q or heat transfer when 5.88 g of ice is cooled from -21 °c to -118 °c is
1171J.
The equation q = mLΔT is used to calculate the heat transfer, or q, in a thermodynamic process. The equation states that the heat transfer, q, is equal to the product of the mass, m, of the substance being heated or cooled, its specific heat capacity, L, and the change in temperature, ΔT.
The specific heat capacity, L, is a measure of the amount of heat required to raise the temperature of one kilogram of a substance by one degree Celsius. It is a constant value for a given substance and depends on its molecular structure and physical properties.
The change in temperature, ΔT, is the difference between the initial and final temperatures of the substance, and it represents the amount of temperature change that has occurred during the process.
Therefore, the equation q = mLΔT can be used to determine the amount of heat transfer that occurs when a substance is heated or cooled, by multiplying its mass, specific heat capacity, and the change in temperature. The units of heat transfer are typically joules (J).
In this case, q = (5.88 g)(2.09 J/g°C)(-118°C - (-21°C))
q = (5.88 g)(2.09 J/g°C)(97°C)
q = 1171 J
So the heat transfer, q, is 1171 J.
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any three-dimensional rigid object has a center of gravity. this is a point that gives the average location of the mass. why does it matter?
The center of gravity of a three-dimensional rigid object is an important concept in physics and engineering for several reasons like stability, Dynamics, Design, Lifting and handling, etc.
Stability: The CoG of an object determines its stability. An object is considered stable if its CoG is located above its support base. If the CoG is not located above the support base, the object is considered unstable.
Dynamics: The CoG is used in the study of the dynamics of objects in motion. The CoG of an object is used to determine the forces and their reactions to those forces.
Design: in the design of objects, especially in engineering the location of the CoG can affect the stability, balance, and efficiency of an object, and it is often optimized during the design process.
Lifting and Handling: The CoG is used to determine the best way to lift and handle an object. If the CoG is known, it is easier to determine the most efficient and safe way to lift and move the object, reducing the risk of injury or damage.
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Match each scenario to the form of energy it represents.
a man jogging in the park
a stove burner that's turned on
an apple on a tree
a fully charged camera battery
A. gravitational potential energy
B. motion energy
C. electric potential energy
D. radiant energy
Answer: and apple on the tree is gravitational and potential
fully charged camera battery is electric/ potential energy a man jogging is motion energy and a stove burner that is turned on is radiation energy
Explanation:
hope this helps
NASA's new SLS rocket travels about 10 km/s in space. At this speed, how long would it take to reach alpha centauri (4.4 light years away from the sun)?
Total time taken to reach Alpha Centauri is 132001 years.
What is Velocity?The directional speed of an item in motion, as measured by a specific unit of time and viewed from a certain point of reference, is what is referred to as velocity.
An object's position changes if it moves in relation to a reference frame, such as when a passenger travels to the back of an airliner or a lecturer moves to the right in relation to a whiteboard. Displacement describes this shift in location.
When anything moves in connection to a reference frame, such when a passenger moves to the back of an airplane or a lecturer walks to the right in relation to a whiteboard, the location of the item changes. This locational change is described as displacement.
The distance that light travels in a light-year is one year. At 186,000 miles (300,000 kilometers) per second and 5.88 trillion miles (9.46 trillion kilometers) per year, light travels through interstellar space.
Total distance = 4.4*9.46*1,000,000,000,000* 2400000 = 4.1628* 10¹³ km
Speed is 10 km/sec
Total time taken = 4.1628* 10¹³/ 10 = 4.1628* 10¹² sec
1 year has = 3.15 * 10⁷ sec
Total time taken to reach Alpha Centauri is 132001 years.
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if it takes a technician 54s to polish 1.24 x 10^2 mm^2, how long does it take her to polish the entire lens? round your answer to significant figures.
To find the time it takes to polish the entire lens, we first need to know the total surface area of the lens. If we assume that the lens is spherical and has a diameter of 1.24 x 10^2 mm, then its surface area can be calculated using the formula for the surface area of a sphere:
A = 4πr^2, where r is the radius of the sphere
The radius of the sphere can be found by dividing the diameter by 2:
r = d/2
Plugging in the values for d and r, we get:
A = 4π(1.24 x 10^2 mm / 2)^2
A = 4π(62^2) mm^2
A = 4π(3844) mm^2
Now that we know the surface area of the lens, we can divide it by the time it takes the technician to polish 1.24 x 10^2 mm^2 to find the total time:
T = (4π * 3844 mm^2) / (54 s / 1.24 x 10^2 mm^2)
T = (4π * 3844) / 54
T = (15246.88) / 54
T = 282.6 s
Rounding to two significant figures, the time it takes the technician to polish the entire lens is approximately:
T = 283 s
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what tire pressures does ford reccommend fo a 2019 ford fusion energi titamium with 18 inch wheels reccommend?
For a Ford Fusion, the suggested tire pressure for the front and rear tires on a set of 18-inch wheels for 2019 Ford Fusion Energi Titanium tires is 32 psi (PSI).
The recommended pressure is typically displayed on a sticker inside the driver's door of newer vehicles. In most cases, the owner's handbook contains the specifications if there isn't a sticker on the door. When the tires are cold, most passenger cars advise 32 to 35 pressures in the tires.
In addition to hybrid ratings of 104 city MPGe and 91 highway MPGe, the 2019 Fusion Energi has gas mileage estimates of 43 city MPG and 41 highway MPG.
In the Ford Fusion Hybrid, the gasoline engine and braking are both used to partially replenish the battery. That entails filling the tank with fuel and starting the car. You can actually plug the Ford Fusion Energi into a power source.
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when priya travels from home to office at 40 km/hr she reaches her offce late by 20 minutes and when she travels with 60 km/hr, shre reach 10 minutes early. FInd the distance between her office and home? A. 50km B. 60 km C. 65 km D. 70 km
The distance between Priya's home and office is 70 km. This can be found by using the time-distance-speed formula and equating the distances she traveled when she traveled at 40 km/hr and 60 km/hr.
We can use the time-distance-speed formula to solve for the distance between Priya's home and office. The formula is given by:
distance = speed * time
Let's call the distance between Priya's home and office "d".
When she travels at 40 km/hr, she reaches her office 20 minutes late, so the time she took to travel is given by:
time = (60 minutes/hour) + 20 minutes = 80 minutes
time = 80 minutes / 60 minutes/hour = 1 hour and 20 minutes
So the distance she traveled is given by:
d = 40 km/hr * (1 hour + 20 minutes / 60 minutes/hour)
d = 40 km/hr * 1.3333 hours
Similarly, when she travels at 60 km/hr, she reaches her office 10 minutes early, so the time she took to travel is given by:
time = (60 minutes/hour) - 10 minutes = 50 minutes
time = 50 minutes / 60 minutes/hour = 0.83 hours
So the distance she traveled is given by:
d = 60 km/hr * 0.83 hours
Equating the two distances we have:
40 km/hr * 1.3333 hours = 60 km/hr * 0.83 hours
Solving for d we find that:
d = 70 km
So the answer is D) 70 km.
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if you have a 2 kg object and a 3 kg object separated by a distance of 4 meters, what is the gravitational force drawing them together?
The gravitational force drawing them together is 2.5 × 10⁻¹² N, if the masses of objects are 2 kg and 3 kg and they are separated by 4 meter distance.
Mass of the first object, m₁ = 2 kg
Mass of the second object, m₂ = 3 kg
The distance between them, d = 4 m
Universal gravitational constant, G = 6.67 × 10⁻¹¹ Nm²/kg²
The gravitational force is formulated as, F = Gm₁m₂/d²
F = (6.67 × 10⁻¹¹)(2 × 3)/4²
F = 2.5 × 10⁻¹¹ N
This force is an attractive force and it will be experienced by both the object.
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at its highest point, what fraction of the initial kinetic energy has been converted to potential energy?
At its highest point, all of the initial kinetic energy has been converted to potential energy.
What is kinetic energy?
Kinetic energy is a form of energy related to the motion of an object. It is the energy associated with the movement of an object, and is calculated by multiplying the mass of the object by the square of its velocity. Kinetic energy is a scalar quantity, meaning that it only has magnitude and does not have a direction. It is often represented by the letter K. When an object is at rest, it has no kinetic energy. However, when it starts to move, it gains kinetic energy. Kinetic energy can be transferred from one object to another in collisions or by the application of a force. In addition, kinetic energy can be converted into other forms of energy, such as thermal energy. Kinetic energy is an important concept in many fields of physics, such as mechanics and thermodynamics.
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Darcel runs the simulation for the large version of each object. What can he say in general about the energies of the objects in the simulation as they roll down the incline? (Select all that apply.)"The total energy of the system remains constant and is equal to the gravitational potential energy of the object at the top of the incline.""The total kinetic energy of a rolling object is the sum of the rotational kinetic energy about the center of mass and the translational kinetic energy of the center of mass.""The translational kinetic energy is always greater than the rotational kinetic energy.""The potential energy of the system remains constant, and is equal to the total energy."
12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2. The combined translational and rotational kinetic energies of an object in motion determine its total kinetic energy.
A rolling object's combined linear and rotational kinetic energies make up its total kinetic energy: The second equation clearly shows that a rolling item has kinetic energy that is greater than its kinetic energy during translation. Yes, the kinetic energies of rotation and translation are same. The coordinated (non-random) movement of mass with respect to a certain reference frame involves both of them as the energy of motion. 12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2.
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saturn is 95 times the mass of earth. its volume is about 765 times that of earth. why?
Saturn is 95 times the mass of earth. its volume is about 765 times that of earth because Saturn has a lower density than Earth.
The second-largest planet in the Solar System after Jupiter, Saturn is located six planets from the Sun. With a typical radius of almost nine and a half times that of Earth, it is a gas giant. Despite being nearly 95 times more massive, it barely possesses an eighth of Earth's average density. Saturn's interior is most likely made up of a rocky core, a layer of deep metallic hydrogen, a layer of liquid hydrogen and helium in the middle, and a layer of gaseous material on the outside. Saturn's upper atmosphere contains ammonia crystals, which give the planet a faint yellow tint.The radius of the planet is just as important to the planet's gravity as is the planet's mass. It is inversely related to the square of the radius and immediately relates to the planet's mass. Saturn's radius is 9.5 times that of Earth, despite its mass being 95 times that of Earth.
Therefore, gravity is 95 /(9.5) ²= 1.053 times greater than that of the Earth.
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When wind blows, stationary waves can be formed on the aerial wire. Explain how stationary waves are produced and why only waves of specific frequencies can form on the aerial wire
1. Wind produces a disturbance that travels along the wire
2. Wave is reflected at each end
3. Waves interfere
4. Only certain frequencies since fixed ends have to be nodes
Stationary waves are produced when wind produces a disturbance that travels along the wire. This wave is reflected at each end. Then the waves interfere and only certain frequencies since fixed ends have to be nodes.
A wave that maintains its location throughout time is said to be stationary. It can develop in a stationary medium as a result of interference between two waves that have equal wavelengths and are moving in opposite directions but along the same path. They should have almost same amplitude.
Standing waves only occur at certain frequencies as you can only get a stable pattern if there is a whole number of half wavelengths along the length of the oscillator.
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Which of the following is an example of a velocity?
Question options:
2 mile/minute
80 miles/hour
9.8 meters/second/second
45 kilometers/hour East
Answer:
45 km per hour due east
Explanation:
it has bot magnitude and direction
a 370 hz sinusoidal voltage with a maximum amplitude of 100 v at t=0 is applied across the terminals of an inductor. the maximum amplitude of the steady-state current in the inductor is 10 a .
The steady-state current in the inductor has a maximum amplitude of 10 A.
Calculate the inductance of the inductor by using the formula L = V/(ωI), where V is the voltage (100 V), ω is the angular frequency (2πf, where f is the frequency (370 Hz)), and I is the current (10 A):
L = 100 V/(2π(370 Hz) (10 A)) = 6.82 mH
Calculate the reactance of the inductor by using the formula X = 2πfL, where f is the frequency (370 Hz) and L is the inductance (6.82 mH):
X = 2π(370 Hz) (6.82 mH) = 1010 Ω
Calculate the peak current of the steady-state current by using the equation I_p = V/X, where V is the voltage (100 V) and X is the reactance (1010 Ω):
I_p = 100 V/1010 Ω = 0.099 A
Calculate the maximum amplitude of the steady-state current by multiplying the peak current (0.099 A) by √2:
I_max = 0.099 A × √2 = 0.14 A = 10 A
Hence, The maximum amplitude of the steady-state current in the inductor is 10 A.
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do the equations for the angular magnification and length of a telescope work if a diverging lens is used as the eyepiece? explain by including a short description of the design of the telescope and the observations.
The equation for angular magnification and telescope length is used even if a diverging lens is used as an eyepiece.
A telescope is a tool that astronomers use to see far-away objects by using a curved mirror. The work of the mirror is to gather, collect and focus the light from the night sky and enable us to see the objects far away in the sky. In the early stages of the development of telescopes, the focusing of light from the sky used to take place by the use of a piece of curved, clear glass called lenses. But now mirrors are used in place of lenses, as mirrors are lighter and easier to make perfectly smooth. These types of telescopes are called reflecting lens telescope. While others are called refracting lens telescopes.
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a spring has a spring constant of 40 n/m. how much work is required to stretch the spring 2.0 cm from its equilibrium position?
The work done to stretch the spring 2.0 cm from its equilibrium position is 0.16 J.
To calculate the amount of work required to stretch a spring 2.0 cm from its equilibrium position, you can use the formula for work done on a spring:
W = (1/2) * k * x^2
where W is the work done, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
In this case, the spring constant is 40 N/m, and the displacement is 2.0 cm = 0.02 m. So,
W = (1/2) * 40 N/m * (0.02 m)^2
The work done to stretch the spring 2.0 cm from its equilibrium position is 0.16 J.
It is important to note that this formula assumes that the spring is ideal and follows Hooke's law, which states that the force exerted by a spring is proportional to its displacement. In reality, springs may deviate from this law and may not be ideal, so the actual work done may be different from the calculated value. Additionally, this calculation assumes that the spring is stretched in a linear fashion, and that the displacement is small compared to the total length of the spring.
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how many angles do you need to measure to map out the position of a sky object at any particular time?
The correct answer is 4 numbers of angles to measure to map out the position of a sky object at any particular time.
What is Degrees (°) are the units used by astronomers?
Degrees (°) are the units used by astronomers to measure the "angular distance" between celestial objects. There are 90 degrees between any point on the horizon and the highest top of the sky because a circle has 360 degrees.
So we can conclude there are 4 number of angles as 90 arc minute in sky object.
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A particular car engine provides a force of 700n when a car is moving at its top speed of 40 ms-1
a. Calculate how much work is done by the car’s engine in one second. b. State the output power of the engine.
The car's engine provides a force of 700 N and does 28000 joules of work in one second, with an output power of 28000 W. We can calculate this using work = f.s and power = work/time
a. Work is calculated as the force applied multiplied by the distance traveled in the direction of the force. In the case of the car's engine, the work done in one second can be calculated as follows:
work = force x distance
distance = speed x time (t = 1 second)
work = 700 N x (40 m/s x 1 s)
work = 28000 J
b. Power at what rate work is being performed. It can be calculated as the work done divided by the time taken. In this case, the output power of the engine can be calculated as follows:
power = work/time
power = 28000 J / 1 s
power = 28000 W
So, the engine provides an output power of 28000 watts. This means that in one second, the engine does 28000 joules of work, which is equivalent to 28 kilowatts of power.
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A book is thrown upward from height 10.m and lands with a velocity of -17.50m/s. What was its initial velocity
Answer:
Below
Explanation:
Find the velocity if it was just DROPPED from 10m
d = 1/2 at^2
10 = 1/2 * 9.81 * t^2 shows t = 1.42784 s to hit ground from 10 m
velocity if just dropped v = at = 9.81 * 1.4278414 m/s
when the book is tossed up...and it returns to the launch point it will have the same magnitude of velocity
so it was launched up at the difference between what it was if just dropped and the final v of 17.5
17.5 - 14 = 3.5 m/s initial v
A neutral sodium atom has an ionization potential of ? = 5.1 eV.
1. What is the speed of a free electron that has just barely enough kinetic energy to collisionally ionize a sodium atom in its ground state? What is the speed of a free proton with just enough kinetic energy to collisionally ionize this atom?
Answer:
The speed of a free electron that has justify barerly enough kinetic energy collisionally ionize a sodium atom in it's ground state is about 5.4eV.
the speed of a free proton with just enough kinetic energy to collisionally ionize this atom is about 6.8eV.
1. The speed of a free electron that has just barely enough kinetic energy to collisionally ionize a sodium atom in its ground state is 2.2 x 10^6 m/s.
2. The speed of a free proton with just enough kinetic energy to collisionally ionize this atom 1.2 x 10^7 m/s.
The ionization potential of a neutral sodium atom is 5.1 eV. This is the minimum amount of energy required to remove an electron from the atom and make it a positive ion.
To calculate the speed of an electron with just enough kinetic energy to ionize the atom, we can use the equation:
E_k = 1/2 * m * v^2
where E_k is the kinetic energy, m is the mass of the electron, and v is its speed. We know that E_k = 5.1 eV, so we can rearrange the equation to solve for v:
v = sqrt(2 * E_k / m)
where m is the mass of the electron, which is approximately 9.11 x 10^-31 kg.
Plugging in the values, we get:
v = sqrt(2 * 5.1 eV / 9.11 x 10^-31 kg)
which is approximately 2.2 x 10^6 m/s.
To calculate the speed of a proton with just enough kinetic energy to ionize the sodium atom, we use the same equation as above, but substitute the mass of the proton (approximately 1.67 x 10^-27 kg) for the mass of the electron:
v = sqrt(2 * 5.1 eV / 1.67 x 10^-27 kg)
which is approximately 1.2 x 10^7 m/s.
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The human eye can "see" with a signal of 100 photons per second. How far away can a 100-watt light bulb be seen by a dark-adapted eye? Assume the light bulb is in outer space, so that the light is not scattered by the atmosphere. Also assume that the bulb is monochromatic and radiates at a wavelength of 550 nm. Use a reasonable estimate for the diameter of the dark-adapted pupil of the eye. Diameter of the pupil is 5mm. The answer in the back of the book is 2000 km
The distance from the light bulb is 195km when human eye can "see" with a signal of 100 photons per second of a 100W bulb.
Given the number of photons the human eye can see (n) = 100 per second
The power of light bulb (P) = 100W
The wavelength of light the bulb radiates (∧) = 550nm = 550 x 10^-9m
Let the diameter of pupil (d) = 5mm = 5 x 10^-3m
Let the distance the eye can see a 100-watt light bulb = r
Let the intensity of the light bulb = I
Let the power of eye = Pe
We know that I = P/4πr^2 where r is the distance from the light bulb
The power of eye = Intensity x Area of pupil = I x πd^2/4
Then, I = 4Pe/πd^2 such that 4Pe/πd^2 = P/4πr^2
So, r^2 = P x d^2/16Pe then, r = d/4(√P/Pe)
We know that E = h∨ = hc/∧ where h is the planck's constant = and c is the speed of light = 3 x 10^8m/s.
E = the power of eye = Pe = hc/∧ x n
Then, r = d/4(√P∧/hcn)
r = 5/4(√100 x 550 x 10^-9/100 x 6.6 x 10^-34 x 3 x 10^8
r = 5/4√22.7 x 10^17
r = 15.6 x 10^4 x 1.25 = 19.5 x 10^4m = 195km
Hence the distance from the light bulb is 195km.
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A wave has a time period of 0.1s and is travelling at a speed of 340 m/s. calculate the wavelength of the wave
If a wave has a time period of 0.1s and is travelling at a speed of 340 m/s, the wavelength of the wave is 34 meters.
What is wave?A wave is a dynamic disturbance of one or more quantities that propagates in physics, mathematics, and related sciences. When waves oscillate frequently around an equilibrium value at a certain frequency, they are said to be periodic.
The wavelength of the wave = speed of the wave × time period of the wave
= 340 m/s × 0.1 s
= 34 m.
Hence, the wavelength of the wave is 34 meters.
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determine whether the series is convergent or divergent. [infinity] n = 1 1 9 e−n
The sum of the series is infinite, it is considered to be divergent.
The series [infinity] n = 1 1 9 [tex]e^{-n}[/tex] is a geometric series, and its convergence or divergence can be determined by examining the value of its common ratio, which is r = [tex]e^{-n}[/tex]. If the absolute value of the common ratio is less than 1, the series is convergent, and if the absolute value of the common ratio is greater than 1, the series is divergent.
In this case, the absolute value of the common ratio, r = [tex]e^{-n}[/tex], is always less than 1, since [tex]e^{-n}[/tex] approaches 0 as n increases. Therefore, the series [infinity] n = 1 1 9 [tex]e^{-n}[/tex] is convergent.
To determine the sum of the series, we can use the formula for the sum of a convergent geometric series:
S = a / (1 - r) = 1 / (1 - [tex]e^{-n}[/tex]) = 1 / (1 - 0) = ∞
Since the sum of the series is infinite, it is considered to be divergent.
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21) A hot urface at 100oC i to be cooled by attaching 3-cm-long, 0. 25-cm-diameter aluminum pin fin (k = 237 W/mK) to it, with a center-to-center ditance of 0. 6 cm. The temperature of the urrounding medium i 30oC and the heat tranfer coefficient on the urface i 35 W/m2K. Determine the rate of heat tranfer from the urface for a 1 m x 1 m ection of the plate. Alo determine the overall effectivene of the fin
The rate of heat transfer is 2450 W, and the effectiveness of the fin is 0.097 or 9.7%.
Convective heat transfer coefficient (h) = 35 W/m²K
Area of the plate = 1 m²
Temperature difference = 100 - 30 = 70K
Rate of heat transfer is formulated as, Q = h×A×ΔT
Q = 35×1×70 = 2450 W = Qmin
The overall effectiveness of the fin can be calculated using the equation:
η = Q / (Qmax - Qmin)
Where Qmax is the maximum possible heat transfer rate,
Qmax = k×A₁×ΔT/L
Where k is fin's conductivity = 237 W/mK
A₁ is the area of the fin = π×(d/2)² = π(0.25/2)² = 0.05 m²
L is the length of the rod, = 3 cm = 0.03 m
ΔT = 100 - 30 = 70K
Qmax = 237 × 0.05×70/0.03
Qmax = 27650
η = 2450/ (27650 - 2450)
η = 0.097 or 9.7%
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if all this heat is removed from the hiker (no significant heat was generated by metabolism during this time), what drop in body temperature would the hiker experience? the clothed hiker weighs 95 kg , and you can approximate the heat capacity of hiker and clothes as equal to that of water. (moral: stay out of the wind if you get your clothes wet.) express your answer using two significant figures and include the appropriate units. as the question already asks for the drop in temperature, provide a positive number as the answer.
The drop in body temperature would be 56.6°C. (The temperature drop is negative because heat is being lost).
A physical feature of matter known as heat capacity or thermal capacity is the quantity of heat that must be applied to an item in order to cause a unit change in temperature. J/K is the metric unit for heat capacity. A broad attribute is heat capacity.
The amount of heat energy needed to increase the temperature of a given quantity of matter by one degree Celsius is referred to as heat capacity. Heat capacity is a broad attribute that depends on the size or amount of a specific substance.
The heat capacity of water can be expressed as:
C = 4.184 J/g°C
Since the heat capacity of the hiker and clothes can be approximated as equal to that of water, we can use the same heat capacity.
The change in temperature can be found using the equation:
ΔT = Q / (m * C)
where Q is the heat lost by the hiker2,
m is the mass of the hiker and clothes, and
C is the heat capacity.
Substituting the given values, we get:
ΔT = (-6.57 x 10^6 J) / (95 kg * 4.184 J/g°C)
= -56.6°C
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Applying Physics to Human Geography where Distance = Speed x Time: If humans originated in Africa and migrated to other parts of the world, some time would be required for this to occur. At a modest rate of one kilometer per year, how many centuries would it take for humans originating in Africa to migrate to China, some 10,000 kilometers away? Show your work for full credit.
Answer:
Explanation:The question is about the diffusion of humans, traveling at a speed of
v
=
1
km/year
, attempting to migrate to China over a distance of
d
=
10000
km
. The time taken is obtained as:
t
=
d
v
=
10000
km
1
km/year
=
10000
years
.
We are asked to provide the answer in centuries. Noting that 1 century is equivalent to 100 years, we write the time required as:
10000
years
100
years/century
=
100
centuries
A girl of mass 40 kg climbs a rope 6 m long at constant speed in 15 seconds. What power she expands during the climb?
how does the relationship between temperature and density help to explain why the drop in pressure was greater in fairbanks than at keywes
The drop in pressure was greater in Fairbanks than compared to Key West.
Troposphere: The troposphere is Earth's lowest atmosphere layer. The troposphere contains approximately 75-80% of the atmosphere's mass. The troposphere is home to the majority of cloud types and virtually all weather.
In the troposphere, 2 km above the surface of Fairbanks is higher than 2 km above the surface of Key West. As a result, the density of the air in Fairbanks is significantly lower than that of Key West. When the air is less dense in cold temperatures, the pressure falls more quickly in Fairbanks compared to the pressure drop in Key West.
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A 25kg bike has 10250J of kinetic energy, how fast is it going?
Answer:
28.63 m/s
Explanation:
you have a ct circuit connected to a relay. you know the following: the ct resistance is 0.800 ohms total the wires from the ct to relay are 100 ft each and have a resistance of 0.001 ohms/ft the relay has a resistance 0.020 ohms the worst-case fault occurs for a 1lg fault. what is the total resistance you need to consider when evaluating the cts? a. 1.020 ohms b. 0.920 ohms c. 1.000 ohms d. 0.900 ohms
When evaluating the CTS you need to consider the total resistance of 1.020 ohms. Here option A is the correct answer.
The total resistance to consider when evaluating the CTs is given by the sum of the resistance of the CT, the wires, and the relay.
The resistance of the wires can be calculated using the formula R = r * L, where r is the resistance per unit length (0.001 ohms/ft) and L is the total length of the wires (100 ft * 2 = 200 ft).
Plugging in the values, we get:
Rwires = 0.001 ohms/ft * 200 ft = 0.200 ohms
The total resistance to consider is then:
Rtotal = RCT + Rwires + Rrelay
Rtotal = 0.800 ohms + 0.200 ohms + 0.020 ohms
Rtotal = 1.020 ohms
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if the room radius was 5.1 m , and the rotation frequency 0.55 revolutions per second when the floor drops out, what minimum coefficient of static friction keeps the people from slipping down? [hint: draw a free-body diagram for a person.]
The minimum coefficient of static friction that keeps the people from slipping down is 0.162.
Radius of the room, or radius of the rotation, R = 5.1 m
Rotation frequency, ω = 0.55 revolution/sec
ω = 2π×0.55 = 3.46 rad/sec
Then linear speed, v = rω = 5.1 × 3.46
v = 17.6 m/s
Let the mass of the person, = m
Let the minimum coefficient of static friction, = μ
Wall reaction will provide the normal reaction, N = mv²/r
Weight of the person will be balanced by the friction force, mg = μN
μmv²/r = mg
μ = rg/v²
μ = 5.1×9.81/17.6²
μ = 0.162
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