An old grindstone, used for sharpening tools, is a solid cylindrical wheel that can rotate about its central axle with negligible friction. The radius of the wheel is 0.330 m. A constant tangential force of 200 N applied to its edge causes the wheel to have an angular acceleration of 0.844 rad/s2.

What is the moment of inertia of the wheel (in kg · m2)?
________kg · m2

What is the mass (in kg) of the wheel?
_______kg

The wheel starts from rest and the tangential force remains constant over a time period of 4.00 s. What is the angular speed (in rad/s) of the wheel at the end of this time period?
_______rad/s

An Old Grindstone, Used For Sharpening Tools, Is A Solid Cylindrical Wheel That Can Rotate About Its

Answers

Answer 1

(a) The moment of inertia of the wheel  is 78.2 kgm².

(b) The mass (in kg) of the wheel is 1,436.2 kg.

(c) The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.

Moment of inertia of the wheel

Apply principle of conservation of angular momentum;

Fr = Iα

where;

F is applied forcer is radius of the cylinderα is angular accelerationI is moment of inertia

I = Fr/α

I = (200 x 0.33) / (0.844)

I = 78.2 kgm²

Mass of the wheel

I = ¹/₂MR²

where;

M is mass of the solid cylinderR is radius of the solid cylinderI is moment of inertia of the solid cylinder

2I = MR²

M = 2I/R²

M = (2 x 78.2) / (0.33²)

M = 1,436.2 kg

Angular speed of the wheel after 4 seconds

ω = αt

ω = 0.844 x 4

ω = 3.376 rad/s

Thus, the moment of inertia of the wheel  is 78.2 kgm².

The mass (in kg) of the wheel is 1,436.2 kg.

The angular speed (in rad/s) of the wheel at the end of this time period is 3.376 rad/s.

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Related Questions

iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weight of iron ball in air?​

Answers

Answer:

453 gm

Explanation:

Immersed objects are buoyed up by force equal to mass of displaced liquid

400 + 53 = 453 gm  in air

why is the bulb of hydrometer is made heavier give two reasons​

Answers

The reason behind the heavier hydrometer bulb is the sinking of hydrometer is inversely proportional to the density of hydrometer, hence hydrometers is made heavier.

We all know that hydrometers float in liquid hence to maintain the centre of gravity while floating the hydrometer is made heavier using lead shots.

Driving space is the space around your car_____
vulnerable to collision.
O
To the side
All of the above
To the rear
To the front
in which you are

Answers

Answer:

to the rear as there will be an elastic collision

Driving space is the space around your car to the rear vulnerable to collision. the correct answer is option(c).

Driving space indicates that you have a space or a larger area to drive in that is unrestricted. You see only broad, open spaces on the road ahead and there are no limits around your automobile, so you are free to travel forward or change lanes without encountering any obstacles.

Any driver must have room around their car, preferably in the front, back, and on the sides, in order to react to problems as they arise. Your separation from the car in front of you is the most important distance to leave. Drivers' Speeding Patterns Federal and state organizations that research various elements of speeding have taken notice of speeding as the most frequent cause of deadly collisions. The NHTSA has discovered tendencies among drivers who speed recently.

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state whether the table represents a relation function both or neither x y 4 -20 1 -17 4 -14 16 5 10 0 -19 -16

Answers

state, whether the table represents a relation function both or neither x y 4 -20 1 -17 4 -14 16 5 10 0 -19 -16 Reconstruction was successful in that it allowed the United States to once again function as a single country by 1877. The states' rights vs. federalism controversy, which had been a point of contention since the 1790s, was also eventually resolved during reconstruction.

By most other standards, reconstruction was a failure: radical Republican legislation eventually failed to shield former slaves from white persecution and to bring about significant alterations to the South's socioeconomic structure. The federalism question, which had been a topic since the 1790s practically immediately, was at hand when President Rutherford B. Former Confederate officials and slaves returned to the South after Hayes withdrew federal soldiers from the region in 1877. These newly powerful white southern legislators established anti-progressive laws like voter ID requirements and black codes with the help of a conservative Supreme Court in an effort to roll back the rights that blacks had won during Radical Reconstruction. With its rulings in the Slaughterhouse Cases, the Civil Rights Cases, and United States v., the U.S. Supreme Court strengthened this anti-progressive movement federalism.


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What is the equation for the enthalpy of vaporization?

A. Q = m*Lv
B. Q = m/Lv
C. Q = 1/m*Lv
D. Q = Lv/m

Answers

Answer:

A: Q = m*Lv

Explanation:

The equation formula for the enthalpy of vaporization is;

Q = m*ΔHv

Where;

q = heat energy

m = mass

ΔHv = heat of vaporization

If a body has a velocity 50 m s-1
and the uniform acceleration is 5 m s-2, find the time it takes to travel a distance
of 240 m.

Answers

Answer:

Using the relation V^2 = U^2 + 2× a× S

V^2 = 50^2 + (2× 5 × 240 )

V^ 2 = 2500 + 2400

V^ 2 = 4900

V= (4900)^0.5 = 70 m/s

hence, velocity at a distance of 240 m will be 70m/s.

Now using the relation,

V= U + a× t

70 = 50 + 5 × t

20 = 5 × t

t = 20/5 = 4m/s

hence , time required to travel a distance of 240m will be 4s.

a simle arrangement by means of which emf are compared is known as

Answers

A simple arrangement by means of which EMF are compared is known as a voltmeter.

Discussion about Voltmeter :

A voltmeter is a straightforward device used to compare electromagnetic fields.When there is no current flowing through a cell, its terminal voltage equals its electromotive force (emf). The difference in potential between a cell's electrodes is what determines its terminal voltage. Since voltmeters use the cell's current to draw voltage, they are unable to measure a cell's emf.Using a voltmeter, one may determine the voltage generated in an electric circuit. Volts are the emf's SI unit (V). Volts are the voltage's SI unit (V). Non-coulomb force, also known as non-electric force operation, defines emf.

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(Please help 25 points)

Asteroids X, Y, and Z have equal mass of 6.0 kg each. They orbit around a planet with M=6.20E^24 kg. The orbits are in the plane of the paper and are drawn to scale.

In the statements below, TE is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy.

The PE of X at r is .... that at s

The TE of Y is .... the TE of X

The PE of Y at u is .... the PE of Z at c

The speed of Y at i is .... that at u

The KE of Z at u is .... that at m

The PE of Y at s is .... the PE of X at c

The TE of Z is .... the TE of X

The PE of X at c is .... the PE of Z at c

(Options are: greater than, less than, equal to)

Answers

The potential energy (P.E) of X at r is less than P.E at s.

The total energy (T.E) of Y is less than total energy (T.E) of X.

The PE of Y at v is greater than the PE of Z at c.

The speed of Y at i is .greater than that at v.

The kinetic energy (KE) of z at u is less than that at n.

The PE of Y at s is less than the PE of X at c.

The PE of X at c is less than the PE of Z at c.

The PE of X at c is less than the PE of Z at c.

PE of X at r  and at s

The potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.

TE of Y is .... the TE of X

The total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.

PE of Y at v is .... the PE of Z at c

The PE of Y at v is greater than the PE of Z at c due to greater displacement at v.

Speed of Y at i is .... that at u

The speed of Y at i is .greater than that at v because i is closer to the planet than v.

KE of Z at u is .... that at n

The kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.

PE of Y at s is .... the PE of X at c

The PE of Y at s is less than the PE of X at c, because position c has greater displacement.

The TE of Z is .... the TE of X

The TE of Z is greater than the TE of X due to greater displacement of Z from the planet.

The PE of X at c is .... the PE of Z at c

The PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.

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A bead of mass 15g is sliding on a wire. It has a speed of 2.0m/s at A, and it stops as it reaches the point C. The length of the wire from A to C is 250cm. How large an average friction force opposed the motion of the bead?

Answers

Answer:

.12 N

Explanation:

Velocity goes from 2 m/s    to   0  m/s   so average velocity = 1 m/s

.250 m / 1 m/s  =  .25 second to stop

change in velocity / change in time = accel

  2 m/s / .25 sec =  8 m/s^2

F = ma

  = .015 kg *  8 m/s^2  = .12 N

The figure illustrates flow through a pipe with diameters of 1.0 mm and 2.0 mm and with different elevations. Px is the pressure in the pipe, and Vx is the speed of a non-viscous incompressible fluid at locations x = Q,R,S,T, or U. Options are: Greater than, Less than, Equal to

PU is ... PQ

VU is ... 2VT

PR is ... PU.

VR is ... VS

VQ is ... VU

PR is ... PS

Answers

By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,

[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]

To find the answer, we need to know about the Bernoulli's equation as well as the Equation of continuity.

How to find the solution?

1) We have to find the relation between pressure at U and Q.

     We have the Bernoulli's equation,

                  [tex]P+\frac{1}{2}dV^2+dgh=constant.[/tex]

where, P is the pressure, V is the velocity, d is density, g is acceleration due to gravity and h is the height of the flow.

By using the equation, we can find the pressure at U and Q.

                       [tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_q+\frac{1}{2}dV_q^2+dgh\\where,\\V_u=V_q, \\since, D_p=D_q\\Thus,\\P_u=P_q+dgh[/tex]

                       [tex]P_u > P_q[/tex]

2) We have to find the relation between velocity at U and T.

For this, we have the equation of continuity as,

                           [tex]AV=constant\\A_1V_1=A_2V_2[/tex]

From the diagram, we have,

                          [tex]A_u=\pi r^2=\pi *(0.5)^2=0.25\pi *mm^2\\A_t=\pi *1=\pi mm^2\\V_u=V\\V_t=?[/tex]

Thus, the relation between velocity at U and T is,

                      [tex]V_t=\frac{A_uV_u}{A_t}=\frac{V}{4}[/tex]

                      [tex]2V_t=2*\frac{V}{4} =\frac{V}{2}\\V_u=V\\[/tex]

                       [tex]V_u > 2V_t[/tex]

3) We have to find the relation between pressure at R and U

                 [tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_r+\frac{1}{2}dV_r^2+dg*0\\\\V_u=V , then\\V_r=V_t=\frac{V}{4}=\frac{V_u}{4} \\\\P_u=P_r+\frac{1}{16}[/tex]

                   [tex]P_u > P_r[/tex]

4)  We have to find the relation between velocity at R and S

Both points R and S, have same area, thus same velocity.

                                     [tex]V_r=V_s[/tex]

5)  We have to find the relation between velocity at Q and U

Both points Q and U, have same area, thus same velocity.               

                                    [tex]V_q=V_u[/tex]

6)  We have to find the relation between pressure at R and S

Both points R and S, have same area and thus, same velocities.

                          [tex]P_r=P_s+dgh[/tex]

                           [tex]P_r > P_s[/tex]

Thus, we can conclude that, By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,

[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]

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What is the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean?
It is slightly less than 9.81 m/s2.
It is very large due to the high pressure.
It is zero.
It is significantly less than 9.81 m/s2.

Answers

The gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure. That is option B

What is gravitational acceleration?

The gravitational acceleration is the acceleration of an object that is under free fall. The acceleration due to gravity is 9.81 m/s2. above the sea level.

One of the factors that affect gravitational acceleration is depth. This is because as the depth increases so will pressure increase.

Increase in pressure leads to increase in gravitational acceleration.

Therefore, the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure.

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A converging lens has a focal length of 20cm. find graphically the image location for an object at each of the following distances from the lens: (a) 50cm (b) 20cm (c) 15cm (d) -40cm: determine the magnification in each case. Check your results by calculating the image position and lateral magnification from Eqs. (10) and (11), respectively.​

Answers

Answer:

4

Explanation:

d

for

haha

very

know

love

do

from

can

and

4 answer

It has been suggested that rotating cylinders about 19.5 mi long and 5.66 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?

_____rad/s

Answers

The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.

Angular speed of the cylinder

The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is calculated as follows;

a = v²/r

v² = ar

(ωr)² = ar

ω²r² = ar

ω²r = a

ω² = a/r

ω = √(a/r)

where;

a is centripetal acceleration = acceleration due to gravity, gr is radius of the cylinder = 5.66 m / 2 = 2.83 mi = 4554.4 mω is angular speed

ω = √(g/r)

ω =  √(9.8/4554.4)

ω = 0.046 rad/s

Thus, the angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.

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If little herbert does something uncon
sciously he will probably

Answers

If little herbert does something unconsciously he will probably, he's definitely very unware of he has done

Doing something unconscious may have some implications which may not be favourable.

What is unconscious?

Unconscious simply means a state of someone being absent minded of what is happening to him or her at a particular period of time

So therefore, if little herbert does something unconsciously he will probably, he's definitely very unware of he has done

Complete question:

What happens if little herbert does something unconsciously he will probably

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7. Four perpendicular forces, 2 N, 3 N, 9 N and 10 N act on object P as shown in Diagram 2. 10 N A B 9 N 3 N 2 N P Diagram 2 What is the magnitude of the resultant force? 10 N C 18 N 14 N D 20 N​

Answers

Answer: R=

A

2

+B

2

+2ABcosθ

θ=90

o

cos90

o

=0

R=

A

2

+B

2

=

3N

2

+4N

2

=5N

Explanation:

How do "inner planets" such as: Mercury, Venus, Earth and Mars compare with the "outer planets" such as: Jupiter, Saturn, Uranus and Neptune? Identify three characteristics that differ between these groups of planets.​

Answers

Answer:

The four inner planets have shorter orbits, slower spin, no rings, and they are made of rock and metal. The four outer planets have longer orbits and spins, a composition of gases and liquids, numerous moons, and rings. The outer planets are made of hydrogen and helium, so they are called gas giants.

Describe at least four techniques used by astronomers to determine distances to stars and galaxies. Make sure you include the scientific theory behind each method and the range over which each method is considered valid.

Answers

Radar - measuring distances in our solar system

Parallax - measuring distances to nearby stars

Cepheids - measuring distances in our Galaxy and to nearby galaxies

Supernovae - measuring distances to other galaxies

Different techniques which can be used by the astronomers to determine the distances to the stars and galaxies include Radar, Parallax, Cepheids, and Supernova.

What are the techniques to determine distance of stars?

The distances to the nearby stars are precisely and accurately determined using the different techniques such as parallax. When a celestial body is seen from a different, widely separated viewing point, its position with respect to the more distant background stars or galaxies varies. This angular difference is known as parallax.

Radar is the measuring of the distances in the solar system.

Parallax is the measuring of distances to the nearby stars.

Cepheids is the measuring of distances in Galaxy and to nearby galaxies.

Supernovae is the measuring of distances to the other galaxies.

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What is meant by constructive interference?
A. Waves combine and their amplitude decreases
B. Waves do not combine and their amplitude decreases
C. Waves do not combine and their amplitude increases
D. Waves combine and their amplitude increases

Answers

Answer:

D. Waves combine and their amplitude increases

Explanation:

amplitude is the height of the wave in a graph

constructive interference happens when two waves are lined up perfectly

example when two speakers playing same music while facing each other, music will appear louder

Destructive interference happens when the peaks match the valleys and they cancel perfectly

like with noise cancelling headphones

during constructive interference, waves collide in phase

in phase means add together making the height of the wave in a graph bigger (amplitude increases)

Example: When we see two speakers right next to each other, we can experience constructive interference when the distance from each speaker to the observer is the same

two waves destructively interfere, they must have the same amplitude in opposite directions

quizlet

flexbooksck12org

byjus

chegg

A car with a mass of 1000 kg accelerates from 0 to 90 km/h in 10 seconds. a) What is its acceleration? b) What is the net force on the car?

Answers

Answer:

v

f=90km/h=25m/s

v_{_{i}}=0v

i=0

t=10\;\mathrm{s}t=10s

m=1000\;\mathrm{kg}m=1000kg

The acceleration of the car is 2.5 m/s². The net force acting on the car is 2500 Newtons (N). The correct answers are  2.5 m/s², 2500 Newtons (N).

Given:

Mass of the car (m) = 1000 kg

Acceleration (a) = 2.5 m/s²

a) The acceleration of the car is:

Acceleration (a) = Change in velocity / Time taken

Final velocity (v(f)) = 90 × 0.27778  = 25 m/s

Acceleration (a) = (Final velocity - Initial velocity) / Time taken

Acceleration (a) = (25 - 0 ) / 10

Acceleration (a) = 2.5 m/s²

Therefore, The acceleration of the car is 2.5 m/s².

b) Newton's second law of motion:

F = m × a

F = 1000 × 2.5

F = 2500 N

The net force acting on the car is 2500 Newtons (N).

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what is atmosphere ?????​

Answers

Answer:

the envelope of gases surrounding the earth or another planet.

Answer:

An atmosphere is the layers of gases surrounding a planet or other celestial body. Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases.

Examine the roller coaster track above. Assume there is negligible friction as the roller coaster moves from position A to position F. Also assume that the roller coaster has minimal kinetic energy at point A. Create three different models below to describe the kinetic energy, the potential energy, and the total energy of the roller coaster at point E. Examples of models include, but are not limited to: pie charts, bar graphs, equations, textual descriptions, and analogies.

Answers

At point E

the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energy

What is the energy of the roller coaster at point E?

The energy of a roller coaster could either be potential energy, kinetic energy or a combination of both potential and kinetic energy.

Using analogies, the energy of the roller coaster at point E can be compared to a falling fruit from a tree which falls onto a pavement and is the rolling towards the floor. Point E can be compared to the midpoint of the fall of the fruit.

At point E

the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energy

In conclusion, the energy of the rollercoaster at E is both Kinetic and potential energy,

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2. Three blocks, A,B and C of mass 2kg. 3kg. 5kg respectively kept side by side with one another are accelerated at 2m/s2 across a smooth horizontal surface by a force F evaluated the magnitude of F and what force the blocks exert on each other.​

Answers

Answer:

Total mass of combination = 2+3+5 = 10kg.

Acceleration produced = 2m/s^2

hence force =( total mass × acceleration)= (2×10)= 20 N.

Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N

applied force on 2 kg block = 20N

Force between 2 kg and 3 kg block = (20-4) = 16N. ans

Net force on 3 kg block = 3 × 2 =6N.

Applied force on 3 kg block due to 2 kg block = 16N.

hence, force between 3 kg and 5 kg block = (16-6) = 10N .

answers:-

(a) 20 N

(b) 16N

(c) 10 N

figue 1 shows a piece of elastic being stretched between 2 pieces of wood

Answers

When a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed

However, in physics, the type of stress applied when an elastic material is stretched is tensile stress.

Recall:

Stess is defined as force per unit area

Mathematically; Stress = F/A

What is elasticity?

Elasticity can be defined as the ability of a deformed elastic material or body to return to its original size and shape when the forces causing the deformation are removed.

So therefore, when a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed

Complete question:

What happens when a piece of elastic material between two pieces of wood is being stretched beyond its limit?

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A 940-kg sports car collides into the rear end of a 2500-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.8 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact.
What was the speed sports car at impact?
Express your answer to two significant figures and include the appropriate units.

Answers

The speed of the sport car at the time of impact is 6.61 m/s.

What is the frictional force of the two cars?

Frictional force of the two cars = coefficient of kinetic frictin × mass × acceleration of gravity

= 0.8 × (2500+940) × 9.8

= 26970N

What is the acceleration of the skidded cars?As per Newton's second law of motion, force = mass × accelerationAcceleration= force / mass

= 26,970/3440

= 7.8 m/s²

What is the velocity of the sport car at the time of impact?As per Newton's equation of motion, V² - U² = 2aSHere, V = 0 m/s, a= -7.8 m/s², S= 2.8 mSo, 0²-U²= 2×(-7.8)×2.8

=> U = √43.68

= 6.61 m/s

Thus, we can conclude that the speed of the sport car at the time of impact is 6.61 m/s.

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How does the suns energy affect the climate of an area

Answers

There wouldn't be any life on Earth and no climate if it weren't for the Sun.

The spherical form of the Earth results in changes in the amount of sunlight that reaches the surface at various latitudes, giving rise to various climatic zones. Seasons are caused by the tilt of the Earth's axis of rotation in relation to the ecliptic plane.

The surface of the sun is around 6000 C hot; at this temperature, the solar mostly produces visible light. The Earth radiates infrared energy back into space to maintain its energy balance after being warmed by incoming solar radiation. The Earth's surface has an average temperature of 15 C, and at this temperature, the planet emits infrared light.

Carbon dioxide, methane, nitrous oxide, and other atmospheric greenhouse gases let solar energy to pass through but absorb infrared radiation that the planet emits back into space. This feature is not shared by other atmospheric elements like oxygen and nitrogen. These greenhouse gases re-emit infrared radiation in all directions to maintain energy balance, some of which is aimed at the Earth's surface and warms it. More greenhouse gases will increase infrared absorption and raise surface temperatures. This is comparable to how much blanket you cover yourself with at night. The blanket's thickness affects how warm you feel. The result of heat brought on by rising levels of greenhouse gases in the atmosphere is climate change.

In the course of billions of years, the Sun will continue to get hotter and brighter, rendering the Earth uninhabitable.

Additionally, all fossil fuels (coal, petroleum, and natural gas) and renewable energy are directly and indirectly derived from the sun (wind, solar, biomass, and hydroelectric).

Thank you,

Eddie

The Sun is the only source of energy for the Earth's climate system. Important to earth's atmosphere is the warming of the atmosphere caused by solar radiation, which also causes global wind patterns and aids in the development of clouds, storms, and rainfall.

An electron is moving the east with a speed of 5.0 × 106 m/s. There is an electric field of
3.0 kV/m in the east direction. What will be the electrons speed after it has moved 1.00 cm?

Answers

The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

What is Electric field?

Electric field is the physical field that surrounds a charge.

How to find final velocity of the electron when it moves some distance in a certain electric field?From Newton's second law, the acceleration the electron will be

a=F/m=qE/m

where q= charge of electron

E= electric field

m= mass of electron

=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)

=10¹⁵×0.526m/s²

The kinematics equation v²=v0²+2a(Δx)where v=final velocity of the electron

v0=initial velocity of the electron =5×10⁶m/s

a=acceleration of the electron =10¹⁵×0.526m/s²

Δx=distance moved by the electron in east direction =1cm=10^-2m

Now v^2=(5×10⁶)²+2×10¹⁵×0.526×10^-2

=25×10¹²+10.52×10¹²

=35.52×10¹²

Now velocity of electron=5.95×10⁶m/s.

Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

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If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical speed be after having fallen a vertical distance of 50.8m if you neglect air resistance over that distance?

Answers

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

Time of motion of the girl

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

v is initial vertical velocity = 0t is time of motiong is acceleration due to gravity

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

Final vertical velocity of the skydiver

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

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I = 30A and R = 30; what is V?



A. 900v
B.90v
C.10v
D.0.1v

Answers

Answer:

[tex]V = 900\; {\rm V}[/tex] for a resistor where [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex].

Explanation:

By Ohm's Law, if the electric resistance of a resistor is [tex]R[/tex] and the current going through that resistor is [tex]I[/tex], the voltage across that resistor would be [tex]V = I\, R[/tex].

Note that electric resistance is typically measured in Ohms, where [tex]1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}[/tex].

Given that [tex]I = 30\; {\rm A}[/tex] and [tex]R = 30\; {\rm \Omega}[/tex] for the resistor in this question, apply the formula [tex]V = I\, R[/tex] to find the voltage [tex]V[/tex] across this resistor:

[tex]\begin{aligned} V &= I\, R \\ &= 30\; {\rm A} \times 30\; {\rm \Omega} \\ &= 30\; {\rm A} \times 30\; {\rm V \cdot A^{-1}} \\ &= 900\; {\rm V} \end{aligned}[/tex].

A uniform linear charge of 3.0 nC/m is distributed along the y axis from y = -3 m to y=2m. Which of the following integrals is correct for the magnitude of the electric field at y = 4 m on the y axis?

Answers

[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex] is the integrals for the magnitude of the electric field.

A characteristic of electricity exists at every location in space when charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.

The formula for the electric field due to a point charge is:

[tex]E = \frac{kq}{r^2}[/tex]

Here q is the charge, r is the distance from the charge, and k = 8.99 × [tex]10^9 Nm^2/ C^2[/tex]

Imagine an infinitely - tiny portion of this charge distribution that has a charge [tex]dq[/tex]. This charge produces an electric field dE with magnitude:

                           [tex]\int\limits^ {} \, dE = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]

                               [tex]E = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]

Here, λ = 3.0 nC/m dq

           = λ.dy dE = ∫k.dq

From y = -3 m to y = 2 m, there is a 3.0 nC/m uniform linear charge distributed along the y axis.

The integrals for the magnitude of the electric field at y = 4 m on the y axis:

[tex]E = k \lambda \int\limits^2_{-3} {} \, \frac{dy}{( 4 - y)^2}[/tex]

[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex]

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It is useful to use a _________ to demonstrate how an electric circuit works

Answers

It is useful to use a model in order to demonstrate how an electric circuit works.

What is a model?

In science, a model is a graphical representation that my result useful to predict the behavior of the components of a given system that works together to produce a particular outcome.

For example, an electrical circuit can be modeled by taking into account resistance, voltage, and intensity as parameters of functioning.

The electrical circuits are graphically represented by modeling the movement or flow of negatively charged electrons (e-) from the negative pole to the positive pole of a closed electric circuit.

In conclusion, it is useful to use a model (ie., a scientific model) to demonstrate how an electric circuit works.

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