Answer:
As^3-, Se^2-, Br^-, Rb^+, Sr^2+
Explanation:
How can we explain the abrupt change from solid to gas that we see between the elements
carbon and nitrogen?
24.04.2021
Science
Junior High School
answered
8. What happened to the molecules when there is change from solid to gas state?
a. The molecules are deposited on cold surface.
b. The molecules are heated.
c. The molecules are bonded with a strong force.
d. All of the above.
9. What can you infer from an ice cube left at an open air?
a. There is a transformation process from solid to liquid.
b. There is a transformation process from liquid to solid.
c. Melting takes place when the temperature is higher.
d. There is no observable process taking place.
10. Which of the following illustrates that gas turns into liquid?
a. melting of ice
b. . steam from boiling water
Gases can be liquified or sublimed to solids. The reverse can also be done. Carbon and nitrogen gases can be formed from their solid state on burning fossil fuels and other decomposing materials under high pressure.
What is sublimation?Sublimation is the physical process of conversion of a material from its solid state to gaseous phase or vice versa. These physical changes involves no bond making or bond breaking.
Non-metals such as carbon, oxygen, nitrogen etc are exists in gaseous state. However they can be liquified under high pressure and low temperature. This process is called condensation.
Some gases can be even converted to solids by extremely high pressure and very low temperature. Solids can be melted into liquids. Similarly they can be converted into gaseous state. But the gases have the tendency to be gaseous form and they form the condensed state at high pressure only
Burning he carbonaceous materials such as fossil fuels evolves carbon gas. We know the evolvement of carbon dioxide from the soda bottle. Similar way, when the pressure is released, solid carbon and nitrogen can be released into their gaseous form.
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How many decigrams (dg) are in 0.779 kg?
Answer:
7790
Explanation:
Answer:
7790 decigrams
Explanation:
How many atoms of hydrogen are there in 36 g of NH4NH4?
explain in detail plz
Answer:
he formula mass of ammonia is 14 + 1 3 = 17. The number of moles in 36 g ammonia is 36/ 17 = 2.11mol. A mole is 6.02 10, so the number of hydrogen atoms in a 2.11 moles of ammonia is 2.11 *6.02*10^23 = 1.27 *10^24 atoms
Explanation:
'How many atoms are in 2.45 moles of copper?
2.46 × 1023 atoms
2.45 atoms
155.70 atoms
1.48 × 1024 atoms
Answer:
[tex]\boxed {\boxed {\sf 1.48 \times 10^{24} \ atoms \ Cu}}[/tex]
Explanation:
We are asked to find how many atoms are in 2.45 moles of copper (Cu).
We can convert moles to atoms using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of copper. There are 6.022 × 10²³ atoms of copper in 1 mole of copper.
We will convert using dimensional analysis, so we must set up a ratio using Avogadro's Number.
[tex]\frac {6.022 \times 10^{23}\ atoms \ Cu}{ 1 \ mol \ Cu}[/tex]
We are converting 2.45 moles of copper to atoms, so we multiply the ratio by this value.
[tex]2.45 \ mol \ Cu*\frac {6.022 \times 10^{23}\ atoms \ Cu}{ 1 \ mol \ Cu}[/tex]
The units of moles of copper cancel.
[tex]2.45*\frac {6.022 \times 10^{23}\ atoms \ Cu}{ 1}[/tex]
The denominator of 1 is the same as the numerator by itself, so it can be ignored.
[tex]2.45* {6.022 \times 10^{23}\ atoms \ Cu}[/tex]
[tex]1.47539 \times 10^{24} \ atoms \ Cu[/tex]
The original measurement of moles (2.45) has 3 significant figures, so our answer must have the same. For the number we found that is the hundredth place. The 5 in the thousandth place to the right tells us to round the 7 up to an 8.
[tex]1.48 \times 10^{24} \ atoms \ Cu[/tex]
There are approximately 1.48 × 10²⁴ atoms of copper in 1 mole of copper.
Answer:
[tex]:\implies \rm Moles =\dfrac{No. \: of \: atoms}{Avogadro's \: number} \\ [/tex]
[tex]:\implies \rm M =\dfrac{N}{N_A} \\ [/tex]
[tex]:\implies \rm N=M \times N_A \\ [/tex]
[tex]:\implies \rm N=2.45\times6.022 \times {10}^{23} \\[/tex]
[tex]:\implies \rm N=14.7539\times {10}^{23} \\[/tex]
[tex]:\implies \rm N=1.47539\times 10^1\times {10}^{23} \\[/tex]
[tex]:\implies\textsf{ \textbf{N = 1.48$\times${10}$^{24}$}} \\[/tex]
conversion from 76 pounds to 1 gram
Answer:
76 Pounds = 34,473,020 Grams
Answer:
76 Pounds = 34,473,020 Grams
Explanation:
becuase one pound weighs 453.592 grams so i just added up
What is the volume of sodium hydroxide,
NaOH solution used to neutralised 25.00 mL
of 0.1500 M hydrocloric acid, HCI?
Answer:
sorry i don't know this question answeer
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9 mol/l). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7 mol/l).
1. Compute the total concentration of [D1]tot that is needed to bind 90% of the HIV-RT at the given concentration [E]tot. Provide your answer as a numerical expression with 3 significant figures in the unit mol/l. You do NOT have to consider competition betwwen the drugs D1 and D2! They are administered separately.
2. Compute the total concentration of [D2]tot that is needed to bind 90% of the HIV-RT at the given concentration [E]tot. Provide your answer as a numerical expression with 3 significant figures in the unit mol/l.You do NOT have to consider competition betwwen the drugs D1 and D2! They are administered separately.
Answer:
C)[D]/[ED] = 5.20
D)[D]/[ED] = 5.20
E)[D']_T = 1.495* 10 ^-7 M
F)[D'] / [ED'] = 0.0579
Explanation:
E = 250 nM =2.5* 10 ^-7 mol/L , T=298.15 K
Dissociation constant of K_D = 1.3 μM (1.3 *10 ^-6 M)
E + D ⇄ ED → K_a = [ED] / [D][E] (association constant)
ED ⇄ E + D → K_D = [E][D] / [ED] (dissociation constant)
C)
[E] =2.5*10^-7 mol/L
K_D = 1.3* 10^-6 M
K_D = [E][D] / [ED] → [D]/[ED] = K_D / [E]
= [D]/[ED] = 1.3* 10 ^-6 / 2.5 *10^-7
= 13/25 * 10
=130/25 = 5.20
[D]/[ED] = 5.20
D)
ΔG =RTln Kd
ΔG_2 for E and D = 1.987 * 298.15 * ln 1.3*10^-6
ΔG_2 592.454 * [ln 1.3 +ln 10^-6]
ΔG_1 = 592.424 [0.2623 - 13.8155]
ΔG_2 = -592.424 * 13.553
ΔG_1 = -8184.633 cal/ mol
ΔG_1 = -8184.633 * 4.18 J/mol = -34244.508 J?mol
ΔG_1 = -34.245 KL/mol
so, ΔG_2 = ΔG_1 - 10.5 KJ/mol
ΔG_2 = -34.245 - 10.5
ΔG_2 = -44.745KJ / mol
ΔG_2 =RT ln K_D
-44.745 *10^3
=8.314 *298.15 lnK_D
lnK_D' = - 44745 / 2478.81 g
ln K_D' = -18.051
K_D' = -18.051
K_D' = e^-18.051
[D]/[ED] = 5.20
E)
[E] = 2.5* 10 ^-7 mol/ L = a
K_D' = [E][D] / [ED'] E +D' → ED'
K_D' = a/2(x-(a/2) / (a/2)
KD' = x - a/2
=2.447 *10^-8 = (2.5/2) * 10^-7
x=2.447 * 10^-8 + 1.25 * 10^-7
x = 2.447 *10^-8 + 1.25 * 10 ^-7
x= 10^-7 [1.25 + 0.2447]
x = 1.4947 * 10^-7
[D']_T = 1.495* 10 ^-7 M
F)
K_D' = [E][D'] / [ED']
[D'] / [ED'] = KD' / [E]
[D'] / [ED'] = 1.447 *10^-8 / 2.5* 10^-7
[D'] / [ED'] = 0.5788 * 10^-1
[D'] / [ED'] = 0.0579
Explanation:
...
Someone answer this for me ty
Answer:
The answer for this is (B: Heat)
1. How are the speed of light and a light-year different?
Answer:
Unlike the speed of your car when running errands, the speed of light is constant throughout the universe and is known to high precision. ... To find the distance of a light-year, you multiply this speed by the number of hours in a year (8,766). The result: One light-year equals 5,878,625,370,000 miles (9.5 trillion km).
Answer:
-Speed of light is the fastest speed ever imaginable. No object having a mass can go faster than light.
Light year is the distance traveled by light, if it moves continuously for 1 whole year, or roughly 365 days.
Explanation:
definition of scientific varable
Answer:
a scientific variable is a factor or condition that can change or effect the final outcome. There are three types being an independent variable, dependent variable, and controlled variable.
What number will go on the top when writing isotopic notation for Carbon-13?
Answer:
1? I guessed and I'm practicing on this stuff because I am new and I still need to learn this stuff
A 0.10 L solution with 1.85 g of Ca(OH)2 is of what concentration, in molarity?
Answer:
0.25M
Explanation:
The formula of concentration is c=m/M•V
c=1.85g/74g.mol•0.10L
c=0.25 M
Drag conversion units onto the boxes in the equation to make conversions. Some boxes can be left empty. Click on a
unit to remove it from its position.
1 cmCu
9 g Cu
9.5 x 1021 atoms Cu
1 g Cu
1 kg
1000 g
1 cm
1 ml
1
1000 cm3
70.0 kg x
X
X
II
70.0 kg•L
We have that 70kg of Copper Cu is having a volume of [tex]V=7.76442liters[/tex]
1 cmCu
=9 g Cu
9.5 x 10^21 atoms Cu
=1 g Cu
1 kg =1000 g
1 cm
=1 ml
1
=1000 cm3
70.0 kg x X _X II
70.0 kg•L
Generally We First determine the No of Atoms in 70kg of cu
No of Atoms of c[tex]u=\frac{weight}{atomic mass of cu}*n[/tex]
Where
n=Avogadro's Constant
[tex]n= 6.02214076 x 10^{23}[/tex]
Therefore
No of Atoms of cu[tex]=\frac{70*10^3}{63.5}*6.02214076 * 10^{23}[/tex]
No of Atoms of cu=6.63858037x10^{26} atoms of Cu
Hence
We determine the the grams of copper derived from [tex]6.63858037x10^{26}[/tex]atoms of Cu
No of grams of cu[tex]=\frac{6.63858037x10^{26}}{9.5 x 10^{21}}*1[/tex]
No of grams of cu=69879.79337 g of Cu
Generally
No of grams of Cu=liters
Where
9 g of Cu= 1cm^3 Cu
Therefore
Volume of cu
[tex]V=(69879.79337)*\frac{1}{9}*\frac{1}{1000}[/tex]
[tex]V=7.76442liters[/tex]
In conclusion
70kg of Copper Cu is having a volume of [tex]V=7.76442liters[/tex]
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We are to drag the given conversion units onto the boxes in the equation in order to make conversions in the boxes that are left empty.
The dimensional analysis for the conversion ratio is given as follows
1cm^3 Cu = 9g Cu 9.5*10^21 atoms of Cu = 1 g Cu
1 kg = 1000 g 1 cm^3 = 1 mL
1 L = 1000 cm^3
Here is the box equation
box box box
70 g ×----- × ------ × ----- =
box box box
From the given information, the volume of the Cu sample in Liters is:
= 7.765 liters
From the parameters given:
the mass of the sample of Cu = 70 kgThe first thing we are to do is to calculate the number of atoms of Cu in 70 kg by using Avogadro's constant.
We know that the number of atoms of Cu is:
[tex]\mathbf{= \dfrac{mass \ weight \ of \ Cu}{atomic \ mass \ of \ cu}\times avogadro's \ constant}[/tex]
where;
weight in Cu = [tex]\mathbf{70 * 10^{3}}[/tex]the atomic mass of Cu = 63.5 Avogadro's constant = [tex]\mathbf{6.023 \times 10^{23} \ Cu \ atoms}[/tex]the number of Cu atoms is:
[tex]\mathbf{= \dfrac{70*10^3}{63.5}\times 6.023 * 10^{23}}[/tex]
[tex]\mathbf{= 6.6395 \times 10^{26} \ atoms \ of \ Cu}[/tex]
However, from the given conversion ratios:
If [tex]\mathbf{9.5\times10^{2}}[/tex] atoms of Cu = 1 gram of Cu
∴
atoms of Cu will be:
[tex]\mathbf{= \dfrac{6.6395 \times 10^{26} \ atoms \ of \ Cu \times 1 \ gram \ of \ Cu}{9.5*10^{21} \ atoms \ of \ Cu }}[/tex]
[tex]\mathbf{= 0.69889 *10^{5} \ grams \ of \ Cu}[/tex]
Since:
1cm³ Cu = 9g Cu and; 1 L = 1000 cm³∴
The correct setup of the sample in the box can be computed as follows:
[tex]\mathbf{= 0.69889 *10^{5} \ gram \ of \ Cu \ \times \dfrac{1 cm^3 \ of \ Cu }{9 \ g \ of \ Cu }\times \dfrac{1 \ Liter}{1000 \ cm^3}}[/tex]
= 7.765 liters
Therefore, we can conclude that the Volume of Cu sample in liters is:
= 7.765 liters
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Which statement describes a property of a proton?
O is found outside the nucleus
O has a positive charge
O has less mass than an electron
O is repelled by electrons
Answer:
has a positive chargeExplanation:
An atom is an indivisible particle and it is composed of mainly three sub atomic particles, they are protons, electrons and neutrons. The proton has a positive charge. The correct option is B.
What are sub subatomic particles?The particles which are smaller in size than an atom are defined as the subatomic particles. The positively charged subatomic particles are called the protons whereas the negatively charged particles are called electrons and neutrons are chargeless.
It is the protons and neutrons which together make up the nucleus of an atom and hence they are called the nucleons. The number of protons or electrons in an atom is known as the atomic number and the mass of proton is 1.676 × 10⁻²⁴ grams.
It was Rutherford who discovered the protons and the charge of proton is + 1.602 × 10⁻¹⁹ Coulombs.
Thus the correct option is B.
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If the average speed of a helium atom at a certain temperature is 1110 m/s, what is the speed in miles per hour? (1 mi = 1609 m)
please help and show how its done
Answer: 2483 miles/hour
Explanation:
[(1 mile/1609 meters) = 0.0006215 miles/meter]
(1110meters/sec)*(0.0006215 miles/meter)*(3600 secs/hour) = 2483 miles/hour!
Note how the units cancel to yield miles/hour. Use the units to determine what conversion factors are needed. We know that the final unit was to be miles/hour, so we converted meters into miles (firsy line) so that the meters would cancel, leaving only miles. Same for seconds and hour (3600 secs/hour).
Which is larger aliter or a quart?
Answer:
a liter is larger, hope that helps :)
life scientist study life and the many processes that occur in living things____-
Answer:
life scientist study life and the many processes that occur in living things__during experiments__-
please mark me brainliest please40 points Critical Thinking Questions
8. Two of the following six numbers are written incorrectly. Circle the two that are incorrect.
What do you think is wrong about the two numbers you circled?
Its option e
Why?
[tex]\\ \sf\longmapsto 0.000354\times 10^4[/tex]
It can be written as
[tex]\\ \sf\longmapsto \dfrac{354}{10000}\times 10^4[/tex]
[tex]\\ \sf\longmapsto \dfrac{354}{10^4}\times 10^4[/tex]
Cancel 10^4[tex]\\ \sf\longmapsto 354[/tex]
Hence its wrongly written
d is also wrong
[tex]\\ \sf\longmapsto 75.3\times 10^2[/tex]
[tex]\\ \sf\longmapsto \dfrac{753}{10}\times 100[/tex]
[tex]\\ \sf\longmapsto 7530[/tex]
Its need not be simplified .A patient is required to take an IV drug for cancer treatment. The required dosage is 5.0 mg drug her lb patient body weight every day. Each of the bags of the drug contains 250 mg drug. If you are treating a 150 lb patient,How many bags of the drug are needed each day.
Answer:
3 bags are required.
Explanation:
Find the number of mg needed for 150 pounds
150 pounds * 5 mg/pound = 750 mg
1 bag = 250 mg
x bags = 750 mg Cross multiply
250 * x= 750 Divide by 250
x = 750/250
x = 3
Convert 30.0 mºto cm3.
O 3.00x105 cm
3.00x103 cm
3.00x105 cm
3.00x107 cm
3.00x 103 cm
Answer:
3.00x107 cm
Explanation:
They answer would be the 4th one
Please help ASAP!!!!!!
Answer:
the moon and the planets are closer than other stars
You can separate sugar from Sand because sugar is and sand is not what does sugar have that stand don't??? Help please
Estimating Circle the correct answer
1. Gas is $5.00 for 2 gallons and you want to fill your almost full gas tank which can hold an additional 1.5 gallons, you will spend a) $5.00 b) less than $5.00 c) more than $5.00
To fill your almost full tank with additional 1.5 gallons, you will spend less than $5.00
According to the question;
2 gallons of gas cost $5.00
Recall that your tank is almost full and what you need is additional 1.5 gallons.
If;
2 gallons of gas cost $5.00
1.5 gallons cost 1.5 * 5.00/2 = $ 3.75
$ 3.75 is less than $5.00 hence the correct answer is option B: less than $5.00.
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What is Iron's atomic number and the number of protons?
Answer:
In February, we have selected iron, the most abundant element on Earth, with chemical symbol Fe (from the Latin word “ferrum”) and atomic number 26. A neutral iron atom contains 26 protons and 30 neutrons plus 26 electrons in four different shells around the nucleus.
Answer:
Iron's atomic number is 26 and it has 26 protons
Use the blue slider labeled mass to carefully adjust the mass of the red block until neither sinks nor floats. The block should stay wherever your cursor places it without moving up or down. Next remove the block from the water and put it in the scale. Record its new mass.
Answer:
4.1 grams
Explanation:
Answer:
4.1
I solve this solution and then i got correct on it so its 4.1 thank you!
Please help me!!!!!!
Answer:
17.8ml-15.6ml is 2.2 ml then convert to cm so 2.2cm^3
How do I convert 1 times 10 to the 20th power seconds to years. Dimensional analysis? 1x10^20 seconds to years
To convert a second measurement to a year measurement, divide the time by the conversion ratio.
Since one year is equal to 31,556,952 seconds, you can use this simple formula to convert:
years = seconds ÷ 31,556,952
1 ×10^20 sec to years = 3.16887646 × 10^12 years
Halogens cause the torch of a flame to turn ____ when they are brought into contact with heated copper.
Answer:
Bright green
Explanation:
Halogens in ionic form, will react with copper wire. When heated in a flame, a wire that contains halogens will produce a bright, green flame.
The heating of halogens with the copper forms a bright green flame.
What is a flame test?A flame test is given as the test for the identification of the elements with the analysis of the color of flame on burning.
The elements on heating are excited to higher energy levels, and when they return, they emit the absorbed radiation in the form of light. The halogens are ionic in nature, and with the flame test in the presence of the heated copper, they liberate bright green flame.
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help me plz this is import this thing is late and comfusing i can give you vrainliest
Answer:
can you please mark me brainliest pleaseA vessel initially containing 1 kmol of CO and 4.76 kmol of dry air forms an equilibrium mixture of CO2, CO, O2, and N2 at 3000 K, 1 atm. Determine the equilibrium composition.
Answer:
Equilibrium composition for, no2 =.7365
The equilibrium composition for, nN2=3.76
Explanation:
