An average speed for a time interval is 40 km/hr. Which is the correct time interval?
(2,20) to (4,100)

(2,20) to (4,80)

(2,20) to (3,100)

(1,20) to (3,80)

Answer:

? = 61.5%

Explanation:

To find the percent abundance of 4d nails, you need to use the following equation:

Percent Abundance = (number of nails / total nails) x 100%

Percent Abundance (4d) = (123 / 123 + 77) x 100%

                                          =  (123 / 200) x 100%

                                          = 0.615 x 100%

                                          =  61.5%

Two months later 13.8 milligrams of the barium-131 still be radioactive.

It is expressed as:

[tex]A = A_{0} \times (\frac{1}{2})^{t/T}[/tex]

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

[tex]A = A_{0} \times (\frac{1}{2})^{t/T}[/tex]

   [tex]= 0.50 \times (\frac{1}{2})^{60/11.6}[/tex]

   [tex]= 0.50 \times (\frac{1}{2})^{5.17}[/tex]

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

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Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

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The partner that is used along with benzaldehyde is acetophenone to yield  1,3-Diphenylprop-2-en-1-one.

In adol condensation, aldehydes or ketones having α - H atoms undergo condensation in the presence of a dilute alkali to form β - hydroxy aldehydes or ketones.

Under mixed or crossed adol condensation,

undergoes condensation in the presence of dilute alkali to form a mixture of β - hydroxy aldehyde or ketone.

The following reaction takes place:

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Question: Mixed aldol condensations involving benzaldehyde yield typically a single product. draw the structure of the partner that was used to synthesize this molecule:

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Chemical process is responsible for the smell of vinegar in an old bottle of aspirin is Hydrolysis of ester i.e. Aspirin.

Aspirin reacts with water leading to the formation of Acetic acid which is a Carboxylic acid derivative.

Aspirin on Hydrolysis forms Acetic acid and Salicylic acid.

The reaction shows up as a fizz when aspirin is added in water.

Aspirin is called Acetyl Salicylic acid and it helps to reduce:

Acetic acid or Ethanoic acid is a colorless liquid. It is an important carboxylic acid. It smells like vinegar.

Acetic acid is used for production of following:

Salicylic acid is a bitter compound which is colorless. It reduces acne and opens up the skin pores.

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Answer:

mass = 107.04 g

Explanation:

The formula for mass is:
[tex]\boxed{mass = mole \space\ no. \times \space\ molar \space\ mass}[/tex].

In this case:

• molar mass = 32.06 g/mol

• mole no. = [tex]\frac{no. \space\ of \space\ atoms}{Avogadro's \space\ number}[/tex]

               = [tex]\frac{2.01 \times 10^{24}}{6.02 \times 10^{23}}[/tex]

               = 3.339 mol

Substituting these values into the formula for mass :

mass = 3.339 mol × 32.06 g/mol

         = 107.04 g

The answer is 107.04 g.

The first step is to find the number of moles of sulfur.

Number of moles = No. of atoms ÷ Avogadro No.

Now, to find the mass, multiply the number of atoms by the molar mass.

The total pressure of the gases in the vessel is found out by using the partial pressures of individual gases and adding them up. The total pressure of the gases in the vessel is 1.72 atm.

The Partial pressure of the gases is the individual pressure of the gases present in a vessel containing a mixture of gases. The total pressure can be found out by adding partial pressure of all gases.

Given:

Volume of vessel, V= 32.5L

Mass of Nitrogen gas = 2.8g

Mass of Hydrogen gas = 0.403g

Mass of Argon gas = 79.9g

We know that:

             Molar Mass of Nitrogen gas = 28g

             Molar Mass of Hydrogen gas = 2g

             Molar Mass of Argon gas = 40g

∴ Moles of gas = Given mass / Molar mass

∴ Using the Ideal Gas Equation:

PV = nRT

where, P is the Pressure of gas

V is the volume of gas

n is the moles of gas

R is the Universal Gas constant

T is the temperature

Applying the above equation of all three gases indivudually,

∴ For Nitrogen,

P₁V = n₁RT                    

⇒ P₁ × 32.5 = 2.8/28 × 0.082 × 298

⇒ P₁ = 0.07atm

∴ For Hydrogen,

P₂V = n₂RT                    

⇒ P₂ × 32.5 = 0.4/2 × 0.082 × 298

⇒ P₂ = 0.15 atm

∴ For Argon,

P₃V = n₃RT                    

⇒ P₃ × 32.5 = 79.9/40 × 0.082 × 298

⇒ P₃ = 1.5 atm

∴ Total pressure of vessel, P = P₁ + P₂ + P₃

                                         P = 1.72 atm

The total pressure of the gases in the vessel is 1.72 atm.

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The minimum amount of heat wasted in the production of methanol is 239kJ/mol of heat.

Now we know that the enthalpy is the heat that is released or absorbed in a reaction. The reaction involves the combination of reactants that leads to the formation of the product(s).

Now we know that the production of methanol leads to the evolution of about 239kJ/mol of heat. This heat is wasted as it goes to no good use but is just lost to the environment.

As such, the minimum amount of heat wasted in the production of methanol is 239kJ/mol of heat.

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Energy required to raise the temperature from 35°C - 45 °C= 25116 J.

specific heat, the quantity of warmth required to raise the temperature of one gram of a substance by means of one Celsius degree. The units of precise warmth are generally energy or joules consistent with gram according to Celsius diploma. for instance, the unique warmth of water is 1 calorie (or 4.186 joules) according to gram in step with Celsius degree.

solving,

Sample of liquid = 400. 0 g

temperature = 30. 0 ºc

joules of energy are required to raise the temperature of the water to 45. 0 ºc

therefore rise in temperature 45 - 30 = 15°C

Specific heat capacity = 4.186 J/g m °C

In kelvin = 273 + 15 = 288

          = ∴ energy required = Q = m s ( t final - t initial)

            =  400*4.186 * 15

           = 25116 joule

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Single displacement

Reactant

Double displacement

Product

Answer:

D

Explanation:

You are looking for   kg / L

  3.188 kg / 3.23 L = .987  kg/L

According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.

IUPAC convention of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).

The name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).

Types of IUPAC  Nomenclature of a few important aliphatic compounds:

Example :

Ethane, which has 2 carbon atoms and 6 hydrogen atoms, with the molecular formula of = C₂H₆

Formation of alkyl group:

Methane (CH₄)  Remove 1 hydrogen (H) convert to methyl (H₃-C-)

Example: Propyl (-CH₃ - CH₂ - CH₂ - )

According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.

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Sodium and chloride are the spectator ions in the reaction between aqueous zncl2 and aqueous na2co3.

Spectator ions are ions that are present on both sides of chemical reactions but do not take part in the reaction itself. The spectator ions on both sides of the equation are cancelled in the net chemical reaction. So, to "spectate" is to "see" the other ions in an aqueous solution interact with one another.

An ion known as a spectator is one that is present both before and after a chemical reaction but does not take part in it. Sodium is a spectator ion in an aqueous solution of sodium hypochlorite (NaOCl, bleach): Na+ + HOCl + OH or OCl- + H2O -

Cross out the spectator ions after comparing the reactant and product sides. Observer ions are any dissolved ions that exhibit the same form on both sides.

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Energy leaves the Sun's core and goes by radiation, convection, and radiation on its way to the surface.

Energy leaves the sun's core and initially travels towards the radiation zone. In the radiation zone, the gas is tightly compressed. Here, electromagnetic waves are absorbed and reradiated to transfer energy. Energy can take more than 100,000 years to get through this area because it is so dense.

Thus, energy radiates out initially from the core before being delivered by convection to the outer layers.

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If the concentration of a dilute solution of nitric acid is 0. 0001 M. The pH of the solution is 4.

pH is used to measure whether the substance is acidic, basic or neutral and the range is 0 - 14.

To calculate the pH hydrogen ion it is expressed as:

pH = - log [H⁺]

So, concentration of hydrogen ion in HNO₃ is 0.0001 M.

pH = - log [0.0001]

     = [tex]-\log (\frac{1}{10000})[/tex]

     = - log (10)⁻⁴

     = -4 × - log (10)

     = - 4 × (-1)

     = 4

Thus from the above conclusion we can say that The pH of the solution is 4.

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n oxidative phosphorylation, ATP production is coupled to the events in the electron-transport chain

Leucine and methionine are the amino acids formed using the n-phthalimido malonic ester synthesis.

The steps involved in phthalimido malonic ester synthesis:

Step 1: Deprotonation To Give An Enolate

In the first step, a base (CH3O– in this case) removes the most acidic proton from the ester (on C2 here, with a pKa of about 13) to give an enolate. The resulting enolate can be drawn as one of two resonance forms.

Step 2: SN2 Reaction Of The Enolate Nucleophile With An Alkyl Halide Electrophile.

Enolates are great nucleophiles. In the second step, the enolate acts as a nucleophile in an SN2 reaction to form a new C-C bond.

Step 3: Acidic Ester Hydrolysis

Acid and water are added to perform the aqueous hydrolysis of the ester to a carboxylic acid.

Step 4: Decarboxylation To Give An Enol

When carboxylic acids have a carbonyl group (C=O) two bonds away, they can readily lose carbon dioxide, because the carbonyl can act as an electron “sink” for the pair of electrons coming from the breaking C–C bond, forming an enol. This is called “decarboxylation”. Note how this is also the case for carboxylic acids with a ketone two bonds away, so-called “β-keto acids”.

Step 5: Tautomerization Of The Enol Back To The Carboxylic Acid

The enol that is formed is not a stable species. It can undergo transformation into its constitutional isomer: in this case, a carboxylic acid. These two constitutional isomers are in equilibrium with each other, although the “keto” form (with the carbonyl group) is greatly favoured. This process is called "tautomerism".

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The given bond is polar covalent bond.

Polar covalent bonds are covalent bonds in which the electrons are shared unequally. Nonpolar covalent bonds are covalent bonds with an equal distribution of electrons. Chemists utilise electronegativity, a relative measurement of how strongly an atom attracts electrons as it forms a covalent connection, to assess the relative polarity of a covalent bond.

Polarity characterises io3-. If a molecule's dipole moment is greater than 0, it is considered to be polar. The three I-O bonds in this combination are polar due to the difference in electronegativity between the I and O atoms. The three I-O bond moments point toward I atom because I is more electronegative than O atom.

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Answer: Use the pH  scale.

Explanation:

3rd statement about this acidic reaction is not true

In acidic reactions,  Litmus paper is available in red and blue varieties and is typically more trustworthy. To determine whether a solution is normal or acidic, use litmus paper. The acid or basic strength is not precisely outlined in Litmus's paper. Thus, Base causes red litmus to turn blue.

The pH scale has numbers 0 through 14. Seven is the neutral pH. Over 7 is a base, and anything below 7 is acidic.

H+ ions are present in all acidic reactions. As a result, whether mineral or organic, all acid solutions transmit electricity. They allow an electric current to flow through them.

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Answer:

homogenous mixture

Explanation:

homogenous mixtures appear in one phase and have even particle distribution.

Answer:

Air is indeed a homogeneous mixture of dinitrogen, dioxygen, carbon dioxide and a few other gases. All of the gases are in the same phase, and thus constitute a homogeneous mixture.

Explanation:

The given statement is true .

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If it takes 35.04ml of a 0.2455M NaOH solution to neutralize 25. 00ml of an unknown HCl solution, the molarity of the HCl solution is 0.34M.

The molarity of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

According to this question, it takes 35. 04ml of a 0. 2455M NaOH solution to neutralize 25.00ml of an unknown HCl solution. The molarity of the HCl can be calculated as follows:

35.04 × 0.2455 = 25.0 × V2

8.602 = 25C2

C2 = 8.6/25

C2 = 0.34M

As a result, the molarity of the HCl solution is 0.34M if it takes 35. 04ml of a 0.2455M NaOH solution to neutralize 25ml of an unknown HCl solution.

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If you were given the the total # of grams of all three compounds with the % of each molecular compound - H2O, CO2 and sugar [you would need to know the type of sugar in the Pop such as C12H22O11 as to find its MM (molar mass)]

To begin take the % of each compound x the total grams of all the compounds. For illustrative purposes let's say it works out to be 50 grams of H2O in the POP. The same would be. done for CO2 and for the sugar.

Step 1) With the mass of each you could determine the # of moles of each:

Example if the number grams of water in the sample is 50g, to determine the # of moles of water you would do the following - 50g H20 x 1 mol/18g H20 = 2.8 mol H2O The same technique would be used for the other compounds to find the # of moles.

Step 2) To find the representative particles of each(molecules, atoms) you would do the following:

as the example given of above for H20 - 50 grams you calculated as shown above to be the number of mol of H20 = 2.8mol

From the number of mol of H20, to determine the # of molecules of water you would set up the following:

2.8 mol H20 x 6.02 x 10^23/1 mol H2O = 1.69 X 10^24 molecules of H20.

The same would be done for CO2 and the sugar.

Step 3) Now to find the number of atoms of element of the compound taking for example the H2O example above:

Take the # of molecules of H2O found above and set it up in the following manner:

1.69 X 10^24 molecules H2O x 2 atoms H/1 molecule H2O = 3.38 x 10^24 atoms H

1.69 x 10^24 molecules H2O x 1 atom O)/1 molecule H2O = 1.69 X 10^24 atoms O

The same would be done for CO2 and for the sugar compound.

When the solute concentration in solution 1 is lower than the solute concentration in solution 2, solution 2 is concentrated solution .

The dilute solution and concentrated solution is relative terms.

Now in any solution there are just solute and solvent.

If amount of solute is comparatively high as compare to amount of solvent  in solution then solution is called concentrated solution. Similarly , If amount of solute is comparatively low as compare to amount of solvent  in solution then solution is called dilute solution.

If the amount of solvent is more in a solution then the amount of solute would be less.Again if the amount of solvent is less in a solution then amount of solute is more.

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The balanced chemical equation in a basic solution will be,

[tex]BrO^{-} + 4OH^{-} +4Fe^{+3}[/tex] → [tex]BrO_{3} ^{-} + 4H_{2} O+4Fe^{+2}[/tex]

The reaction in which oxidation and reduction reaction takes place simultaneously is called redox reaction or oxidation - reduction reaction .

Rules for the balanced chemical equation in a basic solution are :

Therefore, the balanced chemical equation in a basic solution will be,

[tex]BrO^{-} + 4OH^{-} +4Fe^{+3}[/tex] → [tex]BrO_{3} ^{-} + 4H_{2} O+4Fe^{+2}[/tex]

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Tetrahedral geometry is the molecular geometry if you have 4 single bonds around the central atom.

In a tetrahedral molecular geometry, a central atom is located at the centre with four substituents that are located at the corners of a tetrahedron. The bond angles are cos−1(−1⁄3) = 109.4712206...° ≈ 109.5° when all four substituents are the same, as in methane (CH4) as well as its heavier analogues. Methane and other perfectly symmetrical tetrahedral molecules belong to point group Td, but most tetrahedral molecules have lower symmetry. Tetrahedral molecules can be chiral.

The five basic shapes of hybridization are linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. The geometry of the orbital arrangement: Linear: Two electron groups are involved resulting in sp hybridization, the angle between the orbitals is 180°.

Redistribution of the energy of orbitals of individual atoms to give orbitals of equivalent energy happens when two atomic orbitals combine to form a hybrid orbital in a molecule. This process is called hybridization.  During the process of hybridization, the atomic orbitals of comparable energies are mixed together and mostly involves the merging of two ‘s’ orbitals or two ‘p’ orbitals or mixing of an ‘s’ orbital with a ‘p’ orbital as well as ‘s’ orbital with a ‘d’ orbital. The new orbitals thus formed are known as hybrid orbitals. More significantly, hybrid orbitals are quite useful in explaining atomic bonding properties and molecular geometry.

Key Features of Hybridization :

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There are 5 alpha and 5 beta particle  emit emission of thorium-232 nucleus into astatine-212.

A beta ray would be released from such an atomic nucleus during a radioactive decay process known as beta decay. The proton in the nucleus changes from a proton to a neutron throughout beta decay, and vice versa.

It is given that, The atomic mass of Th = 232

Atomic mass of astatine = 212

Atomic number of Th = 90.

Atomic number of  astatine = 85

Number of alpha particle = difference between atomic mass / 4

Number of alpha particle = 232-212 /4

Number of alpha particle = 20/4

Number of alpha particle = 5

Thus, the number of alpha particle will be 5.

Number of beta particle = difference between atomic number

Number of beta particle = 90-85

Number of beta particle = 5

Thus, the number of beta particle will be 5

Therefore, the number of alpha and beta particle will be 5 and 5.

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During action potential, positively charged  sodium ions move inside the cell.

So option D is correct one.

The sodium ion moves inside the cell during a action potential. The stage of action potential is called depolarization . This open voltage gated sodium channel.

Action potentials ( those electrical impulse that send signals around body )  is nothing but more than temporary shift ( from negative to positive ) in the neuron's membrane potential caused by ions suddenly flowing in and out of the neuron.

It consists of phases:

An active potential propagates along the cell membrane of an axon until  it reaches the terminal button.

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15M acetic acid an appropriate solvent in which to perform rate studies of electrophilic bromintations as Acetic acid activates the bromine and makes it a better electrophile.

What is electrophilic halogenation?

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Answer:

A solution with a ph of 6 has 100 times as many hydrogen ions as a solution with a ph of 8.

Explanation:

At 7 on the pH scale, a solution is neutral. Any pH lower than 7 is acidic and any pH above 7 is basic.

Acidity is a measure of the concentration of hydrogen ions in a solution. The more acidic a solution, the more hydrogen ions it has. Therefore, if the pH is decreasing, the hydrogen ion concentration is increasing.

The pH scale increases by a factor of 10. This means that for every one unit change, the hydrogen ion concentration changes tenfold. Therefore, if the pH is decreasing by 2 units (from pH 8 to pH 6), the hydrogen ion concentration should increase 100-fold (10 x 10 = 100).