A centrifuge in a medical laboratory rotates at an angular speed of 3,750 rev/min. When switched off, it rotates through 48.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s²) of the centrifuge.


______rad/s²

Answers

Answer 1

The constant angular acceleration (in rad/s²) of the centrifuge is 255.66 rad/s².

Constant angular acceleration of the centrifuge

The constant angular acceleration of the centrifuge is calculated as follows;

ωf² = ωi² - 2αθ

where;

ωf is the final angular velocity ωi is initial angular velocityθ is angular displacementα is angular acceleration

When the centrifuge is switched off, the final angular velocity = 0

Initial angular velocity: ωi = 3,750 rev/min x 2π rad/rev x 1 min/60 s = 392.7 rad/s

angular displacement: θ = 48 rev = 48 rev x 2π rad/rev = 301.6 rad

0 = ωi² - 2αθ

2αθ = ωi²

α = ωi²/2θ

α = (392.7²) / (2 x 301.6)

α = 255.66 rad/s²

Thus, the constant angular acceleration (in rad/s²) of the centrifuge is 255.66 rad/s².

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Related Questions

The technology in the picture produces which energy conversion?
O A. Light energy to electrical energy
• B. Thermal energy to kinetic energy
C. Chemical energy to kinetic energy
D. Kinetic energy to electrical energy

Answers

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

Option D

[tex]\textsf{ \underline{\underline{Explanation} }:}[/tex]

The given picture shows a dam, and as we know dam ises water current to produce electricity. as the water current has high kinetic energy, so when it hits and rotates the turbine, the generator produces electricity.

Hence, the correct option will be :

❖ D. Kinetic energy to electrical energy

the apparent weight of a student in alift is 564N . if the mass of the student is 60.3kg, what is the acceleration of the lift ? use negative is the acceleration vector is pointing downwards

Answers

Answer:

-.457 m/s^2

Explanation:

Actual weight =   60 .3 (9.81) = 591.54 N

Accel of lift changes this to    60.3 ( 9.81 - L)     where L - accel of lift

                                           60.3 ( 9.81 - L ) = 564

                                               solve for L = .457 m/s^2  DOWNWARD

                                                        so L = - .457 m/s^2

A coin is placed next to the convex side of a thin spherical glass shell having a radius of curvature of 17.0 cm. Reflection from the surface of the shell forms an image of the 1.5-cm-tall coin that is 6.50 cm behind the glass shell.
a) Where is the coin located?
b) Determine the size of the image.

Answers

(a) The position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

(b) The size of the image is 1.8.

Position of the coin

The position of the coin placed next to the convex side of a thin spherical glass shell is calculated as follows;

1/d = 1/f - 1/d'

where;

d' is the position of the coin's imaged position of the coinf is focal length

Focal length = r/2 = 17 cm / 2 = 8.5 cm

1/d = 1/8.5 - (-1/6.5)

1/d = 1/8.5 + 1/6.5

1/d = 0.1176 + 0.1538

1/d = 0.2714

d = 1/0.2714

d = 3.68 cm

Size of the image

Magnification, M = d'/d

M = (6.5)/(3.68)

M = 1.8

Thus, the position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

The size of the image is 1.8.

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In a truck-loading station at a post office, a small 0.200 kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m (Figure 1). The size of the package is much less than 1.60 m, so the package can be treated as a particle. It slides down the track and reaches point B with a speed of 4.80 m/s. From point B, it slides on a level surface a distance of 3.00 m to point C, where it comes to rest.
A). What is the coefficient of kinetic friction on the horizontal surface?
b How much work is done on the package by friction as it slides down the circular arc from A to B ?

Answers

The coefficient of kinetic friction on the horizontal surface, μ = 0.39.

The work done on the package by friction as it slides down the circular arc from A to B, W = -4.176.

What is the frictional force acting on the package moving on the track?

Frictional force is the force which opposes the motion of an object over another.

Frictional force acts at the surface of contact of the objects.

The frictional force, F is related to the coefficient of kinetic friction on the horizontal surface, μ, and the normal reaction or weight, mg,  of the package as follows:

F = μmg

Work done against friction, W = F * d

W = μmgd

The Kinetic energy of the package is equal to the work done against friction.

Kinetic energy of the package = mv²/2

μmgd = mv²/2

μ = v²/2gd

μ = 4.8²/(2 * 9.81 * 3)

μ = 0.39

b. Work done on the package by friction as it slides down the circular arc from A to B is given as follows:

W = mv²/2 - mgh

W = v²/2 - gh

W = 4.8²/2 - 9.81 * 1.6

W = -4.176

In conclusion, the work done by friction is lost in the form of heat.

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An object with a mass of m = 122 kg is suspended by a rope from the end of a uniform boom with a mass of M = 74.9 kg and a length of l = 8.77 m. The end of the boom is supported by another rope which is horizontal and attached to the wall as shown in the figure.
Calculate the tension in the horizontal rope. (The horizontal and the vertical ropes are not connected to each other. They are both independently attached to the end of the boom.)

Answers

The the tension in the horizontal rope is 7,019.4 N.

What is tension?

Tension is described as the pulling force transmitted axially by the means of a string, a cable, chain, or similar object, or by each end of a rod.

Tension can also be described as the action-reaction pair of forces acting at each end of said elements.

The unit of tension is Newton (same unit as force, since tension is also a force).

Tension in the horizontal rope

The tension in the horizontal rope is calculated as follows;

Apply the principle of torque;

T(L/2) cosθ = Mg (L/2) sinθ + mg L sinθ

T = (M + 2m)g sinθ/cosθ

T =  (M + 2m)g tanθ

let θ = 66⁰ (this value should be given in the question)

T =  (M + 2m)g tanθ

T = (74.9    +   2 x 122)(9.8)(tan 66)

T = 7,019.4 N

Thus, the the tension in the horizontal rope is 7,019.4 N.

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i. Which of the following formula gives definition of relative density? d d B. A. C. d water at 4°C d d mercury at 4°C D. d water at 40°C d d alcohol at 4°C​

Answers

Answer:

water at 4°c that's abnormal stage of water

The object that ends up with less electrons has a __________ charge.
A. Positive
B. Not enough info
C. Neutral
D. Negative
Reset Selection

Answers

The object that ends up with less electrons has a positive charge; option A.

What are electrons?

Electrons are negatively charged particles which form a part of the three fundamental particles in an atom.

Electrons can easily be removed from the vicinity of atoms making the atom to become positively charged. On the other hand, when atoms gain extra electrons, they become negatively-charged.

On way of charging objects is by rubbing them against other objects in order to gain extra electrons or to lose electrons.

When two objects are rubbed together, the object that ends up with less electrons has a positive charge, whereas the object that ends up with more electrons has a negative charge.

In conclusion, objects can become charged when they are rubbed against each other, and they can either become negatively or positively-charged by gain or loss of electrons.

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The object indicated here that ends up with fewer electrons has an unknown charge (not enough info, Option B).

What does atomic charge mean?

The atomic charge makes reference to the overall charge of an atom, which can be evidenced by knowing its net charge (positive or negative charge).

The net charge of a molecule and/or atom is obtained by calculating the amount of electrically negative electrons (e-) and the number of positive protons.

Neutrons are another type of subatomic particle that have not net charge (neither positive nor negative).

In conclusion, the object indicated here that ends up with fewer electrons has an unknown charge (not enough info, Option B).

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A thin-walled hollow sphere has a radius 4cm from the center
of the sphere, the eletric field points radially inward and
has a magnitude of 1.5 × 10^4 NC". How much charge is on the surface

Answers

The  electric charge on surface is 2.66×10-⁹NC

What is an electric charge?

The electric charge is the property  of subatomic particle that causes it to experience a force when placed in an electric and magnetic field.

We have given ,

Electric field= 1.5×10⁴N/C

 Radius = 4cm = 0.04m

E = k× q/ r²

 1.5×10⁴×16×10-⁴/9×10⁹=q

 q= 2.66×10-⁹C

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[tex] \large{\rm{Question:}}[/tex]

Give one example where the displacement is zero but the distance traveled is not zero.

Answers

Let us assume a man travelled from a point A to a point B over a distance 'd'. After a while he travels the same distance back to point A.

Therefore, since his initial and final positions are the same, displacement is equal to zero, and the distance travelled is (d + d) = 2d, which is not zero.

Example:

Imagine a person walks 10 meters forward and then turns around and walks 10 meters back to the starting point. In this case, the displacement is zero (starting point to ending point), but the distance traveled is 20 meters (10 meters forward + 10 meters backward).

a resistor wire of diameter 0.6cm has a resistivity of 1.0×00000010 ohms m. what length of the wire would be needed to make a 4 ohm resistor

Answers

The length of the wire is 1.12m

What is Resistance ?

Resistance is opposition to the current flowing in the circuit.

Given ,

D= 0.6m

R= 0.6/2m

R= 28Ω

rho = 1Ωm

R= rho ×l/A

where R is resistance , l is length ,A is area and rho is resistivity

By applying value and Solving we get,

l= 1.12m

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As mass increases, which of the following is always true?
a. volume decreases
b. density decreases
c. inertia increases
d. all of these

Answers

As mass increases, the following which is found to be always true is a corresponding increase in the inertia and is therefore denoted as option C.

What is Inertia?

This is defined as the property of a body to resist changes in velocity or motion. Such feature is characterized by the body having the tendency to remain at rest or in uniform motion unless an external force acts on it.

When mass increase, inertia also increases due to the large amount of force which is needed to change the direction or motion of a body in this scenario. On the other hand, when mass decreases, there is a corresponding decrease in the inertia which is present in a given body over a period of time.

This is therefore the reason why mass of a body is directly proportional to its inertia and makes it the most appropriate choice.

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What is the mass of the sun plus all the planets in solar system?

Answers

It’s a very huge mass
This is test answer bla bla

Complete the following:

When light is incident through the focal point, and then strikes a mirror, ___

the light will reflect parallel to the principal axis
the light will reflect back through the focal point
the light will not reflect at all

Answers

Answer:

the light will reflect parallel to the principal axis

Three professional wrestlers are fighting over a champion’s belt, and each exerts a force on the belt. Wrestler 1 exerts a force F1=40.0 N in the +x-direction, wrestler 2 exerts a force F2=80.0 N in the negative y-direction, and wrestler 3 exerts a force F3=60.0 N at an angle of 36.9° counterclockwise (anticlockwise) from the +x-direction.

Answers

The resultant force of the three professional wrestlers on the championship belt is 98.35 N.

Component of the forces in x - direction

The component of the forces in x -direction is calculated as follows;

Fx = 40 N  +  60(cos 36.9)

Fx = 40 N + 47.98 N

Fx = 87.98 N

Component of the forces in y - direction

The component of the forces in y -direction is calculated as follows;

Fy = -80 N + 60(sin 36.9)

Fy = -43.95 N

Resultant force

R = √Fx² + Fy²

R = √( 87.98²  + 43.95²)

R = 98.35 N

Thus, the resultant force of the three professional wrestlers on the championship belt is 98.35 N.

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A sensor that generates voltages in the range of -2V..+2V for 0..400kg weight values Design a balance circuit with LCD display. ; fosc=4MHz​

Answers

39-72 may it not nah he 472=5

A light bulb in a camper’s flashlight is labeled 4.1 V, 0.40 A. Find the equivalent current if three of these light bulbs are connected in parallel to a standard C size 1.5 V battery.

Answers

Explanation:

first rule of parallel circuits : the voltage is the same in the whole circuit, no matter where we measure.

so, we have 1.5V at every bulb.

second rule of parallel circuits : the total current is the sum of the individual branch currents.

so, if the battery really allows it, then we have 3 times 0.4 A = 3×0.4 = 1.2 A as current in the circuit.

A transverse mechanical wave is traveling along a string lying along the x-axis. The displacement of the string as a function of position and time, y(x,t), is described by the following equation:
[tex]y(x,t)=0.0480[/tex]×[tex]sin(5.40x-128t)[/tex]
where x and y are in meters and the time is in seconds.
1. What is the wavelength of the wave?
2. What is the velocity of the wave? (Define positive velocity along the positive x-axis.)
3. What is the maximum speed in the y-direction of any piece of the string? (Give a positive answer for speed.)

Answers

The wavelength of the wave is 1.16m and the velocity is 23.64m/s.

To find the answer, we have to know more about the Transverse waves.

How to find different parameters of a wave?The displacement of the string as a function of position and time, y(x,t), when the wave traveling along a string lying along the x-axis is given as,

                [tex]y(x,t)=0.048sin(5.40x-128t)[/tex]

Comparing this with the general form of wave equation, we get,

               [tex]amplitude, a=0.048m\\wave vector, k=5.40\\angular frequency,w=128Hz[/tex]

We have to find the wavelength of the wave, for this, we have the expression as,

                [tex]k=\frac{2\pi }{wavelength} \\\\wavelength=\frac{2\pi }{k} =\frac{2*3.14}{5.40} \\\\wavelength=1.16m[/tex]

We have to find the velocity of the wave,

                         [tex]v=frequency*wavelength\\2\pi f=w, thus,\\f=\frac{w}{2\pi } =\frac{128}{2*3.14}=20.38s^{-1}\\\\v=1.16*20.38=23.64m/s[/tex]

Thus, we can conclude that, the wavelength of the wave is 1.16m and the velocity is 23.64m/s

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A cell connected to two bulbs in series lasts longer than a cell connected to the same bulbs in parallel.Explain why?

Answers

Because the voltage stays the same while the amps grow, parallel batteries last longer. It will still be a 12 volt system if you connect two 12v 50ah batteries in parallel, but because the amps quadruple to 100ah, the batteries will last longer. Charges are spread among the bulbs in a parallel circuit because they are flowing in several directions over multiple paths. As a result, each bulb will have less charge since the charge is travelling in multiple directions, and the lights will shine less brightly. On the other hand, in a series circuit, there is only one channel and only one location for the charge to travel, meaning that all of the charge is directed at a single lightbulb. As a result, the lightbulb will shine more brilliantly since there is no need to spread the energy. The rule of conservation of energy is not broken because of the difference in power; instead, smaller resistance causes bigger current, which results in brighter lights. The energy traveling from the source to the bulbs remains constant. Because higher power means that more energy in a given time goes quicker from the source to the bulb, brighter lights require more power rather than energy. Because the energy traveling from the source to the bulbs remains constant, the rule of conservation of energy is not being broken; rather, there is merely a difference in power as a result of smaller resistance leading to bigger current, which will result in brighter lights. This means that brighter lights require more power rather than energy since higher power enables more energy to go from the source to the bulb more quickly.

Thank you,

Eddie

a dog runs back and forth between its two owners, who are walking toward one another. the dog starts running when the owners are 10 m apart. if the dog runs with a speed of 3 m/s and the owners each walk with a speed of 1.3 m/s how far has the dog traveled when the owners meet​

Answers

Answer:

11.54 meters

Explanation:

The owners take  10m / (1.3 + 1.3 m/s)  = 3.85 seconds to meet

The dog is running at constant speed of 3 m/s for these 3.85 seconds

   3 m/s * 3.85 sec = 11.54 meters

a ball bearing x is dropped vertically downwards,from the edge of a table and it takes 0.5seconds to hit the floor. Another bearing y leaves from the edge of the table horizontally with a velocity of 5m/s . Find:.
a)the time taken for bearing y to reach the table?
b)the horizontal distance traveled by y before hitting the floor
c)the height of the table top above the floor level

Answers

Answer:

See below

Explanation:

A) bearing y reaches the FLOOR in the same amount of time   .5 seconds  since there is no initial vertical velocity component

B.  in .5 seconds y will travel     5 m/s * .5 s = 2.5 meters horizontally

C.  d = 1/2 a t^2

         = 1/2 (9.81)(.5^2) = 1.23 m table height

(a) Bearing y takes 0.2 seconds to reach the table. (b) Bearing y travels 1 meter horizontally before hitting the floor. (c)  The height of the table top above the floor level is 1.225 meters.

a) Time is taken for bearing y to reach the table:

For a horizontal motion, the equation to calculate time is:

Time (t) = Distance (d) ÷ Velocity (v)

Time (t) = Width of the table / Velocity of y

t = 1  / 5

t = 0.2 sec

So, bearing y takes 0.2 seconds to reach the table.

b) Horizontal distance traveled by bearing y before hitting the floor:

Distance (d) = Velocity (v) × Time (t)

d = 5 × 0.2

d = 1 m

So, Bearing y travels 1 meter horizontally before hitting the floor.

c) The height of the table top above the floor level:

h = (1/2) × g × t²

h = (1/2) × 9.8 × (0.5)²

h = (1/2) × 9.8 × 0.25

h = 1.225 m

So, the height of the table top above the floor level is 1.225 meters.

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Identify two fields where physical quantities are used in motion calculations​

Answers

The two fields were physical quantities are used in motion calculations are length and mass with time.

The physical quantity in a field is referred as every point in a particular space time.

How physical quantities are used in motion calculations?

 If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.

Length, mass and time  are the physical quantities used in motion calculations.

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A 60 year old person has a threshold of hearing of 79.0 dB for a sound with frequency f=10,000 Hz. By what factor must the intensity of a sound wave of that frequency, audible to a typical young adult, (sound level=43.0 dB) be increased so that it is heard by the older person.

Answers

43.DB(decibels)

Unit conversion

4.3(bels)

4.951NP

4.3(decades)

14.28(octaves)

Interpretations

Power quantity level

Basic unit dimensions

⇉ ( logarithmic quantity ).

They provided the intensity in decibels for the problem, but they are unsure by what factor to increase it (I) to make the sound loud enough for the elderly person to hear.

Neglect f entirely.

The following equation must be used to convert decibels (dB) to I:

I=(10^(dB/10))*10^-12

Divide the elder person's dB by the younger person's dB after doing this for each dB.

1.8372093023.

Decibels are used to measure sound (dB). A motorcycle engine operating is roughly 95 dB louder than regular conversation, which is around 60 dB louder than a whisper. Your hearing may begin to be harmed if exposed to noise over 70 dB for an extended period of time. Your ears can suffer instant damage from loud noise above 120 dB.

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4. A hemispherical surface (half of a spherical surface) of radius R is located in a uniform electric field of magnitude E that is parallel to the axis of the hemisphere. What is the magnitude of the electric flux through the hemisphere surface? how to draw the question?

Answers

It is to be noted that the magnitude of the electric flux through the hemisphere surface  is πR²E. (Option D)

What is an Electric Flux?

The characteristic of an electric field known as electric flux may be thought of as the quantity of electric lines of force (or electric field lines) that cross a certain region.

According to this theory, electric field lines begin with positive electric charges and end with negative charges.

What is the calculation for the above?

Recall  that the A hemispherical surface (half of a spherical surface) of radius R.

In order to derive the Magnitude of the electric flux we use the following formula:

Ф = ∈ x Area of the Curve Surface

⇒ Ф = ∈ x πR²

⇒ Ф = πR²∈

Thus, option D is the correct answer.

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Full Question:

A hemispherical surface (half of a spherical surface) of radius R is located in a uniform electric field of magnitude E that is parallel to the axis of the hemisphere. What is the magnitude of the electric flux through the hemisphere surface?

A) 2πR²∈

B) 0

C) 4 πR²∈/3

D) πR²∈

What phase of matter is pictured below? Image of particles that are spread out, many are not touching, high energy. A. Gas B. Bose-Einstein condensate C. Fermionic condensate D. Plasma

Answers

Option(d)i.e, Plasma is the Image of particles that are spread out, many are not touching, high energy.

Along with solid, liquid, and gas, plasma is frequently referred to as the "fourth state of matter." Heating a gas will result in the formation of plasma, which is a soup of positively and negatively charged particles (ions), similar to how adding energy causes a liquid to boil and transform into a gas (electrons).

Plasmas are less dense than solids or liquids and, like gases, have no set structure or volume. However, in contrast to regular gases, plasmas are composed of atoms in which part or all of the electrons have been removed and positively charged nuclei, known as ions, are free to move around.

Solids, liquids, gases, ionized plasma, quark-gluon plasma, bose-einstein condensate, and fermionic condensate are the seven states of matter.

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Lifting a 81-kg barbell and weights from rest up to a speed of 1.0 m/s in 0.50 s, resisted by the combined weight of the barbell and weights, requires what applied force in N to two significant digits?

Answers

Answer:

960 N

Explanation:

answer should have two signif digits  

a = change in velocity divided by change in time

   1 m/s / .5 s =   2 m/s^2

F = ma      a = g + 2 m/s^2 = 9.81 + 2 =  11.81 m/s^2

  81 kg * 11.81 m/s^2   = 956.61   N = ~ 960 N  (two sig digits)

(Please let me know if this is incorrect....I am not SURE )

the meaninn of dynamics

Answers

Answer:

Dynamics is just a nice word used in physics denoting a branch of physics, related to the study of forces. Usually these forces are not in mechanical equilibrium, else the branch would be statics.

The Kennedy Space Center was in charge of the Apollo 13 mission.

True

False.

Answers

True as they launched the rocket
This answer is true give me brainiest


The velocity of a body is given by the equation v= a + bx, where 'x' is displacement. The unit of b is .......

Answers

Answer:

s^ -1    ( or    1/sec)

Explanation:

Velocity is given in units of displacement / sec

like feet /sec   or   m/sec    

so b would have units of   s^-1

(or perhaps a more general term would be   time^-1)

When a 6kg block is placed on a vertical spring, the spring is compressed by 20cm. How much work is required to compress the spring by an additional 10CM​

Answers

Answer:

Mass of block = 6kg

wright = 6 × g = 60 N using g = 10 m/s^2 .

compression= 0.20m

spring constant =( weight / compression) =( 60/0.20) = 300 N/m .

Work done in compressing 0.20 m =( 1/2 × 300 × 0.20 × 0.20)= 6 joule.

Additional compression = 0.10 m

total compression = 0.20+ 0.10= 0.30 m.

Total work done = ( 1/2 × 300 × 0.30× 0.30) = 13.5 joule.

Hence work done in compressing from 0.20 m to 0.30 m will be = ( 13.5 - 6) = 7.5 joule.

Note :- work done in compressing a spring having spring constant K N/m by x m is equal to 1/2× (K) × X^ 2 .

How much energy is needed to move an electron in a hydrogen atom from the ground state (n = 1) to n = 3?

Answers

The energy needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3 will be 1.93 *10^-18J and 12.09 eV.

How to compute the value?

The following can be deduced:

Energy of electron in hydrogen atom is

En = -13.6 /n2 eV

where n is principal quantum number of orbit.

Energy of electron in first orbit = E1 = -13.6 / 12 = - 13.6eV

Energy of electron in third orbit = E3 = -13.6 /32 = -1.51 eV

Energy required to move an electron fromfirst to thirdorbit ΔE = E3- E1

ΔE = -1.51 - ( 13.6) = 12.09 eV

Energy in Joule = 12.09 *l/× 1.6 × 10^-19 = 1.93 × 10^-18 J.

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Complete question:

How much energy is needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3? Give theanswer (a) in joules and (b) in eV.

Other Questions
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