In this problem, you will explore angle bisectors and proportions.

c. Verbal Make a conjecture about the segments of a triangle created by an angle bisector.

In the given situation of describing the likelihood that it will rain tomorrow given that it rained today, the condition is that it rained today. The condition refers to the event or circumstance that is known or assumed to have occurred or is true. In this case, the condition is the occurrence of rain on the current day.

The conditional probability is a measure of the probability of an event happening given that another event has already occurred. In this context, the condition of rain today serves as the basis for assessing the likelihood of rain tomorrow. By considering the occurrence of rain today, we can update our probability estimate for rain tomorrow, taking into account the potential influence or relationship between these two events. The conditional probability provides insights into the dependency or correlation between events, helping us make more informed predictions or assessments based on the available information.

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Answer:

Step-by-step explanation:

d

The first term of the binomial expansion of (e + 3f)⁶ is 6e⁶. The binomial theorem states that the expansion of (a + b)ⁿ is:

aⁿ + nC₁aⁿ⁻¹b + nC₂aⁿ⁻²b² + ... + nCₙ⁻¹abⁿ⁻¹ + bⁿ

where n is the degree of the binomial, a is the first term, and b is the second term.

In this case, the degree of the binomial is 6, the first term is e, and the second term is 3f. Therefore, the first term of the expansion is:

6C₀e⁶ = 6(1)e⁶ = 6e⁶

The number 6C₀ is called a binomial coefficient. It is the number of ways to choose 0 objects from 6 objects. In this case, there is only 1 way to choose 0 objects from 6 objects, so 6C₀ = 1.

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The radius of a circle with an area of 271 square inches is,

⇒ r = 9.3 inches

We have to give that,

An area of a circle is,

A = 271 square inches.

Since We know that,

The area of the circle is,

A = πr²

Where r is the radius of the circle.

Substitute A = 271 square inches in the above formula,

271 = 3.14 × r²

r² = 271 / 3.14

r² = 86.3

r = √86.3

r = 9.3 inches

Therefore, The radius of a circle with an area of 271 square inches is,

⇒ r = 9.3 inches

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To fulfill the request, two tasks need to be completed. First, a classified statement of marks must be prepared, displaying the marks in the correct order and format. Second, the required closing entries should be prepared, including all necessary calculations.

1) To prepare a classified statement of marks, the marks should be organized in the correct order, such as by subject or category. The statement should clearly display the marks achieved by each student, enabling easy comparison and analysis.

2) Closing entries are necessary to transfer temporary account balances to permanent accounts at the end of an accounting period. These entries help ensure that the temporary accounts are reset to zero for the next accounting period. The required closing entries typically involve transferring revenues, expenses, and dividends to the appropriate accounts. Calculations may be required to determine the closing entries, such as calculating net income or determining the dividend amount. These calculations will depend on the specific financial data and accounts involved in the accounting system being used.

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It seems like you're describing an experiment that will compare different combinations of choices for finishing the raw fabric. The experiment will involve using either metal rollers or natural-bristle rollers to raise the fabric's surface, dyeing the fabric for 30 or 40 minutes, and applying a temperature of either 150°C or 175°C.

In this experiment, the goal is to compare the effects of different combinations of choices for finishing raw fabric. The choices include:

Rollers: The experiment will test two types of rollers: metal rollers and natural-bristle rollers. These rollers are used to raise the surface of the fabric.

Dyeing Cycle Time: Two different dyeing cycle times will be evaluated: 30 minutes and 40 minutes. This refers to the duration for which the fabric is subjected to the dyeing process.

Temperature: Two temperature settings will be tested: 150°C and 175°C. These temperatures represent the heat applied during the fabric finishing process.

For each combination of choices, three fabric specimens will be treated accordingly. Once the treatments are completed, the quality of each fabric specimen will be evaluated and scored. This evaluation will likely involve assessing various attributes such as color vibrancy, texture, smoothness, durability, or any other relevant factors that contribute to fabric quality.

By comparing the scores obtained from each treatment combination, the experiment aims to determine which combination of choices yields the best quality fabric. This information can then be used by Fabric Science, the maker of the fabric, to make informed decisions about their fabric finishing processes.

Please let me know if there's anything else you'd like to understand or any further explanation you require!

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The solutions to the equation 4x² + 4x = 22 are x = -0.5 and x = 2.5. We use the quadratic formula to find the solutions and then round them to the nearest hundredth. The final answers are x ≈ -0.50 and x ≈ 2.50.

To solve the equation 4x² + 4x = 22, we can start by rearranging it to the standard form:

4x² + 4x - 22 = 0

Next, we can use the quadratic formula to find the solutions:

x = (-b ± sqrt(b² - 4ac)) / 2a

where a = 4, b = 4, and c = -22. Substituting these values, we have:

x = (-4 ± sqrt(4² - 4(4)(-22))) / 2(4)

x = (-4 ± sqrt(100)) / 8

x = (-4 ± 10) / 8

Simplifying:

x = -0.5 or x = 2.5

Therefore, the solutions to the equation are x = -0.5 and x = 2.5.

Rounding these solutions to the nearest hundredth, we have:

x ≈ -0.50 and x ≈ 2.50.

Therefore, the solutions to the equation rounded to the nearest hundredth are x ≈ -0.50 and x ≈ 2.50.

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Func1(x, y) returns the sum of the original values of x and y. func2(x, y) returns the average of the final values of x and y after swapping. func3(a, b, c) returns the average of the final values of b and c after swapping and averaging.

Break down the meaning of the value returned by each of the three functions:

1. func1(x, y): This function swaps the values of x and y by assigning x the value of y and y the value of x. Finally, it returns the sum of x and y. Therefore, the value returned by func1(x, y) can be described as the sum of the original values of x and y.

2. func2(x, y): This function calls func1(x, y) and assigns the returned value to y. It then calls func1(y, x) and assigns the returned value to x. Next, it calculates z as the difference between x and y. Finally, it returns the average of x and y, which is (x + y) / 2.

The value returned by func2(x, y) can be described as the average of the final values of x and y after the swapping operations.

3. func3(a, b, c): This function calls func2(a, b) and assigns the returned value to c. It then calls func1(a, c) and assigns the returned value to b. Finally, it returns the average of b and c, which is (b + c) / 3. The value returned by func3(a, b, c) can be described as the average of the final values of b and c after the swapping and averaging operations.

In summary, func1(x, y) returns the sum of the original values of x and y. func2(x, y) returns the average of the final values of x and y after swapping. func3(a, b, c) returns the average of the final values of b and c after swapping and averaging.

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The complete question goes thus:

Consider the following confusing functions: def func1(x,y): x=y y=x y=y return (x+y) def func2(x,y): y=func1(x,y) x=func1(y,x) z=x-y return (x+y)/2 def func3(a,b,c): c=func2(a,b) b=func1(a,c) return (b+c)/3 Explain the meaning of the value returned by each of the three functions, assuming that all of the parameters are integers. (For example, you can write something like "func1(x,y) returns x2 - y2". This specific answer will not give you points because it is wrong. But a similar style answer is correct.)

If you deposit $14,000 into an account paying 2.1% interest compounded monthly, you will earn approximately $2,450 in interest after 8 years.

To calculate the interest earned, we can use the formula for compound interest: A = [tex]P(1 + r/n)^(nt)[/tex], where A is the final amount, P is the principal amount (initial deposit), r is the annual interest rate (expressed as a decimal), n is the number of times interest is compounded per year, and t is the number of years.

In this case, the principal amount is $14,000, the annual interest rate is 2.1% (or 0.021 as a decimal), and the interest is compounded monthly, so n = 12. The time period is 8 years.

Plugging these values into the formula, we get:

A = [tex]14000(1 + 0.021/12)^(^1^2^*^8^)[/tex]

Calculating this expression, we find that the final amount after 8 years will be approximately $16,449.55. To determine the interest earned, we subtract the initial deposit from the final amount:

Interest earned = $16,449.55 - $14,000 = $2,449.55.

Rounding this to the nearest dollar, the interest earned after 8 years will be approximately $2,450.

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The dimensions that minimizes the total cost are 2√2 meters by 1 meter

From the question, we have the following parameters that can be used in our computation:

Volume = 8

Base = square

Base = x

So, the volume is

V = x²h

This gives

x²h = 8

The surface area is calculated as

A = x² + 4xh

This means that the total cost is

C = 2x² + 4xh

Make h the subject in x²h = 8

h = 8/x²

So, we have

C = 2x² + 4x * 8/x²

C = 2x² + 32/x

Differentiate and set to 0

4x - 32/x = 0

So, we have

4x = 32/x

4x² = 32

x² = 8

Differentiate

x = 2√2

Recall that

h = 8/x²

So, we have

h = 8/8

h = 1

Hence, the dimensions are base length of 2√2 meters and a height is 1 meter

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Answer:

Answer: a = 15/2 ,

Step-by-step explanation:

Subtract 21 from both sides  16a+21 = 20a-9

16a + 21 -21=- 20a- 9 -21

Simplify the expression

16a + 21 -21=- 20a- 9 -21

16a=20a -30

Subtract 20a from both sides

16a=20a -30

16a - 20a = 20a -30 - 20a

Solution

a = 15/2

In this scenario, a player can place a bet of $4.00 on the outcome of rolling two dice. If the sum of the roll is 7, the player wins $1600, otherwise, they lose $4.00.

To analyze the possible outcomes of rolling two dice, we need to consider all the combinations of numbers that can appear on each die. Each die has six sides, numbered from 1 to 6. When rolling two dice, we can have a total of 36 different outcomes (6 possibilities for the first die multiplied by 6 possibilities for the second die).

Now, we need to determine the sum of each pair of numbers. For example, if the first die shows a 1 and the second die shows a 6, the sum is 7. We can list all the possible outcomes and their corresponding sums:

(1, 1) - Sum: 2

(1, 2) - Sum: 3

(1, 3) - Sum: 4

(1, 4) - Sum: 5

(1, 5) - Sum: 6

(1, 6) - Sum: 7

(2, 1) - Sum: 3

(2, 2) - Sum: 4

(6, 6) - Sum: 12

Out of these 36 outcomes, there are six combinations that result in a sum of 7. These combinations are: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1). If the sum is 7, the player wins $1600, and if the sum is any other number, the player loses $4.00.

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The relationship between <2 and <4 is Corresponding angle.

1 . Transversal S, Corresponding Angles

2. Transversal R, Same Side Interior Angles

3. Transversal T, Alternate Interior Angles

4. Transversal V, Corresponding Angles

5. Transversal T, Alternate Exterior Angles

6. Transversal S, Alternate Interior Angles

7. Transversal T, Same Side Interior Angles

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Simplifying rational expressions is similar to simplifying fractions in that both processes involve reducing the expression to its simplest form. Both rational expressions and fractions involve division, and the goal is to simplify and make the expression or fraction easier to work with or understand.

Similarities:

Common Factors: Both in rational expressions and fractions, you look for common factors in the numerator and denominator. By canceling out these common factors, you simplify the expression.

Division: Both rational expressions and fractions involve division. In fractions, you divide the numerator by the denominator to get the value. In rational expressions, you divide the polynomials in the numerator and denominator.

Differences:

Variables: Rational expressions often involve variables, whereas fractions typically involve numbers. Variables in rational expressions can represent unknown quantities, allowing for more general expressions.

Polynomials: Rational expressions may involve polynomials in the numerator and denominator, whereas fractions usually involve integers or decimals. Simplifying rational expressions requires factoring and canceling out common factors among the polynomials.

Domain Restrictions: Rational expressions can have domain restrictions due to values that make the denominator equal to zero. These restrictions need to be considered when simplifying rational expressions to ensure that the simplified expression is valid within its domain.

In summary, simplifying rational expressions is similar to simplifying fractions in terms of finding common factors and reducing the expression to its simplest form. However, rational expressions involve variables, polynomials, and domain restrictions, which make the simplification process more complex compared to fractions that typically involve numbers.

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The value of x in the given equation is 6.

We are given that;

The equation ln x + ln 2=6

Now,

We can solve the equation ln x + ln 2 = 6 using the properties of logarithms.

The property we will use is:

log a + log b = log ab

Using this property, we can rewrite the equation as:

ln (x * 2) = 6

Now we can solve for x by taking the exponential of both sides:

e^(ln (x * 2)) = e^6

Simplifying the left side using the inverse of the natural logarithm:

x * 2 = e^6

Dividing both sides by 2:

x = e^6 / 2

Using a calculator to evaluate e^6 / 2, we get:

x ≈ 6

Therefore, by logarithm the answer will be 6.

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The discriminant of equation qx² + rx + s = 0 is  r² - 4qs. Option c is correct.

The discriminant of the quadratic equation qx² + rx + s = 0 is given by the expression b² - 4ac, where a, b, and c are the coefficients of the quadratic equation.

In this case, the coefficients are:

a = q

b = r

c = s

Therefore, the discriminant is:

b² - 4ac = r² - 4qs

Hence, the  discriminant of qx² + rx + s = 0 is  r² - 4qs.

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Answer:

Yes

Step-by-step explanation:
f(x) = 5x^4 - 2x^3 + 3x - 2 + 1 is a polynomial function.Polynomial functions are functions that can be expressed as the sum of power functions in the form f(x) = aₙxⁿ + aₙ₋₁xⁿ⁻¹ + ... + a₁x + a₀, where n is a non-negative integer and a is a constant coefficient.

In this case, the function f(x) is a polynomial function of degree 4 because the highest power of x in the function is 4. The coefficients of the function are also constants, which means that this function satisfies the definition of a polynomial function.

Therefore, we can conclude that f(x) = 5x^4 - 2x^3 + 3x - 2 + 1 is a polynomial function.

Answer:

4.19

Step-by-step explanation:

5^2=25

7^2= 49

25+49=74

The cube root of 74 is 4.19

Function of a pencil: A pencil is a writing instrument used for creating marks on paper or other surfaces by applying graphite or a similar substance to leave a visible trace.

A pencil serves as a versatile tool for writing, drawing, and sketching. It consists of a cylindrical wooden casing that holds a graphite core, which is responsible for leaving marks on surfaces. The function of a pencil is to provide a convenient and easily controllable instrument for making various types of marks. Whether used for writing notes, solving mathematical equations, or creating intricate drawings, a pencil offers precision and flexibility to the user.

One of the key advantages of using a pencil is the ability to erase and correct mistakes. Unlike pens, which often leave permanent marks, pencils allow for erasure using an eraser located at the end of the instrument. This feature makes pencils ideal for tasks that require frequent revisions or adjustments.

Pencils are widely used in educational settings, offices, art studios, and everyday life. They are essential tools for students, professionals, artists, and individuals of all ages. Pencils are inexpensive, portable, and do not require any additional equipment to operate. Additionally, they come in various hardness grades, ranging from soft to hard, which allows users to adjust the darkness and texture of their marks.

In summary, the function of a pencil is to provide a reliable, versatile, and easily erasable tool for writing, drawing, and sketching on different surfaces.

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When all three dimensions of a prism are tripled, the surface area increases by a factor of 18.

When all three dimensions of a prism (length, width, and height) are tripled, the surface area of the prism will change. Let's consider a rectangular prism as an example.

The surface area of a rectangular prism is given by the formula 2lw + 2lh + 2wh, where l, w, and h are the dimensions of length, width, and height, respectively.

If all three dimensions are tripled, the new dimensions would be 3l, 3w, and 3h. Substituting these values into the formula, we get:

New surface area = 2(3l)(3w) + 2(3l)(3h) + 2(3w)(3h)

= 18lw + 18lh + 18wh

As we can see, each term in the formula has been multiplied by a factor of 18. Therefore, the new surface area is 18 times the original surface area.

When all three dimensions of a prism are tripled, the surface area increases by a factor of 18.

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The solutions to the equation are t = 0.36 and t = -1.2. Since t is the time in hours, we can't have a negative time, so the time when the bacteria count reaches 591 is **t = 0.36 hours**.

The composite function N(T(t)) is the function that takes the time t as input and returns the number of bacteria in the food product at that time.

The time when the bacteria count reaches 591:

To find the time when the bacteria count reaches 591, we can set the composite function N(T(t)) to 591 and solve for t.

N(T(t)) = 591

=> 25(5t + 1.8)² - 87(5t + 1.8) + 61.3 = 591

=> 625t² + 225t - 263 = 0

=> (25t - 9)(25t + 3) = 0

```

The solutions to the equation are t = 0.36 and t = -1.2. Since t is the time in hours, we can't have a negative time, so the time when the bacteria count reaches 591 is **t = 0.36 hours**.

The composite function N(T(t)) is found by first evaluating the function T(t) and then evaluating the function N(x) at the output of T(t). In this case, the function T(t) takes the time t as input and returns the temperature of the food product at that time. The function N(x) takes the temperature x as input and returns the number of bacteria in the food product at that temperature.

To find the time when the bacteria count reaches 591, we can set the composite function N(T(t)) to 591 and solve for t. This gives us the equation 625t² + 225t - 263 = 0. We can solve this equation to find the solutions t = 0.36 and t = -1.2. Since t is the time in hours, we can't have a negative time, so the time when the bacteria count reaches 591 is **t = 0.36 hours**.

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The sentence "A rectangle is not always a parallelogram" is false. Hence, a rectangle is always a parallelogram

A rectangle is a special type of parallelogram. All rectangles have four right angles, while not all parallelograms have four right angles. Therefore, all rectangles are parallelograms, but not all parallelograms are rectangles.

To make the sentence true, we would need to replace the word "not" with "always". The correct sentence would be: A rectangle is always a parallelogram .

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The polynomial function in standard form with the given zeros x = 5, 6, and 7 is:

f(x) = x^3 - 18x^2 + 107x - 210

To write a polynomial function in standard form with the given zeros x = 5, 6, and 7, we use the fact that if a value x is a zero of a polynomial function, then (x - a) is a factor of the polynomial, where a is the zero.

Using this information, we can construct the polynomial function as follows:

Since the zeros are x = 5, 6, and 7, the factors of the polynomial are (x - 5), (x - 6), and (x - 7).

To obtain the polynomial function, we multiply these factors together:

f(x) = (x - 5)(x - 6)(x - 7)

Expanding this expression, we get:

f(x) = (x^2 - 11x + 30)(x - 7)

Now, let's multiply further:

f(x) = (x^2 - 11x + 30)(x) - 7(x^2 - 11x + 30)

Expanding again:

f(x) = x^3 - 11x^2 + 30x - 7x^2 + 77x - 210

Combining like terms:

f(x) = x^3 - 11x^2 - 7x^2 + 30x + 77x - 210

Simplifying:

f(x) = x^3 - 18x^2 + 107x - 210

Therefore, the polynomial function in standard form with the given zeros x = 5, 6, and 7 is:

f(x) = x^3 - 18x^2 + 107x - 210

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The expression (n²/³ ÷ n⁻¹/⁶)⁻³ is equivalent to n^(-20). Using the rules of exponents, we simplify the expression to n^(-2^2*5) or n^(-2*10). The equivalent expression is (h) n⁻⁴.

To simplify the expression (n²/³ ÷ n⁻¹/⁶)⁻³, we can use the rule:

(a ÷ b)^n = a^n ÷ b^n

Substituting the given values, we have:

(n²/³ ÷ n⁻¹/⁶)⁻³ = (n²/³ × n⁶/¹)⁻³ = n^(2/3 + 6/1)⁻³ = n^(20/3)⁻³

To simplify this expression further, we can use the rule:

a^(-n) = 1 / a^n

Substituting the given value, we have:

n^(20/3)⁻³ = 1 / n^((20/3) × 3) = 1 / n^20

Therefore, the given expression is equivalent to n^-20, which is the same as n^(-2*10) or n^(-2^2*5).

The answer is (h) n⁻⁴.

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The probability of answering a question correctly if you make a random guess 1/4. The probability of answering correctly after given situation is 1/3.

a) If there are four possible answers for each question and you make a random guess, the probability of answering a question correctly is 1 out of 4, or 1/4. This is because there is only one correct answer out of the four choices.

b) If you are able to eliminate one of the answer choices, the probability of answering correctly increases. With three answer choices remaining, the probability of guessing the correct answer is 1 out of 3, or 1/3. This is because there is only one correct answer out of the three remaining choices. By eliminating one incorrect choice, you have improved your odds of guessing the correct answer.

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The probability that a student chosen at random is taking Spanish, French, or Mandarin Chinese is 36%.

To calculate the probability that a student chosen at random is taking Spanish, French, or Mandarin Chinese, we need to know the percentages of students taking each language.

Let's assume that the percentages of students taking Spanish and French are given as well. For example, let's say the percentage of students taking Spanish is 15% and the percentage of students taking French is 12%.

To find the probability of a student taking Spanish, French, or Mandarin Chinese, we can add up the individual probabilities of each event occurring. Since the events are mutually exclusive (a student cannot be taking multiple languages simultaneously), we can simply sum up the probabilities.

Probability(Spanish) = 15%

Probability(French) = 12%

Probability(Mandarin Chinese) = 9%

To find the probability that a student chosen at random is taking Spanish, French, or Mandarin Chinese, we add up these probabilities:

Probability(Spanish or French or Mandarin Chinese) = Probability(Spanish) + Probability(French) + Probability(Mandarin Chinese)

= 15% + 12% + 9%

= 36%

Therefore, the probability that a student chosen at random is taking Spanish, French, or Mandarin Chinese is 36%.

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The fine amount for a speed of 50 mph would be $235. the fine amount for a given speed (s) in North Washington, taking into account the excess speed over the limit and a base fine.

In a North Washington country, the formula to determine speeding fines is given by f(s) = 13(s - 35) + 40. Let's break down the formula and understand its components.

The formula represents the relationship between the fine amount (f) and the speed of the vehicle (s). The speed of the vehicle is denoted by the variable s.

The term (s - 35) represents the difference between the speed of the vehicle and the speed limit. By subtracting 35 from the speed of the vehicle, we obtain the excess speed over the limit.

Multiplying the excess speed by 13 indicates that the fine increases by $13 for every unit of excess speed over the limit.

Adding 40 to the product of 13(s - 35) ensures that there is a base fine amount, even if the excess speed is zero. The constant term of 40 represents this base fine.

Therefore, the formula f(s) = 13(s - 35) + 40 calculates the fine amount for a given speed (s) in North Washington, taking into account the excess speed over the limit and a base fine.

To determine the specific fine amount for a particular speed, substitute the speed value into the formula. For example, if the speed of the vehicle is 50 mph:

f(50) = 13(50 - 35) + 40

      = 13(15) + 40

      = 195 + 40

      = 235

In this case, the fine amount for a speed of 50 mph would be $235.

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A polynomial is an algebraic expression consisting of variables and coefficients, combined using addition, subtraction, and multiplication operations. It is a mathematical expression that represents a function of one or more variables. The polynomial x⁴ - 4x³ - 5x² can be factored as follows:

x⁴ - 4x³ - 5x² = x²(x² - 4x - 5).

To factor the quadratic expression x² - 4x - 5, we look for two numbers whose product is -5 and whose sum is -4. The numbers -5 and 1 satisfy these conditions, so we can write the quadratic expression as:

x² - 4x - 5 = (x - 5)(x + 1)

Therefore, the polynomial x⁴ - 4x³ - 5x² can be factored as:

x⁴ - 4x³ - 5x² = x²(x - 5)(x + 1)

To check if the factoring is correct, we can multiply the factors together:

x²(x - 5)(x + 1) = x²(x² + x - 5x - 5) = x²(x² - 4x - 5)

Expanding further:

x²(x² - 4x - 5) = x⁴ - 4x³ - 5x²

The factored form matches the original polynomial, so we can conclude that the factoring is correct.

In summary, the polynomial x⁴ - 4x³ - 5x² can be factored as x²(x - 5)(x + 1). This factoring can be verified by multiplying the factors together, which yields the original polynomial.

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The function y = 3x(x + 2)³ has two zeros: x = 0 (with multiplicity 1) and x = -2 (with multiplicity 3). The multiplicity of a zero represents the number of times that zero appears as a root of the function.

To find the zeros of the function, we set y equal to zero and solve for x. In this case, we have: 3x(x + 2)³ = 0

Since the product of factors is zero, we can set each factor equal to zero and solve for x:

1) Setting x = 0, we get 3(0)(0 + 2)³ = 0, which gives us a zero at x = 0 with multiplicity 1.

2) Setting x + 2 = 0, we have 3x(0)³ = 0, which also gives us a zero at x = -2. Since it is raised to the power of 3, it has a multiplicity of 3.

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None of the options are correct based on the calculations.

Annual savings amounts: $830, $1,010, $600

Interest rate: 3.2%

Number of years: 3

FV = PV * (1 + r)^n

FV is the future value

PV is the present value (savings amount)

r is the interest rate

n is the number of years

Year 1:

FV1 = $830 * (1 + 0.032)^1 = $855.76

Year 2:

FV2 = $1,010 * (1 + 0.032)^2 = $1,061.34

Year 3:

FV3 = $600 * (1 + 0.032)^3 = $639.07

Total future value = FV1 + FV2 + FV3

Total future value = $855.76 + $1,061.34 + $639.07

Using a calculator, we find that the total future value is approximately $2,556.17.

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