At how many points does the graph of the function below intersect the x-axis?y = 16x^2-8x+1 A.0 B.2 C.1

Answers

Answer 1

We need to find D.

D=(-8)²-4×16×1=64-64=0

D=0, so the graph of the function intersect the x-axis at 1 point

Answer: C


Related Questions

Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52.

Which expression can you use to find 23% of 52? ..
23% of $52 is $..
An easy way to check your answer is to use the friendly and divide 52 by to get ..

Answers

Answer:

Which expression can you use to find 23% of 52? "0.23 x 52"

23% of $52 is $. "11.96"

An easy way to check your answer is to use the friendly 25% and divide 52 by 4 to get 13.

Step-by-step explanation:

just did it good luck everyone

23% of $52 is $11.96.

In order to determine the value of 23% of $52, we would multiply 23% by $52. Multiplication is a basic mathematical operation that entails adding a certain number by itself a certain number of times. The sign used to represent multiplication is ×.

23% x 52

= 0.23 x 52 = $11.96

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a square stained window is divided into four congurent traiangular sections by iron edging to represent seasons of the year. Each diagonal measures 9 inches. What is the total length of iron edging needed to create the sqaure frame and two diagnols?

Answers

Answer:

Total length of iron needed to make the square frame and two diagonals =  43.44 in (Approx)

Step-by-step explanation:

Given:

Length of diagonal = 9 in

Find:

Total length of iron needed to make the square frame and two diagonals.

Computation:

Area of square = 1/2(diagonal)²

Area of square = 1/2(9)²

Area of square = 40.5 in²

Area of square = Side × Side

40.5 in² = Side × Side

Side = 6.36 (approx)

Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)

⇒ (4 × 6.36) + (2 × 9)

⇒ (25.44) + (18)

⇒ 43.44 in

Total length of iron needed to make the square frame and two diagonals =  43.44 in (Approx)

The population of a town increased from 3450 in 2006 to 4650 in 2011. Find the absolute and relative (percent) increase.

Answers

Answer:

15% increase per year.

Step-by-step explanation:

5,600 - 3,500 = 2,100

2,100 is what percent of 3,500?

2,100 = X*3,500

X =  2,100 / 3,500

X = .60 or 60%

An average of 15% increase per year.

Answer:

the population of a town increased from 3450 and 2006 to 51,50 and 2010 find the absolutes and relative percent increase

Step-by-step explanation:

an automobile traveled 21 miles north from the airport. it then turned directly west and traveled 28 miles. how far is the automobile from the airport??​

Answers

The automobile is 35 miles away from the airport

A physical education class has 21 boys and 9 girls. Each day, the teacher randomly selects a team captain. Assume that no student is absent. What is the probability that the team captain is a girl two days in a row?

The probability of choosing a captain that is a girl two days in a row is
9
%.

Answers

Answer:9%

U already provided the answer. Anyways have a good day!!

The probability of choosing a captain that is a girl two days in a row is 9%

How to determine the probability?

The given parameters are:

Boys = 21

Girls = 9

The total number of students is

Total = 21 + 9

Total = 30

This means that the probability of selecting a girl is:

P(Girl) = 9/30

For two days, the required probability is

P = 9/30 * 9/30

Evaluate

P = 9%

Hence, the probability of choosing a captain that is a girl two days in a row is 9%

Read more about probability at:

https://brainly.com/question/251701

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find the value of x in the triangle shown below ​

Answers

Answer:

..........

Step-by-step explanation:

x + 114 + 33 = 180

x= 33

The average cost of tuition plus room and board at small private liberal arts colleges is reported to be less than $18,500 per term. A financial administrator at one of the colleges believes that the average cost is higher. The administrator conducted a study using 150 small liberal arts colleges. It showed that the average cost per term is $18,200. The population standard deviation is known to be $1,400. Let α= 0.05. What are the null and alternative hypothesis for this study?

Answers

Answer:

The null and alternative hypothesis for this study are:

[tex]H_0: \mu=18500\\\\H_a:\mu< 18500[/tex]

The null hypothesis is rejected (P-value=0.004).

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=18500\\\\H_a:\mu< 18500[/tex]

The significance level is 0.05.

The sample has a size n=150.

The sample mean is M=18200.

The standard deviation of the population is known and has a value of σ=1400.

We can calculate the standard error as:

[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1400}{\sqrt{150}}=114.31[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{18200-18500}{114.31}=\dfrac{-300}{114.31}=-2.624[/tex]

This test is a left-tailed test, so the P-value for this test is calculated as:

[tex]P-value=P(z<-2.624)=0.004[/tex]

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Employees that work at a fish store must measure the level of nitrites in the water each day. Nitrite levels should remain lower than 5 ppm as to not harm the fish. The nitrite level varies according to a distribution that is approximately normal with a mean of 3 ppm. The probability that the nitrite level is less than 2 ppm is 0.0918.
1. Which of the following is closest to the probability that on a randomly selected day the nitrite level will be at least 5 ppm?
(A) 0.0039
(B) 0.0266
(C) 0.0918
(D) 0.7519
(E) 0.9961

Answers

Answer: .0039

Step-by-step explanation:

What’s the correct answer for this?

Answers

Answer:

(2,7)

Step-by-step explanation:

In the attached file

State if the two vectors are parallel, orthogonal, or neither.

u=18i+8j

v=9i+4j

Answers

Answer:

Parallel, since [tex]\vec u = 2\cdot \vec v[/tex].

Step-by-step explanation:

The relation between both vectors is determined by the use of the dot product, whose expression is:

[tex]\cos \theta = \frac{\vec u \bullet \vec v}{\|\vec u\| \|\vec v\|}[/tex]

Where:

[tex]\cos \theta = 1[/tex] if vectors are parallel to each other and [tex]\cos \theta = 0[/tex] if vectors are orthogonal. Then, norms and dot product are calculated hereafter:

[tex]\|\vec u\| = \sqrt{18^{2}+8^{2}}[/tex]

[tex]\|\vec u\| \approx 19.698[/tex]

[tex]\|\vec v \| = \sqrt{9^{2}+4^{2}}[/tex]

[tex]\|\vec v\| \approx 9.849[/tex]

[tex]\vec u \bullet \vec v = (18)\cdot (9) + (8)\cdot (4)[/tex]

[tex]\vec u \bullet \vec v = 194[/tex]

[tex]\cos \theta = \frac{194}{(19.698)\cdot (9.849)}[/tex]

[tex]\cos \theta = 1[/tex]

The two vectors are parallel to each other, which is also supported by the fact that one vector is multiply of the other one. That is,

[tex]18i + 8j = 2\cdot (9i + 4j)[/tex]

[tex]\vec u = 2\cdot \vec v[/tex]

When Jonas becomes the Receiver of Memory, he gets a rule that he may not tell his dreams. He wants to know how many of his 505050 classmates have the same rule. He asks 555 friends from his class whether they may tell their dreams. Of those, 444 say that they may.

Answers

Answer:

101010 classmates can't tell their dreams.

Step-by-step explanation:

I'm not sure what the question is, but if it is an average thing than 444 of 555 is 80 percent, so if that is what it wants 404040 of the students can share their dreams, and 101010 can't.

Hope this helps!

A project is found to have expected time T = 35.33 days and variance V = 3.22.
a. What value of z is needed to find the probability that the project will take at least 40 days? (round final answer to 2 decimals as needed)
b. What value of z is needed to find the probability that the project will take at most 40 days? (round final answer to 2 decimals as needed)
c. What value of z is needed to find the probability that the project will take at most 30 days? (round final answer to 2 decimals as needed)

Answers

Answer:

a) [tex] z = \frac{40-35.33}{1.794}= 2.60[/tex]

b) [tex] z = \frac{40-35.33}{1.794}= 2.60[/tex]

c) [tex] z = \frac{30-35.33}{1.794}= -2.97[/tex]

Step-by-step explanation:

For this case we know that the mean for the random variable of interest is [tex]\mu = 35.33[/tex] and the variance [tex]\sigma^2 = 3.22[/tex] so then the deviation would be [tex]\sigma = \sqrt{3.22}= 1.794[/tex]

The z score is given by thsi formula:

[tex] z = \frac{X -\mu}{\sigma}[/tex]

Part a

We want this probability:

[tex] P(X>40)[/tex]

And if we find the z score we got:

[tex] z = \frac{40-35.33}{1.794}= 2.60[/tex]

And we can find this probability: [tex] P(Z>2.60)[/tex]

Part b

We want this probability:

[tex] P(X<40)[/tex]

And if we find the z score we got:

[tex] z = \frac{40-35.33}{1.794}= 2.60[/tex]

And we can find this probability: [tex] P(Z<2.60)[/tex]

Part c

We want this probability:

[tex] P(X<30)[/tex]

And if we find the z score we got:

[tex] z = \frac{30-35.33}{1.794}= -2.97[/tex]

And we can find this probability: [tex] P(Z<-2.97)[/tex]

A national organization has been working with utilities throughout the nation to find sites for large wind machines that generate electricity. Wind speeds must average more than 15 miles per hour (mph) for a site to be acceptable. Recently, the organization conducted wind speed tests at a particular site. Based on a sample of wind speed recordings (taken at random intervals), the wind speed at the site averaged with a standard deviation of To determine whether the site meets the organization's requirements, consider the test, where μ is the true mean wind speed at the site and Fill in the blanks. "A Type I error in the context of this problem is to conclude that the true mean wind speed at the site _____ 15 mph when it actually _____ 15 mph."

Answers

Answer:

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

Step-by-step explanation:

A Type I error happens when a true null hypothesis is rejected.

In this case, as the claim that want to be tested is that the average wind speed is significantly higher than 15 mph, the null hypothesis has to state the opposite: the average wind speed is equal or less than 15 mph.

Then, with this null hypothesis, the Type I error implies a rejection of the hypothesis that the average wind speed is equal or less than 15 mph. This is equivalent to say that there is evidence that the average speed is significantly higher than 15 mph.

"A Type I error in the context of this problem is to conclude that the true mean wind speed at the site is higher than 15 mph when it actually is not higher than 15 mph."

For several hours you watch a group playing dice on the street and you notice that the owner of the dice often wins.

Answers

Answer:

there is no question

Step-by-step explanation:

It looks like the owner plays dirty, meaning he uses a trick of some kind to somehow influence the outcome in such a way, that it's outcome is no longer random.

By influencing the outcome, the owner can obtain an advantage over the playeers who are not aware of the trick or skill involved.

This is unfair and can be considered "dirty". This game is 'fixed'.

The average lifetime of a set of tires is three years. The manufacturer will replace any set of tires failing within two years of the date of purchase. The lifetime of these tires is known to follow an exponential distribution. What is the probability that the tires will fail within two years of the date of purchase?

Answers

Answer:

48.67% probability that the tires will fail within two years of the date of purchase

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

In this question:

[tex]m = 3, \mu = \frac{1}[3}[/tex]

[tex]P(X \leq 2) = 1 - e^{-\frac{2}{3}} = 0.4867[/tex]

48.67% probability that the tires will fail within two years of the date of purchase

You are overseeing a machine that seals 80 soda cans per minute. In one hour of time, how many soda cans will be sealed? _____ soda cans?

Answers

Answer: 4800

Step-by-step explanation: 80 x 60 = 4800

BRAINLIEST for whoever gets this correct! Factor the expression below.
x^2-16x+64
A. (x-4)(x-16)
B. (x+4)(x+16)
C. (x+8)(x + 8)
D. (x-8)(x-8)​

Answers

Answer:

D. (x - 8) (x - 8)

Step-by-step explanation:

-16x must be split into two terms that can be added to get -16, and multiplied to get 64. The only two terms that can satisfy this, is -8.

(x - 8) (x - 8)

If you're unsure about whether it's correct, you can multiply the two together to see if you get your original expression, [tex]x^2-16x +64[/tex], as your answer.

Verify that 1 + cos 2 theta / 2 cos theta = cos theta is an identity

Answers

Answer and Step-by-step explanation:

We want to verify that (1 + cos(2θ)) / 2cos(θ) = cos(θ).

Let's focus on the left side. Look at cos(2θ). This is an identity, so remember that cos(2θ) = cos²θ - sin²θ. Also, look at the 1. Remember that sin²θ + cos²θ = 1, so plug both of these expressions into our equation:

(1 + cos(2θ)) / 2cos(θ) =? cos(θ)

((sin²θ + cos²θ) + (cos²θ - sin²θ)) / 2cos(θ) =? cos(θ)

2cos²θ / 2cosθ =? cosθ

cosθ = cosθ

Thus, we have proved this is an identity.

Answer:

(1 + cos(2theta))/2cos(theta)

cos(2theta) = 2cos²(theta) - 1

(1 + 2cos²(theta) - 1)/2cos(thetal

2cos²(theta)/2cos(theta)

cos(theta)

A regulation baseball can weigh no more than 149 grams. A factory produces baseballs with weights that are normally distributed with a mean of 146 grams and a standard deviation of 2.3 grams. (a) If a baseball produced by the factory is randomly selected, what is the probability that it is within regulation weight? (b) The baseballs are shipped in boxes of 16. What is the probability that at least 15 of the 16 baseballs in a pack are within regulation weight? (c) The factory will not ship a box of 16 if the average weight of the baseballs in the box exceeds 147 grams. What is the probability that a pack of 16 baseballs would have an average weight of more than 147 grams?

Answers

90.32% probability that it is within regulation weight

(a) The probability that a selected ball is within regulation weight is 84%.

(b) Probability of at least 15 of 16 balls withing regulation weight is 10.5%.

(c) The probability of average weight of more than 147 grams is 66.67%.

Probability of baseball within regulation weight

The probability of baseball within regulation weight is calculated as follows;

one standard deviation above the mean = M + d = 84%

two standard deviation above the mean = M + 2d = 98%

where;

M is the meand is standard deviation

one standard deviation above the mean = 146 g + 2.3 g = 148.3 g

two standard deviation above the mean = 146 g + 2(2.3g) = 150.6 g

150.6 g is above regulation weight.

Thus, when a baseball is randomly selected, the probability that it is within regulation weight is 84%.

Probability of  at least 15 balls out of 16 balls;

outcome = (15, 16) = 2 outcome

P = 2/16 x 84%

P = 10.5%

Probability of average weight of more than 147 grams

Mean of the distribution = 146 = 50%

Average weight more than 147g = ?

Maximum weight of 149g = 100%

(147 - 146)/(149 - 146) = (? - 50)/(100 - 50)

0.333 = (? - 50)/(50)

50(0.333) = ? - 50

? = 50(0.333)  + 50

? = 66.67%

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if i'm 18 and my sister is 19, how much younger am I than she is?

Answers

it would be a year !

Answer:

one year

Step-by-step explanation:

What is more 7 7/9 or 7 4/5?

Answers

First, turn the mixed numbers into improper fractions.

7 7/9 = 70/9

7 4/5 = 39/5

Second, find common denominators.

70/9 = 350/45

39/5 = 351/45

351/45 > 350/45

Therefore, 7 4/5 is greater.

Best of Luck!

Plot the vertex and the axis of symmetry of this function: f(x) = (x – 3)2 + 5.

Answers

Answer:

Vertex: (3, 5)

Axis of symmetry: x=3

What is the slope of y = -4x -3

Answers

Answer:

Slope = -4

Step-by-step explanation:

Slope intercept form: y = mx + b

m = slope

b = y-intercept

Since m represents the slope, then your slope will equal -4.

3x+20=5x how many Solutions does it have

Answers

Answer:

one

Step-by-step explanation:

3x + 20 = 5x

20 = 5x - 3x

20 = 2x

x = 10

one solution

3x+20=5x only have one solution

An alien empire is considering taking over planet Earth, but they will only do so if the portion of rebellious humans is less than 10 % 10%10, percent. They abducted a random sample of 400 400400 humans, performed special psychological tests, and found that 14 % 14%14, percent of the sample are rebellious. Let's test the hypothesis that the actual percentage of rebellious humans is 10 % 10%10, percent versus the alternative that the actual percentage is higher than that. The table below sums up the results of 1000 10001000 simulations, each simulating a sample of 400 400400 humans, assuming there are 10 % 10%10, percent rebellious humans. According to the simulations, what is the probability of getting a sample with 14 % 14%14, percent rebellious humans or more?'

Answers

Answer:

Probability of getting a sample with 14% rebellious humans or more is 0.0104.

Step-by-step explanation:

We are given that an alien empire is considering taking over planet Earth, but they will only do so if the portion of rebellious humans is less than 10%.

They abducted a random sample of 400 humans, performed special psychological tests, and found that 14% of the sample are rebellious.

Let p = population proportion rebellious humans

The z score probability distribution for sample proportion is given by;

                             Z  =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex]  ~ N(0,1)

where, [tex]\hat[/tex][tex]\hat p[/tex] = sample proportion rebellious humans = 14%

            n = sample of humans = 400

            p = population proportion rebellious humans = 10%

Now, probability of getting a sample with 14% rebellious humans or more is given by = P( [tex]\hat p[/tex] [tex]\geq[/tex] 14%)

         P( [tex]\hat p[/tex] [tex]\geq[/tex] 0.14) = P( [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] [tex]\geq[/tex] [tex]\frac{0.14-0.10}{\sqrt{\frac{0.14(1-0.14)}{400} } }[/tex] ) = P(Z [tex]\geq[/tex] 2.31)

                            = 1 - P(Z < 2.31) = 1 - 0.9896 = 0.0104

The above probability is calculated by looking at the value of x = 2.31 in the z table which has an area of 0.9896.

Hence, the required probability is 0.0104.

Answer:

It's 0.7% (make sure to include the % sign)

Step-by-step explanation:

Khan Academy

Four different leadership styles used by Big-Six accountants were investigated. As part of a designed study, 15 accountants were randomly selected from each of the four leadership style groups (a total of 60 accountants). Each accountant was asked to rate the degree to which their subordinates performed substandard fieldwork on a 10-point scale—called the "substandard work scale". The objective is to compare the mean substandard work scales of the four leadership styles. The data on substandard work scales for all 60 observations were subjected to an analysis of variance.
Interpret the results of the ANOVA F test shown on the printout for a = 0.05.
a. At a = 05, there is insufficient evidence of differences among the substandard work scale means for the four leadership styles.
b. At a = .05, three is no evidence of differences among the substandard work scale means for the four leadership styles.
c. At a = .05, there is sufficient evidence of difference among at least two of the substandard work scale means for the four leadership styles.
d. None of the above.

Answers

Answer:

c. At a = .05, there is sufficient evidence of difference among at least two of the substandard work scale means for the four leadership styles.

Step-by-step explanation:

From the given output, df(Between)=3

df (Between) =k-1, where, k denotes number of groups. Therefore, k-1=3, k=4.

Thus the null hypothesis is as follows:

H0:mu1=mu2=mu3=mu4 (there is no difference in substandard work scale means for four leadership styles)

H1: At least one mean scale is different from another.

Per rule, reject H0, if p value corresponding to F test statistic is less than given level of significance, alpha=0.05.

Here, F(3, 56)=6.056, p<0.05 (the p value is 0.0012). Therefore, reject H0, and conclude that at least one substandard work scale mean of a leadership is significantly different from a substandard work scale mean of another leadership.

3 and 1/4 minus 5/8 please help!

Answers

3 1/4 is equal to 13/4 or 26/8.

26/8 - 5/8 = 21/8

21/8 = 2 5/8

Solving One Step Equations:
z - 2.3 = 0.46

Answers

Answer:

z =2.76

Step-by-step explanation:

z - 2.3 = 0.46

Add 2.3 to each side

z - 2.3+2.3 = 0.46+2.3

z =2.76

The teacher decides that no student can win twice, so she removes the tickets of the first winner before drawing the second winner. What is the probability that she draws Kitzen first and then Ava second? Use a / to represent a fraction bar.

Answers

Answer:

3/4

Step-by-step explanation:

Take Kitzen's number of raffle tickets and put them over Ava's tickets to give you 12/16 and the simplify which gives you 3/4 because the fraction is divisible by 4.

You purchased a bond 75 days ago for $911.72. You received an interest payment of $32.00 68 days ago. Today the bond’s price is $993.39.



What is the holding period return (HPR) on the bond as of today?

Answers

Answer:

Holding Period Return (HPR) = 12.47% (Approx)

Step-by-step explanation:

Given:

Purchase price of bond = $911.72

Interest received = $32

Ending price of bond = $993.39

Find:

Holding period return (HPR) = ?

Computation:

⇒ Holding Period Return (HPR) = [Ending price of bond - Purchase price of bond + Interest received] / Purchase price of bond

⇒ Holding Period Return (HPR) = [$993.39 - $911.72 + $32] / $911.72

⇒ Holding Period Return (HPR) = [$113.67] / $911.72

⇒ Holding Period Return (HPR) = 0.12467

⇒ Holding Period Return (HPR) = 12.47% (Approx)

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The author states a claim, supports that claim with several examples, and then issues a call to action. The author compares and contrasts women's rights with men's rights, building to a call to action. The author organizes information sequentially, building a narrative of how unequal rights have affected women. The author begins with a call to action and then uses several examples to support it. Theresa has a rectangular pool 30 ft long, 15 ft wide, and 4 ft deep. Theresa fills her pool using city water at a rate of $3.95 per 100 gallons of water. Nancy has a circular pool with a diameter of 24 ft and a depth of 4 ft. Nancy fills her pool with a water delivery service at a rate of $200 per 6000 gallons. If Theresa and Nancy both fill their pools 6 inches from the top of the pool, determine and state who paid more to fill her pool. [ 1 ft3 water = 7.48 gallons] (x) A change in position is called:(a) Speed(b) velocity(c) displacement(d) distance Help asap Find the surface area of a cylinder with 50 inches long and a raduis of 2 inches The earth has a mass of approximately 6\cdot 10^{24}610 24 6, dot, 10, start superscript, 24, end superscript kilograms (\text{kg})(kg)left parenthesis, start text, k, g, end text, right parenthesis. The volume of the earth's oceans is approximately 1.34\cdot 10^{9}1.3410 9 1, point, 34, dot, 10, start superscript, 9, end superscript cubic kilometers (\text{km}^3)(km 3 )left parenthesis, start text, k, m, end text, cubed, right parenthesis, and ocean water has a mass of about 1.03 \cdot 10^{12}\,\dfrac{\text{kg}}{\text{km}^3}1.0310 12 km 3 kg 1, point, 03, dot, 10, start superscript, 12, end superscript, start fraction, start text, k, g, end text, divided by, start text, k, m, end text, cubed, end fraction . To the nearest hundredth of a percent, what percent of the earth's mass is from the oceans? (Ignore the \%%percent symbol when entering your answer. For example, if the answer is 0.11\%0.11%0, point, 11, percent, enter 0.110.110, point, 11.) John wants to invest P dollars at a 4% interest rate. After 5 years the investment will be worth 2000 dollars. How much will it be worth in 11 years? In paragraph 3, what point is the author making when he talks about acid rain? The changing of the rivers created more ____________ for animals aRegeneration bVegetation c Erosion d Habitats Describe a time you or someone you know faced a stereotype or prejudice. Find the interquartile range (IQR) of the data plot below wil give bianleastFind the first term in the pattern with the formula: 40 6n 1.4001440240 Lee el prrafo y escoge la opcin que contesta la pregunta. Read the paragraph and choose the option that answers the question.Si te gusta explorar calles y estructuras antiguas, entonces te encantara este lugar! Aprenders sobre la historia de los espaoles y otros grupos indgenas durante el tour del fuerte. Explorars los bosques nacionales y las cavernas exticas. Y no te olvides de comer un flan que es uno de los postres ms populares y sabrosos del pas!What country is the narrator describing in the reading? Dominican Republic Costa Rica Puerto Rico Argentina show more notes w. heieie you can do it for