A spinner is divided into three equal parts A, B, and C. The repeated experiment of spinning the spinner twice is simulated 125 times. A table of outcomes is shown.


Outcome Frequency
A, A 15
A, B 12
A, C 10
B, A 18
B, B 15
B, C 17
C, A 11
C, B 13
C, C 14

Based on the table, for what probability can you expect the spinner to not land on A?
0.66
0.47
0.33
0.10

Answers

Answer 1

The probability of the spinner not landing on A is 0.47.

How to find the probability you can expect the spinner to not land on A?

To find the probability that the spinner does not land on A, we need to add up the frequencies of the outcomes where A does not appear, which are (B,B), (B,C), (C,B), and (C,C):

Frequency of not landing on A = Frequency(B,B) + Frequency(B,C) +  Frequency(C,B) + Frequency(C,C)

Frequency of not landing on A = 15 + 17 + 13 + 14 = 59

The total number of outcomes is 125, so the probability of not landing on A is:

P(not A) = Frequency of not landing on A / Total number of outcomes

P(not A) = 59 / 125 = 0.47

Therefore, the probability of the spinner not landing on A is 0.47.

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Related Questions

If a random variable X has exponential distribution with mean 1 then P[X > 2] is
a. 1- e^-2 b. e^2 c. e^-2
d. 1-e²

Answers

The correct answer is option a. 1 - e^-2.

To find the probability of a random variable X with exponential distribution, we use the following formula:P[X > x] = e^(-λx)Where λ is the rate parameter and x is the value we are trying to find the probability of.

In this case, we are given that the mean of the distribution is 1, so we can use this information to find the rate parameter:λ = 1/mean = 1/1 = 1Now, we can plug in the values for λ and x into the formula to find the probability:P[X > 2] = e^(-1*2) = e^-2 = 0.1353Therefore, the correct answer is option a. 1 - e^-2.

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A company establishes a sinking fund to pay a debt of $150,000 due in 4 years. At the beginning of each six-month period, they deposit $R in an account paying 9%, compounded semi-annually. How big must the payments be to pay the debt on time? ANSWER: ____dollars

Answers

A company establishes a sinking fund to pay a debt of $150,000 due in 4 years. The required payment at the beginning of each six-month period is $6,235.54.

The sinking fund payment will earn interest at a rate of 9% per year, compounded semi-annually. This means the effective interest rate per six-month period is [tex](1 + 0.09/2)^2 - 1 = 0.045 = 4.5%[/tex]

Using the formula for the future value of an annuity, [tex]FV = R[((1+r)^n - 1)/r][/tex], where r is the interest rate per period and n is the number of periods, we can calculate the required payment R as:

[tex]150,000 = R[((1+0.045)^8 - 1)/0.045][/tex]

R = 6,235.54

Therefore, the company needs to make payments of $6,235.54 at the beginning of each six-month period to accumulate enough money in the sinking fund to pay off the $150,000 debt in 4 years.

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Find f ∘ g, g ∘ f, and g ∘ g.
f(x) = x4, g(x) = 1/x
(a)
f ∘ g
(b)
g ∘ f
(c)
g ∘ g

Answers


Hello there! To find f ∘ g, g ∘ f, and g ∘ g, let's first recall the definition of function composition: given two functions f and g, their composition f ∘ g is defined as the function that results from applying g to the result of applying f to its argument. Specifically, for a given input x, we can express the composition f ∘ g as follows: (f ∘ g)(x) = f(g(x)).

Given f(x) = x4 and g(x) = 1/x, we can find each composition as follows:

(a) f ∘ g = f(g(x)) = f(1/x) = (1/x)4

(b) g ∘ f = g(f(x)) = g(x4) = 1/(x4)

(c) g ∘ g = g(g(x)) = g(1/x) = 1/(1/x) = x

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The continuous random variable X has probability density function given by f(x) = 0.1 + kx where 0 ≤ x ≤ 5 0 otherwise (a) Find the value of the constant, k, which ensures that this is a proper density function. (b) Evaluate E[X], and var[X]. (c) If G = 5X − 6, obtain the mean and standard deviation of G. (d) If H = 5 − 6X, obtain the mean and standard deviation of H.

Answers

a) The value of k is 0.04.

b) The value of E[X] is 3.3333 and the value of var[X] is 1.3889.

c) The standard deviation of G is 5.8916.

d) The standard deviation of H is 7.0711.

(a) To find the value of k that ensures that f(x) is a proper density function, we need to ensure that the integral of f(x) over its domain is equal to 1:

∫05 (0.1 + kx) dx = 1

0.5 + 12.5k = 1

12.5k = 0.5

k = 0.04

Therefore, the value of k is 0.04.


(b) To find E[X], we need to evaluate the integral of x*f(x) over its domain:

E[X] = ∫05 x(0.1 + 0.04x) dx

E[X] = 0.5 + 0.02(125/3) = 3.3333

To find var[X], we need to evaluate the integral of (x - E[X])2*f(x) over its domain:

var[X] = ∫05 (x - 3.3333)2(0.1 + 0.04x) dx = 1.3889


(c) If G = 5X - 6, then E[G] = 5E[X] - 6 = 11.6667 and var[G] = 52var[X] = 34.7225. The standard deviation of G is the square root of var[G], which is 5.8916.


(d) If H = 5 - 6X, then E[H] = 5 - 6E[X] = -14.9998 and var[H] = 62var[X] = 49.9994. The standard deviation of H is the square root of var[H], which is 7.0711.

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Help is greatly appreciated :). Will mark brainliest !:D

Answers

Answer:

The volume of a rectangular solid is given by the formula V = LWH, where L is the length, W is the width, and H is the height.

In this case, we have:

W = x + 3

L = x + 2

H = x

So the volume is:

V = (x + 2)(x + 3)(x)

V = x(x + 2)(x + 3)

V = x(x^2 + 5x + 6)

V = x^3 + 5x^2 + 6x

Therefore, the volume of the rectangular solid is given by the polynomial expression x^3 + 5x^2 + 6x.

Find the inverse of each of the following matrices (g) \( \left[\begin{array}{ccc}-1 & -3 & -3 \\ 2 & 6 & 1 \\ 3 & 8 & 3\end{array}\right] \) (h) \( \left[\begin{array}{ccc}1 & 0 & 1 \\ -1 & 1 & 1 \\

Answers

For matrix g : \(\displaystyle g^{-1}=\frac{1}{\left| g \right|}\left[\begin{array}{ccc}6 & 1 & -3 \\ -8 & -3 & 2 \\ 3 & -1 & -3\end{array}\right] \)
For matrix h : \(\displaystyle h^{-1}=\frac{1}{\left| h \right|}\left[\begin{array}{ccc}1 & 0 & -1 \\ 1 & -1 & 1 \\ 0 & 1 & -1\end{array}\right] \)

For matrix g, the inverse can be found using the following equation:

\(\displaystyle g^{-1}=\frac{1}{\left| g \right|}\left[\begin{array}{ccc}6 & 1 & -3 \\ -8 & -3 & 2 \\ 3 & -1 & -3\end{array}\right] \)



For matrix h, the inverse can be found using the following equation:

\(\displaystyle h^{-1}=\frac{1}{\left| h \right|}\left[\begin{array}{ccc}1 & 0 & -1 \\ 1 & -1 & 1 \\ 0 & 1 & -1\end{array}\right] \)



Where \(\left| g \right|\) is the determinant of the matrix g and \(\left| h \right|\) is the determinant of the matrix h.

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Someone please answer my question

Answers

Answer:

Point D is the solution to the system of equations.

Step-by-step explanation:

When asked for a solution involving 2 equations, the goal is to find a point (x,y) that would be a solution to both equations.  Any point on a line that is defined by an equation is a solution to that equation.  For an equation of y = 2x + 2, possible solutions are (1,4), (2,6), (5,12) etc.  These points all lie on the line formed by that equation.  There are an infinite number of possible solutions.  If a second eqaution is added, there is now a constraint on the possible answers.  The goal is to find a point that satisfies both equations.

If a seond equation of y = 1x + 3 were matced with y=2x+2, both are straight lines, but with different slopes.  So they will intersect at some point.  One may either solve mathematically using substitution, or by graphing, as was done here.  

Matematically:

y = 2x + 2

y = 1x + 3

Rearrange either equation to isolate a variable, x or y.  These are already isolated (since I made them up) so go to the next step of substituting one expression of y into the other:

y = 1x + 3

2x + 2 = 1x + 3

x = 1

Now use this value of x to find y:

y = 2x + 2

y = 2*(1) + 2

y = 4

The point these two lines intersect is (1,4) and is the "solution" to this series of equations.

See the attached graph.

A watch was bought for 2,700 including 8% VAT. Find its price before the VAT was added.

Answers

Answer:

Let's assume that the price before adding the VAT is x.

We know that the VAT rate is 8%, which means that the VAT amount is 8% of x, or 0.08x.

The total price including VAT is the sum of the price before VAT and the VAT amount, so we can write:

Total price = price before VAT + VAT amount

or

2,700 = x + 0.08x

Simplifying this equation, we can combine like terms on the right-hand side to get:

2,700 = 1.08x

To solve for x, we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by 1.08:

x = 2,700 / 1.08

x = 2,500

Therefore, the price before VAT was added is 2,500.

Without making calculations, what data set has the smallest standard deviation?

Answers

Answer: the last option

Step-by-step explanation:

Standard derivation reflects the degree if dispersion  of a data set

so the answer is 1,1,1,1,2,2,2,2

Let \( A=\left[\begin{array}{ccc}0 & -2 & -3 \\ -3 & 1 & -3 \\ -3 & 2 & 3\end{array}\right] \). (a) Find the determinant of \( A \). \( \operatorname{det}(A)= \) (b) Find the matrix of cofactors of \(

Answers

a)\( -9 \)

b)\( \left[\begin{array}{ccc}+18 & -18 & +9 \\ +9 & -9 & +4 \\ -4 & +4 & -1\end{array}\right] \).

(a) The determinant of \( A \) can be calculated using the Laplace expansion, which states that the determinant of a matrix can be found by multiplying the elements in the first row of the matrix by the determinant of the matrix formed by removing the elements of the first row and column of the original matrix, then subtracting the result from the elements in the second row multiplied by the determinant of the matrix formed by removing the elements of the second row and column of the original matrix, and so on.

Using the Laplace expansion, the determinant of \( A \) can be found as follows:

\( \operatorname{det}(A) = 0 \times \operatorname{det}\left[\begin{array}{cc}1 & -3 \\ 2 & 3\end{array}\right] - (-2) \times \operatorname{det}\left[\begin{array}{cc}-3 & -3 \\ 2 & 3\end{array}\right] + (-3) \times \operatorname{det}\left[\begin{array}{cc}-3 & 1 \\ -3 & 3\end{array}\right] \)

\( \operatorname{det}(A) = 0 \times 18 + 2 \times (-18) + 3 \times 9 \)

\( \operatorname{det}(A) = 0 - 36 + 27 \)

\( \operatorname{det}(A) = -9 \)

Therefore, the determinant of \( A \) is \( -9 \).

(b) The matrix of cofactors of \( A \) can be found by taking the determinant of the matrix formed by removing the elements of the first row and column of the original matrix and multiplying it by the sign of the elements of the first row and column, then subtracting the result from the elements in the second row multiplied by the determinant of the matrix formed by removing the elements of the second row and column of the original matrix and multiplying it by the sign of the elements of the second row and column, and so on.

Using this method, the matrix of cofactors of \( A \) can be found as follows:

\( \left[\begin{array}{ccc}C_{11} & C_{12} & C_{13} \\ C_{21} & C_{22} & C_{23} \\ C_{31} & C_{32} & C_{33}\end{array}\right] = \left[\begin{array}{ccc}+18 & -18 & +9 \\ +9 & -9 & +4 \\ -4 & +4 & -1\end{array}\right] \)

Therefore, the matrix of cofactors of \( A \) is \( \left[\begin{array}{ccc}+18 & -18 & +9 \\ +9 & -9 & +4 \\ -4 & +4 & -1\end{array}\right] \).

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CRB of variance estimation(20 pts.).. Suppose that we have a system that is zero mean and a variance o2 +0 with a known baseline variance o?, X~N(0,02 +0) with 0 > 0. This type of system is important for real world application when a system is known to be noisy with minimum variance o2. For n i.i.d. samples derive the CRB for estimating the parameter 8.

Answers

The CRB (Cramér-Rao Bound) of variance estimation is a lower bound on the variance of an unbiased estimator of a parameter. The CRB of variance estimation for this system is (02 +0)^2/(02 +0 + (02 +0)^2). This is the minimum variance that an unbiased estimator of the parameter 8 can achieve.

In this case, the parameter we are trying to estimate is 8. To derive the CRB for estimating the parameter 8, we first need to find the Fisher Information matrix, which is defined as:
I(8) = E[(d log f(X; 8)/d8)^2]
where f(X; 8) is the probability density function of X and E is the expectation operator.

Since X~N(0,02 +0), the probability density function of X is:
f(X; 8) = (1/sqrt(2*pi*(02 +0)))*exp(-X^2/(2*(02 +0)))

Taking the derivative of the log of this function with respect to 8, we get:
d log f(X; 8)/d8 = -(1/(02 +0))*((X^2)/(02 +0) - 1)

Squaring this and taking the expectation, we get:
I(8) = E[(1/(02 +0))^2*((X^2)/(02 +0) - 1)^2]

Simplifying and using the fact that E[X^2] = 02 +0, we get:
I(8) = (1/(02 +0))^2*(02 +0 + (02 +0)^2)

Finally, the CRB for estimating the parameter 8 is given by the inverse of the Fisher Information matrix:
CRB(8) = 1/I(8) = (02 +0)^2/(02 +0 + (02 +0)^2)

Therefore, the CRB of variance estimation for this system is (02 +0)^2/(02 +0 + (02 +0)^2). This is the minimum variance that an unbiased estimator of the parameter 8 can achieve.

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Let X (3, 0.02). Given Tx = 300 calculated by the Esscher Premium Principle with parameter 1, calculate h

Answers

The value of h is 99.969.

The Esscher Premium Principle is a method of calculating insurance premiums that considers the risk of an event occurring and the potential severity of the loss. The formula for the Esscher Premium Principle is:

Ex = ln(∑eαx Px)/α

Where Ex is the Esscher premium, α is the parameter, x is the loss amount, and Px is the probability of the loss occurring.

In this case, we are given X (3, 0.02), meaning that the loss amount is 3 and the probability of the loss occurring is 0.02. We are also given that the Esscher premium is 300 and the parameter is 1. Plugging these values into the formula, we get:

300 = ln(∑e1(3) 0.02)/1

Simplifying the equation, we get:

300 = ln(0.02e3)

Taking the natural logarithm of both sides, we get:

e300 = 0.02e3

Dividing both sides by 0.02, we get:

e300/0.02 = e3

Taking the natural logarithm of both sides again, we get:

300 - ln(0.02) = 3

Solving for h, we get:

h = (300 - ln(0.02))/3

h = 99.969

Therefore, the value of h is 99.969.

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Dave travel of 120 km/h it takes him 90 minutes to reach his destination It takes him. How far is his destination​

Answers

Here is the answer with working. The key is to convert the time to allow for the use of the formula: Speed = Distance/Time.

A vector u and a set S are given. If possible, write u as a linear combination of the vectors in S. U = [3], S= {[1], [2], [-2}}
[8] {[2] [3] [-5]}

Answers

Therefore, one possible way to write vector u as a linear combination of the vectors in set S is:

u = [2] + [3]

To write vector u as a linear combination of the vectors in set S, we need to find scalars a, b, and c such that:

u = a[1] + b[2] + c[-2]

Substituting the given values of u and the vectors in S, we get:

[3] = a[1] + b[2] + c[-2]

To solve for the scalars a, b, and c, we can set up a system of equations:

3 = a + 2b - 2c

Since we only have one equation and three unknowns, there are infinitely many solutions to this system. One possible solution is:

a = 1, b = 1, c = 0

Substituting these values back into the equation, we get:

[3] = 1[1] + 1[2] + 0[-2]

Therefore, one possible way to write vector u as a linear combination of the vectors in set S is:

u = [1] + [2]

Similarly, for the second set of vectors, we need to find scalars d, e, and f such that:

u = d[2] + e[3] + f[-5]

Substituting the given values of u and the vectors in S, we get:

[8] = d[2] + e[3] + f[-5]

To solve for the scalars d, e, and f, we can set up a system of equations:

8 = 2d + 3e - 5f

Since we only have one equation and three unknowns, there are infinitely many solutions to this system. One possible solution is:

d = 2, e = 2, f = 0

Substituting these values back into the equation, we get:

[8] = 2[2] + 2[3] + 0[-5]

Therefore, one possible way to write vector u as a linear combination of the vectors in set S is:

u = [2] + [3]

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Prove that, for a, b, and c ∈ Z, a > b and c > 0 =⇒ ac
> bc (part 3 of Proposition 2)

Answers

Our assumption is false

We can prove this statement by contradiction. Suppose a > b and c > 0 but ac < bc.

Since a > b, then a - b > 0. Multiplying both sides by c > 0 gives (a - b)c > 0.

We can then add bc to both sides to get (a - b)c + bc > bc.

Since we assumed that ac < bc, then (a - b)c < 0, and thus (a - b)c + bc < bc, which contradicts the previous result.

Therefore, our assumption is false, and we can conclude that for a, b, and c ∈ Z, a > b and c > 0 =⇒ ac ≥ bc.

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A circle moves through 145 degrees in 25 seconds. If the radius
of the circle is 21 cm, find the linear and angular speeds.

Answers

The linear speed of the circle is 2.125 cm/s and the angular speed of the circle is 0.1012 rad/s.

The linear speed of the circle can be found by calculating the length of the arc traveled in 25 seconds. The length of an arc is given by the formula L = rθ, where r is the radius of the circle and θ is the central angle in radians. Converting the given angle from degrees to radians, we have:

θ = 145 degrees * π/180 = 2.53 radians

Substituting the values into the formula, we get:

L = 21 cm * 2.53 = 53.13 cm

Therefore, the linear speed of the circle is:

v = L/t = 53.13 cm/25 s = 2.125 cm/s

The angular speed of the circle can be found by dividing the central angle by the time taken to travel that angle. Therefore, the angular speed of the circle is:

ω = θ/t = 2.53 radians/25 s = 0.1012 rad/s

Hence, the linear speed of the circle is 2.125 cm/s and the angular speed of the circle is 0.1012 rad/s.

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Help me, please. I hate math and I suck at it

Answers

Answer:

See below.

Step-by-step explanation:

We are asked to find the value of x.

We should know that these angles are Same-Side Interior Angles.

What are Same-Side Interior Angles?

Same-Side Interior Angles are 2 angles that aren't equal, but supplementary. They're formed inside 2 parallel lines.

What are Supplementary Angles?

Supplementary angles are 2 angles that add up to 180°.

Since these 2 angles are Same-Side Interior Angles, both can be added to equal 180°.

[tex]4x+2x+12=180[/tex]

Combine Like Terms:

[tex]6x=168\\x = 28[/tex]

The value of x is 28.

A tank contains 12 litres of water in which is dissolved 24 grams of chemical A solution containing 4 grams per litre of the chemical flows into the tank at a rate of 4 litres per minute, and the well-stirred mixture flows out at a rate of 2 litres per minute. Determine the amount of chemical in the tank after 15 minutes.

Answers

The amount of chemical in the tank after 15 minutes is 154.14 grams.

To determine the amount of chemical in the tank after 15 minutes, we need to use the formula for the concentration of a solution:

C = m/V

Where C is the concentration of the solution, m is the mass of the chemical, and V is the volume of the solution.

Initially, the tank contains 12 litres of water and 24 grams of chemical A, so the initial concentration of the solution is:

C0 = 24/12 = 2 grams per litre

The solution flows into the tank at a rate of 4 grams per litre and 4 litres per minute, so the amount of chemical flowing into the tank per minute is:

4 grams per litre × 4 litres per minute = 16 grams per minute

The well-stirred mixture flows out of the tank at a rate of 2 litres per minute, so the amount of chemical flowing out of the tank per minute is:

C × 2 litres per minute = 2C grams per minute

The net change in the amount of chemical in the tank per minute is:

16 grams per minute - 2C grams per minute = 16 - 2C grams per minute

After 15 minutes, the net change in the amount of chemical in the tank is:

(16 - 2C) grams per minute × 15 minutes = 240 - 30C grams

The final amount of chemical in the tank is:

m = 24 + 240 - 30C = 264 - 30C grams

The final volume of the solution in the tank is:

V = 12 + 4 litres per minute × 15 minutes - 2 litres per minute × 15 minutes = 42 litres

The final concentration of the solution in the tank is:

C = m/V = (264 - 30C)/42

Solving for C, we get:

42C = 264 - 30C

72C = 264

C = 264/72 = 3.67 grams per litre

The final amount of chemical in the tank is:

m = C × V = 3.67 grams per litre × 42 litres = 154.14 grams

Therefore, the amount of chemical in the tank after 15 minutes is 154.14 grams.

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The question is in the screenshot:

Answers

We can deduce that 3pi/4<5pi/3<2pi

The angle is in the 4th quadrant. To find the angle you just do:

[tex]2\pi -\frac{5\pi }{3}=\frac{\pi }{3}[/tex]

The answer to your question is B. I hope that this is the answer that you were looking for and it has helped you.

See Solution Bcore: 5 Penalty: None gleton Operations on Functions 6:13PM f(x)=x^(2)-5x-50 and g(x)=x+5, find (f-g)(x)

Answers

The value of (f-g)(x)  is  x^(2)-6x-55.

What are Mathematical operations on a function?

Mathematical operations on a function involve the manipulation or transformation of the function, such as adding, subtracting, multiplying, dividing, and integrating the function. These operations can be done either to the function itself or to the domain or range of the function. This can be used to find the inverse of a function, calculate the area under the curve, or find the first or second derivative of a function.

To find (f-g)(x), we need to subtract the function g(x) from the function f(x).



(f-g)(x) = f(x) - g(x)

= (x^(2)-5x-50) - (x+5)

= x^(2)-5x-50 - x - 5

= x^(2)-6x-55

Therefore, (f-g)(x) = x^(2)-6x-55.

This is the final answer for the difference between the two functions f(x) and g(x).

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if tan t = 11/7 and 0≤ t≤????/2 find sin t, cost, csc t, sect, and cott. To enter the square root of a number, type "sqrt(a)". For example, type "sqrt(2)" to enter √2. sin t = cos t = csc t = sec t = cot t =

Answers

The hypotenuse is sqrt(11^2 + 7^2) = sqrt(170). Then, sin t = 11/sqrt(170), cos t = 7/sqrt(170), csc t = sqrt(170)/11, sec t = sqrt(170)/7, and cot t = 7/11.

Since we know that tan t = 11/7, we can use the Pythagorean identity (sin^2 t + cos^2 t = 1) to find the other trigonometric functions. First, we will find sin t and cos t:

tan t = 11/7 = opposite/adjacent = sin t/cos t

sin t = 11*cos t

cos t = 7*sin t

Substituting the second equation into the first equation:

sin t = 11*(7*sin t)

sin^2 t = 121*sin^2 t

121*sin^2 t - sin^2 t = 0

120*sin^2 t = 0

sin^2 t = 0/120

sin^2 t = 0

sin t = 0

Since sin t = 0, cos t = 1. Now we can find the other trigonometric functions:

csc t = 1/sin t = 1/0 = undefined

sec t = 1/cos t = 1/1 = 1

cot t = 1/tan t = 1/(11/7) = 7/11

So, the values of the trigonometric functions are:

sin t = 0

cos t = 1

csc t = undefined

sec t = 1

cot t = 7/11

Note: Another way to find the values of the trigonometric functions is to use the Pythagorean Theorem to find the hypotenuse of the right triangle with sides 11 and 7.

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Help me solve this question

Answers

Hypothesis: The P-value for this test is 0.026251 which is less than the significance level of 0.05.

What is Hypothesis?

Hypothesis is a statement or explanation proposed to explain a phenomenon. It is a logical conjecture, based on observations or experiments, made in order to draw out and test its consequences. In scientific research, a hypothesis is used as a starting point for further investigation and is tested through the scientific method. A hypothesis must be testable and falsifiable, meaning it can be tested and disproved using scientific evidence.

Therefore, we can reject the null hypothesis that there is no difference in the proportions of almonds in the new and old recipes. This means that the proportion of almonds in the new recipe is greater than in the previous recipe.


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which equation of the least squares regression line most closely matches the data set?

Answers

The equatiοn οf the least squares regressiοn line which mοst clοsely matches the data set is y = 3.5 x + 43.8

Hοw tο sοlve fοr the data set?  

Tο sοlve fοr the data set, lets lοοk at the table,

X            1190         1992          1994         1996           1998

Y             45             51               57            61               75

Let the equatiοn that shοws the abοve data be

y = b + a x ---------(1)

Where, a = Σy Σx² - Σx Σxy

And, b = (Σxy - Σx Σy) / n Σx² -(Σx)²

By the abοve table,

Σx=20

Σxy = 1296

Σx² = 120

Σy=289

By substituting these values in the abοve value οf a and b,

We get b = 43.8 and a = 3.5

Substitute this value in equatiοn (1)

We get, the equatiοn that shοws the given data is,

y = 3.5 x + 43.8

Therefοre, οptiοn 3 is cοrrect.

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What is the measure of angle P? q is 65° P is 67°
​this IXL is due tomorrow so I need help fast make sure to explain

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Check the picture below.

In 1968 the remains of a young boy buried with over 100 tools of stone and antlers were found by accident by a construction worker on private property owned by the Anzick family in Montana. The bones were determined by radiocarbon-dating to be 12,600 years old. The half-life of Carbon-14 is 5730 years. What percent of the original amount of Carbon-14 was in the bone remains when found in 1968? Show how you obtained your equation and how you solved it. In 2014, a daughter of the Anzick family, Sarah Anzick, who was inspired by the finding and had become a genome researcher, was a member of the team that did DNA sequencing on the remains.

Answers

To find the percent of the original amount of Carbon-14 in the bone remains when found in 1968, we can use the following formula:
A = A0 * (1/2)^(t/h)
Where A is the final amount of Carbon-14, A0 is the original amount of Carbon-14, t is the time elapsed, and h is the half-life of Carbon-14.

Plugging in the given values, we get:
A = A0 * (1/2)^(12600/5730)
Simplifying the exponent, we get:
A = A0 * (1/2)^2.199
Using a calculator, we find that (1/2)^2.199 is approximately 0.153, so:
A = A0 * 0.153
This means that the final amount of Carbon-14 is 15.3% of the original amount of Carbon-14. Therefore, the percent of the original amount of Carbon-14 in the bone remains when found in 1968 is 15.3%.

As for the second part of the question, Sarah Anzick was a member of the team that did DNA sequencing on the remains in 2014. This allowed for further analysis and understanding of the remains and their significance in terms of human history and evolution.

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What is the slope of the line that contains the points (2, −7) and (−1, 5)?
−4
negative one fourth
one fourth
4

Answers

Answer:

The answer is -4

Step-by-step explanation:

The slot of the line can be calculated using the formula : y2 - y1/ x2 - x1.

So, you would plug in the values making the equation 5 - (-7)/ -1 - 2 and solve.

Exercise 12. Let X and Y be independent random variables satisfying E|X+Y|^n < [infinity] for some a > 0. Show that E|X|^n < [infinity].

Answers

E|X|n < ∞

Let X and Y be independent random variables satisfying E|X+Y|n < ∞ for some a > 0. We can show that E|X|n < ∞ using the triangle inequality.



Let b = a/2. Since E|X+Y|n < ∞, we know that E|X+Y| < ∞. Then by the triangle inequality, we have E|X| < |X+Y| + |Y| < ∞.



Raising both sides of the inequality to the nth power gives us E|X|n < (|X+Y| + |Y|)n < ∞.



Therefore, E|X|n < ∞.

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Use a calculator to approximate the measure of the acute angle A to the nearest tenth of a degree. sin A = 0.9659

a. 60.3 Degrees
b. 56 Degrees
c. 75 Degrees
d. 55.5 Degrees

Answers

Answer:

OPTION C

Step-by-step explanation:

There are 3 sides in a triangle. 2 of them are legs, and one of them is the Hypotenuse. "Sin" refers to Opposite/Hypotenuse.

To find A given a sine value, we must use inverse sin. I would suggest using desmos for this, but you need to switch to degrees in the online caluclator.

So the Equation is: [tex]sin^{-1} (0.9659)[/tex]

After plugging that into desmos, we get 74.994 degrees. Because that is not one of the answer, I'm assuming we must round our answer to the nearest whole number. In that case, your answer is 75 degrees, or OPTION C

A cart weighing 40 lb is placed on a ramp inclined at 15° to the horizontal. The cart is held in place by a rope inclined at 60° to the horizontal, as shown in the figure. Find the force that the rope must exert on the cart to keep it from rolling down the ramp.

Answers

Answer:

11.97 lb

Step-by-step explanation:

To find the force that the rope must exert on the cart to keep it from rolling down the ramp, we need to resolve the forces acting on the cart along the direction of the ramp and perpendicular to the ramp.

First, we resolve the weight of the cart into its components. The weight of the cart acting vertically downwards can be resolved into a component perpendicular to the ramp and a component parallel to the ramp.

The component perpendicular to the ramp is given by:

W_perp = W * cos(theta) = 40lb * cos(15°) = 38.6lb

The component parallel to the ramp is given by:

W_parallel = W * sin(theta) = 40lb * sin(15°) = 10.4lb

where W is the weight of the cart, and theta is the angle of inclination of the ramp.

Next, we resolve the force exerted by the rope into its components. The force exerted by the rope can be resolved into a component perpendicular to the ramp and a component parallel to the ramp.

The component perpendicular to the ramp is given by:

F_perp = F * cos(phi) = F * cos(60°) = 0.5F

The component parallel to the ramp is given by:

F_parallel = F * sin(phi) = F * sin(60°) = 0.87F

where F is the force exerted by the rope, and phi is the angle of inclination of the rope.

To keep the cart from rolling down the ramp, the force exerted by the rope must balance the weight of the cart along the direction of the ramp. That is,

F_parallel = W_parallel

0.87F = 10.4lb

Solving for F, we get:

F = 11.97lb

Therefore, the force that the rope must exert on the cart to keep it from rolling down the ramp is approximately 11.97lb.

if I get an annual income of 420 600,000 and get an increase of 8.2% calculate my new income​

Answers

Answer:

Step-by-step explanation:

To calculate your new income after an increase of 8.2%, you can use the following formula:

New income = Old income + (Percentage increase * Old income)

Plugging in the values given in the problem, we get:

New income = 420,600,000 + (8.2% * 420,600,000)

New income = 420,600,000 + (0.082 * 420,600,000)

New income = 420,600,000 + 34,524,120

New income = 455,124,120

Therefore, your new income after an increase of 8.2% would be 455,124,120.

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