Under the given conditions of 2.00 V and a current of 5.00 A for 15.00 minutes, approximately 1.37 grams of Ni is expected to be deposited on the zinc electrode using Faraday's law of electrolysis.
To calculate the expected amount of Ni deposited on a zinc electrode, we can use Faraday's law of electrolysis, which relates the amount of substance deposited to the current, time, and molar mass.
The equation for Faraday's law is:
moles of substance = (current * time) / (n * F)
Where:
current is the electric current in amperes (A)
time is the time in seconds (s)
n is the number of electrons transferred in the reaction (equal to the stoichiometric coefficient of the substance in the balanced equation)
F is Faraday's constant, approximately 96,485 coulombs per mole of electrons
First, we need to determine the number of moles of electrons transferred in the reaction. The balanced equation for the deposition of Ni is:
Ni2+(aq) + 2e- -> Ni(s)
From the equation, we can see that 2 moles of electrons are required for the deposition of 1 mole of Ni.
Given:
current = 5.00 amperes
time = 15.00 minutes = 15.00 * 60 seconds = 900 seconds
n = 2
Substituting the values into Faraday's law:
moles of Ni = (5.00 A * 900 s) / (2 * 96,485 C/mol)
moles of Ni = 0.0234 mol
Finally, to determine the amount of Ni deposited, we need to multiply the number of moles by the molar mass of Ni, which is 58.69 g/mol:
mass of Ni = 0.0234 mol * 58.69 g/mol
mass of Ni = 1.37 g
Therefore, the expected amount of Ni deposited on the zinc electrode under the given conditions is approximately 1.37 grams.
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helpp me with this please
Which of the following organic solvents would be suitable for use in the extraction of an aqueous solution?
a. methanol
b. hexane
c. acetone
d. ethanol
e. none of the above
None of the above solvents (methanol, hexane, acetone, ethanol) would be suitable for the extraction of an aqueous solution.
In order to extract an aqueous solution, an organic solvent that is immiscible with water is typically used. Methanol, acetone, and ethanol are all miscible with water, meaning they can mix and dissolve in water. Hexane, on the other hand, is immiscible with water but it is a non-polar solvent, which makes it unsuitable for extracting polar compounds from an aqueous solution.
The suitable solvents for extracting an aqueous solution are typically non-polar solvents that do not mix with water. Examples of such solvents include diethyl ether, dichloromethane (methylene chloride), and ethyl acetate. These solvents have low polarity and can effectively separate non-polar or slightly polar compounds from an aqueous solution through liquid-liquid extraction. They form distinct layers with water, allowing for the separation of the organic phase containing the extracted compounds.
Therefore, the correct answer is e. none of the above, as none of the solvents mentioned (methanol, hexane, acetone, ethanol) are suitable for the extraction of an aqueous solution.
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what minimum volume of 0.282 m potassium iodide solution is required to completely precipitate all of the lead in 165.0 ml of a 0.150 m lead (ii) nitrate solution? what minimum volume of 0.282 potassium iodide solution is required to completely precipitate all of the lead in 165.0 of a 0.150 lead nitrate solution?351 ml 87.8 ml 176 ml 43.9 ml
The minimum volume of 0.282 M KI solution required to completely precipitate all of the lead in 165.0 mL of 0.150 M Pb(NO3)₂ solution is 87.8 mL.
The chemical reaction that takes place when a potassium iodide solution is added to lead (II) nitrate solution is given as follows:
Pb(NO3)₂ + 2KI → 2KNO₃ + PbI₂
From the chemical reaction, it can be seen that 2 moles of KI will react with 1 mole of Pb(NO3)₂ to yield 1 mole of PbI₂. The number of moles of lead nitrate in the given volume can be calculated as follows:
n = M × V
n = 0.150 M × 165.0 mL/1000
n = 0.02475 moles
The number of moles of KI required to precipitate all the lead can be calculated as follows:
n = 0.5 × 0.02475
n = 0.012375 moles
The volume of 0.282 M KI solution required can be calculated as follows:
V = n × M-1
V = 0.012375 moles × 0.282 L/mole
V = 0.00349 L
V = 3.49 mL
V = 87.8 mL (rounded off to three significant figures)
The answer is that 87.8 ml of 0.282 M potassium iodide solution is required to completely precipitate all of the lead in 165.0 ml of a 0.150 M lead (II) nitrate solution.
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What does iron (ll) indicate that a compound contains?
iron ions with a ll+ charge
iron ions with a ll+ charge
iron ions with 2+ charge
iron ions with 2+ charge
iron ions with 2- chaarge
iron ions with 2- chaarge
two types of iron ions
Answer:
iron ions with a 2+ charge
1. If the density of mercury is 13.6 g/cm3, what will be the volume of 300g
of mercury?
Answer:
Volume (V) = 2.2058823529412E-5 cubic meter
Explanation:
Round if nessesarry
v = 0.3kg / 13600
v = 2.2x10^-5 m^3
the order for a 33-kg dog is 5 micrograms/kg/min dobutmine. a 12.5 mg/ml solution of dobutamine is available. the dobutamine will be run at a rate of 20 ml/hr and will be added to a 500-ml bag of fluid. what quantity (ml) will you add to the bag?
Based on the given parameters, adding 0.5 mL of the 12.5 mg/mL dobutamine solution to the 500 mL bag of fluid will achieve the desired concentration and infusion rate for the 33 kg dog.
To determine the quantity of dobutamine to add to the 500 mL bag of fluid, we need to calculate the total amount of dobutamine required based on the dog's weight and the infusion rate.
First, we convert the weight of the dog from kilograms to grams:
33 kg × 1000 g/kg = 33000 g
Next, we calculate the total amount of dobutamine required per minute:
5 micrograms/kg/min × 33 kg = 165 micrograms/min
Since the concentration of the dobutamine solution is given in mg/mL, we need to convert micrograms to milligrams:
165 micrograms/min × 1 mg/1000 micrograms = 0.165 mg/min
Now, we convert the infusion rate from milliliters per hour to milliliters per minute:
20 mL/hr ÷ 60 min/hr = 0.33 mL/min
Finally, we can calculate the quantity of dobutamine to add to the bag:
0.165 mg/min ÷ 0.33 mL/min = 0.5 mg/mL
Therefore, you would add 0.5 mL of the 12.5 mg/mL dobutamine solution to the 500 mL bag of fluid.
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Consider these two cases.
Case 1: An electron jumps from energy level 3 to energy level 4 in an atom.
Case 2: An electron jumps from energy level 3 to energy level 5 in an atom.
For case 1, what happens when an electron jumps from energy level 3 to energy level 4 in an atom?
A photon is absorbed by the atom.
A neutron is absorbed by the atom.
A photon is emitted by the atom.
A neutron is emitted by the atom.
Assuming that both cases describe Hydrogen‑like atoms with one electron, for which case is more energy emitted or absorbed?
The energy is the same for both cases.
More energy is emitted or absorbed for case 1.
More energy is emitted or absorbed for case 2.
It is impossible to tell.
In case 1, when an electron jumps from energy level 3 to energy level 4 in an atom, a photon is emitted by the atom.
In case 2, when an electron jumps from energy level 3 to energy level 5 in an atom, a photon is also emitted by the atom. Since both cases involve the emission of photons, we can conclude that the same type of energy change occurs in both cases.
When an electron jumps between energy levels in an atom, it undergoes a transition and releases or absorbs energy in the form of a photon. The energy of the emitted or absorbed photon corresponds to the difference in energy between the initial and final energy levels of the electron.
In both case 1 and case 2, photons are emitted by the atom, indicating that energy is being released. The energy difference between energy levels 3 and 4 is smaller than the energy difference between energy levels 3 and 5. Therefore, more energy is emitted or absorbed in case 2, where the electron jumps from energy level 3 to energy level 5, compared to case 1.
Hence, more energy is emitted or absorbed for case 2 than for case 1 in a Hydrogen-like atom with one electron.
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If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?
Answer:
The answer is 14.29 %Explanation:
The percentage error of a certain measurement can be found by using the formula
[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]
From the question
actual density = 0.70 g/mL
error = 0.8 - 0.7 = 0.1
So we have
[tex]P(\%) = \frac{0.1}{0.7} \times 100 \\ = 14.285714...[/tex]
We have the final answer as
14.29 %Hope this helps you
question the substances in a beaker are at room temperature before a chemical reaction takes place. what do you know if you touch a beaker during the chemical reaction and it feels cold?
When substances in a beaker are at room temperature before a chemical reaction takes place, the beaker will usually feel neutral or at the same temperature as the surroundings. If you touch a beaker during the chemical reaction and it feels cold, it indicates an endothermic reaction.
What is an endothermic reaction? An endothermic reaction is a type of chemical reaction that absorbs heat energy from its surroundings. Endothermic reactions require an external energy source to drive the reaction. During the reaction, energy is absorbed, causing the surrounding environment to feel cooler than before. This causes the temperature of the beaker to decrease, resulting in a cold sensation when touched. This type of reaction is characterized by a positive change in enthalpy (ΔH>0). What is an exothermic reaction? Exothermic reactions, on the other hand, release energy into the surroundings.
These reactions occur spontaneously, and heat is released as a result. The temperature of the beaker increases, causing it to feel warm to the touch. The reaction has a negative change in enthalpy (ΔH<0). ConclusionIn conclusion, if the beaker feels cold during a chemical reaction, it is a good indication that an endothermic reaction is taking place, and energy is being absorbed from the surroundings. If the beaker feels warm, it is an exothermic reaction, and energy is being released into the surroundings.
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a tank at is filled with of dinitrogen difluoride gas and of boron trifluoride gas. you can assume both gases behave as ideal gases under these conditions. calculate the mole fraction of each gas. round each of your answers to significant digits.
To calculate the mole fraction of each gas, we need to first calculate the total number of moles of the gas in the tank using the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is the temperature.
We can rearrange this equation to solve for n, which gives us:n = PV/RTWhere:P = pressure = 1 atmV = volume = not givenR = universal gas constant = 0.08206 L·atm/(mol·K)T = temperature = not givenSince we don't have information about the volume or temperature of the gas in the tank, we cannot calculate the total number of moles directly. However, we can use the mole fraction to find the number of moles of each gas present in the tank.
We can find the mole fraction of dinitrogen difluoride (N2F2) by dividing the number of moles of N2F2 by the total number of moles of gas present in the tank:x(N2F2) = n(N2F2)/n(total).
Similarly, we can find the mole fraction of boron trifluoride (BF3) by dividing the number of moles of BF3 by the total number of moles of gas present in the tank:x(BF3) = n(BF3)/n(total)To find the mole fraction of each gas, we need to know the total number of moles of gas present in the tank. Without the volume or temperature of the gas in the tank, we cannot calculate the total number of moles or the mole fraction of each gas.
Without the volume or temperature of the gas in the tank, we cannot calculate the mole fraction of each gas.
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HW 2 - Matter Day 1
1.
Classify the following as Matter or Not matter
a. Calculator
b. Heat
C. Air
d. Wind
e. Water
f. Ice
g. Electricity
which of the following aqueous solutions when mixed produces a precipitate? question options: a) nh4no3(aq) and bacl2(aq) b) li2so4(aq) and cabr2(aq) c) ki(aq) and na2co3(aq) d) cscl and (nh4)3po4 e) naoh and hcl g
When aqueous solutions of NH4NO3 and BaCl2 are mixed, they don't produce a precipitate.
The mixing of an aqueous solution of NH4NO3 and BaCl2 will not result in a precipitate being formed. The reaction that takes place in the aqueous solution is NH4NO3 + BaCl2 → Ba(NO3)2 + 2NH4Cl. The balanced equation shows that the products of the reaction are Ba(NO3)2 and NH4Cl, both of which are soluble in water. As a result, there will be no formation of a precipitate when the two solutions are mixed. Aqueous solutions of NH4NO3 and BaCl2 will not produce a precipitate when mixed.
There will be no visible change in the appearance of the mixture as the products formed are soluble in water.
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Which number determines how the Periodic Table is arranged?
Answer:
B. the atomic number
Explanation:
The atomic number (number of protons) orders the elements
The number that determines how the Periodic Table is arranged is the atomic number of each element.
The atomic number is a unique identifier for each chemical element and corresponds to the number of protons found in the nucleus of an atom of that element. It is represented by the symbol "Z." For example, the atomic number of carbon is 6, meaning a carbon atom has 6 protons in its nucleus.
In the modern Periodic Table, the elements are arranged in ascending order of their atomic numbers. This arrangement results in elements with similar chemical properties being placed in the same vertical columns, known as groups or families. The Periodic Table is organized in a way that elements in the same group have the same number of valence electrons, which determines their chemical behavior and reactivity.
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How do you figure out the number of
electrons in a neutrally charged atom?
Answer:
The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number (Z).
Answer:
The number of protons in the nucleus of the atom is equal to the atomic number.
The number of electrons in a neutral atom is equal to the number of protons.
Explanation:
Use the value of the activation energy (Ea = 1.50 x 102 kJ/mol) and the given rate constant of the reaction at either of the two temperatures to predict the rate constant at 542 K. The rate constant at 701 K is measured as 2.57 M−1⋅s−1 and that at 895 K is measured as 567 M−1⋅s−1.
To predict the rate constant at 542 K using the given activation energy and the rate constant at 701 K, we can apply the Arrhenius equation. By substituting the values into the equation, we can calculate the rate constant at the desired temperature.
To predict the rate constant at 542 K using the given activation energy (Ea = 1.50 x 10^2 kJ/mol), we can use the Arrhenius equation:
k2 = k1 * e^(-Ea / (R * T2))
where k1 is the rate constant at the known temperature (701 K), k2 is the rate constant at the desired temperature (542 K), Ea is the activation energy, R is the gas constant (8.314 J/(mol*K)), and T2 is the temperature in Kelvin (542 K).
First, we need to convert the activation energy from kJ/mol to J/mol by multiplying it by 1000:
Ea = 1.50 x 10^2 kJ/mol * 1000 J/1 kJ = 1.50 x 10^5 J/mol
Now, we can calculate the rate constant at 542 K:
k2 = 2.57 M^(-1)s^(-1) * exp(-1.50 x 10^5 J/mol / (8.314 J/(molK) * 542 K))
k2 ≈ 2.57 M^(-1)*s^(-1) * exp(-34.84)
Using the above calculation, we can determine the rate constant at 542 K.
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If 150 grams of water is to be heated from 15.0°C to 100°C to make a cup of tea, how much heat must be added? The specific heat of water is 4.18 J/g°C
Answer:
The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.
Explanation:
The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.
1.) Draw a diagram of the chemical structure of oil-based paint.
With an explanation
The specific composition of oil-based paint can vary depending on the brand and formulation.
Oil-based paint typically consists of three main components: pigments, binders, and solvents. The pigments provide the color and opacity to the paint, while the binders are responsible for holding the pigment particles together and adhering them to the painted surface. The solvents help to adjust the paint's consistency and facilitate its application.
The binder in oil-based paint is commonly a natural oil, such as linseed oil or tung oil. These oils are composed of fatty acid molecules, which contain a long carbon chain with a carboxyl group (-COOH) at one end. The carboxyl group can react with oxygen in a process called oxidation, forming a cross-linked network of molecules that harden over time, creating a durable paint film.
The solvents in oil-based paint are typically organic compounds, such as mineral spirits or turpentine. These solvents dissolve the binder and pigments, making the paint flowable and easy to apply. As the solvent evaporates, the paint gradually dries and the binder undergoes the oxidation process, resulting in the formation of a solid paint film.
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Bena thinks that dissolving more salt in water causes the mixture’s freezing temperature to change.
FAST PLEASE
Which is the best type of scientific investigation for Bena to use to study this?
an experimental investigation, because it can provide the most data
a comparative investigation, because it uses a wide range of variables
an experimental investigation, because it allows for the control of variables
a comparative investigation, because it would take the least amount of time
Answer:
The right option is; an experimental investigation, because it allows for the control of variables.
Explanation:
The type(s) of intermolecular forces exhibited by hydrogen bromide molecules, HBr, is/are ________.
The type(s) of intermolecular forces exhibited by hydrogen bromide molecules, HBr, are dipole-dipole interactions and London dispersion forces.
Hydrogen bromide (HBr) is a polar molecule due to the difference in electronegativity between hydrogen and bromine atoms. Bromine is more electronegative than hydrogen, resulting in a partial negative charge on the bromine atom and a partial positive charge on the hydrogen atom. This creates a permanent dipole moment in the HBr molecule. Dipole-dipole interactions occur between the positive end of one molecule (the hydrogen atom) and the negative end of another molecule (the bromine atom). These intermolecular forces are relatively stronger than the London dispersion forces.
In addition to dipole-dipole interactions, hydrogen bromide molecules also experience London dispersion forces. These forces arise due to temporary fluctuations in electron distribution within molecules. Even though HBr is a polar molecule, it can still exhibit London dispersion forces since all molecules, regardless of polarity, have electrons that are constantly in motion. These temporary fluctuations in electron distribution create instantaneous dipoles, leading to attractive forces between neighboring molecules.
Overall, the intermolecular forces in hydrogen bromide (HBr) include both dipole-dipole interactions and London dispersion forces. These forces play a crucial role in determining the physical properties and behavior of HBr, such as boiling point, solubility, and viscosity.
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Even if an object is sitting perfectly still and not moving, the atoms and molecules that the object is made of still have kinetic energy due to their constant motion
true or false?
Answer:
True
Explanation:
the atoms never stop moving, so the answer is true
Most thermal conductors are made of which material?
Answer:
Most are made of copper.
Explanation:
Answer: The answer is metal
Explanation:
I took the test:) np!
For the titration of 40.0 mL of 0.250 M acetic acid with 0.200 M sodium hydroxide, determine the pH when:
(a) 40.0 mL of base has been added
(b) 50.0 mL of base has been added
(c) 60.0 mL of base has been added
a) pH is approximately 13.10. b) pH will be slightly above 7, indicating a basic solution. c) pH will be higher than the pH at the equivalence point, further indicating a basic solution.
(a) When 40.0 mL of base (0.200 M sodium hydroxide) has been added to the 40.0 mL of 0.250 M acetic acid, we have a neutralization reaction between the acid and base. Acetic acid (CH3COOH) is a weak acid, and sodium hydroxide (NaOH) is a strong base.
To calculate the pH at this point, we need to determine the moles of acid and base present and determine the excess or deficit of either. Since acetic acid and sodium hydroxide react in a 1:1 ratio, the moles of acid are equal to the moles of base added.
Using the formula:
Moles = Volume (L) x Concentration (M)
The moles of acetic acid are:
Moles of acetic acid = 0.040 L x 0.250 mol/L = 0.010 mol
Since the moles of acetic acid and sodium hydroxide are equal, we have 0.010 mol of sodium hydroxide in 0.040 L.
To calculate the concentration of hydroxide ions, we divide the moles of sodium hydroxide by the total volume (80.0 mL or 0.080 L):
Concentration of OH- = 0.010 mol / 0.080 L = 0.125 M
Using the equation for the dissociation of water (Kw = [H+][OH-]), we can calculate the concentration of H+ ions:
Kw = [H+][OH-]
1.0 x 10^-14 = [H+][0.125]
[H+] = 8.0 x 10^-14 M
Taking the negative logarithm of the concentration of H+ ions gives us the pH:
pH = -log[H+] = -log(8.0 x 10^-14) ≈ 13.10
(b) When 50.0 mL of base has been added, the calculation follows a similar process. The moles of acetic acid remain the same (0.010 mol), but the moles of sodium hydroxide increase to 0.0125 mol due to the additional volume (50.0 mL or 0.050 L) of base added.
Using the formula:
Moles = Volume (L) x Concentration (M)
The moles of sodium hydroxide are:
Moles of sodium hydroxide = 0.050 L x 0.200 mol/L = 0.010 mol
Since the moles of acetic acid and sodium hydroxide are equal (0.010 mol), we have reached the equivalence point of the titration. At the equivalence point, all the acetic acid has been neutralized by the sodium hydroxide, resulting in a solution of sodium acetate (CH3COONa) and water.
The pH at the equivalence point depends on the nature of the resulting salt, sodium acetate. Sodium acetate is the conjugate base of a weak acid, acetic acid, and is a weak base. The hydrolysis of sodium acetate in water leads to the formation of hydroxide ions, resulting in a slightly basic solution.
Therefore, at the equivalence point, the pH will be slightly above 7, indicating a basic solution.
(c) When 60.0 mL of base has been added, the calculation follows the same process as in part (b). At this point, the moles of sodium hydroxide are greater than the moles of acetic acid.
Using the formula:
Moles = Volume (L) x Concentration (M)
The moles of sodium hydroxide are:
Moles of sodium hydroxide = 0.060 L x 0.200 mol/L = 0.012 mol
Since the moles of sodium hydroxide (0.012 mol) are greater than the moles of acetic acid (0.010 mol), there is an excess of base present in the solution.
The excess base, sodium hydroxide, will result in a basic solution. The pH will be higher than at the equivalence point, indicating a stronger basic character.
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Which of the following is NOT true of elliptical galaxies?
A)They contain some older stars
B)They are oval in shape
C)They have a bright bulge in the center
D)Many new stars are being formed
its just 8th grade science. also add me on ig: im._em not to
promote or anything... comment ur ig and ill follow you ig
Answer:
its b there circle e not oval
Explanation:
The shape of elliptical galaxies is ellipsoid and not oval shape. They contain more older stars and formation of new stars is hard in the case of elliptical galaxies. Hence, the statement which is not true is options B and D.
What is galaxy?Galaxy is a group of stars, dust and dark matter which are joined together by a force of gravitation. There are billions of galaxies in the universe and they each contains trillions of stars.
The galaxies are of different shapes, force and light. Spiral, elliptical, oval etc are some of them. The light energy and gravitational pull of each of these galaxies differ from each other. The galaxie near to earth is milky way.
The elliptical galaxies are mainly composed of older stars and dust. They have a shape of ellipsoid. Formation of new stars in ellipsoid galaxies is rare. Thus options B and D are not true.
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A person accidentally swallows a drop of liquid oxygen, O2(l), which has a density of 1.149 g/mL. Assuming the drop has a volume of 0.053 mL, what volume of gas will be produced in the person's stomach at body temperature (37°C) and a pressure of 1.0 atm?
Answer:
First, let's determine how many moles of oxygen we have.
Atomic weight oxygen = 15.999
Molar mass O2 = 2*15.999 = 31.998 g/mol
We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml
Since the density is 1.149 g/mol,
we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2
Divide the number of grams by the molar mass to get the number of moles 0.17235 g / 31.998 g/mol = 0.005386274 mol
Now we can use the ideal gas law. The equation PV = nRT where P = pressure (1.0 atm) V = volume n = number of moles (0.005386274 mol) R = ideal gas constant (0.082057338 L*atm/(K*mol) ) T = Absolute temperature ( 30 + 273.15 = 303.15 K)
Now take the formula and solve for V, then substitute the known values and solve.
PV = nRT V = nRT/P V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm V = 0.133987239 L*atm / 1.0 atm V = 0.133987239 L
So the volume (rounded to 3 significant figures) will be 134 ml.
The volume of the gas that will be produced in the person's stomach at body temperature (37°C) and a pressure of 1.0 atm is 48.36 mL
We'll begin by calculating the mass of the liquid oxygen. This can be obtained as follow:
Density = 1.149 g/mL
Volume = 0.053 mL
Mass =?Mass = Density × Volume
Mass of O₂ = 1.149 × 0.053
Mass of O₂ = 0.060897 gNext, we shall determine the number of mole in 0.060897 g of O₂.
Mass of O₂ = 0.060897 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mole of O₂ =?
Mole = mass / molar mass
Mole of O₂ = 0.060897 / 32
Mole of O₂ = 0.0019 moleFinally, we shall determine the volume of the gas produced in the stomach. This can be obtained as follow:
Mole of O₂ (n) = 0.0019 mole
Temperature (T) = 37 °C = 37 + 273 = 310 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L /Kmol
Volume (V) =? PV = nRT1 × V = 0.0019 × 0.0821 × 310
V = 0.04836 L
Multiply by 1000 to express in mL
V = 0.04836 × 1000
V = 48.36 mLTherefore, the volume of the gas produced in the person's stomach is 48.36 mL
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8. What is the mass of copper in a sample of copper(I) chloride weighing 6.93 g ?*
Answer:
4.5g
Explanation:
Given parameters:
Mass of copper(i)chloride = 6.93g
Unknown:
Mass of copper = ?
Solution:
Formula of the compound = CuCl
atomic mass of Cu = 63.6g/mol, atomic mass of Cl = 35.5g/mol
Molecular mass = 63.6 + 35.5 = 99.1g/mol
So,
The mass of copper = [tex]\frac{63.6}{99.1}[/tex] x 6.93 = 4.5g
A doctor sees 10 patients in one day. The following is a list of their ailments. Patient 1 - seasonal allergies Patient 2 - common cold Patient 3 - sinus infection Patient 4 - seasonal allergies Patient 5 - chronic heartburn Patient 6 - seasonal allergies Patient 7 - migraines Patient 8 - back pain Patient 9 - broken wrist Patient 10 - chronic heartburn Which of the ailments listed had a frequency of three?
Answer:
seasonal allergies
Explanation:
The ailments listed had a frequency of three is seasonal allergies. Thus, 1st is the correct option.
What is seasonal allergy?Allergy is an infection caused due to entrance of some unwanted allergy causing components in body and they cause sneezing, coughing, ittiching and other symptoms that make trouble for the patient.
Seasonal allergy is the form of allergy that occurs in a particular season and they affect the individual in a particular season only.
Allergic substance can be anything it means allergy is experienced by any substance like some people are allergic from wheat, some are allergic from dust and likewise there are different allergy causing substances present.
In case of allergy, anti allergic medicines are given to the patient to avoid serious condition.
Therefore, the ailments listed had a frequency of three is seasonal allergies. Thus, 1st is the correct option.
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Hydrocarbons pollute the Earth's oceans, threatening the marine environment.
1. Where fo hydrocarbons come from? Identify two sources.
2. Where do the contaminants accumulate, and what damage do they do?
3. Oceans are much larger than lakes, but they are equally vulnerable to pollution. How does pollution from human activity reach the ocean? Exaplain answers by giving at least two examples of ocean contamination.
Hydrocarbons come from natural sources like the Earth's crust and human-made sources such as burning fossil fuels. They can harm marine life through toxicity and habitat destruction. Pollution reaches the ocean through runoff, discharge, and oil spills, among other pathways.
1. Hydrocarbons come from natural and human-made sources. Two common sources of hydrocarbons are:
a) Natural Sources: Hydrocarbons are naturally present in the Earth's crust and can be released into the environment through natural processes such as volcanic activity, erosion of rocks, and seepage from underground oil and gas deposits.
b) Human-Made Sources: Human activities also contribute significantly to the release of hydrocarbons. Some examples include the burning of fossil fuels for transportation and energy production, industrial processes, and accidental spills from oil tankers or offshore drilling operations.
2. Contaminants, including hydrocarbons, can accumulate in various parts of the ocean, such as surface waters, sediments, and marine organisms. When hydrocarbons enter the marine environment, they can have several damaging effects, including:
a) Toxicity: Hydrocarbons can be toxic to marine organisms, affecting their growth, reproduction, and overall health. This toxicity can disrupt the balance of ecosystems and harm the biodiversity of marine species.
b) Habitat Destruction: Hydrocarbons can also contaminate and degrade habitats, such as coral reefs, seagrass beds, and mangrove forests. These habitats provide essential resources and shelter for marine organisms, and their destruction can have cascading effects on the entire ecosystem.
3. Pollution from human activities can reach the ocean through various pathways. Here are two examples of ocean contamination caused by human activity:
a) Runoff and Discharge: When it rains, water runs over the land, picking up pollutants along the way, including hydrocarbons. This runoff can carry pollutants from urban areas, agricultural lands, and industrial sites into rivers and eventually into the ocean. Additionally, untreated sewage and industrial wastewater discharged directly into rivers and coastal areas can introduce hydrocarbons and other pollutants into the marine environment.
b) Oil Spills: Accidental oil spills from oil tankers, offshore drilling operations, or pipeline ruptures can release a large amount of hydrocarbons directly into the ocean. These spills can have catastrophic consequences, causing immediate and long-term damage to marine ecosystems, including coastal areas, beaches, and wildlife.
It is important to note that these are just two examples, and there are other pathways through which pollution can reach the ocean, such as atmospheric deposition and deposition of microplastics. Each pathway has its unique characteristics and potential impacts on the marine environment.
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what is a constant in an experiment?
Science experiments usually include an independent variable, dependent variable, and control.Science experiments also include something called constants. A constant is the part that doesn't change during the experiment.A constant variable does not change. A control variable on the other hand changes, but is intentionally kept constant throughout the experiment so as to show the relationship between dependent and independent variables.A scientific control is an experiment or observation designed to minimize the effects of variables other than the independent variable. This increases the reliability of the results, often through a comparison between control measurements and the other measurements
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Calculate the theoretical mass of NaBH4 needed to reduce 100. mg of benzil to (+) and (-) benzoin.
To reduce 100 mg of benzil to benzoin, the theoretical mass of NaBH4 needed is approximately 0.423 g.
:
To calculate the theoretical mass of NaBH4 required, we need to consider the stoichiometry of the reaction and the molar masses of the compounds involved.
The balanced chemical equation for the reduction of benzil using NaBH4 is:
C14H10O2 + 4 NaBH4 -> C14H12O2 + 4 NaBO2 + 8 H2
From the equation, we can see that 1 mole of benzil (C14H10O2) reacts with 4 moles of NaBH4 to produce 1 mole of benzoin (C14H12O2).
First, let's calculate the molar mass of benzil:
Molar mass of benzil (C14H10O2) = (14 * 12.01 g/mol) + (10 * 1.01 g/mol) + (2 * 16.00 g/mol) = 228.23 g/mol
Next, we calculate the amount of benzil in moles:
Mass of benzil = 100 mg = 0.100 g
Moles of benzil = mass / molar mass = 0.100 g / 228.23 g/mol ≈ 0.000438 mol
Since the stoichiometry of the reaction is 1:4 (benzil to NaBH4), the moles of NaBH4 required can be calculated as follows:
Moles of NaBH4 = 4 * moles of benzil ≈ 4 * 0.000438 mol ≈ 0.00175 mol
Finally, we calculate the mass of NaBH4:
Molar mass of NaBH4 = (1 * 22.99 g/mol) + (1 * 1.01 g/mol) + (4 * 1.01 g/mol) + (1 * 4.00 g/mol) = 37.83 g/mol
Mass of NaBH4 = moles of NaBH4 * molar mass of NaBH4 = 0.00175 mol * 37.83 g/mol ≈ 0.0661 g ≈ 0.423 g (rounded to three decimal places)
Therefore, the theoretical mass of NaBH4 needed to reduce 100 mg of benzil to benzoin is approximately 0.423 g.
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Which sentence describes all atoms of one element?
1.) they have the same number of isotopes?
2.) they have the same number of neutrons?
3.) they have the same number of electrons?
4.) they have the same number of protons?
Answer:
4. they have the same number of protons
Explanation:
while all the other particles and attributes can be changed, protons cannot.
