if this graph of f(x)=a^(x+g) +k then;

A. the domain is (h,∞) and the range is (-∞,∞)
B. the domain is (-∞,∞) and the range is (h,∞)
C. the domain is (h,∞) and the range is (k,∞)
D. the domain is (-∞,∞) and the range is (k,∞)

Using translation concepts, the equation for function g is given by:

g(x) = 7x/3 + 1.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

Supposing that we have a function f(x), a horizontal compression by a factor of a is equivalent to finding f(ax).

In this problem, the function is:

f(x) = 7x + 1.

For the horizontal compression by a factor of 1/3, we have that:

g(x) = f(1/3x) = 7x/3 + 1.

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Answer:

y = -0.6x^2 + 5x + 6

Step-by-step explanation:

First, find the equation of a linear line that passes through the points (0,6) and (3, 15.6) in the slope intercept form, y = mx + b. We know that the line has a y-intercept of 6, so b = 6. Substitute 3 for x, 15.6 for y, and 6 for b to find m.

y = mx + b

15.6 = 3m + 6

9.6 = 3m

m = 3.2

y = 3.2x + 6

y = a(x - 0)(x - 3) + 3.2x + 6

y = a(x)(x - 3) + 3.2x + 6

Finally, substitute 10 for x and -4 for y in the equation above to find a.

-4 = a(10)(10 - 3) + 3.2*10 + 6

-4 = a(10)(7) + 32 + 6

-4 = 70a + 38

-42 = 70a

a = -0.6

Simplify to write in standard form.

y = -0.6(x)(x - 3) + 3.2x + 6

y = -0.6x^2 + 5x + 6

a. Central angle: Angle BAC

b. Major arc: Arc BEC

c. Minor arc: Arc BC

d. m(BEC) = 260°

e. m(BC) = 100°

A major arc can be defined as an arc that has a measure that is greater than a semicircle (half a circle) or greater than 180 degrees.

A minor arc can be defined as an arc that has a measure that is less than a semicircle (half a circle) or less than 180 degrees.

An angle whose vertex is at the center of a circle and has two radii of as its  sides is called a central angle of a circle.

a. Central angle in the image given is: Angle BAC

b. Major arc of the circle is: Arc BEC

c. Arc BC is a minor arc.

d. m(BEC) = 360 - 100 [based on the central angle theorem]

m(BEC) = 260°

e. angle BAC = 100°

m(BC) = angle BAC [based on the central angle theorem]

m(BC) = 100°

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Using translation concepts, the trigonometric graph is given by:

y = sin(x) + 1 = 1sin(1x) + 1.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

The parent function given in this problem is:

y = sin(x).

The dashed line is a shift up one unit of the parent function, hence the definition is:

y = sin(x) + 1 = 1sin(1x) + 1.

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The length of the apothem of the regular pentagon shown is 5.2 meters

Represent the central angle of the regular pentagon using x

The value of the central angle of the regular pentagon is then calculated as:

x = 360/n

Where n represents the number of sides

i.e n = 5

So, we have:

x = 360/5

Evaluate the quotient

x = 72

Represents the apothem with y.

The apothem is then calculated as:

tan(x/2) = (Side length/2)/Apothem

This gives

tan(72/2) = (7.6/2)/y

Evaluate the quotient

tan(36) =3.8/y

Multiply both sides by y

y tan(36) = 3.8

Divide both sides by tan(36)

y = 3.8/tan(36)

Evaluate the quotient

y = 5.2

Hence, the length of the apothem of the regular pentagon shown is 5.2 meters

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The resulting value of the function when the values of t is 2 and 6 are 3.5 and 6.5 respectively

Functions are expressions in form of variables. Given the following quadratic equation expressed as:

f(t) = 0.25t^2 − 0.5t + 3.5

We can find the equivalent value of the function when the value of t a re 2 and 6.

If the value of t is 2. hence;

f(2) =  0.25(2)^2 − 0.5(2) + 3.5

f(2) = 1 - 1 + 3.5

f(2) = 3.5

If the value of t is 6, hence;

f(6) = 0.25(6)^2 − 0.5(6) + 3.5

f(6) = 9 - 3 + 3.5

f(6) = 6.5

Hence the resulting value of the function when the values of t is 2 and 6 are 3.5 and 6.5 respectively

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(8) The algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.

(9) The minimum number of shares needed to achieve the required profit is 1223, using the algebraic expression 2.25x ≥ 2750, where x is the number of shares.

(10) The number of books needed to be sold for the novelist to make a profit of $10,000 is 4350, using the algebraic expression 5000 + 1.1495x ≥ 10000, where x is the number of books sold,

(8) Weekly target for Ms. Reed is $350.

The cost of each unit she sells is $22.

We assume the number of units she sold to be x.

Thus, the total sales done by Ms. Reed is $22x.

For her to remain employed, her total sales should exceed her target, which can be shown as an algebraic expression: 22x ≥ 350.

Thus, the algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.

(9) Profit on each share is $2.

The additional profit is $0.25.

Thus, the total profit on each share is $2 + $0.25 = $2.25.

The required profit by the customer is $2750.

We assume the number of shares needed to be x.

Thus, the total profit made by the customer is $2.25x.

For the customer to make the required profit, we can write the algebraic expression, 2.25x ≥ 2750.

To solve this, we divide both sides by 2.25 to get:

2.25x/2.25 ≥ 2750/2.25,

or, x ≥ 1222.22.

Thus, the minimum number of shares needed to achieve the required profit is 1223.

(10) Default contract of Book Maker publisher is $5000 and 5% royalty.

The cost of the book, for which the novelist has got the contract is $22.99.

We assume the number of books sold to be x.

The royalty share on each book given to the novelist is 5% of $22.99, or, $ 5/100 * 2299/100 = $ 11495/10000 = $1.1495.

Thus, the royalty received on x number of books = $1.1495*x = $1.1495x.

Thus, the total profit to the novelist = (5000 + 1.1495x).

Since the novelist wants to make a minimum profit of $10000, we can show it as the algebraic expression:

5000 + 1.1495x ≥ 10000.

To solve this, we go as follows:

5000 + 1.1495 ≥ 10000,

or, 1.1495x ≥ 10000 - 5000,

or, 1.1495x ≥ 5000,

or, x ≥ 5000/1.1495,

or, x ≥ 4349.717.

Approximating, we get x ≥ 4350.

Thus, 4350 books need to be sold to achieve the wanted profit.

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Answer:

5250%

Also, if you could label this brainliest that would be a great help!

Thanks xx

-Dante

Step-by-step explanation:

1) Formulate

2) Calculate

3) Transform expression

4) Calculate

5) Invert and multiply

6) Simplify

7) Calculate

8) Calculate

9) Rewrite the number

10) Calculate

11) Calculate

12) Convert the number

You’re done!

[tex]30 \: percent \: alcohol \: in \: 260 \: ml \\ alcohol = 0.3 \times 26 0= 78 \: ml[/tex]

[tex]c( \gamma ) = \frac{78 + 0.95\gamma }{260 + \gamma } \times 100[/tex]

[tex]c( \gamma ) = 75[/tex]

[tex] \frac{78 + 0.95\gamma }{260 + \gamma } = 0.75[/tex]

[tex]78 + 0.95\gamma = 0.75 \gamma + 195 \\ 0.2 \gamma = 117 \\ \gamma = 585[/tex]

[tex]we \: need \: 585 \: ml \: of \: 95% \: alcohol[/tex]

Answer:

You will need 585 mL of the 95% solution.

Step-by-step explanation:

From the given functions, of the cost, c(x) = 300 + 260•x, and revenue, r(x) = 300•x - x², we have;

First part;

The values of x to break-even are;

x = 30, or x = 10

Second part;

The profit function, P(x) is presented as follows;

P(x) = x•(40 - x) - 300

Third part;

The cost is c(x) = 300 + 260•x

Revenue is r(x) = 300•x - x²

First part;

At the break even point, we have;

Which gives;

300 + 260•x = 300•x - x²

x² + 260•x - 300•x + 300 = 0

Factoring the above quadratic equation gives;

x² - 40•x + 300 = (x - 30)•(x - 10) = 0

At the break even point, x = 30, or x = 10

The values of x at the break even point are;

Second part;

Profit = Revenue - Cost

The profit function, P(x), is therefore;

P(x) = r(x) - c(x)

Which gives;

P(x) = (300•x - x²) - (300 + 260•x)

P(x) = 300•x - x² - 300 - 260•x

P(x) = 300•x - 260•x - x² - 300

P(x) = 40•x - x² - 300

The profit function is therefore;

Third part;

When 10 more units are sold than the break even point, we have;

x = 30 + 10 = 40 or x = 10 + 10 = 20

The profit at x = 40 or x = 20 are;

P(40) = 40•(40 - 40) - 300 = -300

When the number of units sold, x = 40, the profit is, P(40) = -($300) unexpected loss

At x = 20, we have;

P(20) = 20•(40 - 20) - 300 = 100

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The number of tickets sold are:

From the question, we have the following parameters:

Represent the children tickets with x and adults ticket with y.

So, we have the following system of equations

x + y = 63

6x + 8y = 444

Express the equations as a matrix

x      y

1       1       63

6      8       444

Apply the following transformation

R2 = R2 - 6R1

This gives

x      y

1       1       63

0      2       66

Apply the following transformation

R2 = 1/2R2

x      y

1       1       63

0      1       33

From the above matrix, we have the following system of equations

x + y = 63

y = 33

Substitute y = 33 in x + y = 63

x + 33 = 63

Subtract 33 from both sides of the above equation

x = 30

Hence, 30 children tickets were sold and 33 adult tickets were sold

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Answer:

[tex]\textsf{Option 3}: \quad -10 x^2y^2-16x^{-2}y^2+8x^{-1}y^3[/tex]

Step-by-step explanation:

Given expression:

[tex]-2x^{-3}y(5yx^5+8xy-4y^2x^2)[/tex]

Distribute:

[tex]\implies -2x^{-3}y(5yx^5) -2x^{-3}y(8xy)-2x^{-3}y(-4y^2x^2)[/tex]

Multiply the constants and collect like terms:

[tex]\implies -10 x^{-3}x^5yy-16x^{-3}xyy+8x^{-3}x^2yy^2[/tex]

Remember that a = a¹.

[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies -10 x^{(-3+5)}y^{(1+1)}-16x^{(-3+1)}y^{(1+1)}+8x^{(-3+2)}y^{(1+2)}[/tex]

[tex]\implies -10 x^2y^2-16x^{-2}y^2+8x^{-1}y^3[/tex]

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The equation become u = k p^2 / d.

According to the statement

we have given that some conditions for the equations and we have t make the equation from the given equations.

So, For this purpose, we have given that

The equation in which u is varies directly with the square of p and inversely with d and use the k as the constant of proportionality.

So, From all these above the equation will become is

u = k p^2 / d

In latex form the equation write as :

[tex]u = \frac{kp^{2}}{d}[/tex]

In this equation all the given conditions are applicable.

So, The equation become u = k p^2 / d

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Write an equation that expresses the following relationship. u varies directly with the square of p and inversely with d In your equation, use k as the constant of proportionality.

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Answer:

The third one

Step-by-step explanation:

It cannot be the first 2 as the corners wouldn't line up. It cannot be the last one as B and R are not the same angles

The required probabilities are:

A) P(D or 5) = 4/13

B) P(H and J) = 1/13

C) P(J or 8) = 2/13

D) P(H or S) = 1/2

E) P(R and F) = 3/26

F) P(R or Q) = 7/13

The ratio of favorable outcomes to the total outcomes of an event is said to be its probability.

P(E) = n(E)/n(S)

It is given that a single card is drawn at random from a standard deck of 52 cards.

So, the sample space consists of 52 cards in total

From those,

4 suits: Hearts, Clubs, Spades, Diamonds

Each of the suit has 13 cards: { Ace, 2,3,4,5,6,7,8,9,10, Jack, Queen, King}

There are 26 Red cards and 26 Black cards.

A) The probability of drawing a diamond or a 5:

P(D or 5) = P(D) + P(5) - P(D and 5)

               = 13/52 + 4/52 - 1/52

               = 16/52 = 4/13

B) The probability of drawing a heart and a jack:

P(H and J) = P(H) × P(J) (Since they are independent events)

                 = 13/52 × 4/13

                 = 1/13

C) The probability of drawing a jack or 8:

P(J or 8) = P(J) + P(8) - P(J and 8)

              = 4/52 + 4/52 - 0

              = 2/13

D) The probability of drawing a heart or a spade:

P(H or S) = P(H) + P(S) - P(H and S)

               = 13/52 + 13/52 - 0

               = 26/52 = 1/2

E) The probability of drawing a red and face card:

P(R and F) = P(R) × P(F) (Since they are independent)

                 = 26/52 × 12/52

                 = 1/2 × 3/13

                 = 3/26

(There are three face cards- jack, king, and queen: each of 4)

F) The probability of drawing a red card or a queen:

P(R or Q) = P(R) + P(Q) -P(R and Q)

               = 26/52 + 4/52 - 2/52

               = 28/52 = 7/13

Thus, the required probabilities are calculated.

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Answer:

[tex]x=1+\sqrt[n]{y}[/tex]

Step-by-step explanation:

Since: [tex](x-1)*(x-1)*(x-1)=y[/tex]

that would imply: [tex](x-1)=\sqrt[3]{y}[/tex]

This is a bit more clear, if you write the equation as:

[tex](x-1)^3=y[/tex]

and then take the cube root of both sides

[tex]\sqrt[3]{(x-1)^3}=\sqrt[3]{y}[/tex]

Which simplifies to

[tex]x-1=\sqrt[3]{y}[/tex]

Now add 1 to both sides, and you get the equation:

[tex]x=1+\sqrt[n]{y}[/tex]

The responses include:

In mathematics, a real number simply means a value of a continuous quantity which can represent a distance along a line.

In this case, real numbers are the numbers that include both rational and irrational numbers. Here, Rmrational numbers such as integers (-2, 0, 1), fractions(1/2, 2.5) and the irrational numbers such as √3, π(22/7), etc., are all real numbers.

In conclusion, the correct options are A, B, and C.

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In matrix form, the system is given by

[tex]\begin{bmatrix} -1 & 1 & -1 \\ 2 & -1 & 1 \\ 3 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -20 \\ 29 \\ 29 \end{bmatrix}[/tex]

I'll use G-J elimination. Consider the augmented matrix

[tex]\left[ \begin{array}{ccc|c} -1 & 1 & -1 & -20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right][/tex]

• Multiply through row 1 by -1.

[tex]\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 2 & -1 & 1 & 29 \\ 3 & 2 & 1 & 29 \end{array} \right][/tex]

• Eliminate the entries in the first column of the second and third rows. Combine -2 (row 1) with row 2, and -3 (row 1) with row 3.

[tex]\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 5 & -2 & -31 \end{array} \right][/tex]

• Eliminate the entry in the second column of the third row. Combine -5 (row 2) with row 3.

[tex]\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 3 & 24 \end{array} \right][/tex]

• Multiply row 3 by 1/3.

[tex]\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right][/tex]

• Eliminate the entry in the third column of the second row. Combine row 2 with row 3.

[tex]\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right][/tex]

• Eliminate the entries in the second and third columns of the first row. Combine row 1 with row 2 and -1 (row 3).

[tex]\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 9 \\ 0 & 1 & 0 & -3 \\ 0 & 0 & 1 & 8 \end{array} \right][/tex]

Then the solution to the system is

[tex]\boxed{x=9, y=-3, z=8}[/tex]

If you want to use G elimination and substitution, you'd stop at the step with the augmented matrix

[tex]\left[ \begin{array}{ccc|c} 1 & -1 & 1 & 20 \\ 0 & 1 & -1 & -11 \\ 0 & 0 & 1 & 8 \end{array} \right][/tex]

The third row tells us that [tex]z=8[/tex]. Then in the second row,

[tex]y-z = -11 \implies y=-11 + 8 = -3[/tex]

and in the first row,

[tex]x-y+z=20 \implies x=20 + (-3) - 8 = 9[/tex]

The answers to these questions are:

a. In the question we have the existence of the mean, the mode and the median hence the answer to this question is none.

b. if the measurement 14 is replaced by 2, the data that it is going to have the most effect on is going to be the mean. It would reduce the mean.

c. If the largest measurement is removed, it is going to have the most effects on the mean and the median.

d. If the data is skewed then the mean of the data set is going to be greater.

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Answer:

120°

Step-by-step explanation:

The angle just below 'x' is 40°    (alternate angles/parallel lines)

40 + x + 20 = 180  ( straight line)

x = 120°

The function that best fits the graph points is; B: y = 65.0778 * 772.9605ˣ

From the given graph, we can see that is parabolic form and as such we can say it is an exponential function.

Looking at the options, only option B is in exponential form and as such, we will take one point on the graph to check if this is the right function.

Let us use the coordinate (0.9, 26000)

y = 65.0778 * 772.9605ˣ

y = 65.0778 * 772.9605^(0.9)

y = 25837.76

This is very close and as such is the correct option.

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Answer:

8.16 Kg

Step-by-step explanation:

average is calculated as

average = [tex]\frac{sum}{count}[/tex]

here average = 0.17 and count = 48 , then

0.17 = [tex]\frac{sum}{48}[/tex] ( multiply both sides by 48 )

8.16 = sum

that is total mass = 8.16 Kg

I'm tentatively changing my answer to say this kind of relies on practical knowledge of how stores tend to operate. If 20 coupons are given out, the store has sold all 500 shirts, arguably at a loss to the retailer. They have to have more shirts in stock to be sold at full price because, well, that's how they make money. It's more likely that such a store would carry more than just 500 shirts at the start of each day, so A is (probably) wrong.

Answer:

15.2m2

Step-by-step explanation:

hope it helps.good day

Using the relation between velocity, distance and time, it is found that the rate of the current is of 3.33 mph.

Velocity is distance divided by time, hence:

v = d/t

A small motorboat travels 12mph in still water. With the current, upstream, 46 miles are traveled in t hours, hence:

12 + r = 46/t

r = 46/t - 12

Downstream, the time is of t + 2 hours, hence:

12 - r = 46/(t + 2)

r = 12 - 46/(t + 2)

Hence, equaling the values for r:

46/t - 12 = 12 - 46/(t + 2)

46/t + 46/(t + 2) = 24

[tex]\frac{46t + 92 + 46t}{t(t + 2)} = 24[/tex]

92t + 92 = 24t² + 48t

24t² - 44t - 92 = 0

Using a quadratic equation calculator, the solution is t = 3. Hence the rate is found as follows:

r = 46/t - 12 = 46/3 - 12 = 3.33 mph.

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Answer:

x=18

Step-by-step explanation:

[tex]\frac{4}{12} =\frac{6}{x} \\[/tex]

[tex]\frac{4}{12}[/tex] ÷ [tex]\frac{2}{2}[/tex] = [tex]\frac{2}{6}[/tex] = [tex]\frac{6}{x}[/tex]

[tex]\frac{2}{6} = \frac{6}{x}[/tex]  

2×3 =6

6×3=18

x=18

Using Hinton's method;

A four-dimensional shape (4D) is a mathematical extension of a three-dimensional or 3D space.

Three-dimensional space is the simplest possible abstraction of the observation that one only needs three numbers, called dimensions, to describe the sizes or locations of objects.

Using Hinton's method;

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(i) The expanded form of (1 / 2 - 2 · x)⁵ in ascending form is 1 / 32 - (5 / 8) · x + 5 · x² - 20 · x³ + 40 · x⁴ - 32 · x⁵.

(ii) The coefficient of x³ from (1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ is - 265 / 8.

In this problem we must apply the concept of Pascal's triangle to expand the power of a binomial of the form (x + y)ⁿ and further algebra properties.

(i) First, we proceed to expand the power binomial (1 / 2 - 2 · x)⁵ in ascending order:

(1 / 2 - 2 · x)⁵ = (1 / 2)⁵ + 5 · (1 / 2)⁴ · (- 2 · x) + 10 · (1 / 2)³ · (- 2 · x)² + 10 · (1 / 2)² · (- 2 · x)³ + 5 · (1 / 2) · (- 2 · x)⁴ + (- 2 · x)⁵

( 1 / 2 - 2 · x)⁵ = 1 / 32 - (5 / 8) · x + 5 · x² - 20 · x³ + 40 · x⁴ - 32 · x⁵

(ii) Second, we proceed to expand the following product of polynomials by algebra properties:

(1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ = (1 + a · x + 3 · x²) · [1 / 32 - (5 / 8) · x + 5 · x² - 20 · x³ + 40 · x⁴ - 32 · x⁵]

(1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ = 1 / 32 + (a / 32 - 5 / 8) · x + (- 5 · a / 8 + 163 / 32) · x² + (- 175 / 8 + 5 · a) · x³ + (65 - 20 · a) · x⁴ + (- 92 + 40 · a) · x⁵ + (120 - 32 · a) · x⁶ - 96 · x⁷

In accordance with the statement, we find that:

- 5 · a / 8 + 163 / 32 = 13 / 2

- 5 · a / 8 = 45 / 32

a = - 9 / 4

Thus, the coefficient of x³ is:

C = - 175 / 8 + 5 · (- 9 / 4)

C = - 265 / 8

The coefficient of x³ from (1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ is - 265 / 8.

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