A rectangle has dimension 23cm by 41cm and is made with a piece of wire How long will each length be for an equilateral triangle?

Answers

Answer 1

Each side of equilateral triangle will have the length equals to 42.7 cm.

Quadrilaterals

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram.  Each type is defined accordingly to its length of sides and angles. For example, in a rectangle,  the opposite sides are equal and parallel and their interior angles are equal to 90°.

The perimeter of a geometric figure is the sum of its sides. Thus, for a rectangle, the perimeter is 2L+2W.

You should find the perimeter of the rectangle.

2P=23+23+41+41= 128 cm

The equilateral triangle will have the same perimeter of the rectangle. An equilateral triangle presents the equal three sides, thus,

128= 3L

L=128/3=42.7 cm

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Related Questions

What is the solution to 3/2b + 5 < 17? Explain How.
(1) b < 8

(2) b > 8

(3) b < 18

(3) b > 18

Answers

3/2b + 5 < 17

We subtract 5 from both sides of the inequality.

3/2b + 5 - 5 < 17 - 53/2 b < 12

Multiply both sides by 2/3.

( 2/3) * (3/2b) < (2/3) * 12b < 8

Therefore, the correct option is alternative "A".

We would think that it is option B, but the only difference is that it changes the direction of the sign.

Answer:  [A]: " b < 8 " .
_____

Step-by-step explanation:

Given:
Find the solution to:   " 3/2b + 5 < 17 " ; and choose from the answer choices.

So; we have:  

 (3/2)b + 5 < 17  ;

 Now, subtract "5" from each side of this inequality:
 (3/2)b + 5 − 5  <  17 − 5  ;

   To get:
  (3/2)b  <  12 ;

Now, let's multiply Each Side of this inequality by "2" ;

 to get rid of the fraction:

    "  2*(3/2)b  <   12*2 "  ;

{Note: " [tex]2 *\frac{3}{2}=\frac{2}{1}*\frac{3}{2}[/tex] " } ;

Note:  To simplify:  " [tex]\frac{2}{1} * \frac{3}{2}[/tex] " ;
   Note the "2" in the denominator in the "first term" ;  

   And:  The "2" in the denominator in the "second term" ;

      Both "cancel out" to "1" ;  since:  "[ 2 / 2 = 2÷2 = 1 ]" ;

   And:  we have:  " [tex]\frac{1}{1}*\frac{3}{1}= 1 *3 = 3[/tex] " };

_____
and rewrite:
   " 3b < 24 "  ;

Now, divide Each side of the inequality by "3" ;

 to isolate "b" on one side of the inequality;

and to solve for "x" ;
_____
 " 3b/3 < 24/3 " ;

 to get:

_____

   " b < 8 " ; which corresponds to the correct answer:

Answer choice:  [A]:  " b < 8 " .
_____

Hope this is helpful to you! Best wishes!
_____

Need help with my math please. 31-41.

Answers

Answer:

31: 98,765 x 9 + 3 = 888,888

32: 12.345 x 9 + 6 = 111,111

33: 3,367 x 15 = 50,505

34: 15,873 x 35 = 555,555

35: 33,334 x 33,334 = 1,111,155,556

36: 11,111 x 11,111 = 123,454,321

You skipped 37-39

40: 3 + 9 + 27 + 81 + 243 = 3(243-1)/2

41: 1/2 + 1/4 + 1/8 + 1/16 + 1/32 = 1 - 1/32

Step-by-step explanation:

It's just patterns bro

Thomas and Matthew are saving up money to buy a video game together. Thomas has saved $30. Matthew has saved $35. How much money have they saved up together in total?

Answers

Answer: $65

Step-by-step explanation:

Thomas saved $30

Matthew saved $35

 Saved up together in total is asking how much money they got together which addtion.

so we do 30 +35 which is $65

The data set below has 7 values. Find the mean absolute deviation for the data set. If necessary, round your answer to the nearest hundredth. 14, 13, 16, 12, 17, 21, 26

Answers

Answer:

Hey stu132057, your the MAD for the data set given is

Step-by-step explanation:

Step 1: Find the mean of the data: (14+13+16+12+17+21+26)/7 = 17

Step 2: Find the difference between each data and mean:Difference between 14 and 17 is 3

Difference between 13 and 17 is 4

Difference between 16 and 17 is 1

Difference between 12 and 17 is 5

Difference between 17 and 17 is 0

Difference between 21 and 17 is 4

Difference between 26 and 17 is 9

Step 3: Add all the differences: 3+4+1+5+0+4+9 = 26

Step 4: Divide it by the number of data:26/7 = 3.7

So, the MAD = 3.7

-------------------------

Have a great day,

Nish

Line segment st is dilated to create line segment s't' using the dilation rule dq,2.25. point q is the center of dilation. line segment s t is dilated to create line segment s prime t prime. the length of q t is 1.2 and the length of q s is 2. the length of s s prime is x and the length of t t prime is 1.5. what is x, the distance between points s' and s?

Answers

The distance between points S' and S is 2.5 units.

What is proportionality theorem in triangles?

If a line is drawn parallel to any one side of a triangle so that it intersects the other two sides in two distinct points, then the other two sides of the triangle are divided in the same ratio.

Given that,

line segment ST is dilated to create line segment S'T' using the dilation rule DQ.

Also, SQ = 2 units, TQ = 1.2 units, TT'=1.5 units, SS' = x units.

We need to find the value of x, the distance between points S' and S.

Since the line ST is dilated to S'T' with center of dilation Q, so the triangles STQ and S'T'Q must be similar.

We know that the corresponding sides of two similar triangles are proportional.

So, from ΔSTQ and ΔS'T'Q, we get

[tex]\frac{SQ}{S'Q} =\frac{TQ}{T'Q}[/tex]

[tex]\frac{SQ}{SQ+S'S} =\frac{TQ}{TQ+T'Q}[/tex]

[tex]\frac{2}{2+x} =\frac{1.2}{1.2+1.5}[/tex]

[tex]\frac{2}{2+x} =\frac{1.2}{2.7}[/tex]

[tex]\frac{2}{2+x} =\frac{12}{27}[/tex]

[tex]\frac{1}{2+x} =\frac{6}{27}[/tex]

12+6x = 27

6x = 15

x = 2.5

Hence, Thus, the required value of x is 2.5 units.

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Find parametric equation for the tangent line to the curve given by x(t)=e^-t cos(t), y(t) =e^-t sin(t), z(t)=e^-t and point p(1,0,1)

Answers

The parametric equation for the tangent line to the curve is x = 1 - t, y = t, z = 1 - t.

For this question,

The curve is given as

x(t)=e^-t cos(t),

y(t) =e^-t sin(t),

z(t)=e^-t

The point is at (1,0,1)

The vector equation for the curve is

r(t) = { x(t), y(t), z(t) }

Differentiate r(t) with respect to t,

x'(t) = -e^-t cos(t) + e^-t (-sin(t))

⇒ x'(t) = -e^-t cos(t) - e^-t sin(t)

⇒ x'(t) = -e^-t (cos(t) + sin(t))

y'(t) = - e^-t sin(t) + e^-t cos(t)

⇒ y'(t) = e^-t ((cos(t) - sin(t))

z'(t) = -e^-t

Then, r'(t) = { -e^-t (cos(t) + sin(t)), e^-t ((cos(t) - sin(t)), -e^-t }

The parameter value corresponding to (1,0,1) is t = 0. Putting in t=0 into r'(t) to solve for r'(t), we get

⇒  r'(t) = { -e^-0 (cos(0) + sin(0)), e^-0 ((cos(0) - sin(0)), -e^-0 }

⇒  r'(t) = { -1(1+0), 1(1-0), -1 }

⇒  r'(t) = { -1, 1, -1 }

The parametric equation for line through the point (x₀, y₀, z₀) and parallel to the direction vector <a, b, c > are

x = x₀+at

y = y₀+bt

z = z₀+ct

Now substituting the (x₀, y₀, z₀) as (1,0,1) and <a, b, c > into x, y and z, respectively to solve for the parametric equation of the tangent line to the curve, we get

x = 1 + (-1)t

⇒ x = 1 - t

y = 0 + (1)t

⇒ y = t

z = 1 + (-1)t

⇒ z = 1 - t

Hence we can conclude that the parametric equation for the tangent line to the curve is x = 1 - t, y = t, z = 1 - t.

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Find the volume of the cylinder shown using the formula in the box below. Round your answer to the nearest tenth. Show your work

Answers

Answer: 1960.2 cm

Step-by-step explanation:

v = πr^2h

v = π7.4^2(11.4)

= π54.76(11.4)

= 171.9464(11.4)

= 1960.2

The volume of the cylinder rounded to the nearest tenth is 1,960.2 cubic cm

What is the volume of the cylinder?

Volume of the cylinder = πr²h

Where,

r = radius = 7.4 cm

h = height = 11.4 cm

π = 3.14

So,

Volume of the cylinder = πr²h

= 3.14 × 7.4² × 11.4

= 3.14 × 54.76 × 11.4

= 1,960.18896

Approximately to the nearest tenth

= 1,960.2 cubic cm

Therefore, 1,960.2 cubic cm is the volume of the cylinder with radius 7.4 cm and height 12.4 cm

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Can someone explain step by step how to do this problem? Thanks! Calculus 2

Answers

Answer:

  1.314 MJ

Step-by-step explanation:

As water is removed from the tank, decreasing amounts are raised increasing distances. The total work done is the integral of the work done to raise an incremental volume to the required height.

There are a couple of ways this can be figured. The "easy way" involves prior knowledge of the location of the center of mass of a cone. Effectively, the work required is that necessary to raise the mass from the height of its center to the height of the discharge pipe.

The "hard way" is to write an expression for the work done to raise an incremental volume, then integrate that over the entire volume. Perhaps this is the method expected in a Calculus class.

Mass of water

The mass of the water being raised is the product of the volume of the cone and the density of water.

The cone volume is ...

  V = 1/3πr²h . . . . . . for radius 2 m and height 8 m

  V = 1/3π(2 m)²(8 m) = 32π/3 m³

The mass of water in the cone is then ...

  M = density × volume

  M = (1000 kg/m³)(32π/3 m³) ≈ 3.3510×10^4 kg

Center of mass

The center of mass of a cone is 1/4 of the distance from the base to the point. In this cone, it is (1/4)(8 m) = 2 m from the base.

Easy Way

The discharge pipe is 2 m above the base of the cone, so is 4 m above the center of mass. The work required to lift the mass from its center to a height of 4 m above its center is ...

  W = Fd = (9.8 m/s²)(3.3510×10^4 kg)(4 m) = 1.3136×10^6 J

Hard Way

As the water level in the conical tank decreases, the remaining volume occupies a space that is similar to the entire cone. The scale factor is the ratio of water depth to the height of the tank: (y/8). The remaining volume is the total volume multiplied by the cube of the scale factor.

  V(y) = (32π/3)(y/8)³

The differential volume at height y is the derivative of this:

  dV = π/16y²

The work done to raise this volume of water to a height of 10 m is ...

  (9.8 m/s²)(1000 kg/m³)(dV)((10 -y) m) = 612.5π(y²)(10 -y) J

The total work done is the integral over all heights:

  [tex]\displaystyle W=612.5\pi\int_0^8{(10y^2-y^3)}\,dy=\left.612.5\pi y^3\left(\dfrac{10}{3}-\dfrac{y}{4}\right)\right|_0^8\\\\W=612.5\pi\dfrac{2048}{3}\approx\boxed{1.3136\times10^6\quad\text{joules}}[/tex]

It takes about 1.31 MJ of work to empty the tank.

Find the first four nonzero terms in a power series expansion about x0 for a general solution to the given differential equation. 0

Answers

Answer:

Start with equation,

         y''(x) = f(x) = 6y/(10x-x²)               about point x₀ = 5

Then,

       y(x) = a₀ + a₁(x-5) + a₂(x-5)²+ a₃(x-5)³ + a₄(x-5)⁴...….

by inspection,

           y(5) = a₀      and       y'(5) = a₁

then,

y''(5) = 6a₀/(50-25) = 6a₀/25              

y'''(x) = 6y'/(10x-x2) - 6y(10-2x)/(10x-x2)2

then,                      

                              y'''(5) = 6a₁/25 - 0 = 6a₁/25                

y''''(x) = 6y''/(10x-x2) -12y'(10-2x)/(10x-x2)² + 12y/(10x-x2)² + 12y(10-2x)2/(10x-x2)³

then,

    y''''(5) = (6/25)(6a₀/25) + 0 + 12a₀/625 + 0

              = 48a₀/625

So,

y(x) = f(x) = f(5) + f'(5)(x-5) + f''(5)(x-5)2/2! + f'''(5)(x-5)3/3! + f''''(5)(x-5)4/4! …

                                                       or

y(x) = f(x) = a₀ + a₁(x-5) + (6ao/25)(x-5)2/2! + (6a1/25)(x-5)3/3! + (48a₀/625)(x-5)4/4!...

                                                         or

y(x) = f(x) = a₀ + a₁(x-5) + (3a₀/25)(x-5)²+ (a₁/25)(x-5)³+ (2a₀/625)(x-5)⁴.....

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what function has a growth factor of 3

what function has an initial value of 2

what function has an initial value of 0.2

what function has an initial value of 1

what function has a decay factor of 0.2

what functions are increasing across real numbers?

what functions are decreasing across all real numbers?

Answers

Step-by-step explanation:

y = a(b^x)

a = initial value

If b > 0 and b < 1, then 1 - b is the decay factor.

If b > 1, then b is the growth factor.

what function has a growth factor of 3

Function 3

what function has an initial value of 2

Function 2

what function has an initial value of 0.2

Function 4 since 1/5 = 0.2

what function has an initial value of 1

Function 3

what function has a decay factor of 0.2

None. In Function 2, the decay factor is 1 - 1/5 = 0.8, not 0.2.

what functions are increasing across real numbers?

Functions 3, 4

what functions are decreasing across all real numbers?

Functions 1, 2

Find the perimeter of the shaded figure. PLS ASAP

Answers

Answer:

54

Step-by-step explanation:

In the circle below, AB is a diameter. Suppose stack CB equals 32 degrees and m angle B C D equals 52 degrees.

Find the following. Type your numerical answers (without units) in each blank.

Answers

The 32° measure of arc CB, and m<BCD which is 52° gives m<BAC and m<ACB as 16° and 90° respectively, from which we have;

m<CBA = 74°

m<ACD = 38°

Which circle theory can be used to find the required angles?

First part;

Given;

Angle subtended by arc CB = 32°

m<BCD = 52°

Based on circle theory, we have;

Angle subtended by an arc at the center of a circle is twice the angle subtended at the circumference

Therefore;

Arc CB = 2 × m<BAC

Which gives;

Arc CB = 32° = 2 × m<BAC

m<BAC = 32° ÷ 2 = 16°

Angle subtended by the diameter at the circumference is 90°.

Therefore;

m<ACB = 90°

In triangle ∆ABC, we have;

m<ACB + m<BAC + m<CBA = 180°

m<CBA = 180° - (m<ACB + m<BAC)

Therefore;

m<CBA = 180° - (90° + 16°)

m<CBA = 180° - (90° + 16°) = 74°

m<CBA = 74°

Second part;

The arc subtending m<ACD is AB which is also the diameter.

Angle formed by the diameter, which is a straight line = 180°

Therefore;

Angle subtended at the center by arc AB = 180°

Angle subtended at the circumference, m<ACB is therefore;

m<ACB = 180° ÷ 2 = 90°

A

m<ACB = m<ACD + m<BCD (Angle addition property)

Therefore;

90° = m<ACD + 52°

m<ACD = 90° - 52° = 38°

m<ACD = 38°

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Geometry: complete this proof, ASAP!!!! It’s urgent

Answers

Answer:

1. Given.

2. Triangle Exterior Angle Theorem.

3. Definition of Equilateral Triangles.

4. Substitution Property of Equality.

5. Addition Property of Equality.

In the accompanying diagram, three vertices of parallelogram ORST are O(0,0), R(b,d), and T (a,0). What are the coordinates of S

Answers

Based on the coordinates of the vertices of the parallelogram ORST, the coordinates of S can be found to be (a + b, d).

What are the coordinates of point S?

As this is a parallelogram, the horizontal distance between O and R would be the same as the horizontal distance between S and T.

The horizontal distance between O and R is represented by "b".

The horizontal distance between T and S would therefore be:

= a + b

The fact that R and S are on the same plane would mean that the y-value of S is the same as that of R which is d.

The coordinates of S is:

( a + b, d).

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A locker combination consists of two non-zero digits. the digits in a combination are not repeated and range from 2 through 9. event a = the first digit is an odd number event b = the second digit is an odd number if a combination is picked at random with each possible locker combination being equally likely, what is p(b|a) expressed in simplest form? a. b. c. d.

Answers

The P(B|A) expressed in the simplest form will be (B) 2/7.

What is probability?Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true. The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

To find the P(B|A) expressed in the simplest form:

Given -

Event A = the first digit is less than 5Event B = the second digit is less than 5

Total possible numbers = 2,3,4,5,6,7,8,9

Let the value of the number be AB.

The total possible values below 5 are 2,3, and 4.The probability of the first digit is less than 5, P(A) = 3/8.The second digit is less than 5, P(B/A) = 2/7.

Therefore, the P(B|A) expressed in the simplest form will be (B) 2/7.

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The complete question is given below:
A locker combination consists of two non-zero digits. The digits in a combination are not repeated and range from 2 through 9.

Event a = a first digit is an odd number

Event b = the second digit is an odd number

If a combination is picked at random with each possible locker combination being equally likely, what is P(B/A) expressed in the simplest form?

A.1/4

B.2/7

C.4/9

D.1/2

A 105
5) How will you educated, uneducated people in your locality
about the environment problems of your locallly.
I will educated uneducated people on my locality

Answers

Get your associates, neighbors, friends, family, or even your local government concerned. It's much more comfortable and more useful to apply environmental attention and create a local project if you cooperate with others in our community.

How to improve the uneducated people in our locality about the environmental problems of our local?

Get your associates, neighbors, friends, family, or even your local government concerned. It's much more comfortable and more useful to apply environmental attention and create a local project if you cooperate with others in our community. Encouraging environmental awareness exists a vital aspect of being an environmental guardian.

Facilitate knowledge transfer from workers approaching retirement to workers of all ages. Work with families to support children in school and control illiteracy. Provide young people from deprived backgrounds the norms to study. Improve access to education for Aboriginal people.

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5- Calculate the radius of a circle whose area is equal to the sum of the areas of 3 circles of radii 2cm, 3cm and 4cm
respectively.​

Answers

the radius of the new circle =5cm

5cm is your answer love

Henry will need a total of 15 pints of paint. The 3 pints of yellow were multiplied by 3 to get 9 total, so 2 pints of red would be multiplied by 3 to get 6 total.

Which ideas did you include in your response? Check all that apply.
Henry will need 15 pints altogether.
The number of pints of yellow (3) is multiplied by 3 to get 9, so he would multiply 2 by 3 to get 6 pints of red.
Add: 6 + 9 = 15 pints.

Answers

Answer:

All answers are correct.

Step-by-step explanation:

Henry needs a total of 15 pints.

3 pints of yellow multiplied by 3 gives 9 pints of yellow, he needs 6 pints of red to get to 15, so he multiplies 2 pints of red by 3 to get 6 pints of red.

You add 9 + 6 to get the total of 15 pints he needs.

How many faces, edges and vertices does the shape below have?
Faces:
Edges:
Vertices:

Answers

Faces:7
Edges:15
Vertices:10

An Escalator Moves At The Rate Of 2 Feet Per Second. At What Rate Does The Escalator Move In Miles Per Hour?
A)0.02 mph
B)0.34 mph
C)0.68 mph
D)1.36 mph

Answers

Answer:

1.36mph

Step-by-step explanation:

The escalator is moving at 2ft/s, lets convert this to miles/second.

2ft/s = 0.000378788miles/s.

Now that we have the miles/second lets multiply this value by 3600 to get the miles/h, because there are 3600 seconds in an hour.

2ft/s=1.3636368miles/h

Or approximately 1.36miles/h.

Consider this function. f ⁡ ( x ) = 1 /2 ⁢ x + 1 /4 Which graph represents the inverse of function f? Which graph represents the inverse of function f?

Answers

The inverse function of f(x) = 1/2x + 1/4 is f-1(x) = 2x - 1/2

How to determine the graph of the inverse function?

The function is given as:

f(x) = 1/2x + 1/4

Rewrite the function as

y = 1/2x + 1/4

Swap the positions of x and y

x = 1/2y + 1/4

Multiply through by 4

4x = 2y + 1

Subtract 1 from both sides

2y = 4x - 1

Divide by 2

y = 2x - 1/2

Rewrite as an inverse function

f-1(x) = 2x - 1/2

Hence, the inverse function of f(x) = 1/2x + 1/4 is f-1(x) = 2x - 1/2

See attachment for the graph of the inverse function

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Answer:

Step-by-step explanation:

e graph opens upward, and it has a vertex of (0,0)

What is vertex?

The vertex of an equation is the minimum or the maximum point on the graph of the equation

The equation of the graph is given as:

The above equation represents an absolute value function

An absolute value function is represented as:

So, by comparison, we have:

This means that the graph opens upward, and it has a vertex of (0,0)

See attachment for the graph of

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If f (x) = startroot 4 x 9 endroot 2, which inequality can be used to find the domain of f(x)?

Answers

The domain of the given function [tex]f(x) = \sqrt{(4x + 9)} + 2[/tex].

So long as x ≥ -9/4, the function f(x) will be defined.

How to find the domain of the function [tex]f(x) = \sqrt{(4x + 9)} + 2[/tex]?

Given: "f(x) = Startroot 4 x + 9 Endroot + 2" should be written as

[tex]f(x) = \sqrt{(4x + 9)} + 2[/tex].

Note that [tex]$\sqrt{(4x + 9)}[/tex] exists a variation of the basic function [tex]y = \sqrt{x}[/tex], whose domain exists [0, ∞ ).

The domain of [tex]$f(x) = \sqrt{(4x + 9) }+ 2[/tex] exists seen by taking the "argument" 4x + 9 of [tex]\sqrt{(4x + 9)}[/tex]and setting it equivalent to zero:

4x + 9 ≥ 0

simplifying the equation, we get

4x ≥ -9

x ≥ -9/4

This exists the domain of the given function [tex]f(x) = \sqrt{(4x + 9)} + 2[/tex].

So long as x ≥ -9/4, the function f(x) will be defined.

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Answer:

B

Step-by-step explanation:

I tink old up

no its BBBBB

Chris bought 11 watermelons for his 11th birthday. The first watermelon weighed 1 pound, the second 2 pounds, the third 3 pounds and so on, Can he divide all of his watermelons into two groups with the same weight?

Answers

Answer:

ther r 2group 5%

i hope this is helpful to you

Write 2^8 * 8^2 * 4^-4 in the form 2^n

Answers

The given expression 2^8 * 8^2 * 4^-4 can be written in the exponential form 2^n as 2^6.

What are exponential forms?

The exponential form is a more convenient way to write repetitive multiplication of the same integer by using the base and its exponents.

For example:

If we have a*a*a*a, it can be written in exponential form as:

=a^4

where

a is the base, and4 is the power.

The power in this format reflects the number of times we multiply the base by itself. The exponent is also known as the index or power

From the information given:

We can write 2^8 * 8^2 * 4^-4 in form of 2^n as follows:

[tex]\mathbf{= 2^8\times (2^3)^2 \times (2^2)^{-4} }[/tex]

[tex]\mathbf{= 2^8\times (2^6) \times (2^{-8}) }[/tex]

[tex]\mathbf{= 2^{8+6+(-8)}}[/tex]

[tex]\mathbf{= 2^{6}}[/tex]

Therefore, we can conclude that by using the exponential form, the given expression 2^8 * 8^2 * 4^-4 in the form 2^n is 2^6.

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What is the equation of a line in point-slope form passing through (-4,6) and (2, 3)?

Answers

Answer:

[tex]y-3=-\frac{1}{2}(x-2)[/tex]

Step-by-step explanation:

The slope is

[tex]\frac{6-3}{-4-2}=-\frac{1}{2}[/tex]

So, using the point (2,3), the equation is

[tex]y-3=-\frac{1}{2}(x-2)[/tex]

Triangle X Y Z is shown. Angle X Z Y is a right angle. The length of Z X is b, the length of Z Y is a, and the length of hypotenuse X Y is c.
Given right triangle XYZ, which correctly describes the locations of the sides in relation to ∠Y?

Answers

In triangle XYZ, angle X Z Y is a right angle. The length of Z X is b, the length of Z Y is a, and the length of hypotenuse X Y is c. Then, the side XZ which is the perpendicular, is opposite to ∠Y. Side XZ is adjacent to the ∠Y, and side ZY, which is the base, is also adjacent to ∠Y. We can say that ∠Y has been formed by the sides XZ and ZY.

It is given that,

In triangle X Y Z, angle X Z Y is a right angle or 90°.

The length of the hypotenuse XY is c.

⇒ The side with length c is adjacent to ∠Y.

The sides XZ and ZY form the right angle, thus one is base and the other is perpendicular.

Now, in relation to ∠Y, side ZY of length a is the base (adjacent to angle Y)

Similarly, side XZ of length b forms the perpendicular and is opposite to ∠Y.

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if AB = 3 centimeters and AC = 2 centimeters, what is the largest possible perimeter, in centimeters, of isosceles triangle ABC?

Answers

Answer:

8

Step-by-step explanation:

AB is 3 cm and AC is 2 cm, and since triangle ABC is an isosceles triangle, BC can either be 3 cm or 2 cm. We want the longest perimeter possible, so make BC 3 cm, and add the side lengths to find the perimeter.

P = 3 + 3 + 2 = 8.

if an average orange weighs 75 g, how many oranges would weigh 4.5 kg?​

Answers

Answer: 60 oranges

Step-by-step explanation:

Given information

Weight = 75 g / orange

Total = 4.5 kg

Given formula

Total = Number of oranges × Average weight

Convert Kilogram unit to Gram

1 kg = 1000 g

4.5 kg = 4.5 × 1000 = 4500 g

Substitute values into the given formula

Total = Number of oranges × Average weight

Number of oranges = Total / Average weight

Number of oranges = 4500 / 75

Simplify by division

[tex]\Large\boxed{Number~of~oranges~=~60}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

60 oranges

Step-by-step explanation:

Let the unknown number of oranges be x.Given that,

    The average weight of an orange ⇒ 75g

     Total weight of oranges ⇒ 4.5 kg

Therefore,

      Number of oranges                       Weight ( in grams)

              1                                                   75 g

              x                                                   (4.5 × 1000) g

To find the number of oranges we can make an expression like this.

        1  ⇒  75

        x  ⇒ 4500

      Use cross multiplication and find the value of x.

         75x = 4500 × 1

         75x = 4500

     Divide both sides by 75.

           x = 60

Therefore, 60 oranges would weight 4.5kg

Give the equation of a line that has
a. no x-intercept
b. one x-intercept and one y-intercept
c. an infinite number of x-intercepts.
d. a y-intercept of -7.

Answers

a. x=5

b. y=x

c. y=0

d. y=x-7

Geometry: write formal proofs, ASAP!!!!!

Answers

Two lines are said to be parallel if and only if the value of the angle between them is [tex]180^{o}[/tex].

Thus the required proofs for each question are stated below:

6. A bisector is a line that divides a given line or angle into two equal parts.

Thus to prove that: AD ║BC

Given that: AC ⊥ BD, then:

BX ≅ DX (midpoint property of a line)

<ADX ≅ <DBX (alternate angle property)

<DAX ≅ <BCX (alternate angle property)

<AXD ≅ <BXC (vertical opposite angle property)

Also,

ΔAXD ≅ ΔBXC (congruent property of similar triangles)

Therefore, it can be deduced that;

AD ║BC

7. Given: CD ≅ CE

<B ≅ <D

proof: AB ║DE

<ABC  ≅EDC

Thus,

CB  ≅ CA (congruent property of similar triangle)

<BAC  ≅ <EDC (alternate angle property)

ABC  ≅ <DEC (alternate angle property)

Also,

CA ≅ CB (congruent side of similar triangles)

ΔABc ≅ ΔCDE (congruent property of similar triangles)

Thus,

AB ║DE (congruent property)

8. Prove: AB ║ DE

Given: <1 ≅ < 3

Then,

<1 ≅ <2 ≅ <3 ≅ [tex]90^{o}[/tex]

So that,

BC ≅ EF

also,

<1 + <2 = [tex]180^{o}[/tex] (supplementary angles)

Therefore it can be inferred that;

AB ║ DE (congruent property of parallel lines intersected by transversals)

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