(c2−4c+7) -(7c2−5c+3).

Step-by-step explanation:

6/10 > _ > 1/3

3/5 > _ > 1/3

½(⅗+⅓)

½(9+5/15)

½(14/5)

=7/15

Answer:

7/15

Step-by-step explanation: 10 and 3 LCM is 30

6/10 x 3 =18/30 and 1/3x 10= 10/30

10/30 and 18/30 average is 14/30 which simplified is 7/15

The answer is 7/15

Hope it helps

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { A. \:2 \sqrt{30} }}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}[/tex]

[tex] = \sqrt{3} \times \sqrt{8} \times \sqrt{5} [/tex]

[tex] = \sqrt{3 \times 2 \times 2 \times 2 \times 5} [/tex]

[tex] = \sqrt{ ({2})^{2} \times 2 \times 3 \times 5} [/tex]

[tex] = 2 \sqrt{2 \times 3\times 5} [/tex]

[tex] = 2 \sqrt{30} [/tex]

[tex] \sqrt{ ({a})^{2} } = a[/tex]

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

Answer:

A. 2√30

Step-by-step explanation:

[tex] \small \sf \: \sqrt{3} \times \sqrt{8} \times \sqrt{5} \\ [/tex]

split √8

[tex] \small \sf \leadsto \sqrt{3 × 2 × 2 × 2 × 5} [/tex]

[tex] \small \sf \leadsto \: 2 \sqrt{2 \times 3 \times 5} [/tex]

[tex] \small \sf \leadsto \: 2 \sqrt{30} [/tex]

Answer:

The possible values are a = -2.5 or a = 4.5.

Step-by-step explanation:

Composite function:

The composite function of f(x) and g(x) is given by:

[tex](f \circ g)(x) = f(g(x))[/tex]

In this case:

[tex]f(x) = 4x^2 - 8x - 20[/tex]

[tex]g(x) = 2x + a[/tex]

So

[tex](f \circ g)(x) = f(g(x)) = f(2x + a) = 4(2x + a)^2 - 8(2x + a) - 20 = 4(4x^2 + 4ax + a^2) - 16x - 8a - 20 = 16x^2 + 16ax + 4a^2 - 16x - 8a - 20 = 16x^2 +(16a-16)x + 4a^2 - 8a - 20[/tex]

Value of a so that the y-intercept of the graph of the composite function (fog)(x) is (0, 25).

This means that when [tex]x = 0, f(g(x)) = 25[/tex]. So

[tex]4a^2 - 8a - 20 = 25[/tex]

[tex]4a^2 - 8a - 45 = 0[/tex]

Solving a quadratic equation, by Bhaskara:

[tex]\Delta = (-8)^2 - 4(4)(-45) = 784[/tex]

[tex]x_{1} = \frac{-(-8) + \sqrt{784}}{2*(4)} = \frac{36}{8} = 4.5[/tex]

[tex]x_{2} = \frac{-(-8) - \sqrt{784}}{2*(4)} = -\frac{20}{8} = -2.5[/tex]

The possible values are a = -2.5 or a = 4.5.

Answer:

The amount of the loan is going to be $ 182,700, and the monthly payments, if the interest is 6%, are going to be $ 537.95, while if the interest is 7%, are going to be $ 543.02.

Step-by-step explanation:

Given that you want to buy a $ 203,000 home, and you plan to pay 10% as a down payment, and take out a 30 year loan for the rest, for A) determine how much is the loan amount going to be, B) determine what will your monthly payments be if the interest rate is 6%, and C) determine what will your monthly payments be if the interest rate is 7%, the following calculations must be made:

A) 100 - 10 = 90

203,000 x 0.90 = X

182,700 = X

B) (182,700 x 1.06) / (30 x 12) = X

193,662 / 360 = X

537.95 = X

C) (182,700 x 1.07) / (30 x 12) = X

195,489 / 360 = X

543.025 = X

Therefore, the amount of the loan is going to be $ 182,700, and the monthly payments, if the interest is 6%, are going to be $ 537.95, while if the interest is 7%, are going to be $ 543.02.

Answer:

a)  [tex]h=286.8ft[/tex]

b)  [tex]\frac{dh}{dt}=5.7ft/s[/tex]

Step-by-step explanation:

From the question we are told that:

Angle [tex]\theta=35[/tex]

a)

Slant height [tex]h_s=500ft[/tex]

Generally the trigonometric equation for Height is mathematically given by

[tex]h=h_ssin\theta[/tex]

[tex]h=500sin35[/tex]

[tex]h=286.8ft[/tex]

b)

Rate of release

[tex]\frac{dl}{dt}=10ft/sec[/tex]

Generally the trigonometric equation for Height is mathematically given by

[tex]h=lsin35[/tex]

Differentiate

[tex]\frac{dh}{dt}=\frac{dl}{dt}sin35[/tex]

[tex]\frac{dh}{dt}=10sin35[/tex]

[tex]\frac{dh}{dt}=5.7ft/s[/tex]

Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the vertices of the triangle are not given.

A general explanation is as follows;

To calculate distance between two points, we use:

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

Take for instance;

[tex]A = (1,4)[/tex]

[tex]B = (3,-2)[/tex]

Distance AB is:

[tex]AB = \sqrt{(1 - 3)^2 + (4 - -2)^2}[/tex]

[tex]AB = \sqrt{(- 2)^2 + (4 +2)^2}[/tex]

[tex]AB = \sqrt{(- 2)^2 + (6)^2}[/tex]

Evaluate the exponents

[tex]AB = \sqrt{4 + 36}[/tex]

[tex]AB = \sqrt{40}[/tex]

[tex]AB = 6.32[/tex]

Answer:

for edmentum

Step-by-step explanation:

Answer:

Step-by-step explanation:

I have this saved on my computer in notepad b/c this type of question get asked sooo often :/

point P1 (-4,-2)  in the form (x1,y1)

point P2(3,1)  in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

My suggestion is copy that above and save it on your computer for questions like this

now use it

Point 1  , P1 = (2,-4)   in the form (x1,y1)

Point 2 , P2 = (4,-1)  in the form (x2,y2)

m = [ -1-(-4) ]  /  [ 4-2]

m =  (-1+4) / 2

m = 3 / 2

so now we know the slope is  3/2  :)  

Answer:

Step-by-step explanation:

The only mistake is in the last line. You need to replace the y by x, So:

f-1(x) = (x - 4)/-8

It's usual to put the negative on the top so it becomes

-(x -4)/8

- and we can simplify this a bit more to give

f-1(x) = (4 - x)/5

Answer:

The z-score for the trainee is of 2.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of the test scores is 72 with a standard deviation of 5.

This means that [tex]\mu = 72, \sigma = 5[/tex]

Find the z-score for a trainee, given a score of 82.

This is Z when X = 82. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{82 - 72}{5}[/tex]

[tex]Z = 2[/tex]

The z-score for the trainee is of 2.

Answer:

equation : y= -6 + 1

Step-by-step explanation:

Answer:

-3072

Step-by-step explanation:

[tex] cos(A) = \frac{ {b}^{2} + {c}^{2} - {a}^{2} }{2bc} [/tex]

The cos A will be b/c

Cosine function in a triangle is the ratio of the adjacent side to that of the hypotenuse

The steps are as follow:

AB = c

BC = a

AC = b

Cos A = Adjacent side to A / Hypoteneous

Cos A = AC / AB

Cos A = b / c

Therefore the value of Cos A in given figure will be b / c

Learn more about Cosine function here:

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Answer:

1/2

Step-by-step explanation:

Convert 2/3 to 4/6

Subtract: 4/6 - 1/6

You get 3/6

Simplify: 1/2

Hope this helps!

Answer: The answer is 1/2

Hello!

log₃(x) + log₃(x - 6) = log₃(7) <=>

<=> log₃(x * (x - 6)) = log₃(7) <=>

<=> log₃(x² - 6x) = log₃(7) <=>

<=> x² - 6x = 7 <=>

<=> x² - 6x - 7 = 0 <=>

<=> x² + x - 7x - 7 = 0 <=>

<=> x * (x + 1) - 7 * (x + 1) = 0 <=>

<=> (x + 1) * (x - 7) = 0 <=>

<=> x + 1 = 0 and x - 7 = 0 <=>

<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>

<=> x = 7

Good luck! :)

Answer:

363,000,000

..........

Answer:

A seems to be correct

Step-by-step explanation:

Answer:

b) Then z(s) is in the rejection region for H₀. We reject H₀. The p-value is smaller than α/2

c)CI 95 %  =  ( 0.00002 ;  0.09998)

Step-by-step explanation: In both cases, the size of the samples are big enough to make use of the approximation of normality of the difference of the proportions.

Recent Sample

Sample size    n₁  =  1000

Number of events of people with financial fitness more than fair

x₁  =  410

p₁ =  410/ 1000  =  0.4     then q₁ = 1 - p₁    q₁ =  1 -  0.4    q₁  = 0.6

Sample a year ago

Sample size    n₂ =  1200

Number of events of people with financial fitness more than fair

x₂  =  420

p₂  =  420/1200     p₂ = 0.35   q₂  =  1 - p₂    q₂  = 1 - 0.35   q₂ = 0.65

Test Hypothesis

Null Hypothesis                                  H₀              p₁  =  p₂

Alternative Hypothesis                      Hₐ              p₁  ≠  p₂

CI  95 % then significance level  α  =  5%   α  = 0.05    α/2  = 0.025

To calculate p-value:

SE  =  √ (p₁*q₁)/n₁  +  (p₂*q₂)/n₂

SE  =  √ 0.4*0.6/1000 +  0.65*0.35/1200

SE  =  √ 0.00024 + 0.000189

SE = 0.021

z(s) =  ( p₁ - p₂ ) / SE

z(s) = ( 0.4 - 0.35 )/0.021

z(s) = 0.05/ 0.021

z(s) =  2.38

We find p-value from z-table to be   p-value = 0.00842

Comparing

p-value with  α/2   = 0.025

α/2 >  p-value  

Then z(s) is in the rejection region for H₀. We reject H₀

CI 95 %  =  ( p₁  -  p₂ )  ±  2.38*SE

CI 95 %  =  ( 0.05 ± 2.38*0.021 )

CI 95 %  =  ( 0.05 ± 0.04998)

CI 95 %  =  ( 0.00002 ;  0.09998)

CI 95 % does not contain the 0 value affirming what the hypothesis Test already demonstrate

Answer:

6/7

Step-by-step explanation:

7 days make a week. 7 would go into the denominator and 6 would go in the numerator. 6 is the amount of days through the week that it is dry.

Answer:

6/7

Step-by-step explanation:

[tex]\frac{number \ of \ dry \ days}{total \ number \ of \ days \ in \ a \ week} =\frac{6}{7}[/tex]

Answer:

Step-by-step explanation:

This is a related rates problem from calculus using implicit differentiation. The main equation is going to be Pythagorean's Theorem and then the derivative of that. Pythagorean's Theorem is

[tex]x^2+y^2=c^2[/tex] where c is the hypotenuse and is a constant. Therefore, the derivative of this with respect to time, and using implicit differentiation is

[tex]2x\frac{dx}{dt}+2y\frac{dy}{dt}=0[/tex] and dividing everything by 2 to simplify a bit:

[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex]. Upon analyzing that equation, it looks like we need values for x, y, [tex]\frac{dx}{dt}[/tex], and [tex]\frac{dy}{dt}[/tex]. And here's what we were given:

[tex]\theta=45[/tex] and [tex]\frac{dx}{dt}=.5[/tex]  In the greater realm of things, that's nothing at all.

BUT we can use the right triangle and the angle we were given to find both x and y. The problem we are looking to solve is to

Find [tex]\frac{dy}{dt}[/tex] at the instant that [tex]\frac{dx}{dt}[/tex] = .5.

Solving for x and y:

[tex]tan45=\frac{x}{6}[/tex] and

6tan45 = x ( and since this is a 45-45-90 triangle, y = x):

[tex]6(\frac{\sqrt{2} }{2})=x=y[/tex] so

[tex]x=y=3\sqrt{2}[/tex] and now we can fill in our derivative. Remember the derivative was found to be

[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex] so

[tex]3\sqrt{2}(\frac{1}{2})+3\sqrt{2}\frac{dy}{dt}=0[/tex] and

[tex]\frac{3\sqrt{2} }{2}+3\sqrt{2} \frac{dy}{dt}=0[/tex] and

[tex]3\sqrt{2}\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}[/tex] and multiplying by the reciprocal of the left gives us:

[tex]\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}(\frac{1}{3\sqrt{2} })[/tex] so

[tex]\frac{dy}{dt}=-\frac{1}{2}\frac{m}{s}[/tex]

Answer:

triangle KLM

Step-by-step explanation:

x-1 meaning subtractikn so u subtract l from its original x cord making it move left 1

y-8 same thing but for the y making it move down 8 spaces

Answer:

option a.

[tex] + - \frac{13}{5} [/tex]

Step-by-step explanation:

[tex]25x^2\: - \:169 = 0 [/tex]

[tex]25x^2 = 169[/tex]

[tex] {x}^{2} = \frac{169}{25} [/tex]

[tex]x = + - \sqrt{ \frac{169}{25} } [/tex]

[tex]x = + - \frac{13}{5} [/tex]

Answer:

4th option

Step-by-step explanation:

tanZ = [tex]\frac{opposite}{adjacent }[/tex] = [tex]\frac{XY}{ZY}[/tex]

Answer:

We reject the Null and conclude that There is significant evidence that the slope values are greater than 0.

Step-by-step explanation:

Based on the ANOVA output given :

The F critical value can be obtained thus ;

F(df regression, df error)

Using an α-value of 0.01

F(2, 12) at α = 0.01 is 6.927

The F statistic as obtained from the ANOVA table = 134.65

Since, F statistic > F critical we reject the Null and conclude that slope values are significantly > 0

Similarly,

Using the Pvalue :

The Pvalue of the slope are extremely small :

Viscosity <0.0001

Load <0.0001

At α = 0.01, 0.025

The Pvalue < α ; The null will be rejected.

Answer:

how accurate the statistic is when using it to estimate the parameter.

Step-by-step explanation:

The margin of error may be referred to as a range or interval around a calculated statistic. The margin of error usually employed when calculating the confidence interval, will give a certain range of value within the sample statistic. This is sample statistic and margin is used to estimate the parameter albeit a certain percentage or proportion within the sample statistic. This provides the accuracy level at which the statistic will estimate the parameter.

Margin of Error :

Margin of Error = Zcritical * σ/√n ; OR

Margin of Error = Tcritical * s/√n

Where ;

σ = population standard deviation

s = sample standard deviation

Answer:

30

Step-by-step explanation:

The given is right triangle with angle measure 90-60 and 30 degrees as we can see on the image.

Answer:

Let's solve for k.

x2−y2=k

Step 1: Flip the equation.

k=x2−y2

Answer:

k=x2−y2

Step-by-step explanation:

Given:

The number 55 is attached to a two-digit number to its left and the formed 4-digit number is divisible by 24.

To find:

The 2-digit numbers.

Solution:

Let the two digit number be [tex]ab[/tex]. Then the 4 digit number will be [tex]55ab[/tex].

We know that the number [tex]55ab[/tex] lies in the range 5500 to 5599.

Now,

[tex]5500=229\times 24+4[/tex]

It means, [tex]5500-4=5496[/tex] is divisible by 24. So, the numbers lie in the range 5500 to 5599 and divisible by 24 are:

[tex]5496+24=5520[/tex]

[tex]5520+24=5544[/tex]

[tex]5544+24=5568[/tex]

[tex]5568+24=5592[/tex]

Therefore, the possible 2-digit numbers are 20, 44, 68, 92.

The limit of the difference quotient of the above function [tex]f(x)[/tex] at [tex]x=3[/tex] is [tex]3[/tex] such that [tex]f(x)=x^{3} - 4x^{2} + 2[/tex].

The difference quotient of a function [tex]f(x)[/tex] is [tex]\frac{f(x+h)-f(x)}{h}[/tex].

The given equation is, [tex]f(x)=x^{3} -4x^{2} +2[/tex]

So, [tex]f(x+h)=(x+h)^{3} -4(x+h)^{2} +2= x^{3} +h^{3}+3x^{2} h+3xh^{2} -4x^{2} -4h^{2} -8xh+2[/tex]

Now, [tex]f(x+h)-f(x)[/tex]

[tex]=x^{3}+h^{3}+3x^{2}h+3xh^{2}-4x^{2}-4h^{2}-8xh+2-x^{3}+4x^{2}-2[/tex]

[tex]=h^{3}+3x^{2}h+3xh^{2}-4h^{2}-8xh[/tex]

So, [tex]\frac{f(x+h)-f(x)}{h} =\frac{h^{3}+3x^{2}h+3xh^{2} -4h^{2}-8xh }{h}[/tex]

[tex]=h^{2}+3x^{2}+3xh-4h-8x[/tex]

Now, at [tex]x=3[/tex],

[tex]h^{2}+3x^{2}+3xh-4h-8x=h^{2}+27+9h-4h-24=h^{2}+5h+3[/tex]

If   [tex]h[/tex]→[tex]0[/tex], the value of [tex]h^{2}+5h+3=3[/tex]

Thus, the limit of the difference quotient of the above function [tex]f(x)[/tex] at [tex]x=3[/tex] is [tex]3[/tex].

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Answer:

The probability that the proportion of persons with a retirement account will be less than 57%=31.561%

Step-by-step explanation:

We are given that

n=570

p=58%=0.58

We have to find the probability that the proportion of persons with a retirement account will be less than 57%.

q=1-p=1-0.58=0.42

By takin normal approximation to binomial  then sampling distribution of sample proportion  follow normal distribution.

Therefore,[tex]\hat{p}\sim N(\mu,\sigma^2)[/tex]

[tex]\mu_{\hat{p}}=p=0.58[/tex]

[tex]\sigma_{\hat{p}}=\sqrt{\frac{p(1-p)}{n}}[/tex]

[tex]\sigma_{\hat{p}}=\sqrt{\frac{0.58\times 0.42}{570}}[/tex]

[tex]\sigma_{\hat{p}}=0.02067[/tex]

Now,

[tex]P(\hat{p}<0.57)=P(\frac{\hat{p}-\mu_{\hat{p}}}{\sigma_{\hat{p}}}<\frac{0.57-0.58}{0.02067})[/tex]

[tex]P(\hat{p}<0.57)=P(Z<-0.483)[/tex]

[tex]P(\hat{p}<0.57)=0.31561\times 100[/tex]

[tex]P(\hat{p}<0.57)[/tex]=31.561%

Hence,  the probability that the proportion of persons with a retirement account will be less than 57%=31.561%