The Mass of glycine = Molality × Molar mass × Mass of solvent=0.0153 × 75 × 800=91.35 g ≈ 91 g Mass of C2H5NO2 that was dissolved is approximately 91 g.
Hence, the correct option is 91.
Given,Normal boiling point of liquid X, T1
= 121.7°C Boiling point elevation constant, Kb
= 131°C kg mol-1 Mass of solvent, w2
= 800 g Boiling point of solution, T2
= 123.7°C
Now, Boiling point elevation is given by, ΔTb
= T2 - T1ΔTb
= 123.7 - 121.7ΔTb
= 2°C The boiling point elevation is given by,ΔTb
= Kb × bΔTb/Kb
= b Molality (b) of solution, b
= ΔTb/Kb
=2/131
=0.0153 mol/kg
The molality of the solution is 0.0153 mol/kg.Molar mass of glycine, C2H3NO2
= 75 g/mol
We need to calculate the mass of glycine dissolved in the solution.
The Mass of glycine
= Molality × Molar mass × Mass of solvent
=0.0153 × 75 × 800
=91.35 g ≈ 91 g Mass of C2H5NO2 that was dissolved is approximately 91 g.
Hence, the correct option is 91.
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