Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!

Answer:

[tex] \huge \bold \blue{ \underline{ answer}}[/tex]

The splitting up of light into its constituent colours while passing from one medium to the other is called dispersion.

Answer:

[tex]\huge\boxed{\sf a = 1200\ m/s\²}[/tex]

Explanation:

Given Data:

Initial Velocity = Vi = 40 m/s

Final Velocity = Vf = 80 m/s

Distance = S = 200 m

Required:

Acceleration = a = ?

Formula:

2aS = Vf² - Vi² (THIRD EQUATION OF MOTION)

Solution:

2a (200) = (80)² - (40)²

400a = 6400 - 1600

400a = 4800

Divide 400 to both sides

a = 4800 / 400

a = 1200 m/s²

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

The locations where the riders feel less than their normal weight are Location A, Location C and Location D.

The given parameters;

The normal weight of the riders is calculated by applying Newton's second law of motion as follows;

W = mg

W = 9.8m

The apparent weight of the riders for the upward acceleration is calculated  as follows;

[tex]R = m(g + a)[/tex]

The apparent weight of the riders for the downward acceleration is calculated  as follows;

[tex]R = m(g - a)[/tex]

The apparent weight of the riders at location A is calculated as follows;

[tex]R_ A = m(9.8 - 10)\\\\R_ A = -0.2 m[/tex]

The apparent weight of the riders at location B is calculated as follows;

[tex]R_B = m(9.8 + 2)\\\\R_B = 11.8 m[/tex]

The apparent weight of the riders at location C is calculated as follows;

[tex]R_C = m(9.8 - 6)\\\\R_C = 3.8 m[/tex]

The apparent weight of the riders at location D is calculated as follows;

[tex]R_D = m(9.8 - 12)\\\\R_D = -2.2 m[/tex]

The apparent weight of the riders at location E is calculated as follows;

[tex]R_E = m(9.8 + 6)\\\\R_E = 15.8 m[/tex]

Thus, the locations where the riders feel less than their normal weight are;

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Answer:

Your parents or anyone in your ancestry.

Explanation:

Answer:

n/a

Explanation:

No diagram found. I am willing to help

In a hand-cranked flashlight first, mechanical energy produced with the hand is converted into electrical energy then the electrical energy is converted into light energy, therefore the correct answers are the option B and option E.

The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.

The expression for total mechanical energy can be given as follows

ME= PE + KE

As given in the problem, the energy transfer diagram for a piece of equipment is shown. You are using a hand-cranked flashlight. One minute of cranking typically provides about 30 to 60 minutes of light.

The transformation that is taking place is the mechanical energy to electrical energy and then electrical energy to light energy.

Thus, the correct options are option are B and E.

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Hi there!

We can use the following:

W = ΔKE = F · d

Find the work done on the cart:

W = 200 · 10 = 2000 J

Now, this is equal to the change in kinetic energy of the object. Its initial kinetic energy is 0 J since it starts from rest, so:

2000J = KEf - KEi

KE is given as:

[tex]KE = \frac{1}{2}mv^2[/tex]

2000J = 1/2(55)v²

4000 = 55v²

√(4000/55) = 8.53 m/s

Answer:

35.2644

I suppose mew is refractive index

Explanation:

( sin i ) / (sin r) = refractive index

( sin 60) / (sin r) = 1.5

( sin 60) / 1.5 =sin r

r=35.844

sorry if I'm wrong

Answer:

oK so  here's  what you should do is  add .09 and 0.6

Explanation:

People often wants to be recognized for their achievement. The true statement is that People from individualistic cultures may find awards that single them out as more reinforcing than people from

collectivistic cultures.

It is often based on the individual self and its specific qualities that distinguishes one from others.

Collectivism is simply known as a cultural system that place emphasis on the needs of the group/society more than our self need self.

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Answer:

  2.5 m/s east

Explanation:

Let east be the positive direction for velocity.

The change in momentum of the 0.75 kg model car is ...

  m1·v2 -m1·v1 = (0.75 kg)(11 m/s) -(0.75 kg)(-9 m/s)

  = (0.75 kg)(20 m/s) = 15 kg·m/s

The change in momentum of the 2.0 kg model car is the opposite of this, so the total change in momentum is zero.

  m2·v2 -m2·v1 = (2 kg)(v2 m/s) -(2 kg)(10 m/s) = 2(v2 -10) kg·m/s

The required relation is ...

  15 kg·m/s = -2(v2 -10) kg·m/s

  -7.5 = v2 -10 . . . . divide by -2

  2.5 = v2 . . . . . . . add 10

The velocity of the model truck after the collision is 2.5 m/s east.

Answer:

D) It cannot be determined without more information.​

Explanation:

Velocity is a vector meaning it has both magnitude and direction.

Force and acceleration are also vectors.

Without knowing the directions of each, we cannot know if the mass has a speed (scalar value) change.

We can know that the mass will have a velocity change at the rate of 2 m/s² in the direction of the applied force.

If that force is applied in the direction of initial velocity, the velocity (and speed) will increase in magnitude in the same direction.

If that force is applied opposite of the initial velocity, the  the velocity (and speed) will decrease in magnitude in the same direction. If the acceleration lasts long enough, velocity will eventually become zero and then become negative. At the same time, speed will become zero, and then increase again as speed is the absolute value of the magnitude of velocity.

If the force is applied at any other angle, both the velocity and the speed will change in both magnitude and direction.

The pulleys will reduce the mechanical force (effort) required to lift the block and will change the mechanical advantage.

The pulley system is a type of simple machine which makes our work easier and faster by overcoming a large load when a small force (effort) is applied to it.

The efficiency of a machine is calculated as follows;

[tex]Eff = \frac{M.A}{V.R} \times 100\%[/tex]

where;

[tex]M.A = \frac{load}{effort}[/tex]

The velocity ratio of a pulley system = number of pulleys

The velocity ratio of a pulley system increases with increase in the number of pulleys.

Thus, we can conclude that the pulleys will reduce the mechanical force (effort) required to lift the block and will change the mechanical advantage.

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Answer:

Energy is conserved.

Explanation:

Without friction, kinetic energy and gravity potential energy are always swapping back and forth.

The block slides down an inclined friction-less track to a infinite hill that the block begins to climb and slow down, in which the energy is conserved.

Friction refers to the force that prevents hard surface, fluid layers, as well as material elements from sliding against each other.

There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in contact solid surfaces.

It is thought to be caused by the interactions of tiny bumps on surfaces rubbing against one another.

The bumps on each surface bend and exert force on one another, making it difficult for the surfaces to slide over one another.

A block's speed increases while its acceleration remains constant as it slides down a frictionless incline. After being placed on a ramp inclined at an angle with the horizontal, a crate remains stationary.

Thus, the block slides beneath an inclined friction-less track to an unlimited hill, where it commences to climb as well as slow down, preserving energy.

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Answer:

Force is equal to the change in momentum per change in time.

Explanation:

That situation is described by Newton's Second Law of Motion. According to NASA, this law states, "Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration." This is written in mathematical form as Force = mass.

Answer:

Explanation:

F = ma

F = 55000 kg(10.4)

F = 572000 N

That is an amazingly large elephant, more like 11 elephants

A more typical mass for a single elephant would be 5000 kg with a weight on Saturn of 52000 N

Answer:

Explanation:

I will ASSUME this means torque about the dot.

3) 20(3) + 10(6) - 30(4) = 0 N•m

4) 10(0.5) - 6sin45(1) = -0.7573593... or about 0.76 N•m CCW

5) 25(3) - 40sin30(4) = -5 N•m or 5 N•m CCW

6) 15(3) - 12(2) - 10sin45(6) = -21.4264068... or about 21 N•m CCW

Answer:

Explanation:

E = mgh

mg = E/h

mg = 60/0.75 = 80 N

The acceleration due to gravity on Mars is 11.81 m/s².

The given parameters:

The equation of motion to determine the acceleration due to gravity on the moon is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2[/tex]

where;

Since the time measured is two way time, the new equation for the total distance traveled is calculated as;

[tex]v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{320 \times 27.1}{2} \\\\d = 4,336 \ m[/tex]

The acceleration due to gravity is calculated as follows;

[tex]s = vt + \frac{1}{2} gt^2\\\\4,336 = 0 \ + \ \frac{1}{2} \times g \times (27.1)^2\\\\4,336 = 367.21g\\\\g = \frac{4,336}{367.21} \\\\g = 11.8 1 \ m/s^2[/tex]

Thus, the acceleration due to gravity on Mars is 11.81 m/s².

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Answer:

i think your answer is this: the objects have no interactive with each other.

Explanation:

if you think about it tissue paper doesn't really have a static electrical charge if it does it is very weak so therefore cannot really attract or repel anything.

The change of sodium bicarbonate breaking down into sodium carbonate and water is a chemical change. The cooling of mercury until it is in the solid state is physical change. The correct option for 1 is A and for 2 is B.

A chemical change occurs as a consequence of a reaction, whereas a physical change occurs when transformation occurs forms but retains its chemical identity.

Chemical changes include burning, cooking, rusting, and rotting. Physical changes include boiling, melting, freezing, and shredding.

A physical change is required to a specimen of matter in which some of the material's properties change but the matter's identity does not.

Physical changes can be classified as either reversible or irreversible. Melting is a reversible physical change because the melted ice cube can be refrozen.

In the first case, sodium bicarbonate is breaking down and forming sodium carbonate and water, this implies a chemical change.

In the second case, mercury is just cooling down, changing its physical shape. So it is physical change.

Thus, the correct option for 1 is A and for 2 is B.

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Answer:

more likely it is to have gravity

it changes ever 9.8 m/sec2.

Answer:

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

Explanation:

In the middle, when the object was changing position at a constant velocity, the acceleration was 0. This is because the object is no longer changing its velocity and is moving at a constant rate.

The acceleration due to gravity would be 5.95 m/s²

A force is known to be a push or pull and it is the change in momentum per time. It can be expressed by using the relation.

From the parameters given:

By replacing the given values into the above equation, we can determine the acceleration.

∴

625 N = 105 kg × acceleration.

[tex]\mathbf{acceleration = \dfrac{625 \ N}{105 \ kg}}[/tex]

acceleration = 5.95 N/kg

acceleration = 5.95 m/s²

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Answer:  A) It has the same types of atoms on both sides of the reaction

arrow.

Explanation:  A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow.

Answer: Time (days) = 88, the (mass) = 0.2180

Explanation:

Time (days) = 88, the (mass) = 0.2180

0.8 seconds

Explanation:

time of flight = 2u/g

u=4m/s

g=10

= 8/10

= 0.8 sec

just a trial...not sure!!!

Given :

∅ = 60⁰

u = 4 m/s

g = 10m/s²

to find :

T = ?

Solution :

as per formula,

[tex]t = \frac{2u \: sin \theta}{g} [/tex]

now put the value : [tex]t \: = \frac{2 \times 4 \times sin \: 60}{10} [/tex]

as we know [tex] sin60 \: = \frac{ \sqrt{3} }{2} [/tex]

therefore,

[tex]t \: = \frac{8 \times \frac{ \sqrt{3} }{2} }{10} [/tex]

as we solve this we get,

[tex]t \: = \frac{ 2\sqrt{3} }{5} [/tex]

that's t = 0.69 sec

[tex]\sf\fbox\red{\:I \:hope \:it's \:helpful \:to \:you}[/tex]

Answer:

Explanation:

v² = u² + 2as

a = (v² - u²) / 2s

a = (93² - 0²) / (2(49))

a = 88.255102...

a = 88 m/s²

Explanation:

a) Here is the free-body diagram. Note that I included the components of the weight mg (shown in dotted arrows) for use in the other parts of the problem.

b) The component of the weight parallel to the plane (shown in the diagram as a dotted arrow along the x-axis) is [tex]mg\sin15[/tex] and it is equal to

[tex]mg\sin15 = (25\:\text{kg})(9.8\:\text{m/s}^2)\sin15 = 63.4\:\text{N}[/tex]

c) Applying Newton's 2nd law to the y-axis, we can write

[tex]y:\;\;\;N - mg\cos15 = 0 \Rightarrow N = mg\cos15[/tex]

[tex]N = (25\:\text{kg})(9.8\:\text{m/s}^2)\cos15 = 236.7\:\text{N}[/tex]

d) The component of the weight mg into the plane is the same as the normal force, hence it's also 236.7 N.

e) To solve for the coefficient of friction, we apply Newton's 2nd law to the x-axis:

[tex]x:\;\;\;mg\sin15 - F_f = 0[/tex]

[tex]\Rightarrow F_f = mg\sin15\;\;(2)[/tex]

where [tex]F_f[/tex] is the frictional force defined as [tex]F_f = \mu N[/tex] so we can use Eqn(1) on Eqn (2) to write

[tex]\mu (mg\cos15) = mg\sin15[/tex]

Solving for [tex]\mu,[/tex] we get

[tex]\mu = \dfrac{\sin15}{\cos15} = \tan15 = 0.27[/tex]

Answer:

x=v.t

The answer: Distance= Speed x Time

And also

Time = Distance/Speed

Speed= Distance/Time