac{1}{2}[/tex][tex]at^{2}[/tex]
S=0+[tex]\frac{1}{2}[/tex]*0.056*[tex](300)^{2}[/tex]
S=2500mI just got asked a question about quantum entanglement. Can someone please give me a basic understandable of what it is
In physics, what is the positive and negative sign used for when applied to velocity and acceleration?
Answer:
Opposite direction
Explanation:
For example: The first object travels in the direction pointing to east, while the other one travels pointing to the west.
The first object will have a positive value while the second one will have a negative, cause it's going to the opposite direction
A car moves with constant speed and then constant acceleration
Which graph is the speed-time graph for the car?
Answer:
You have no graph on the post.
Help 100 points ixl! Need it due in 10 minutes!
She travelled in one third of time=160km
Total distance=160×3=480km
Time=6h
[tex]\\ \bull\tt\dashrightarrow Velocity=\dfrac{Displacement}{Time}[/tex]
[tex]\\ \bull\tt\dashrightarrow Velocity=\dfrac{480}{6}[/tex]
[tex]\\ \bull\tt\dashrightarrow Velocity=80km/h[/tex]
Answer: 160km
Explanation:
Ms. Reitman's scooter starts from rest and accelerates at
2.0 m/s2. What is the scooter's velocity after 7 s?
Answer:
14 m/s
Explanation:
a = v/t
subbing in:
2 = v/7
v = 14 m/s
PLS FAST WILL GIVE BRAINLIEST Describe why atoms can be neutral when they contain charged subatomic particles.
Answer:
Atoms are neutral if they have the same number of charged protons and electrons, balancing positive and negative charges. As long as the numbers of electron and protons are the same, the charges will balance.
If a line has a slope of 2 and a
rise of 12 what was the run
Which of the following is an example of an indirect tax?
Answer:Sales tax, value-added tax, excise tax, and customs duties are examples of indirect taxes.
Explanation:
i just need x isolated
Answer:
[tex]x=\frac{-y+\sqrt{y^2+4rt} }{2r}[/tex]
[tex]x=\frac{-y-\sqrt{y^2+4rt} }{2r}[/tex]
Explanation:
[tex]rx+y=\frac{t}{x}\\\\x(rx+y)=(\frac{t}{x})x\\\\rx^2+yx=t\\\\rx^2+yx-t=t-t\\\\rx^2+yx-t=0[/tex]
Solve using the quadratic formula.
[tex]x=\frac{-y+\sqrt{y^2+4rt} }{2r}[/tex]
[tex]x=\frac{-y-\sqrt{y^2+4rt} }{2r}[/tex]
Answer:
x=-y+[tex]\sqrt{[/tex]y^2+4rt/2r
Explanation:
solve using the quadratic equation
What is a primary source?
A.A textbook that explains a wide range of science topics
B.A technical article written by an experimenter
C.A newspaper article about a recent discovery
D.A summary of research written for an average reader
Answer:
Explanation:
B
A primary source is one that is written by the person who lived through an advenure or is one doing the action and recording it.
In this case, the answer is B.
Most frequently, for a historian, a primary source is something like a diary or a bunch of letter written by someone experiencing something.
It cannot be about someone else's work. Not C or D
A textbook is not the answer either. It is a bulky summary of scientific, or other kind of thought.
xy+4z=
X=2
Y=2
Z=3
Solve for
Answer:
x×y=2×2=4. 4×z=4×3=12. 4+12=16
Some expressways are curved, banked and designed to maximize ___________ at higher speeds.
Acceleration
Safety
Traffic
Conflict
Answer:
Safety
Explanation:
Expressways are banked to resist centifugal action
NEED HELP RN!!
All scientist use the scientific method 1 point True False
Answer:
True
Explanation:
It is true because scientists must use this method to get a correct and accurate solution.
7. MANSON'S FAVORITE SINGING GROUP WAS...
O THE TEMPTATIONS
O THE BEACH BOYS
O THE ROLLING STONES
O THE BEATLES
Example #4: Mrs. Smith is going on vacation to Greece for
her anniversary and the weather is predicted to be 27 °C.
Mrs. Smith lives in the U.S. Though and doesn't know what
to pack for this weather. Help her determine the
temperature in F so she can pack.
Answer:
The temperature is [tex]$80.6$[/tex] degrees Fahrenheit.
Explanation:
The weather is predicted to be 27 °C.
[tex]c=\frac{5}{9}(F-32)[/tex]
[tex]27=\frac{5}{9}(F-32)[/tex]
[tex]$5(F-32)=243$[/tex]
[tex]$F-32=\frac{243}{5}$[/tex]
[tex]$F-32+32=\frac{243}{5}+32$[/tex]
[tex]$F=\frac{403}{5}$[/tex]
[tex]F=80.6[/tex]
The temperature is [tex]$80.6$[/tex] degrees Fahrenheit.
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a crane gradually lifts a car with a mass of 1000kg at constant speed to height of 5cm. Calculate the potential energy of the car at that height.
Answer:
490.5
Explanation:
Formula
U = mgh
= 1000 x 9.81 x 0.05m
= 490.5
partes son de un estadio de futbol
Las dos líneas más largas del terreno de juego se denominarán líneas de banda. Las dos más cortas se llamarán líneas de meta. El terreno de juego será rectangular y la longitud de las líneas de banda deberá ser mayor que las de las líneas de meta. La longitud de la línea de banda debe tener como mínimo 90 metros y como máximo 120 metros. La anchura de la línea de meta debe de tener como mínimo 45 metros y como máximo de 90 metros. Todas las líneas del terreno de juego deberán se líneas continuas y tener la misma anchura, como máximo 12 cm., menos las líneas de meta que deben tener la misma anchura que los postes y larguero de la portería. Todas las líneas que delimitan al campo forma parte del terreno de juego. El terreno de juego puede ser de tierra, césped natural ó césped artificial de color verde según las normas del reglamento de la competición. El terreno de juego está dividido en dos partes iguales por una línea que unirá los puntos medios de las dos líneas de banda. El centro del campo estará marcado con un punto situado en la mitad de la línea media que divide las dos partes iguales del campo, tomando este punto como centro, haremos circulo de un radio de 9,15 metros. También se puede poner un banderín en cada extremo de la línea de media, a una distancia mínima de 1 m al exterior de la línea de banda.
If ball A rolls off a 50 cm high table at the same instant that ball B rolls off a 75 cm high table, which will hit the ground first?
ball a
Explanation,
Hope it helps
