As additional resistors are connected in parallel to a constant voltage source, how is the power supplied by the source affected?.

The frequency of the wave is given as 2.5 * 10^9 Hz.

The term wavelength is the distance that is covered by a wave. It is also referred to as the distance between two successive crests or two successive troughs. It can also be defined as half of the distance between two nodes.

Now nodes are the points in which there is no movement while antinodes are the points in which there is movement.

Given that;

c = λf

c = speed of light =  3 * 10^8 m/s

λ = 2(6cm) = 12 cm or 12 * 10^-2 m

f = ??

Thus;

f = c/ λ

f =  3 * 10^8 m/s/12 * 10^-2 m

f = 2.5 * 10^9 Hz

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Consider the 5-bit generator, g=10011, and suppose that d has the value 1010101110. Then the value of r is 0100.

We obtain 1011011100 when we divide 10011 by 1010101010 0000, with a remainder of R=0100 in 5-bit generator

A generator converts mechanical energy into electrical energy. When you are not linked to the power grid, it supplies electricity to your devices and appliances. Generators are critical safety equipment during natural disasters like hurricanes and snowstorms, as well as any power outage.

It operates on the principle of the faraday law of electromagnetic induction. According to the faradays law, whenever a conductor is placed in a fluctuating magnetic field, EMF is induced and thus induced. A standby generator can power a medium-sized home for up to 3,000 hours on average, while it is not suggested that you run a generator for more than 500 hours continually. Although both EMF and terminal potential difference (V) are measured in volts, they are not the same thing.

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The resistance of the conductor is 0.07940 Ohms.

The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.

and it is formulated as:  

[tex]R=p\frac{l}{s}[/tex]

where,

p - resistivity of the conductor (0.0214-ohm mm²/m)

R - resistance

l- length of conductor (50 feet) (15.24 m)

s - the area of the wire

Thus the resistance can be calculated as

R = 0.07940 Ohms.

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The difference between the observed points and the regression line points is equal to the correlation.

The strength and direction of a relationship between two or more variables are described by the statistical measure of correlation, which is given as a number. However, a correlation between two variables does not necessarily imply that a change in one variable is the reason for a change in the values of the other.

Regression expresses the relationship as an equation, whereas correlation assesses the strength of the linear link between two variables. The square of the correlation coefficient, also known as Pearson's r, between the observed and predicted values in a regression is sometimes referred to as R2.

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Answer:

            2500W

Explanation:

                     P = W/t

             As we know that

                  W = mgh

             so:

                     P = mgh/t    

            put values

                      P = (200)(10)(25) / 20

                       P = 2500W

343 N is the gravitational force a 35 kg person standing on the earth's surface exerts on the earth .

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

According to Newton's universal law of gravitation, The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them.

According to newtons second law

Force = mass * acceleration

since , we need to find gravitational force so, acceleration will be equal to acceleration due to gravity on earth.

Force = mg

          = 35 * 9.8

          = 343 N

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In series combination less rate of joule hating should be observed as compared to when connected in parallel combination .

Joule heating, also known as resistive, resistance, or Ohmic heating, is the process by which the passage of an electric current through a conductor produces heat.

Joule's first law states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current:

When two or more resistors are connected end to end consecutively, they are said to be connected in series combination. The combined resistance of any number of resistances connected in series is equal to the sum of the individual resistances.

When two or more resistances are connected between the same two points, they are said to be connected in parallel combination. The reciprocal of the combined resistance of a number of resistances connected in parallel is equal to the sum of the reciprocals of all the individual resistances.

Rate of joule heating can be calculated by the formula

Power = [tex]V^{2}[/tex] / R

V = voltage

R = resistance

When both are connected in series than their equivalent resistance will be more as compared to when they are connected in parallel.

Power is inversely related to resistance , if voltage is constant

In series combination less rate of joule hating should be observed as compared to when connected in parallel

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A piano string of density 0.005 0 kg/m is under a tension of 1350 N, then the velocity with which a wave travels on the string would be 519.61 m/s

It is a particular variety of mechanical waves made up of the disruption brought on by the movements of the energy. In an elastic medium like the air, a sound wave travels through compression and rarefaction.

As given in the problem a piano string of density 0.005 0 kg/m is under a tension of 1350 N,

V= √F/μ

V=√(1350/0.005)

V =  519.61 m/s

Thus, the velocity with which a wave travels on the string comes out to be  519.61 m/s

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The current through the 10 Ω resistor is 0.586A which is connected with a resistor in series combination.

Voltage divides in a Series combination and current divides in a parallel combination.

Let the three resistors joined in parallel be R₁, R₂, R₃

where, R₁= 4 Ω

R₂ = 6 Ω

R₃ = 10 Ω

Given, a battery of 12V and a 2Ω resistor say r is series with the parallel combination.

Equivalent resistance(R) in parallel combination is:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/4 + 1/6 + 1/10

On solving, R = 1.9 Ω

Now, the Equivalent resistance(R) of parallel combination is in series with r = 2Ω

Let Equivalent resistance of Series combination be R'

R' = R + r

R' = 1.9 + 2 Ω

R' = 3.9 Ω

Now let's calculate the voltage drop in the resistor r = 2Ω

v = i × r           where, i is the current in r and v is the voltage drop across r

v = 3.07 × 2

v = 6.14V

Voltage drop, V' across the Equivalent resistance(R) in parallel combination = Total voltage - voltage drop in the resistor r

V' = 12 - 6.14 V

V' = 5.86V

Now, the Voltage drop, V' across the Equivalent resistance(R) in parallel combination is same for all the three resistors R₁, R₂, R₃

So, Voltage is same in a parallel combination.

V' = I × R₃

5.86 = I × 10

I = 0.586A

Hence, The current through the 10 Ω resistor is 0.586A

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The possible impact of the maunder minimum on earth is a) lower temperatures

The Maunder Minimum, also known as the "prolonged sunspot minimum", was a period around 1645 to 1715 during which sunspots became exceedingly rare. During a 28-year period (1672–1699) within the minimum, observations revealed fewer than 50 sunspots.

The most recent grand solar minimum occurred during Maunder Minimum (1645–1710), which led to reduction of solar irradiance by 0.22% from the modern one and a decrease of the average terrestrial temperature by 1.0–1.5°C

During the Maunder Minimum, the Sun emitted less strong ultraviolet light, and so less ozone formed. The decrease in ozone affected planetary waves, the giant wiggles in the jet stream that we are used to seeing on television weather reports

correct option is

a) lower temperatures

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Answer:

B (buoyant force) = weight of air displaced - weight of balloon

Both balloons will displace the same amount of air but the weight of the balloon filled with He is much less and will experience a greater buoyant force - actually if a balloon is filled with air its weight would be the same as the weight of the air displaced and there would be no buoyant force

Answer:

Both erg and Joule are units of Energy in the CGS and S.I system respectively.

Joule and erg can also be written as (kg m2/s2) and (g cm2/s2) respectively.

Explanation:

1 Joule = 107 erg ⇒ 107 kg m2/s2.

==>  One erg of energy is the amount of work done when one dyne of force acts through a distance of one centimeter.

==>  One Joule of energy is the amount of work done when one Newton of force (100,000 dynes) acts through a distance of one meter (100 centimeters).

==>  That makes one Joule the same amount of energy as 10 million (10⁷) dynes.

The sphere’s Electric potential energy is 1.6*[tex]10^{-6}[/tex]J

Given,

q=6. 5 µc, V=240 v,

We know that sphere’s Electric potential energy(E) = qV=6.5*[tex]10^{-6} *240[/tex]=1.6*[tex]10^{-6}[/tex]J

The configuration of a certain set of point charges within a given system is connected with the potential energy (measured in joules) known as electric potential energy, which is a product of conservative Coulomb forces. Two crucial factors—its inherent electric charge and its position in relation to other electrically charged objects—can determine whether an object has electric potential energy.

In systems with time-varying electric fields, the potential energy is referred to as "electric potential energy," but in systems with time-invariant electric fields, the potential energy is referred to as "electrostatic potential energy."

A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere’s potential energy?

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The time elapsed is 8.98 sec when it turns through the 220 radians.

given:

using second equation of motion for rotation

   we get ,

[tex]220=0.t + \frac{1}{2}.5.45.t^{2}[/tex]

t^2 =80.98

t=8.98sec

therefore time elapsed is 8.98sec .

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Answer:

Giant impacts in its early history may have torn away much of its original crust and mantle.

So Mercury has a giant iron core, but why?

There are three general ideas.

1. Mercury was once the core of a gas giant that vaporized when the Sun became a fully-fledged star. This gas giant was probably more like Uranus or Neptune than Jupiter or Saturn.

There are significant issues here, especially that Mercury's existing surface has been exposed to space since the solar system's initial beginnings. On Mercury, remnants of the first massive bombardment have been found.

2. Mercury formerly had a deeper mantle and was a bigger terrestrial planet. During the early history of the solar system, a dwarf planet made a massive impact that robbed the planet of its mantle.

The existing surface of Mercury has been exposed to space since the very beginning of the solar system, which raises major issues once more.

Due to the factors in explanation 1, characteristics from the first significant bombardment have been found on Mercury. The quantity of low temperature volatiles that are trapped and sometimes sublimate out of the crust, causing hollows, is also a major issue. By such an impact, these low temperature volatiles—such as sodium, sulphur, magnesium, etc.—would have been completely pushed out.

3. A mostly iron-rich body developed, and "rock steam"—a gaseous mixture of atomic oxygen and silica—condensed and accreted onto it from the protoplanetary disk near the Sun. Small rock particles with lower temperature volatiles were subsequently formed into a crust. Additionally, it appears that iron was concentrated in the inner region of the protoplanetary disk by the Sun's early, extremely powerful magnetosphere.

Whilst there are a few minor issues with this, this appears by far the most likely scenario.

Its crust and mantle may have been significantly altered during its early history by massive collisions.

The extremely hot and dense core of Earth is called the core. Under the mainly solid mantle and the chilly, brittle crust is the ball-shaped core. The radius of the core is about 3,485 kilometers, and it can be located around 2,900 kilometers (1,802 miles) beneath the surface of the Earth (2,165 miles). Earth is more ancient than the core.

Approximately 4.5 billion years ago, Earth was a uniform ball of hot rock. The ball warmed up considerably more due to radioactive decay and residual heat during planetary formation. After roughly 500 million years, the temperature of our new planet reached 1,538 degrees Celsius (2,800 degrees Fahrenheit), which is the temperature at which iron melts. The iron catastrophe refers to this critical moment in Earth's history.

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Answer:

We assume the second train was standing still and that momentum is conserved.

Then the product of mass and velocity before the collision is

(5000 kg)·(100 m/s) = 500,000 kg·m/s.

After the collision, where M is the mass of the second train, the momentum is

((5000+M) kg)·(50 m/s) = 500,000 kg·m/s

Dividing by 50 m/s and subtracting 5000 kg, we have

(5000 +M) kg = 10,000 kg

M kg = 5000 kg

The mass of the second train is 5000 kg

The distance between PQwill be 10,time taken to cover PQ will be 0.25sec and time taken to cover PR will be 3sec.

What is uniform deceleration?

Uniform deceleration is when velocity decrease by equal intervals of time .

Given ,

Velocity at P is 40 m/ s,

Velocity at Q is 20 m/ s

Distance between QR will be 50m.

let the whole distance between PR will be x,

so time taken of PQ, equating both times of PQ and QR we will get this,

x-50/40 = 50/ 20

after calculating ,

x = 60m , this the distance of whole straight line

60-50=. 10 m

the distance between PQ will be 10

2) time taken to cover PQ

. V= d/ t

 t= 0.25s

3) time taken to cover PR

20=60/ t

t= 3sec.

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1. PQ=150m.

2. PQ: [tex]t=5s[/tex]

3. QR: [tex]t=5s[/tex]

The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s) over the change in time (t). Speed (or rate, r) is a scalar number, denoted by the equation r = d/t, that quantifies the distance traveled (d) over the change in time (t).

QR=50m.

[tex]V_{Q} (u)=20ms^{-1} ,V_{R} v[/tex]

[tex]v^{2} =u^{2}+2as[/tex]

[tex]0=20^{2} +2a*50[/tex]

100a=-400

[tex]a=-4ms^{-2}[/tex]

1. Distance PQ:

[tex]u_{p} (u)=40msx^{-1} , v_{Q (v)=20ms^{-1}[/tex]

[tex]v^{2} =u^{2} +2as[/tex]

[tex]20^{2} =40^{2} -2*4s[/tex]

400=1600-400

8s=1600-400

[tex]s=\frac{1200}{8} =150m[/tex]

PQ=150m

2.Time taken to cover PQ:

v=u+at

20=40-4t

4t=40-20

[tex]t=\frac{20}{4}=5s[/tex]

3. Time taken to cover PR​:

v=u+at

0=20-4t

[tex]t=\frac{20}{4}=5s[/tex]

1. PQ=150m.

2. PQ: [tex]t=5s[/tex]

3. QR: [tex]t=5s[/tex]

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The separation between them is [tex]\frac{r}{\sqrt{20} }[/tex]

Concept :

If the force increases, distance between charges must decrease. Force is indirectly proportional to the distance squared.

Given,

Two point charges are brought closer together, increasing the force between them by a factor of 20.

Original force is

F = [tex]\frac{kq_{1} q_{2} }{r^{2} }[/tex] -------- ( 1 )

Here, [tex]q_{1} , q_{2}[/tex] are charges and r is the distance between them

New force F' = [tex]\frac{kq_{1q_{2} } }{r'^{2} }[/tex] ----------- (2 )

Divide ( 1 ) and ( 2 )

[tex]\frac{F'}{F}[/tex] = [tex]\frac{\frac{kq_{1}q_{2} }{r'^{2} } }{\frac{kq_{1}_{2} }{r^{2} } }[/tex]

20 = [tex]\frac{r^{2} }{r'^{2} }[/tex]

r' = [tex]\frac{r}{\sqrt{20} }[/tex]

Given that force between them are increasing and therefore distance between them decrease by [tex]\frac{r}{\sqrt{20} }[/tex]

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The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

E = kq/r²

where;

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

F = Eq

where;

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

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The radio region of the electromagnetic spectrum is where molecular clouds with extremely low temperatures emit the majority of their light.

To find the answer, we need to know more about the molecular clouds.

Thus, we can conclude that, the radio region of the electromagnetic spectrum is where molecular clouds with extremely low temperatures emit the majority of their light.

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Answer:

answer is make marshland better

Explanation:

so if they made marshland better then as a result of that action of making marshland better then marshland would be better!
hopefully i helped dawg

According to the Newton's law of universal gravitation 2.4, the force between any more than two or three types of heavier mass which really involves with mass falling to the ground is proved by the distance, the mass's rotational speed and the rotating direction. It happens the changes in space and time, and also in the diameter of it's own mass.

The frequency of the green light emitted by a hydrogen atom with a wavelength of 486. 1 nm will be 6.17 * [tex]10^{-14}[/tex] Hz

The wavelength of light is the distance between corresponding points in two adjacent light cycles, and the frequency of light is the number of cycles of light that pass a given point in one second.

Visible light falls in the range of the EM spectrum between infrared (IR) and ultraviolet (UV). It has frequencies of about 4 × 1014 to 8 × 1014 cycles per second, or hertz (Hz) and wavelengths of about 740 nanometers (nm) or 2.9 × 10−5 inches, to 380 nm (1.5 × 10−5 inches)

f = c/lambda

where

f = frequency of light = ?

lambda = wavelength of light =  486. 1 nm = 486.1 * [tex]10^{-9}[/tex] m

c = speed of light = 3 * [tex]10^{8}[/tex] m/s

f = 3 * [tex]10^{8}[/tex]  / 486.1 * [tex]10^{-9}[/tex] = 6.17 * [tex]10^{-14}[/tex] Hz

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Answer:

It took [tex]\bf 4.07 \space\ \mathrm{s}[/tex] to travel.

Explanation:

To calculate the time taken to travel a distance of 122 m at a speed of 30 m/s, we can use the formula for speed:

[tex]\boxed{speed = \frac{distance}{time}}[/tex].

We can substitute the known values, and then solve for time:

[tex]30 = \frac{122}{\mathrm {time}}[/tex]

⇒ [tex]\mathrm{time } = \frac{122}{30}[/tex]

⇒ [tex]\mathrm{time } \approx \bf 4.07 \space\ \mathrm{s}[/tex]

It will be about 26 degrees north of observer's meridian.

To find the answer, we have to know more about observer's meridian.

Thus, we can conclude that, the moon due south on the meridian will be

about 26 degrees north of observer's meridian, after two nights at the same time.

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Answer:

If the light were incident upon two polarizers at right angles, no light would get thru - thus each polarizer must block 50% of the light.

One polarizer would allow 50% of the light to pass.

Answer:

The density of the object is 8000 kg/m^3

Explanation:

Weight in air = 7.84 n

Weight in water = 6.86 N

density of water = 1000 kg/m^3

Let d be the density of the object

According to the Archimedes principle, when a body is immersed in a liquid partly or wholly, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in weight of the body.

Loss in weight of the object = Weight of object in the air - the weight of an object in the water

Loss in weight = 7.84 - 6.86 = 0.98 N

The volume of body x density of water x g = 0.98

Let V be the volume of the body

V x 1000 x 9.8 = 0.98

V = 10^-4 m^3

Weight in air = Volume of body x density of body x g

7.84 = 10^-4 x d x 9.8

d = 8000 kg/m^3

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The density of the object is ([tex]\rho_{ob}[/tex])= 80,000 [tex]kg/m^3[/tex]

To calculate the density, we have to calculate the buoyancy force that the water exerts on the object. To calculate the buoyancy force we use the formula,

[tex]B= W_{air}- W_{water}[/tex]

Here we are given,

[tex]W_{air}[/tex] = The weight of the object in air = 7.84 N

[tex]W_{water}[/tex]= The weight of the object in water= 6.86 N

We have to calculate the buoyancy force =B

Now we put the known values in the above equation, we get

[tex]B= 7.84-6.86[/tex] = 0.98 N.

We know that the buoyant force depends on the volume of water displaced by the Volume of the object, so the formula stands,

[tex]B= \rho_{water} \times V_{ob}\times g[/tex]

Or, [tex]V_{ob}=\frac{B}{g\times \rho_{water}}[/tex]

Here we are given,

B= The buoyancy force = 0.98N.

[tex]\rho_{water}[/tex]= The density of water = 1000 [tex]Kg/m^3[/tex]

g= gravitational acceleration= 9.81[tex]m/s^2[/tex]

We have to calculate the volume of the object= [tex]V_{ob}[/tex]

Now we put the known values in the above equation, we get

[tex]V_{ob}=\frac{B}{g\times \rho_{water}}[/tex]=[tex]\frac{0.98}{9.81\times 1000}[/tex]=[tex]1.0\times 10^{-5} m^3[/tex].

So, now the volume of the object ([tex]V_{ob}[/tex])= [tex]1.0\times 10^{-5} m^3[/tex]

The weight of the object in the air can be calculated using the following formula, [tex]W_{ob}= m_{ob} \times g[/tex]

[tex]m_{ob}[/tex]=the mass of the object.

From this equation we can calculate the mass of the object,

[tex]m_{ob}=\frac{W_{ob}}{g}[/tex]= [tex]\frac{7.84}{9.81}[/tex]=0.80Kg.

(We know that the weight of the object in the air is the original weight of the object, so [tex]W_{ob} = W_{air}[/tex]=7.84N )

So, the mass of the object is ([tex]m_{ob}[/tex])= 0.80 Kg.

Now, let us consider the density of the object is [tex]\rho_{ob}[/tex]

From the definition of the density we can simply know that,

[tex]\rho_{ob}=\frac{m_{ob}}{ V_{ob}}[/tex]

Or,[tex]\rho_{ob}=\frac{0.80 }{1.0\times 10^{-5} }[/tex]

Or.[tex]\rho_{ob}=8\times 10^{4} Kg/m^3[/tex]

Or, [tex]\rho_{ob}=80,000 Kg/m^3[/tex]

From the above calculation we can define that the  density of the object is 80,000 [tex]kg/m^3[/tex]

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The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

Displacement (denoted by Δx)

Initial Velocity v0

Final Velocity denoted by v

Time interval (denoted by t)

Constant acceleration (denoted by a)

These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.

v = u + at

0 = 9.5 + a (2)

a = - 9.5 /2  m/[tex]s^{2}[/tex]

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as

0 =  [tex](9.5)^{2}[/tex] + 2* (- 9.5 /2) * s

-  [tex](9.5)^{2}[/tex]  = - 9.5 s

s = 9.5 m

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At resonance, a driven rlcrlc circuit has vcvc = 5. 0 vv , vrvr = 8. 0 vv , and vlvl = 5. 0 vv having a peak voltage across the entire circuit

For any voltage waveform, the peak voltage is the highest point or voltage value. When Pulse Width Modulation (PWM) devices, like variable frequency drives, are added to a power system with a peak voltage that is equal to the square root of two times the RMS voltage, a power quality problem results.

Find the peak voltage, for instance, if the RMS voltage is 85 V. The average voltage and maximum voltage of AC power coming from the wall are both about 110 V. Therefore, the real peak voltage is 120/0.707 = 170 V. The sinusoid's amplitude is divided in half by this. Peak-to-peak voltage (Vp-p), also known as the total amplitude, is 340 V, or twice the peak voltage.

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broglie wavelength of this electron is 107.5pm.

what is de broglie wavelength?

The wavelength (λ) that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength.

Given:

de broglie wavelength of this electron? [ke[ke = 12mv2;12mv2; 1 electron volt (ev)(ev) = 1. 602×10−19j] is 107.5pm

[tex]h = 6.63 \times 10 { }^{ - 34} [/tex]

[tex]k = 120ev[/tex]

[tex]me = 9 \times 10 {}^{ - 31} kg[/tex]

[tex]1ev = 1.6 \times 10 {}^{ - 19} [/tex]

[tex]p = \sqrt{2mk} [/tex]

[tex] = \sqrt{2 \times 9 \times 10 { }^{ - 31} \times 1.6 \times 10 {}^{ - 19} } [/tex]

[tex] = 5.88 \times 10 {}^{ - 24} kgm/s[/tex]

de broglie wavelength

λ=h/p

[tex] = \frac{6.63 \times 10 {}^{ - 34} }{5.88 \times 10 {}^{ - 24} } [/tex]

Thus from the above calculation the de broglie wavelength comes out to be 107.5pm

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