The reading on the scale is 96.31 N.
What is meant by reading on the scale?The Reading Scale describes how people progress through the difficult process of learning to read. It provides teachers with methods for viewing and analyzing their observations of children's developing reading skills, knowledge, and comprehension.
When the elevator stops, its speed decreases from 4 m/s to 0 m/s.
This suggests a slowing down. The amount of force being applied to the
F= mass times acceleration
Assuming the deceleration is constant, we have the following equation:
V = U + at
Where V = Final speed = 0
U = initial speed = 4
a = acceleration
t = time
Solving, we get:
0 = 4 + 2a
a = -2 m/s^2
Solving, we get:
0 = 4 + 2a
a = -2 m/s^2
Thus the object decelerates at 2 m/s^2
The mass of the person = 80 / 9.81 = 8.155 kg
F = 8.155 * 2
F = 16.31 N
Weight in total: 80 + 16.31 = 96.31 N (This is the reading on the scale).
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distinguishing inner and outer planetsa 2 column by 2 row table. column 1 is titled planet with the following entries: a, b. column 2 is titled length of a day in hours with the following entries: 16 hours, 1,408 hours.which planet is an inner planet, and which one is an outer planet? explain your answer.
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A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
ANSWER ASAP!!! I AM GIVING EXTRA POINTS!!!! PLEASSEEE HELP!!!
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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Jasper is using an equal force to move a tennis ball and a bowling ball. What prediction can Jasper make about the force and the motion of the objects?
Both objects will have an equal change in motion.
Neither object will have any change in motion.
The bowling ball will have a greater change in motion.
The tennis ball will have a greater change in motion.
When Jasper uses the same amount of force to move a tennis ball and a bowling ball, d)the tennis ball will have a greater change in motion.
What is the second law of motion of Newton?Newton's second law states that an object's net force is equal to the sum of its mass and acceleration.
F = ma is the formula, where F denotes force, m denotes mass, and a denotes acceleration.
When the force F is constant and we rearrange the equation, we get acceleration as a = F/m. We know that acceleration is inversely linked to the mass m. Greater mass results in smaller acceleration, and conversely, smaller mass results in greater acceleration.
We know that mass of bowling ball is more than tennis ball.
Tennis ball > bowling ball will have the highest rate of acceleration since the relationship between acceleration and mass is inverse.
It follows that tennis balls will accelerate their change of direction more quickly than bowling balls.
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50 POINTS!
Write a paragraph that answers the questions below:
If there is a situation that would require a person to use self defense, what offensive strategies would you recommend they use?
What defensive strategies would you recommend they use?
Based on the videos, which move(s) look most effective for offense if there is a situation that would need self defense?
Based on the videos, which move(s) look most effective for defense if there is a situation that would need self defense?
If a person is forced to utilize self-defense, the offensive techniques that should be recommended are as follows:
Take the initiative.I would advise them to employ the following defense strategies:
Keeping your head safeKeeping your elbow between you and the evil person.Based on the films, the move(s) that appear to be the most successful for the offense in a circumstance requiring self-defense are to target the problem rather than the person.
What is an offensive strategy?An aggressive competitive strategy is a form of company strategy that involves actively pursuing industry changes.
Companies that go on the offensive typically make acquisitions and invest extensively in R&D and technology in order to remain ahead of the competition.
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three objects are at the top of an inclined plane: a disk, a sphere, and a ring. all of the objects have the same radius and the same mass. which object would finish last in a race down the incline if they are all released from rest? (hint: use conservation of energy methods, and note that at the bottom there is both translational and rotational energy)
The ring would finish at last in the race down the incline.
Incline is a a plane surface tilted at some angle from the horizontal.
The moment of inertia of the ring = [tex]mr^{2}[/tex]
The moment of inertia of the disc = ( [tex]mr^{2}[/tex] ) / 2
The moment of inertia of the solid sphere = 2( [tex]mr^{2}[/tex] ) / 5
Since the moment of inertia is the resistance to rotational motion, we see that the object with the smallest moment of inertia will reach the bottom first.
The gain in total kinetic energy is equal to the loss in gravitational potential energy, which in turn is the same for all the objects and is equal to 'mgh'
where h is the height of the inclined plane.
So the order of reaching the bottom is Sphere, disc and ring.
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spring a is stiffer than spring b (ka > kb). the spring force of which spring does more work if the springs are compressed (a) the same distance and (b) by the same applied force?
Given that A was stiffer than B (KA > KB), the force given to both springs is the same for A, whose spring constant is higher than B's but whose expansion is smaller, and whose work will thus be less than B's.
What does physics' ideal spring look like?The equilibrium length of a perfect spring exists. When a spring is squeezed, a force pushing each end apart has a magnitude proportional to the length drop from the equilibrium length.
What is the Spring-Hooke law?Hooke aimed to show how a spring's elasticity and the forces acting on it are related. According to Hooke's Law, a spring's extension is proportional to the load placed on it. As long even as load does not exceed a material's elastic limit, a variety of materials abide by this rule.
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How can I figure out the area of something in physics?
Area in physics can be found by division of the area into simple figures such as triangles, rectangles and trapezoids and offsets from a straight line.
How to find area in physics?Area is a measure of how much space is there inside a shape and calculating the area of a shape or surface can be useful in everyday life.
The amount of surface a two-dimensional shape can cover which is measured in square units is called area and the SI unit of area is the square meter.
Area = length x breadth and Area = π × radius × radius - formulas can be used for finding area of different quadrilaterals.
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a volleyball player hits a ball of mass m horizontally against a vertical wall. the ball rebounds with the same speed v with which it struck the wall. has the momentum changed, and if so, by how much (what magnitude)?
The magnitude of the change in momentum is twice the initial momentum 2mV.
Momentum is the same as the mass of an item elevated by using its pace and is equal to the pressure required to bring the item to a stop in a unit length of time.
Calculation:-
mass of the ball = m
Let the initial velocity coming the vertical wall is = +v
Final velocity bouncing back from the wall = - V
momentum = mv
Change in momentum = m ( final velocity - initial velicity)
= m ( -V - V)
= - 2mV
Only magnitude = 2mV.
Linear momentum, translational momentum, or true momentum is manufactured from the mass and speed of an item. it's far a vector quantity, possessing a magnitude and a course. If m is an object's mass and v is its velocity. Momentum is a dimension of mass in movement. How tons mass is in how much movement. additionally, it is given the symbol p.
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what is the magnitude of the net displacement of a point on the rim of the blade during the deceleration?
The net displacement of a point on the blade's rim as a result of the deceleration is 10.0 in. or 0.254 m..
In reality, the term "deceleration" refers to an acceleration that has been reversed. We are aware that deceleration is the rate at which an object slows down and that acceleration is the pace at which an object accelerates. For instance, when we apply the brakes while driving, we are employing the benefits of deceleration to lower the speed of the car.
When we sense ourselves going forward in relation to the car while driving, we are decelerating. Deceleration in this context is a specific case of acceleration that only applies to moving things. It is hence the speed at which an object slows down.
Since acceleration must be reported as both a magnitude and a direction, it is a vector. Whenever there is one-dimensional motion.
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if momentum is conserved during inelastic collision of the two cars, what would you expect the ratio of final to initial total momentum be? calculate the ratio of final to initial total momentum. does the ratio agree with your expectation?
Inelastic collision The total momentum of the system prior to the collision was 22 361 kg*m/s, and as momentum is conserved, it is also the total momentum of the system following the collision.
The system's overall momentum is distributed equally among all of the automobiles due to their equal mass. In an inelastic collision, as opposed to an elastic impact, internal friction prevents the conservation of kinetic energy. Is called inelastic collision.
Momentum, also known as linear momentum, translational momentum, or simply momentum in Newtonian physics, is the result of an object's mass and velocity. It has a direction and a magnitude, making it a vector quantity.
final to original total momentum is equal to 22361/22361, which is 1.
therefore beginning and ultimate momentum are equal.
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1.what did you observe about the motion of objects during and after collisions? 2. based on the velocity change of each object, what did you infer about the direction of forces during a collision?
1.When two objects collide, both objects experience forces that are equal in magnitude and opposite in direction. Such forces often cause one object to accelerate (gain speed) and another object to slow down (lose speed).
2. The effect of the forces experienced on the objects during the collision is different if the masses of the objects are different. The same force causes different changes in velocity for objects with different masses. An object with a smaller mass has a greater change in velocity when the same force is applied.
What is collision?A collision means that two objects collide with each other for a very short time. In other words, a collision is the interaction of two masses in a very short period of time, where the momentum and energy of the colliding masses change.
The law of conservation of momentum usually applies to collisions between two masses, but some collisions may involve kinetic energy. Depending on the conservation of energy there can be two types of conservation:
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a tree house is 8 m above the ground. if tarzan does 360 j of work while pulling the box at constant speed from the ground up to his tree house with a rope, what is the mass of the box?
Mass refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
What is the mass of the box?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter.It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.The change caused by an applied force is smaller the more mass a body has.
The work done to place the box at tree house=350 J.
The distance from ground to tree house =4.0 m and g = 9.8/8²
E =mgh
m = 350 J / (9.8/8²* 4.0m)
m=8.929kg
Hence the mass of the box is 8.929kg
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A metal block of mass 5kg lies on a horizontal platform. if a horizontal force of 8n applied to the block through its centre of mass just slides the block on the platform. what will be the coefficient of limiting friction between the block and the platform
Answer: the coefficient would be either 4 or 5
Explanation:
A kangaroo moves with a constant speed of 90 km/h for 20 m on a straight road. Calculate the distance traveled in this period of time
We first apply the data to the problem.
Data:
V = 90km/hT = 20minD = ?Now, we convert the minutes to hours.
Conversion:
T = 20 min • (1 hr / 60 min)T = 1/3 hrThen, we apply the formula that is.
Formula:
D = V • TFinally we develop the problem.
Developing:
D = (90km/h) • (1/3h)D = 30kmThe distance traveled by the kangaroo is 30 kilometers.
Your car is going to make a 400 meter run. Your car will start at rest and accelerate at a rate of 5.89 m/s/s until it reaches top speed. This process will last for 5.83 seconds. The remainder of the run will take place at top speed. Predict the top speed and the total time of the run.
The top speed of the car is 34.34 m/s and the total time of the run is 11.65 seconds.
What is the top speed of the car?
The top speed of the car is the final or maximum speed of the car and can be determined by applying the following kinematic equation.
v = u + at
where;
v is the final speed of the car or top speed of the caru is the initial speed of the cara is the acceleration of the cart is the time of motion of the carThe initial velocity of the car = 0, since the car started from rest.
The final equation for the top speed of the car becomes;
v = 0 + at
v = at
The given parameters include the following;
v = 5.89 m/s² x 5.83 s
v = 34.34 m/s
The total time of the run is calculated as follows;
s = ut + ¹/₂at²
where;
u is the initial velocity = 0t is the total time of the runs is the total distances = 0 + ¹/₂at²
s = ¹/₂at²
t = √(2s/a)
t = √(2 x 400 / 5.89)
t = 11.65 seconds
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how do you predict that the amplitude of alpha waves recorded from a subject tested alone, in a darkened room, differ from subjects tested in a lab full of students? what might account for this?
The subject tested alone would yield better findings and higher alpha values than the subject evaluated in a lab with several pupils.
How are alpha waves recorded?Electrophysiological and closely related techniques, such as electroencephalography (EEG) or magnetoencephalography (MEG) can detect and quantify some types of brain waves, including alpha waves (qEEG).Alpha brainwaves have a higher amplitude and are slower.They oscillate between 9 and 14 cycles per second.An alpha state is frequently experienced by someone who has finished a task and is taking a break.When someone takes some time to think or meditate, they are typically in an alpha state.To learn more about Alpha brainwaves refer,
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Moving a charge from point A
A
, where the potential is 350 V
V
, to point B
B
, where the potential is 130 V
V
, takes 4.7×10−4 J
J
of work.
Answer:
Explanation:
Given:
φ₁ = 350 V - potential of point A
φ₂ = 130 V - potential of point B
A = 4.7·10⁻⁴ J - Work of the electric field
______________________
Q - ?
The magnitude of the electric charge:
Q = J / Δφ
Potential difference:
Δφ = φ₁ - φ₂ = 350 - 130 = 120 V
Then:
Q = J / Δφ = 4.7·10⁻⁴ / 120 ≈ 3.9·10⁻⁶ C or Q
Q = 3.9 mkC
suppose you have a planet with the same average density as the earth, but half the radius. how would the acceleration due to gravity on an object near the surface of that planet compare to our g (the acceleration due to gravity on an object near the surface of the earth)?
It would be half of (1/2) acceleration due to gravity on an object near the surface of that planet compare to our g.
Gravity on the planet (g') = [tex]\frac{GM}{R'^{2} }[/tex] = G(ρx [tex]\frac{4}{3}[/tex][tex]\pi[/tex][tex]R^{3}[/tex])/[tex]R'^{2}[/tex]
Where R' is the radius of the planet.
g' = [tex]\frac{4}{3}[/tex][tex]\frac{\pi GPR'}{1}[/tex]
gravity on the Earth (g) = G[tex]M_{E}[/tex]/RE
= G([tex]\frac{P 4/3\pi R_{E} ^{3} }{R_{E^{2} } }[/tex])
g = 4/3 [tex]\pi[/tex]GP[tex]R_{E}[/tex]
Now, g'/g = R'/[tex]R_{E}[/tex] = [tex]R_{E} 2[/tex]/[tex]R_{E}[/tex] = 1/2
g' = 1/2
it would be half of g.
What is acceleration?Acceleration is defined as the rate of change of velocity with respect to time. Acceleration is a vector quantity because it has both magnitude and direction. It is also the second derivative of position with respect to time or the first derivative of velocity with respect to time. The SI unit of acceleration is as [tex]m/s^2[/tex].
An object is said to accelerate when its velocity changes. A change in the speed of an object can be an increase or decrease in speed or a change in direction of motion. Some examples of acceleration are a falling apple, the moon orbiting the Earth, or a car stopping at a traffic light.
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Serena travels 1100m in 26.2s. How many significant digits should be in your answer?
The speed of Serena in the correct number of significant figures is 43.00 m/s
What is the speed?The term speed is defined as the ratio of the distance to the time that is taken. Let us recall that speed is a vector quantity hence we do not need to use the direction in finding the speed at all.
We now have the following;
Distance travelled = 1100m
Time taken = 26.2s
Speed of Serena = 1100m/26.2s
= 42.98 m/s
The speed of Serena to the correct number of significant figures is 43.00 m/s.
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what if a primordial black hole with the mass of our moon and a schwarzchild radius of 0.01cm approached, passed through, and exited the earth? what might happen to our planet and to life here?
When it will pass through our Earth, it will contain the whole of our earth as its gravitational field is so high.
What is a primordial black hole?A hypothetical type of dark gap that formed soon after the Big Bang is known as primordial dark openings. High densities and inhomogeneous circumstances in the early cosmos may have caused sufficiently thick regions to experience gravitational crumpling, which would have framed black openings. Supermassive dark gaps can be distinguished from bring down mass clusters by certain characteristics. Firstly, due to some SMBHs, the usual thickness of an SMBH (defined as the mass of the dark opening divided by the volume inside its Schwarzschild range) may be less than the thickness of water.Given that the volume of a round question, such as the occasion skyline of a non-pivoting dark opening, is specifically relative to the 3D square of the span, and that a dark gap's thickness is. On the other hand, conversely relative to the square of the mass, higher mass dark gaps have lower normal thickness, this is the reason. As with thickness, the tidal power of a body at the occasion of skyline is counterintuitively related to the square of the mass, Therefore, the tidal powers in the region of the occasion skyline are essentially weaker for monstrous dark apertures. It's a slow-moving event.When it will pass through our Earth, it will contain the whole of our earth as its gravitational field is so high.To learn more about primordial black hole, refer to
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When it will pass through our Earth, it will contain the whole of our earth as its gravitational field is so high.
What is a primordial black hole?A hypothetical type of dark gap that formed soon after the Big Bang is known as primordial dark openings.High densities and inhomogeneous circumstances in the early cosmos may have caused sufficiently thick regions to experience gravitational crumpling, which would have framed black openings.Supermassive dark gaps can be distinguished from bring down mass clusters by certain characteristics.Firstly, due to some SMBHs, the usual thickness of an SMBH (defined as the mass of the dark opening divided by the volume inside its Schwarzschild range) may be less than the thickness of water.Given that the volume of a round question, such as the occasion skyline of a non-pivoting dark opening, is specifically relative to the 3D square of the span, and that a dark gap's thickness is.On the other hand, conversely relative to the square of the mass, higher mass dark gaps have lower normal thickness, this is the reason.As with thickness, the tidal power of a body at the occasion of skyline is counterintuitively related to the square of the mass,Therefore, the tidal powers in the region of the occasion skyline are essentially weaker for monstrous dark apertures.It's a slow-moving event.When it will pass through our Earth, it will contain the whole of our earth as its gravitational field is so high.To learn more about primordial black hole, refer to
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two balls a and b, having different but unknown masses, collide. a is initially at rest when b has a speed v. after collision, b has a speed of v/2 and moves at a right angle to its original motion. find the direction in which the ball a moves after the collision.
If A ball is at rest, the moving ball's velocity vector must point to the center of the stationary ball.
Explain about the velocity vector?A velocity vector shows the rate of change in an object's position. The magnitude of a velocity vector represents an object's speed, whereas the vector's direction represents an object's direction. Velocity vectors can be added or removed in accordance with the principles of vector addition. the velocity vectors' length.
If we just state that a car is moving at 70 km/h, we have not fully described its motion because we have not stated the direction in which it is moving. Thus, a vector quantity such as velocity is an example.
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Which of the following objects have kinetic energy?
An elephant walking 1.5 m/s along the ground.
A jet flying across the sky 4,000 m above the ground.
A car traveling 20 m/s along a flat road.
A concrete block sitting on the ground.
An apple on a tree branch 3.0 m above the ground.
if, in actuality, a 710-kg car with an initial speed of 114 km/h is observed to coast up a hill and stops at a height 25 m above its starting point, how much thermal energy was generated by friction in j?
The thermal energy was generated by friction is 180490.52J.
What is thermal energy?Molecules moving within an item or substance are referred to as thermally moving. The sun is the main source of thermal energy in our solar system, but every material possesses some form of thermal energy. Heat is a flow of thermal energy that occurs when energy is transferred from one substance or object to another.
Given,
Initial speed = 114km/h = 114000/3600 = 31.66 m/s
Height = 25m
[tex]E_{intial} = E_{final}[/tex]
mg[tex]y_{i}[/tex] + 1/2m[tex]v^{2} _{i{} }[/tex] = mg[tex]y_{f}[/tex] +1/2m[tex]v^{2} _{f{} }[/tex]
Solving [tex]y_{f}[/tex] we have,
[tex]y_{f}[/tex] = m(g[tex]y_{i}[/tex] + 1/2m[tex]v^{2} _{i{} }[/tex]-1/2m[tex]v^{2} _{f{} }[/tex])
[tex]y_{f}[/tex] = (0+ 1/2 (114×1000/60×60)²-0)/9.8
[tex]y_{f}[/tex] = h = 50.94m
loss of energy = mg (50.94 - 25)
loss of energy = 710× 9.8× 25.94
loss of energy = 180490.52J.
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a 60-kg uniform board 2.4 m long is supported by a pivot 80 cm from the left end and by a scale at the right end. how far from the left end should a 40-kg child sit for the scale to read zero?
Should a 40-kg youngster sit for a 60-kg uniform board's scale to read zero at x = 0.61 m from the left end Support for the 2.4 m long piece comes from a pivot 80 cm from the left end and a scale at the right end.
Given the information that M = 60 kg and m = 40 kg, Force is viewed as a reading. The provided pivot point's torque, N, is equal to Force*(2.4 - 0.80) = 1.6 Force. (counterclockwise)
0.4*60*9.8 = 235.2 N-m is the torque of magnesium about the specified pivot point (clockwise)
Mass m should be positioned to the left scale of the pivot, and its torque should be calculated as follows:
mg*(0.80 - x) = 40*9.8*(0.80 - x) = 392
when Force = 100 N
note 1.6Force = 160 235.2 (0.80 -x)
160 + 392(0.8 - x) = 235.2
x = 0.61 m
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Using the data collected from the motion detector, the group of students is
able to calculate both initial and final velocities. The initial velocity is
measured when the mass is released, and the final velocity is measured just
as the mass hits the floor. Using these velocities, they calculate the initial and
final kinetic energies. They also calculate the initial gravitational potential
energy by measuring the initial height when the mass is released. The final
gravitational potential energy is taken to be zero at the floor. When they
compare the final (kinetic) energy value to the initial energy value (that is, the
sum of the initial kinetic and gravitational potential energies), which of the
values is greater...
if the assumptions presented in the previous problem are true?
The initial and final energies a
if the assumptions presented in the previous problem are not true?
[ Select ]
Unless the above assumptions are clear, the initial and final energies are equal.
What is kinetic energy?Kinetic energy is the form of energy that an object or a particle possess due to its motion. If work, that transfers energy, is done on an object by applying a net force, the object accelerates and thereby gains kinetic energy. Kinetic energy is a property of a moving object or particle and depends on its motion as well as its mass. The type of motion may be translational (or motion along a path from one place to another), rotational, vibrational, or any combination of motions. Translational kinetic energy is one-half the product of its mass (m) and the square of its velocity (v) or 1/2mv².
Given,
Initial and final velocities = v₁ and v₂
Initial kinetic energy = [tex]\frac{1}{2} mv_{1} ^{2}[/tex]
Final kinetic energy = [tex]\frac{1}{2} mv_{2} ^{2}[/tex]
Gravitational potential energy is calculated = mgh
As the assumptions are not clear, this question assumes no air resistance. As a result, no energy is consumed by work.
then
Initial Kinetic Energy = Final Kinetic Energy
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what is the typical power radiated by an ils localizer? what is the potential problem with an ils localizer assigned to 108.1 mhz and a nearby fm broadcast station assigned to 107.7 mhz (hint: what is the typical power radiated by fm radio stations)?
The transmitters operate between 190 and 535 kHz, have a range of at least 15 miles, and have a power of less than 25 watts.
A localizer's sensitivity range.The localizer course is typically 5°, which is fairly narrow. High needle sensitivity follows from this. When the airplane is 2.5° to either side of the centerline with this course width, a full-scale deviation is visible. This sensitivity enables precise alignment to the runway for landings.
Operating between the frequencies of 108.10 MHz and 111.95 MHz, the localizer transmitter uses one of the 40 ILS channels. Signals give the pilot direction to the middle of the runway.
An instrument landing system is a precise runway approach device that uses two radio beams to give pilots horizontal and vertical guidance as they approach the landing. The glideslope (GS) defines the proper vertical descent profile, while the localizer (LOC) offers azimuth guidance.
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The pressure of the gas is 112 kPa when its temperature is 35 °C.
The gas is heated to 340°C using some different apparatus.
Calculate the pressure of the gas when its temperature is 340 °C.
Assume the gas has a constant volume.
Pressure =
kPa
Answer:
Pressure = 223 kPa
Explanation:
Given:
p₁ = 112 kPa = 112 000 Pa
t₁ = 35°C; T₁ = 273 + 35 = 308 Pa
t₂ = 340°C; T₂ = 273 + 35 = 613 Pa
V - const
___________
p₂ - ?
Charles' law:
p₁ / T₁ = p₂ / T₂
The pressure:
p₂ = p₁·T₂ / T₁
p₂ = 112 000·613 / 308 ≈ 223 000 Pa or p₂ = 223 kPa
A sample of gas has a pressure of .87atm at 25 ˚C. What is its pressure when the temperature is increased to 50˚C?
It states that: "At constant volume the pressure of a gas sample is directly proportional to the absolute temperature."
This means that doubling the pressure of the gas will cause its absolute temperature to double.
Mathematically this law is expressed as:
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_{1}}{T_{1}}=\frac{P_{2}}{T_2} \iff \ P_1T_2=P_2T1 } \end{gathered}$} }[/tex]
We have that the data is:
P₁ = 0.87 atm
T₁ = 25 °C + 273 = 298 K
T₂ = 50 °C + 273 = 323 K
P₂ = ?
We clear for the final pressure:
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{P_{2}=\frac{P_1T_2}{T_{1}} } \end{gathered}$}}[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{P_{2}=\frac{(0.87 \ atm)\cdot(323\not{k})}{298\not{k}} } \end{gathered}$}}[/tex]
[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{P_{2}=0.94 \ atm } \end{gathered}$}}}[/tex]
If the temperature increases to 50°C, its new pressure will be 0.94 atm.when a star is moving towards us (the earth) due to a planet orbiting it and tugging on it, we see a blue shift in the star's spectrum. this corresponds to what in terms of its radial velocity?
When the radial velocity is positive, it means the distance between the objects is or was becoming closer; when it is negative, it means the distance between the source and the observer is or was getting closer.
What is radial velocity?The portion of a particle's velocity that is moving in the direction of its radius vector. or radial motion, which is the speed at which an observer approaches or recedes from a celestial body or other source of radiation in the line that connects the two: speed in the visual field.
This technique is one of the detection methods that enables us to calculate an exoplanet's mass, a crucial factor in the hunt for worlds similar to Earth and other extraterrestrial life.
Radial velocity has been used to locate hundreds of distant planets and was the first effective approach for exoplanet discovery. Because stars do not need to be continuously monitored as they do with transit photometry, it is perfect for ground-based telescopes.
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suppose you photographed earth's dark side from space, using ultraviolet-sensitive film, and using infrared-sensitive film. what would you expect to see in the photo?
The infrared image would reveal radiation coming from all around Earth, whereas the ultraviolet image would only show artificial sources like lighting.
What purposes does infrared serve?There are numerous uses for infrared. Heat sensors, thermal imaging technology, and night vision gear are some of the most popular. Infrared light is used in both wired and wireless communications and networking operations.
To avoid Earth's atmosphere and obtain a clearer view of the planets, stars, and galaxies that we are studying, space telescopes are primarily launched into orbit. Only some light can enter our atmosphere because it acts as a barrier, blocking all other light.
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