According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
Let's assume the mass of the receiver is denoted as "m" (in kg).
Before the collision:
Momentum of the tackler (p1) = mass of the tackler (m1) * velocity of the tackler (v1)
Momentum of the receiver (p2) = mass of the receiver (m) * velocity of the receiver (0, as the receiver is standing still)
After the collision:
Total momentum = momentum of the tackler + momentum of the receiver
The total momentum after the collision is:
Total momentum = (mass of the tackler + mass of the receiver) * velocity after the collision (3 m/s)
Since momentum is conserved, we can equate the total momentum before and after the collision:
p1 + p2 = (m1 * v1) + (m * 0) = (m1 * v1) = (m1 + m) * 3
Simplifying the equation, we get:
m1 * v1 = m1 * 3 + m * 3
m1 * v1 = 3 * (m1 + m)
Now we can substitute the given values into the equation. Given:
m1 = 100 kg
v1 = 4.0 m/s
Substituting the values, we have:
100 * 4.0 = 3 * (100 + m)
Simplifying the equation:
400 = 300 + 3m
3m = 100
m = 100 / 3 ≈ 33.33 kg
Therefore, the mass of the receiver is approximately 33.33 kg.
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For the beam and loading shown, determine the minimum required width 6, knowing that for the grade of timber used, Call = 18 MPa and Tall = 975 kPa. b = 43 mm Х 2.0 kN 6.8 KN 8.4 kN B D E 300 mm 4 m 4 m 4m 0.50 m
The minimum required width b of the beam is 200 mm.
The following steps were used to calculate the minimum required width:
Calculate the maximum bending moment Mmax at the center of the beam.
Mmax = (2.0 kN)(4 m) + (6.8 kN)(4 m) + (8.4 kN)(4 m) = 67.2 kNm
Calculate the required modulus of section Z to resist the maximum bending moment.
Z = Mmax / Tall = 67.2 kNm / 975 kPa
Z = 68.8 cm^3
Calculate the required cross-sectional area A of the beam.
A = Z / b = 68.8 cm^3 / 200 mm
A = 0.344 m^2
Calculate the required width b of the beam.
b = A / h = 0.344 m^2 / 0.50 m = 0.688 m
b= 200 mm
The minimum required width of the beam is 200 mm.
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Discuss whether any work is being done by each of the following agents and, if so, whether the work is positive or negative. (c) a crane lifting a bucket of concrete
The crane lifting the bucket of concrete is doing positive work as it applies a force in the direction of the displacement.
In the case of a crane lifting a bucket of concrete, work is indeed being done. The work done by the crane can be determined by the equation:
Work = Force x Distance x cos(θ)
Here, the force is the upward force exerted by the crane on the bucket, the distance is the vertical displacement of the bucket, and θ is the angle between the force and the displacement.
Since the crane is lifting the bucket upward, the force exerted by the crane and the displacement of the bucket are in the same direction. Therefore, the angle θ between them is 0 degrees, and the cosine of 0 degrees is 1. As a result, the work done by the crane is positive.
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