Answer:
Can u explain more pls?
Step-by-step explanation:
Answer:
Square
Step-by-step explanation:
If two people earn a total of $23, how many people will earn a total of $92
Answer:
8
Step-by-step explanation:
[tex] \frac{23}{2} = 11.5[/tex]
[tex]92 \div 11.5 = 8[/tex]
In one week, Alex worked 35 hours at $ 12.50 per hour plus 5 hours overtime at 'time and half'. How much would Alex have earned for the week? *
PLEASE ANSWER ASAAPPPPPPPP
Answer:
3
Step-by-step explanation:
Need help on this!!!!
Answer:
D
Step-by-step explanation:
First find h(3)
2(3)-2= 4
then find g(4)
4³-5= 59
out of 1300 students in a school , only 60% passed . find the number of students failed .
Hi there!
»»————- ★ ————-««
I believe your answer is:
520 students.
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
60% of the 1300 students passed. This means that 40% of the students failed.
⸻⸻⸻⸻
[tex]1300 * 0.4= 520[/tex]
⸻⸻⸻⸻
520 students failed school.
⸻⸻⸻⸻
[tex]\boxed{\text{Another way to find this...}}\\\\\text{Take 60}\% \text{ of 1300:}\\\\1300 * 0.6 = 780\\\\\text{780 students passed school.}\\\\\text{Subtract 780 from 1300:}\\\\1300 - 780 = \boxed{520}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
A car and a bus were travelling towards each other at uniform speeds. They were 250 km apart at noon and passed each other at 2 p.m. If the speed of the car was 75 km/h, find the speed of the bus.
Answer:
50 km/hr
Step-by-step explanation:
speed = x + 75
distance = 250km
time = 2
250 = (x + 75) * 2
125 = x + 75
x = 50
daca cel mai mare divizor comun al lor a si b este 21 iar produsul lor este 15435 cat sunt a si b
Answer:
[tex]{\dag{\underline{{\sf{\red{t {}^{2} = \: \dfrac{4.05}{5} \: = 0.81 \: , \: \: t = 0.9s}}}}}}[/tex]
PLEASE HELP!!! Urgent. Will mark as brainliest
Answer:
Step-by-step explanation:
m∠2 = [tex]\frac{1}{2}[/tex](55+41)
m∠2 = [tex]\frac{1}{2}[/tex](96)
m∠2 =48°
m∠1 = 180-48 = 132°
what is the length of segment SR?
ST = ST (Common)
RT = TQ (Given)
∠ RTS = ∠ SQT (Both 90°)
So, ∆ RTS ≅ ∆ QTS (By SAS congruency rule)
So, RS = QS (By C.P.C.T.)
=> 2x + 8 = 8x - 4
=> 8 + 4 = 8x - 2x
=> 12 = 6x
=> 12/6 = x
=> 2 = x
SR = 2x + 8 (Given)
=> SR = 2(2) + 8 (Putting the value of x)
=> SR = 4 + 8
=> SR = 12
Answer:
Step-by-step explanation:
How long is JK?
Choose 1 answer:
A: 3
B: 2 square root 3
C: 3 square root 3
D: 6
E: 9
Answer:
C) 3 times the sq root of 3
Step-by-step explanation:
In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So
COS 60 = JK/JL
COS 60 = JK/(6*sq root 3)
.5 = JK/(6*3**1/2)
JK = .5 *(6*3**1/2)
JK = 3*3**1/2
Please helpppp
Find l.
Answer:
Step-by-step explanation:
radius of base=8/2=4 ft
l²=4²+9²=16+81=97
l=√97 ft
Find the missing side or angle. Round to the nearest tenth. C=95° a=5 c=6 A=[?]°
Answer:
Missing angle A = 56.1° (approximately)
Step-by-step explanation:
<A = arcsin(a×sin(C)/c)
= arcsin(5×sin 95/6)
= 56.1154084° ≈ 56.1°
Answered by GAUTHMATH
if p-1/p = 4 Find (p+1/p)²
Answer:
4
Step-by-step explanation:
[tex] \frac{p - 1}{p} = 4[/tex]
Solve for p.
The numerator. difference has to be 4 times the answer of the denomiator.
So we can say
[tex]p - 1 = 4p[/tex]
Solve for p
[tex] - 1 = 3p[/tex]
[tex]p = - \frac{1}{3} [/tex]
Now plug this in for the other formula.
[tex]( \frac{ - \frac{1}{3} +1}{ \frac{1}{3} } ) {}^{2} = 2 {}^{2} = 4[/tex]
So
What is the equation of the following line?
(-4, 8)
(0,0)
Answer
Step-by-step explanation:
y = -2x + 0
Therefore; y = -2x
The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Find the two weights that separate the top 3% and the bottom 3%. (These weights could serve as limits used to identify which components should be rejected)
Answer:
The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
Step-by-step explanation:
We are given that
Mean, [tex]\mu=8.04 g[/tex]
Standard deviation, [tex]\sigma=0.08g[/tex]
We have to find the two weights that separate the top 3% and the bottom 3%.
Let x be the weight of machine components
[tex]P(X<x_1)=0.03, P(X>x_2)=0.03[/tex]
[tex]P(X<x_1)=P(Z<\frac{x_1-8.04}{0.08})[/tex]
=0.03
From z- table we get
[tex]P(Z<-1.88)=0.03, P(Z>1.88)=0.03[/tex]
Therefore, we get
[tex]\frac{x_1-8.04}{0.08}=-1.88[/tex]
[tex]x_1-8.04=-1.88\times 0.08[/tex]
[tex]x_1=-1.88\times 0.08+8.04[/tex]
[tex]x_1=7.8896[/tex]
[tex]\frac{x_2-8.04}{0.08}=1.88[/tex]
[tex]x_2=1.88\times 0.08+8.04[/tex]
[tex]x_2=8.1904[/tex]
Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
c) What should be subtracted from 5m - 3n to get 2m + 5n?
What she hechosomoce 2-59
Answer:
3m-8n
Step-by-step explanation:
Set up an equation:
(5m-3n)-(2m+5n) = ?
Solve:
5m-3n
- 2m+5n
3m-8n
Hope this helps!
Uma empresa do ramo de confecções produz e comercializa calças jeans. Se x representa a quantidade produzida e comercializada (em milhares de reais) e L(x) = -x² + 8x – 16 representa o lucro (em milhares de reais) da empresa para x unidades, então quando L(x) = 0 a empresa terá produzido e comercializadas quantas unidades dessas calças jeans? *
Answer:
I am in 5 classso i did not known answer
What percentage of temperatures are below 55°? A. 50% B. 25% C. 75% D. 20%
Step-by-step explanation:
C
im not sure of my answer. hope to help
Find x and y
Help me please
Answer:
x = 70 y = 140
Step-by-step explanation:
Apologies if I get any names of vocabulary terms wrong, I never pay much attention to the names.
The central angle measure of an arc is the same as the arc's measure. In this case, y is the central angle and 140 is the arc's measure, so y = 140.
The inscribed angle measure of an arc is 1/2 the arc's measure. An inscribed angle lies on the circle. So 140/2 = 70 = x.
Are the two triangles similar. If so, State how
Answer:
Yes by AAA
Step-by-step explanation:
Angle A is the same for both triangles. Angle D is congruent to Angle A since BC and DE are parallel lines and same with angle E. So by AAA the triangles are similar
Charlie dve 208 miles in 4 hours at a constant speed he continues at that speed give the equation that shows the relationship between driving hours
Answer:
52 miles per hour
Step-by-step explanation:
I think you're missing some info, so this is all I can help with right now
Log problem below in the picture
Your answer is 2.98004491789381.
given the nth term of geometric expression is (as in the diagram)
a) state the value of k
b) the first term of progression
Step-by-step explanation:
a) k = 1
b) geometric progression formula:
Tn = ar^(n-1)
first term, a = 3/2
Find angle D if angle B = 50
============================================================
Explanation:
I'm assuming that segments AD and CD are tangents to the circle.
We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.
By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.
----------------------------
Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.
Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.
We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.
---------------------------
Here's what we have so far for quadrilateral DAEC
angle A = 90angle E = 100angle C = 90angle D = unknownNow we'll use the idea that all four angles of any quadrilateral always add to 360 degrees
A+E+C+D = 360
90+100+90+D = 360
D+280 = 360
D = 360-280
D = 80
Or a shortcut you can take is to realize that angles E and D are supplementary
E+D = 180
100+D = 180
D = 180-100
D = 80
This only works if AD and CD are tangents.
Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.
Write the expression as an exponent:
5^8 x 25
6^15 x 36
Answer:
a.) 5¹⁰
b.) 6¹⁷
Step-by-step explanation:
a.) 5⁸ × 25
Write 25 in the exponential form with the base of 5.
5⁸ × 5²To calculate product use exponent rule
5⁸+²5¹⁰b.) 6¹⁵ × 36
Similarly, 6¹⁵ × 36
Write 25 in the exponential form with the base of 6.
6¹⁵ × 6²To calculate product use exponent rule.
6¹⁵ + ²6¹⁷Answer:
[tex] \displaystyle {5}^{10} [/tex]
[tex] \displaystyle {6}^{17} [/tex]
Step-by-step explanation:
Question-1:we want to rewrite the following expression as an exponent
[tex] \displaystyle {5}^{8} \times {25}[/tex]
remember that 25 is the square of 5 therefore
[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]
recall that,
[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
with that law we obtain:
[tex] \displaystyle {5}^{8 + 2} [/tex]
simplify addition:
[tex] \displaystyle {5}^{10} [/tex]
Question-2:likewise Question-1 36 is the square of 6 Thus,
[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]
similarly apply law of exponent:
[tex] \displaystyle {6}^{15 + 2} [/tex]
simplify addition:
[tex] \displaystyle {6}^{17} [/tex]
hence,
we have written the expression as an exponent
What is the slope of the graph shown below
Answer:
B=-5
Step-by-step explanation:
Slope=rise/run
The line passes in
P1(-1,3)
and
P2(0,-2)
So slope=(3-(-2))/(-1-0)=5/-1=-5
Can someone please help me really struggling
Answer:
your y-intercept is 5 and your slope is 1 hope this helps with translating into the form you want
Step-by-step explanation:
If A = [tex]\left[\begin{array}{ccc}cosx&-sinx\\sinx&cosx\end{array}\right][/tex], then show that [tex](A^{-1} )^{-1}[/tex]
Given:
The matrix is:
[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
To show:
[tex](A^{-1})^{-1}=A[/tex]
Solution:
If a matrix is:
[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]
Then,
[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]
We have,
[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
Using the above formula, we get
[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
Now, the inverse of [tex]A^{-1}[/tex] is:
[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]
[tex](A^{-1})^{-1}=A[/tex]
Hence proved.
In a geometric progression, the first tern is 81 and the fourth term is 24. find the common ratio
Step-by-step explanation:
81/24= 27/8Hello,
Let's say a the first term and r the ratio of the G.P.
[tex]u_1=a=81\\u_2=a*r\\u_3=a*r^2\\u_4=a*r^3\\\\\dfrac{u_4}{u_1} =\dfrac{a*r^3}{a} =r^3=\dfrac{24}{81} =\dfrac{8}{27} \\\\r=\sqrt[3]{\dfrac{8}{27} } \\\\\boxed{r=\dfrac{2}{3}}\\[/tex]
the first day she walked 27 kilometers. each day since she walked 2/3 of what she walked the day before. what is the total distance cecelia has traveled be the end of the 5th day?
Answer: 70
Step-by-step explanation:
We are required to calculate the total distance Cecilia travelled in 5 days
The total distance Cecilia travelled for 5 days is 99 kilometers
Day 1 = 27 kilometers
Day 2 to day 5 = 2/3 of 27
= 2/3 × 27
= 2 × 9
= 18 kilometers each day
Total distance = day 1 + day 2 + day 3 + day 4 + day 5
= (27 + 18 + 18 + 18 + 18) kilometers
= 99 kilometers
Therefore, the total distance Cecilia travelled for 5 days = 99 kilometers
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