Answer:
Step-by-step explanation:
We will work in the y-dimension only here. What we need to remember is that acceleration in this dimension is -9.8 m/s/s and that when the projectile reaches its max height, it is here that the final velocity = 0. Another thing we have to remember is that an object reaches its max height exactly halfway through its travels. Putting all of that together, we will solve for t using the following equation.
[tex]v=v_0+at[/tex]
BUT we do not have the upwards velocity of the projectile, we only have the "blanket" velocity. Initial velocity is different in both the x and y dimension. We have formulas to find the initial velocity having been given the "blanket" (or generic) velocity and the angle of inclination. Since we are only working in the y dimension, the formula is
[tex]v_{0y}=V_0sin\theta[/tex] so solving for this initial velocity specific to the y dimension:
[tex]v_{0y}=35sin(35)[/tex] so
[tex]v_{0y}=[/tex] 2.0 × 10¹ m/s
NOW we can fill in our equation from above:
0 = 2.0 × 10¹ + (-9.8)t and
-2.0 × 10¹ = -9.8t so
t = 2.0 seconds
This is how long it takes for the projectile to reach its max height. It will then fall back down to the ground for a total time of 4.0 seconds.
If U= {1,2,3,......8} , A={1,4,6,7} , B= {2,4,5,7} & C= {3,5,6,7} prove that 1) An( BUC ) = ( AnB) U ( AnC ). 2) AU (BnC)= (AUB) n ( AUC )
Step-by-step explanation:
BUC={2,3,4,5,6,7}
An(BUC)={4,6,7}
AnB={4,7},AnC={6,7}
(AnB)U(AnC)={4,6,7}
Au(BnC)={1,4,5,6,7}
(AUB)n(AUC)= {1,4,5,6,7}
The table shows the relationship between the number of faculty members and the number of students at a local school. What is the missing value?
Faculty
Students
1
17
2
34
3
51
4
?
17
68
85
102
Answer:
68
Step-by-step explanation:
I did it on my test
The missing value in the table is 68. The correct answer would be option (B).
What is the linear relationship?A linear relationship is a connection that takes the shape of a straight line on a graph between two distinct variables - x and y. When displaying a linear connection using an equation, the value of y is derived from the value of x, indicating their relationship.
The table shows the relationship between the number of faculty members and the number of students at a local school.
Faculty Students
1 17
2 34
3 51
4 ?
The relationship between the number of faculty members and the number of students at the local school is that for every faculty member, there are 17 students.
Therefore, if there are 4 faculty members, we can find the number of students by multiplying 4 by 17, which gives us 68.
Thus, the missing value in the table is B. 68.
Learn about the linear relationship here :
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the sum of the square of the number and a second number is 42
Step-by-step explanation:
x+x squared =42. The square of the number is the number square. By my incredibly accurate guess and check strategy (works most of the time )6*6 = 36+6=42
help me with this please pleaseee!
Answer:
2
Step-by-step explanation:
Since the two rectangles are similar, the ratio of their similar sides will be a constant k
Hence;
18/9 = 12/6 = k
Since they are all the same, then;
k = 18/9
k = 2
Hence the scale factor is 2
Answer:
D. 1/2Step-by-step explanation:
The scale factor is the ratio of corresponding sides:
k = 9/18 = 1/2or
k = 6/12 = 1/2Correct choice is D
In one state lottery game, you must select four digits (digits may be repeated). If your number matches exactly the four digits selected by the lottery commission, you win.
1) How many different numbers may be chosen?
2) If you purchase one lottery ticket, what is your chance of winning?
3) There are ___ different numbers that can be chosen. (Type a whole number.)
4) There is a ___ chance of winning.*
*The answer choices for number 4 are:
1 in 10,000
1 in 6,561
1 in 100
1 in 1,000
1 in 9,999
Answer:
Part 1)
10,000 different numbers.
Part 2)
A) 1 in 10,000.
Step-by-step explanation:
Part 1)
Since there are four digits and there are ten choices for each digit (0 - 9) and digits can be repeated, then we will have:
[tex]T=\underbrace{10}_{\text{Choices For First Digit}}\times\underbrace{10}_{\text{Second Digit}}\times\underbrace{10}_{\text{Third Digit}}\times \underbrace{10}_{\text{Fourth Digit}} = 10^4=10000[/tex]
Thus, 10,000 different numbers are possible.
Part 2)
Since there 10,000 different tickets possible, the chance of one being the correct combination will be 1 in 10,000.
This is equivalent to 0.0001 or a 0.01% chance of winning.
Determine whether the following fractions terminate in their decimal form. Show all work and explain your reasoning. YOU CAN NOT USE A CALCULATOR. Try not using long division.
Answer:
8/22: this fraction will NOT terminate
189/270: this fraction WILL terminate
Step-by-step explanation:
I saw in the question that it says to solve the question by demonstrating the method discussed in class. I don't know what's the method you were taught, but I'll explain how I solved it.
When a fraction is in its simplest form, write out the prime factors of the denominator. If the denominator has 2s and/or 5s, the fraction WILL terminate in their decimal form.
8/22 in its simplest form is 4/11:
The only prime factors of the denominator, 11, are 1 and 11. There are no 2s and/or 5s present, so this fraction will NOT terminate.
189/270 in its simplest form is 7/10.
The prime factors of 10 are 2 and 5, meaning that this fraction WILL terminate.
Hope it helps (●'◡'●)
Graph: y = (x + 3)2 – 4
Which values are solutions of the quadratic equation
0 = (x + 3)2 – 4? Check all that apply.
y
X
-4
WIEC
6
0 -5
-4
.
0 -3
-1
-6
-4
-2
2
4
6
02
3
-2 -4
0,5
-6
Answer:
0.534375
45328
36763
-6
-78
The values of x and y that satisfy the graphs are:
(-1, 0), and (-5, 0).
What is a quadratic equation?A basic quadratic equation, or a second-order polynomial equation with a single variable, is represented by the equation x : ax² + bx + c = 0, where a≠0 for the variable x. As it is a second-order polynomial equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution.
We can start by simplifying the quadratic equation:
y = (x + 3)² – 4
y = x² + 6x + 9 - 4
y = x² + 6x + 5
Now, we can use various methods to find values of x and y that satisfy this equation. Here are five possible values:
If we substitute x = -1, we get:
y = (-1)² + 6(-1) + 5
y = 0
So, one solution is (-1, 0).
If we substitute x = 0, we get:
y = 0² + 6(0) + 5
y = 5
So, another solution is (0, 5).
If we substitute x = -5, we get:
y = (-5)² + 6(-5) + 5
y = 0
So, another solution is (-5, 0).
To find rational solutions, we can factor in the quadratic expression:
y = x² + 6x + 5
y = (x + 1)(x + 5)
So, the solutions are x = -1 and x = -5. Substituting these values into the equation, we get:
For x = -1, y = (-1)² + 6(-1) + 5 = 0
For x = -5, y = (-5)² + 6(-5) + 5 = 0
So, the solutions are (-1, 0) and (-5, 0).
To learn more about the quadratic equation;
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Urgent help!!!
*Picture included
Answer:
3x+4
Step-by-step explanation:
When you factor 9x^2+24x+16, it factors to (3x+4)^2
Factoring 9x^2 - 16 factors to (3x+4)(3x-4)
Therefore the common factor is 3x+4
I hope this helps!
if sine Theta is less than 0 and tan Theta is greater than 0 then
Answer:
Sine Theta is a negative number, Tan Theta is a greater number then zero.
Step-by-step explanation:
If Sine Theta is less then zero, she is a negative number. So 0 - y = -y.
So if Tan Theta is a greater number than zero, her number is not negative. So 0 + y = y
I hope this helped! I didn’t really understand the question though.
Find the slope of every line that is parallel to the line on the graph ob Enter the correct answer. 6 4 OOO DONE Clear al N ? (-8,0) 10-12 pop -6 ko 8 ४ 2 2 8 do
Step-by-step explanation:
x=-6 y= 0
x0 y= -1
y=mx+b
b= -1
0= -6m -1
-6m= 1
m= -1/6
parallel lines have the same slope
slope = -1/6
Identify the sampling technique used for the following study.
A statistics student interviews the last fifteen attendees to arrive.
A) Census
B) Stratified Sample
C) Systematic Sampling
D) Simple Random Sampling
E) Cluster Sampling
F) Convenience Sampling
Answer:
F) Convenience Sampling
Step-by-step explanation:
Samples may be classified as:
Convenient: Sample drawn from a conveniently available pool.
Random: Basically, put all the options into a hat and drawn some of them.
Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.
Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.
A statistics student interviews the last fifteen attendees to arrive.
Conveniently available, so convenience, and the correct answer is given by option F.
Today, 11:50
Sawing and cutting. Level
Arjun cut a loaf of bread and made
sandwiches. How many sandwiches did he
make if he made 10 cuts?
Answer:
5 sandwiches he made in bread
In a town. the population of registered voters is 46% democrat, 42% republican and 12% independent polling data shows 57% of democrats support the increase , 38% of republicans support the increase, and 76% of independents support the increase.
Required:
a. Find the probability that a randomly selected voter in the town supports the tax increase.
b. What is the probability that a randomly selected voter does not support the tax increase?
c. Suppose you find a voter at random who supports the tax increase. What is the probability he or she is a registered Independent?
Answer:
a) 0.513 = 51.3% probability that a randomly selected voter in the town supports the tax increase.
b) 0.487 = 48.7% probability that a randomly selected voter does not support the tax increase.
c) 0.1777 = 17.77% probability he or she is a registered Independent.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Question a:
57% of 46%(democrats)
38% of 42%(republicans)
76% of 12%(independents)
So
[tex]P = 0.57*0.46 + 0.38*0.42 + 0.76*0.12 = 0.513[/tex]
0.513 = 51.3% probability that a randomly selected voter in the town supports the tax increase.
Question b:
1 - 0.513 = 0.487
0.487 = 48.7% probability that a randomly selected voter does not support the tax increase.
c. Suppose you find a voter at random who supports the tax increase. What is the probability he or she is a registered Independent?
Event A: Supports the tax increase.
Event B: Is a independent.
0.513 = 51.3% probability that a randomly selected voter in the town supports the tax increase.
This means that [tex]P(A) = 0.513[/tex]
Probability it supports a tax increase and is a independent:
76% of 12%, so:
[tex]P(A \cap B) = 0.76*0.12[/tex]
Thus
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.76*0.12}{0.513} = 0.1777[/tex]
0.1777 = 17.77% probability he or she is a registered Independent.
Rewrite in simplest terms: (9x+5)-(-2x+10)(9x+5)−(−2x+10)
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { 18 {x}^{2} - 69x - 55}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex] = (9x + 5) - ( - 2 x+ 10)(9x + 5) - ( - 2x + 10)[/tex]
[tex] = (9x + 5) + 2x (9x + 5) - 10(9x + 5) - ( - 2x + 10)[/tex]
[tex] = 9x + 5 + 18 {x}^{2} + 10 x- 90x - 50 + 2x - 10[/tex]
Collect the like terms.
[tex] = 18 {x}^{2} + (9x + 10x- 90x + 2x) + (5 - 50 - 10)[/tex]
[tex] = 18 {x}^{2} + (21x - 90x) +(5 - 60)[/tex]
[tex] = 18 {x}^{2} - 69x - 55[/tex]
[tex]\boxed{ Note:}[/tex][tex]\sf\pink{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]
I need help with this math
Answer:
[tex]PQ=6\frac{1}{2} =\frac{13}{2}[/tex]
[tex]|Q-P|=\frac{13}{2}[/tex]
[tex]|Q+4|=\frac{13}{2}[/tex]
[tex]Q+4=+-\frac{13}{2}[/tex]
[tex]Q=-4[/tex] ± [tex]\frac{13}{2}[/tex]
[tex]Q=\frac{21}{2} \times2\frac{1}{2}[/tex]
[tex]Answer: C)~2\frac{1}{2}[/tex]
------------------------
Each shirt = $12.25
so, x = shirts = 12.25 x
cost including shipping= 77.49
So,
12.25 x + 3.99=77.49
Answer: D)
-------------------------
hope it helps...
have a great day!!
What is the range of the given set of ordered pairs?
(9,-2) (4,3) ( 8, 10) (-4, 8)
Answer:
(-2,3,10,8)
Step-by-step explanation:
eg
(x,y)=(domain,range)
x components are domain and y components are range in the given set of ordered pairs
ab=6cm ac=12 calculate the length of cd
Answer:
is that the full question?
Answer:
Solution:-
Given,
ab =perpendicular (p)= 6cm
ac =hypotenuse (h)= 12cm
cd =base (b)= ?
using , Pythagoras theorem we have ,
b²=√h²-p²
or,cd²=√ac²-ab²
= √12²-6²
= √144-36
=√108
=√10.8²
=10.8cm
the length of cd is 10.8 cm
hope it is helpful to you
Prove this plzzz help me
Answer:
Answer is in the picture. have a look
The systolic blood pressure of adults in the USA is nearly normally distributed with a mean of 120 and standard deviation of 18 . Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher. a. Around what percentage of adults in the USA have stage 2 high blood pressure
Answer:
The percentage of adults in the USA have stage 2 high blood pressure=98.679%
Step-by-step explanation:
We are given that
Mean, [tex]\mu=120[/tex]
Standard deviation, [tex]\sigma=18[/tex]
We have to find percentage of adults in the USA have stage 2 high blood pressure.
[tex]P(x\geq 160)=P(Z\geq \frac{160-120}{18})[/tex]
[tex]P(x\geq 160)=P(Z\geq \frac{40}{18})[/tex]
[tex]P(x\geq 160)=P(Z\geq 2.22)[/tex]
[tex]P(x\geq 160)=1-P(Z\leq 2.22[/tex]
[tex]P(x\geq 160)=0.98679[/tex]
[tex]P(x\geq 160)=98.679[/tex]%
Hence, the percentage of adults in the USA have stage 2 high blood pressure=98.679%
The manager of a donut store believes that 35% of the customers are first-time customers. A random sample of 150 customers will be used to estimate the proportion of first-time customers. Assuming this belief is correct, what is the probability that the sample proportion will be between 0.2 and 0.4
Answer:
0.8996 = 89.96% probability that the sample proportion will be between 0.2 and 0.4
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
The manager of a donut store believes that 35% of the customers are first-time customers.
This means that [tex]p = 0.35[/tex]
Sample of 150 customers
This means that [tex]n = 150[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.35[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.35*0.65}{150}} = 0.0389[/tex]
What is the probability that the sample proportion will be between 0.2 and 0.4?
p-value of Z when X = 0.4 subtracted by the p-value of Z when X = 0.2.
X = 0.4
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.4 - 0.35}{0.0389}[/tex]
[tex]Z = 1.28[/tex]
[tex]Z = 1.28[/tex] has a p-value of 0.8997
X = 0.2
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.2 - 0.35}{0.0389}[/tex]
[tex]Z = -3.85[/tex]
[tex]Z = -3.85[/tex] has a p-value of 0.0001
0.8997 - 0.0001 = 0.8996
0.8996 = 89.96% probability that the sample proportion will be between 0.2 and 0.4
Thomas Supply Company Inc. is a distributor of gas-powered generators. As with any business, the length of time customers take to pay their invoices is important. Listed below, arranged from smallest to largest, is the time, in days, for a sample of The Thomas Supply Company Inc. invoices.
13 13 13 20 26 29 32 33 34 34 35 35 36 37 38
41 41 41 45 46 47 47 48 52 54 55 56 62 67 82
(Round your answers to 2 decimal places.)
a. Determine the first and third quartiles.
Q1 =
Q3 =
b. Determine the second decile and the eighth decile.
D2 =
D8 =
c. Determine the 67th per
Answer:
Q1 = 32.5
Q3 = 50
D2 = 29
D8 = 52
67th percentile = 46.5
Step-by-step explanation:
Given the ordered data:
13, 13, 13, 20, 26, 29, 32, 33, 34, 34, 35, 35, 36, 37, 38, 41, 41, 41, 45, 46, 47, 47, 48, 52, 54, 55, 56, 62, 67, 82
The first quartile :
Q1 = 1/4(n+1)th term
n = sample size = 30
Q1 = 1/4(31) = 7.75 = (7th + 8th) / 2 = (32+33) / 2 = 32.5
Q3 = 3/4(n+1)th term
n = sample size = 30
Q3 = 3/4(31) = 23.25 = (23rd + 24th) / 2 = (48+52) / 2 = 50
D2 = 2nd decile
2 * 10% = 20%
20% * n
0.2 * 30 = 6th = 29
D8 = 8th decile
8 * 10% = 80%
80% * 30 = 24th = 52
67th percentile :
0.67 * 30 = 20.1 th
(20th + 21th) / 2
(46 + 47) / 2
= 46.5
Plss help Get brainiest if right!
The first side of a triangle is 2/3
as long as the second side. The
length of the third side of the triangle is 1/2 of the sum of the
first and second sides. Find the length of the sides of the triangle
if the perimeter is 50.
Answer:
In Picture
Step-by-step explanation:
Brainliest please~
a girl painted a rectangular-shaped portrait which is 10 inches long and 8 inches wide. if she trimmed 2/1/2 inches on both sides of the width and 2 inches on one side of the length, what would be the resulting area?
Answer:
32 in^2
Step-by-step explanation:
8-2=6, 6-2=4. 4 inches wide
10-2=8. 8 Inches tall.
4*8=32
A law firm offers some services “pro bono”, which means that they work for clients free of charge. The legal firm accepted 2% of its cases pro bono last year. What is the total of cases they completed if they accepted 252 pro bono cases?
Answer:
ok so we have to find 2% or 252 so
252*0.02=5.04
So they completed 5 cases this year
Hope This Helps!!!
What is the greatest common factor of 3^3 x 5^4 and 2 x 5^3 x 11?
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{3^3 \times 5^4}[/tex]
[tex]\mathsf{3^3}[/tex]
[tex]\mathsf{= 3\times3\times3}[/tex]
[tex]\mathsf{= 9\times3}[/tex]
[tex]\mathsf{= \bf 27}[/tex]
[tex]\mathsf{5^4}[/tex]
[tex]\mathsf{= 5\times 5\times5\times 5}[/tex]
[tex]\mathsf{= 25\times25}[/tex]
[tex]\mathsf{= \bf 625}[/tex]
[tex]\mathsf{27 \times625}[/tex]
[tex]\mathsf{= \bf 16,875}[/tex]
[tex]\mathsf{2\times5^3\times11}[/tex]
[tex]\mathsf{5^3}[/tex]
[tex]\mathsf{= 5\times 5\times5}[/tex]
[tex]\mathsf{= 25\times 5}[/tex]
[tex]\mathsf{\bf = 125}[/tex]
[tex]\mathsf{2\times125\times11}[/tex]
[tex]\mathsf{= 250\times11}[/tex]
[tex]\mathsf{\bf = 2,750}[/tex]
[tex]\large\textsf{Find the Greatest Common Factor (GCF) of 16,875 \& 2,750}[/tex]
[tex]\large\textsf{16,875: 1, 3, 5, 9, 15, 25, 27, 45, 75, 125, 135, 225, 375, 625, 675, 1,125,}\\\\\large\textsf{1,875, 3,375, 5,625, \& 16,875}[/tex]
[tex]\large\textsf{2,750: 1, 2, 5, 10, 11, 22, 25, 50, 55, 110, 125, 250, 275, 550, 1,375, \& 2,750}[/tex]
[tex]\boxed{\boxed{\huge\textsf{Answer: the GCF is \bf 125 }}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
solve 5x^2-2=-12 by taking the square root
Answer:
x = ±i√2
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality
Algebra II
Imaginary root i
i = √-1Step-by-step explanation:
Step 1: Define
Identify
5x² - 2 = -12
Step 2: Solve for x
[Addition Property of Equality] Add 2 on both sides: 5x² = -10[Division Property of Equality] Divide 5 on both sides: x² = -2[Equality Property] Square root both sides: x = ±√-2Rewrite: x = ±√-1 · √2Simplify: x = ±i√2Y=2x-8 and intercept at (-4,-1)
Answer:
y=2x+7
Step-by-step explanation:
y=2x-8
2 is the gradient.
-4 is x
-1 is y
-1=2(-4)+c
-1=-8+c
-1+8=c
c=7
therefore,
y=2x+7
Simplify the given expression below:
(4 + 21) – (1 – 71)
Hey there!
(4 + 21) - (1 - 71)
4 + 21 = 25
= 25 - (1 - 71)
1 - 71 = -70
= 25 - (-70)
= 25 + 70
= 95
Answer: 95
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
A football is punted so that its path is described by the function h(t) = -4.9(t - 3.5)2 + 15 where h(t) is the height of the football, in meters at time t, in seconds.
What time in seconds does it take for the football to reach its maximum height? Round your answer to the nearest tenth.
Answer:
Step-by-step explanation:
You already have this set up to answer your question. This quadratic is in work form, aka vertex form, where the vertex is (3.5, 15). The first coordinate of the vertex is the time it takes to reach its max height, which is the second coordinate of the vertex. So it takes 3.5 seconds to reach a max height of 15 meters.
Round your answer to one decimal digit. The volume of a cylinder is 1800cm squared. if the height of the cylinder is 40cm then the diameter of cylinder is
[tex]_____________________________________[/tex]
[tex]\sf\huge\underline\red{SOLUTION:}[/tex]
Use formula:
[tex]\sf{V = \pi(\frac{d}{2})^2h}[/tex]
Solving for diameter:
[tex]\sf d = 2 \times \sqrt{ \frac{V}{\pi h} } \\ \sf = 2 \times \sqrt{ \frac{40}{\pi \times 1800} } \approx0.16821 \\ = \sf \large\boxed{\sf{\green{d = 0.17}}}[/tex]
[tex]\sf\huge\underline\red{FINAL \: ANSWER}[/tex]
[tex]\large\boxed{\sf{\green{d=0.17}}}[/tex]
[tex]_____________________________________[/tex]
✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ
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