Answer:
hdggdskjn ijwzsa
Explanation:
a sleepy student drops a calculator out of a window. we can ignore air resistance. what is the velocity of the calculator after falling for 1.8s?
Answer: -18
Explanation:
Answer:
its -18
Explanation:
Khan Academy
You are a member of a geological team in Central Africa. Your team comes upon a wide river that is flowing east. You must determine the width of the river and the speed of the current (the speed of the water relative to the earth). You have a small boat with an outboard motor. By measuring the time it takes to cross a pond where the water isn’t flowing, you have calibrated the throttle settings to the speed of the boat in still water. You set the throttle so that the speed of the boat relative to the river is a constant vv1. Traveling due north across the river, you reach the opposite bank in tt1. For the return trip, you change the throttle setting so that the speed of the boat relative to the water is vv2. You travel due south from one bank to the other and cross the river in tt2. (a) How wide is the river, and what is the speed of the current? (b) With the throttle set so that the speed of the boat relative to the water is 6.00 m/s, what is the shortest time in which you could cro
In an experiment, a variable, position-dependent force F(x)F(x) is exerted on a block of mass 1.0kg1.0kg that is moving on a horizontal surface. The frictional force between the block and the surface has a constant magnitude of FfFf. In addition to the final velocity of the block, which of the following information would students need to test the hypothesis that the work done by the net force on the block is equal to the change in kinetic energy of the block as the block moves from x=0x=0 to x=5mx=5m?
Answer:
The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).
(C) is correct option.
Explanation:
Given that,
Mass of block = 1.0 kg
Dependent force = F(x)
Frictional force = F(f)
Suppose, the following information would students need to test the hypothesis,
(A) The function F(x) for 0 < x < 5 and the value of F(f).
(B) The function a(t) for the time interval of travel and the value of F(f).
(C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).
(D) The function a(t) for the time interval of travel, the time it takes the block to move 5 m, and the value of F(f).
(E) The block's initial velocity, the time it takes the block to move 5 m, and the value of F(f).
We know that,
The work done by a force is given by,
[tex]W=\int_{x_{0}}^{x_{f}}{F(x)\ dx}[/tex].....(I)
Where, [tex]F(x)[/tex] = net force
We know, the net force is the sum of forces.
So, [tex]\sum{F}=ma[/tex]
According to question,
We have two forces F(x) and F(f)
So, the sum of these forces are
[tex]F(x)+(-F(f))=ma[/tex]
Here, frictional force is negative because F(f) acts against the F(x)
Now put the value in equation (I)
[tex]W=\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}[/tex]
We need to find the value of [tex]\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}[/tex]
Using newton's second law
[tex]\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{ma\ dx}[/tex]...(II)
We know that,
Acceleration is rate of change of velocity.
[tex]a=\dfrac{dv}{dt}[/tex]
Put the value of a in equation (II)
[tex]\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{m\dfrac{dv}{dt}dx}[/tex]
[tex]\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{v_{0}}^{v_{f}}{mv\ dv}[/tex]
[tex]\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}[/tex]
Now, the work done by the net force on the block is,
[tex]W=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}[/tex]
The work done by the net force on the block is equal to the change in kinetic energy of the block.
Hence, The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).
(C) is correct option.
Consider the free-body diagram. Assume there is a net force of 30N to the right and the friction force equals 20N. What is the applied force in this situation?
A.) 20N
B.) 30N
C.) 50N
D.) 80N
Answer:the answer would be C.50N
Explanation:I just took the test
Answer:
50n
Explanation:
A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a power of 10. All numbers in scientific notation have the following form.
A✕10^n
The mass of the Sun is 1,990,000,000,000,000,000,000,000,000,000 kg. Express the mass in kg using scientific notation. (Enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e+2 for 120. WebAssign allows you to enter answers using scientific notation. For example, a number in scientific notation such as 1.32 104 would need to be entered as 1.32e4. The system requires that you do not use spaces. Enter your answer to two decimal places.)Â
____________kg
Answer:
[tex]Mass = 1.99 * 10^{30} kg[/tex]
Explanation:
Given
[tex]Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg[/tex]
Required
Rewrite using scientific notation
The format of a number in scientific notation is
[tex]Digit = a * 10^n[/tex]
Where [tex]1 \geq\ a\geq\ 10[/tex]
So the given parameter can be rewritten as
[tex]Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg[/tex]
Express as a power of 10
[tex]Mass = 1.99 * 10^{30} kg[/tex]
Hence, the equivalent of the mass of the sun in scientific notation is:
[tex]Mass = 1.99 * 10^{30} kg[/tex]
A box is dragged across an ice covered lake. The box accelerates at 0.05m/s2 and is pulled by a 45 N force. What is the mass of the box? (use the formula m=F/a)
Explanation:
a=0.05m/s
f=45N
we knw that
m=f/a
m=45/0.05
m=900kg
please please please i need heeelp
9514 1404 393
Answer:
A and B started at the same time
Explanation:
Speed is the slope of the position vs. time curve. Here, both curves have positive slope (positive speed) at t=0, so both A and B started at the same time.
Two boxes are pulled along a frictionless surface, as shown in the figure. m1 = 1.5 kg, m2 = 3.0 kg and F = 7.0 N. What is the tension in the string?
Answer:
4.7 N
Explanation:
Use ratios. 3.0 kg out of 4.5 kg total means 2/3 of the applied force = 4.7 N
Which of the following statements best describes the definition of
distance?
Explanation:
The distance covered by a body is equal to the sum of total path covered. It is equal to the total path traveled by an object during its entire journey. This quantity is always positive. It can't be 0 or a negative number.It is defined as a scalar quantity.Mathematically, it can be calculated as follows :distance = speed × time
The half-life of a radioactive substance is the amount of time required for half its mass to decay. Suppose we have 41 grams of the radioactive substance Krypton. Assume that it decays continuously at an annual rate of 6.5%.
Write a function
f
that determines Krypton's mass (in grams) in terms of the number of years
t
since we measured its initial amount.
Answer:
[tex]N(t)=41\, \,e^{-0.065*t}[/tex]
Explanation:
We use exponential decay for this example, considering that the initial amount of substance is 41 grams, and the continuous rate of decay is 6.5%:
[tex]N(t)=N_0\, \,e^{-k*t}\\N(t)=41\, \,e^{-0.065*t}[/tex]
where N(t) is the Krypton's mass of the sample in grams, in terms of number of years "t"
Using the exponential distribution concept, the expression which models the function can be expressed thus : [tex] N(t) = 41 e^{0.065t} [/tex]
Given the Parameters :
Initial mass of Krypton = 41 Decay rate, r = 6.5% = 0.065Using the exponential decay relation :
[tex] N(t) = N_{0} e^{rt} [/tex] [tex] final \: amount = N(t) [/tex] [tex] Initial \: mass = N_{0} [/tex] [tex] time = t [/tex] [tex] Decay \: rate = r [/tex]Hence, following the exponential Decay relation ; the function which models the mass of krypton based on the initial amount, decay rate and time can be expressed thus :
[tex] N(t) = 41 e^{0.065t} [/tex]Therefore, the function which models the scenario is [tex] N(t) = 41 e^{0.065t} [/tex]
Learn more :https://brainly.com/question/10992447
An object has a constant acceleration of 2.0 meters
per second2
. The time required for the object to
accelerate from 8.0 meters per second to 28 meters
per second is
Answer: 10s
Explanation:
The time required for the object to accelerate is 10 seconds.
Given the following data:
Acceleration = 2.0 [tex]m/s^2[/tex]Initial velocity = 8.0 m/s.Final velocity = 28 m/s.To find the time required for the object to accelerate, we would use the first equation of motion:
Mathematically, the second equation of motion is given by the formula;
[tex]V = U + at[/tex]
Where:
V represents the final velocity. U is the initial velocity. a represents the acceleration.t is the time measured in seconds.Substituting the parameters into the formula, we have;
[tex]28.0 = 8.0 + 2t\\\\2t = 28.0 - 8.0\\\\2t = 20.0\\\\t = \frac{20.0}{2}[/tex]
Time, t = 10 seconds.
Therefore, the time required for the object to accelerate is 10 seconds.
Read more: https://brainly.com/question/8898885
An egg is thrown upward with a velocity of 4.5 m/s. How long will it take to reach it's maximum height?
Answer:
0.45 seconds
Explanation:
Letting the value of g = 10 m/s/s
final velocity (v) = 0 m/s (since the egg will come to rest at the maximum height)
initial velocity(u) = 4.5 m/s
acceleration = -10 m/s/s (since the gravity is acting against the egg)
time = t seconds
From the first equation of motion:
v = u + at
0 = 4.5 + (-10)t
t = -4.5 / -10
t = 0.45 seconds
If the Temperature of a black body is suddenly halved the radiating power will reduce approximately by,
Consider an object with mass m that is thrown with an initial speed 0 at an angle θ with respect to the ground. The gravitational acceleration is g and it can be assumed to be constant. Derive the differential equations, and initial conditions, that govern the horizontal and vertical motion of the object assuming
(a) no air resistance and
(b) air resistance is proportional to the speed of the object.
Answer:
a) dx = v₀o cos θ dt , dy = (v_{oy} - g t) dt
b) dx / dt = v₀ₓ e^{- (\gamma/ m) t} , dv_y/dt - γ/m v_y + g =0
Explanation:
For this exercise we will use Newton's second law on each axis
F = m a
F = m d²x / dt²
let's use trigonometry for the components of the initial velocity
cos θ = v₀ₓ / v₀
sin θ = v_{oy} / v₀
v₀ₓ = vo cos θ
v_{oy} = v₀ sin θ
now we will work on each component
a) in this case there is no air resistance
X axis
Fₓ = 0
0 = m d²x / dt²
0 = m dv / dt
we integrate once
m dv = 0
m (vf- vo) = 0
v_f = v₀
we use the definition of velocity
v = dx / dt
vₓ = dx / dt
dx = v₀ₓ dt
dx = v₀o cos θ dt
we integrate once
x_f-x₀ = vₓ cos θ (t-0)
y axis
in this case the force is the weight of the body
F = W = - mg
F = m a
-m g = ma
a = -g
we use the relationship between acceleration and velocity
a = dv / dt
dv / dt = -g
dv = -g dt
we integrate
(v_y-v_{oy}) = -g (t-0)
v_y = v_{oy} - g t
now we love the relationship
v = dy / dt
dy / dt = v_{oy} - g t
dy = (v_{oy} - g t) dt
we integrate
y- y_o = v_{oy} - ½ g t²
y = y_o + v₀ sin tea t - ½ g t²
B) in this case there is air resistance, we will assume that in the two axes
x-axis) resistance always opposes movement
fr = - g v
∑ F = m aₓ
- γ vx = m dvₓ / dt
dvₓ / vₓ = - γ/m dt
ln vₓ / ln v₀ₓ = - γ/m (t-0)
vₓ = v₀ₓ [tex]e^{- (\gamma/ m) t}[/tex]
let's use the relationship between speed and distance
dx / dt = v₀ₓ e^{- (\gamma/ m) t}
dx = v₀ₓ e^{- (\gamma/ m) t} dt
Y axis
∑ F = m a_y
fr- W = m a_y
γ v_y - m g = m a_y
a_y = γ/m v_y - g
d v_y / dt = (γ /m v_y - g)
dv_y/dt - γ/m v_y + g =0
in this equation differences for the initial time the velocities vo = vo sin θ
A Top Fuel Dragster initially at rest undergoes an average acceleration of 39 m/s2 for 3.97 seconds. How far will it go in this time?
Answer:
s = 307.34 m
Explanation:
In order to find the distance covered by the dragster during the given time, we will use second equation of motion. The second equation of motion is written as follows:
s = Vi t + (0.5)at²
where,
s = distance covered by the dragster = ?
Vi = Initial Velocity = 0 m/s
t = time interval = 3.97 s
a = acceleration = 39 m/s²
Therefore,
s = (0 m/s)(3.97 s) + (0.5)(39 m/s²)(3.97 s)²
s = 307.34 m
A 100 kg man stands on bathroom scale inside an elevator, on planet where free fall acceleration is 10 m.s^2. Elevator which was initially at rest starts moving moving up with constant acceleration 5 m/s^2. Reading of the scale is
Answer:
The scale will read 1kNExplanation:
The man will feel heavy than they really are (because the floor is pushing up on them with a force larger than their weight)
like wise if the elevator descends the man will feel lighter than he is
we know
Force= mass X acceleration due to gravity
given that the mass m of the man=100kg
free fall acceleration is= 10 m.s^2.
the scale reading will be equal to the force F
F=100*10
F=1000N
The scale will read 1000N or 1kN
what is a compound and a element
Answer:
An element is made of only one type of atom. (Oxygen or sulphur) A compound is two or more elements that are chemically combined. (Iron oxide or Carbon monoxide)
Explanation:
one way to increase acceleration is by
Answer:
One way to increase acceleration is by changing the velocity.
Dr. John Paul Stapp was U.S. Air Force officer whostudied the effects of extreme deceleration on thehuman body. On December 10, 1954, Stapp rode a rocketsled, accelerating from rest to a top speed of 282 m/s(1015 km/h) in 5.00 s, and was brought jarringly back torest in only 1.40 s! Calculate his:
a. Acceleration
b. Deceleration.
Express each in multiples ofby taking its ratio to the acceleration ofgravity.
Answer:
(a) a = 56.4 m/s², his acceleration a, in multiples of gravity g, is 5.76 g
(b) a = -201.43 m/s², his deceleration -a, in multiples of gravity g, is -20.56 g
Explanation:
(a)
When moving upwards, the initial velocity, u = 0 (he accelerated from rest)
When moving upwards, the final velocity, v = 282 m/s
time of motion during this acceleration, t = 5 s
His acceleration is calculated as;
v = u + at
282 = 0 + 5a
a = 282 / 5
a = 56.4 m/s²
Ratio of his acceleration, a to gravity, g = a/g = 56.4 / 9.8 = 5.76
a = 5.76 g
(b)
When moving downwards, the initial velocity, u = 282 m/s
When moving downwards, the final velocity, v = 0 (he was brought to rest)
time of motion during this deceleration, t = 1.4 s
His deceleration is calculated as;
v = u + at
0 = 282 + 1.4a
1.4a = -282
a = -282 / 1.4
a = -201.43 m/s²
Ratio of his deceleration, -a to gravity, g = -a/g = 201.43 / 9.8 = 20.56
a = -20.56 g
Mr. Daumer wants to create a magnet. He attaches a battery to a metal wire and
wants to wrap the wire around an object. Which object should he wrap the wire around?
a) A battery
b) A pencil
c) A ruler
d) A piece of steel metal.
Older televisions display a picture using a device called a cathode ray tube, where electrons are emitted at high speed and collide with a phosphorescent surface, causing light to be emitted. The paths of the electrons are altered by magnetic fields. Consider one such electron that is emitted with an initial velocity of 2.00 x10^7 m/s in the horizontal direction when magnetic forces deflect the electron with a vertically upward acceleration of 5.25 x 10^15 m/s^2. The phosphorescent screen is a horizontal distance of 6 cm away from the point where the electron is emitted.
Required:
a. How much time does the electron take to travel from the emission point to the screen?
b. How far does the electron travel vertically before it hits the screen?
Answer:
a) [tex]3*10^{-9}\ s[/tex]
b) 2.36 cm
Explanation:
a) The horizontal distance = x = 6 cm
1 cm = 0.01 m
6 cm = 6 cm * 0.01 m/cm = 0.6 m
Therefore the time taken (t) by the electron to travel from the emission point to the screen can be gotten from:
x = t * [tex]V_i[/tex]
[tex]V_i=initial\ velocity=2*10^7\ m/s[/tex]
[tex]x=tV_i\\\\t=\frac{x}{V_i}\\ \\t=\frac{0.06}{2*10^7}\\ \\t=3*10^{-9}\ m/s[/tex]
b) The vertical distance (y) traveled by the electon before it hits the screen is given by:
[tex]y=\frac{1}{2}at^2\\ \\a=upward\ acceleration=5.25*10^{15}\ m/s^2\\\\Substituting:\\\\y=\frac{1}{2}*5.25*10^{15}* (3*10^{-9})\\\\y=0.0236\ m\\y=2.36\ cm[/tex]
A(n) ____ is an example of a mechanical wave.
Answer:
like fixing are car engine would be an example of a mechanical wave
A train is moving in the positive direction down a track. First the train speeds up, and then it slows down. What is its acceleration?
A. The train has positive acceleration throughout.
B.The train has negative acceleration throughout.
C.The train first has positive acceleration and then negative acceleration.
D.The train first has negative acceleration and then positive acceleration.
Answer:
The answer is The train first has positive acceleration and then negative acceleration.
Explanation: I answered the question right on my online school quiz.
A pendulum is observed to complete 20 full cycles in 60 seconds. Determine the period and the frequency of the pendulum.
i hope i have been useful buddy.
good luck ♥️♥️
Which notation is commonly used on force diagrams to show forces acting on an object? (FD, FZ, FN or FX)
Answer:
FD guys
Explanation:
The notation that is commonly used on force diagrams to show forces acting on an object is FD.
What is free body diagram (FD)
A free body diagram is a diagram that contains all the forces acting on an object.
These forces acting on an object include the following:
Upward force (normal reaction due to weight of the object)Downward force (downward force due to weight of the object)Frictional force (force resisting the motion)Thus, the notation that is commonly used on force diagrams to show forces acting on an object is FD.
Learn more about free body diagram here: https://brainly.com/question/21691401
The process of testing a hypothesis by collecting data is called
The mass of the planet Mars is 6.39 x 10^23 kg. Using Newton's Law of Gravitation, calculate the force of gravity between the planet Mars and the 74 kg Mars Rover drone on the surface if the distance between the center of Mars and surface is 2129.9 km. Show all work.
Need it ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Answer:
F = 695.25 N
Explanation:
The force between Mars and Rover can be given by Newton's Law of Gravitation can be written as follows:
F = Gm₁m₂/r²
where,
F = Force of Gravity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of rover = 74 kg
m₂ = mass of mars = 6.39 x 10²³ kg
r = distance between the centers of mars and rover = 2.1299 x 10⁶ m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(74 kg)(6.39 x 10²³ kg)/(2.1299 x 10⁶ m)²
F = 695.25 N
Why vacuum flask is known as thermos flak?
The flask was later developed using new materials such as glass and aluminum; however, Dewar refused to patent his invention. ... The name later became a genericized trademark after the term "thermos" became the household name for such a vacuum-insulated container for liquids.
A projectile only has _____ acceleration and ______ velocity at the top of its path?
a. vertical, vertical
b. horizontal, horizontal
c. horizontal, vertical
d. vertical, horizontal
Answer:
d. vertical, horizontal
Explanation:
A projectile's acceleration is constantly downwards.
At the top of the path, the vertical velocity is 0, leaving only the horizontal component.
Which of the following is a type of natural disaster that has impacted Florida? A. Avalanche B. Flood C. Typhoon D. Volcano
If you get it right you get 100 points and brainliest
Answer:
B-flood
Explanation:
The Sunshine State is famous all around the world for many great things but also is famous because of a big array of natural disasters.From hurricanes, tropical storms, tornadoes, to fires and floods many natural disasters in Florida affect the lives of residents.
Answer:
B. Flood
Explanation:
I would say Floods because hurricanes creates floods so...yeah
