Amy is solving the equation using the steps shown.



Which could be the correct next step in solving the equation?


Subtract 2 from both sides of the equation to yield (x 2 – 16) = 0.
Subtract 2 from both sides of the equation to yield (, x , 2, – 16) = 0.

Multiply (x 2 – 16)(x + 2) on the left side of the equation to yield x 3 + 2x 2 – 16x – 32 = 0.
Multiply (, x , 2, – 16)(, x, + 2) on the left side of the equation to yield , x, , 3, + 2, x, , 2, – 16, x, – 32 = 0.

Factor (x 2 – 16) on the left side of the equation to yield (x + 4)(x – 4)(x + 2) = 0.
Factor (, x , 2, – 16) on the left side of the equation to yield (, x, + 4)(, x, – 4)(, x, + 2) = 0.

Add 16 to both sides of the equation to yield x 2(x + 2) = 0.
Add 16 to both sides of the equation to yield , x , 2, (, x, + 2) = 0.

Answer:

domain will be ( -∞, ∞)

Step-by-step explanation:

The given functions are f(x) = x² - 1 and g(x) = 2x - 3

We have to find domain of (fog)(x)

We will find the function (fg)(x) first.

(fog)(x) = f[g(x)]

         = (2x - 3)²

         = 4x² + 9 - 12x - 1

        = 4x² - 12x + 8

       = 4 (x² - 3x + 2)

The given function is defined for all values of x.

Therefore, domain will be ( -∞, ∞)

https://brainly.com/question/2458431

The formula in terms of sum of two angle measures is c 3[sin(90 + 60)]t

Since the alternating current i in amperes after t seconds is i = 3(sin150)t.

We want to write 150 as the sum of two angles measures.

So, 150 = 90 + 60.

So, the current i = 3(sin150)t

i = 3[sin(90 + 60)]t

So, the formula in terms of sum of two angle measures is c 3[sin(90 + 60)]t

Learn more about sum of two angles here:

https://brainly.com/question/16560125

Answer:

HOPE IT HELPS YOU BRAINLIEST

Answer:

36 yards

Step-by-step explanation:

48 - 31 = 17

17 + 3 + 5 + 7 + 4 = 36

The total distance between  the ball and the goal line is 36 yards

In computing, data is information that has been translated into a form that is efficient for movement or processing.

Given:

Eagles have the ball 48 yards away from the goal line.

On the first play, the Eagles gain 31 yards on a pass toward the goal line. On the next four plays, the Eagles lose 3, 5, 7, and 4 yards.

After first day they have yards remaining

=48 - 31

= 17

Now, the total distance between  the ball and the goal line

=17 + 3 + 5 + 7 + 4

= 36

Learn more about data here:

https://brainly.com/question/15403824

#SPJ2

Answer:

3 < r

Step-by-step explanation:

167<6+7(2+7r)

distribute the 7 to the 2 and 7r

7 * 2 = 14 and 7 * 7r = 49r

167 < 6 + 14 + 49r

combine like terms: 6 + 14 = 20

167  < 20 + 49r

subtract 20 from both sides

147 < 49r

divide both sides by 49

3 < r

Answer: There is no picture.

Step-by-step explanation:

Answer:

1348

Step-by-step explanation:

Answer:

$3671.58

Step-by-step explanation:

Take the annual salary and divide it by the number of months

i do not know but its something around number

answer in the photo thank me later mate

Answer:

19/50

Step-by-step explanation:

19 males and 50 people are in total

Answer:

19/50

Step-by-step explanation:

number of men=19

total passengers = 19+31=50

ratio of men to total people's = 19/50

Answer:

-3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(2-(-4))/(6-8)

m=(2+4)/-2

m=6/-2

m=-3

It is right but what's the full question

Answer:

2/9

Step-by-step explanation:

2(2/3)^2-4(2/3)+2

2(4/9)-8/3+2

8/9-8/3+2

-16/9+2

2/9

Answer:

19

Step-by-step explanation:

Answer:

x=20. y=15

Step-by-step explanation:

in similar triangles the sides are all in proportion. this means:

[tex] \frac{25}{5} = \frac{x}{4} = \frac{y}{3} [/tex]

[tex] \frac{25}{5} = 5[/tex]

so:

[tex] \frac{x}{4} = 5[/tex]

x=5×4

x=20

and...

[tex] \frac{y}{3} = 5[/tex]

y=3×5

y=15

Answer:

i got 47/88

Step-by-step explanation:

Divide each number by two

Answer:0.11

Step-by-step explanation:

Problem 1 (on the left)

[tex]10^2+12^2 = \boldsymbol{244}\\\\14^2 = \boldsymbol{196}\\\\\text{What kind of triangle?} \textbf{ Acute}[/tex]

-------------------------------

Explanation:

The converse of the pythagorean theorem can be used to determine what kind of triangle we're dealing with.

Here are 3 important rules to have in your notes:

[tex]\cdot \text{If } a^2+b^2 > c^2 \text{ then the triangle is } \underline{\text{acute}}\\\\\ \cdot \text{If } a^2+b^2 < c^2 \text{ then the triangle is } \underline{\text{obtuse}}\\\\\cdot \text{If } a^2+b^2 = c^2 \text{ then the triangle is a } \underline{\text{right}} \text{ triangle}\\\\[/tex]

The third rule is probably the most familiar as it's the pythagorean theorem itself.

In this case, we have [tex]a^2+b^2 = 10^2+12^2 = 244[/tex] larger than [tex]c^2 = 14^2 = 196[/tex], which fits the first rule mentioned.

=========================================================

Problem 2 (on the right)

[tex]8^2+15^2 = \boldsymbol{289}\\\\17^2 = \boldsymbol{289}\\\\\text{What kind of triangle?} \textbf{ Right}[/tex]

-------------------------------

Explanation:

We follow the same idea as problem 1. This time, both [tex]a^2+b^2[/tex] and [tex]c^2[/tex] result in the same value (289). Therefore, [tex]a^2+b^2 = c^2[/tex] is a true equation, and we go for the third rule mentioned earlier. An 8-15-17 right triangle is one of the infinitely many pythagorean triples.

[tex]R.H.S\\\\= (a+b)(a^2-ab +b^2)\\\\=a^3-a^2b +ab^2+ba^2-ab^2+b^3\\\\=a^3+b^3\\\\=L.H.S\\\\\text{Hence, proved.}[/tex]

Answer: No real solution.

Step-by-step explanation:

Since the parabola never crosses the x-axis, there are no real solutions.

Answer:

are we doing ur homework

Step-by-step explanation:

Answer:

y=-3x+1

Step-by-step explanation:

Answer:

It will be the last one.

Step-by-step explanation:

Answer:

3.24 inches

Step-by-step explanation:

3 times 108% is 3.24

The range is the y value of where the dots are located.

Answer: (3,4,5,6)

Answer:

26V^5+2V^7

Step-by-step explanation:

Answer:

3. ASA

4. Corresponding sides of congruent triangles are congruent

Step-by-step explanation:

I marked this in the attached image. ∠B ≅∠E, ∠ACE ≅ ∠DCE, and the side between them BC ≅ EC, so the the triangles ΔACB and ΔDCE are congruent by ASA.

If the triangles are congruent, then all corresponding angles and sides are also congruent.