a child pulls a friend in a little wagon with constant speed. if the child pulls with the force of 16 n for 10.0 m and the handle of the wagon is inclined 25 degrees with respect to the horizontal, how much work does the child do on the wagon?

Answers

Answer 1

The work done by the child on the wagon is 158.4 J

Work done is defined as the product of the force applied on the object and the component of distance traveled by the object in the direction of the force. Mathematically,

W = FdCosθ

where,

W = work done = ?

F = force applied = 16 N

d = displacement = 10 m

θ = angle of inclination = 25°

Therefore,

W = (16 N) (10 m)Cos(25°)

W = 158.4 J

Hence, work done by the child on the wagon is 158.4 J

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Related Questions

Salem, Sabrina’s magical black cat, gets scared and jumps straight upward with an initial velocity of 20 m/s from a height of 115-meters.

Draw a velocity vs time graph to describe the cat’s motion for the first five seconds of motion.
What is the cat’s velocity and acceleration at it’s maximum height?
What is the cat’s velocity when it hits the ground?
How long does it take for the cat to hit the ground?

PLS HELP!!!!!

Answers

Considering a quadratic equation to model the height of the car, we have that:

The graph is given at the end of the answer.At the maximum height, the velocity is of zero and the acceleration is of -9.8 m/s².The velocity when the cat hits the ground is: -51.54 m/s.It takes 7.30 seconds for the cat to hit the ground.

What is the quadratic equation for a projectile's height?

Considering an acceleration = gravity of -9.8m/s², the equation for the height is given as follows:

h(t) = -4.9t² + v(0)t + h(0).

In which:

v(0) is the initial speed.h(0) is the initial height.

Considering the values of these parameters for this problem, of v(0) = 20, h(0) = 115, the equation is:

h(t) = -4.9t² + 20t + 115.

At the maximum height point, we have that:

The velocity is of zero. (standard)The acceleration if of -9.8 m/s². (standard).

The velocity function is:

v(t) = v(0) - gt

v(t) = 20 - 9.8t.

Which is the linear function graphed at the end of the answer.

The cat hits the ground at t > 0 for which h(t) = 0, hence:

-4.9t² + 20t + 115 = 0.

Which is a quadratic equation with coefficients given by:

a = -4.9, b = 20, c = 115.

Using a calculator, the positive solution for this equation is:

t = 7.30s.

At this instant, the velocity is:

v(t) = 20 - 9.8(7.3) = -51.54 m/s.

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two wheels, a and b, are both shaped like uniform disks and have the same overall mass, but wheel a has twice the radius of wheel b. how do we calculate the moments of inertia (around the axis of symmetry) for each wheel?

Answers

The ratio of I sub A to I sub B is 4.

How can you calculate the ratio of A to B?

A/B would be your formula if you were comparing one data point (A) to another data point (B). This indicates that you are multiplying information A by information B. For instance, your ratio will be 5/10 if A is 5 and B is 10. How do we determine each wheel's moments of inertia (around the axis of symmetry) I is equal to 1 over 2 times m times R squared is used to compute the moments of inertia for both masses and radii. We simply use a common factor to cancel. So 4:2=2:1 . The simplest representation of the ratio 4 to 2 is the ratio 2 to 1. Additionally, since each pair of numbers has the same relationship, the ratios are equivalent.

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How can gravity's role in tectonic plate motion be described? question 6 options: earth's magnetic field reverses ridge push and slab pull circulating material in the mantle earth's internal heating

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Gravity's role in the tectonic plate motion can be described on the basis of ridge push and slab pull of tectonic plates.

What are ridge push and slab pull?

Ridge push refers to gravitational sliding. It is a driving force for plate motion in plate tectonics, occurring at mid-ocean ridges as the result of the rigid lithosphere sliding down the hot and raised asthenosphere below mid-ocean ridges.

Slab pull is a pulling force that is exerted by a cold and dense oceanic plate plunging into the mantle. The term for the process of a tectonic plate descending into the mantle is subduction. Subduction may emerge due to gravity.

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monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.35 mm. find the wavelength of the light.

Answers

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

How to find Wavelength of the light?

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

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4. Predict whether a greater amount of energy will be
transferred as heat between 1 kg of water at 10 °C
and a freezer at -15 °C or between 1 kg of water at
60 °C and an oven at 65 °C.

Answers

The greater amount of energy is transferred during the first case and the difference in energies is: 84 × 10³ J

What is internal energy of a system?

Internal energy refers to all energy within a particular system, including the kinetic energy of molecules and the energy stored in chemical bonds between molecules. The interaction of heat, work, and internal energy involves the transfer and conversion of energy whenever a change is made to the system.

The amount of heat (Q) gained or lost from the sample can be calculated using the formula Q = mcΔT. where m is the mass, c is the specific heat, and ΔT is the temperature change.

For the first case:

Q = mcΔT

Q = mc(T₁ - T₂)

m = 1 kg or 1000 g

c =  4.2 J g⁻¹/°C

T₁ = 10 °C

T₂ = -15 °C

Q₁ = 1000 × 4.2 × (10 -(-15))

Q₁ = 105 × 10³ J

For the second case:

Q = mcΔT

Q = mc(T₂ - T₁)

m = 1 kg or 1000 g

c =  4.2 J g⁻¹/°C

T₁ = 60 °C

T₂ = 65 °C

Q₂ = 1000 × 4.2 × (65 - 60)

Q₂ = 21 × 10³ J

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how is cmb observed from earth

Answers

The Cosmic Microwave Background radiation, or CMB for squat, is a faint glow of light that fills the universe, falling on Earth from each direction with nearly uniform intensity.

How does CMB observe Earth?

The CMB represents the heat leftover from the Big Bang. You can't see the CMB with your bare eye, but it is everywhere in the universe. It is unseen to humans because it is so cold, just 2.725 degrees above total zero. Planck mapped out the warp in the CMB due to gravitational lensing caused by dark matter's existence. The CMB materialized as an electromagnetic fog on optical telescopes and as a static hum on radio telescopes. The CMB will certainly emerge slightly different from any distant galaxy,

So we can conclude that The Cosmic Microwave Background (CMB) is the cooled remains of the first light that could ever travel freely throughout the Universe.

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an automobile manufacturer claims that its product will travel 1.2 km in 20 s, starting from rest. what is the magnitude of the constant acceleration required to do this? answer in units of m/s 2 .

Answers

The amount of constant acceleration needed to accomplish this is:

6 m/s2.

What is constant acceleration?A velocity change that does not alter over time is referred to as a constant acceleration. A car's average acceleration remains steady at 20 mph per minute even if it increases its speed by 20 mph in one minute and another 20 mph the next.

Given;

The car will drive a distance of d = 1.2 km

To convert 1.2 km to m

1.2 x 1000

= 1200 m.

beginning speed of the car, where u = 0.

Travel time, t = 20 s

To get the constant acceleration, use the following kinematic equation;

d = ut + ¹/₂at²

1200 = 0 + ¹/₂(20)²a

1200 = 400 /2

1200 = 200a

a = 1200 / 200

a = 6 m/s²

Therefore, 6 m/s² of constant acceleration is needed to accomplish this.

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The amount of constant acceleration needed to accomplish this is 6 m/s2.

What is constant acceleration?

A velocity change that does not alter over time is referred to as a constant acceleration. A car's average acceleration remains steady at 20 mph per minute even if it increases its speed by 20 mph in one minute and another 20 mph the next.

Given;

The car will drive a distance of d = 1.2 km

To convert 1.2 km to m

1.2 x 1000

= 1200 m.

beginning speed of the car, where u = 0.

Travel time, t = 20 s

To get the constant acceleration, use the following kinematic equation;

d = ut + ¹/₂at²

1200 = 0 + ¹/₂(20)²a

1200 = 400 /2

1200 = 200a

a = 1200 / 200

a = 6 m/s²

Therefore, 6 m/s² of constant acceleration is needed to accomplish this.

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a solid sphere has a radius of 0.200 m and a mass of 150 kg. how much work is required to get the sphere rolling with an angular speed of 50.0 rad/s on a horizontal surface? assume the sphere starts from rest and rolls witho

Answers

Work done on sphere is 10500 J.

Kinetic energy = 1/2 [tex]iw^{2}[/tex] + 1/2 [tex]m v^{2}[/tex]

I = 2/5 [tex]m R^{2}[/tex]

w = [tex]\frac{v}{r}[/tex]

Now, put these values in formula KE = 1/2 [tex]iw^{2}[/tex] + 1/2 [tex]m v^{2}[/tex]

KE = 10500 J

Now, by work energy theorem

Work done = 10500 - 0 = 10500 J

Hence, Work done on sphere is 10500 J.

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a playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.350 rev/s. what is its angular velocity (in rev/s) after a 15.0 kg child gets onto it by grabbing its outer edge? the child is initially at rest.

Answers

Angular velocity (in rev/s) after a 15.0 kg child gets onto it by grabbing its outer edge is 1.575 rad/s.

The angular velocity of the merry-go-round after a child gets on it is equal to the angular velocity of the child plus the angular velocity of the merry-go-round.

The angular velocity of a rotating object can be calculated using a formula:

ω = ω + (m/r)

where ω is the original angular velocity, m is the mass of an object that's been added to it, r is its radius, and (m/r) is the change in mass divided by its radius. When we plug in our values for this problem, we get:

ω = 0.350 rad/s + ((15 kg)/(1.8 m)) rad/s

= 0.350 rad/s + 1.25 rad/s

= 1.575 rad/s

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a funny car accelerates from rest through a measured track distance in time t with the engine operating at a constant power p. if the track crew can increase the engine power by a differential amount dp, what is the change in the time required for the run? (use any variable or symbol stated above as necessary.)

Answers

dT = -T^4/(2mD^2)dP


P = W/T = FD/T = (m a)D/T

dP = -maD/T^2 dT

dT = -T^2/(maD)dP

V = aT

D = 1/2 a T^2

a = 2D/T^2

dT = -T^4/(2mD^2)dP



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Gravity obeys an inverse square relation. This statement implies that the force due to gravity betweentwo massesa.will increase as the distance between the two masses increases.*b.will decrease as the square of the distance between the two masses increases.c.will cause the two masses to move away from each other.d.will cause the two masses to move in a straight line.e.will cause the two masses to orbit each other.

Answers

The inverse square relation implies that  force resulting from gravity between two masses will decrease as the square of the distance between the two masses increases.

The force of gravity between any two objects is given by,

F = GM₁M₂/R²

Where,

M₁ and M₂ are the masses of the bodies.

R is the distance between them.

We know, if the masses are constant. then the force of gravity will be inversely proportional to the square of the distance between them.

This is what inverse square relation means here.

As the force of gravity and the square of the distance are inversely proportional to each other,

So, when the square of the distance between the masses increases, the force of gravity between the decreases.

Hence of all the options provided, b is the correc0,t which says, the force will decrease on increasing the inverse square of the distance.

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Explain how heating a gas can lead to: no change in the kinetic energy of the gas.​

Answers

Heating of gas leads to change in kinetic energy of the gas.

As the temperature of the system increases, the molecules in it begin to move faster, and the speed of the particles is directly proportional to the kinetic energy.

Kinetic energy is the energy possessed by the gaseous particles while they are in motion.

Mathematically, KE = (1/2)mv^2,

where KE is kinetic energy, m is mass, and v is velocity.

When the temperature of a gas increases but the pressure remains the same, the volume of the gas increases, which means that the molecules must cover more space in the same amount of time by moving faster.

Kinetic energy increases as collisions between different molecules increase and the speed of motion increases. This behavior is demonstrated by Charles's law with the equation V/T = k. In this equation, V is the volume and T is the temperature, and the two are directly proportional. Similarly, temperature and pressure are also directly related, as in the Pressure law equation, P/T = k, where P is pressure and T is temperature.

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the moon orbits earth at an average distance of 3.84 x 108 m in a path that takes 27.3 days to complete. what is the centripetal acceleration of the moon? (remember, you must convert time into seconds.)

Answers

If the moon orbits the Earth at a distance of 3.84 x 10⁸ on a path that takes 27.3 days to complete, its centripetal acceleration will be 2.7x 10⁻³ m/s².

How can we determine the centripetal speed of the moon?

A body moving in a circular path at a high rate of speed is said to be experiencing centripetal acceleration. We can calculate the moon's centripetal acceleration using the centripetal acceleration formula.

We are informed that the moon is approximately 3.84 x 10⁸ miles away from Earth and that a full rotation of the moon takes 27.3 days.

The distance traveled by the moon in 27.3 days is its velocity.

v = x/t

v = 2 πr/t

v = 2.41x10⁹/2.35x10⁶

v = 1025.5

The radius is 3.84 x 108 m and the velocity is 1,025.5 m/s. Here, we will determine the centripetal acceleration of the moon.

[tex]a_{c}[/tex] = v²/r

[tex]a_{c}[/tex] = (1025.5)²/3.84 x 10⁸

[tex]a_{c}[/tex] = 2.7 x 10⁻³

We now know the centripetal acceleration of the moon to be 2.7 103 m/s².

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if you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out because an outward force balances the pull of gravity on the water. if you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out because an outward force balances the pull of gravity on the water. true false

Answers

We must understand both inertia and gravity to find a solution.

What is inertia?

The matter has an attribute called inertia that makes it resist changes in velocity (speed and direction). Newton's first law of motion states that an object moving at a certain speed will stay there unless an outside force acts upon it.

What is gravity?

A planet or other body's gravitational field pulls objects toward its center. The force of gravity is what keeps every planet in its orbit around the sun.

A vertical circle spun while holding a bucket full of water prevents the water from spilling out due to inertia.

Keep the bucket in place as the water tries to fly off.

Therefore we can conclude that it is false.

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A car (mass 1 000 kg) uses 50 000 J of energy (from fuel) to accelerate the car from rest to 5.5 m/s (about 20 km/h). How efficient is the car’s engine? ( Think, Eff = Eout/Ein x 100/1)

Answers

The energy output from the car is 15125 J and the input energy is given 50000 J. Thus, the efficiency of the car is 30.25 %.

What is engine efficiency?

The efficiency of an engine is the ratio of its energy output to the energy input multiplied by 100. The efficiency of a heat engine can be found similarly using the input heat and output heat.

Given the mass of the car is 1000 Kg and it is accelerated to 5.5 m/s. Therefore the kinetic energy output is is calculated as follows:

KE = 1/2 mv²

     = 1/2  1000 kg × (5.5 m/s)²

     =  15125 J

The input energy is 50000 J. Therefore, the energy efficiency is :

efficiency = output energy / input energy × 100

                = ( 15125 J/ 50000J ) × 100

                = 30.25 %

Hence, the energy efficiency of the car is 30.25 %.

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a wire with a resistance of 6.0 () is drawn out through a die so that its new length is three times its original length. find the resistance of the longer wire, assuming that the resistivity and density of the material are not changed during the drawing process.

Answers

R0 is the original resistance. Thus, R = 9(6.0Ω) = 54 Ω.

Electric current flowing through and potential difference across an electrical component can be used to determine its resistance.

Ohm's Law, which depicts the connection between potential difference, current, and resistance:

V = I R, where V is the potential difference (in volts), V I is the current (in amps), A R is the resistance (in ohms), and

The following equation can be changed to determine the resistance:

R = V ÷ I

According to Ohm's equation, I = V/R, the behaviour of the material may be predicted if the resistance remains constant over a significant range of voltage. The definition above applies to both AC and DC applications of resistors, despite the fact that it deals with DC current and voltage.

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what is the point in the sky directly overhead called? which constellation is closest to this point tonight?

Answers

The answers include the following:

The point in the sky which is directly overhead is called Zenith.The constellation which is closest to this point tonight is Polaris.

What is Constellation?

This is referred to as a group of stars that form a perceived pattern or outline and are usually given names and an example is hydra.

The Zenith as the name implies is known as the overhead point in the sky which is usually hardly seen while the constellation which is closest to this point tonight is Polaris due to the position thereby making it the most appropriate choice.

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Substances in a(n)________
separate properties.
keep their separate properties, but in a(n)___________
the parts are bonded and do not keep their

Answers

Substances in a mixture keep their separate properties, but in a compound the parts are bonded and do not keep their separate properties.

Mixtures contains elements and compounds without any fixed ratio and not by any means of chemical bonds. The elements and compounds are physically mixed and so they will be visibly distinct.

Compounds contains elements in a fixed ratio and is connected by chemical bonds. They only contain one type of molecule. Since they are chemically combined the particles appear as one and is not visibly distinct.

Therefore, substances in a mixture keep their separate properties, but in a compound the parts are bonded and do not keep their separate properties.

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when a mass m1is placed on top of a spring and allowed to come to rest, the spring iscompressed by an amount x1. how much would the spring compress if it is an elevatoraccelerating upwards at 3g and has a mass of 4m1placed on top of the spring?a)16x1b)12x1c)4x1d)7x1e)8x

Answers

The spring compresses if it is an elevator accelerating upwards at 3g is Option A. a)16x

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

Gravitational acceleration = g

Spring constant of the spring = k

Mass of the first block = m1

Compression of the spring due to the first block = X1

m1g = kX1

Mass of the second block = 4m1

Upward acceleration of the elevator = 3g

The force from the spring on the second block = F

Compression of the spring due to the second block in the elevator = X2

From the free-body diagram of the 4m1 block,

(4m1)(3g) = F - 4m1g

F = 16m1g

kX2 = 16m1g

kX2 = 16(kX1)

X2 = 16X1

Compression of the spring due to a 4m1 block placed on it in an elevator accelerating upwards at 3g = 16X1.

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A student travels on a motorcycle and moves at a constant speed of 80 k/h for 15 m, determine the distance traveled in that time​

Answers

Uniform line movement

Data:

V = 80km/h

T = 15m = 0.25 h

d = ?

We perform a conversion from minutes to hours.

           15 m * 1 h/60 m = 0.25 h

The formula for uniform motion is:

                      V = d/t

We clear for distance:

                  d = v * t

                  d = 80 km/h * 0.25 h

                  d = 20 km

The distance traveled in that time is 20 km.

How do you calculate this?

Answers

Answer: Find the right angle degree and then you will find ow to do the rest.

How much gravitional potential energy would a 65.0kg rollerblader have at the top of a hill that is 45.0 meters high

Answers

Roller balder will have 28,665 J gravitational potential energy at the top of a hill that is 45.0 meters high

gravitation potential energy = m*g*h

mass = 65 kg

g = 9.8 [tex]m/s^{2}[/tex]

h = 45 m

gravitation potential energy  = 65 * 9.8 * 45 = 28,665 J

Roller balder will have 28,665 J gravitational potential energy at the top of a hill that is 45.0 meters high

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Which statement is true regarding a distance vs. time graph? (1 point)
O The graph should show distance on the vertical axis.
O The graph can include only straight line segments.
O The graph must have a horizontal segment.
O The graph needs to start at the origin.

Answers

The statement that is true regarding a distance vs. time graph is option A: The graph should show distance on the vertical axis.

Where is the plot of distance?

How far an object has come in a certain amount of time is displayed on a distance-time graph. Time is represented on the X-axis and Distance is plotted on the Y-axis (left) (bottom).

On a distance-time graph, an object's motion is indicated by a sloping line. The slope or gradient of the line in a distance-time graph is equal to the object's speed. The object is travelling more quickly the steeper the line is (and the bigger the gradient).

Note that the distance-time graph shows the relationship between distance and time by plotting distance on the y-axis and time on the x-axis.

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Answer:

(Question) Which quantity is scalar?

(Answer) Energy

(Question) Which option describes a vector quantity?

(Answer) It has magnitude, units, and direction.

(Question) A sailboat ends up 7 miles to the west of a pier. Which statement is true about this situation?

(Answer) It describes displacement, which is a vector quantity.

(Question) Which statement is true regarding a distance vs. time graph?

(Answer) The graph should show distance on the vertical axis.

(Question) On a distance vs. time graph for an object, a line segment that is sloping upward indicates

(Answer) motion in the positive direction.

Explanation:

just finished the quick check UwU

Which statement best describes heat?

A. Heat flows from cold to hot and is a form of thermal energy.

B. Heat flows from hot to cold and is the transfer of thermal energy.

C. Heat flows from hot to cold and is a form of thermal energy.

D. Heat flows from cold to hot and is the transfer of thermal energy.

Answers

Answer: D

Explanation:

Pls help answer this

Answers

Answer: The rods both have the same charge therefore they repel each other.  The force of repulsion creates a downward force on the balance pan and therefore the balance registers a higher reading.

A 1.80-kg block is suspended from a spring with a spring constant of 220.0 N/m. A 0.060-kg bullet is fired into the block from directly below with a speed of 270.0 m/s and is embedded in the block. (A) Find the amplitude of the subsequent motion. (B) What fraction of the original kinetic energy of the bullet appears as mechanical energy in the system of block-spring-bullet?

Answers

The fraction of the original kinetic energy of the bullet appears as mechanical energy in the system of block-spring-bullet is 0.72 m.

Amplitude=0.72 m

KE of system=0.5*(1.8+0.06)*8.7^2=70.39 j

Conservation of momentum

0.06*270=(1.8+0.06)*v

v=8.7 m/s

conservation energy

0.5*(1.8+0.06)*8.7^2=0.5*220*x^2+(1.8+0.06)*9.81*x

x=0.72 m

Amplitude=0.72 m

Original KE of bullet = 0.5*0.06*270^2=2187j

KE of system = 0.5*(1.8+0.06)*8.7^2=70.39 j

Amplitude in physics is stated to be the maximum displacement or distance that is moved by a factor on a body that is vibrating or wave measured from its equilibrium role.

As the pendulum swings through its equilibrium point (straight down), it swings to a maximum distance away from the center.

The amplitude of a wave is related to the amount of energy it includes. An excessive amplitude wave consists of a massive amount of power; a low amplitude wave consists of a small quantity of strength. Amplitude and intensity are associated, but not equal.

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which answer would you choose if the rocks fall out through a hole in the floor of the car, one at a time?

Answers

The car speeds remains constant.

Using the following equation for momentum:

Pi=Pf

(c=car and r=rock)
              McVc + MrVr = McV'c + MrV'r

Initially
                         Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc

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an obstruction is just ahead on the shoulder. your front wheel leaves the roadway at high speed. when do you countersteer?

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An obstruction is just ahead on the shoulder. Your front wheel leaves the roadway at a high speed. You countersteer when the front tire touches the roadway.

Countersteer is usually done by the cyclists and motorcyclists to turn at higher speeds. It is advisable to be done only on the race tracks. This is because the two wheels do not follow the same path during turning and it may affect other vehicles on normal roads. The rider must be leaned in the direction of turn in order to complete the turn. As the front wheel leaves at a higher speed, countersteering is done when the front wheel touches the ground.

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A van accelerates from a velocity of 2 m/s to a velocity of 20 m/s in 12 s.
Calculate the acceleration of the van.

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Answer:

Explanation:

Given:

V₀ = 2 m/s

V = 20 m/s

Δt = 12 s

__________

a - ?

The acceleration of the van:

a = ΔV / Δt = (V - V₀) / Δt

a = (20 - 2) / 12 = 18 / 12 ≈ 1.5 m/s²

what is the potential difference across a 19- m -long, 2.0- mm -diameter copper wire carrying an 7.6 a current?

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The potential difference across a 19m long, 2.0mm diameter copper wire carrying a 7.6A current is 676 V.

The resistance of the wire is given by R = ρ L/A

where ρ is the resistivity of copper (ρ = 1.72E-8 Ωm) and L is the length of the wire (19m). So,

R = 1.72E-8 * 2.0E-3/7.6E3

= 912 Ω.

Assuming that no other circuit elements are present, the potential difference across this wire will be equal to the voltage drop across that resistor:

V = IR = 912 * 7.6E3

= 676 V

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