Answers
Explanation:
A charge is a scalar quantity associated with every material. when we say a body or an object is charged then it means that a body or an object gained a positive charge or negative charge.
A conductor is a metal that contains a lot of electrons in it.
A dark knob or a ground is the source or sink where any charge is dumped.
(1)
when there is a negative charge on an object that will be spread over the surface by the Coulomb force.
so (c) spread out over a large area on the object.
(2)
both the positive and negative charges move to the conductor and exit the conductor.
(3)
(b) a person can not be shocked if they have a neutral charge.
All options have been defined.
Related Questions
i need help with this mechanical question please
Answers
The maximum velocity of the water that will allow it to fall into the bowl is 9.4 m/s.
What is the time of motion of the water?
The time of motion of the water is the time taken for the water to travel from the bubbler into the drinking bowl.
The time of motion of the water is calculated as follows;
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity of the water = 0t is the time of motion of the water = ?h is the height travelled = 5 cm = 0.05 mg is acceleration due to gravity = 9.8 m/s²h = 0 + ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
t = √(2 x 0.05 / 9.8)
t = 0.1 second
The maximum velocity of the water that will allow it to fall into the bowl is calculated as follows;
X = Vₓt
where;
X is the maximum horizontal displacement of the waterVₓ is the maximum horizontal speed of the watert is the time of motion of the waterX = diameter of the bowl minus 3 cm
X = 50 cm - 3 cm
X = 47 cm
X = 0.47 m
X = Vₓt
X = (V cosθ)t
where;
V is the largest or maximum velocity of the waterθ is the angle of inclination of the water0.47 = [V cos(60)](0.1)
0.47 / 0.1 = V cos(60)
4.7 = V(0.5)
V = 4.7 / 0.5
V = 9.4 m/s
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What planet is more similar in size to earth
Answers
Answer: Venus
Explanation:
An infinitely long line of charge has linear charge density 5.00×10−12 C/m5.00×10−12 C/m. A proton (mass 1.67×10−27 kg1.67×10−27 kg, charge +1.60×10−19 C+1.60×10−19 C) is 18.0 cm from the line and moving directly toward the line at 3.50×103 m/s.3.50×103 m/s. (a) Calculate the proton’s initial kinetic energy. (b) How close does the proton get to the line of charge?
Answers
(a) The initial kinetic energy of the proton is 1.023 x 10⁻²⁰ J.
(b) The position of the proton from the line of charge depends on the time of motion of the proton.
What is the initial kinetic energy of the proton?The initial kinetic energy of the proton is the energy of the proton due to its motion.
Mathematically, the initial kinetic energy of the proton is given by the following formula,
K.E = ¹/₂mv²
where;
m is the mass of the protonv is the initial velocity of the protonK.E = ¹/₂(1.67 x 10⁻²⁷)(3.5 x 10³)²
K.E = 1.023 x 10⁻²⁰ J
The position of the line is calculated as follows;
x = Q/σ
where;
Q is the charge of the protonσ is the linear charge densityx = (1.6 x 10⁻¹⁹ C) / (5 x 10⁻¹² C/m)
x = 3.2 x 10⁻⁸ m
We can determine the how close the proton get to the line of charge, if we know the time of motion of the proton. Unfortunately, more information is needed to determine the time of motion of the proton.
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Not yet answered Marked out of 1.00
Which of the following statements about gravitational force, Fe, is not
correct?
Oa. The gravitational force between two objects depends on their separation.
Ob. Gravitational force is the strongest of the fundamental forces.
Oc. Gravitational forces always exist in pairs of equal magnitude.
Od. Gravitational force is an attractive force only; it is never repulsive.
Answers
a. The distance between two objects affects the gravitational force between them.
All physical things with mass are drawn to the gravitational force, which can be thought of as an attracting force. It is by far the most insignificant natural force.
The gravitational attraction, an attractive force whose magnitude is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another, attracts all objects with mass toward one another.
According to Newtonian mechanics, the "pull" of gravity is caused by mass. There is only a pull between any two masses and every other mass. However, the fact that the magma is so hot is what causes the gravitational pull, not the magma itself.
The gravitational pull between two objects is proportional to their masses and becomes weaker as their distance from one another grows. Both things are attracted to one another equally; for example, a falling object is attracted to the Earth with a force equal to that of the Earth's attraction.
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A 100 g piece of copper is at room temperature (20°C). It is then held over a flame and its temperature increases to 120°C after which it is dropped in a thermally insulated beaker which contains 200 g of oil. The specific heat of copper is 388 J/kg Ka) How much heat has the copper piece absorbed from the flame?b) Describe if and how the temperatures of the copper and the oil change after the metal was dropped in the oil.
Answers
We will have the following:
[tex]Q=C\cdot m\cdot\Delta T[/tex]a) The heat that the copper piece absoved was:
[tex]Q=(388J/kg\cdot K)(0.1kg)(120-20+273.15)\Rightarrow Q=14478.22J[/tex][tex]\Rightarrow Q=14.47822kJ[/tex]So, the heat that the copper piece absorved was 14.47822 kJ.
b) The temperature of the copper will decrease when dropped in the oil, since the oil has a smaller energy state then the heat will disperse towards the lower energy state, thus making the copper colder and making the oil hotter. At some point the temperature of both will reach equilibrium and the temperature of the copper piece and the oil will be the same; this means the temperature of the copper piece will be lower and the temperature of the oil will be greater.
Logan pushes a box with a 400n of force with a direction angle of 30 degrees, while Andrew pushes the same box with a force of 250N with a direction angle of 290 degrees.Which of the following represents the component vectors of the force applied by Andrew?
Answers
Given:
The force applied by the logan is
[tex]F=400\text{ N}[/tex]The force applied by the Andrew is
[tex]F=250\text{ N}[/tex]Required: component of force applied by the andrew.
Explanation:
first, draw the free body diagram,
from the free body diagram we can write resolve the force into two components
one along the y axis and one along the x axis
Along x axis
[tex]F\sin(290^{\circ})[/tex]Plugging the values, we get
[tex]\begin{gathered} =250\times\sin(290) \\ =250\times-0.939 \\ =-234.92\text{ N} \end{gathered}[/tex]Along y axis
[tex]\begin{gathered} F\cos(290^{\circ}) \\ =250\times\cos(290^{\circ}) \\ =250\times0.342 \\ =85.50\text{ N} \end{gathered}[/tex]Thus, the component of forces are
[tex]85.50\text{ N, }-234.92\text{ N}[/tex]and option first is correct.
A heavy sled is being pulled by two people as shown in the figure. The coefficient of static friction between the sled and the ground is s=0.579, the coefficient of kinetic friction is k=0.405, and the combined mass of the sled and its load is =336 kg. The ropes are separated by an angle =29∘, and they make an angle with the horizontal. Assuming both ropes pull equally hard, what is the minimum rope tension required to get the sled moving?
Answers
The minimum rope tension required to get the sled with a load of 336 kg moving if the coefficient of static friction between the sled and the ground is s=0.579 is 1155.5 N
[tex]F_{s}[/tex] = μ[tex]_{s}[/tex] * N
N = m g
[tex]F_{s}[/tex] = Static frictional force
μ[tex]_{s}[/tex] = Co-efficient of static friction
N = Normal force
m = Mass
g = Acceleration due to gravity
μ[tex]_{s}[/tex] = 0.579
m = 336 kg
g = 9.8 m / s²
[tex]F_{s}[/tex] = 0.579 * 336 * 9.8
[tex]F_{s}[/tex] = 1906.5 N
[tex]F_{s}[/tex] = 2 T cos θ cos ( φ / 2 )
T = Tension
θ = Angle between horizontal and rope
φ = Angle between the two ropes
θ = 32°
φ = 29°
1906.5 = 2 * T * cos 32° * cos ( 29 / 2 )°
1906.5 = 2 * T * 0.85 * 0.97
T = 1906.5 / 1.65
T = 1155.5 N
Therefore, the minimum rope tension required to get the sled moving is 1155.5 N
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Speed (m/s) vs. Time (s) Graph
30
*K
8
10
E-F
A-B
30
43
Car's Speed vs Time
E
50
Teets
LL
70
In the speed vs Time Graph, which time interval(s) show pricitive (+) acceleration?
Calculate the car's acceleration between the following points
(Acceleration (Speed-Speed,
F-G
In the speed vs Time Graph, which time interval(s) show negative (-) acouleration?
30
In the speed vs Time Graph, which lime interval(s) show constant speed?
92
100
Time, Time,) or Acceleration Aspeed/ Alime
B-C
C-D
G-H
D-E
H-I
Answers
Considering the acceleration concept and the speed vs time graph, it is found that:
The acceleration is positive in intervals CD and EF.The acceleration is negative in intervals BC, GH and HI.The acceleration is constant in intervals AB and FG.For each interval, the acceleration is given as follows:
AB: 0 m/s².BC: -1 m/s².CD: 1 m/s².DE: -1 m/s².EF: 3 m/s².FG: 0 m/s².GH: -3 m/s².HI: -1 m/s².How to calculate acceleration?Acceleration is given by the change in velocity divided by the change in time, according to the following formula:
[tex]a = \frac{\Delta v}{\Delta t}[/tex]
Considering a graph of velocity x time, the acceleration is:
Positive when the graph is increasing, hence in intervals CD and EF.Negative when the graph is decreasing, hence in intervals BC, GH and HI.Constant when the graph is constant, hence in intervals AB and FG.Considering that each point has a time interval of 10s, and the numeric values of the velocity, the acceleration for the intervals is found as follows:
AB: 0 m/s². (constant velocity).BC: (10 - 20)/20 = -1 m/s².CD: (20 - 10)/10 = 1 m/s².DE: (10 - 20)/10 = -1 m/s².EF: (40 - 10)/10 = 3 m/s².FG: 0 m/s². (constant velocity).GH: (10 - 40)/10 = -3 m/s².HI: (0 - 10)/10 = -1 m/s².More can be learned about acceleration at https://brainly.com/question/14344386
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What did Piaget believe about his stages of cognitive development?
A. It is not required to complete one stage to move on to the next one.
B. All children go through the stages in the exact same order.
C. A child’s age is the main factor to determine when they enter a stage.
D. All adults complete all four stages of development by the age of 25.
Answers
All adults complete all four stages of development by the age of 25. Option D.
For Piaget cognitive development was the gradual reorganization of mental processes as a result of biological maturation and environmental experience. Children make sense of the world around them and experience discrepancies between what they already know and what they discover around them.
Fundamentally Piaget believed that man could make sense of the world on his own. From a theological point of view, he was a psychological constructivist believing that learning is caused by a mixture of two processes for him assimilation and adaptation. Piaget supported the idea that children think differently than adults and his research identified several important milestones in children's intellectual development.
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Question 6 of 25What does the labeled point in the diagram represent?АА2A. A crestB. A troughO C. The frequency
Answers
By definition, the trough of a wave is the lowest point on a wave, since the labelled is on such a point we conclude that the point is representing a trough and the answer is B.
Please help me solving these questions :(
Answers
A block is at rest on an inclined on the plane.
(a) The forces acting on the object shows in the picture.
(b) The component of gravitational force on the slope is (Fsinθ)=50N
(c) The amount of friction is (f)=25N
(d) The force perpendicular to the plane is (Fcosθ)=86.60N
What is force?Force is a physical quantity when it is applied on a object which is at rest start moving and a moving object change its velocity. It can be measured in Newton and Dyne.
How can we calculate the force?(b) To calculate the component of gravitational force on the slope we are using the formula, r=Fsinθ
Here we are given,
F= The amount of force acting on the object. = 100N
θ= The angle which was made by the plane. =30°
We have to calculate the values of the component of gravitational force on the slope = r
Now we put the values in the equation,
r=Fsinθ
Or, r=100*cos(30)
Or, r=50N
From the calculation we can say, The component of gravitational force on the slope is (Fsinθ)=50N
(c) To calculate friction we are using the formula,
f= μₙr
Here we given,
μₙ= coefficient of dynamic friction = 0.5
r= The component of gravitational force on the slope = 50N
Now we put the values in above equation we get,
f= μₙr
Or, f= 0.5*50
Or, f=25N
So we can say, The amount of friction is (f)=25N
(d) To calculate the force perpendicular to the plane we are using formula here is, N= Fcosθ
As we know both the values of F and θ.
Then we put the values in the equation we get,
N=Fcosθ
Or, N= 100* cos30
Or, N=86.60N
According to the calculation we can say that, The force perpendicular to the plane is (Fcosθ)=86.60N
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2. The gravitational force between the star and object X is equal to the forces between the
star and the two planets. From that information, what can you conclude about object X?
Answers
if the star's gravitational pull on object X is equivalent to the star's pull on the two planets.
The mass of the object X is equal to the mass of the two planets and the distance between the star and object X is equal to the distance between the star and two planets.
Simply put, the gravitational force is the force that pulls objects with mass together. It draws crowds together.
According to the information provided, the gravitational attraction between the star and planet A and planet B will be equal.
The gravitational attraction force grows together with the mass. This will result in decreased gravitational forces as the separation distance increases.
As the gravitational force is directly proportional to mass and inversely proportional to the square of the distance, therefore, the mass of object X is equal to the mass of the planets and the distance between the star and object X is equal to the distance between the star and the two planets.
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1. What is the acceleration of a car that takes 8.5 seconds to change its velocity from 35 m/s to 5 m/s?
Knowns:
Unknowns:
Formula:
Solve:
Answers
Answer:
Final velocity(v)= 25m/s^2
Initial velocity(u)=10m/s^2
Acceleration(a)=5m/s^2
let time taken be t sec
From first eq of motion
v=u+at
v-u=at
25–10=5t
15=5t
t=3s.
Given a ball at some height above the ground where its total mechanical energy is 5.00 J. If the ball falls down to a lower height in free fall where it’s gravitational potential energy is 2.00 J then what must its kinetic energy be at this lower height?A) 3.00 JB) 9.10X10^-1 JC) 12.9 JD)15.3 JE)6.40 J
Answers
ANSWER
A. 3.00 J
EXPLANATION
By the law of conservation of energy, total mechanical energy must be conserved. At both points, the kinds of mechanical energy the ball has are gravitational potential energy and kinetic energy,
[tex]ME=PE+KE[/tex]At some point, the total mechanical energy is 5 J. This energy must be conserved, so if at the lower height its gravitational potential energy is 2J, then its kinetic energy must be such that the sum gives 5J,
[tex]\begin{gathered} 5J=2J+KE \\ KE=5J-2J=3J \end{gathered}[/tex]Hence, the kinetic energy at the lower height is 3.00 J.
Note: specific heat capacity of water C= 4184 J/kg 0 CWith 31,840 Joules, a water was heated raising its temperature from 22.0 °C to 28.5 °C. Find the mass of the water, in grams. Q =m=ΔT=C=Solution:
Answers
We are given the following information
Specific heat capacity of water = 4184 J/kg.°C
Amount of heat = 31,840 Joules
Change in Temperature = 22.0 °C to 28.5 °C
We are asked to find the mass of the water in grams.
Recall the specific heat capacity formula is given by
[tex]Q=m\cdot c\cdot\Delta T[/tex]Let us substitute the given values and solve for mass (m)
[tex]\begin{gathered} Q=m\cdot c\cdot\Delta T \\ 31,840=m\cdot4184\cdot(28.5-22.0) \\ 31,840=m\cdot4184\cdot6.5 \\ 31,840=m\cdot27,196 \\ m=\frac{31,840}{27,196} \\ m=1.1708\; kg \end{gathered}[/tex]Multiply the mass in kg by 1000 to convert into grams.
[tex]m=1.1708\times1000=1170.8\; g[/tex]Therefore, the mass of the water is 1170.8 grams.
If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). what is theminimum speed required to take 84 meter radius banked at 17 degree so that you don't slide inward.
Answers
For the car to stay on the road without sliding in or sliding out, all the forces on the x-axis must equal each other. Thus by equating all the forces on the x-axis, we can find the coefficient of the friction.
In order to determine the minimum speed of the car, use the following expression:
[tex]v=\sqrt[]{R\cdot g\cdot\tan \theta}[/tex]where,
R: radius of the road = 84m
g: gravtitational acceleration constant = 9.8m/s^2
θ: angle of banking of the road = 17 degrees
Replace the previous values of the parameters into the formula for v:
[tex]\begin{gathered} v=\sqrt[]{(84m)(9.8\frac{m}{s^2})(\tan 17)} \\ v\approx15.86\frac{m}{s} \end{gathered}[/tex]Hence, the minimum speed requierd is approximately 15.86m/s
In order to determine the value of the minimum coefficient friction required, use the following formula:
[tex]\mu=\frac{v^2-Rg\tan \theta}{v^2\tan \theta+Rg}[/tex]by replacing, you get:
[tex]undefined[/tex]At a baseball game, a ball of m = 0.15 Kg moving at a speed of v = 30m/s is caught by a fan.
a. Show that the impulse supplied to bring the ball to rest is 4.5 N x s. Remember to use the correct units (0.25pts)
b. Show that if the ball is stopped in 0.02 s, then the average force of the ball on the catcher’s hand is 225 N. Remember to use the correct units. (0.25pts)
Answers
A. The impulse supplied to bring the ball to rest 4.5 Ns. Details below
B The average force of the ball is 225 N. Details below
What is impulse?This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final momentum – Initial momentum
Impule = m(v - u)
Where
m is the massu is the initial velocityv is the final velocityAlso,
Impulse = force × time
Therefore
Force × time = final moment – Initial momentum
A. How to determine the impulse
The impulse can be obtainedas illustrated below
Mass (m) = 0.15 KgInitial velocity = 30 m/sFinal velocity = 0 m/sImpulse =?Impulse = m(v + u) since the came to rest
Impulse = 0.15 × (0 + 30)
Impulse = 0.15 × 30
Impulse = 4.5 Ns
Thus, the impulse is 4.5 Ns
B. How to determine the average force
The average force can be obtained as follow:
Impulse = 4.5 NsTime = 0.02Average force = ?Impulse = force × time
4.5 = average force × 0.02
Divide both sides by 0.02
Average force = 4.5 / 0.02
Average force = 225 N
Thus, the average force is 225 N
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A pool cue strikes a 0.25 kg billiard ball with a force of 22 N. If the felt on the pool table supplies
a force of 7 N what is the acceleration of the billiard ball.
Answers
Answer:
Approximately [tex]0.06\; {\rm m \cdot s^{-2}}[/tex], assuming that the force from the pool cue is horizontal.
Explanation:
As the billiard ball moves forward, the pool table will exert friction on the ball. In this question, it is given that the magnitude of this friction is [tex]7\; {\rm N}[/tex]. If the ball is moving forward, this friction will point backward.
The cue exerts a forward force of magnitude [tex]22\; {\rm N}[/tex] on the billiard ball. The [tex]22\; {\rm N}[/tex] forward force from the cue and the [tex]7\; {\rm N}[/tex] backward force from the table interact with each other. The resultant force on the ball will be [tex](22\; {\rm N} - 7\; {\rm N}) = 15\; {\rm N}[/tex], forward.
When an object of mass [tex]m[/tex] experiences a net force of [tex]F[/tex], the acceleration [tex]a[/tex] of that object will be [tex]a = (F / m)[/tex].
Apply unit conversion and ensure that the mass of the billiard ball is in standard units (grams): [tex]m = 0.25\; {\rm kg} = 250\; {\rm g}[/tex].
In this question, the net force on this billiard ball is [tex]F = 15\; {\rm N}[/tex]. With a mass of [tex]m = 250\; {\rm g}[/tex], the acceleration [tex]a[/tex] of this billiard ball will be:
[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{15\; {\rm N}}{250\; {\rm g}} = 0.06\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].
Changing which of the following would affect the power output or a person climbing stairs? Select all that apply.
SELECT ALL THAT APPLY
The number of stairs the person runs up.
The mass of the person.
The height of the person.
The amount of time that it takes for the person to climb the stairs.
Answers
The power output of a person climbing stairs is the mass of the person. Option B.
It is clear that carrying a heavy object up a flight of stairs requires more strength than carrying a lighter one. But even if you don't have anything you have to support your weight against gravity. Therefore, the heavier the weight the greater the force required to climb the stairs. Climbing stairs improves the amount of good cholesterol in your blood.
Stair climbing can be an important priority for building leg strength and reducing the risk of fall injury in older adults. Climbing stairs helps you achieve and maintain a healthy weight. Calculate the amount of power developed Power is the amount of work divided by the time it took to do the work. The work done in climbing stairs is the force applied by multiplying the weight by the distance climbed and the height of the stairs.
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What would cause the AMA of a machine to decrease?How could you increase the AMA of a machine?
Answers
The AMA is the quotient between the input and output forces and is given by:
[tex]AMA=\frac{F_o}{F_I}[/tex]Where:
[tex]\begin{gathered} F_o=\text{ output force} \\ F_I=\text{ input force} \end{gathered}[/tex]Therefore, the AMA is decreased if the input force is increased. If in a machine the friction force increases due to low maintenance then the required input force would increase and therefore, the AMA would decrease.
In a first-class lever we have the following:
We can calculate the ratio between input and output forces by adding the torque around the fulcrum:
[tex]F_oR_o-F_iR_i=0[/tex]Adding the product of the input force and input distance:
[tex]F_oR_o=F_iR_i[/tex]Now, we divide both sides by the input force:
[tex]\frac{F_oR_o}{F_i}=R_i[/tex]Now, we divide both sides by the output distance:
[tex]\frac{F_o}{F_i}=\frac{R_i}{R_o}[/tex]Therefore, the AMA is:
[tex]AMA=\frac{R_i}{R_o}[/tex]Therefore, if in the lever we increase the input distance or decrease the output distance we would increase the AMA.
Your heating system is 45 percent energy efficient. A) What amount of energy would it consume to transform 9000 kWh into useful thermal energy for heating the house during the winter?
Answers
Let E be the total amount of energy that the heating system would consume in order to transform 9000kWh into useful thermal energy.
Since the efficiency of the system is 45%, then, 9000kWh is equal to 45% of E.
This means that 45% of the total energy consumed is transformed into useful thermal energy. Then:
[tex]\frac{E}{100}=\frac{9000kWh}{45}[/tex]Solve for E:
[tex]E=\frac{100}{45}\times9000kWh=20,000kWh[/tex]Therefore, the total amount of energy consumed by the system would be 20,000kWh.
Convert 690cm^3 to litres.
Answers
We need to convert 690 cu cm to liters
First we have the next equivalence
1 liter= 1000 cm^3
[tex]\frac{690\text{ cm}^3\times1L}{1000\operatorname{cm}^3}=0.69L[/tex]690 cm^3=0.69 liters
The pilot of an airplane traveling 180 km/h wants to drop supplies to flood victims isolated on a patch of land 160 m below. The supplies should be dropped how many seconds before the plane is directly overhead?
Answers
Given speed of airplane is 18km/h, then the supplies should be dropped 5.71 sec before the plane is directly overhead.
Motion of an object thrown into the air is called projectile motion. When the initial force launches the object, it experiences only the force of gravity. The object is called a projectile and path is its trajectory. Throwing the ball straight upward, or kicking a ball or just dropping things and make them free fall are examples of projectile motion.
Given, y = -160 m
As we know, g = 9.8 m/s
y = Vt - ½ gt^2
=1/2gt^2
t = (-2y/g)^0.5
t =[-2(-160m)/9.8m/s]^0.5
= 5.71 sec
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A race car rounds a curve at 54 m/s. The radius of the curve is 441 m, and the car’s mass is 610 kg. (Assume that the car’s speed remains constant. Take the radially inward direction to be positive) The car’s acceleration is 6.61 m/s2. What is the value of this acceleration in terms of "g"?
Answers
Given:
The speed of the car is: v = 54 m/s
The radius of the curve is: r = 441 m
The mass of the car is: m = 640 kg
The acceleration of the car is: a = 6.61 m/a^2
To find:
The value of acceleration in terms of g (acceleration due to gravity).
Explanation:
The car has an acceleration of 6.61 m/s^2.
The acceleration of 6.61 m/s^2 can be written in terms of g (acceleration due to gravity) as:
[tex]a_g=\frac{a}{9.8\text{ m/s}^2}\times g=\frac{6.61\text{ m/s}^2}{9.8\text{ m/s}^2}\times g=0.675g[/tex]Final answer:
The acceleration of the car in terms of g (acceleration due to gravity) is 0.675g.
Calculate the net force.
Answers
The forces are unbalanced
A brick dropped from rest falls for 4 seconds. How far does the brick fall?
Answers
Free fall acceleration of any object at any time is 10 m/s^2
distance = 1/2 a t ^2 = 1/2 * 10m/s^2 * (4s )^2= 80 m
A book of mass 0.5 kg is dropped from a height of 2.8 m. How much mechanical energy does it have right before it hits the ground? (Assume there is no air resistance.) Acceleration due to gravity is g = 9.8 m/s2.
Answers
The mechanical energy the book has right before it hits the ground is equal to 13.72 J.
What is mechanical energy?Mechanical energy can be described as the sum of potential energy and kinetic energy. The law of conservation of mechanical energy states that for an isolated system is only subjected to the conservative forces then its mechanical energy is constant.
The mechanical energy of the object is conserved during the fall in absence of air resistance. When the book is just about to hit the ground, the initial gravitational potential energy at the beginning of the fall will be completely converted into kinetic energy.
Therefore, the mechanical energy at the beginning of the fall will be equal to the mechanical energy just before the book hits the ground.
The mechanical energy in starting is all gravitational potential energy:
U = mgh
where m = 0.5 kg is the mass of the book, g = 9.8 m/s² is the acceleration of gravity, h = 2.8 m is the height above the ground.
U = 0.5× 9.8×2.8
U = 13.72 J
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A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of 22 N · m. If the mechanic grasps the wrench as shown in the figure below, determine the magnitude (in N) of the force she must exert on the wrench.
Answers
Given,
The magnitude of the torque is
[tex]T=22\text{ N.m}[/tex]The angle is
[tex]\theta=60\text{ }[/tex]The distance d is
[tex]d=0.30\text{ m}[/tex]Solution:
The torque is calculated by the formula,
[tex]T=dFsin\theta[/tex]Calculate the magnitude of the force.
[tex]\begin{gathered} F=\frac{T}{dsin\theta} \\ F=\frac{22\text{ N.m}}{0.30\text{ m}\times sin(60)} \\ F=\frac{22\text{ N.m}}{0.30\times\frac{\sqrt{3}}{2}} \\ F=157.8\text{ N} \end{gathered}[/tex]Thus, the magnitude of the force is 157.8 N.
Which of the following is the weakest hypothesis for the question, "Is there evidence of water on Mars?"
OA.
OB.
O C.
OD.
There is water under the surface of Mars.
There might have been water but it's difficult to tell.
There was never water on Mars.
Mars once had a lake filled with water.
Answers
There might have been water but it's difficult to tell is the weakest hypothesis for the question, "Is there evidence of water on Mars.
The rusty red color of Mars, the fourth planet from the sun, is well known. The atmosphere of the cold, arid Red Planet is extremely thin. However, the dusty, (as far as we can tell) dead planet is everything from boring.Extreme dust storms may cover the whole planet, the atmosphere can get so frigid that carbon dioxide condenses into snow or ice, and marsquakes, a type of earthquake that occurs on Mars, are a common occurrence.Because of its considerable distance from the sun, Mars is significantly colder than Earth. It's roughly - 80 degrees Fahrenheit on average.To know more about Marsvisit : https://brainly.com/question/14623285
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A frictionless pulley, which can be modeled as a 0.83 kg solid cylinder with a 0.33 m radius, has a rope going over it, as shown in (Figure 1). The tensions in the rope are 12 N and 10 N . What is the angular acceleration of the pulley?
Answers
A frictionless pulley, which can be modeled as a 0.83 kg solid cylinder with a 0.33 m radius, contains a rope going over it. The tensions in the rope exists 12 N and 10 N. The angular acceleration of the pulley will be 13.025 rad/s².
What is meant by angular acceleration?The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement exists radians per second. Rotational acceleration is another name for angular acceleration.
Rotational acceleration is another name for angular acceleration. It has both magnitude and direction, making it a vector quantity.
We know that,
Torque = I α = r × Fnet
Iα = r × Fnet
0.5 × m × r² * α = 2 × r × sin 90
After solving, we get
α = 4/mr = 4/(0.83 × 0.37)
α = 13.025 rad/sec²
Therefore, the angular acceleration of the pulley exists 13.025 rad/sec².
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