The student can use a micrometer, also known as a micrometer caliper, to accurately measure the thickness of one page of a book. A micrometer is a precision measuring instrument that has a calibrated screw for measuring small distances. To use a micrometer, the student should:
Place the micrometer jaws on the page, making sure that the jaws are parallel to the edges of the page.
Close the jaws gently until they touch the page.
Read the measurement on the micrometer's scale.
Repeat the measurement a few times to ensure accuracy and take an average of the readings.
Alternatively, the student can use a ruler or a thickness gauge which is a small device that can be used to measure the thickness of small objects.
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Object A of mass 19 kg travels to the east at 4.2 m/s and object B of mass 24 kg travels to the south at 3.6 m/s. They collide and stick together in a perfect inelastic collision as shown below. What is the magnitude and direction (with respect to the horizontal) of the velocity of the two objects after the collision?
The velocity of the two objects after the collision is 0.1535 m/s in south direction.
What is law of conservation of momentum?The law of conservation of momentum asserts that, unless an external force is applied, the total momentum of two or more bodies operating upon one another in an isolated system remains constant.
From the law of conservation of momentum, it can be written that:
Total initial momentum = total final momentum
19 kg × 4.2 m/s + 24 kg × (-3.6) m/s = (19 kg + 24 kg)× v
v = [19 kg × 4.2 m/s + 24 kg × (-3.6) m/s] ÷ (19 kg + 24 kg)
v = - 0.1535 m/s
Hence, the velocity of the two objects after the collision is 0.1535 m/s in south direction.
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A 0.297 mol sample of CO2 gas is contained in a 6.00 L flask at room temperature and pressure. What is the density of the gas, in grams/liter, under these conditions?
The density of sample CO₂ gas under the given conditions is calculated to be 2.18 g/L.
Density in grams/litre = (mass of CO₂ gas present in flask)/(volume of flask)
We know, number of moles = (mass)/(molar mass)
Molar mass of CO₂ = 44.01 g/mol
Mass of CO₂ = number of moles × molar mass = 0.297 × 44.01 = 13.071 g
Volume of flask is given as = 6.00 L
So, the density of gas inside the flask = 13.071 g/6 L = 2.18 g/L
Hence, the density of CO₂ gas under the given condition is calculated to be 2.18 g/L.
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how does the wavelength of a fast-pitched baseball compare to the wavelength of an electron traveling at 1/10 the speed of light? what is the significance of this comparison? see sample exercise 7.3
The wavelength of a fast-pitched baseball is much larger than the wavelength of an electron traveling at 1/10 the speed of light.
The wavelength of a fast-pitched baseball is measured in the range of meters, whereas the wavelength of an electron traveling at 1/10 the speed of light is in the range of nanometers. This is due to the very big difference in their speeds, as the speed of light is much greater than the speed of a pitched baseball.
The significance of this comparison is that it gives us the idea of how the difference in scale between macroscopic objects and subatomic particles. The wavelength of a pitched baseball is in the macroscopic range and can be observed with the normal eye, while the wavelength of an electron is in the subatomic range and can only be observed with advanced instrumentation, such as a transmission electron microscope.
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You charge a 2.0-cm-radius metal sphere with -13 nC of charge. At what distance from the surface of the sphere is there a force of 1.0 x 10-'N on a charge of -1.6 x 10-'C? not sure Now choose from one of the following options Why? a) 196 cm b) 14 cmc)0.07 cm d) 0.005 cm
Option C is correct. On the x-axis, there are three equal positive charges: one at the origin, one at x=2m, and a third at x=4m.
On the x-axis, there are three equally sized positive charges: the first is at the origin, the second is at x = 2, and the third is at x = 4 m. a. x = 1 mb. x = 3 mc. x = 5 md. The vertices of an equilateral triangle have three positive charges of equal value, q.F e is the electrostatic force exerted on the charge.
=1.5×10 \s−3 \s N
The particle's charge is measured at q=1108 C.
F e = qE is the formula describing the relationship between the electrostatic force and the electric field resulting from a charge.
⇒E= \sq \sF \se
= \s1×10 \s−61.5×10 \s−3
=1.5×10 \s3 \s N/C.
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a toy duck is floating on the water. the average density of the duck is rhod = 620 kg/m3, while the density of water is rho = 1.0 x 103 kg/m3. the volume of the duck is vd = 0.000125 m3.
Given the toy duck's average density (rhod) and volume (vd), we can determine its total mass (m): rhod * vd = m So the toy duck's mass is: 0.77 kg = m = 620 kg/m3 * 0.000125 m3.
The volume of the submerged toy duck in water may be computed as follows: Vsub = m / (rho - rhod) Where rho represents the density of water. 0.000125 m3 = Vsub = 0.77 kg / (1.0 x 103 kg/m3 - 620 kg/m3) As a result, the volume of the toy duck submerged in water equals the toy duck's overall volume. This indicates that the complete toy duck will float in water, with the proportion of its volume submerged equaling the overall volume. toy duck is floating on the water. the average density of the duck is rhod = 620 kg/m3, while the density of water is rho = 1.0 x 103 kg/m3. the volume of the duck is vd = 0.000125 m3.
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a boy is using a rope to pull a sled to the left. what are the directions of the (a) tension force and the (b) friction force on the sled?
The direction of the tension force is to the right, while the friction force is downwards.
What is Force?A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
In conclusion, a force is not something that an object possesses or possesses. Another object applies a force to another. The concept of a force is not limited to living or non-living things.
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a clock battery wears out after moving 10,700 c of charge through the clock at a rate of 0.490 ma. (a) how long (in s) did the clock run?
To calculate the amount of time the clock ran, we can use the formula
time = charge / current
where charge is measured in coulombs (C), current is measured in amperes (A), and time is measured in seconds (s).
Given that the clock moved 10,700 C of charge at a rate of 0.490 mA, we can plug these values into the formula
time = 10,700 C / (0.490 mA / 1000) A
We convert the current from mA to A by dividing by 1000, since 1 A = 1000 mA.
time = 10,700 C / 0.490 A = 21857.142857142857 s
So the clock ran for approximately 21857.14 seconds or around 6.1 hours.
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a water wave has a frequency of 0.20 hz. how many wavelengths will have passed a fixed point after 1.5 min? (9.1)
a water wave has a frequency of 0.20 hz. 18 wavelengths will have passed a fixed point after 1.5 minutes.
To calculate the number of wavelengths that have passed a fixed point after a given time, we need to find the distance traveled by the wave and divide it by the wavelength.
First, we need to convert the time from minutes to seconds:
1.5 min = 90 sec
Next, we can find the distance traveled by the wave using the formula:
distance = velocity * time
where the velocity of a water wave is given by the equation:
velocity = frequency * wavelength
In this case, the frequency is 0.20 Hz and the wavelength can be calculated as follows:
wavelength = velocity / frequency
Substituting the values, we get:
wavelength = (0.20 Hz * velocity) / frequency = velocity / frequency
Therefore, the distance traveled by the wave can be calculated as:
distance = velocity * time = (0.20 Hz * wavelength) * 90 sec = 18 * wavelength
Finally, the number of wavelengths that have passed a fixed point after 1.5 minutes is calculated as:
number of wavelengths = distance / wavelength = 18 * wavelength / wavelength = 18
Therefore, 18 wavelengths will have passed a fixed point after 1.5 minutes.
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1. Renu has the following symptoms.
swelling of the feet, loss of feeling in hands and feet
sores in the mouth loss of appetite
The type of diet she needs to eat should be rich in --------
A
vitamin B B
iodine
C
calcium D
vitamin C
Answer:
A. vitamin B
Explanation:
what is fup , the magnitude of the force exerted upward on the bottom of the liquid?
FUP, the magnitude of the force exerted upward on the bottom of the liquid is equal to pressure times area.
In order to describe an object's maximal size and direction, we use magnitude. Scalar and vector quantities both use magnitude as a common link.
An object with mass can alter its velocity, or accelerate, as a result of a force. A force is the modification of an object's condition brought on by its surroundings. An object will be at stationary or moving as a result of forces. Think of a ball lying still on the ground as an illustration. You must exert considerable force on the ball in order to shift it in any way.
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the speed of light in empty space is approximately 300,000km/s. how many seconds would it take a pulse of light at this speed to get from the earth to the moon? assume that the distance from the earth to the moon is 384,400 km. choose the closest answer:
Answer:
Below
Explanation:
384 400 km / 300 000 km/s = 1.28 seconds
convert to 2.77 atm to torr
To convert 2.77 atm(Atmospheric Pressure) to torr, multiply 2.77 by 760, which gives us 2,108 torr.
Atmosphere (atm) and torr are both units of pressure measurement. Torr is a unit of pressure in the centimeter-gram-second (CGS) system, while atm is a unit of pressure in the International System of Units (SI).
The conversion from atm to torr involves multiplying the atm value by a conversion factor of 760. This is because 1 atm is equal to 760 torr.
To convert 2.77 atm to torr, multiply 2.77 by 760, which gives us 2,108 torr. It is important to keep in mind that these units are used in different systems of measurement, so it is important to know the correct conversion factor when converting between them. In conclusion, 2.77 atm is equal to 2,108 torr.
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a box of mass 10 kg attached to a spring is pulled to a maximum of 44 cm . the box is released. what is the speed when the box reaches a point 10 cm from the equilibrium position? the spring constant k
The speed of the box when it reaches 10 cm from the equilibrium position is 4.28 m/s, if the mass of the box is 10 kg.
The mass of the box, m = 10 kg
Maximum amplitude of the spring, A = 44 cm = 0.44 m
Displacement of the box, x = 10 cm = 0.1 m
Let the velocity of the box, = v
Spring constant, K = 1000 N/m
By the law of conservation of energy,
0.5 mv² + 0.5 kx² = 0.5 kA²
0.5×10×v² + 0.5×1000×0.1² = 0.5×1000×0.45²
0.5×10×v² = 101.25 - 5
v² = 96.25/5 = 19.25
v = √19.25 = 4.387 m/s
--The given question is incomplete, the complete question is:
"a box of mass 10 kg attached to a spring is pulled to a maximum of 44 cm . the box is released. what is the speed when the box reaches a point 10 cm from the equilibrium position? the spring constant k = 1000 N/m."--
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PLEASE HELP! THX
Particles q1 = +8.0 UC, q2 = +3.5 uC, and
93 = -2.5 uC are in a line. Particles q, and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q1?
Answer:
Explanation:
To find the net force on particle q1, we need to calculate the force between each pair of particles and then add them together. The force between two particles is given by Coulomb's law:
F = k * (q1 * q2) / r^2
where F is the force, k is the Coulomb constant (approximately 8.99 x 10^9 N*m^2/C^2), q1 and q2 are the charges of the two particles, and r is the distance between them.
The force between q1 and q2 is:
F = 8.99 x 10^9 N*m^2/C^2 * (8.0 uC * 3.5 uC) / (0.10 m)^2
The force between q2 and q3 is:
F = 8.99 x 10^9 N*m^2/C^2 * (3.5 uC * -2.5 uC) / (0.15 m)^2
The net force on particle q1 is the sum of the two forces, which can be positive, negative or zero, depending on the direction of the force.
It's important to note that this calculation is based on the assumption that the charges are point charges, and that the forces are acting along a straight line. In real-world situations, charges are usually distributed over a certain volume, and the forces acting on the charges can be affected by various factors such as the presence of other charges or conducting materials, which can change the net force.
Bob’s mass is 100 kg. Bob can teleport to different planets, fill in this chart.
Based on the information in the graph, it can be inferred that the force that Bob exerts with his weight is 980 N on Earth, 160 N on the moon, 2,590 N on Jupiter, 61 N on Pluto, 373 N on Mercury, and 80 Not in pampering
How to calculate the force that Bob exerts with his mass on different planets?To calculate the force that Bob exerts with his mass on different planets we must carry out the following formula.
P = force of gravity * massIn this formula we must substitute the values of force of gravity and mass to find the values on each planet. According to the above, the N on each planet would be:
980 N on Earth.160 N is the Moon.2,590 N on Jupiter.61 N on Pluto.373 N on Mercury.80 N at Mimas.Learn more about newtons in: https://brainly.com/question/13549064
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a.) An electron is moving east in a uniform electric field of 1.50 N/C directed to the west. At point A, the velocity of the electron is 4.48×105 m/s pointed toward the east. What is the speed of the electron when it reaches point B, which is a distance of 0.360 m east of point A? b.) A proton is moving in the uniform electric field of part A. At point A, the velocity of the proton is 1.92×104 m/s, again pointed towards the east. What is the speed of the proton at point B?
Answer:
2.007 * 10^11 m/s, 19100.52m/s
Explanation:
Given data:
Electric field = 1.50 N/C
velocity of electron is 4.48 * 10^5 m/s
distance of point B from point A is 0.360 m
we know that acceleration of particle is given as
a) for electron: a = qE/m
= 1.6 * 10^-19 *1.50/9.1 * 10-31
= 4 * 10^-21
from equation of motion we have
v^2 = u^2 +2as
= (4.48 * 10^5)^2 + 2(4 * 10^-21 * 0.360)
≈ 2.007 * 10^11 m/s
Please verify my calculations lol
d=V/E=1.91×10^4/1.48
d=12905.4m
At point B
Distance=12905.4+0.360=12905.770
V=Ed=12905.760*1.48=19100.52m/s
Explain how DNA, which is 6 feet long, can be stored in the nucleus of a tiny human cell?
Answer:
A process named Chromatin remodeling enables the DNA to be stored in the nucleus of a tiny human cell.
Explanation:
The DNA, which is a 6ft long thread-like structure, can still be stored in the nucleus of a tiny human cell. A process known as chromatin remodeling allows a human cell's nucleus to condense and securely pack a 6ft long DNA strand. By coiling and folding the DNA molecule and attaching particular proteins called histones to the DNA, this enables the DNA to fit into the constrained space of the nucleus. A chromosome is a highly compressed structure created by coiling, folding, and histone attachment and may be seen under a microscope during cell division. The tiny nucleus of a human cell may accommodate the chromosome, a compact form of DNA.
How much energy (in Joules) does it take to melt 1 kg of ice? How much energy (in Joules) does it take to raise 1 kg of water by 50oC? Which number is greater? Latent heat for water = 3.33 x 10^5
It takes334kJ to melt 1 kg of ice and 210kJ to raise 1 kg of water by 50oC when the ice is converted to water at 0oC and then the water is raised to 50oC.
Given the mass of ice (m) = 1kg = 1000g
Latent heat of water (Lw) = 3.33 x 10^5
Here, the heat is required to melt the ice. So,
The latent heat of fusion of ice (Li) = 334 kJ/kg
We know that, Q = mLf (melting/freezing) where Lf is latent heat of fusion
Qi = 1kg x 334 kJ/kg = 334kJ
Hence, the energy required to melt 1kg of ice is 334kJ
Given temperature (T) = 50oC
To raise 1kg of water to vapor we need latent heat of vaporization which is the Latent heat of water.
Q = mcΔT where c is the specific heat and ΔT is change in temperature.
When the ice is converted to water the temperature is 0oC.
Q = 1000g x 4.2J/g x (50 - 0)
Q = 210kJ
Hence, the energy required to raise 1 kg of water by 50oC is 210kJ
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how to find least count of voltmeter if circuit element is 2.04 voltz
The least count is 0.01 of voltmeter if the circuit element is 2.04 Voltz
The circular scale for a micrometre has 50 divisions, and the smallest division on the main scale is 0.5 mm. Using the formula L.C = 0.5/50 = 0.01mm, we can calculate the least count.
As a result, the smallest least count in metres is 0.1 cm or 1 mm.
A voltage metre also referred to as a voltage metre, is a device that gauges the voltage or potential difference existing between two points in an electrical or electronic circuit. Direct Current (DC) or Alternating Current (AC) circuits are typically the two types of circuits that the voltmeter is used for.
Millivolt, kilovolt, and volt are the voltmeter's measurement units. The three most common units are these three. One volt is equal to 1,000 kilovolts and 0.001 millivolts.
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I need help w all a,b,c,d
A. The total force acting on the plane during take-off is 563,140 N. This is calculated by multiplying the thrust of each engine (281,570 N) by the number of engines (2).
What is engine?An engine is an mechanical device that converts energy into useful work, typically in the form of rotational force. Engines are used in a variety of applications, from cars and airplanes to power plants and generators.
b. The acceleration the plane experiences during take-off can be calculated using Newton's Second Law of Motion, which states that Force = Mass x Acceleration. Therefore, the acceleration is 563,140 N / 369,000 kg = 1.53 m/s2.
c. To calculate the time it takes the plane to reach take-off speeds, we can use the kinematic equation for average acceleration, which states that the time taken is equal to the change in velocity (76 m/s) divided by the acceleration (1.53 m/s2). Therefore, the time taken is 49.8 seconds.
d. Using the kinematic equation for displacement, we can calculate the displacement the plane covers during take-off. This equation states that displacement is equal to the initial velocity (0 m/s) multiplied by the time taken (49.8 seconds) plus one-half of the acceleration (1.53 m/s2) multiplied by the time taken squared (49.8 seconds x 49.8 seconds). Therefore, the displacement is 3,814.7 m.
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3. how does an earthquake of magnitude 8.4 compare to an earthquake of magnitude 3.7? round answer to the nearest whole number. [a4]
The comparison of the larger intensity earthquake is 2 times that of a smaller intensity earthquake from the given data.
When two ground slabs abruptly move past one another, an earthquake occurs. The region where they slip is the fault or fault plane. The movement creates seismic waves, which travel through the Earth and cause the ground to tremble. These seismic waves are made up of elastic strain energy that has been built up.
The given larger intensity earthquake has 8.4 magnitude.
The given smaller intensity earthquake has 3.7 magnitude.
So, the ratio of intensity is,
⇒ (larger intensity)/(smaller intensity)
⇒ 8.4/3.7 = 2.27 ≈ 2.3 ≈ 2
Hence, we can conclude that larger earthquake's intensity is 2 times as great as the smaller earthquake's intensity.
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it is possible to view the moon in third-quarter phase the day after a total lunar eclipse. group of answer choices true false
It is indeed possible to view the moon in the third-quarter phase the day after a total lunar eclipse. The third quarter phase of the Moon is the phase that occurs two weeks after a new moon.
During this phase, the Moon appears half-illuminated, with the illuminated portion facing away from Earth. This is because the Moon is now located on the opposite side of the Earth from the Sun, with the Earth in the middle. A total lunar eclipse occurs when the Moon passes through the Earth's shadow, causing it to appear dark. This usually occurs at the time of a full moon, when the Earth is directly between the Sun and the Moon. After a total lunar eclipse, the Moon is still located on the opposite side of the Earth from the Sun. Consequently, the Moon will still appear half-illuminated, and can thus be viewed in its third-quarter phase the day after a total lunar eclipse.
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the displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion , where is measured in seconds. find the average velocity during each time period:
The average velocity of a particle moving back and forth along a straight line can be found by calculating the displacement over a given time period and dividing it by the time elapsed.
Find the average velocity during each time period?Average velocity = (Displacement)/(Time Period)For example, if the displacement during the period from 0 seconds to 5 seconds is 10 cm, then the average velocity during that period would be 2 cm/s:Average velocity = (10 cm)/(5s) = 2 cm/sThis is known as the average velocity equation, and it is given by: v_avg = (x_f - x_i)/(t_f - t_i)where x_f and x_i are the final and initial displacement of the particle respectively, and t_f and t_i are the final and initial time, respectively. Therefore, for a given time period, the average velocity is equal to the change in displacement over the change in time. For example, if the displacement of the particle is given by the equation of motion , where is measured in seconds, and the time period is given by seconds, then the average velocity during this period can be calculated as follows:v_avg = (x(t_f) - x(t_i))/(t_f - t_i)
= (x(2) - x(1))/(2 - 1)
= (2 - 1)/(2 - 1)
= 1 cm/s
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If the average speed of a person was 1.2 meters/second, does this mean that their speed was exactly 1.2 meters/second the whole time? Is the average speed related to the maximum or minimum speed of the person? Explain why you think so.
No, the average speed of a person does not necessarily mean that their speed was exactly 1.2 meters/second the whole time.
Average speed is calculated by dividing the total distance traveled by the total time elapsed. In simple words, Average speed is distance divided by the time interval for the distance traveled. So, if a person's speed varies over time, their average speed will be a reflection of all the different speeds they traveled at during that time period.
The average speed is not related to the maximum or minimum speed of a person. It's the measure of the average rate at which an object covers distance over time. It can be different from the maximum or minimum speed that an object has reached during that time.
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Four particles have the following masses in terms of m), speeds (in terms of v), and radii (in terms of r). Particle Mass Speed Radius m 2y m /2 2m 1/2 2v Which two particles have the same centripetal force? A. Particle 1 B. Particle 2 C. Particle 3 D. Particle 4
Particle 1 and Particle 2, two particles are observed to have the same centripetal force. Correct options are (A) and (B).
A centripetal force is any force that shifts the direction of motion in the direction of the centre of a circular motion. The portion of the force that is perpendicular to the velocity creates the centripetal force.
The formula for centripetal acceleration is a = v²/r.
For particle 1: a₁ = v²/r
For particle 2; a₂ = (2v)²/2r = 2v²/r
For particle 3; a₃ = (v/2)²/r = v²/4r
For particle 4; a₄ = (2v)²/3r = 4v²/3r
Centripetal force (F) = ma
Thus,
F₁ = = ma = mv²/r
F₂ = (m/2)a₂ = mv²/r
F₃ = 2ma₃ = 2mv²/4r = mv²/2r
F₄ = m4v²/3r = 4/3 mv²/r
The given question is incomplete. The complete question is ' Particle Mass Speed Radius
1 m v r
2 m/4 2v r
3 2m v/2 r
4 3m 2v 3r'
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you are approaching a cyclist riding near the right edge of the lane on a two-lane country road. at the same time, you notice a large truck approaching from the distance in the oncoming lane. you accelerate to pass the cyclist using the oncoming lane and then move to the lane-right position before meeting the oncoming truck. what is this an example of?
According to the problem this is an example of wrong-way passing.
What is wrong-way passing?Wrong-way passing is when a driver passes another vehicle on the wrong side of the road. This is an incredibly dangerous and illegal maneuver, as it can lead to head-on collisions. Wrong-way passing often occurs when the driver is unfamiliar with the area, or is distracted by something else. It can also happen when the driver is under the influence of alcohol or drugs, or is in a rush to get to their destination. Drivers should always obey the rules of the road, and be aware of their surroundings to avoid this dangerous behavior.
Wrong-way passing is a dangerous maneuver in which a vehicle drives on the wrong side of the road to pass a slower vehicle. It is illegal in most countries, and carries a high risk of collision with oncoming traffic.
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For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product.
Part A
H2O2(g)→H2(g)+O2(g)
Express your answer as an integer.
−Δ[H2O2]Δt = Δ[H2]Δt
The rate of disappearance of each reactant is related to the rate of appearance of each product as:
Δ[H2O2]Δt = Δ[H2]Δt = Δ[O2]Δt
The rate of disappearance of H2O2 (Δ[H2O2]/Δt) is equal to the rate of appearance of H2 (Δ[H2]/Δt).
Similarly, the rate of disappearance of H2O2 (Δ[H2O2]/Δt) is equal to the rate of appearance of O2 (Δ[O2]/Δt).
So, in this reaction,
Δ[H2O2]/Δt = Δ[H2]/Δt = Δ[O2]/Δt
or
Δ[H2O2]Δt = Δ[H2]Δt = Δ[O2]Δt
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In Oulu, Finland:Does the sky rotate in the same direction as Fort Collins?How much of the sky is circumpolar compared to Fort Collins?Are there any constellations you can see here that aren’t visible in Fort Collins?How long is the day here at this time of year compared to Fort Collins?
No, the sky in Singapore and Malaysia rotates in the opposite direction from that in Fort Collins. Electric vehicles will undoubtedly be crucial in resolving the energy and environmental issues we are now facing.
However, it was discovered that one of the major problems with the launch strategy for EVs was the problem with EV charging station locations. While more influencing elements and restrictions must be taken into account while locating EV charging stations because EVs have some unique characteristics. Any person who enjoys stargazing should be aware of how the sky changes as the stars rise in the east and set in the west. Looking north from the northern hemisphere, we can observe the sky moving against clockwise around the North Celestial Pole, which is close to Polaris.
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a power transmission line is made of copper that is 1.80 cm in diameter. the resistivity of copper is 1.73×10−8 ω·m. what is the resistance of 1.50 mi of the line?
The resistance of the power transmission line which is made up of copper whose length is 1.50 miles is 0.1644Ω
Given:
Diameter of the copper wire (d)=1.80cm
Copper wire resistivity (ρ)=1.73×10⁻⁸Ωm
The radius of the copper wire (r)= 0.90cm = 0.90×10⁻²meters
Length(L) = 1.50 mile = 2414.02meters
The cross-sectional area of the copper wire(A) = πr²
A = 3.14 × 0.81 × 10⁻⁴
A = 25.434 × 10⁻⁵m²
Calculating resistance
R= ρL/A
on putting the values
R= 1.73×10⁻⁸×2414.02/25.434×10⁻⁵
R= 0.1644Ω
The resistance of the 1.50-mile line is 0.1644Ω
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the speed of a transverse wave on a string is 557 m/s, while the wavelength is 0.156 m. the amplitude of the wave is 2.69 mm. how much time is required for a particle of the string to move through a total distance of 1.27 km?
The speed of a transverse wave on a string is 557 m/s, time required for a particle of the string to move is 33sec.
C=557m/s
wavelength=0.156m
A=2.69mm=3*10^-3
d=1.27km
frequency=C/wavelength=557/0.156
frequency=3571
total distance moved per sec =4A/T=4Af
=4*3*10^-3*3571=38
time required=1.27*10^3/38=33sec
Motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, secondary waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.
Longitudinal waves are mechanical waves that require a medium for propagation, transverse waves are non-mechanical waves that do not require a medium for propagation.
In a transverse wave, the particles are displaced perpendicular to the direction the wave travels.
Amplitude is the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position.
Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.
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