Answer:
(a) The potential near its surface is 45 * 10^6 V.
(b) The distance from which its center is the potential 1.00 MV is 45 m.
(c) Its energy in MeV when the atom is at the distance found in part b is 132 MeV.
Explanation:
Note: This question is not complete. The complete question is therefore provided before answering the question.
A research Van de Graaff generator has a 2.00-m diameter metal sphere with a charge of 5.00 mC on it. (a) What is the potential near its surface?
(b) At what distance from its center is the potential 1.00 MV?
(c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?
The explanation of the answer is now provided as follows:
(a) What is the potential near its surface?
Q = Charge on the generator = 5 mC = 5 * 10^(-3)C
r = Sphere radius = 2 / 2 = 1 m
k = Constant of the electric force = 9 * 10^(9) N . m^2 / C^2
Therefore, the electric potential of a point charge can be calculated as follows:
V = kQ / r
V = (9 * 10^9 * 5 * 10^(-3)) / 1 = 45 * 10^6 V
Therefore, the potential near its surface is 45 * 10^6 V.
(b) At what distance from its center is the potential 1.00 MV?
This implies the distance where the potential is 1 MV.
Since the electric potential of a point charge is as follows:
V = kQ / r
Therefore, we can solve for r and estimate it as follows:
R = kQ / V = (9 * 10^9 * 5 * 10^(-3)) / 1 * 10^6 = 45 m
Therefore, the distance from which its center is the potential 1.00 MV is 45 m.
(c) An oxygen atom with three missing electrons is released near the Van de Graaff generator. What is its energy in MeV when the atom is at the distance found in part b?
The link between the potential difference and electrical potential energy can be stated as follows:
ΔV = ΔU / q
Therefore, we have:
ΔU = qΔV = q(Va - Vb) = 3 * (45 – 1) = 132 MeV
Therefore, its energy in MeV when the atom is at the distance found in part b is 132 MeV.
2x^2+8x-7 solve the equation
Answer:
x = (-4 + √30) / 2, or x = (-4 – √30) / 2
Explanation:
x = (-b ± √b² – 4ac) / 2a →
y = ax² + bx + c
given
y = 2x² + 8x – 7 →
x = (-(8) ± √(8)² – 4(2)(-7)) / 2(2) →
x = (-8 ± √64 + 56) / 4 →
x = (-8 ± √120) / 4 →
x = (-8 ± 2√30) / 4 →
x = (-4 ± √30) / 2 →
x = (-4 + √30) / 2, or x = (-4 – √30) / 2
Calculate the individual percent recoveries of benzoic acid, naphthalene and 3-nitroaniline if you were able to collect 9.75 g of benzoic acid, 6.41 g of naphthalene, and 7.71 g of 3-nitroaniline from a set of extractions. The starting mass of the mixture was 26.24 g. (0.6 pt)
Answer:
Benzoic acid= 37.16%
Naphthalene = 24.43%
3-Nitroaniline= 29.38%
Explanation:
Data given:
percentage recovery of benzonic acid = 9.75/26.24 * 100 = 37.16%
Percentage recovery of napthalene = 6.41/26.24 * 100 = 24.43%
Percentage recovery of 3-nitroaniline = 7.71/26.24 * 100 = 29.38%
Which of the following is an alkaline earth metal?
O A. Carbon (C)
O B. Aluminum (AI)
O C. Magnesium (Mg)
O D. Silicon (Si)
Answer:
Magnesium (Mg)
Explanation:
The elements have very similar properties: they are all shiny, silvery-white, somewhat reactive metals at standard temperature and pressure.
Please mark me as brainliest
Thank You
Answer:
The answer is C. Magnesium(Mg)
Pls thank you
A. Directions:Describe ways on how to protect humans and plants and animals Choose your answer in the box and fill in the concept map below
Answer:
i) Humans - drinks lot of water
- use umbrella
- use hats and sunglasses
- apply sunblock when swimming
- wear rush guard
ii) Plants - water the plants
-put a shade on the plants
iii) Animals - provide pets with plenty of water
- place the animals under the tree during noon time
name this organic compound
I don't need explaination just give the name
Answer:
Toluene
Explanation:
This compound is called toluene.
It is a phenyl group where it is bonded a methyl.
It is an aromatic compound.
IUPAC name can be, Methylbenzene.
As an organic compound it can not be dissolved in water.
This can be a reaction of synthesis:
C₆H₅H + CH₃Cl → C₆H₅CH₃ + HCl
which is not one of daltons hypothesis of atomic theory
elements are composed of atoms
compounds are composed of atoms of more than one element
a chemical reaction involved the rearranging of atoms
all atoms of a given element are identical
the atoms of one element are the same as another
Answer:
because atoms is just a chemical ahahahah
Explanation:
hope it helps ☺️
Dalton's hypothesis of atomic theory was given by John Dalton. The atoms of one element are the same as another and are not part of Dalton. Thus, option E is correct.
What is Dalton's theory?Dalton gave the atomic theory where atoms are the fundamental unit of the element of the periodic table. More than one element and atoms combine to form molecules and compounds.
The property of the atoms to get rearranged is the basis of the chemical reaction that results in the formation of the new product. This resulted in the formulation of chemical combinations. The atoms of the given element are said to be the same like the potassium contains the same atom.
The atoms of one element cannot be the same as another atom, like the atom of sodium and chloride are not the same. They are different in physical and chemical properties.
These atoms follow the law of conservation of mass. The atoms are composed of sub-atomic particles that have been constituted of neutrons, electrons, and protons.
Therefore, in option E. the atoms of two elements can never be the same.
Learn more about Dalton's theory, here:
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True/False: Chemical reactions can NOT proceed in the reverse direction
Please help me ASAP I’ll mark Brainly
Answer:
1. Vacuole
2. chloroplast
3. Nucleus
4. Plasma membrane - cell membrane
5. Vacuole (same as #1 ?) could be vesicle
Explanation:
Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.)
______________ → BaBr2 + H2O
Answer:
Ba(OH)₂ + 2 HBr ⇒ BaBr₂ + 2 H₂O
Explanation:
We have the products of a reaction and we have to predict the reactants. Since the products are binary salt and water, this must be a neutralization reaction. In neutralizations, acids react with bases. The acid that gives place to Br⁻ is HBr, while the base the gives place to Ba²⁺ is Ba(OH)₂. The balanced chemical equation is:
Ba(OH)₂ + 2 HBr ⇒ BaBr₂ + 2 H₂O
b) What is the change in entropy of the reaction if ΔH° = -3.2 kJ mol-1?
The Hammond Postulate describes the relationship between the energy of the transition state and the productdistribution in a reaction that is capable of following more than one pathway.
What are the appropriate labels for the sentence?
The Hammond postulate states that reactions which are thermodynamically endothermic and kinetically ___________ have transitions states that occur ___________ in the reacton time frame, and resemble the ___________ in terms of energy and structure.
Chloride ion is a strong nucleophile and bromide is a good leaving group. The major product of treating (S)-2-bromobutane with NaCl in CH3C(O)CH3 (acetone) is _________. (1S,2R)-1-chloro-2-bromobutane cis-2-butene (1R,2S)-1-chloro-2-bromobutane (S)-2-chlorobutane trans-2-butene (R)-2-chlorobutane
Answer:
Chloride ion is a strong nucleophile and bromide is a good leaving group. The major product of treating (S)-2-bromobutane with NaCl in CH3C(O)CH3 (acetone) is _________. (1S,2R)-1-chloro-2-bromobutane cis-2-butene (1R,2S)-1-chloro-2-bromobutane (S)-2-chlorobutane trans-2-butene (R)-2-chlorobutane
Explanation:
The reaction of (S)-2-bromobutane with NaCl in CH3C(O)CH3 (acetone) forms the following product:
The answer is (R)-2-chlorobutane.
The reaction take splace through [tex]S_{N} _2[/tex] mechansim and inversion in configuration happens.
Identify the most oxidized compound. Group of answer choices CH3CH2CHO CH3CH2CH3 CH3CH2CH2OH CH3CH2OCH3 CH3CH2COOH
Answer:
Huh!?
Explanation:
explain me please
A 1.5-m 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa. Now paddle-wheel work is done on the system until the pressure in the tank rises to 150 kPa. Determine the entropy change of carbon dioxide during this process. Assume constant specific heats
Answer:
The entropy change of carbon dioxide = 0.719 kJ/k
Explanation:
Given:
1.5 m - 3 insulated rigid tank contains 2.7 kg of carbon dioxide at 100 kPa
The objective is to determine the entropy change of carbon dioxide
Formula used:
ΔS=
Solution:
On considering,
[tex]C_{P} =0.846 kJ/kg K\\C_V=0.657 kJ/kg k\\[/tex]
ΔS=[tex]mc_{v} lu\frac{p_{2} }{P_{1} }[/tex]
On substituting the values,
ΔS=[tex]2.7*0.657lu\frac{150}{100}[/tex]
ΔS=0.719 kJ/k
The entropy change is "0.719 kJ/K".
Given values are:
Mass of tank,
m = 2.7 kgPressure,
P₁ = 100 kPaRised pressure,
P₂ = 150 kPaAssumption of constant specific heat is,
[tex]C_v = 0.657 \ kJ/kgK[/tex]As we know the formula,
→ [tex]\Delta S = mC_v \ ln(\frac{P_2}{P_1} )[/tex]
[tex]= (2.7)(0.657) \ ln (\frac{150}{100} )[/tex]
[tex]= 1.7739\times 0.4055[/tex]
[tex]= 0.7193 \ kJ/K[/tex]
Thus above answer is right.
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the force of attraction between non polar molecules are what
Answer:
dispersion force
Explanation:
On the basis of your knowledge of the reaction of halogens with alkanes, decide which product you would not expect to be formed in even small quantities in the bromination of ethane?
A) BrCH2CH2Br
B) CH3CH2CH2Br
C) CH3CHBr2
D) CH3CH2CH2CH3
E) BrCH2CH2CH2CH2Br
Answer:
On the basis of your knowledge of the reaction of halogens with alkanes, decide which product you would not expect to be formed in even small quantities in the bromination of ethane?
A) BrCH2CH2Br
B) CH3CH2CH2Br
C) CH3CHBr2
D) CH3CH2CH2CH3
E) BrCH2CH2CH2CH2Br
Explanation:
The reaction of ethane with bromine in presence of UV light forms mono substituted ethane at all primary and secondary carbons.
This is an example of free radical substitution.
The structure of ethane and its bromination is shown below:
Among the given options that which is not possible to form is option B) that is CH3CH2CH2Br(propyl bromide).
Remaining all other products are possisble to form on free radical substitution of ethane.
Which is a nervous system test?
Answer:
Sorry, is there supposed to be an attachment, If so kindly republish your Question.
One student measured a spectrum and observed double yellow lines. He claimed that it must be Sodium. Please justify if he is correct. Why
Answer:
We know that the student was measuring a spectrum, and observed double yellow lines, he claimed that it was Sodium.
There are multiple elements with double yellow lines, like Mercury or Sodium, but Sodium has two bright yellow lines, so it is usually identified by them.
So when we look at a spectrum and we see a strong doublet in the yellow range, we can easily assume that it is Sodium.
Here we assume that the student only saw the yellow doublet, this would imply that the yellow doublet is way more intense than the other lines, that can't be seen (while for other elements with double yellow lines, we should see other lines with similar intensity) then we can conclude that it is Sodium.
The student is correct.
When electrons in a molecule are not found between a pair of atoms but move throughout the molecule, this is called Group of answer choices
Answer:
delocalised electrons
Explanation:
they are called delocalised electrons because that can move freely in the molecule
A student performs an experiment similar to Experiment 1 using hydrochloric acid (HCl) and potassium hydroxide (KOH). The mass of the hydrochloric acid solution is 250.000 g. After combining the HCl and KOH, the final combined mass is 400.000 g. Given what you have learned about the conservation of mass in this experiment, what must have been the mass of the KOH solution
Answer:
150.000 g
Explanation:
The law of conservation of mass states that the mass of reactants and products of a reaction must be equal to one another.
In other words, for this case:
Mass of KOH + Mass of HCl = Mass of ProductsWe are given all required data to calculate the mass of the KOH solution:
Mass of KOH + 250.000 g = 400.000 gMass of KOH = 150.000 gA hypnotist's watch hanging from a chain swings back and forth every 0.98 s. What is the frequency (in Hz) of its oscillation?
Answer:
1.02 Hz
Explanation:
frequency= (1/t) = (1/0.98) = 1.02 hz
Rock, metal, wood, glass, animals, and plants are all forms of what?
Acetic acid and water react to form hydronium cation and acetate anion, like this:
HCH3CO2(aq) + H2O → H3O+(l)(aq) + CH3CO2^-(aq)
Imagine 226 mmol of CH3CO2- are added to a flask containing a mixture of HCH3CO2, H2O, H3O + and CH3CO2- at equilibrium.
Required:
What is the rate of the reverse reaction before any CH3CO2^- has t:een added to the flask?
Answer:
The rate of the reverse reaction before any addition of CH3CO2- is zero
Explanation:
When the reaction is in equilibrium:
HCH3CO2(aq) + H2O ⇄ H3O+(l)(aq) + CH3CO2^-(aq)
The reaction quotient, Q = Ka and no more products or reactants are produced because their concentrations are in the right proportion.
Now, as no reaction occurs,
The rate of the reverse reaction before any addition of CH3CO2- is zeroGiven the amount of camphor (200mg) we are using in this experiment, please determine how many mg of sodium borohydride to use in this reaction. We would like you to use 5.2 molar equivalents of this reagent. This means 5.2 times the mmol of camphor we are using. As an example: for 110.0 mg of camphor,142 mg of NaBH4 would be used (see if you can confirm this result). For complete credit, your work needs to be clearly drawn out!
Answer:
Explanation:
From the given information:
Camphor may be reduced as readily in the presence of sodium borohydride(NaHB4). The resulting compound which is stereoselective requires 1 mole of sodium borohydride (NaHB4) to reduce 1 mole of camphor in this reaction. The reaction is shown below.
Through the reduction process of camphor, the reducing agent can reach the carbonyl face with a one-carbon linkage. The product stereoisomer is known as borneol.
If the molecular weight of camphor = 152.24 g/mol
and it mass = 200 mg
The its no of moles = 200 mg/ 152.24 g/mol
= 1.3137 mmol
Now the amount of the required mmol for NaBH4 to be consumed in the reaction = 5.2 × 1.3137 mmol
= 6.831 mmol
since the molar mass of NaBH4 = 37.83 g/mol
Then, using the same formula:
No of moles = mass/molar mass
mass = No of moles × molar mass
mass = 6.831 mmol × 37.83 g/mol
mass of NaBH4 used = 258.42 mg
if salt and sand is mixed with distilled water, what will be the residue and what will be the filtrate?
Answer:
salt and sand
Explanation:it is what it is
Explain how Green Chemistry Principles can be applied to one of these five topics:
Radioactive Waste
Peak Power: Demand
Safety
Security (Weapons Proliferation and Physical Protection)
High Power-Plant Costs
You may use the "Online Librarian" to assist in your research.
This assignment must be a minimum of 500 words double spaced. Once you’ve completed your paper you will turn it into a Brainfuse Writing to critique it and then to me for final grading.
Answer:
Principles of green chemistry:
• Prevent wastes rather than treat them.
• Incorporates all raw materials into the final product.
• Use of synthetic methods.
• To design chemical products to reduce toxicity.
• Use of energy-efficient processes.
• Use of renewable raw materials.
• Reuse chemical intermediates to reduce waste.
• Improve health and safety for staff and customers.
• Cleaner production technologies.
Green chemistry principles can be applied to radioactive wastes by:
• We should choose reagents and procedures that lessen the toxicity and volume of all the wastes. We need to design experiments that radioactive wastes that are produced separately from biologically or chemically hazardous wastes if flexible.
• Substitutes with short-lived radionuclides were feasible.
• Reduce the activity and volumes of wastes generated.
• Limit the number of users of radioactive materials.
• Replace hazardous or mixed wastes.
• Non-radioactive wastes will not be mixed with radioactive wastes. If it is not done then the volume of wastes increases.
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Write the symbol for every chemical element that has atomic number less than 14 and atomic mass greater than 23.2 u.
Answer:
that symbol less than atomic number 14 and greater than mass number 23.2 is mg
Which statement is true about molarity and percent by mass? (3 points)
They have the same unit.
They are inversely related.
They are different units of dilution.
They are different units of concentration.
Answer:
The guy above used photoshop here is the actual answer.
Explanation:
The true statements about molarity and percent by mass is that they are the different units of concentration
What is concentration?Concentration of any substance present in any solution guves idea about their relative amount in that and it can de described in terms of molarity and percent by mass.
Molarity is define as the moles of solute present in per unit volume of the solution and has a unit of mol/L.Percent by mass is define as the mass of solute present in total mass of solution and it is a unit less quantity.They both gives idea about the concentration, not of the dillutions.They are not inversely related else they are directly related to each other as they are depends on the moles or mass of solute.Hence, molarity and percent by mass are the different units of concentration and directly related to each other.
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A student conducted an experiment 4 times. His results were very close to each other each time he ran the experiment and
were very close to the true or actual value. His results showed
A. None of these answers are correct
B. poor accuracy and poor precision
C. good accuracy and good precision
D. poor accuracy and good precision
E. good accuracy and poor precision
Answer:
d is the answer have a good one
In an exothermic reaction, reactants are __ products.
a more stable than
b equal to
c equally stable as
d less stable than
Answer:
Less stable
Explanation:
When an exothermic reaction occurs, the reactants have a greater energy level than the outputs. The products, in other respects, are more stable than that of the reactants.
The outcomes of an exothermic reaction have a lower energy to react. The enthalpy of a process is the difference between some of the activation energy and the power of the products.
