A student randomly draws a card from a standard deck of 52 cards. He records the type of card drawn and places it back in the deck. This is repeated 20 times. The table below shows the frequency of each outcome.


Outcome Frequency
Heart 7
Spade 3
Club 6
Diamond 4


Determine the experimental probability of drawing a diamond.
0.13
0.20
0.35
0.70

Answer:

Let's assume that the company invites x people to the dinner party.

The cost of the function room is a fixed cost of $280.

The cost of dinner is $40 per person. Therefore, the total cost of dinner for x people is 40x.

The total cost of the dinner party is the sum of the cost of the function room and the cost of dinner:

Total cost = 280 + 40x

The problem states that the company has a budget of no more than $1500. Therefore, we can write:

280 + 40x ≤ 1500

Subtracting 280 from both sides gives:

40x ≤ 1220

Dividing both sides by 40 gives:

x ≤ 30.5

Since we cannot invite a fraction of a person, the company can invite at most 30 people to the dinner party.

Therefore, the greatest number of people they can invite to the dinner is 30.

Step-by-step explanation:

To construct a proof demonstrating the validity of the argument ∃xF x → ∀xF x, F g ∴ Mg, we need to use the rules of propositional logic and quantifier rules.

1. Assume ∃xF x (Assumption)
2. Choose an arbitrary element g and assume F g (Assumption)
3. From ∃xF x, we can conclude that there exists an element x such that F x (Existential Elimination)
4. Since we assumed F g in step 2, we can use Universal Instantiation to conclude that ∀xF x (g is an arbitrary element)
5. From the premise ∃xF x → ∀xF x, we can use Implication Elimination to conclude ∀xF x
6. Using Universal Elimination, we can conclude F g from ∀xF x
7. From F g and the premise F g ∴ Mg, we can use Modus Ponens to conclude Mg
8. Since we assumed ∃xF x in step 1 and derived Mg in step 7, we can use Existential Introduction to conclude ∃xMx

Therefore, we have constructed a proof demonstrating the validity of the argument ∃xF x → ∀xF x, F g ∴ Mg, which can be summarized as follows:

1. ∃xF x (Assumption)
2. F g (Assumption)
3. ∃xF x → ∀xF x (Premise)
4. ∃x F x (Existential Elimination)
5. ∀xF x (Implication Elimination)
6. F g (Universal Elimination)
7. F g ∴ Mg (Premise)
8. Mg (Modus Ponens)
9. ∃xMx (Existential Introduction)

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Answer:

x=5 y=1.5

Step-by-step explanation:

Answer:

x=5 y=1.5

Step-by-step explanation:

i used a graphing calculator

The system of inequalities represents this situation is:

c + f ≤ 200

5c + 6f ≥ 500

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Let c represent candles arrangements

Let f represent flower arrangements.

The girls estimate that at most they will sell 200 items.

The equation will be:

c + f ≤ 200

They would like to raise at least $500. They are selling candles for $5 and flower arrangements for $6.

$5 × c + $6 × f ≥ $500

5c + 6f ≥ 500

Therefore, the system of inequalities is given as:

c + f ≤ 200

5c + 6f ≥ 500

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(a) The probability that all 4 missiles will fire is 0.2098 and (b) The probability that at most 2 will not fire is 0.0099.

Here we need to use the concept of combinations to get our required answer.

Here we have been given that 4 out of 14 missiles are defective.

Hence 10 missiles are working.

A sample of 4 missiles was chosen

Hence the simple can be chosen in ¹⁴C₄ ways

a)

The probability that all 4 missiles will fire is

¹⁰C₄/¹⁴C₄

= 0.2098

b)

The probability that at most 2 will not fire is

1 - the probability of including all three defective missiles

= 10³C₃/¹⁴C₄

= 0.0099

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(a) Probability all 4 fire: 0.3297. (b) Probability at most 2 not fire: 0.9591.

(a) To track down the chance that all of the 4 rockets will fire, we actually need to do not forget the quantity of methods we can select 4 operating rockets out of the eleven that are not unsuitable, isolated by the all out range of approaches we will select four rockets out of the whole component.

The amount of ways of selecting four operating rockets out of the eleven that aren't improper is given by way of the combination recipe:

C(eleven,four) = 330

The absolute quantity of methods of selecting four rockets out of the entire part is given via:

C(14,4) = 1001

Subsequently, the chance that each one of the four rockets will hearth is:

P(all four hearth) = C(11,four)/C(14,4) = 330/1001 ≈ zero.3297

(adjusted to 4 decimal spots)

(b) To find the likelihood that at most 2 rockets might not fire, we need to remember every one of the potential conditions in which 0, 1, or 2 poor rockets are selected, and afterward song down the likelihood of every case and upload them up.

Case 1: No defective rockets are selected

The amount of ways of selecting four working rockets out of the eleven that are not faulty is given through the mixture recipe:

C(11,four) = 330

Subsequently, the chance of choosing no defective rockets is:

P(0 inadequate) = C(eleven,4)/C(14,four) ≈ 0.3297

Case 2: One defective rocket is chosen

The quantity of ways of selecting three operating rockets out of the eleven that are not poor is given with the aid of the combo equation:

C(eleven,three) = 165

The amount of ways of selecting 1 damaged rocket out of the three that are available is given through the mix equation:

C(three,1) = 3

Subsequently, the all out number of approaches of selecting 1 insufficient and three running rockets is:

C(eleven,three) × C(3,1) = 495

Thusly, the probability of choosing one deficient rocket and three running rockets is:

P(1 deficient) = C(eleven,three) × C(three,1)/C(14,4) ≈ 0.4655

Case three: Two poor rockets are selected

The amount of approaches of choosing 2 poor rockets out of the three which might be handy is given through the combination recipe:

C(3,2) = 3

The amount of ways of choosing 2 running rockets out of the 11 that aren't faulty is given via the mix recipe:

C(11,2) = 55

In this way, the all out number of methods of selecting 2 broken rockets and 2 working rockets is:

C(3,2) × C(eleven,2) = one hundred sixty five

Subsequently, the chance of choosing two incorrect rockets and two operating rockets is:

P(2 insufficient) = C(3,2) × C(11,2)/C(14,four) ≈ 0.1638

Subsequently, the likelihood that at maximum 2 rockets might not fireplace is:

P(at maximum 2 don't fire) = P(zero imperfect) + P(1 blemished) + P(2 deficient) ≈ 0.9591

(adjusted to 4 decimal spots).

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The angle formed by the radius of a circle and a tangent line to the circle is always equal to 90°

From the question, we have the following parameters that can be used in our computation:

The statement

In the statement, we have

As a general rule, the pojnt of intersection between the Radius of a circle and a Tangent line is right angles

This means that the angle is 90 degrees

Hence, the angle formed by the radius of a circle and a tangent line to the circle is always equal to 90°

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The value of the integral is π/2 - 2ln|1+sin(x)/cos(x)| + ln|cos(x)| + C.

To evaluate the integral, we can use the beta function and make a substitution. Let's start by writing the integral in terms of sine and cosine:

∫sins^5(x)/(tan(x)+tan^3(x)) dx = ∫sin^4(x)cos(x)/(sin(x)/cos(x)+sin^3(x)/cos^3(x)) dx

Now, let's make the substitution u = sin(x)/cos(x), which gives us:

∫sin^4(x)cos(x)/(sin(x)/cos(x)+sin^3(x)/cos^3(x)) dx = ∫u^4/(u+u^3) du

Next, we can use the beta function to write this integral in terms of gamma functions. Recall that the beta function is defined as:

B(x, y) = ∫t^(x-1)(1-t)^(y-1) dt from 0 to 1

Using this definition, we can write:

∫u^4/(u+u^3) du = ∫u^2/(1+u)^2 * u^2/(1-u+u^2)^2 du

Now, we can use the substitution v = 1/(1+u) to get:

∫u^2/(1+u)^2 * u^2/(1-u+u^2)^2 du = ∫v^2(1-v)/(1-v^2)^2 dv

Using partial fractions, we can write:

v^2(1-v)/(1-v^2)^2 = 1/(1-v^2) - 1/(1-v)^2

Substituting this back into the integral, we get:

∫v^2(1-v)/(1-v^2)^2 dv = ∫(1/(1-v^2) - 1/(1-v)^2) dv

Using the beta function, we can write:

∫1/(1-v^2) dv = B(1/2, 1/2) * tan^(-1)(v) = π/2

And:

∫1/(1-v)^2 dv = B(1, 1/2) * (1-v)^(-1) = 2/(1-v)

Substituting these back into the integral and simplifying, we get:

∫sins^5(x)/(tan(x)+tan^3(x)) dx = π/2 - 2ln|1+sin(x)/cos(x)| + ln|cos(x)| + C

Therefore, the value of the integral is π/2 - 2ln|1+sin(x)/cos(x)| + ln|cos(x)| + C.

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If this is a sample of 4 scores, then By using the definitional formula, SS equals 5. Your answer: 5.

Using the definitional formula, SS can be calculated as:

SS = ∑(x - X)2

where X is the sample mean.

To find X, we can use the formula:

X = ∑x / n

where n is the sample size.

Given that ∑x = 22 and n = 4, we can calculate X as:

X = 22 / 4 = 5.5

Now, we'll plug these values into the formula:

SS = 126 - (22)² / 4

Calculate (∑x)² / n:

(22)² / 4 = 484 / 4 = 121
Now we can plug in the values into the formula for SS:

SS = ∑(x - X)2
  = (1-5.5)2 + (2-5.5)2 + (3-5.5)2 + (4-5.5)2
  = (-4.5)2 + (-3.5)2 + (-2.5)2 + (-1.5)2
  = 20.5

Therefore, SS equals 20.5.

So, using the definitional formula, SS equals 5. Your answer: 5.

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The rate of each type of the given apples above would be = organic apple $2.50/pound;regular $2.00/pound. That is option C.

For organic apple;

The quantity of apples sold for $7.50 = 3 pounds.

The amount that is sold for an apple would be = ?.

That is ;

$7.50 = 3 pounds

$x. = 1 pound

make X the subject of formula;

X = 7.50/3

Therefore 1 pound = 7.50/3 = $2.50/pound.

For regular apple;

The rate can be detected from the graph;

1 pound of apple = $2

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The equation, as the problem requests will be 16 - 0.2h.

The mean is an appropriate measure of central tendency to use for this data, since there are no extreme outliers apparent upon inspection of the data.

Hence, the mean is

(0.5+0.6+0.5+0.7+0.7+0.5+0.5+0.6)/8 = 0.575

The average burning candle from this factory, then, loses 0.575 ÷ 3 ounces per hour (the table showed the weight lost by each of the eight candles after three hours of burning, so we need to divide that by 3 to get an hourly rate).

In conclusion, the equation, as the problem requests will be 16 - 0.2h.

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Answer:

-8.5

Step-by-step explanation:

First we need to get the -4x by it self which means moving the 8 so what we need to do is subtract 8 from its self and what we do on one side we do to the other so 42-8=34 then the last thing to do is just divided 34 divided by -4 and we get

-8.5 as the answer.

PLS GIVE BRAINLIST MEAN THE WORLD

HAVE A GREAT DAY!!

The solution to the absolute value equation |x-3| > 4 is (-∞, -1) U (7, ∞) in interval notation

To solve the absolute value equation |x-3| > 4 and express the answer in interval notation, follow these steps:

1. Break the absolute value inequality into two separate inequalities:
  a) x - 3 > 4 (when x - 3 is positive)
  b) -(x - 3) > 4 (when x - 3 is negative)

2. Solve each inequality:
  a) x - 3 > 4 => x > 7
  b) -(x - 3) > 4 => -x + 3 > 4 => -x > 1 => x < -1

3. Write the solution in interval notation:
  (-∞, -1) U (7, ∞)

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The statement "Given the logistic function 3 x(t) = e-1.08 t +0.09 The time needed to reach x(t)= 98 is t=3." is :

(b) False

The logistic function is a mathematical function that is used to model growth processes that are limited by saturation. It is often used in the field of biology to model population growth, as well as in economics to model the growth of markets and the adoption of new technologies.

Given the logistic function x(t) = 3e^(-1.08t) + 0.09, you want to determine if x(t) = 98 when t = 3.

Step 1: Plug in t = 3 into the function
x(3) = 3e^(-1.08*3) + 0.09

Step 2: Calculate the result
x(3) ≈ 3e^(-3.24) + 0.09 ≈ 0.0705

Since x(3) ≈ 0.0705 and not 98, the statement "The time needed to reach x(t) = 98 is t = 3" is false. Therefore, the correct answer is:

b. False

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Demand refers to the quantity of a product or service that buyers are willing and able to purchase at a certain price level. A demand curve is a graphical representation of the relationship between the quantity of a good or service that buyers are willing to purchase at different price levels.

In the market for VCRs, the demand and supply equations are Qd = 1,000 - 6P and Qs = 4P respectively. The government decides to impose a tax of $30 per unit sold on VCRs. This will lead to a shift in the supply curve upwards by $30, resulting in a new equilibrium point.

1. To find the new equilibrium quantity with the tax, we set Qd = Qs + tax. Thus, 1,000 - 6P = 4P + 30. Solving for P, we get P = $105. The equilibrium quantity is therefore Q = 1,000 - 6($105) = 370.

2. The price paid by buyers is the same as the equilibrium price, which is $105.

3. The price paid by sellers is the equilibrium price minus the tax, which is $75.

4. The diagram below illustrates the impact of the tax on the market for VCRs. The original equilibrium point is E0, with a price of $70 and a quantity of 400. With the tax, the new equilibrium point is E1, with a higher price of $105 and a lower quantity of 370. The tax creates a vertical distance between the two equilibrium points, which represents the tax revenue collected by the government.

[Insert Diagram Here]

5. The deadweight loss due to the tax is the reduction in total surplus (consumer surplus + producer surplus) that results from the tax. Using the original equilibrium as a benchmark, the total surplus is (1/2)($70)(400) = $14,000. With the tax, the total surplus is (1/2)($75)(340) = $6,375. Thus, the deadweight loss is $7,625.

6. To calculate the consumer surplus due to the tax, we need to compare the original consumer surplus with the new consumer surplus. Using the original equilibrium as a benchmark, the consumer surplus is (1/2)($70)(400 - 70) = $5,950. With the tax, the consumer surplus is (1/2)($105)(370 - 105) = $12,145. Thus, the consumer surplus due to the tax is $6,195.

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The surface area of the rectangular prism is 2600 square inches

In geometry, the surface area is the total area that the surface of a 3-dimensional object covers. Is.

Therefore, the surface area of the rectangular prism is:

=2 * (23 in. * 8 in.) (top and bottom faces)

=2 * (36 in. * 8 in.) (front and back faces)

=2 * (23 in. * 36 in.) (left and right faces)

= 368 + 576 + 1656

= 2600 square inches

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According to the given information :

(1) 2% of the calories in one serving of Fattoush come from carbohydrates.

(2) If the man consumes one serving of Fattoush, which contains 21.39g of protein, he still needs to consume an additional 46.45g of protein during the rest of the day.

1. To calculate the percent of Fattoush calories that comes from fat and carbohydrates, we need to know the total number of calories in one serving of Fattoush. Let's assume that the total number of calories in one serving of Fattoush is 200.

To calculate the percent of calories from fat:
- We know that 1g of fat = 9 calories, so if there are 21.39g of fat in one serving of Fattoush, we can multiply that by 9 to get the total number of calories from fat: 21.39g x 9 = 192.51 calories from fat.
- To calculate the percent of calories from fat, we can divide the total calories from fat (192.51) by the total number of calories in one serving of Fattoush (200) and then multiply by 100: (192.51 / 200) x 100 = 96.3%.

So, 96.3% of the calories in one serving of Fattoush come from fat.

To calculate the percent of calories from carbohydrates:
- We know that 1g of carbohydrates = 4 calories, so if there are 1g of carbohydrates in one serving of Fattoush, we can multiply that by 4 to get the total number of calories from carbohydrates: 1g x 4 = 4 calories from carbohydrates.
- To calculate the percent of calories from carbohydrates, we can divide the total calories from carbohydrates (4) by the total number of calories in one serving of Fattoush (200) and then multiply by 100: (4 / 200) x 100 = 2%.

So, 2% of the calories in one serving of Fattoush come from carbohydrates.

2. To calculate the RDA for protein for a 187# man, we need to convert his weight from pounds to kilograms:
- 187# / 2.205 = 84.8 kg
- RDA = 0.8g protein per kg of body weight
- RDA = 0.8 x 84.8 = 67.84g of protein

If the man consumes one serving of Fattoush, which contains 21.39g of protein, he still needs to consume an additional:
- 67.84g - 21.39g = 46.45g of protein during the rest of the day.

3. If we add 3 oz of grilled chicken to one serving of Fattoush, the new total calories would be:
- 200 (calories in one serving of Fattoush) + 130 (calories from 3 oz of grilled chicken) = 330 total calories

To calculate the new percentages of calories from fat and carbohydrates:
- We know that 1g of fat = 9 calories, so if there are now 24.39g of fat in the dish (21.39g from the Fattoush and 3g from the chicken), we can multiply that by 9 to get the total number of calories from fat: 24.39g x 9 = 219.51 calories from fat.
- To calculate the percent of calories from fat, we can divide the total calories from fat (219.51) by the total number of calories in the dish (330) and then multiply by 100: (219.51 / 330) x 100 = 66.5%.

So, the percent of calories from fat has decreased from 96.3% to 66.5%.

- We know that there is 1g of carbohydrates in one serving of Fattoush and 1g of carbohydrates in the chicken, so the total number of calories from carbohydrates is: 1g x 4 = 4 calories from carbohydrates.
- To calculate the percent of calories from carbohydrates, we can divide the total calories from carbohydrates (4) by the total number of calories in the dish (330) and then multiply by 100: (4 / 330) x 100 = 1.2%.

So, the percent of calories from carbohydrates has slightly decreased from 2% to 1.2%.

The percent increase in total calories is:
- We know that the original total number of calories in one serving of Fattoush was 200.
- We added 130 calories from the chicken.
- The percent increase in total calories is (130 / 200) x 100 = 65%.

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A graph of the image after a dilation by a scale factor of 2 centered at the origin is shown below.

In Mathematics and Geometry, a dilation simply refers to a type of transformation which typically changes the size of a geometric object, but not its shape.

Next, we would apply a dilation to the coordinates of the pre-image by using a scale factor of 2 centered at the origin as follows:

Ordered pair R (0, -2) → Ordered pair R' (0 × 2, -2 × 2) = R' (0, -4).

Ordered pair S (0, 3) → Ordered pair S' (0 × 2, 3 × 2) = S' (0, 6).

Ordered pair T (2, -4) → Ordered pair T' (2 × 2, -4 × 2) = T' (4, -8).

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The area of the trapezoid in this problem is given as follows:

C. [tex]A = 96\sqrt{3}[/tex] mm².

The area of a trapezoid is given by half the multiplication of the height by the sum of the bases, hence:

A = 0.5 x h x (b1 + b2).

The bases in this problem are given as follows:

11 mm and 15 + 6 = 21 mm.

The height of the trapezoid is obtained considering the angle of 60º, for which:

We have that the tangent of 60º is given as follows:

[tex]tan{60^\circ} = \sqrt{3}[/tex]

The tangent is the division of the opposite side by the adjacent side, hence the height is obtained as follows:

[tex]\sqrt{3} = \frac{h}{6}[/tex]

[tex]h = 6\sqrt{3}[/tex]

Thus the area of the trapezoid is obtained as follows:

[tex]A = 0.5 \times 6\sqrt{3} \times (11 + 21)[/tex]

[tex]A = 96\sqrt{3}[/tex] mm².

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The work done on lifting the steel beam by crane upwards is 3.3×10⁵ joules, based on given data.

Since the crane is lifting the steel beam upwards, the total force will be sum of mass and force due to acceleration due to gravity.

So, the formula will be-

W = F × d

W = m(g + a) × d

W = 425 (10 + 1.8) × 66

Performing addition in the parenthesis first

W = 425 × 11.8 × 66

Multiplying all the digits on Right Hand Side of the equation

W = 3,30,990 Joules

Hence, the work done is 3.3 × 10⁵ Joules

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The producer’s risk is 0.99 and the consumer’s risks for each sampling plan are 0.347, 0.049, and 0.176 for acceptance criteria 0, acceptance criteria 1, and acceptance criteria 2 respectively.

a. The operating characteristic curve (OC curve) shows the probability of accepting a lot with a given quality level, based on the sample size and acceptance criteria. Here are the OC curves for acceptance criteria of 0, 1, and 2, assuming a binomial distribution:

Acceptance Criteria = 0:
Sample size: 20
Probability of acceptance (p): 0.01
Probability of rejection (1-p): 0.99
OC Curve:
Quality Level (proportion defective) | Probability of acceptance
0% | 0.994
1% | 0.988
2% | 0.977
3% | 0.958
4% | 0.928
5% | 0.883
6% | 0.821
7% | 0.743
8% | 0.653
9% | 0.556
10% | 0.458

Acceptance Criteria = 1:
Sample size: 20
Probability of acceptance (p): 0.92
Probability of rejection (1-p): 0.08
OC Curve:
Quality Level (proportion defective) | Probability of acceptance
0% | 1.000
1% | 1.000
2% | 1.000
3% | 1.000
4% | 1.000
5% | 1.000
6% | 0.999
7% | 0.998
8% | 0.993
9% | 0.981
10% | 0.951

Acceptance Criteria = 2:
Sample size: 20
Probability of acceptance (p): 0.83
Probability of rejection (1-p): 0.17
OC Curve:
Quality Level (proportion defective) | Probability of acceptance
0% | 1.000
1% | 1.000
2% | 1.000
3% | 1.000
4% | 0.999
5% | 0.998
6% | 0.992
7% | 0.978
8% | 0.949
9% | 0.898
10% | 0.824

b. The producer's risk (Type I error) is the probability of rejecting a good lot, while the consumer's risk (Type II error) is the probability of accepting a bad lot. Here are the calculations for each sampling plan:

Acceptance Criteria = 0:
Producer's risk = α = 1 - p0 = 0.99
Consumer's risk = β = 1 - OC at p1 = 1 - 0.653 = 0.347

Acceptance Criteria = 1:
Producer's risk = α = 1 - p0 = 0.99
Consumer's risk = β = 1 - OC at p1 = 1 - 0.951 = 0.049

Acceptance Criteria = 2:

Producer's risk = α = 1 - p0 = 0.99
Consumer's risk = β = 1 - OC at p1 = 1 - 0.824 = 0.176

Note that the producer's risk is the same for all three sampling plans since it is based on the specified probability of a defective unit in the lot. The consumer's risk, however, varies depending on the acceptance criteria and sample size. Generally, a more lenient acceptance criterion (higher p-value) or a larger sample size will result in lower consumer risk.

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The probability of rolling a sum of 12 with these dice is  1/36.

The likelihood of rolling an entirety of 12 with two standard dice can be found utilizing the equation:

P(D1 + D2 = 12) = number of ways to induce an entirety of 12 / total possible results

There's as it were one way to roll a whole of 12: rolling a 6 on both dice.

The whole conceivable results can be found by noticing that there are 6 conceivable results for each dice roll, since each kick the bucket has 6 sides. In this manner, the whole number of conceivable results is:

6 x 6 = 36

So the likelihood of rolling a whole of 12 with two standard dice is:

P(D1 + D2 = 12) = 1/6 * 1/6 = 1/36

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Answer:

what

Step-by-step explanation:

The simplified expression is [tex]21x^2 - 25x - 28[/tex] in the given case.

An expression in mathematics is a combination of numbers, symbols, and operators (such as +, -, x, ÷) that represents a mathematical phrase or idea. Expressions can be simple or complex, and they can contain variables, constants, and functions.

"Expression" generally refers to a combination of numbers, symbols, and/or operations that represents a mathematical, logical, or linguistic relationship or concept. The meaning of an expression depends on the context in which it is used, as well as the specific definitions and rules that apply to the symbols and operations involved. For example, in the expression "2 + 3", the plus sign represents addition and the meaning of the expression is "the sum of 2 and 3", which is equal to 5.

To simplify the expression, first distribute the -3x and (3x + 4) terms:

[tex]-3x(4 - 5x) + (3x + 4)(2x - 7) = -12x + 15x^2 + (6x^2 - 21x + 8x - 28)[/tex]

Next, combine like terms:

[tex]-12x + 15x^2 + (6x^2 - 21x + 8x - 28) = 21x^2 - 25x - 28[/tex]

Therefore, the simplified expression is [tex]21x^2 - 25x - 28.[/tex]

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The product of the terms   [tex](d - 9)[/tex]  and  [tex](2d^{2} + 11d -4)[/tex]  will be [tex](2d^{3} - 7d^{2} - 103d + 36)[/tex].

We have to find the product of two terms.

First term = (d - 9)

Second term = [tex](2d^{2} + 11d -4)[/tex]

To find the product of these two terms, we will be using the distributive property. According to the distributive property, when we multiply the sum of two or more addends by a number, it will give the same result as when we multiply each addend individually by the number and then add the products together.

We have to find :  [tex](d - 9) (2d^2 + 11d -4)[/tex]

Using the distributive property,

[tex]d * 2d^{2} + d * 11 + d * (-4) - 9 * 2d^2 - 9 * 11d - 9 * (-4)[/tex]

After further multiplication, we get

[tex]2d^{3} + 11d^2 - 4d - 18d^{2} - 99d + 36[/tex]

Now, combine all the like terms.

[tex]2d^{3} + 11d^{2} - 18d^{2} - 4d - 99d + 36[/tex]

[tex]2d^{3} - 7d^{2} - 103d + 36[/tex]

Therefore, the product of d-9 and 2d^2 + 11d -4 is [tex]2d^{3} - 7d^{2} - 103d + 36[/tex]

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The weight of the ice after 10 hours is 1217 lb

A 523 lb mass of ice melts at 4.3 hours

The first step is to calculate the weight after one hour

523= 4.3

x= 1

cross multiply both sides

4.3x= 523

x= 523/4.3

x= 121.7

The weight after 10 hours can be calculated as follows

121.7= 1

y= 10

y= 121.7 × 10

y= 1217

Hence the weight after 10 hours is 1217 lb

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Angle PBC is 126 degrees.

Let's start by drawing the triangle ABC and marking the point P on AC such that APB = ABP.

Since APB = ABP, we can conclude that the triangle ABP is an isosceles triangle, which means that angles ABP and BAP are equal.

Let's call angle ABP and angle BAP x, then we have:

angle ABC = 2x (since triangle ABP is isosceles)

angle ACB = 2x - 39 (from the given information)

Since the sum of angles in a triangle is 180 degrees, we can write:

angle PBC + angle ABC + angle ACB = 180

Substituting the values we found for angle ABC and angle ACB, we get:

angle PBC + 2x + (2x - 39) = 180

Simplifying the equation, we get:

angle PBC = 219 - 4x

We still need to find the value of x to calculate angle PBC. To do that, let's use the fact that the sum of angles in a triangle is 180 degrees for triangle ABP:

angle ABP + angle BAP + angle APB = 180

Substituting x for angle ABP and BAP, we get:

2x + angle APB = 180

But we also know that angle APB = ABP (from the given information), so we can substitute:

2x + ABP = 180

Solving for ABP, we get:

ABP = 90 - x

Now we can substitute this value for ABP in our equation for angle PBC:

angle PBC = 219 - 4x

= 219 - 4(90 - ABP)

= 219 - 4(90 - (90 - x))

= 219 - 4x

Simplifying, we get:

angle PBC = 3x - 9

So to find the value of angle PBC, we need to find the value of x:

2x + ABP = 180

2x + (90 - x) = 180

x = 45

Now we can substitute x = 45 in our equation for angle PBC:

angle PBC = 3x - 9

= 3(45) - 9

= 126

Therefore, angle PBC is 126 degrees.

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Full Question ;

Point P is on side AC of the triangle ABC such that APB = ABP and ABC - ACB = 39 find PBC in degrees.

The sine and cosine without anything other than this diagram are given below.

(√3/2, 1/2) = (cos 30, sin 30)

(√2/2, √3/2) = (cos 45, sin 45)

(1/2, √3/2) = (cos 60, sin 60)

(0, 1) = (cos 90, sin 90)

We have,

From the diagram we see that,

For 30:

180 = π

30 = 30 x π/180 = π/6

And,

(√3/2, 1/2) = (cos 30, sin 30)

Similarly,

For 45:

180 = π

45 = 45 x π/180 = π/4

And,

(√2/2, √3/2) = (cos 45, sin 45)

For 60:

180 = π

60 = 60 x π/180 = π/3

And,

(1/2, √3/2) = (cos 60, sin 60)

For 90:

180 = π

90 = 90 x π/180 = π/2

And,

(0, 1) = (cos 90, sin 90)

Thus,

The sine and cosine without anything other than this diagram are given above.

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Answer: You can convert it by dividing it by 12 which would give you 3.5 and since half of 12 is 6 the answer is 3ft and 6inches

Step-by-step explanation: