The first half-reaction is the oxidation of Cr2O7^2– to Cr^3+ and the second half-reaction is the reduction of I^– to IO3^–. When combined, the overall reaction is Cr2O7^2– + I^– → Cr^3+ + IO3^–.
The electrolytic cell consists of two electrodes, one anode and one cathode, both of which are immersed in an electrolyte solution. At the anode, the Cr2O7^2– ions are oxidized to Cr^3+ ions, releasing electrons into the external circuit.
At the cathode, the I^– ions are reduced to IO3^– ions, and the electrons from the external circuit are used to drive the reaction. The electrolyte solution must contain both Cr2O7^2– and I^– ions in order to facilitate the transfer of electrons between the electrodes.
The overall reaction is driven by the potential difference between the anode and the cathode, which is created by the flow of electrons through the external circuit.
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will the product of KOH + FeCl3 form precipitate
Answer:
The reaction between ferric chloride and potassium hydroxide leads to the formation of ferric hydroxide and potassium. It is a precipitation reaction in which ferric and hydroxide ion on reaction with each other results in the formation of ferric hydroxide as reddish-brown precipitate.
In addition to pH meter, what other methods and/or experimental devices may be used to determine the Ksp values of sparingly soluble electrolytes? Please give at least three examples.
What factor(s) may change Ksp values? Please elaborate your answer.
According to the solubility of of sparingly soluble electrolytes by conductometer and potentiometer.
Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.It can also be determined for electrolytes.
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Part D
Now predict the shape of a graph that shows velocity in the x direction (v) versus time
The shape of a graph that shows the velocity in the x direction (v) versus time when the object is accelerating in the x direction would be a curve with a non-zero slope.
What is the velocity of a body?The rate at which an object's displacement changes in relation to a frame of reference is its velocity. The direction of the movement of the body or the object is defined by its velocity.
According to the equation v = s/t, velocity (v) is a vector quantity that quantifies displacement (or change in position, s), over the change in time (t).
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Answer: I expect a horizontal line (slope 0). As time increases, the velocity in the x direction stays about the same.
Explanation: Edmentum sample answer
I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE
The number of mole of Ba₃(PO₄)₂ produced from 3.54 L of 0.373 M BaCl₂ is 0.44 mole
How do i determine the mole of Ba₃(PO₄)₂ produced?We'll begin our calculation by obtaining the mole of BaCl₂ in 3.54 L of 0.373 M BaCl₂. This is shown below:
Volume = 3.54 LMolarity = 0.373 MMole of BaCl₂ =?Mole = molarity × volume
Mole of BaCl₂ = 0.373 × 3.54
Mole of BaCl₂ = 1.32 mole
Finally, we can determine the number of mole of Ba₃(PO₄)₂ produced from the reaction. This is illustrated below:
Balanced equation for the reaction:
3BaCl₂ + 2H₃PO₄ -> Ba₃(PO₄)₂ + 6HCl
From the balanced equation above,
3 moles of BaCl₂ reacted to produce 1 mole of Ba₃(PO₄)₂
Therefore,
1.32 mole of BaCl₂ will react to produce = 1.32 / 3 = 0.44 mole of Ba₃(PO₄)₂
Thus, we can conclude from the calculation made above that the number of mole of Ba₃(PO₄)₂ produced is 0.44 mole
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2. Label the different layers of the atmosphere and the separating boundaries between each layer.
The layers of the atmosphere with the boundaries that are between them are shown in the image attached here.
Layers of the atmosphereThe troposphere, which rises up to an altitude of roughly 10-15 km, is the layer that is closest to the Earth's surface. The majority of the Earth's air mass is contained here, which is also where weather happens.
The tropopause marks the transition from the troposphere to the stratosphere, the next layer. It designates the altitude at which the temperature stops dropping.
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Determine how many moles of unknown gas are in a 5 liter container at 1 atm and 0 °C. Answer with two decimal places. R=.08206 L*atm/K*mol
To determine the number of moles of gas in a 5 L container at 1 atm and 0°C, one will use the ideal gas law: PV = nRT. After solving for n,
n = (1 atm ×5 L) / (0.08206 L.atm/K.mol ×273.15 K)
n = 0.206 mol
Therefore, there are 0.21 moles of gas in the 5 L container at 1 atm and 0°C.
The ideal gas law is an equation that describes the behavior of gases under certain conditions. It states that the product of pressure and volume of a gas is directly proportional to the number of moles of gas, the gas constant, and the absolute temperature of the gas. The ideal gas law is represented by the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the absolute temperature in Kelvin.
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please answer the questions in the picture
If 5.34 g of tricarbon octahydride reacts with 25.2 g of oxygen gas, the limiting reactant is tricarbon octahydride.
8.72168 grams of water is produced.
5.84 grams of excess reactant is left over after the reaction is complete.
The percent yield of water, if 6.98 g of water is actually produced in a laboratory experiment is 80.0459 %.
What is the equation of the combustion reaction?The equation of the combustion reaction is given below:
C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
molar masses:
tricarbon octahydride: 44.11 g/mol
oxygen gas: 32 g/mol
water: 18.02 g/mol
carbon dioxide: 44.01 g/mol
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Thank you in advance.
The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.
How to calculate rate expression?The rate expression for this reaction can be written as:
Rate = k [BF₃]^m[NH₃]^n
The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.
When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.
Therefore, the rate expression for the reaction is:
Rate = k [BF₃]²[NH₃]
The overall order of the reaction is m + n = 3.
Using the data from experiment 4, substitute the values and solve for k:
Rate = k [BF₃]²[NH₃]
1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)
k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)
k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹
Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.
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The following reaction forms 16.5 g of Ag(s): 2Ag2O(s)→4Ag(s)+O2(g)
What total volume of gas forms if it is collected over water at a temperature of 25 ∘C
and a total pressure of 763 mmHg?
10.5L is the total volume of gas forms if it is collected over water at a temperature of 25 ∘C and a total pressure of 763 mmHg.
A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch.
Volume and length (cubed) have a symbiotic relationship. The volume more a container is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the quantity of fluid (liquid or gas) that the container may hold.
2Ag[tex]_2[/tex]O(s)→4Ag(s)+O[tex]_2[/tex](g)
moles of Ag = 16.5/ 107.8=0.15 moles
moles of oxygen = (1/2)×0.15 =0.075moles
P×V = n×R×T
763×V =0.075×0.081×25
V= 10.5L
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If 128g of a certain gas in a container with a volume of 21.5 L has a pressure of 140 kPa and a temperature of 45°C, what is the molar mass of the gas?
The molar mass of the gas contained in a container with a volume of 2.15L with a pressure of 140kPa is 112.28 g/mol.
How to calculate molar mass?The molar mass of a substance can be calculated by dividing the mass of the substance by its no of moles.
According to this question, 128g of a certain gas in a container with a volume of 21.5 L has a pressure of 140 kPa and a temperature of 45°C. The no of moles must first be calculated as follows:
PV = nRT
Where;
P = pressureV = volumen = no of molesR = gas law constantT = temperature1.38 × 21.5 = n × 0.0821 × 318
29.67 = 26.1078n
n = 1.14 moles
molar mass = 128g ÷ 1.14 moles = 112.28 g/mol
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Four friends were playing on the playground. They began to question where
all organisms get energy from. Here are their thoughts:
Brock:
Malik:
Kira:
Sydney:
I think that the main source of energy for most life is food.
I think that the main source of energy for most life is water.
I think that the main source of energy for most life is the Sun.
I think that most organisms make their own energy.
Circle the friend you most agree with. Explain why you agree with that person.
The friend I agree with the most is Kira because all living organisms directly or indirectly depend on the sun for their energy.
Source of energy for living organismsKira is the one who is right because the main source of energy for most life on Earth is indeed the Sun.
Photosynthesis is the process by which plants, algae, and some bacteria convert sunlight into chemical energy, which is then used to fuel cellular processes.
Even organisms that do not photosynthesize directly, such as animals, ultimately rely on the Sun's energy because they consume plants or other organisms that do.
While food and water are important for sustaining life, they are ultimately derived from the energy captured by photosynthetic organisms from the Sun.
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5.1 g sodium carbonate solution was dissolved in water to make 500cm³ of solution.20cm³ of this solution was tirated against 20.45 cm³ of 0.04M hydrochloric acid . Calculate the % of purity of the sodium carbonate solid
Answer:
We know that, Va= 20.45 cm³, Vs= 20 cm³, Ma= 0.04M . But molar mass of Na₂CO₃ = 106. So, concentration (g/dm³) = 0.02045 × 106 = 2.1677 g/dm³. Hence, The percentage purity of the sodium carbonate solid is 21.25%.
A mixture of He , Ar , and Xe has a total pressure of 2.10 atm . The partial pressure of He is 0.250 atm , and the partial pressure of Ar is 0.300 atm . What is the partial pressure of Xe ? Express your answer to three significant figures and include the appropriate units.
The partial pressure of the gas in a mixture is the pressure that the gas would exert if present alone in the vessel at the same temperature as that of the mixture. Here the partial pressure of Xe is
The pressure exerted by a mixture of two or more non-reacting gases enclosed in a definite volume is equal to the sum of the partial pressures of the component gases.
According to Dalton's law of partial pressures, total pressure is:
P = p₁ + p₂ + ...
2.10 = 0.250 + 0.300 + p
p = 1.55
Partial pressure of Xe = 1.55
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What is the answer to this?
3. What is the percentage composition of Ba(NO3)2?
(Find the mass percent of each element.)
Ba(NO₃)₂ has the following percentage composition: 52.6% Ba, 10.7% N, and 36.7% O.
How to calculate percentage composition?The molar mass of Ba(NO₃)₂ is:
Ba: 1 x 137.33 g/mol = 137.33 g/mol
N: 2 x 14.01 g/mol = 28.02 g/mol
O: 6 x 16.00 g/mol = 96.00 g/mol
Adding these up gives us a total molar mass of 261.35 g/mol.
The mass percent of each element is then:
Ba: (137.33 g/mol / 261.35 g/mol) x 100% = 52.6%
N: (28.02 g/mol / 261.35 g/mol) x 100% = 10.7%
O: (96.00 g/mol / 261.35 g/mol) x 100% = 36.7%
Therefore, the percentage composition of Ba(NO₃)₂ is: 52.6% Ba, 10.7% N, and 36.7% O.
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3 What does this model show?
AECO
A.A single type of atom bonded together
B.An element because all the particles are the same
C.A molecule because there is more than one type of atom
D.An element because there is more than one type of atom
The model shows a molecule because there is more than one type of atom (option C).
What is a molecule?A molecule is the smallest particle of a specific element or compound that retains the chemical properties of that element or compound.
A molecule is made up of two or more atoms held together by chemical bonds.
According to this question, a model AECO is given. Each alphabet represents a different element, hence, indicating that four different atoms are bonded together to form a molecule.
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5. How many moles of NaCl are in a 500mL solution with a concentration of 0.66M?
How many grams of SrCl₂ are in a 768mL solution with a concentration of 0.978M?
What is the volume of a solution with 500grams of CaBr, and a concentration of 0.879M?
How many molecules of MgCl₂ are in a 759mL solution with a concentration of 0.99M?
How many milligrams of LiCI are in a 999mL solution with a concentration of 0.951M?
How many kilograms of KCI are in a 1556mL solution with a concentration of 1.23M?
6.
7.
8.
9.
0.
Cacl₂?
hp
consider the combustion of carbon monoxide in oxygen gas.2CO(g)+O2(g)=2CO2(g).In this reaction 10.8 moles of carbon dioxide was produced. Calculate the number of moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide.
In this reaction 10.8 moles of carbon dioxide was produced. 10.8moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide.
In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like molecules, atoms, or other predetermined particles. The mole designates 6.02214076 1023 units, which is a very large number.
For the Worldwide System of Units (SI), the mole is defined as this number as of May 20, 2019, according to the General Convention on Measurements and Weights. The total amount of atoms discovered through experimentation to be present in 12 grammes of carbon-12 was originally used to define the mole.
2CO(g)+O[tex]_2[/tex](g)=2CO[tex]_2[/tex](g)
moles of carbon dioxide= 10.8 moles
According to stoichiometry
moles of carbon monoxide= (2/2)× 10.8 =10.8moles.
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Readiness Test: Populations, Communities, and Ecosystems
The structure of an ecosystem is characterized by the organization of both biotic and abiotic components. The reduction of the resources decrease the population of a species. The correct option is A.
An ecosystem is defined as the structural and functional unit of ecology in which the living organisms interact with each other and the surrounding environment. The living components of the ecosystem are called biotic components and the non-living components are called abiotic components.
In short, raw material extraction can adversely affect the environment, biodiversity loss, damage to ecosystem functions and global warming.
Thus the correct option is A.
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What is the pH of 6.00 M H2CO3 if it has 7% dissociation? SHOW YOUR WORK!!!
From the calculation, the pH of the solution can be obtained as 0.39.
What is the pH of the solution?We first have to obtain the dissociation constant of the solution;
α = √Ka/C
Ka = Cα^2
Ka = 4.9 * 10^-3 * 6
Ka = 0.0294
Then we have that;
0.0294 = [x]^2/[6 - x]
0.0294 * [6 - x] = x^2
0.1764 - 0.0294 x = x^2
x^2 + 0.0294 x - 0.1764 =0
x = 0.41 M
Thus the pH of the solution is;
pH = -log[0.41]
= 0.39
pH is an important parameter in chemistry, biology, and many other fields, as it can affect the behavior and properties of substances and reactions.
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If you mix 20.0 mL of 0.010 M MgCl2with 20.0 mL of 0.0020 M Na2CO3, will magnesium carbonate, MgCO3, precipitate out from the solution? Explain. Given: Ksp(MgCO3) = 4.0 × 10-5.
If you mix 20.0 mL of 0.010 M MgCl[tex]_2[/tex] with 20.0 mL of 0.0020 M Na[tex]_2[/tex]CO[tex]_3[/tex], magnesium carbonate will not precipitate out from the solution.
The byproduct of the condensing of atmospheric water vapour that falls from clouds as a result of gravitational pull is referred to as precipitation in meteorology. Rain, sleet, slush, ice pellets, graupel, drizzle, and hail are the main types of precipitation.
When a region of the outside world becomes completely saturated with water vapour, the water condenses or "precipitates" or falls. Because the water vapour does not enough condense to precipitate, fog and mist are instead colloids rather than precipitation. magnesium carbonate will not precipitate out from the solution.
Ksp =[Mg²⁺][CO₃²⁻]
[0.010][20] = C₂×40
C₂=0.001M
Q= 0.005×0.001
= 5×10⁻⁶M
Q<Ksp
precipitation will not occur
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Calculate the volume in mL of 0.567 M Ca(OH)2 needed to neutralize 42.8 mL of 0.490 M H3PO4 in a titration.
The volume in mL of 0.567 M Ca(OH)₂ needed to neutralize 42.8 mL of 0.490 M H₃PO₄ in a titration is 36.98ml.
A neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together to form a salt and water as products.
In a reaction to water, neutralization results in excess hydrogen or hydroxide ions present in the solution. The pH of the neutralized solution depends on the strength of the acid or base involved in it.
Given,
Concentration of calcium hydroxide = 0.567M
Volume of phosphoric acid = 42.8 moles
Concentration of phosphoric acid = 0.49M
During neutralization, the number of moles of acid and base remain same,
M₁V₁ = M₂ V₂
i.e. Moles of acid = moles of base
0.49 × 42.8 = 0.567 × V₂
V₂ = 36.98 ml
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Balance equation Pb(C2H3O2)2 + CO2 + H2O= PbCO3 + HC2H3O2
The balanced equation is: Pb(C2H3O2)2 + CO2 + H2O → PbCO3 + 2 HC2H3O2
Balancing chemical equationsIn a balanced chemical equation, the number of atoms of each element is the same on both sides of the equation. Thus, the balanced equation of the reaction is:
Pb(C2H3O2)2 + CO2 + H2O → PbCO3 + 2 HC2H3O2
The coefficients used to balance the equation are:
1 Pb(C2H3O2)2 + 1 CO2 + 1 H2O → 1 PbCO3 + 2 HC2H3O2
After balancing the equation, we can see that one molecule of lead(II) acetate reacts with one molecule of carbon dioxide and one molecule of water to produce one molecule of lead(II) carbonate and two molecules of acetic acid.
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Adding 1.64 g of naphthalene to 80.00 g of cyclohexane, C.H₁2() lowers the freezing point from
5.53°C to 1.37°C. If K, for cyclohexane is 19.9°C/m, calculate the molar mass of the naphthalene.
A cycloalkane with the chemical formula C6H12 is cyclohexane. Non-polar describes cyclohexane.
Thus, Colorless and combustible, cyclohexane has a characteristic detergent-like stench that is reminiscent of cleaning products.
The industrial manufacturing of adipic acid and caprolactam, which are building blocks for nylon, uses cyclohexane primarily.
cyclohexanone and cyclohexanol that serves as the starting point for the production of adipic acid and caprolactam, which are both precursors to nylon. Annual production of cyclohexanone and cyclohexanol totals several million kilos.
Thus, A cycloalkane with the chemical formula C6H12 is cyclohexane. Non-polar describes cyclohexane.
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what mass of oxygen is required to oxidise 10g of ammonia to NO? Can someone explain to me step by step on how to do this reacting mass calculation?
4 NH3 + 5 O2 = 4 NO + 6 H2O
Taking into account the reaction stoichiometry, 13.33 grams of oxygen is required to oxidise 10g of ammonia to NO.
Reaction stoichiometryIn first place, the balanced reaction is:
4 NH₃ + 5 O₂ → 4 NO + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
NH₃: 4 molesO₂: 5 molesNO: 4 molesH₂O: 6 molesThe molar mass of the compounds is:
NH₃: 17 g/moleO₂: 32 g/moleNO: 30 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
NH₃: 4 moles ×17 g/mole= 68 gramsO₂: 5 moles ×32 g/mole= 160 gramsNO: 4 moles ×30 g/mole= 120 gramsH₂O: 6 moles ×18 g/mole= 108 gramsMass of O₂ requiredThe following rule of three can be applied: If by reaction stoichiometry 120 grams of NO are produced by 160 grams of O₂, 10 grams of NO are produced by how much mass of O₂?
mass of O₂= (10 grams of NO ×160 grams of O₂)÷120 grams of NO
mass of O₂= 13.33 grams
Finally, 13.33 grams of O₂ is required.
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Write a K expression for
[CoCl4]2-(aq)(blue) + 6H2O(l) ⇌ [Co(H2O)6]2+(aq)(pink) + 4Cl-(aq)
The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant, K.
Thus, When a reaction is homogeneous, all of the products' and reactions' states of matter are the same (the prefix "homo" means "same"). The solvent typically controls the reaction's overall state of matter.
When a reaction is in chemical equilibrium, the concentrations of the reactants and products do not significantly fluctuate over time. A double arrow between the reactants and products denotes these reversible reactions.
As described, this reaction is endothermic, therefore when heat is added, the equilibrium constant moves to the right. In turn, this turns the solution blue. Cl- is drawn out of solution by the addition of AgNO3.
Thus, The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant, K.
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determine whether each molecule will have hydrogen bonding. defend your answer with evidence from your notes.
A - Has no hydrogen bond since hydrogen is not bonded to an electronegative element
B - Has a hydrogen bond due to the N- H bond
C - Has a hydrogen bond due to the O - H bond
D - Has a hydrogen bond due to the H -I bond
What is the hydrogen bond?In a hydrogen bond, a weak electrostatic connection is created when the positively charged hydrogen atom is drawn to the negatively charged electronegative atom.
This contact is stronger than van der Waals forces but not as strong as covalent or ionic bonds or other intermolecular forces.
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How would you describe the reactivity of this element?
Reactivity is the propensity of an element to gain or lose electrons. The most reactive metals are alkaline metals.
Reactivity in chemistry is an indication of how easily a substance reacts chemically. The chemical may react on itself or with other atomic particles or compounds, and in either case, energy will typically be released. The most reactive substances and elements have the potential to spontaneously or explosively ignite.
Periodic trends (patterns in the Periodic Table) can be used to anticipate an element's reactivities. Let's begin with cyclical tendencies. Reactivity is the propensity of an element to gain or lose electrons. The most reactive metals are alkaline metals (Group 1) because they have the highest propensity to lose electrons.
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2.50 g of As2O3 are titrated with 38.5 mL of KMnO4 to reach the end point.
5As2O3(s)+4MnO−4(aq)+9H2O(l)+12H+(aq)⟶10H3AsO4(aq)+4Mn2+(aq)
Calculate the concentration of the KMnO4 solution.
50 g of As[tex]_2[/tex]O[tex]_3[/tex] are titrated with 38.5 mL of KMnO[tex]_4[/tex] to reach the end point. 0.26M is the concentration of the KMnO[tex]_4[/tex] solution.
Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass in unit volume is typically used.
The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.
5As[tex]_2[/tex]O[tex]_3[/tex](s)+4MnO[tex]_4[/tex]⁻(aq)+9H[tex]_2[/tex]O(l)+12H⁺(aq)⟶10H[tex]_3[/tex]AsO[tex]_4[/tex](aq)+4Mn[tex]_2[/tex]⁺(aq)
the stoichiometry ratio between As[tex]_2[/tex]O[tex]_3[/tex] and MnO[tex]_4[/tex]⁻ is 5:4
0.0126 moles of As[tex]_2[/tex]O[tex]_3[/tex] will react with 4/5×0.0126 moles = 0.01008moles
0.01008moles of MnO[tex]_4[/tex]⁻ is present in 38mL
concentration of KMnO[tex]_4[/tex]= moles×volume
= 0.010/38×1000
=0.26M
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5. What is the mass of nitrogen in 125 g NH3? (find % composition first!)
The mass of nitrogen in 125 g NH3 is 102.9375g
Showing the calculation of mass in a chemical equationTo start by finding the percentage composition of nitrogen in NH3, we find the molar mass of NH3:
1N + 3H = 1(14) + 3(1) = 14 + 3 = 17g/mol
The percent composition of nitrogen in NH3 is:
mass of nitrogen in 1 mol NH3 / molar mass of NH3 x 100%
= (14/17 )x 100
= 82.35%
So, 82.35% of the mass of NH3 comes from nitrogen.
To find the mass of nitrogen in 125 g NH3, we can set up a proportion:
mass of nitrogen / 125 g NH3 = 82.35 / 100
mass of nitrogen = (125 g NH3) x (82.35 / 100)
mass of nitrogen = 102.9375 g
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What mass of oxygen gas, O2, from the air is consumed in the combustion of 702 g of octane, C8H18, one of the principal components of gasoline?
Select one:
A. 13.22 g
O B. 25.0 g/mol
O C. 32.0 g
O D. 33.22 g/mol
O E. 39.0 g
The principal components of gasoline is 702 g of octane.
Thus, Crude oil and other petroleum liquids are used to create gasoline, a fuel. The majority of gasoline is utilized in car engines.
For retail sale at gas stations, finished motor gasoline is produced at petroleum refineries and blending facilities.
In order to create finished motor gasoline, petroleum refineries primarily produce gasoline blendstocks, which must be blended with other liquids. In order to create finished motor gasoline in various grades and formulas, gasoline blendstocks, finished gasoline, and fuel ethanol are combined at blending terminals.
Thus, The principal components of gasoline is 702 g of octane.
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