Calculate the distance between the points C=(-1, -3) and H=(2, -8) in the coordinate plane.
Give an exact answer (not a decimal approximation).

Answers

Answer 1

Answer:

The distance between two points C=(-1, -3) and H=(2, -8) is 5.831

Step-by-step explanation:

We need to calculate the distance between two points C=(-1, -3) and H=(2, -8)

The formula used to find distance between two points is:

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

We have [tex]x_1=-1, y_1=-3, x_2=2, y_2=-8[/tex]

Putting values in formula and finding distance:

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(2-(-1))^2+(-8-(-3))^2}\\Distance=\sqrt{(2+1)^2+(-8+3)^2}\\Distance=\sqrt{(3)^2+(-5)^2}\\Distance=\sqrt{9+25}\\Distance=\sqrt{34}\\Distance=5.831[/tex]

So, the distance between two points C=(-1, -3) and H=(2, -8) is 5.831


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Step-by-step explanation:

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Answer

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

well it is b

Step-by-step explanation:

well I tried my best

When a figure or a shape is dilated, the size of its image will either be enlarged or compressed.

The scale of dilation from A to B is 1.5

See attachment for the image that completes the question.

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[tex]\mathbf{A = 1\ inch}[/tex]

[tex]\mathbf{B = 1.5\ inches}[/tex]

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[tex]\mathbf{k = \frac BA}[/tex]

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follow me say a thanks mark me branliest

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The second one is correct

Answer:

Step-by-step explanation:

y≥54

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