Answer:
C3N6 is also known as propene(Meythlethylene)
Explanation:
Propene has 3 Carbon molecules and 6 nitrogen molecules. This makes the new substance a non-metal.
3. The average American male consumes 2,000 to 3,000 calories and
females consume 1,600 to 2,400 calories. *
True or False
Answer:
True
Explanation:
Took the quiz already
Answer:
This is true.
Explanation:
The average male consumes 2000-3000 calories per day whereas the average female consumes 1600-2400.
A force of 10 N acts over a surface area of 2 m2. What is the pressure
Answer:
pressure is equals to F/A tge answer is 5pa
A plane decelerates at a constant rate of 3.9 m/s [W]. If the
plane's initial velocity was 24 m/s [E], how long does it take for the
plane to come to a complete stop?
Answer:
t = 6.15 [s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}-a*t[/tex]
where:
Vf = final velocity = 0 (the plane comes to stop)
Vo = initial velocity = 24 [m/s]
a = desacceleration = 3.9 [m/s²]
t = time [s]
Note: The negative sign of the acceleration means that the plane is decreasing its velocity.
[tex]0=24-3.9*t\\3.9*t = 24\\t = 6.15[s][/tex]
A 21.2-kg object is being pulled in one direction by a force of 68.8 N while a force of 26.5 N pulls in the opposite direction. What is the acceleration of the object
The net force is in the direction of the larger force. If we take that direction to be positive, then the net force has a magnitude of
68.8 N - 26.5 N = 42.3 N
Use Newton's second law to solve for the acceleration:
F = m a
42.3 N = (21.2 kg) a
a = (42.3 N) / (21.2 kg)
a ≈ 2.00 m/s²
(you might also try 1.99 or 2.01 in case that doesn't get accepted)
Describe what sandpaper does to wood to make it smoother, and explain why.
Answer it scapes away loose anf rough pieces of wood
Explanation:
Answer:
To achieve a nice smooth finish, it's essential to sand to help prepare the area for painting application, by sanding you are removing imperfections (also known as pimples), creating a nice smooth finish while at the same time adding adhesion by developing small, rough ridges for the paint to stick to.
Using the right sandpaper can make all the difference in a woodworking, painting, or finishing project; but choosing between the many different types of sandpaper that are available can be a challenge. Here are some tips on how to choose the best sandpaper for your next project.
Explanation:
Sry if this is wrong :(
what Is rotational force
Han stands at the rim of the Grand Canyon and yodels down to the bottom. He hears the yodel echo back from the canyon 5.20 seconds later. If sound travels at 340 m/s in air, how deep is the canyon at this location? [Hint: The answer is not equal to 1768 meters]
Answer:
884 meters
Explanation:
h=(340 m/s) x (5.2 s)=1,768
1,768/2=884 meters!
Hope this helped!
What is the force of friction between a block of ice (weighs 930N) and the ground if µs = .12?
Answer: 111.6
Explanation: You would multiply the normal force of the block of ice which is the same number as the weight that was given (930N) , you multiply that by .12 to get the answer of 111.6 N as the force of friction.
a.
According to Figure 2-1, what is the displacement of the mass during interval A-D?
12 meters
18 meters
20 meters
24 meters
Well, the figure seems to report that velocity is measured in m/s²... That label should say m/s. (Unless of course this is the graph of acceleration over time, but then the answer would probably be more complicated than the given choices.)
If the graph indeed shows velocity, and the unit is just a typo, then the displacement from A to D is equal to the area under the curve.
From A to B, the area is of a triangle with height 4 m/s and base 1 s, hence the area is 1/2 • (4 m/s) • (1 s) = 2 m.
From B to C, it's a rectangle with length 3 s and height 4 m/s, hence with area (3 s) • (4 m/s) = 12 m.
From C to D, it's a trapezoid with "height" 2 s and bases 4 m/s and 2 m/s, hence with area 1/2 • (4 m/s + 2 m/s) • (2 s) = 6 m.
The total displacement is then 2 m + 12 m + 6m = 20 m.
what do our ears do
Answer:
hear
Explanation:
stuff stuff moaning and stuff
Which two terms describe the relationship between the two variables in this graph?
A student is collecting data about the transfer of kinetic energy using a pitcher of lemonade. She uses the following procedure in one of the trials of her experiment:
Measure the temperature of the lemonade without ice.
Add 10 ice cubes to the pitcher.
Which step should be next in the procedure?
(1 point)
Set a timer and find out how long it takes for the lemonade to get cold.
Determine the mass of the lemonade with the ice.
Add more ice cubes to the lemonade.
Measure the temperature of the lemonade after the ice has melted.
Answer:
Explanation:
D is my answer
What is represented by the slope of this graph
Answer:
D
Explanation:
on the left u see it says velocity
The process of wind blowing sand from one location to another is called
Weathering
Deposition
Erosion
Answer:
deposition
Explanation:
you are depositing something over
The process of wind blowing sand from one location to another is called erosion. The correct option is option (3).
The process of wind blowing sand from one location to another is known as wind erosion. It involves the movement and transport of sand particles through the force of the wind.
Wind erosion occurs when the force of wind lifts and carries sand particles, causing them to collide with and erode other surfaces. This process can lead to the formation of sand dunes and the reshaping of landscapes.
Therefore, The process of wind blowing sand from one location to another is called erosion. The correct option is option (3).
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Molly likes to eat oranges year round, but her friends tell her that she is not living sustainably by doing that. Why is that?
A. oranges take a long time to grow
B. oranges are not a healthy fruit
C. oranges are too expensive
D. out-of-season fruit has to be shipped in from around the world
E. orange peel takes too long to decompose
Answer:
E. orange peel takes too long to decompose
Explanation:
Orange peels: It is estimated that orange peels take around 6 months to decompose,
Answer:
The answer is A
Explanation:
I used the process of elimination.
It couldn't be B because oranges are healthy
It couldn't be C because oranges aren't that expensive
It couldn't be D because oranges are sold year round
It couldn't be E because even though they do take around 6 months to decompose, they aren't bad for the environment
That leaves A
A supertanker ( = 1.70 × 108 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.40 × 105 N. Determine (a) the magnitude of the resistive force exerted on the tanker by the water and (b) the magnitude of the upward buoyant force exerted on the tanker by the water.
I need work shown thank u
Answer:
(a) 0 (b) [tex]F=1.67\times 10^9\ N[/tex]
Explanation:
Given that,
Mass of a supertanker, [tex]m=1.7\times 10^8\ kg[/tex]
The engine of a generate a forward thrust of, [tex]F=7.4\times 10^5\ N[/tex]
(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :
F = ma, a is the acceleration
For constant velocity, a = 0
So, F = 0
(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.
F = mg
[tex]F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N[/tex]
Hence, this is the required solution.
while dipping a solid object in a liquid upthrust on the object due to the liquid and the weight of the displaced liquid are shown to be equal in an experiment.which principal does the experiment?
Answer:
If you try to lift up a weight in a swimming pool and then try to lift the same weight on the edge of the pool, it feels much lighter in the water.
This was supposed to have been first explained by the Greek scientist Archimedes. He said that the water gives an upward force or upthrust on any object in it.
You can weigh an object in air and then in water and actually work out the upthrust, it is the difference between the two readings. For this reason the upthrust is often called the loss in weight of the object.
HURRYYYWhich tools do meteorologists use to collect data about the weather?
Answer:
A. Satellites
( Hope this helps ) <3 ( Give person above brainliest )
_________ is stored energy.
(A) Potential
(B) Kinetic
(C) None of the above
(D) All of the above
Answer:
I think so is b kinetic o a potential
. A car going 50 m/s accelerates to pass a truck. Five seconds later the car is going 80m/s. Calculate the acceleration of the car.
What does the blackboard do when white light falls on it?
Is speed always equal to velocity?
Answer: Speed can equal to velocity, even though they have different formulas.
Explanation: Speed is the rate at which an object covers distance or how much space the object passed, which is usually measured in miles, meters, or kilometers. Velocity is the rate at which the position changes. Therefore, speed is and can equal to velocity.
Formulas:
Speed = distance/change in time
Velocity = change in distance/ change in time
What is the kinetic energy of a baseball moving at a speed of 40 m/s if the baseball has a mass of 0.15kg
Answer:
120
Explanation:
KE = (mv^2)/2
= ((0.15)(40)^2)/2
= ((0.15)(1600))/2
= 240/2
The world speed record on water was set on October 8, 1978 by Ken Warby. If Ken drove his motorboat a distance of 1500 m in 8.102s, how fast was his boat moving in meters per second and kilometers per hour?
Answer:
317.52 mi/hr
Explanation:
First convert Meters into miles as the answer is required in miles/ h
1000m = 0.62 mi
Now, convert second into hours
7.45s = 0.0001 hr
The speed of the boat would be
v = 0.62/0.0001
=317.52 mi/hr
the second question. the answer to the first part is 616. pls i have a 34 on the assignment rn pls help
Answer:
a) Ffloor = 616.56[N]
b) Ffloor = 484.16 [N]
Explanation:
In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.
Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.
ΣF = m*a
where:
F = force [N] (units of Newtons]
m = mass [kg]
a = acceleration [m/s²]
g = gravity acceleration = 9,81 [m/s²]
a)
[tex]F_{floor} -m*g = m*a[/tex]
[tex]F_{floor} -(56*9.81)=56*1.2\\F_{floor}= 616.56[N][/tex]
b) Using Newton's second law we have.
[tex]F_{floor}-m*g= -m*a\\F_{floor}=-m*a+m*g\\F_{floor} = -(56*1.2) + (56*9.81)\\F_{floor} = 484.16 [N][/tex]
A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second. What is the magnitude of the vertical component of its initial velocity?
Answer:
5 sq. root 3
Explanation:
theta= 60°
=> u sin theta = 10 × sin 60
= 10× sq. root 3/2
= 5 sq. root 3
we have that from the Question"A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second" it can be said that
the magnitude of the vertical component of its initial velocity is
Fy=8.660NFrom the Question we are told
A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second. What is the magnitude of the vertical component of its initial velocity?
Generally the equation for vertical component is mathematically given as
The vertical component will be the resolution of the vertical axis
Therefore
Fy=10sin60
Fy=8.660N
Therefore
the magnitude of the vertical component of its initial velocity is
Fy=8.660NFor more information on this visit
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Sanjeev wants a rug for his room. Which SI unit is best for describing the area of his room?
Answer:
meters squared
Explanation:
Need help ASAP please!!!
Starting from rest, you apply a constant, horizontal force of magnitude F to an object of mass M, causing the object to move distance D. You do work W on the object. If you repeated the scenario but with an object of mass 2M, how much work would you do on the object?
The answer choices are W/4, W/2, W, 2W, and 4W.
Anwer should W
Becuase W= F*D
Which would take a longer time to warm up, a piece of brass or a piece of marble, given that both have the same mass? Explain your answer.
Answer:
you probably have to take into account molecular density if you want the scientific answer. I would assume that marble is significantly more dense then brass and on top of that metals are a better conductor of heat. So I would say that a piece of brass would warm up faster
A football punter wants to kick the ball so that it is in the air for 4.2 s and lands 55 m from where it was kicked. Assume that the ball leaves 1.0 m above the ground.
Part A: At what angle should the ball be kicked?
Part B: With what initial speed should the ball be kicked?
Answer:
[tex]57.24^{\circ}[/tex]
24.21 m/s
Explanation:
x = Displacement in x direction = 55 m
y = Displacement in x direction = 0
[tex]y_0[/tex] = Height of the ball when the ball is kicked = 1 m
t = Time taken = 4.2 s
[tex]a_y=g[/tex] = Acceleration due to gravity = [tex]-9.81\ \text{m/s}^2[/tex]
u = Initial velocity of ball
Displacement in x direction is given by
[tex]x=u_xt+\dfrac{1}{2}a_xt^2\\\Rightarrow 55=4.2u_x+0\\\Rightarrow u_x=\dfrac{55}{4.2}\\\Rightarrow u\cos\theta=13.1\ \text{m/s}\\\Rightarrow u=\dfrac{13.1}{\cos\theta}[/tex]
Displacement in y direction is given by
[tex]y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 0=1+4.2u\sin\theta+\dfrac{1}{2}\times (-9.81)\times 4.2^2\\\Rightarrow 0=4.2u\sin\theta-85.5242\\\Rightarrow u\sin\theta=20.36\ \text{m/s}\\\Rightarrow u=\dfrac{20.36}{\sin\theta}[/tex]
[tex]\dfrac{13.1}{\cos\theta}=\dfrac{20.36}{\sin\theta}\\\Rightarrow \dfrac{20.36}{13.1}=\dfrac{\sin\theta}{\cos\theta}\\\Rightarrow \theta=\tan^{-1}\dfrac{20.36}{13.1}\\\Rightarrow \theta=57.24^{\circ}[/tex]
The ball should be kicked at an angle of [tex]57.24^{\circ}[/tex]
[tex]u=\dfrac{13.1}{\cos\theta}=\dfrac{13.1}{\cos57.24^{\circ}}\\\Rightarrow u=24.21\ \text{m/s}[/tex]
The initial speed of the ball is 24.21 m/s.
The number of unknowns in the question are two therefore two equations
are required to find a solution.
Part A: The angle at which the ball should be kicked is approximately 57.56°
Part B: The initial speed with which the ball should be kicked is approximately 24.41 m/s.
Reasons:
The given parameters are;
Time the ball should be in the air = 4.2 s
Point the ball should land, d = 5.5 m from where it was kicked
Height at which the ball leaves the ground = 1.0 m
Part A;
The angle at which the ball should be kicked.
Solution;
The horizontal distance, d = uₓ·t
Therefore;
[tex]u_x = \dfrac{d}{t} = \dfrac{5.5}{4.2} = \dfrac{55}{42}[/tex]
[tex]u_x = u \cdot cos(\theta)= \dfrac{55}{4.2}[/tex]
Where;
u = The initial velocity
[tex]Vertical \ motion , \ h =\mathbf{h_0 + u_y\cdot t - \dfrac{1}{2} \cdot g \cdot t^2}[/tex]
Which gives;
[tex]0 =1 + u_y\times 4.2 - \dfrac{1}{2} \times 9.81 \times 4.2^2 = 4.2\cdot u_y - 86.5242[/tex]
[tex]u_y =u \cdot sin(\theta) = \dfrac{86.5242}{4.2} = 20.601[/tex]
[tex]\dfrac{u_y}{u_x} =\dfrac{20.601}{\left(\dfrac{55}{4.2} \right)} = \mathbf{ \dfrac{u \cdot sin(\theta)}{u \cdot cos(\theta)}} = tan\left( \theta)[/tex]
[tex]\mathrm{The \ angle \ at \ which \ the \ ball \ should \ kicked } \ \theta = arctan \left(\dfrac{20.601}{\left(\dfrac{55}{4.2} \right)} \right) \approx \underline {57.56 ^{\circ}}[/tex]
Part B
[tex]u \cdot cos(\theta)= \dfrac{55}{4.2}[/tex]
[tex]The \ initial \ speed, \ u= \dfrac{55}{4.2 \times cos(57.56^{\circ })} \approx 24.41[/tex]
The initial speed of the ball, u ≈ 24.41 m/s
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