The circumference of the pad to the nearest tenth is 39.6 meters
Formula for calculating the circumference of a circle?The circumference of a circle is the arc length of the circle, as if it were opened up and straightened out to a line segment. It is also known as the perimeter of a circle.
The formula for calculating the circumference of a circle is expressed as;
C = 2πr
where
π = 3.14
r is the radius of the circle
Given the following parameters
π = 3.14
r = 6.3m
Substitute to have:
C = 2 * 3.14 * 6.3
C = 6.28 * 6.3
C = 39.564
Hence the circumference of the pad to the nearest tenth is 39.6 meters
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) The following scatterplot shows the percentage of the vote a candidate received in the 2016 senatorial elections
according to the voter's income level based on an exit poll of voters conducted by a news agency. The income
levels 1-8 correspond to the following income classes:
1 = Under $15,000; 2 = $15-30,000; 3 = $30-50,000; 4 = $50-75,000; 5 = $75-100,000;
6 = $100-150,000; 7 = $150-200,000; 8 = $200,000 or more.
Use the election scatterplot to the find the critical values corresponding to a 0.01 significance level used to test
the null hypothesis of ρs = 0.
A) -0.881 and 0.881
B) -0.881
C) -0.738 and 0.738
D) 0.881
The critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881
How to determine the critical values corresponding to a 0.01 significance level?The scatter plot of the election is added as an attachment
From the scatter plot, we have the following highlights
Number of paired observations, n = 8Significance level = 0.01Start by calculating the degrees of freedom (df) using
df =n - 2
Substitute the known values in the above equation
df = 8 - 2
Evaluate the difference
df = 6
Using the critical value table;
At a degree of freedom of 6 and significance level of 0.01, the critical value is
z = 0.834
From the list of given options, 0.834 is between -0.881 and 0.881
Hence, the critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881
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WILL GIVE BRAINLIEST
Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.
1) 50 mph
2) 70 mph
3) x mph
4) (x+10)mph
5) (x-5)mph
The length of the trip at a distance of 300 miles and the given times are
6 hours30/7 hours300/x hours300/x + 10 hours300/x - 5 hoursHow to determine the length of the trip?The distance is given as:
d = 300
The formula is represented as:
d = r * t
Make t the subject
t = d/r
Substitute 300 for d
t = 300/r
When r = 50 mph,
t = 300/50
Evaluate
t = 60
When r= 70 mph, we have
t = 300/70
Evaluate
t = 30/7
When r = x, we have
t = 300/x
When r = x + 10, we have
t = 300/x + 10
When r = x - 5, we have
t = 300/x - 5
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Complete question
A train traveled 300 miles. How long did the trip take if the train was traveling at a rate of:
Note * Use the d=rt formula (distance = rate * time). NOTE: You may not be able to solve for the variable. If you do not have enough information to solve for the variable then write the equation.
Please please answer
Answer:
thanks for your support of the personal information on the direction of economics class
Find g(x), where g(x) is the translation 2 units left and 13 units up of f(x)=–7x+7.
Answer:
[tex]g(x)=-7x+6[/tex]
Step-by-step explanation:
Translations
For a > 0
[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]
[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]
[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]
[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]
Parent function:
[tex]f(x)=-7x+7[/tex]
Translation of 2 units left:
[tex]\implies f(x+2)=-7(x+2)+7[/tex]
Translation of 13 units up:
[tex]\implies f(x+2)+13=-7(x+2)+7+13[/tex]
Simplifying:
[tex]\implies g(x)=-7(x+2)+7+13[/tex]
[tex]\implies g(x)=-7x-14+7+13[/tex]
[tex]\implies g(x)=-7x+6[/tex]
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In a school, all pupils play either Hockey or Football or both. 400 play Football, 150 play Hockey, and
130 play both the games. Find
(i) The number of pupils who play Football only,
(ii) The number of pupils who play Hockey only,
(iii) The total number of pupils in the school
Answer:370 play football and 20 play hockey
Step-by-step explanation: because 400 - 130 equals 370 for football
then hockey 150-130 equals 20
Then the total students are 420
150+400-130 equals 420
Simplify (15x^-4)(x^15)/(5x^4)(x^5)
Answer:
[tex]3x^2[/tex]
Step-by-step explanation:
First main thing to know is the product and quotient rule of exponents.
Product Rule:
[tex]x^a*x^b = x^{a+b}[/tex]
And if this doesn't make sense, you can think of the exponent like this:
[tex]x^a*x^b = (x*x*x*x...\text{ a amount of times}) * (x * x * x \text{ b amount of times})[/tex]
and since multiplication is commutative, we can just combine all these x's, and since the total amount on the left is "a", and the right is "b", the total combined x's should be a+b, which can be expressed as:
[tex]x*x*x... \text{ a+b amount of times}[/tex]
which can be expressed as an exponent (x^(a+b))
Quotient Rule:
[tex]\frac{x^a}{x^b} = x^{a-b}[/tex]
You can use similar reasoning for this, since if you write it out you get
[tex]\frac{x*x*x...\text{ a amount of times}}{x*x*x\text{ b amount of times}}[/tex]
and since you have an x in the numerator and the denominator, you can simply cancel the x's out. In doing this you want to remove the denominator, so you cancel out "b" x's. So there will be (a-b) x's left in the numerator, and a 1 in the denominator, so it's just x^(a-b)
Ok so now let's apply these to solve your question
[tex]\frac{(15x^{-4})*x^{15}}{(5x^4)*x^5}\\[/tex]
So let's combine the exponents in the numerator and denominator using the product rule
[tex]\frac{15x^{11}}{5x^9}\\[/tex]
Now we can divide the 15 by 5, and divide the x^11 by the x^9 using the quotient rule
[tex]3x^2[/tex]
What is the distance from (-1,-14) and (-2,-6)?
Answer:
d = [tex]\sqrt{65}[/tex]
Step-by-step explanation:
The distance between two points is found by
d = [tex]\sqrt{( x2-x1)^2 + ( y2-y1)^2}[/tex] where (x1,y1) and (x2,y2) are the two points
d = [tex]\sqrt{(-2 - -1)^2+(-6 - -14)^2 }[/tex]
d =[tex]\sqrt{( -2+1)^2 + (-6+14)^2}\\[/tex]
d = [tex]\sqrt{(-1)^2 +( 8)^2 }[/tex]
d = [tex]\sqrt{1+64}[/tex]
d = [tex]\sqrt{65}[/tex]
Please help. Which spinner will give maria the best probability of winning a prize
Explain why.
03* For which one of the following functions is (-1,-1) a relative minimum?
f(x,y)=xy + 1/x + 1/y
f(x,y)=x^2 +2x
f(x,y)=xy-y^2
f(x,y)=xy-1/x-1/y
If (-1, -1) is an extremum of [tex]f[/tex], then both partial derivatives vanish at this point.
Compute the gradients and evaluate them at the given point.
[tex]f(x,y)=xy+\frac1x +\frac1y[/tex][tex]\nabla f = \left\langle y - \dfrac1{x^2}, x - \dfrac1{y^2}\right\rangle \implies \nabla f (-1,-1) = \langle-2,-2\rangle \neq \langle0,0,\rangle[/tex]
[tex]f(x,y) = x^2+2x[/tex][tex]\nabla f = \langle 2x+2,0\rangle \implies \nabla f(-1,-1) = \langle0,0\rangle[/tex]
[tex]f(x,y)=xy-y^2[/tex][tex]\nabla f = \langle y, x-2y\rangle \implies \nabla f(-1,1) = \langle-1,1\rangle \neq\langle0,0\rangle[/tex]
[tex]f(x,y) = xy-\frac1x-\frac1y[/tex][tex]\nabla f = \left\langle y + \frac1{x^2}, x + \frac1{y^2}\right\rangle \implies \nabla f(-1,1) = \langle0,0\rangle[/tex]
The first and third functions drop out.
The second function depends only on [tex]x[/tex]. Compute the second derivative and evaluate it at the critical point [tex]x=-1[/tex].
[tex]f(x,y) = x^2+2x \implies f'(x) = 2x + 2 \implies f''(x) = 2 > 0[/tex]
This indicates a minimum when [tex]x=-1[/tex]. In fact, since this function is independent of [tex]y[/tex], every point with this [tex]x[/tex] coordinate is a minimum. However,
[tex]x^2 + 2x = (x + 1)^2 - 1 \ge -1[/tex]
for all [tex]x[/tex], so (-1, 1) and all the other points [tex](-1,y)[/tex] are actually global minima.
For the fourth function, check the sign of the Hessian determinant at (-1, 1).
[tex]H(x,y) = \begin{bmatrix} f_{xx} & f_{xy} \\ f_{yx} & f_{yy} \end{bmatrix} = \begin{bmatrix} -2/x^3 & 1 \\ 1 & -2/y^3 \end{bmatrix} \implies \det H(-1,-1) = 3 > 0[/tex]
The second derivative with respect to [tex]x[/tex] is -2/(-1) = 2 > 0, so (-1, -1) is indeed a local minimum.
The correct choice is the fourth function.
the perimeter of a rectangle if 24 inches. the rectangle is enlarged so that each side is twice as long as the original. what effect does this enlargement have on the perimeter?
The perimeter becomes double when each side is twice as long as the original.
According to the statement
we have given that the perimeter of a rectangle is 24 inches. and we have to find that the what effect does this enlargement have on the perimeter.
So, For this purpose, we know that the
A rectangle is a parallelogram all of whose angles are right angles especially : one with adjacent sides of unequal length.
The formula to find the perimeter of rectangle is 2(L + B)
And we the length is goes to increased by double then the perimeter will also goes to double.
Because perimeter is directly proportional to the length and breadth of rectangle.
So, The perimeter becomes double when each side is twice as long as the original.
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In a sample of 198 observations, there were 80 positive outcomes. Find the margin of error for the 95% confidence interval used to estimate the population proportion.
Using the z-distribution, the margin of error for the 95% confidence interval used to estimate the population proportion is 0.0683 = 6.83%.
What is a confidence interval of proportions?
A confidence interval of proportions is given by:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
The margin of error is given by:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which:
[tex]\pi[/tex] is the sample proportion.z is the critical value.n is the sample size.In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.
For this problem, the parameters are given as follows:
[tex]n = 198, \pi = \frac{80}{198} = 0.404[/tex]
Hence the margin of error is:
[tex]M = 1.96\sqrt{\frac{0.404(0.596)}{198}} = 0.0683[/tex]
The margin of error for the 95% confidence interval used to estimate the population proportion is 0.0683 = 6.83%.
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find the price, discount, markup, or cost to store.
Markup=80%
Selling price= $21.60
Cost to store?
Using proportions and the markup concept, it is found that the cost to store is of $12.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
The markup price of 80% means that the selling price is of 180% = 1.8 of the cost to store of x. The selling price is of $21.60, hence:
1.8x = 21.60
x = 21.60/1.8
x = $12.
The cost to store is of $12.
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FIND THE INDICATED PROBABILITY FOR THE FOLLOWING:
IF P(A OR B) = 0.9, P(A) = 0.5, AND P(B) = 0.6, FIND P(A AND B)
The value of the probability P(A and B) is 0.20
How to determine the probability?The given parameters about the probability are
P(A or B) = 0.9
P(A) = 0.5
P(B) = 0.6
To calculate the probability P(A and B), we use the following formula
P(A and B) = P(A) + P(B) - P(A or B)
Substitute the known values in the above equation
P(A and B) = 0.5 + 0.6 - 0.9
Evaluate the expression
P(A and B) = 0.2
Hence, the value of the probability P(A and B) is 0.20
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How is the Gauss-Jordan elimination method different from the Gaussian elimination method?
The Gauss-Jordan elimination method different from the Gaussian elimination method in that unlike the Gauss-Jordan approach, which reduces the matrix to a diagonal matrix, the Gauss elimination method reduces the matrix to an upper-triangular matrix.
What is the Gauss-Jordan elimination method?
Gauss-Jordan Elimination is a technique that may be used to discover the inverse of any invertible matrix as well as to resolve systems of linear equations.
It is based on the following three basic row operations that one may apply to a matrix: Two of the rows should be switched around. Multiply a nonzero scalar by one of the rows.
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A lender requires PMI that is 0.8% of the loan amount of $470,000. How much (in dollars) will this add to the borrower's monthly payments? (Round your answer to the nearest cent.)
$
The amount add to the borrower's monthly payment is $313.33.
Given that lender requires PMI that is 0.8% of the loan amount of $470,000.
A loan's PMI, or personal mortgage insurance, is a type of mortgage insurance used by lenders when making traditional loans such as home loans. A PMI helps cover the loss to the lender (bank) if the borrower stops making monthly mortgage payments on their home loan. Therefore, the PMI can be described as a kind of risk mitigation tool for the bank when the borrower defaults on their EMIs (monthly mortgage payments). So, PMI for a borrower is an additional cost or payment for the borrower on top of his monthly payments i.e. EMI.
Thus, the additional amount of dollars that the borrower has to pay for the PMI on his loan along with his monthly mortgage payments
= Principal Loan amount × (PMI/12)
= $470,000 × (0.8%/12)
= $470,000 × (0.008/12)
= $470,000 × 0.0006666667
=$313.333349
Hence, the additional monthly payment for PMI where lender requires PMI that is 0.8% of the loan amount of $470,000 is $313.33.
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A 5 -ounce container of Greek yogurt contains 150 calories. Find the unit rate of calories per ounce.
Answer:
30calories
Step-by-step explanation:
Answer:
30 calories per ounce
Step-by-step explanation:
The answer given by rachelwang2022 is correct.
I am just adding to the explanation
Since there are 150 calories in a 5-ounce container, you can determine the number of calories per ounce by simply dividing 150 by 5.
150/5 = 30 calories per ounce
Find the intercepts of y=−7x+3
Answer:
X-intercepts:
[tex] (\frac{3}{7} ,0)[/tex]
Y-intercepts:(0,3)
Step-by-step explanation:
Hello!
given expression
[tex]y = - 7x + 3[/tex]
x-intercept is the point on the graph where y=0
solve
[tex] - 7x + 3 = 0 \\ - 7x = - 3 \\ x = \frac{3}{7} [/tex]
Thus, x-intercept
[tex]( \frac{3}{7} ,0)[/tex]
y-intercept is the point on the graph where x=0
solve
[tex]y = - 7(0) + 3 \\ y = 0 + 3 \\ y = 3[/tex]
Thus, y-intercept (0,3)
Hope it helps!
Add (x^3 -2x^2+4) + (2x^3+x^2-2) express in standard form
Answer:
3x^3-x^2+0x+2Step-by-step explanation:
add both the equations then you will get
3x^3-x^2+2
but in the standard form there should be an x^1 term or x term since there is no term like that we write it as 0x
so the equation will be
3x^3-x^2+0x+2
(5+2g)exp5 for g=-2
help pls
The value of the expression when g = -2 is -1
How to simplify the expressionGiven the expression;
(5+2g)exp5
(5+2g)^5
For g = -2
Let's substitute the value of g in the expression
= ( 5 + 2 ( -2) ) ^5
Expand the bracket
= ( 5 - 4) ^ 5
Find the difference
= (-1) ^5
= -1
Thus, the value of the expression when g = -2 is -1
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Find the simple interest earned after 4 years on $2,250 invested at an interest rate of 5%.
simple interest= principal x time x rate/100
Graph the hyperbola using the transverse axis, vertices, and co-vertices:
12x2−3y2−108=0
Use the green key point to change the orientation of the transverse axis, and the red key points to adjust the locations of the vertices and co-vertices.
See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0
How to graph the hyperbola?The equation of the hyperbola is given as:
12x^2 - 3y^2 - 108 = 0
Start by calculating the transverse axis
So, we have:
Transverse axis
The vertices of the given hyperbola are (0, 0)
This means that
(h, k) = 0
Where
a = 3 and b = 6
The transverse axis is calculated as:
y = ±b/a(x - h) + k
So, we have:
y = ±6/3(x - 0) + 0
Evaluate the difference and sum
y = ±6/3x
Evaluate the quotient
y = ±2x
This means that the transverse axes are y = 2x and y =-2x
The vertices
In the above section, we have:
The vertices of the given hyperbola are (0, 0)
This means that
(h, k) = 0
The co-vertices
In the above section, we have:
The vertices of the given hyperbola are (0, 0)
This means that
(h, k) = 0
And
a = 3 and b = 6
The co-vertices are
(h - a, k) and (h + a, k)
So, we have:
(0 - 3, 0) and (0 + 3, 0)
Evaluate
(-3,0) and (3, 0)
See attachment for the graph of the hyperbola
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Which table of values represents a function?
x y
-3 10
4 4
-5 -3
4 4
x y
2 8
6 9
6 3
5 7
x y
1 2
1 4
1 6
1 8
x y
5 2
-3 2
2 2
1 7
The table in the list of tables that represent an actual function is the first table i.e.
x y
-3 10
4 4
-5 -3
4 4
How to determine the table of values represents a function?The table of values is given as:
Table 1
x y
-3 10
4 4
-5 -3
4 4
Table 2
x y
2 8
6 9
6 3
5 7
Table 3
x y
1 2
1 4
1 6
1 8
Table 4
x y
5 2
-3 2
2 2
1 7
For a table to represent a function, each of the x value on the table must correspond to exactly one y value
i.e.
x1 = y1
x2 = y2
And so on
Using the above highlights, the table that represents a function is table 1
Hence, the table in the list of tables that represent an actual function is the first table i.e.
x y
-3 10
4 4
-5 -3
4 4
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The Bureau of Alcohol, Tobacco, and Firearms (BATF) has been concerned about lead levels in California wines. In a previous testing of wine specimens, lead levels ranging from 47 to 660 parts per billion were recorded. How many wine specimens should be tested if the BATF wishes to estimate the true mean lead level for California wines to within 10 parts per billion with 95% confidence? (Round your answer up to the nearest whole number.)
The number of specimens should be tested is 1352.
According to the statement
we have to given that the in testing of wine specimens, lead levels ranging from 47 to 660 parts per billion were recorded. and we have to find the number specimen should be tested.
so,
Using the uniform and the z-distribution, it is found that 1353 specimens should be tested.
For an uniform distribution of bounds a and b, the standard deviation is given by:
σ = [tex]\sqrt{\frac{(b-a^{2})}{12} }[/tex]
and put the values a= 50 and b= 700 then the
standard deviation is 187.64
And here the critical value become 1.6 then
We want the sample for a margin of error of 10, thus, we have to solve for n with the help of value of m is 100.
Then n is 1352.
So, The number of specimens should be tested is 1352.
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What value is needed to complete the square? Show all steps
X^2-2x+___
The perfect square trinomial is x² - 2x + 1.
Hence, the value needed to complete the square of the expression ( x² - 2x + --- ) is 1.
What value is needed to complete the square?The quadratic expression in its standard form is;
ax² + bx + c
Given the expression in the question;
x² - 2x + ------
Compared with the standard for a quadratic expression
a = 1b = -2c = ?Let the missing value be represented by "c"
x² - 2x + c
Now, to find the value of c, we divide the coefficient of x by 2 and then square the result.
Note that, coefficient of x is b
c = ( b/2 )²
We substitute
c = ( -2/2 )²
c = ( -1 )²
c = 1
The perfect square trinomial is x² - 2x + 1.
Hence, the value needed to complete the square of the expression ( x² - 2x + --- ) is 1.
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6. Dacă a + 2b = 18 şi b+3c=17, calculaţi 3a+8b+6c.
Answer:
Răspuns: 88=>rezultatul
Explicație pas cu pas:
a+2b =18/×3
b+3c=17/×2
3a+6b =54 ^
2b+6c=34 | +
3a+(6b+2b)+6c=54+34
3a+8b+6c=88
Step-by-step explanation:
Simplify. ‒36 ÷ (27 ÷ 3 ∙ 2)
The simplified value of expression -36/(27/3*2) is -8.
Given an expression -36/(27/3*2).
We are required to find the simplified value of given expression. To simplify the expression we need to use addition,subtraction,multiplication, division, brackets, etc. We can say that we have to use BODMAS in order to find the simplified value of expression.
Expression is combination of numbers, symbols, coefficients, determinants, indeterminants, fraction,algebraic operations,etc. usually not found in equal to form.
The given expression :
=-36/(27/3*2) (Multiplying 3 and 2 first)
=-36/(27/6)
=(-36*2)/9 (Invert the fraction given in denominator)
=-72/9 (Multiplying -36 to 2)
=-8
Hence the simplified value of expression -36/(27/3*2) is -8.
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B) Using the two point above find the slope using the formula m =
y/₁y₁
x₂-1
C) Plug in your slope and one of the two points above into point-slope formy - y₁ = m(x-x₁)
D) Change above equation into slope-intercept form y = mx + b. (See page 5 in lesson 5.06).
16+20
The linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
The slope of the lineThe complete question is added as an attachment
The two points from the graph are (20, 25) and (38, 41)
The slope of the line is calculated using
m = (y2 - y1)/(x2 - x1)
Substitute the known values in the above equation
m = (41 - 25)/(38 - 20)
Evaluate
m =0.89
The linear equation in point slope formThis is calculated as:
y - y1 = m(x - x1)
Substitute the known values in the above equation
y - 25 = 0.89 * (x - 20)
Evaluate
y - 25 = 0.89(x - 20)
The linear equation in slope-intercept formWe have:
y - 25 = 0.89(x - 20)
Expand
y - 25 = 0.89x - 17.8
Add 25 to both sides
y = 0.89x + 7.2
Hence, the linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
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what base could be written in the blank to make the exponential function model 15% decay ? y= (__1/2__) ^t\12
Answer:
0.85
Step-by-step explanation:
1 - 15% = 1 - 0.15 = 0.85
[tex] y = (0.85)^\frac{t}{12} [/tex]
Answer: 0.85
- Describe the slope of each line. Then find the slope.
thank you for helping
Answer: TRS is congruent to CSE
Step-by-step explanation:
You can find congruent angles by locating the ones with the same number of lines. You want to start with the angles in the order of TRS.
Angle T has 1 line, so is congruent to C, which also has 1 line.
Angle R has 2 lines, so is congruent to S, which also has 2 lines.
Angle S has 3 lines, so is congruent to E, which also has 3 lines.
You want to keep these in the same order, so TRS, in the order of 1-2-3 lines, is congruent to CSE, also in the order of 1-2-3 lines (aka congruency markings).
