An air-filled parallel-plate capacitor of capacitance C is connected to a battery and charged to a voltage V. The capacitor is then disconnected from the battery. If the distance between the capacitor plates is halved while the charge on the capacitor remains the same, which of the following is true?

Answers

Answer 1

The capacitance and the voltage would be halved. Option B

What is the relationship between the capacitance and the distance?

The capacitance of a parallel plate capacitor is directly proportional to the area of the plates and inversely proportional to the distance between the plates. This relationship can be described by the equation:

C = εA/d

Where C is the capacitance, ε is the permittivity of the medium between the plates, A is the area of the plates, and d is the distance between the plates.

As the distance between the plates increases, the capacitance decreases. This is because as the distance increases, the electric field between the plates becomes weaker, which means that less charge can be stored on the plates for a given voltage. On the other hand, when the distance decreases, the capacitance increases, this happens because the electric field between the plates gets stronger, allowing more charge to be stored on the plates for a given voltage.

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An Air-filled Parallel-plate Capacitor Of Capacitance C Is Connected To A Battery And Charged To A Voltage

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a substance contains 9 x 10^30 free electrons per cubic meter. if the collision time for these electrons is 3 x 10^-14 what is the conductivity of the substance

Answers

The conductivity of the substance containing free electrons is calculated to be 7.59 × 10⁹ siemens/m or mho.

Number of free electrons is given as 9 × 10³⁰

Collision time is given as 3 × 10⁻¹⁴ s

Mass of electron is known to be = 9.1 × 10⁻³¹ kg

Charge on electron = 1.6 × 10⁻¹⁹ C

Conductivity of the substance is given by the formula,

σ = (n e² τ)/m

where,

σ is conductivity

n is number of electrons

m is mass of electron

e is charge of electron

τ is time

Putting in the values in the above equation, we have,

σ = [(9 × 10³⁰)(1.6 × 10⁻¹⁹)² (3 × 10⁻¹⁴)]/(9.1 × 10⁻³¹) = (69.12× 10⁻²²)/(9.1 × 10⁻³¹) = 7.59 × 10⁹ siemens/m.

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a large sheet of metal has a hole cut in the middle of it. when the sheet is heated, the area of the hole will

Answers

Answer:

A1 = π R^2        original area

A2 = π (R + ΔR)^2        area of hole increased in radius by ΔR

A2 - A1 = π (2 R ΔR + ΔR^2) change in area due to heating

Δ A = π 2 R ΔR           ΔR^2 is small and will be omitted

ΔR = R c ΔT        where ΔT is the temperature change

Thus the coefficient of area expansion is twice that of the coefficient of linear expansion

Which of the following is an example of a velocity?

Question options:

2 mile/minute


80 miles/hour


9.8 meters/second/second


45 kilometers/hour East

Answers

Answer:

45 km per hour due east

Explanation:

it has bot magnitude and direction

two forces act on an object one force F1=25N west .By accurate construction and using appropriate scale find the magnitude and direction of F2 ,if resultant of the two forces is 40N South​

Answers

Answer:

the force F2 has a magnitude of 45.5 N and a direction of 128.7° counterclockwise from the x-axis

Explanation:

To determine the second force (F2), we can use vector addition.

Starting from F1=25 N west, we add F2 in the opposite direction of the resultant (40 N south) until the vectors sum to the desired resultant:

F1 + F2 = 40 N south

25 N west + F2 = 40 N south

To find F2, subtract F1 from both sides:

F2 = 40 N south - 25 N west

Using the Pythagorean theorem, the magnitude of F2 can be found as follows:

F2 = √(F2x^2 + F2y^2) = √((-25)^2 + 40^2) = √(625 + 1600) = √2125 = 45.5 N

The direction of F2 can be found using inverse tangent:

Θ = atan2(F2y, F2x) = atan2(40, -25) = 128.7° (measured counterclockwise from the x-axis)

to help determine the roots of x=tan(x), grapgh y=x and y=tan(x), and look at the intersection points of the two curves

Answers

The roots of given equations can be solved by calculus and the intersection of the 3 equations are at the origin i.e (0,0)

The roots of x=tan(x) :

The solution is the x-value of the point of intersection.

x = 69.05396782n, 4.49340945+69.05396782n,7.72525183+69.05396782n,14.06619391+

69.05396782n,20.37130295+69.05396782n,26.66605425 +69.05396782n,42.38791356 +69.05396782n

, for any integer n

Graph the line using the slope and y-intercept, or two points.

Slope:

1

y-intercept: (0,0)

x          y

0         0

1           1

Graph the trigonometric function using the amplitude, period, phase shift, and vertical shift.

Vertical Asymptotes: x = pi/2 + pi.n ,for any integer n

Amplitude: None

Period: π

Therefore, the intersection is origin here.

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suppose you are in an elevator. as the elevator starts upward, its speed will increase. during this time when the elevator is moving upward with increasing speed, your weight will be . view available hint(s)for part a suppose you are in an elevator. as the elevator starts upward, its speed will increase. during this time when the elevator is moving upward with increasing speed, your weight will be . equal to your normal weight at rest greater than your normal weight at rest less than your normal weight at rest

Answers

The correct answer is A)greater than your normal weight at rest.

When an elevator moves upward, the passengers inside experience a change in their gravitational potential energy. According to the law of conservation of energy, the change in potential energy must be compensated by an equal and opposite change in some other form of energy, such as kinetic energy or thermal energy.

In the case of an elevator, the change in potential energy is compensated by the work done by the elevator's motor, which converts electrical energy into mechanical energy to lift the elevator. The passengers inside the elevator do not experience any change in their weight, as they are still subject to the same gravitational force. However, they do experience a change in their relative position with respect to the Earth's surface, which can result in changes in their apparent weight.

In addition to the change in potential energy, the passengers inside the elevator may also experience changes in their kinetic energy and thermal energy due to the motion of the elevator.

Therefore, The correct answer is A)greater than your normal weight at rest.

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What average power would a 1000 kg speedboat need to go from rest to 20.0 m/s in 5.00 s, assuming the water exerts a constant drag force of magnitude fd = 500 N and the acceleration is constant.

Answers

The average power required by a 1000 kg speedboat to go from rest to 20.0 m/s in 5.00 s is 60000 Watts.

The average power required to accelerate an object is equal to the force required to overcome resistance multiplied by the velocity gained. In this case, the drag force fd opposes the acceleration of the speedboat, and so the net force on the boat is equal to the difference between the force applied to the boat and the drag force:

Fnet = Fapplied - fd = ma - fd

where m is the mass of the boat (1000 kg) and a is the acceleration. The acceleration can be calculated from the velocity gained and the time taken:

a = (vf - vi) / t = (20 m/s - 0 m/s) / 5.00 s = 4 m/s^2

So, the net force is:

Fnet = ma - fd = 1000 kg * 4 m/s^2 - 500 N = 3000 N

The power required to overcome the drag force and accelerate the speedboat is equal to the net force multiplied by the velocity gained:

P = Fnet * v = 3000 N * 20 m/s = 60000 Watts

Therefore, the average power required is 60000 Watts.

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since the time that the doe handbook was written (1993), about how many different elements had been identified (including unstable ones made artificially in accelerators)?

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Over 118 elements have been identified and placed on the periodic table, including unstable elements made artificially in accelerators. Since 1993, a number of new elements have been discovered or synthesized in the laboratory, but the exact number may have changed.

There are more than 118 components in the occasional table, including some that were made falsely in labs. This number has expanded since the time the DOE handbook was written in 1993. The disclosure of new components is a continuous interaction, and researchers are continually attempting to find and recognize new components. Nonetheless, it's difficult to give a precise number of the number of new components that have been found starting around 1993, as the field of science is continuously developing and new disclosures are being made. In this way, any reasonable person would agree that the occasional table has extended starting around 1993, and more components might be included what's in store.

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a week after full moon, the moon's phase is: a week after full moon, the moon's phase is: first quarter. third quarter. new.

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A week after full moon, the moon's phase is third quarter.

In its spherical form, the moon completes one orbit of the Earth every 29.5 days. It's being lit up by the sun from all sides as it rotates. When the moon is in its "new moon" position between the Earth and the Sun, the side of the moon that is facing us is completely in the dark, and is only dimly illuminated by sunlight reflected from the Earth. The side of the Moon that we can see from Earth grows increasingly bright as it orbits the planet. The "third quarter phase" of the moon occurs exactly one week (or 21 days) after the "new moon" phase begins or seven days after full moon. The sun's light is now shining on the opposite half of the moon's visible face.

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if the room radius was 5.1 m , and the rotation frequency 0.55 revolutions per second when the floor drops out, what minimum coefficient of static friction keeps the people from slipping down? [hint: draw a free-body diagram for a person.]

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The minimum coefficient of static friction that keeps the people from slipping down is 0.162.

Radius of the room, or radius of the rotation, R = 5.1 m

Rotation frequency, ω = 0.55 revolution/sec

ω = 2π×0.55 = 3.46 rad/sec

Then linear speed, v = rω = 5.1 × 3.46

v = 17.6 m/s

Let the mass of the person, = m

Let the minimum coefficient of static friction, = μ

Wall reaction will provide the normal reaction, N = mv²/r

Weight of the person will be balanced by the friction force, mg = μN

μmv²/r = mg

μ = rg/v²

μ = 5.1×9.81/17.6²

μ = 0.162

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Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 kmh-1?

Answers

Answer:

208333 J (approx)

Explanation:

Work required to stop = Kinetic energy of car

So,

Kinetic Energy = 1/2 * m * v^2

Convert 60 kmh-1 to ms-1

= 1/2 * 1500 * (50/3)^2

= 208333.33 J

An USB charging hub has four ports, each of which outputs a 5.0 V, 0.50 A current when in use. The ports are connected in parallel. What is the resistance of each port? When all four ports are being used, what are the resistance, voltage, and current of the circuit as a whole.

Answers

We only need to multiply 5V by the amount of current the device is drawing from the port because power is equal to current times voltage.

What is Voltage?

Although the USB port is only designed to handle electricity up to 5 A, certain manufacturers may offer a higher maximum current.

The potential difference in charge between two sites in an electrical field is quantified as voltage, also known as electromotive force.

The amount of charge carriers that pass a fixed point in a unit of time via a conducting or semiconducting medium for a certain flow resistance increases with voltage, i.e., the number of charge carriers that pass a fixed point in a unit of time.

Therefore, We only need to multiply 5V by the amount of current the device is drawing from the port because power is equal to current times voltage.

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falling raindrops frequently develop electric charges. does this create noticeable forces between the droplets? suppose two 1.8 mg drops each have a charge of 29 pc . the centers of the droplets are at the same height and 0.36 cm apart.

Answers

The electric force between the droplets, and the horizontal acceleration this force produce on the droplets are: 5.84*10^-7 N and 0.32 m/s² respectively

What is electric force?

In physics the electric force is the force that attracts or repels two charges (q) separated at a distance called (r), this is expressed in the international system of units in Newton.

To solve this exercise the electric force formulas and the procedures we will use are:

F = (k * q1 * q2)/r²F = m * a

Where:

F = electric forcek = coulomb constantq1 = charge 1q2 = charge 2m = massa = accelerationr = separation distance of the charges

Given Info:

q1= 29 pC = 2.9*10^-11 Cq2= 29 pC = 2.9*10^-11 Cr = 0.36 cm = 3.6*10^-3 mm= 1.8 mg= 1.8*10^-6 kgF =?k= 9 *10^9 N*m²/C²a=?

Applying the electric force formula we have:

F = (k * q1 * q2)/r²

F = [(9 *10^9 N*m²/C² * (2.9*10^-11 C) * (2.9*10^-11 C)]/ (3.6*10^-3 m)²

F = 7.569*10^-12 N*m² /1.296*10^-5 m²

F = 5.84*10^-7 N

Applying the force formula and clearing the acceleration, we get:

a= F/m

a= 5.84*10^-7 N/ 1.8*10^-6 kg

a= 0.32 m/s²

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Determine the ecape peed for a rocket to leave Earth' Moon. The radiu of Moon i 1740km and it ma i 7. 36×1022kg

Answers

The value of escape velocity will be 2.38 Km/s

The minimal speed necessary for an object to liberate itself from the gravitational attraction imposed by a big object is defined as escape speed, also known as escape velocity.

Escape velocity is the minimal velocity necessary to overcome a big body's gravitational potential and escape to infinity.

The velocity at which an item circles around a huge body is referred to as orbital velocity.

The escape speed from the moon can be calculated using the formula:

[tex]v_{escape = \sqrt{(2GM/r)[/tex]

Where G is the gravitational constant (6.67x10^-11 N.m^2/kg^2),

M is the mass of the moon (7.36x10^22 kg), and

r is the radius of the moon (1740 km or 1.74x10^6 m).

Plugging in the values, we get:

[tex]v_{escape = \sqrt{(2 \times 6.67 \times 10^{-11} \times 7.36 \times 10^22 / 1.74 \times 10^6)[/tex]

= 2.38 km/s

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a 0.42-kg mass attached to a spring undergoes simple harmonic motion with a period of 0.71 s . part a what is the spring constant of the spring?

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32.8N/m is the spring constant of the spring.

How does simple harmonic motion work?

Simple harmonic motion is described as the periodic motion of a point along a straight line with an acceleration that is always toward a fixed point in that line and a distance from that point that is proportional to that acceleration.

When the restoring force is inversely proportional to the displacement, the oscillations are the simplest. Recall that the equation F = kx from Hooke's law represents this circumstance. Thus, simple harmonic motion, the most basic type of oscillation, is described by and subject to Hooke's law.

We know that:

T=2π√m/k

k=4π^2×m/T^2

m = 0.42kg

T = 0.71s

k= 4*3.14*3.14*0.42/ 0.71*0.71

k = 32.8N/m

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air flows through this tube at a rate of 1200 cm3/s . assume that air is an ideal fluid.

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The height h of mercury in the right side of the U-tube is 4.37 cm.

The Bernoulli's principle of fluid dynamic states that as a fluid's static pressure or potential energy falls, so too does its speed.

Given,

Rate if volume flow Q = 1200 cm³/s

The broader end diameter D1 = 2.0 cm

The narrower end diameter D2 = 0.4 cm

By using bernoulli's theorem,

1/2pv1² + P1 = 1/2pv2² + P2

P1 - P2 = 1/2pv1² - 1/2pv2²

By using continuity equation,

Q = π(D1²/2)²v1 = π(D2²/2)²v2 = 1200 cm³/s

v2 = 4 × 1200 cm³/s / π × (0.4)² = 9550 cm/s = 95.5 m/s

v1 = 4 × 1200 cm³/s / π × (2)² = 382 cm/s = 3.82 m/s

P1 - P2 = 1/2 p(v2² - v1²)

P1 - P2 = 1/2 × 1.28 kg/m³ × ( (95.5m/s)² - (3.82m/s)² )

P1 - P2 = 5827.6 N/m²

then,

pgh = 5827.6 N/m²

h = 5827.6 N/m² / pg

h = 5827.6 N/m² / 13600 kg/m³ × 9.8 m/s² = 0.0437 m

h = 4.37 cm.

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Q. Air flows through the tube shown in figure below at a rate of 1200 cm³/s. Assume that air is an ideal fluid. What is the height h of mercury in the right side of the U-tube?

a cabin entry light of 10 watts and a dome light of 20 watts are connected in parallel to a 30-volt source. if the voltage across the 10-watt light is measured, it will be

Answers

The same as the voltage across the 20-watt light, which is 30 volts.

When two or more electrical components are connected in parallel, they are connected to the same voltage source and share the same potential difference. In this case, the 10-watt cabin entry light and the 20-watt dome light are connected in parallel to a 30-volt source.

Since they are connected to the same voltage source, the voltage across both components will be the same, which is 30 volts. This is because the potential difference across each component is determined by the voltage of the source, and not by the power or current that the component requires.

The power and current of each component will be determined by the component's resistance and the voltage across it. However, since the voltage across both components is the same, their power and current will be determined by their own individual resistances.

So even though the dome light requires more power than the cabin entry light, they will both receive the same voltage and the same potential difference.

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derive the solution of mx$ kx = 0 and plot the result for at least two periods for the case with ω n = 2 rad>s, x0 = 1 mm, and v0 = 15 mm>s.

Answers

The solution for 2 periods are x ( t) = 1 cos 2t + √5₂ Sin 2t

x ( t ) = cos 2 t + ( .1 ) 8 sin 2 t. and we can plot a graph using them

Given mx + kx = 0

x + k/m x = 0

Wn = √K/m = 2

(Dᵃ + k/m) = 0

0 =  ± i (2)

x (t) = c1 cos √k/m t + c2 sin √k/m t

x (1) = c1 cos 2t + c2 sin2t

x(0) = 1 mm

x (0) = c1 = 1 mm

x ( t ) = -2 c2 sin2t +2 c2 cos 2t

x ( 0 ) = v0 =√ 5 = 0 + 2c2

c2 = (√5₂

x ( t) = 1 cos 2t + √5₂ Sin 2t

x ( t ) = cos 2 t + ( .1 ) 8 sin 2 t

using the above two equations we can plot a graph for the two periods.

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any three-dimensional rigid object has a center of gravity. this is a point that gives the average location of the mass. why does it matter?

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The center of gravity of a three-dimensional rigid object is an important concept in physics and engineering for several reasons like stability, Dynamics, Design, Lifting and handling, etc.

Stability: The CoG of an object determines its stability. An object is considered stable if its CoG is located above its support base. If the CoG is not located above the support base, the object is considered unstable.

Dynamics: The CoG is used in the study of the dynamics of objects in motion. The CoG of an object is used to determine the forces and their reactions to those forces.

Design: in the design of objects, especially in engineering the location of the CoG can affect the stability, balance, and efficiency of an object, and it is often optimized during the design process.

Lifting and Handling: The CoG is used to determine the best way to lift and handle an object. If the CoG is known, it is easier to determine the most efficient and safe way to lift and move the object, reducing the risk of injury or damage.

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A parent is looking at their kids backpacks and wants to compare their masses. What is the best tool to find the mass of each bag

Answers

Answer:

balence

Explanation:

Final answer:

A balance scale would be the most accurate tool for a parent to use when trying to compare the masses of their kids' backpacks.

Explanation:

The best tool for comparing the masses of the backpacks would be a balance scale. A balance scale allows for precise comparison of items' weight or mass. In order to use the tool, the parent would first place one backpack on one side of the balance scale and the second backpack on the other side. The balance scale will tip towards the side of the heavier backpack, allowing the parent to determine which one has a larger mass. For a more quantitative measurement, weights can be added to the lighter side until the scale balances again. The total mass of the weights then corresponds to the mass of the heavier backpack.

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A region has a uniform electric field of 200,000 N/C directed to the northeast.A. An additional +0.25 µC placed into this region. What is the electric force on this charge?B. Now replace the first charge by a -0.25 µC. What is the electric force on this charge?A. 0.8 N southwest for A. 0.8 N northeast for B.B. 0.05 N northeast for bothC. 0.05 N southwest for A. 0.05 N northeast for B.D. 0.8 N northeast for bothE. 0.05 N northeast for A. 0.05 N southwest for B.F. 0.8 N northeast for A. 0.8 N southwest for B.

Answers

A region has a uniform electric field of 200,000 N/C directed to the Southwest. The electric force on this electron would point southwest (opposite to the direction of the electric field.)

Imagine yourself in an electric field. This field would exert an electric force on a positive point charge placed there. By definition, the field's direction at that location corresponds to the force that it applies to the positive point charge there in terms of electric field.

It should be obvious that the electric field in this area in this query points northeast. A positive point charge would therefore experience an electric force in the same direction—to the northeast—if it were placed in this area.

Negative charge characterizes electrons. An electron would experience electric force in the opposite direction from a positive point charge positioned in the same location. The positive point charge in this area has an electric force that points northeast (same as the direction of the electric field). Southwest is the polar opposite of northeast. Therefore, the direction of the electric field acting on an electron in this location would be southwest

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calculate the peak current in a 5.6 k resistor connected to a 120 v rms ac source.

Answers

The peak current in a 5.6 k resistor connected to a 120 v rms ac source   Is 0.03 Amp.

The peak current is the maximum amount of current which output is capable of sourcing for brief periods of time. When a power supply or an electrical device is first turned on, high initial current flows into the load, starting at zero and rising until it reaches a peak value, known as the peak current.

Vrms = 120v , R = 5600 ohm

Peak current = Ip

                      = peak voltage /resistance = Vp/R

Also Vp = Vrma × √2

=) Ip = Vrms ×√2 /R

       = 120√2/5600 = 0.0303 A

=) Ip = 0.03A

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which of the following are examples in which the distance traveled is not equal to the magnitude of displacement? check all that apply. group of answer choices rabbit returns home after going to eat dandelions 5 m away. a fish swims laps in the fish tank. satellite orbits earth one time. a rock falls off a mountain. a balloon is released into the air and floats away.

Answers

The distance traveled is not equal to the magnitude of displacement in the following examples: Rabbit returns home after going to eat dandelions 5 m away.

Which of the following are examples in which the distance traveled is not equal to the magnitude of displacement?Even though it has traveled 5 m, its displacement will be 0 m, since it has ended up at the same place it started. A fish swims laps in the fish tank. Even though it has swum back and forth, its displacement is 0 m since it ends up at the same place.A satellite orbits Earth one time. Even though it has traveled a great distance, its displacement is 0 m since it ends up at the same place it started. A rock falls off a mountain.Even though it has traveled a great distance, its displacement is the vertical distance from the starting point to the landing point. A balloon is released into the air and floats away. Even though it has traveled a great distance, its displacement is the straight-line distance from the starting point to the landing point.In general, the distance traveled is not equal to the magnitude of displacement when an object moves in a curved path and returns to its starting point, or when the object moves in a straight line but lands at a different location than where it started.

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The speedometer in every car also has an odometer that records the distance traveled. a) If the odometer reads zero at the beginning of a trip and 25 km a half hour later, what is the average speed in km/h? b) What is the average speed in mi/h (mph)? c) If a cheetah can maintain a constant speed of 25 m/s it will cover 25 meters every second. At this rate, how far will it travel in 5 seconds? d) How far will the cheetah travel in 1 minute?

Answers

The average speed of the car is 50 km/h and in miles per hour it is 31.0686 miles.

What is the average speed?

Average speed can be defined as the total distance travelled by an object in a particular time period. This is a scalar quantity. The SI unit of average speed is meter per second.

A. Distance travelled in half an hour = 25km

Therefore, the distance covered in an hour = 25 × 2 = 50km

The speed of the car will be 50km/hr

B. The in average speed miler per hour will be:

1km = 0.621371miles

50km = 31.0686 miles

The speed will be 31068 miles per hour.

C. Speed of cheetah = 25m/s

If, the time is 5 seconds then the distance covered by the cheetah with this speed will be:

Speed = Distance/ Time
25 = D/ 5

Distance = 25 × 5

Distance = 125 meters

D. Distance travelled in 1 minute = 60 seconds will be:

Speed = Distance/ Time

25 = D/ 60

Distance = 25 × 60

Distance = 1500 meters

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14. You should have noticed that A-tape (or B-tape for that matter) is attracted to your hand and just about any other neutral object you place in its vicinity. Why is that? 15. Humid air often makes it difficult to perform experiments with static electricity because charged objects lose their charge quickly. Why is this? 16. Why does rubbing your fingers on the non-sticky side of A-tape neutralize its charge? Keep in mind that it is the sticky side of the tape that gets charged when you peel it off the base. 17. With the triboelectric effect in mind, why do clothes taken out of the dryer tend to have a lot of static electricity? How do you think dryer sheets work to eliminate this static charge?

Answers

The answer to the multiple questions asked on friction, Humidity,  triboelectric effect and static electricity is given below.

14. A-tape (or B-tape) is attracted to a neutral object because the tape acquires a static charge through friction, and like charges repel each other while opposite charges attract. When the charged tape comes near a neutral object, the neutral object acquires an electric charge of the opposite sign, causing an attraction between the charged tape and the neutral object.

15. Humid air makes it difficult to perform experiments with static electricity because the humidity in the air provides a path for the static charge to flow to the ground, thus reducing the charge on the object. This is because water is a good conductor of electricity, allowing the static charge to dissipate more quickly than in dry air.

16. When you rub your fingers on the non-sticky side of A-tape, you transfer some electrons from your fingers to the tape, effectively neutralizing its charge. The triboelectric effect, which is the transfer of electrons from one material to another through friction, can result in a buildup of static charge on the tape. By rubbing your fingers on the tape, you equalize the distribution of electrons between the tape and your fingers, neutralizing the charge on the tape.

17. Clothes taken out of the dryer tend to have a lot of static electricity because of the triboelectric effect. As the clothes rub against each other and the dryer drum during the tumbling and spinning action, they transfer electrons, resulting in a buildup of static charge. Dryer sheets work to eliminate this static charge by releasing positively charged ions into the dryer that neutralize the static charge on the clothes. The positively charged ions are attracted to the negatively charged clothes, effectively reducing the static charge and making the clothes less likely to cling to each other.

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a basketball player of mass 56 kg wishes to jump 1.9 m up. to rise to that height, how fast must she be moving the instant her foot leaves the ground.

Answers

The basketball player must be moving at approximately 10.5 m/s to jump 1.9 m.

To calculate the speed the player must be moving at to jump 1.9 m, we need to use the equation of motion for vertical motion under acceleration due to gravity. This equation is:

v^2 = u^2 + 2as

where:

v = final velocity (speed)

u = initial velocity (speed)

a = acceleration due to gravity (9.8 m/s^2)

s = vertical distance (1.9 m)

Since the player is jumping vertically from rest (u = 0), the equation becomes:

v^2 = 2as

Substituting in the values for a and s:

v^2 = 2 * 9.8 * 1.9

v^2 = 37.24

Taking the square root of both sides:

v = sqrt(37.24)

v = approximately 6.1 m/s

So, the player must be moving at approximately 6.1 m/s the instant her foot leaves the ground to jump 1.9 m.

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on a distant planet, an astronaut drops a wrench. the wrench falls a distance of 1.52m in a time of 0.705 seconds. what is the accelration due to gravity on this planet

Answers

The acceleration due to gravity on that planet is 6.13 m/s², if the height of drop of wrench is 1.52 m and time is 0.705 seconds.

Initial velocity of the wrench, u = 0   [initially at rest]

Height travelled by the wrench, h = 1.52 m

Time taken to travel through 1.52 m height, t = 0.705 sec

Let the acceleration due to gravity at that planet is g.

By the second equation of motion,

h = ut + 0.5gt²

1.52 = 0 × t + 0.5 × g × 0.705²

1.52 = 0.248g

g = 1.52/0.248

g = 6.13 m/s²

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how many angles do you need to measure to map out the position of a sky object at any particular time?

Answers

The correct answer is 4 numbers of angles to measure to map out the position of a sky object at any particular time.

What is Degrees (°) are the units used by astronomers?

Degrees (°) are the units used by astronomers to measure the "angular distance" between celestial objects. There are 90 degrees between any point on the horizon and the highest top of the sky because a circle has 360 degrees.

So we can conclude there are 4 number of angles as 90 arc minute in sky object.

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An iron cube floats im a bowl of liquid mercury at 0 degrees C. a) if the temperature is raised to 25 degrees C, will the cube float highter or lower in the mercury? b) by what percent will the fraction of volume suberged change?

Answers

If the temperature rises to 28°c, the submerged volume fraction of the cube will increase by 0.2%.

Due to a temperature increase is defined by the following expression:

at 20∘c and then its temperature is increased by 100∘c

When the iron cube if partly immersed in mercury, the buoyant force that is acting on it will be

FB=ρVg where V is the volume of the iron cube immersed in the liquid.

Since we have a constant mass of the iron cube, from the relation of density with mass and volume for the iron cube

ρi=miVi

since the density of the iron block will decrease, to produce the same amount of buoyant force (FB=ρVg), the volume of the iron block immersed in the liquid will have to increase for the cube to not sink in the mercury.

Part (a)

If the temperature rises to 28°c, then the cube will float lower since the submerged fraction is higher (0.580), and before it was 0.578.

Part (b)

If the temperature rises to 28°c, the submerged volume fraction of the cube will increase by 0.2%. In effect, when the temperature was 0°c the submerged fraction was 57.8%, then the temperature increases to 28°c and the submerged fraction is now 58.0%.

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the property of a star that most directly affects its color is the stars ___.

Answers

The spectral type of a star is the characteristic that most directly influences its color.

A star's spectral type determines its color uniquely. A star's color is intimately correlated with its spectral class. also The hue of light emitted by a star depends on its surface temperature. Yellow stars are hotter than red stars, and yellow stars are hotter yet than blue stars. A red dwarf is the most common type of star. Spectral classes are divided into seven categories. These seven spectral classes are denoted by the letters O, B, A, F, G, K, and M, ranging from hottest to coolest. Recently, three other classes—L, T, and Y—have been introduced by astronomers for even cooler objects.

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