Can anybody please help me with this question

the value of the expression is 0.

To solve this expression, we can use the PEMDAS order of operations:

since there are no Parentheses and Exponents we move to multiplication and division

-2(-3) + 27 ÷ (-3) + 3 = 6 + (-9) + 3

6 + (-9) + 3 = 0

As a result, the equation has a value of 0.

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("="). For illustration, 2x - 5 = 13.

Here,

5 and 13 are expressions for 2x.

These two expressions are joined together by the sign "=".

Two expressions are combined in an equation using an equal symbol ("="). The "left-hand side" and "right-hand side" of the equation are the two expressions on either side of the equals sign. Typically, we consider an equation's right side to be zero. As we can balance this by deducting the right-side expression from both sides' expressions, this won't reduce the generality. The two most well-known groups of equations in algebra are linear equations and polynomial equations. P(x) = 0 can be used to represent polynomial equations with a single variable. P is a polynomial, and axe + b = 0 is the standard form for linear equations. Here, are the parameters a and b.

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Coordinates of the vertices of the pre-image are (-4, 4), (-1, 9), and (1, 9).

And the graph is given below.

A transformation of a triangle can refer to any process that changes the size, position, or shape of a triangle.

Translation involves moving the triangle without changing its shape or size. To translate a triangle, you can simply move it in any direction by a certain distance, without rotating or flipping it.

Here we have

From the graph

The coordinates of the triangle are (1, 1) (4, 6), and (6, 3)

Given T < -5, 3 > (x, y)

Hence, the coordinates of the pre-image are

(1, 1) => (1 - 5,  1 + 3)  = (-4, 4)  

(4, 6) => (4 - 5, 6 + 3) = (-1, 9)

(6, 3) => (6 - 5,  3+3) = (1, 6)

Hence,

Coordinates of the vertices of the pre-image are (-4, 4), (-1, 9), and (1, 9).

And the graph is given below.

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Yes, the graph represents a function.

A relation is a function if it has only One y-value for each x-value.

The given ordered pairs from the given graph are (-7, 3), (-3, -3), (0,1), (2, 4), (3, -1), (5, -6)

The given graph represents a relation.

Since each value of x has unique y value.

So the given graph represents a function.

Hence, yes the graph represents a function.

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[2x^(2) + 7x + 6 = 0] has C. two real solutions

The quadratic equation 2[tex]x^{(2)}[/tex] + 7x + 6 = 0 has two real solutions. To solve, use the Quadratic Formula:

x = [-b ± √([tex]b^{2}[/tex] - 4ac)]/2a  

Where a = 2, b = 7, and c = 6.

So, x = [-7 ± √([tex]7^{2}[/tex]- 4(2)(6))]/2(2)  

x = [-7 ± √(49 - 48)]/4  

x = [-7 ± 1]/4  

x = -3/2 and x = 1/2  


Therefore, the equation has two real solutions: x = -3/2 and x = 1/2.

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Answer:

34

Step-by-step explanation:

3dds

Answer: To calculate the incidence of cervical cancer among women in the United States in 2019, we need to divide the number of new cases (346) by the total population at risk (i.e., the number of women without cervical cancer) and then multiply by 100,000 to express the result per 100,000 women.

Number of women without cervical cancer = Total number of women - Number of women with cervical cancer

Number of women without cervical cancer = 166,238,619 - 295,382

Number of women without cervical cancer = 165,943,237

Incidence of Cervical Cancer = (New cases / Number of women without cervical cancer) x 100,000

Incidence of Cervical Cancer = (346 / 165,943,237) x 100,000

Incidence of Cervical Cancer = 0.21 per 100,000 women

Therefore, the incidence of cervical cancer among women in the United States in 2019 was 0.21 per 100,000 women.

Step-by-step explanation:

If the mean of five scores is 27, then the number 33 must be added to the previous five scores to make the mean of six scores as 28.

It is given that mean of five scores is 27. If the unknown number x is added to the five scores, the new mean becomes 28. To calculate the value of x, the following equations are considered.

Let us say that the five scores are A, B, C, D and E.

∴ Mean of five scores = (A+B+C+D+E)/ 5 = 27

⇒ (A+B+C+D+E) = 27 × 5 = 135

Now, if sixth score x is added, then mean score becomes 28.

⇒ (A+B+C+D+E+x)/ 6 = 28

⇒ (A+B+C+D+E+x) = 28×6 = 168

Putting the value of (A+B+C+D+E) in above equation, we get:

135 + x = 168

x = 168 - 135 = 33

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The two real solutions of the equation are:

z=32.5/18 ± √(81+32.5z)/18

The equation 18z2-65z-72=0 can be solved by completing the square. We start by taking half of the coefficient of the squared term and squaring it:

(18/2)2 = (9)2 = 81

We then add 81 to both sides of the equation to complete the square:

18z2-65z-72+81=0+81

18z2-65z+9=81

Now, we take half of the coefficient of the z-term, subtract it from both sides of the equation, and add it in the parentheses:

18z2-(65/2)z+(65/2)z+9=81+(65/2)z

(18z-32.5)2=81+32.5z

We now have a perfect square on the left side, so we can simplify:

(18z-32.5)2=81+32.5z

18z-32.5=±√(81+32.5z)

18z=32.5±√(81+32.5z)

z=32.5/18 ± √(81+32.5z)/18

Therefore, the two real solutions of the equation are:

z=32.5/18 ± √(81+32.5z)/18

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The inequality is given as 12x ≥ 15,000

An inequality in mathematics is a statement that compares two quantities or expressions using inequality symbols such as "<" (less than), ">" (greater than), "<=" (less than or equal to), ">=" (greater than or equal to), or "≠" (not equal to).

The least number of rides needed for 15000 people is given as 12x ≥ 15,000.

12x ≥ 15,000.

x ≥ 15,000 / 12

x  ≥ 1250

The least number of rides needed for 15000 people is 1250.

If the park is open for 12 hours. 15000 / 12 is the number of persons that can ride in 1 hour

Hence it is not possible for the ride to have 15000 persons in a day

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The formula:

[tex]\huge\begin{array}{ccc}C=2\pi r\end{array}[/tex]

[tex]r[/tex] - radius

We have:

[tex]r=6.5m[/tex]

Substitute:

[tex]C=2\cdot6.5m\cdot\pi=13\pi m[/tex]

Use: [tex]\pi\approx3.14[/tex]

[tex]C\approx13m\cdot3.14=40.82m[/tex]

Answer:40.82 meters

The circumference of the circle.

The formula:

- radius

SOLUTION:

We have:

Substitute:

Use:

Step-by-step explanation:

Give bro above me the good stuff

The factored form of the given polynomial is 5(x-9)(x-2).

To factor the given polynomial, 5x^(2)-55x+90, we first need to factor out the greatest common factor (GCF) which is 5. Factoring out the GCF will make the polynomial easier to factor completely.

5x^(2)-55x+90 = 5(x^(2)-11x+18)

Now, we need to factor the polynomial inside the parentheses completely. We can do this by finding two numbers that multiply to give us the constant term (18) and add to give us the coefficient of the x term (-11).

The two numbers that fit these criteria are -9 and -2. So, we can factor the polynomial inside the parentheses as follows:

x^(2)-11x+18 = (x-9)(x-2)

Putting it all together, we get the completely factored form of the given polynomial:

5x^(2)-55x+90 = 5(x-9)(x-2)

Therefore, the factored form of the given polynomial is 5(x-9)(x-2).

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The system of equations for the two plans is:

y = 8x + 25

y = 12x + 5

To write a system of equations for each plan, let:

x = number of month

y = Total amount

Equation of plan A:

one-time membership fee = initial value or y-intercept (b) = 8

Monthly fee per month = slope/unit rate (m) = 25

The equation would be y = 8x + 25

Equation of plan B:

one-time membership fee = initial value or y-intercept (b) = 12

Monthly fee per month = slope/unit rate (m) = 5

The equation would be y = 12x + 5

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Answer:

Step-by-step explanation:

Given: Length of the building = 78 ft

Scale = 1 in : 8 ft

To find: Length of the building in the drawing

Now we have the scale where

8 ft = 1 inch

So using unit rule

1 ft = (1/8) in

So

78 ft = (1/8)(78) in = 9.75 inch

So length of the building in the drawing is 9.75 inch.

The length of the drawing is 9.75 inches.

To calculate the length of the drawing, find out how many inches correspond to 78 feet using the scale provided.

Since the scale is 1in:8ft, this means that 1 inch on the drawing represents 8 feet in real life.

To determine the length of the drawing, divide the length of the building by the scale factor:

Length of drawing = Length of building / Scale factor

Length of drawing = 78 ft / 8

Length of drawing = 9.75 inches

Hence, the drawing is 9.75 inches long.

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The discriminant is positive (D = 8), the equation x² - 6x + 7 = 0 has two distinct real solutions, which supports Jason's claim.

The quadratic equation's roots are represented geometrically by the discriminant. The equation has two separate real roots if the discriminant is positive, and as a result, the graph of the quadratic function meets the x-axis twice. The quadratic function's graph crosses the x-axis precisely one time if the discriminant is zero, which indicates that the equation has one real root.

To find the discriminant of the given equation, we can substitute the values of a, b, and c into the formula:

D = (-6)² - 4(1)(7) = 36 - 28 = 8

Since the discriminant is positive (D = 8), the equation x² - 6x + 7 = 0 has two distinct real solutions, which supports Jason's claim.

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The complete question is:

The possible solutions from the triangle does not exist

From the question, we have the following parameters that can be used in our computation:

B = 50 degrees

a = 102 units

b = 41 units

The angle A is calculated as

sin(A)/a = sin(B)/b

So, we have

sin(A)/102 = sin(50)/41

This gives

sin(A) = 102 * sin(50)/41

Evaluate

sin(A) = 1.9057

Take the arc sin of both sides

A = DNE

This is so because the solution does not exist for the angle A

By extension, the values of angle C and side c cannot be calculated

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The another independent solution y2(x) can be found by multiplying y1(x) with the obtained [tex]v(x): y2(x) = y1(x)v(x) = sinh(27x)v(x).[/tex]

To find another independent solution to the given differential equation, [tex]y(x) + p(x)y'(x) + q(x)y(x) = 0[/tex], with one solution [tex]y1(x) = sinh(27x)[/tex], we can use the formula for finding a second linearly independent solution using the Wronskian.

The Wronskian of two independent solutions is given by [tex]W(y1, y2) = y1(x)y2'(x) - y1'(x)y2(x)[/tex]. Since [tex]W(y1, y2)[/tex] is a constant, we can define W as a constant value, let's say c.

Introduce a new function v(x) such that [tex]y2(x) = y1(x)v(x), so y2(x) = sinh(27x)v(x).[/tex] Compute the derivative of y2(x): [tex]y2'(x) = 27cosh(27x)v(x) + sinh(27x)v'(x)[/tex]. Substitute [tex]y1(x), y1'(x), y2(x), and y2'(x)[/tex]into the Wronskian equation: c = [tex]sinh(27x)[27cosh(27x)v(x) + sinh(27x)v'(x)] - 27cosh(27x)sinh(27x)v(x)[/tex]

Divide by [tex]sin(27x)cos(27x)[/tex] to simplify the equation: c / [tex](27sinh(27x)cosh(27x)) = v(x) + (1/27)v'(x).[/tex] Rearrange the equation to obtain a first-order linear differential equation:  [tex]v'(x) - 27v(x) = 27c / sinh(27x)cosh(27x)[/tex]

Solve the differential equation for[tex]v(x)[/tex] (you can use an integrating factor or another method). Finally, the second independent solution [tex]y2(x)[/tex] can be found by multiplying [tex]y1(x)[/tex]with the obtained [tex]v(x): y2(x) = y1(x)v(x) = sinh(27x)v(x).[/tex]

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The error made by the student is instead of taking +4 as common he has taken - 4 as common.

To factor an expression by grouping, we need to look for groups of terms that have common factors. Then, we factor out those common factors from each group and see if there is a common factor that can be further factored out.

Here we have

6x² ​ – x​ – 12  

The above expression can be factorized as follows

=> 6x² – x – 12

= 6x² – 9x + 8x – 12        [ Splitting the middle term ]

= 3x(2x – 3) + 4(2x – 3)     [ Grouping the terms ]  

= (3x + 4)(2x – 3)  

Hence, the factors of given expression are (3x + 4) and (2x – 3)  

The error made by the student is in step 3 instead of taking +4 as common he has taken - 4 as common which doesn't give the common factors in the next step taken.    

Therefore,

The error made by the student is instead of taking +4 as common he has taken - 4 as common.

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Yes, the equation y = 3/4(x) represent a proportional relationship because its line passes through the origin.

In Mathematics, a proportional relationship is a type of relationship that produces equivalent ratios and it can be modeled or represented by the following mathematical expression:

y = kx

Where:

Generally speaking, the graph of any proportional relationship such as the linear equation is characterized by a straight line that passes through all the points and the origin, which is denoted by the ordered pair (0, 0).

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Answer: Stem-and-leaf plot, because you can see each individual data point.

Step-by-step explanation:im taking the test.

Answer:stem and leaf plot

If a rectangular prism has dimensions of 1.5 feet by 3.5 feet by 2 feet, its volume, expressed in cubic feet, is 10.5 cubic feet.

The rectangular prism's measurements are —

3.5 feet in length

1.5 feet wide in Size

Height is two feet.

The volume of the rectangular prism is calculated by multiplying these dimensions collectively.

Volume equals length, width, and height, or 3.5 feet, 1.5 feet, and 2 feet.

= 10.5 cubic feet of volume

Hence, the rectangular prism has a volume of 10.5 cubic feet.

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Answer:

See below.

Step-by-step explanation:

I'm sure the question is asking to solve for ∠BDC, but we'll solve for all of the angles.

We should note that we have a Given Exterior Angle.

An Exterior Angle is an angle that is formed by extended lines.

An exterior angle is equal to the combined sum of the two nonadjacent, and interior angles.

Using what we learned, ∠BCD and ∠CDB will equal ∠DBE°.

Let's turn this problem into an equation.

60° + ∠BDC = 120°
Subtract 60 from both sides.

∠BDC = 60°.

We can also identify that ∠CBD is a linear pair with ∠DBE.

A Linear Pair is 2 adjacent angles that add up to 180°. Linear Pairs are straight lines with one line intersecting in between.

Meaning that ∠CBD + ∠DBE = 180°.

∠CBD + 120° = 180°.

∠CBD = 60°.

We can identify that this triangle is an Equilateral Triangle. An Equilateral  Triangles is a triangle that has all congruent sides and angles.

Our final answers are;

∠BDC = 60°.

∠CBD = 60°.

Answer:

Let's first find the volume of the original cuboidal box:

Volume = Length x Width x Height = 3 x 3 x 2 = 18 cubic units

We can then set up an equation to relate the volume of the original box to the volume of the new cuboid:

Volume of new cuboid = Volume of original box

Let's call the length and height of the new cuboid "x" (since we know that the length and height are the same). We know that the width of the new cuboid is 15 units. Therefore, we can write:

Volume of new cuboid = Length x Width x Height = x x 15 x x = 15x^2

Now we can set up the equation:

15x^2 = 18

Dividing both sides of the equation by 15 gives:

x^2 = 18/15

Simplifying the right side of the equation gives:

x^2 = 1.2

Taking the square root of both sides of the equation gives:

x ≈ 1.095

Therefore, the length and height of the new cuboid are approximately 1.095 units.

Answer:

Step-by-step explanation:

So when x is translated the + means going right. With y the - means going down. So P is gonna be (-9,-1), Q(-4,0) , and R (-2,-1). See if that helps but I think it is that, but I have another idea what it could be but see if this is right.

(a) The area of a triangle can be found using the formula A = (1/2)bh, where b is the base and h is the height. In this case, the base is one of the sides with length 13 or 15, and the height is the altitude with length 12. Using the formula, the area is A = (1/2)(13)(12) = 78 square units.

(b) The area of a triangle can also be found using Heron's formula, which is A = √[s(s-a)(s-b)(s-c)], where s is the semiperimeter of the triangle, and a, b, and c are the lengths of the sides. In this case, s = (10+10+16)/2 = 18, so the area is A = √[18(18-10)(18-10)(18-16)] = 80 square units.

(c) Using Heron's formula again, s = (5+12+13)/2 = 15, so the area is A = √[15(15-5)(15-12)(15-13)] = 30 square units.

(d) The area of an isosceles triangle can be found using the formula A = (1/2)bh, where b is the base and h is the height. In this case, the base is 30 and the height can be found using the Pythagorean theorem, h = √(17^2 - (30/2)^2) = 8. So the area is A = (1/2)(30)(8) = 120 square units.

(e) The area of an isosceles triangle can also be found using the formula A = (1/2)ab sin C, where a and b are the lengths of the two equal sides and C is the vertex angle. In this case, a = b = 20 and C = 68°, so the area is A = (1/2)(20)(20) sin 68° = 190.4 square units.

(f) Using the same formula as in (e), but with a = b = 30 and C = 62°, the area is A = (1/2)(30)(30) sin 62° = 675 square units.

(g) The area of a triangle inscribed in a circle can be found using the formula A = (1/2)ab sin C, where a and b are the lengths of the two sides and C is the angle between them. In this case, one side is a diameter with length 8 (2 times the radius of 4), another side has an unknown length, and the angle between them is 30°. The area is A = (1/2)(8)(b) sin 30° = 2b square units.

(h) The area of a triangle cut off by a line parallel to the base can be found using the formula A = (1/2)bh, where b is the length of the base and h is the height. In this case, the base is 10 and the height is 5 - 6 = -1, so the area is A = (1/2)(10)(-1) = -5 square units.

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The volume of the small can is  25.12 inches cube.

Mrs. Roberts' dog, Rover, loves to eat peanuts. A large can of peanuts has a diameter of 4 inches and a height of 6 inches. The small can that she plans to purchase has the same diameter but is 1/3 of the height of the large can.

Therefore, the approximate volume of the small can can be found as follows:

Hence,

volume of the small can = πr²h

where

Therefore,

r = 4 / 2 = 2 inches

h = 1 / 3 (6) = 2 inches

Hence,

volume of the small can = 3.14 × 2² × 2

volume of the small can = 3.14 × 4 × 2

volume of the small can = 3.14 × 8

volume of the small can = 25.12 inches cube

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Answer:

Step-by-step explanation:

(h)

[tex]KE= \frac{1}{2}mv^{2} \\KE=\frac{mv^{2} }{2} \\2KE=mv^{2}\\2KEm=v^{2} \\v=\sqrt{2KEm}[/tex]

(g)

[tex]s=\frac{(u+v)t}{2} \\2s=(u+v)t\\\frac{2s}{t}=u+v\\u= \frac{2s}{t}-v[/tex]

(i)

[tex]s=ut+\frac{1}{2} at^{2} \\s-ut=\frac{at^{2} }{2} \\2s-2ut=at^{2} \\\sqrt{2s-2ut}=at\\a=\sqrt{2s-2ut}-t[/tex]

(j)

[tex]\frac{pV}{T} =nR\\T=\frac{pV}{nR}[/tex]

(k)

[tex]a^{2} -b^{2} +c^{2} \\a^{2} +c^{2} =b^{2} \\b=\sqrt{a^{2} +c^{2} }[/tex]

(i)sinθ[tex]=\frac{a}{b}[/tex]

       θ=[tex]\frac{a}{sin(b)}[/tex]

Answer:  1.09 is closer to 1

The area of the trapezoid is 65.16 metres squared.

The area of a trapezoid can be found as follows:

area of a trapezoid = 1 / 2 (a + b)h

where

Therefore,

a = 5metres

b = 13.1 metres

h = 7.2 metres

Hence,

area of a trapezoid = 1 / 2 (5 + 13.1) 7.2

area of a trapezoid = 1 / 2 (18.1)7.2

area of a trapezoid = 130.32 / 2

Therefore,

area of a trapezoid = 65.16 metres squared

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the real solutions to this equation are x = 2√2 and x = -2√2.

Solution:

(a) -n + √(6n + 19) = 2

To find the solution algebraically, we need to isolate the radical on one side of the equation and then square both sides to get rid of the radical.

-n = 2 - √(6n + 19)

(-n - 2)^2 = (2 - √(6n + 19))^2

n^2 + 4n + 4 = 4 - 4√(6n + 19) + 6n + 19

n^2 - 2n - 19 = -4√(6n + 19)

(n^2 - 2n - 19)^2 = (-4√(6n + 19))^2

n^4 - 4n^3 - 18n^2 + 76n + 361 = 96n + 304

n^4 - 4n^3 - 114n^2 + 76n + 57 = 0

This is a quartic equation that can be solved using the Rational Root Theorem or by factoring. However, this equation does not have any real solutions. Therefore, there are no real solutions to this equation.

(b) x^4 - 20x^2 + 64 = 0

This equation can be factored as:

(x^2 - 8)^2 = 0

x^2 - 8 = 0

x^2 = 8

x = ±√8

x = ±2√2

Therefore, the real solutions to this equation are x = 2√2 and x = -2√2.

Remember to check your solutions by plugging them back into the original equation and seeing if they make the equation true.

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Answer:

parallelogram

Step-by-step explanation: