a partice set into motion within a circle ofradiusm 14 cm having 33.3 if the particle starts on the positive x axis at time --

The correct descending order of power for the given prefixes is giga, mega, kilo, nano.

A more detailed explanation of the prefixes and their descending order of power:

1. Giga (G): Giga is a prefix used to denote one billion (1,000,000,000) units. It is often used in relation to large quantities or measurements, such as gigabytes (GB) for computer storage or gigawatts (GW) for power.

2. Mega (M): Mega represents one million (1,000,000) units. It is commonly used to describe large-scale quantities, such as megabytes (MB) for file sizes or megahertz (MHz) for processor speeds.

3. Kilo (k): Kilo signifies one thousand (1,000) units. It is frequently used to measure smaller quantities, such as kilobytes (KB) for data storage or kilowatts (kW) for power consumption.

4. Nano (n): Nano represents one billionth (1/1,000,000,000) of a unit. It is used to describe extremely small measurements, such as nanometers (nm) for length or nanoseconds (ns) for time.

Therefore, the correct descending order of power for the given prefixes is giga, mega, kilo, nano.

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The combined mass of the package and the sled is 96.75 kg (A).

Changes in the price level and changes in interest rates will shift the AD (Aggregate Demand) curve, while changes in foreign demand and changes in wealth will not shift the AD curve.

The AD curve represents the relationship between the aggregate quantity of goods and services demanded in an economy and the overall price level. It is influenced by various factors, and changes in some of these factors can cause the AD curve to shift.

Changes in the price level: An increase or decrease in the price level will result in a movement along the AD curve, known as a movement along the demand curve. This is because as the price level changes, the purchasing power of consumers also changes, affecting their willingness and ability to spend on goods and services.

Changes in interest rates: Changes in interest rates have an impact on borrowing costs, investment decisions, and consumer spending. When interest rates decrease, it becomes cheaper to borrow money, leading to increased investment and consumer spending.

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Part A: The magnitude of the electric field at a distance of 0.350 m from the sphere's center is 1.97 × 10^6 N/C.

Part B: The magnitude of the electric field at a distance of 3.95 m from the sphere's center is 1.13 × 10^5 N/C.

Part C: The magnitude of the electric field at a distance of 4.15 m from the sphere's center is 9.84 × 10^4 N/C.

Part D: The magnitude of the electric field at a distance of 6.00 m from the sphere's center is 4.37 × 10^4 N/C.

The electric field (E) at a point in space due to a charged sphere can be calculated using the formula:

E = k * (Q / r^2),

where k is the electrostatic constant (9 × 10^9 N m^2/C^2), Q is the charge on the sphere, and r is the distance from the center of the sphere to the point where the electric field is measured.

Part A:

Using the given values, we can calculate the electric field at a distance of 0.350 m:

E = (9 × 10^9 N m^2/C^2) * (-6.70 × 10^(-6) C) / (0.350 m)^2

= -1.97 × 10^6 N/C (magnitude)

Part B:

Calculating the electric field at a distance of 3.95 m:

E = (9 × 10^9 N m^2/C^2) * (-6.70 × 10^(-6) C) / (3.95 m)^2

= -1.13 × 10^5 N/C (magnitude)

Part C:

Calculating the electric field at a distance of 4.15 m:

E = (9 × 10^9 N m^2/C^2) * (-6.70 × 10^(-6) C) / (4.15 m)^2

= -9.84 × 10^4 N/C (magnitude)

Part D:

Calculating the electric field at a distance of 6.00 m:

E = (9 × 10^9 N m^2/C^2) * (-6.70 × 10^(-6) C) / (6.00 m)^2

= -4.37 × 10^4 N/C (magnitude)

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The electric field in a metal sphere is zero inside the sphere due to the charges being pushed to the sphere's surface. Outside the sphere, the electric field can be calculated using Gauss's law or the formula E = kQ/r².

The question pertains to the concept of electric field and is related to Gauss's Law in electromagnetism. Gauss's law states that the electrostatic flux passing through any closed surface is equal to 1/ε_0 times the total charge enclosed by the surface. In order to answer this question, we will need to understand the concept of electric field intensity.

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When a fully discharged 500mF capacitor is connected to a 5V power supply with a current limit of 1 ampere, the supply immediately goes into current limit due to the high initial charging current required by the capacitor. The power supply acts like an ideal current source during this time.

The time it takes for the power supply to come out of current limit depends on the discharge time constant of the capacitor and the resistance of the circuit. It can be calculated using the formula t = RC, where R is the circuit resistance and C is the capacitance. Plotting the voltage across the capacitor over time will show an exponential decay as it charges up.

After the protection disengages, the current drawn from the supply several seconds later depends on the circuit connected to the power supply output. Without specific details about the circuit, the exact current value cannot be determined.

To keep the power supply in current limit until the wire is removed, a capacitor with a very large value would be needed, ideally approaching infinity.

When a fully discharged capacitor is connected to the power supply, it acts like a short circuit due to its low impedance. This causes a high initial current to flow, exceeding the current limit of the power supply and triggering the current protection mechanism.

The time it takes for the power supply to come out of current limit is determined by the discharge time constant of the capacitor, which depends on the product of resistance and capacitance (RC). The resistance includes any resistance present in the circuit and the internal resistance of the power supply.

The current drawn from the power supply after the protection disengages will depend on the circuit connected to the power supply output. Without specific details about the circuit, it is not possible to determine the exact current value.

To keep the power supply in current limit until the wire is removed, a capacitor with a very large value would be needed. Ideally, the capacitance would approach infinity, creating a short circuit condition that would continuously draw excessive current and keep the power supply in current limit.

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Answer:

shut up figure it out

Explanation:

Answer; Cross training enables your body to recuperate faster from injuries, in some cases because other exercises can directly improve the condition caused by your regular activity. For example, Achilles tendonitis, caused by overuse, can be improved by eccentric strengthening of the calf muscles.Explanation:

The coefficient of kinetic friction is given as 0.22. Hence, the main answer to the question is that the upper block's acceleration would be 4.62 m/s².

Let the acceleration of the block be a.To calculate the force of friction, use the formula Ff = μk Fn where Ff = force of friction,μk = coefficient of kinetic friction, andFn = normal forceThe weight of the block can be calculated as W = mgwhere m = mass of the block = 4.8 kg (total mass of the two blocks)and g = acceleration due to gravity = 9.8 m/s²W = 4.8 kg × 9.8 m/s²= 47.04 NThe normal force on the block is the force exerted by the table on the block and is equal in magnitude to the weight of the block.The formula to calculate the force exerted by the upper block is given as F = ma where m = 4.8 kg and a is the acceleration of the upper block.Substituting the values of Fn and Ff in the formula

F = ma gives

F - Ff = ma47.04 - 0.22

Fn = 4.8 × aa = (47.04 - 0.22Fn) / 4.8

Note that the two blocks are connected by a string, and hence the tension in the string is the same for both blocks.The formula to calculate the tension in the string is given as T = m₁g + where m₁ and m₂ are the masses of the two blocks and g is the acceleration due to gravity.

T = 1.6 × 9.8= 15.68 N

The net force on the upper block is given as Fnet = T - FfFnet = 15.68 - 0.22Fn

As per Newton's second law of motion,

Fnet = ma, where m is the mass of the block and a is the acceleration of the block.

Fnet = ma 15.68 - 0.22 Fn = 4.8aa = (15.68 - 0.22Fn) / 4.8 Substituting this value of a in the equation  

F - Ff = ma,

we get

F - Ff = 4.62 m/s²

Therefore, the upper block's acceleration is 4.62 m/s²

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The velocity of the boat relative to the shore is the vector sum of its velocity relative to the water and the velocity of the river and the velocity will be 15.03m/s. The boat has moved 200 meters downstream by the time it reaches the north shore.

(a) To determine the velocity of the boat relative to the shore, we can use vector addition. The boat has a velocity of 15.0 m/s due north relative to the water, and the river flows due east at 1.00 m/s. We can represent the velocities as vectors:

Velocity of the boat relative to the shore = Velocity of the boat relative to the water + Velocity of the water

Velocity of the boat relative to the shore = 15.0 m/s (north) + 1.00 m/s (east)

Using vector addition, we can find the resultant velocity:

Velocity of the boat relative to the shore = √((15.0 m/s)² + (1.00 m/s)²) = 15.03 m/s.

(b) To determine how far downstream the boat has moved by the time it reaches the north shore, we can use the time it takes to cross the river and the velocity of the river.

Time taken to cross the river = Distance/Relative velocity = 200 m / 1.00 m/s = 200 s

Distance downstream = Velocity of the river x Time taken to cross = 1.00 m/s x 200 s = 200 m

Therefore, the boat has moved 200 meters downstream by the time it reaches the north shore.

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Answer:

A

Explanation:

In order to answer the question about how far a sound wave moves before the microphone first detects a minimum in the sound intensity, we need to use the formula for sound intensity and the properties of sound waves. The sound intensity formula is given by: I = P / A .

where I is the sound intensity, P is the sound power, and A is the area through which the sound wave is passing. The properties of sound waves include wavelength, frequency, and velocity. The distance traveled by a sound wave before the microphone first detects a minimum in the sound intensity depends on the wavelength of the sound wave and the distance from the sound source to the microphone.

Specifically, the distance traveled is equal to half of the wave length. Based on this information, we can use the following formula to find the distance traveled by a sound wave before the microphone first detects a minimum in the sound intensity: d = λ/2 where d is the distance traveled, and λ is the wavelength of the sound wave. Therefore, the answer to the question is that the distance traveled by the sound wave before the microphone first detects a minimum in the sound intensity is equal to half of the wavelength. The appropriate units for this answer are meters (m), which is the SI unit of length.

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Answer:

t = 4.47 seconds

Explanation:

Given that,

Speed of a train, v = 360 m/s

We need to find the time taken by the train to cover 1 mile. For this first we must know 1 mile equal to how many meters.

1 mile = 1609.34 m

Let t is time.

Speed = distance/time

[tex]t=\dfrac{d}{v}\\\\t=\dfrac{1609.34\ m}{360\ m/s}\\\\t=4.47\ s[/tex]

So, it will take 4.47 seconds to travel one mile.

The pressure just inside the natural draft hyperbolic cooling tower must be determined based on an air flow rate of 150,000 mgfs and a flow area of 940 m2.

To calculate the pressure just inside the cooling tower, we can use the equation for mass flow rate:

Mass flow rate = density × velocity × area

Given that the mass flow rate (m) is 150,000 mgfs (mgfs stands for "metric gallons per minute"), and the flow area (A) is 940 m2, we need to convert mgfs to a standard unit of flow rate such as kg/s.

1 mgfs = 0.06308 kg/s

Therefore, the mass flow rate in kg/s is:

m = 150,000 mgfs × 0.06308 kg/s = 9,462 kg/s

Next, we need to consider the density of the air (ρ). At standard conditions (typically 20°C and 1 atm), the density of air is approximately 1.2 kg/m3.

Using the equation for pressure (P) and rearranging the mass flow rate equation, we have:

P = m / (ρ × A)

Substituting the known values:

P = 9,462 kg/s / (1.2 kg/m3 × 940 m2)

Simplifying:

P = 7.917 atm

Therefore, the pressure just inside the cooling tower must be approximately 7.917 atm

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Given parameters:

Mass of load = 20kg

Height of man = 1.4m

Unknown:

Work done by man = ?

Work done is the force applied to move a body in a particular direction.

Often times, it is mathematically expressed as;

           Work done  = Force x distance

In this problem, we use the formula of potential energy to find the work done;

     Work done  = Potential energy  = mgh

where m is the mass of the load

            g is the acceleration due to gravity  = 9.8m/s²

            h is the height of the body

Now, input the parameters, and solve for work done;

        Work done = 20 x 9.8 x 1.4  = 274.4J

The work done by man is  274.4J

To find the values of t for which the rocket's height is 151 feet, we can set the equation for height h equal to 151 and solve for t. The equation is as follows:

h = 253 - 16t^2

Setting h = 151, we have:

151 = 253 - 16t^2

Rearranging the equation, we get:

16t^2 = 253 - 151

16t^2 = 102

Dividing both sides by 16, we get:

t^2 = 102/16

t^2 = 6.375

Taking the square root of both sides, we get:

t = ±√(6.375)

Calculating the square root, we find:

t ≈ ±2.52

Rounding to the nearest hundredth, the values of t for which the rocket's height is 151 feet are approximately 2.52 seconds and -2.52 seconds. The negative value indicates the time before the rocket was launched..

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Rotational velocity is commonly denoted using the following units:

a) radians per second

b) degrees per second

e) revolutions per second

The unit of radians per second (rad/s) is the most commonly used unit for rotational velocity. Radians are a unit of angular measurement, and when divided by time, it gives the angular velocity or rotational velocity. This unit is widely used in physics and engineering to describe the rate of rotation.

Degrees per second (°/s) is another unit used for rotational velocity. Degrees are another unit of angular measurement, and when divided by time, it provides the angular velocity in degrees per second. While radians per second is the more preferred unit, degrees per second is still used in some applications where degrees are more familiar or convenient.

Revolutions per second (rps) is also a common unit for rotational velocity. It represents the number of complete revolutions or cycles completed in one second. This unit is often used in situations where the frequency or rotational speed is emphasized, such as in mechanical systems or rotating machinery.

On the other hand, meters per second (m/s) is a unit used for linear velocity, which describes the rate of change of position in meters per second. It is not directly applicable to rotational velocity.

Arc seconds are units used to measure angles and are not typically used to express rotational velocity.

In summary, the units commonly used for expressing rotational velocity are radians per second, degrees per second, and revolutions per second.

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Answer:  1.) The intensity of the sound wave which reaches the listener’s ear.

2.) The square of the amplitude of the sound wave.

3.) The mass of air which can be set into vibration.

Explanation:

The energy that a moving object possesses is known as kinetic energy. It is the energy required to bring an object of a specific mass to a particular speed.

The sphere has no potential energy because it is situated on the ground and is not elevated. Therefore, the only source of energy is the spring, which provides energy to the sphere. It can be assumed that the sphere begins moving with a velocity v after being pushed by the spring.

The spring's energy is transformed into kinetic energy as the sphere rolls freely on a smooth surface. The spring's maximum potential energy, E0, equals 1/2 kx², where k is the spring constant and x is the compression of the spring. As a result, the maximum kinetic energy, E, of the sphere can be determined using the law of conservation of energy.E = E0The main answer is:E = E0 = 1/2 kx²Where k is the spring constant and x is the distance that the spring has been compressed. The sphere's kinetic energy is determined by this formula.

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The analogous dam or canal that controls and directs the flow of passions like a river is referred to as virtue.

When the passions are compared to a river, the general notion is that they are flowing, overflowing and quite strong.They may become dangerous or beneficial. A canal or dam is used to control the water flow of the river in the same way virtue is used to control and direct the flow of our passions. Virtue provides guidance, which can help a person take control of their life and passions.

It can help you to maintain balance and to understand what your desires mean and to guide them in a more positive and constructive direction. Virtue . Virtue is the control and canal that directs the passions’ flow.

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The magnitude of vector B is 2.0 m, and its direction is in the +z-direction. Given that the magnitude of the vector product (A x B) is 16.0 m² and it is in the +z-direction, we can use the formula for the magnitude of the vector product:

|A x B| = |A| * |B| * sin(theta)

where theta is the angle between vectors A and B.

Since vector A is in the --x-direction, its y and z components are zero, and its x component is -8.0 m.

Let's assume that vector B has components (0, By, Bz) in the x, y, and z directions, respectively.

The magnitude of vector A can be calculated as:

|A| = sqrt(Ax² + Ay² + Az²) = sqrt((-8.0 m)² + 0² + 0²) = 8.0 m

Now we can solve for the magnitude of vector B using the given information:

16.0 m² = (8.0 m) * |B| * sin(theta)

Since sin(theta) is always positive, we can ignore the sign. Thus, we have:

|B| = 16.0 m² / (8.0 m) = 2.0 m

Therefore, the magnitude of vector B is 2.0 m.

To determine the direction of vector B, we can analyze the given information. Since the vector product is in the +z-direction, vector B must have a non-zero z-component, which is positive.

Hence, the direction of vector B can be expressed as (0, 0, Bz) in Cartesian coordinates, where Bz > 0.

In summary, the magnitude of vector B is 2.0 m, and its direction is in the +z-direction.

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Answer:

120

Explanation:

cant explain trust me.

Mugabe gained power by using political strategies, forming alliances, and exploiting his status as a liberation hero within ZANU-PF.

Robert Mugabe, the former president of Zimbabwe, was able to build power through a combination of political strategies and alliances. One key factor was his involvement in the liberation struggle against white minority rule in Rhodesia (now Zimbabwe).

Mugabe emerged as a prominent figure within the Zimbabwe African National Union (ZANU) party, which later merged with the Zimbabwe African People's Union (ZAPU) to form the Zimbabwe African National Union - Patriotic Front (ZANU-PF). Mugabe's role as a liberation hero and his ability to mobilize support among the majority black population of Zimbabwe gave him a strong power base.

Within ZANU-PF, Mugabe strategically positioned himself and gained influence by forming alliances and outmaneuvering rivals. He rose to become the party's leader and played a key role in negotiating the Lancaster House Agreement in 1979, which paved the way for Zimbabwe's independence in 1980. Mugabe became the country's first prime minister and later transformed the position into an executive presidency, consolidating his authority.

Mugabe maintained power through various means, including controlling key institutions such as the military, intelligence agencies, and the ruling party. He also utilized patronage networks, distributing resources and positions to loyal supporters within the party and government. Mugabe's policies, such as the controversial land reform program, further solidified his power base by appealing to nationalist sentiments and redistributing land from white farmers to black Zimbabweans.

However, Mugabe's consolidation of power was also marked by authoritarianism, human rights abuses, and a declining economy. His grip on power faced challenges over the years, including opposition movements, internal party factions, and economic crises. Ultimately, his rule came to an end in 2017 when he was ousted from power following a military intervention.

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a. The focal length of the farsighted patient's eye when an object is at their near point of 40.0 cm is approximately 68.6 cm. This focal length is longer than the focal length of a normal eye with the object at the commonly-used near point of 25.0 cm.

b. Without using corrective lenses, the farsighted patient above will experience difficulty focusing on objects that are closer to them. Their eye's focal length is longer than that of a normal eye, making it harder to bring near objects into clear focus.

a. Focal Length Calculation:

The near point is the closest distance at which the eye can focus on an object clearly without strain. For the farsighted patient, their near point is 40.0 cm.

The focal length (f) of the eye can be calculated using the lens formula: 1/f = 1/v - 1/u, where u is the distance of the object and v is the distance of the image formed.

Since the near point is the object distance, u = -40.0 cm (negative sign indicates that the object is on the same side as the eye).

The image distance (v) is the distance between the lens and the retina, which is given as 1.70 cm.

Substituting the values into the lens formula: 1/f = 1/1.70 - 1/-40.0

Simplifying the equation gives: 1/f = 0.5882 + 0.025

Therefore, the focal length (f) is approximately 68.6 cm.

The farsighted patient's eye has a longer focal length compared to the commonly-used near point of 25.0 cm for a normal eye, indicating that the farsighted patient needs to keep objects at a greater distance to bring them into clear focus.

b. Without Corrective Lenses:

Without using corrective lenses, the farsighted patient will have difficulty focusing on objects that are closer to them.

The longer focal length of their eye means that light rays from nearby objects will converge beyond the retina, resulting in a blurry image on the retina.

This blurriness makes it challenging for the farsighted patient to see nearby objects clearly without additional focusing effort.

Corrective lenses, such as convex lenses, can help bring the focal point closer to the retina, allowing the farsighted patient to see nearby objects clearly without straining their eyes.

Therefore, without using corrective lenses, the farsighted patient will face difficulty focusing on objects that are closer to them due to the longer focal length of their eye.

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The acceleration of a box is 111 N / m, when weighing 666 n if a force of 777 n upwards is applied to it

To find the acceleration of the box, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

The equation for Newton's second law is:

F = m * a

Where:

F is the net force applied to the object,

m is the mass of the object, and

a is the acceleration.

In this case, the force applied is 777 N upwards, and the weight of the box (due to gravity) is 666 N. Since the force is applied in the opposite direction of gravity, we need to consider the net force.

Net force = Force applied - Weight

Net force = 777 N - 666 N = 111 N (upwards)

Now we can use Newton's second law to find the acceleration:

111 N = m * a

Since the mass (m) is not given, we cannot calculate the exact value of the acceleration without knowing it. However, if the mass is provided, we can divide both sides of the equation by the mass to find the acceleration.

a = 111 N / m

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In the given scenario, the electric field vanishes along the midpoint of the two point charges, i.e., at 1.5 meters away from each point charge along the horizontal line.

Let Q₁ and Q₂ be two point charges placed at a distance of d from each other. A line segment passing through the midpoint of the two point charges is called the perpendicular bisector (PB) of the line segment joining the two point charges. This PB line divides the electric field space into two halves,

On one half, the electric field due to Q₁ and Q₂ acts in the same direction. As a result, the electric field magnitude on this side of the PB line is non-zero and the electric field is additive to the net electric field. On the other side of the PB line, the electric field due to Q₁ and Q₂ acts in opposite directions.

As a result, the electric field magnitude on this side of the PB line is non-zero and the electric field is subtractive to the net electric field. Thus, the electric field is zero at any point on the PB line.

Hence, in the given scenario, the electric field vanishes along the midpoint of the two point charges, i.e., at 1.5 meters away from each point charge along the horizontal line.

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We have the given information;

Initial velocity u = 12 m/s

Time taken t = 3.06 seconds

Final velocity v = 0 (at the highest point, velocity is zero)

Acceleration a = acceleration due to gravity

g = -9.81 m/s²

We need to calculate the height of the cliff above the ground below using the given information.

We can use the following kinematic equation to find the height of the cliff above the ground below; v² - u² = 2

as, where, v = 0 (at the highest point, velocity is zero)

u = 12 m/st = 3.06 second

sa = -9.81 m/s²

s = height of the cliff above the ground below Putting the given values in the above formula;

0² - 12² = 2(-9.81)s

simplifying the equation we get;

S = (12²)/(2 x 9.81)

S = 7.25 m

Therefore, the height of the cliff above the ground below is 7.25 meters.

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The following is the main answer to your question about a tennis ball that is thrown upward at an angle from point A, it follows a parabolic trajectory and hits the ground at point D. At the instant shown, the ball is at point B. Point C represents the highest position of the ball above the ground.

The statement that is true concerning the ball when it is at C, the highest point in its trajectory is:The velocity of the ball is zero at point CThe maximum height that the ball can reach is the highest point of the trajectory. At this point, the ball's velocity will be zero because its direction of motion is reversing from upwards to downwards. This means that the ball will stop rising and begin to descend.

At point C, the ball has its highest potential energy because it is at its greatest height from the ground. At this point, it has no kinetic energy because its velocity is zero.Therefore, the true statement concerning the ball when it is at point C, which is the highest point in its trajectory is that the velocity of the ball is zero at point C.

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The correct answer is option B. Gravitational energy and E. Chemical energy.

Gravitational energy or gravitational potential energy is the potential energy a massive object has in relation to any other big object because of gravity. It is the potential energy related to the gravitational field, this is released (transformed into kinetic energy) when the objects fall in the direction of each other.

Chemical energy is energy stored inside the bonds of atoms and molecules. Batteries, biomass, petroleum, natural gas, and coal are some examples of chemical energy. Chemical energy is converted to thermal strength while human beings burn timber in a fire or burn fuel in a vehicle's engine.

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The earth behaves as a magnetic dipole. Therefore a freely suspended magnet always points towards in the north-south direction because the north pole of the suspended magnet attracts the south pole of the earth's magnet which is the geographical north pole of the earth.

hope this help!

Answer:

Because the north pole of a compass needle points towards geographical N and S poles and the compass needle points towards georaphical south.

Explanation:

Earth is a huge magnet.

Hope it was helpful....

A) There could be several reasons why water in an experiment does not boil at 100°C at sea level such as Impurities, Altitude etc. Some possible explanations include:

1. Impurities: Water may contain impurities such as dissolved minerals or gases, which can raise or lower its boiling point. These impurities can act as "boiling point elevators" or "boiling point depressants," causing the water to boil at a temperature different from 100°C.

2. Altitude: The boiling point of water decreases with increasing altitude. If the experiment is conducted at a location above sea level, where atmospheric pressure is lower, water will boil at a temperature lower than 100°C.

3. Pressure variations: Changes in atmospheric pressure can also affect the boiling point of water. For example, if the experiment is conducted in a closed container with higher or lower pressure than normal, it can cause the boiling point to deviate from 100°C.

B) To calculate the percent error for each sample of water, we can use the formula:

Percent error = [(Measured value - Theoretical value) / Theoretical value] × 100%

For the sample that boils at 102°C:

Percent error = [(102 - 100) / 100] × 100% = 2%

For the sample that boils at 99.2°C:

Percent error = [(99.2 - 100) / 100] × 100% = -0.8%

The positive percent error in the first sample indicates that it boiled at a slightly higher temperature than the theoretical value. The negative percent error in the second sample suggests that it boiled at a slightly lower temperature. These variations can be attributed to factors such as the accuracy of the temperature measuring equipment, impurities in the water, or atmospheric pressure fluctuations.

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