The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases.
What is amplitude?
A periodic variable's amplitude is a gauge of its change over a single period. A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several definitions of amplitude, which are all functions of the size of the disparities between the variable's extreme values.
The change in pressure that a sound wave causes when it is measured at a particular location is related to the amplitude of the wave. If the amplitude rises, the sound is heard as louder; if it falls, the sound is regarded as quieter.
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A pressure vessel support bracket is to be designed so that it can withstand a tensile loading cycle of 0-500 MN/m2 once every day for 25 years. Which of the following steels would have the greater tolerance to intrinsic defects in this application: (i) a maraging steel (Ke-82 MNm-, C= 0.15 × 10-11, m-41), or (ii) a medium-strength steel (Kic 50 MN m1, C0.24x 10-", m 3.3)? For the loading situation a geometry factor of 1.12 may be assumed.
Ao for a maraging steel (82 M Nm-, C= 0.15 10-11, m-41) is equal to 58.2*10^-6m, and for a medium-strength steel, it is 40.6*10^-6m (50 MN m1, C0.24x 10-", m 3.3). The second case can be more tolerant.
Ultra-high-strength steel alloys, or maraging steels, are a unique class of low-carbon steel that have comparable ductility while being stronger and tougher than most other steels. A structure's capacity to safely withstand until repair can be made is known as damage tolerance. Based on the presumption that defects can exist in any building and that these problems spread with use, the approach to engineering design that takes damage tolerance into account.
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - A)
Ao = 58.2*10^-6m
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - Ao)
comparable to case two
Ao = 40.6*10^-6m
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Six artificial satellites complete one circular orbit around a space station in the same amount of time. Each satellite has mass m and radius of orbit L. The satellites fire rockets that provide the force needed to maintain a circular orbit around the space station. The gravitational force is negligible. Rank the net force acting on each satellite from their rockets. Rank from largest to smallest. To rank items as equivalent, overlap them.
ω is the same for all satellites.
T = ω2 mL, scaled as the product of m and L
a) milliliters = 800*5000 = 4*10^6
b) milliliters = 100*2500 = 0.25*10^6
c) milliliters = 100*10000 = 1*10^6
d) milliliters = 200*5000 = 1*10^6
e) milliliters = 300*7500 = 2.25*10^6
f) milliliters = 400*2500 = 1*10^6
a, e, c=d=f, b
A satellite or artificial satellite is an object intentionally placed in orbit in space.
Apart from passive satellites, most satellites have power generation systems for onboard equipment such as: B. Solar panels or thermoelectric radioactive isotope generators (RTG). Most satellites also have a way of communicating with ground stations called transponders.
Many satellites use standardized buses to save cost and effort, but the most popular are the smaller CubeSats.
Satellites are launched by rockets from the Earth's surface high enough to avoid their orbits collapsing in the atmosphere. The satellite can then change or maintain its orbit by means of propulsion, usually chemical or ion thrusters.
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What Are Balanced and Unbalanced Forces?
Balanced forces are equal in size and opposite in direction, whereas unbalanced forces are not equal in magnitude.
When forces are balanced, there's no alter in motion. In one of your circumstances within the last section, you pushed or pulled on an object from opposite directions but with the same force. To have unbalanced forces implies that the force applied in one direction is greater than the force applied within the opposite direction. When unbalanced forces are acting on an object, there's an alteration in speed and/or direction. By applying an unequal force, you'll be able to alter the motion of an object. Unbalanced forces can make an object at rest begin moving, make a moving object halt, or alter the direction and speed of the object.
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If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity of object 2 if the two objects collide and bounce off of each other and object 1 has a final velocity of -2 m/s?
The final velocity of object 2 is: 3 m/sec
What is the conservation of mass?According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.
According to conservation of mass,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Given that,
m₁ = 50 kg
m₂ = 75 kg
u₁ = 4 m/s
u₂ = -1 m/s
v₁ = -2 m/s
v₂ = ?
Now, putting the values,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)
or, 125 = -100 + 75 v₂
or, 75 v₂ = 225
or, v₂ = 3 m/sec.
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what is the maximum speed of a 330 kg car if the spring is compressed the full amount? express your answer with the appropriate units.
A spring that has been fully compressed can move at a maximum speed of 4.993 m/s. According to kinetic theory, molecules in any system are orientated arbitrarily.
Determine the maximum speed?The weight of the spring is 330 kg, According to kinetic theory, molecules in any system are orientated arbitrarily. The radial and angular components of every molecule are unique.According to theory, the root mean square notion is used to compute energy leakage in any system.An illustration of determining energy dissipation parameters in electronics is zero current.When 3RT = mv2 and v2 = 3RT/m T/m = 1, K.E = 3RT/2 and K.V = mv2.A spring that has been fully compressed can move at a maximum speed of 4.993 m/s.To learn more about Maximum speed refer to:
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A photon is incident on a Hydrogen atom that is in the ground state, resulting in an ejected electron. Which of the following regions of the electromagnetic spectrum could that photon be associated with? Visible Infrared Radio UV?
UV (Ultraviolet) is the regions in the electromagnetic type of spectrum that could photon must be associated with it. Option (4)
Ultraviolet radiation will reaches the Earth's floor is made of forms of rays, referred to as UVA and UVB. Ultraviolet radiation additionally comes from solar lamps and tanning beds. It can reason pores and skin damage, untimely aging, melanoma, and different forms of pores and skin cancer.
A photon become absorbed via way of means of a hydrogen atom in its floor state, and the electron become precipitated to the 5th orbit. When the excited atom returned. to its floor state, seen and different quanta had been emitted. Absorbed mild is mild that is not visible at the same time as emitted mild is mild this is visible. Emission is while electrons go back to power levels. Absorption is while electrons advantage power and soar to better power levels.
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Correct Question:
A photon is incident on a Hydrogen atom that is in the ground state, resulting in an ejected electron. Which of the following regions of the electromagnetic spectrum could that photon be associated with?
1. Visible
2. Infrared
3. Radio
4. UV (Ultraviolet).
bob's car ran out of gas 3.4 km from the nearest gas station. if it requires a 500 n force to push his car, how much work will bob do to get his car to the gas station? (1.7 MJ or 1.7 10 j)
The mileage of the car is calculated by dividing the number of miles traveled by the amount of gas used. Car's Gas Mileage is 147.0
How do you calculate how far you can go on a tank of gas?Gas Run Out.Turn on your hazard lights and safely pull your car over to the right shoulder.If you have emergency gear, such as a reflective triangle, set it up as needed.Go for a stroll to the closest gas station.Place a roadside assistance call.How to Calculate Your Car's Gas MileageThe outcome is your car's normal miles per gallon, which you can calculate by dividing the distance traveled by the number of petrol tanks you filled up.For instance, your car would average 25 miles per gallon if you traveled 200 miles on 8 gallons of gas.Car's Gas Mileage = 500/3.4
=147.0
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A 50 g rock is launched vertically in the air by a slingshot. The slingshot exerts an average force of 53 N on the rock over a distance of 0.750 m.
The work done by the average force is 39.75 J.
What is the work done by the average force?The work done by the average force of the slingshot is calculated by applying the following equation as shown below.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the average forced is the displacement of the rockThe given parameters include;
average force, f = 53 Ndisplacement, d = 0.75 mThe work done by the average force is calculated as follows;
W = 53 N x 0.75 m
W = 39.75 J
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24. Circle each letter beside something that continues to happen as long as the
switch is closed in the primary circuit.
a. A current flows in the secondary circuit.
b. A voltage is applied across the secondary circuit.
c. A magnetic field exists around the primary coil.
d. A magnetic field exists around the secondary coil.
When the switch in the primary circuit is closed, the following continue to happen:
1. the current flows in the secondary circuit
2. voltage is supplied across the secondary circuit and
3. A magnetic field exist around the primary coil.
What happens when the primary circuit is closed?Closing the switch in the primary circuit produces a constant electric current in the conducting wire. This constant electric current produces a magnetic field in the primary coil. The soft-iron ring enhances the strength of the magnetic field, and the ring itself becomes magnetized.
The primary circuit refers to the input section of an isolated power supply, which is connected to the AC mains. This section of the power supply has dangerous voltage levels and not designed to be directly accessed by users.
Therefore when the primary circuit switch is closed, the current flows in the secondary circuit, a voltage is supplied across the secondary circuit and a magnetic field exist around the primary coil.
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which of the following statements about a mercury barometer are correct? select all that apply. multiple select question. the atmospheric pressure is proportional to the height of the mercury in the tube. the space above the mercury in the inverted tube contains air at atmospheric pressure. the mercury tube is sealed at the top. the barometer contains a tube filled with mercury that is inverted in a container of mercury.
The mercury tube is sealed at the top, and ambient pressure is inversely proportional to the height of the mercury within.
On Mercury, are people still alive?Living on Mercury wouldn't be simple, but it might not be impossible. Remember that you wouldn't last very long without a space suit because there isn't any atmosphere up there. On top of all of this, Mercury experiences one of the Solar System's biggest temperature variations.
What makes Mercury so valuable?Mercury is frequently utilized in numerous devices, including switches and batteries, since it is an effective electrical conductor. In small-scale mining operations, it is utilized to amalgamate gold and silver because it easily joins with other metals.
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A 1800 kg car traveling at a speed of 23 m/s skids to a halt on wet concrete where μk = 0.60. How long are the skid marks?
The length of the skid marks of a car of mass 1800 kg is 21.59 m.
What is length?Length is the distance between two points.
To calculate the length of the skid mark, we use the formula below
Formula:
d = (v²-μv²)/g.................. Equation 1Where:
d = Length of the skid marksv = Velocity of the carμ = Coefficient of kinetic frictiong = Acceleration due to gravityFrom the question,
Given:
v = 23 m/sμ = μk = 0.6g = 9.8 m/s²Substitute these values into equation 1
d = [23²-(0.6×23²)]/9.8d = (529-317.4)/9.8d = 211.6/9.8d = 21.59 mHence, the length of the skid marks is 21.59 m.
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Germanium, element 32 on the Periodic Table, is shown here. If a proton is added to the nucleus of germanium, what outcome(s) would occur? Select ALL That apply.A) The atom would increase in mass but would remain germanium.
B) The atom would become arsenic and have different properties.
The atom would remain germanium, but it would have a positive charge.
D) The atom would increase in mass and have different elemental properties.
E) The atom would expel a neutron to maintain a constant mass and chemical properties.
If a proton is added to the nucleus of germanium, the atom would increase in mass and have different elemental properties (option D).
What is mass number?Mass number of an element is the total number of protons and neutrons in an atomic nucleus. The atomic number of the element is the number of protons contained in the nucleus of the atom.
Elements are arranged in an hierarchical order on the periodic table, which is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group (column).
According to this question, germanium is an element on the periodic table with atomic number of 32. This means that germanium has 32 protons in its nucleus. The number of protons of an atom represents the identity of that element.
This means that adding a proton to the nucleus of germanium atom will increase it to 33, hence, changing the identity of the element.
Therefore, option D correctly describes what will happen if a proton is added to germanium atom.
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Open the Rotation Curve of a Spiral Galaxy animation and click at various distances from the galactic center to create a graph of the galaxy's rotation curve; be sure to start with points very close to the galactic center and continue to well beyond the visible part of the galaxy. Which of the following statements best describes the pattern of the graph?
Starting from the center, speeds at first rise rapidly, and then become nearly constant with increasing distance.
The Rotation Curve of a Spiral Galaxy animation and click on at various distances from the galactic center to create a graph of the galaxy's rotation curve beginning from the center, speeds in the beginning upward push hastily, after which turn out to be nearly consistent with increasing distance.
Circ = R ∂Φ/∂R. mean orbital motion and their bulk rotational speed can be slightly smaller than the round pace. Spectroscopic radial velocities may be used to determine the rotational velocities of spiral galaxies provided that the galaxies are inclined to the line of sight.
The rotation curve (RC) of our Galaxy, the Milky Way, is built starting from its very internal regions (few hundred parsecs) out to a massive galactocentric distance of ∼2 hundred kpcs the usage of kinematical statistics on an expansion of tracer gadgets shifting in the gravitational potential of the Galaxy, without assuming any theoretical.
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Ultrasound in Medicine. A 1.70-MHz sound wave travels through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 72 beats per second are detected. The speed of sound in body tissue is 1500 m/s. Calculate the speed of the fetal heart wall at the instant this measurement is made.
The speed of the fetal heart wall at the instant is 0.031 m/s when 72 beats per second of hart beat was detected.
The Doppler Effect, defined as the change in frequency of a wave in relation to an observer moving relative to the wave source, must be used.
Let
v= magnitude of the heart wall speed
V= speed of sound = 1500
fh= the frequency the heart receives (and reflects) =
fi= original frequency
ff= reflected frequency
fb= frequency for the beats=72
Make use of the Doppler Effect formula.
We have this formula because the heart is a moving observer and the device is a stationary source.
[tex]f_h = [(V+ v)/(v)] fi....(1)[/tex]
We can use this formula if we consider the heart to be a moving source and the device to be a stationary observer.
[tex]f_f = [(V)/(V-v)] fh....(2)[/tex]
The beats' frequency would be the difference between the original and reflected frequencies.
[tex]f_b = f_f -f_i......(3)[/tex]
substituting (1) and (2) into (3),
[tex]f_b=\frac{V}{V-v}\frac{V+v}{V}f_i-f_i\\\\f_b=f_i(\frac{V+v}{V-v}-1)\\\\f_b=f_i\frac{V+v-V+v}{V-v}\\\\f_b=\frac{2v}{V-v}[/tex]
solving for v ,
[tex]v=V\frac{f_b}{2f_i-f_b}=1500\frac{72}{2(1.70*10^6)-72}=0.031 m/s[/tex]
Thus, the speed of fetal heart is 0.031 m/s
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An electron is released from rest in a uniform electric field. If the electric field is 1.25 kN/C, at the end of 20 ns
the electron's velocity will be approximately
At the end of 20 ns, the electron's velocity will be approximately 5.2 × 10⁶ m/s.
What is electric field?The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
Electric charge or magnetic fields with variable amplitudes can produce an electric field. The attraction forces that keep together atomic nuclei and electrons at the atomic scale are brought on by the electric field.
Given that:
the electric field is 1.25 kN/C
So, acceleration of the electron: a = eE/m
= (1.6 × 10⁻¹⁹×1.25×10³)/(9.1×10⁻³¹) m/s²
= 2.6 × 10¹⁴ m/s².
Hence, after the end of 20 ns the electron's velocity will be = at
= 2.6 × 10¹⁴ × 20 × 10⁻⁹ second
= 5.2 × 10⁶ m/s.
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What is the mass of a ball with a momentum of 18 kg*m/s and a velocity of 9 1 m/s? O 2 m/s O 2 kg O 162 m/s O 162 kg
Answer:
B: 2 kg.
Explanation:
To find the mass of an object given its momentum and velocity, you can use the following formula:
mass = momentum / velocity
In this case, the momentum of the ball is 18 kg*m/s and its velocity is 9 1 m/s, so the mass of the ball is:
mass = 18 kg*m/s / 9 1 m/s
= 2 kg
Therefore, the correct answer is B: 2 kg.
The helium flying balloon has the same size of 6 m radius.Find the volume of the helium.
Answer:904.8m³
Explanation:
V=4π/3×(r)³
V=4π/3×(6)³
V=4π/3×216
V=4π×72
V=288π
V=904.8m³(904.77)
examine the second figure(figure 2), in which you see jackie's spaceship traveling at 1000 km/hr , with the ship's headlight on. according to special relativity, jackie would say that a beam of light from the headlight is traveling at , and you would say that the beam of light is traveling at .
light from the headlight is traveling at speed of light , and you would say that the beam of light is traveling at Speed of light.
A fundamental premise of relativity is that everyone always measures the same speed of light, c, no matter how the observer or the light source may be moving. Note that this makes light different from material objects such as baseballs.
The speed of light in a vacuum, commonly denoted by c, is a universal physical constant important in many areas of physics. The speed of light, c, is exactly 299,792,458 meters/second (about 300,000 km/second; 186,000 miles/second; 671 million miles/hour). According to special relativity, c is the speed at which conventional matter or energy (and thus any signal carrying information) can travel in space.
All forms of electromagnetic radiation, including visible light, travel at the speed of light. For many practical purposes, light and other electromagnetic waves appear to travel instantaneously, but for long distances and highly sensitive measurements, finite velocities have significant implications.
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define the principal focus of a concave mirror
The principal focus of a concave mirror is a point on the axis of the mirror at which parallel rays of light are brought to focus after being reflected by the mirror. A concave mirror is a mirror with a curved surface that is shaped like the inside of a bowl, with the center of the curve facing outward. When light rays are reflected by a concave mirror, they are brought to a focus at the principal focus of the mirror. The distance from the center of the mirror to the principal focus is known as the focal length of the mirror. The principal focus of a concave mirror is an important concept in optics and is used in the design and operation of various optical instruments, such as telescopes and cameras.
if a person pulls on the rope with a constant force what is the acceleration of the system? answer in units of m/s2.
The tension in a given rope may be thought of as T = (m g) + (m a), where "g" denotes the gravitational acceleration of any items the rope is supporting and "a" denotes any additional accelerations placed on those same objects.
How do you find the tension of a rope with acceleration?Because of the forces tugging on the rope from both ends, a particular strand of thread or rope will be under strain. Remember that force is defined as mass times acceleration. Any change in mass or acceleration of the objects the rope is supporting will result in a change in the tension in the rope, assuming the rope is stretched firmly. A system's components are nevertheless subject to gravity's continual acceleration even when it is at rest. The tension in a given rope may be thought of as T = (m g) + (m a), where "g" denotes the gravitational acceleration of any items the rope is supporting and "a" denotes any additional accelerations placed on those same objects. The assumption that our rope, cable, etc. is thin, massless, and incapable of being stretched or broken is made for the majority of physics problems.Consider a system where a weight is suspended from a wooden beam using only one rope as an example (see picture). The system is completely at rest because neither the weight nor the rope are moving. Due to this, we are aware that in order for the weight to be maintained in equilibrium, the tension force and the weight's gravitational force must be equal. Or, tension (Ft) Equals force of gravity (Fg) = m g.In that case, the tension force would be 10 kg x 9.8 m/s2 = 98 Newtons, assuming the weight is 10 kg.To Learn more About acceleration refer To:
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a drum rotates around its central axis at an angular velocity of 11.00 rad/s. assume that the drum then slows at a constant rate of 4.30 rad/s2. (a) how much time does it take and (b) through what angle does it rotate in coming to rest?
The time taken by the drum to come to rest is 2.55 seconds and the angle that it makes is 14π.
The drum rotates around the central axis with angular velocity of 11 rad/s. After that it slow down with constant rate of 4.3 rad/s².
(a) The time taken by the drum to come at rest will he given by,
W' = W + at
W is initial angular velocity,
W' is final angular velocity,
a is the rate of slowing down,
t is the time taken.
Putting values,
11 = 4.3t
t = 11/4.3
t = 2.55 seconds.
(b) The angular displacement will be given by,
2aS = W'² - W²
S is the angles made while slowing down,
Putting values,
2(4.3)S = (11)²
S = 14 rad.
So, the angle made is 14π.
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Treating the nucleus as a Fermi gas, estimate the time it takes for a typical bound nucleon to cross the nucleus. Now, calculate the time for one revolution of a rigid rotor with j=2, I=5000amu fm2, and A= 208. You may find this helps justify the Nilsson model, where we treat the nucleon as if its orbiting around an essentially stationary rotor.
The time taken for one revolution of a rigid rotor to cross the nucleus is 6,240,000×10⁻¹⁵ sec .
Microwave rotational spectroscopy utilizes microwave radiation to quantify the energies of rotational advances for atoms in the gas stage. It achieves this through the communication of the electric dipole snapshot of the particles with the electromagnetic field of the astonishing microwave photon.
To test the unadulterated rotational advances for particles, researchers use microwave rotational spectroscopy. This spectroscopy uses photons in the microwave reach to cause changes between the quantum rotational energy levels of a gas particle.
We know that time taken to complete one revolution of a rigid rotor is
given by the formula J×(J+1)× B × h
where J is rotational quantum number,
B or I is rotational constant
and h or A is value of atomic mass of the nucleus.
So, on putting we get
=>t=2×(2+1)×5000×208
=>t=2×3×5000×208
=>t=6,240,000fm-sec or
=>t=6,240,000×10⁻¹⁵ sec
Hence, required time is 6.240,000×10⁻¹⁵ sec .
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b(4+a) ;where a = 6 and b - 2
= 2(4+6)
= 2×10
= 20
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An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s. What is the maximum height the object reaches? What is the object's final velocity as it hits the ground? (use g=9.8 m/s^2)
The maximum height the object reaches be 5.81 m.
The object's final velocity as it hits the ground be 10.67 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
An object starts with an initial height of 5 meters above the ground. It is thrown upward with an initial velocity of 4 m/s.
So, maximum height obtained by it be: H = 5 m + (4²/2×9.8) m = 5.81 m.
The object's final velocity as it hits the ground = √(2gH)
= √(2×9.8×5.81) m/s
= 10.67 m/s.
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Find the kinetic energy KKK of the block at the moment labeled B.
Express your answer in terms of kkk and AAA.
The kinetic energy KKK of the block at the moment labeled B is 3/8kA^2.
Kinetic energy is the energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.
Kinetic energy is the energy a body has due to its motion. If you want to accelerate an object you have to apply a force. To add strength, we need our work. When the work is done, the energy is transferred to the object and it moves at a new constant speed.
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Please help me
Jadee S. pulls a piece of luggage across the airport, notices that she is lagging behind her parents and wants to catch up for a short amount of time. She pulls with a horizontal force of 33.3 N. The force due to friction for the luggage is 12.3 N and the mass of the luggage is 50.0 kg.
Answer:
The acceleration of the luggage is:
a = (33.3 N - 12.3 N) / 50.0 kg = 0.466 m/s²
Explanation:
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Consider a fish swimming forward in the ocean. Which of the following describes the basic action/reaction forces between the fish and the water? Explain the answer.
a. The forces point in the same direction because forces in liquid media behave differently than forces in air.
b. The force of the fish points forward while the force of the water points back.
c. The force of the fish points back while the force of the water points forward.
d. The force of the fish points upward while the force of the water pulls downward.
Answer:
turn off the force
Explanation:
you now take three pieces of string from the previous problem and tie two of them together to make a string of double the mass density. you tie the single string and double string together and to two lamp posts that are 40 m apart as seen below. the interface is centered between the posts and the tension is 1.2 n. you briefly shake the string interface at 5 hz. By how many seconds does it win the race?
Taking three pieces of string from the previous problem and tie two of them together to make a string of double the mass density, V₁ = [tex]\sqrt{2}[/tex]V₂ it wins the race.
What is the mass density?An object's mass per unit volume is referred to as its mass density. The units that can be used to describe this characteristic are pounds per square foot (lb/ft²) and kilograms per square meter (kg/m³).
Given that,
tension = 1.2 N
Frequency = 5 Hz.
Length = 40 m
Let, mass density of thin string = m
mass density of thick string = 2m
As we know,
V₁ = [tex]\sqrt{F/m}[/tex]
V₂ = [tex]\sqrt{F/2m}[/tex]
Now,
V₁/V₂ = [tex]\sqrt{F/m} / \sqrt{F/2m}[/tex]
or, V₁/V₂ = [tex]\sqrt{2} /1[/tex]
or, V₁ = [tex]\sqrt{2}[/tex]V₂
Thus, speed of the thin string is [tex]\sqrt{2}[/tex] times greater than the speed of the thick string. So, it will comes first.
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what will the pressure inside the container become if the piston is moved to the 1.20 l mark while the temperature of the gas is kept constant?
The new pressure of the system when we move the piston to the 1.20 L mark is obtained as 0.833 atm.
What is the pressure inside the container?We know that if we want to obtain any of the parameters that has to do with a gas we have to apply any of the gas laws that pattern to the ideal gas and in this case we are looking at an ideal gas.
We are told that;
Initial pressure [tex]P_{1}[/tex]= 1 atm, Initial volume [tex]V_{1}[/tex]= 1 L
Final pressure [tex]P_{2}[/tex] = ? , Final volume [tex]V_{2}[/tex]= 1.20 L
By the use of the formula;
[tex]P_{1}[/tex] [tex]V_{1}[/tex] = [tex]P_{2}[/tex] [tex]V_{2}[/tex]
[tex]P_{2}[/tex] = 1 atm * 1L/1.20 L
= 0.833 atm
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Missing parts;
Inside the container is an ideal gas at 1.00 atm, 20.0 ∘C, and 1.00 L. This information will apply to the first three parts of this problem.
A) What will the pressure inside the container become if the piston is moved to the 1.20 L mark while the temperature of the gas is kept constant?
A 215-g object is attached to a spring that has a force constant of 77.5 N/m. The object is pulled 7.25 cm to the right of equilibrium and released from rest to slide on a horizontal, frictionless table. Calculate the maximum speed of the object.Find the locations of the object when its velocity is one-third of the maximum speed. Treat the equilibrium position as zero, positions to the right as positive, and positions to the left as negative.
(a) The maximum speed of the object is 1.37 m/s.
(b) The locations of the object when its velocity is one-third of the maximum speed is 5.87 cm.
In easy words, speed is the rate at which some thing actions in a specific direction. For instance as the rate of a vehicle journeying north on a highway, or the rate a rocket travels after launching. The scalar method absolutely the cost value of the rate vector is constantly be the rate of the motion.
Velocity is a vector expression of the displacement that an item or particle undergoes with appreciate to time . The preferred unit of speed value (additionally called speed ) is the meter according to second (m/s). Alternatively, the centimeter according to second (cm/s) may be used to specific speed value.
Maximum speed for the object:
[tex]w=\sqrt{ \frac{k}{m}\\\\\\w=\sqrt{ \frac{77.5}{0.215}\\\\\\\\\\\\\w=\sqrt{ 360.46}\\\\\\\\w=18.98[/tex]
Maximum velocity = ωr
v= 18.98*0.0725
v= 1.37.
Maximum velocity = ωr = 1.37.
The speed of the object at a distance x from its mean position is given as:
[tex]v=w\sqrt{a^2- x^{2} } } \\so,\\ v=x\\x=\sqrt[]{8(*7.25} \\x= 5.87[/tex]
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