Answer:[tex]\sqrt{65} m/s[/tex]
Explanation:
Describe at least four techniques used by astronomers to determine distances to stars and galaxies. Make sure you include the scientific theory behind each method and the range over which each method is considered valid.
Radar - measuring distances in our solar system
Parallax - measuring distances to nearby stars
Cepheids - measuring distances in our Galaxy and to nearby galaxies
Supernovae - measuring distances to other galaxies
Different techniques which can be used by the astronomers to determine the distances to the stars and galaxies include Radar, Parallax, Cepheids, and Supernova.
What are the techniques to determine distance of stars?
The distances to the nearby stars are precisely and accurately determined using the different techniques such as parallax. When a celestial body is seen from a different, widely separated viewing point, its position with respect to the more distant background stars or galaxies varies. This angular difference is known as parallax.
Radar is the measuring of the distances in the solar system.
Parallax is the measuring of distances to the nearby stars.
Cepheids is the measuring of distances in Galaxy and to nearby galaxies.
Supernovae is the measuring of distances to the other galaxies.
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a simle arrangement by means of which emf are compared is known as
A simple arrangement by means of which EMF are compared is known as a voltmeter.
Discussion about Voltmeter :
A voltmeter is a straightforward device used to compare electromagnetic fields.When there is no current flowing through a cell, its terminal voltage equals its electromotive force (emf). The difference in potential between a cell's electrodes is what determines its terminal voltage. Since voltmeters use the cell's current to draw voltage, they are unable to measure a cell's emf.Using a voltmeter, one may determine the voltage generated in an electric circuit. Volts are the emf's SI unit (V). Volts are the voltage's SI unit (V). Non-coulomb force, also known as non-electric force operation, defines emf.Learn more about voltmeter here:
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A 940-kg sports car collides into the rear end of a 2500-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.8 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact.
What was the speed sports car at impact?
Express your answer to two significant figures and include the appropriate units.
The speed of the sport car at the time of impact is 6.61 m/s.
What is the frictional force of the two cars?Frictional force of the two cars = coefficient of kinetic frictin × mass × acceleration of gravity
= 0.8 × (2500+940) × 9.8
= 26970N
What is the acceleration of the skidded cars?As per Newton's second law of motion, force = mass × accelerationAcceleration= force / mass= 26,970/3440
= 7.8 m/s²
What is the velocity of the sport car at the time of impact?As per Newton's equation of motion, V² - U² = 2aSHere, V = 0 m/s, a= -7.8 m/s², S= 2.8 mSo, 0²-U²= 2×(-7.8)×2.8=> U = √43.68
= 6.61 m/s
Thus, we can conclude that the speed of the sport car at the time of impact is 6.61 m/s.
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What is meant by constructive interference?
A. Waves combine and their amplitude decreases
B. Waves do not combine and their amplitude decreases
C. Waves do not combine and their amplitude increases
D. Waves combine and their amplitude increases
Answer:
D. Waves combine and their amplitude increases
Explanation:
amplitude is the height of the wave in a graph
constructive interference happens when two waves are lined up perfectly
example when two speakers playing same music while facing each other, music will appear louder
Destructive interference happens when the peaks match the valleys and they cancel perfectly
like with noise cancelling headphones
during constructive interference, waves collide in phase
in phase means add together making the height of the wave in a graph bigger (amplitude increases)
Example: When we see two speakers right next to each other, we can experience constructive interference when the distance from each speaker to the observer is the same
two waves destructively interfere, they must have the same amplitude in opposite directions
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The figure illustrates flow through a pipe with diameters of 1.0 mm and 2.0 mm and with different elevations. Px is the pressure in the pipe, and Vx is the speed of a non-viscous incompressible fluid at locations x = Q,R,S,T, or U. Options are: Greater than, Less than, Equal to
PU is ... PQ
VU is ... 2VT
PR is ... PU.
VR is ... VS
VQ is ... VU
PR is ... PS
By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,
[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]To find the answer, we need to know about the Bernoulli's equation as well as the Equation of continuity.
How to find the solution?1) We have to find the relation between pressure at U and Q.
We have the Bernoulli's equation,[tex]P+\frac{1}{2}dV^2+dgh=constant.[/tex]
where, P is the pressure, V is the velocity, d is density, g is acceleration due to gravity and h is the height of the flow.
By using the equation, we can find the pressure at U and Q.[tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_q+\frac{1}{2}dV_q^2+dgh\\where,\\V_u=V_q, \\since, D_p=D_q\\Thus,\\P_u=P_q+dgh[/tex]
[tex]P_u > P_q[/tex]
2) We have to find the relation between velocity at U and T.
For this, we have the equation of continuity as,[tex]AV=constant\\A_1V_1=A_2V_2[/tex]
From the diagram, we have,[tex]A_u=\pi r^2=\pi *(0.5)^2=0.25\pi *mm^2\\A_t=\pi *1=\pi mm^2\\V_u=V\\V_t=?[/tex]
Thus, the relation between velocity at U and T is,[tex]V_t=\frac{A_uV_u}{A_t}=\frac{V}{4}[/tex]
[tex]2V_t=2*\frac{V}{4} =\frac{V}{2}\\V_u=V\\[/tex]
[tex]V_u > 2V_t[/tex]
3) We have to find the relation between pressure at R and U
[tex]P_u+\frac{1}{2}dV_u^2+dg*0= P_r+\frac{1}{2}dV_r^2+dg*0\\\\V_u=V , then\\V_r=V_t=\frac{V}{4}=\frac{V_u}{4} \\\\P_u=P_r+\frac{1}{16}[/tex]
[tex]P_u > P_r[/tex]
4) We have to find the relation between velocity at R and S
Both points R and S, have same area, thus same velocity.[tex]V_r=V_s[/tex]
5) We have to find the relation between velocity at Q and U
Both points Q and U, have same area, thus same velocity.[tex]V_q=V_u[/tex]
6) We have to find the relation between pressure at R and S
Both points R and S, have same area and thus, same velocities.[tex]P_r=P_s+dgh[/tex]
[tex]P_r > P_s[/tex]
Thus, we can conclude that, By Bernoulli's equation as well as the Equation of continuity the relation between pressure and velocities at different points are,
[tex]P_u > P_q[/tex] [tex]V_u > 2V_t[/tex] [tex]P_u > P_r[/tex] [tex]V_r=V_s[/tex] [tex]V_q=V_u[/tex][tex]P_r > P_s[/tex]Learn more about the Bernoulli's equation here:
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(Please help 25 points)
Asteroids X, Y, and Z have equal mass of 6.0 kg each. They orbit around a planet with M=6.20E^24 kg. The orbits are in the plane of the paper and are drawn to scale.
In the statements below, TE is the total mechanical energy, KE is the kinetic energy, and PE is the potential energy.
The PE of X at r is .... that at s
The TE of Y is .... the TE of X
The PE of Y at u is .... the PE of Z at c
The speed of Y at i is .... that at u
The KE of Z at u is .... that at m
The PE of Y at s is .... the PE of X at c
The TE of Z is .... the TE of X
The PE of X at c is .... the PE of Z at c
(Options are: greater than, less than, equal to)
The potential energy (P.E) of X at r is less than P.E at s.
The total energy (T.E) of Y is less than total energy (T.E) of X.
The PE of Y at v is greater than the PE of Z at c.
The speed of Y at i is .greater than that at v.
The kinetic energy (KE) of z at u is less than that at n.
The PE of Y at s is less than the PE of X at c.
The PE of X at c is less than the PE of Z at c.
The PE of X at c is less than the PE of Z at c.
PE of X at r and at sThe potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.
TE of Y is .... the TE of XThe total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.
PE of Y at v is .... the PE of Z at cThe PE of Y at v is greater than the PE of Z at c due to greater displacement at v.
Speed of Y at i is .... that at uThe speed of Y at i is .greater than that at v because i is closer to the planet than v.
KE of Z at u is .... that at nThe kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.
PE of Y at s is .... the PE of X at cThe PE of Y at s is less than the PE of X at c, because position c has greater displacement.
The TE of Z is .... the TE of XThe TE of Z is greater than the TE of X due to greater displacement of Z from the planet.
The PE of X at c is .... the PE of Z at cThe PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.
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state whether the table represents a relation function both or neither x y 4 -20 1 -17 4 -14 16 5 10 0 -19 -16
state, whether the table represents a relation function both or neither x y 4 -20 1 -17 4 -14 16 5 10 0 -19 -16 Reconstruction was successful in that it allowed the United States to once again function as a single country by 1877. The states' rights vs. federalism controversy, which had been a point of contention since the 1790s, was also eventually resolved during reconstruction.
By most other standards, reconstruction was a failure: radical Republican legislation eventually failed to shield former slaves from white persecution and to bring about significant alterations to the South's socioeconomic structure. The federalism question, which had been a topic since the 1790s practically immediately, was at hand when President Rutherford B. Former Confederate officials and slaves returned to the South after Hayes withdrew federal soldiers from the region in 1877. These newly powerful white southern legislators established anti-progressive laws like voter ID requirements and black codes with the help of a conservative Supreme Court in an effort to roll back the rights that blacks had won during Radical Reconstruction. With its rulings in the Slaughterhouse Cases, the Civil Rights Cases, and United States v., the U.S. Supreme Court strengthened this anti-progressive movement federalism.
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What is the equation for the enthalpy of vaporization?
A. Q = m*Lv
B. Q = m/Lv
C. Q = 1/m*Lv
D. Q = Lv/m
Answer:
A: Q = m*Lv
Explanation:
The equation formula for the enthalpy of vaporization is;
Q = m*ΔHv
Where;
q = heat energy
m = mass
ΔHv = heat of vaporization
If a body has a velocity 50 m s-1
and the uniform acceleration is 5 m s-2, find the time it takes to travel a distance
of 240 m.
Answer:
Using the relation V^2 = U^2 + 2× a× S
V^2 = 50^2 + (2× 5 × 240 )
V^ 2 = 2500 + 2400
V^ 2 = 4900
V= (4900)^0.5 = 70 m/s
hence, velocity at a distance of 240 m will be 70m/s.
Now using the relation,
V= U + a× t
70 = 50 + 5 × t
20 = 5 × t
t = 20/5 = 4m/s
hence , time required to travel a distance of 240m will be 4s.
In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of the effect resulting from evacuating air from a container. It is the basis for this problem. Two steel hemispheres of radius 0.430 m (1.41 feet) with a rubber seal in between are placed together and air pumped out so that the pressure inside is 15.00 millibar. The atmospheric pressure outside is 940 millibar.
1. Calculate the force required to pull the two hemispheres apart. [Note: 1 millibar=100 N/m2. One atmosphere is 1013 millibar = 1.013×105 N/m2 ]
2. Two equal teams of horses, are attached to the hemispheres to pull it apart. If each horse can pull with a force of 1450N (i.e., about 326 lbs), what is the minimum number of horses required?
The values of the required solutions are
F= 53731 N N=37.05What is the minimum number of horses required?What is Force?
In the field of physics, an influence that can alter the motion of an object is referred to as a force. An object having mass can experience a change in its velocity, often known as an acceleration, when subjected to a force. Intuitively, force can also be conceptualized as either a push or a pull. Because it may be measured in both magnitude and direction, a force is considered a vector quantity.
What is atmospheric pressure?
The pressure that is exerted within the atmosphere of the Earth is referred to as barometric pressure as well as atmospheric pressure. As a unit of pressure, the standard atmosphere is defined as having a value of 101,325 Pa. This value is equivalent to 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.
In most situations, the equation for force can be expressed numerically as
Force = pressure * A
Therefore
[tex]F= (970 - 15 B)(\pi * (0.430 )^2)[/tex]
F= 53731 N
In conclusion, If each horse can pull with a force of 1450N
The number of horses required is
[tex]N=\frac{60754 }{1450}[/tex]
N=37.05
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A bead of mass 15g is sliding on a wire. It has a speed of 2.0m/s at A, and it stops as it reaches the point C. The length of the wire from A to C is 250cm. How large an average friction force opposed the motion of the bead?
Answer:
.12 N
Explanation:
Velocity goes from 2 m/s to 0 m/s so average velocity = 1 m/s
.250 m / 1 m/s = .25 second to stop
change in velocity / change in time = accel
2 m/s / .25 sec = 8 m/s^2
F = ma
= .015 kg * 8 m/s^2 = .12 N
If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical speed be after having fallen a vertical distance of 50.8m if you neglect air resistance over that distance?
The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.
Time of motion of the girl
The time of motion of the girl is calculated as follows;
h = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0t is time of motiong is acceleration due to gravitySubstitute the given parameters and solve for time of motion;
50.8 = 0 + ¹/₂(9.8)t²
2(50.8) = 9.8t²
101.6 = 9.8t²
t² = 101.6/9.8
t² = 10.367
t = √10.367
t = 3.22 seconds
Final vertical velocity of the skydivervf = vi + gt
where;
vi is the initial vertical velocity = 0
vf = 0 + 9.8(3.22)
vf = 31.56 m/s
Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.
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How does the suns energy affect the climate of an area
There wouldn't be any life on Earth and no climate if it weren't for the Sun.
The spherical form of the Earth results in changes in the amount of sunlight that reaches the surface at various latitudes, giving rise to various climatic zones. Seasons are caused by the tilt of the Earth's axis of rotation in relation to the ecliptic plane.
The surface of the sun is around 6000 C hot; at this temperature, the solar mostly produces visible light. The Earth radiates infrared energy back into space to maintain its energy balance after being warmed by incoming solar radiation. The Earth's surface has an average temperature of 15 C, and at this temperature, the planet emits infrared light.
Carbon dioxide, methane, nitrous oxide, and other atmospheric greenhouse gases let solar energy to pass through but absorb infrared radiation that the planet emits back into space. This feature is not shared by other atmospheric elements like oxygen and nitrogen. These greenhouse gases re-emit infrared radiation in all directions to maintain energy balance, some of which is aimed at the Earth's surface and warms it. More greenhouse gases will increase infrared absorption and raise surface temperatures. This is comparable to how much blanket you cover yourself with at night. The blanket's thickness affects how warm you feel. The result of heat brought on by rising levels of greenhouse gases in the atmosphere is climate change.
In the course of billions of years, the Sun will continue to get hotter and brighter, rendering the Earth uninhabitable.
Additionally, all fossil fuels (coal, petroleum, and natural gas) and renewable energy are directly and indirectly derived from the sun (wind, solar, biomass, and hydroelectric).
Thank you,
Eddie
Examine the roller coaster track above. Assume there is negligible friction as the roller coaster moves from position A to position F. Also assume that the roller coaster has minimal kinetic energy at point A. Create three different models below to describe the kinetic energy, the potential energy, and the total energy of the roller coaster at point E. Examples of models include, but are not limited to: pie charts, bar graphs, equations, textual descriptions, and analogies.
At point E
the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energyWhat is the energy of the roller coaster at point E?The energy of a roller coaster could either be potential energy, kinetic energy or a combination of both potential and kinetic energy.
Using analogies, the energy of the roller coaster at point E can be compared to a falling fruit from a tree which falls onto a pavement and is the rolling towards the floor. Point E can be compared to the midpoint of the fall of the fruit.
At point E
the kinetic energy of the rollercoaster is small compared to the potential energythe potential energy is greater than the kinetic energythe total energy is a mixture of potential and kinetic energyIn conclusion, the energy of the rollercoaster at E is both Kinetic and potential energy,
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Question 5 & 6 plissssssss
Question: 5
The length of the pendulum is 7.6 m.
What is the expression of length of a pendulum in term of time period?Time period of the pendulum (T) = 2π×√(L/g)L= length of pendulum, g = acceleration due to gravity on earthSo, L = T²g/4π²
What is the length of the pendulum, if the time period is 3.20 s and acceleration due to gravity becomes 3×g?T= 3.20 sL = (3.2²×3×9.8)/4π²= 7.6 m
Thus, we can conclude that the length of the pendulum is 7.6 m i.e option C is correct.
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Question: 6
The object takes 2.55 seconds to reach the ground.
What is the expression of time taken to reach the earth surface by an object?From the conversation of energy, (1/2)mv²=mghSo, v=√(2gh)From Newtown's equation of motion, v=u+atHere, a= acceleration due to gravity which is gSo, √(2gh)=gtt= √(2h/g)
What is the time taken by an object dropped from 31 m to reach the ground?t= √(2×31/9.8)
= 2.55s
Thus, we can conclude that the option A is correct.
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It has been suggested that rotating cylinders about 19.5 mi long and 5.66 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?
_____rad/s
The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
Angular speed of the cylinder
The angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is calculated as follows;
a = v²/r
v² = ar
(ωr)² = ar
ω²r² = ar
ω²r = a
ω² = a/r
ω = √(a/r)
where;
a is centripetal acceleration = acceleration due to gravity, gr is radius of the cylinder = 5.66 m / 2 = 2.83 mi = 4554.4 mω is angular speedω = √(g/r)
ω = √(9.8/4554.4)
ω = 0.046 rad/s
Thus, the angular speed such a cylinder must have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.046 rad/s.
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A car with a mass of 1000 kg accelerates from 0 to 90 km/h in 10 seconds. a) What is its acceleration? b) What is the net force on the car?
Answer:
v
f=90km/h=25m/s
v_{_{i}}=0v
i=0
t=10\;\mathrm{s}t=10s
m=1000\;\mathrm{kg}m=1000kg
The acceleration of the car is 2.5 m/s². The net force acting on the car is 2500 Newtons (N). The correct answers are 2.5 m/s², 2500 Newtons (N).
Given:
Mass of the car (m) = 1000 kg
Acceleration (a) = 2.5 m/s²
a) The acceleration of the car is:
Acceleration (a) = Change in velocity / Time taken
Final velocity (v(f)) = 90 × 0.27778 = 25 m/s
Acceleration (a) = (Final velocity - Initial velocity) / Time taken
Acceleration (a) = (25 - 0 ) / 10
Acceleration (a) = 2.5 m/s²
Therefore, The acceleration of the car is 2.5 m/s².
b) Newton's second law of motion:
F = m × a
F = 1000 × 2.5
F = 2500 N
The net force acting on the car is 2500 Newtons (N).
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figue 1 shows a piece of elastic being stretched between 2 pieces of wood
When a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed
However, in physics, the type of stress applied when an elastic material is stretched is tensile stress.
Recall:
Stess is defined as force per unit area
Mathematically; Stress = F/A
What is elasticity?Elasticity can be defined as the ability of a deformed elastic material or body to return to its original size and shape when the forces causing the deformation are removed.
So therefore, when a piece of elastic material between two pieces of wood is being stretched beyond its limit, the elastic material or the object does not return to its original length when the force is removed
Complete question:
What happens when a piece of elastic material between two pieces of wood is being stretched beyond its limit?
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An electron is moving the east with a speed of 5.0 × 106 m/s. There is an electric field of
3.0 kV/m in the east direction. What will be the electrons speed after it has moved 1.00 cm?
The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
What is Electric field?Electric field is the physical field that surrounds a charge.
How to find final velocity of the electron when it moves some distance in a certain electric field?From Newton's second law, the acceleration the electron will bea=F/m=qE/m
where q= charge of electronE= electric field
m= mass of electron
=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)
=10¹⁵×0.526m/s²
The kinematics equation v²=v0²+2a(Δx)where v=final velocity of the electronv0=initial velocity of the electron =5×10⁶m/s
a=acceleration of the electron =10¹⁵×0.526m/s²
Δx=distance moved by the electron in east direction =1cm=10^-2m
Now v^2=(5×10⁶)²+2×10¹⁵×0.526×10^-2=25×10¹²+10.52×10¹²
=35.52×10¹²
Now velocity of electron=5.95×10⁶m/s.Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.
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What is the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean?
It is slightly less than 9.81 m/s2.
It is very large due to the high pressure.
It is zero.
It is significantly less than 9.81 m/s2.
The gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure. That is option B
What is gravitational acceleration?The gravitational acceleration is the acceleration of an object that is under free fall. The acceleration due to gravity is 9.81 m/s2. above the sea level.
One of the factors that affect gravitational acceleration is depth. This is because as the depth increases so will pressure increase.
Increase in pressure leads to increase in gravitational acceleration.
Therefore, the gravitational acceleration on the board of the Deepsea Challenger when it is in the Mariana Trench, 11 km below the surface of the Pacific Ocean is very large due to the high pressure.
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why is the bulb of hydrometer is made heavier give two reasons
The reason behind the heavier hydrometer bulb is the sinking of hydrometer is inversely proportional to the density of hydrometer, hence hydrometers is made heavier.
We all know that hydrometers float in liquid hence to maintain the centre of gravity while floating the hydrometer is made heavier using lead shots.
A converging lens has a focal length of 20cm. find graphically the image location for an object at each of the following distances from the lens: (a) 50cm (b) 20cm (c) 15cm (d) -40cm: determine the magnification in each case. Check your results by calculating the image position and lateral magnification from Eqs. (10) and (11), respectively.
Answer:
4
Explanation:
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4 answer
2. Three blocks, A,B and C of mass 2kg. 3kg. 5kg respectively kept side by side with one another are accelerated at 2m/s2 across a smooth horizontal surface by a force F evaluated the magnitude of F and what force the blocks exert on each other.
Answer:
Total mass of combination = 2+3+5 = 10kg.
Acceleration produced = 2m/s^2
hence force =( total mass × acceleration)= (2×10)= 20 N.
Net force on 3kg block = acceleration × mass = (2 × 2 )= 4 N
applied force on 2 kg block = 20N
Force between 2 kg and 3 kg block = (20-4) = 16N. ans
Net force on 3 kg block = 3 × 2 =6N.
Applied force on 3 kg block due to 2 kg block = 16N.
hence, force between 3 kg and 5 kg block = (16-6) = 10N .
answers:-
(a) 20 N
(b) 16N
(c) 10 N
iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weight of iron ball in air?
Answer:
453 gm
Explanation:
Immersed objects are buoyed up by force equal to mass of displaced liquid
400 + 53 = 453 gm in air
If little herbert does something uncon
sciously he will probably
If little herbert does something unconsciously he will probably, he's definitely very unware of he has done
Doing something unconscious may have some implications which may not be favourable.
What is unconscious?Unconscious simply means a state of someone being absent minded of what is happening to him or her at a particular period of time
So therefore, if little herbert does something unconsciously he will probably, he's definitely very unware of he has done
Complete question:
What happens if little herbert does something unconsciously he will probably
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It is useful to use a _________ to demonstrate how an electric circuit works
It is useful to use a model in order to demonstrate how an electric circuit works.
What is a model?In science, a model is a graphical representation that my result useful to predict the behavior of the components of a given system that works together to produce a particular outcome.
For example, an electrical circuit can be modeled by taking into account resistance, voltage, and intensity as parameters of functioning.
The electrical circuits are graphically represented by modeling the movement or flow of negatively charged electrons (e-) from the negative pole to the positive pole of a closed electric circuit.
In conclusion, it is useful to use a model (ie., a scientific model) to demonstrate how an electric circuit works.
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The tires of a car make 68 revolutions as the car reduces its speed uniformly from 85.0 km/h to 56.0 km/h. The tires have a diameter of 0.80 m.
a)What was the angular acceleration of the tires?
Express your answer using two significant figures.
b)If the car continues to decelerate at this rate, how much more time is required for it to stop?
Express your answer to two significant figures and include the appropriate units.
c)If the car continues to decelerate at this rate, how far does it go? Find the total distance.
Express your answer to three significant figures and include the appropriate units.
a) The wheel of the car decelerates at an angular acceleration of - 0.577 radians per square second.
b) The wheel of the car requires a time of 51.149 seconds to stop.
c) The wheel of the car travels a distance of 683.225 meters before stopping.
How to analyze a decelerating rotating wheel
a) In this case we have a rotating wheel that decelerates at constant rate. The angular acceleration, in radians per square second, of the tires is determined by the following formula:
α = [ω'² - ω²] / (2 · θ) (1)
Where:
ω - Initial angular velocity, in radians per second.ω' - Final angular velocity, in radians per second.θ - Change in the angular displacement, in radians.The initial and final angular velocities, in radians per second, are now determined:
ω' = v' / R (2)
ω = v / R (3)
Where:
v - Initial linear velocity, in meters per second.v' - Final linear velocity, in meters per second.R - Radius of the tire, in meters.If we know that R = 0.80 m, v = 23.611 m / s, v' = 15.556 m / s and θ ≈ 427.257 radians, then the angular acceleration of the tire is:
ω' = (15.556 m / s) / (0.80 m)
ω' = 19.445 rad / s
ω = (23.611 m / s) / (0.80 m)
ω = 29.513 rad / s
α = [(19.445 rad / s)² - (29.513 rad / s)²] / [2 · (427.257 rad)]
α = - 0.577 rad / s²
b) The time required to stop the car, in seconds, is determined by the following expression:
t = (ω' - ω) / α (4)
t = (0 rad / s - 29.513 rad / s) / (- 0.577 rad / s²)
t = 51.149 s.
c) First, we find the change in angular displacement of the tire:
θ = [ω'² - ω²] / (2 · α) (5)
θ = [(0 rad / s)² - (29.513 rad / s)²] / [2 · (- 0.577 rad / s²)]
θ = 754.781 rad
Lastly, the distance traveled by the vehicle is:
s = R · θ (6)
s = (0.80 m) · (754.781 rad)
s = 683.825 m
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A uniform linear charge of 3.0 nC/m is distributed along the y axis from y = -3 m to y=2m. Which of the following integrals is correct for the magnitude of the electric field at y = 4 m on the y axis?
[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex] is the integrals for the magnitude of the electric field.
A characteristic of electricity exists at every location in space when charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
The formula for the electric field due to a point charge is:
[tex]E = \frac{kq}{r^2}[/tex]
Here q is the charge, r is the distance from the charge, and k = 8.99 × [tex]10^9 Nm^2/ C^2[/tex]
Imagine an infinitely - tiny portion of this charge distribution that has a charge [tex]dq[/tex]. This charge produces an electric field dE with magnitude:
[tex]\int\limits^ {} \, dE = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]
[tex]E = \int\limits^ {} \, \frac{k dq}{r^2}[/tex]
Here, λ = 3.0 nC/m dq
= λ.dy dE = ∫k.dq
From y = -3 m to y = 2 m, there is a 3.0 nC/m uniform linear charge distributed along the y axis.
The integrals for the magnitude of the electric field at y = 4 m on the y axis:
[tex]E = k \lambda \int\limits^2_{-3} {} \, \frac{dy}{( 4 - y)^2}[/tex]
[tex]E = \int\limits^2_{-3} {} \, \frac{27dy}{( 4 - y)^2}[/tex]
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How do "inner planets" such as: Mercury, Venus, Earth and Mars compare with the "outer planets" such as: Jupiter, Saturn, Uranus and Neptune? Identify three characteristics that differ between these groups of planets.
Answer:
The four inner planets have shorter orbits, slower spin, no rings, and they are made of rock and metal. The four outer planets have longer orbits and spins, a composition of gases and liquids, numerous moons, and rings. The outer planets are made of hydrogen and helium, so they are called gas giants.
Driving space is the space around your car_____
vulnerable to collision.
O
To the side
All of the above
To the rear
To the front
in which you are
Answer:
to the rear as there will be an elastic collision
Driving space is the space around your car to the rear vulnerable to collision. the correct answer is option(c).
Driving space indicates that you have a space or a larger area to drive in that is unrestricted. You see only broad, open spaces on the road ahead and there are no limits around your automobile, so you are free to travel forward or change lanes without encountering any obstacles.
Any driver must have room around their car, preferably in the front, back, and on the sides, in order to react to problems as they arise. Your separation from the car in front of you is the most important distance to leave. Drivers' Speeding Patterns Federal and state organizations that research various elements of speeding have taken notice of speeding as the most frequent cause of deadly collisions. The NHTSA has discovered tendencies among drivers who speed recently.
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