The [H3O+] in step 1 is 0.0034 M while the [H3O+] in step 2 is 0.00039 M
What is the contribution of each step?Let us set up the ICE table in each case, for K1;
H2A(aq) + H2O(l)--------> H3O^+(aq) + HA^-(aq)
I 0.12 0 0
C -x +x +x
E 0.12 - x x x
Ka1= [H3O^+] [HA^-]/[ H2A]
Ka1= x^2/ 0.12 - x
1.0×10^−4 = x^2/ 0.12 - x
1.0×10^−4(0.12 - x ) = x^2
1.2 * 10^-5 - 1.0×10^−4x = x^2
x^2 + 1.0×10^−4x - 1.2 * 10^-5 = 0
x =0.0034 M
[H3O+] = 0.0034 M
Again; [H3O+] = [HA^-] = 0.0034 M
HA^-(aq) + H20(l) -------> A^-(aq) + H3O^+
I 0.0034 0 0
C -x + x +x
E 0.0034 - x x x
Ka2= [A^-] [H3O^+]/[HA^-]
5.0×10^−5 = x^2/ 0.0034 - x
5.0×10^−5 (0.0034 - x ) = x^2
1.7 * 10^-7 - 5.0×10^−5x = x^2
x^2 + 5.0×10^−5x - 1.7 * 10^-7 = 0
x=0.00039 M
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Simon measured the density of a piece of metal
to be 11.70 g/cm³. However, the manufacturer
claims it has a density of 12.00 g/cm³. What is
the percent error of Simon's measurement?
From the question we know that 12 - 11.70 = 0.3 so 0.3 / 12 = 0.025 therefore Simon's percent error is 2.5%.
Percent error compares an estimate to an accurate value and expresses the difference among them as a percent. This statistic lets analysts recognize the scale of the mistake relative to the true cost. it's also referred to as percentage error as well as % mistakes.
Percentage errors Calculation Steps :
Subtract one cost from another.Divide the mistake by the exact or ideal price (not your experimental or measured value).Convert the decimal variety into a percentage by multiplying it by using 100.Add a percent or % symbol to record your percentage mistakes value.Percentage error tells you the way huge your mistakes are when you degree something in an experiment. Smaller values suggest that you are close to the accepted or actual value. for instance, a 1% blunder means that you obtain very near the accepted value, whilst 45% means that you were pretty a long way off from the real value.
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Which is an acidic functional group that can dissociate and release h into a solution?
The acidic functional group that can dissociate and release h into a solution is -COOH.
Characteristics of a carboxyl group -COOHCarbon atom is bonded to a high electronegative oxygen and a hydroxyl group in the Carboxyl groupExample: Acetic acid CH3COOHThe acidic functional group ( -COOH ) dissociate and releases H atom from the hydroxyl group into a solution as a proton or as a H+ ionHence the Oxygen atom gets a negative chargeThis negative charge moves between both the oxygen atom.From the characteristics of -COOH group we can conclude it as the acidic functional group that can dissociate and release H into a solution.
Disclaimer: The question was incomplete
Which is an acidic functional group that can dissociate and release h into a solution?
A. -OH
B. -COOH
C. -NH2
D. -SH
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Two cars A and B are moving in opposite directions with the velocity of 20m/s and 6m/s respectively Calculate the relative of car A with respect to car B If they move in the same velocity what will be the relative velocity of CarA with respect to Car B
The relative velocity is described as the velocity of an object with respect to another viewer. It is the time rate of shift of relative position of one object with respect to another object.
How to find out the Relative Velocity of car A and car B ?a) Velocity of car A (Va) = 20m/s
Velocity of car B (Vb) = -6m/s
To find the Relative Velocity, we should apply the formula as,
Relative Velocity of car A and car B = Vab
Vab = Va - Vb
Vab = 20 - (-6)
Vab = 20+6
Vab = 26m/s
b). if Velocity of car A = Velocity of car B
Va = Vb
In this case,
Relative Velocity = Vab
Vab = Va - Vb
(since Va = Vb)
Vab = 0m/s
Hence, the Relative Velocity in a). is 26m/s and in b). is 0m/s.
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Electric vehicles have less range they can drive compared to plug-in hybrid electric vehicles. true false
Answer is plug-in hybrid cars also offer advantages and disadvantages. The primary benefit is range. Plug-in hybrid vehicles include a gasoline engine in addition to an electric motor, whereas an electric car can only go as far as its batteries will allow. Plug-in drivers benefit from having the best of both worlds as a consequence.
what is a electric vehicle?
An electric car is fully electric. Instead of a petrol tank, it has a battery, and an electric motor rather than an internal combustion one. If your batteries run out, there isn't a backup motor like in a hybrid electric vehicle. Many versions, nevertheless, offer space for an extra battery. The Nissan Leaf, Tesla Model S, and Ford Focus Electric are a few examples.
what is a plug in hybrid electric vehicle?
A plug-in hybrid electric car combines (or, if you prefer, is a hybrid of) an electric and gasoline-powered vehicle. They have a gas tank, an internal combustion engine, an electric motor, and a battery. You could say they have everything. Gasoline and electricity are both used as fuel in plug-in hybrid electric vehicles. The Chevrolet Volt, Toyota Prius Plug-in, and Cadillac ELR are a few examples.
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Finding mole ratios from chemical formulae
This is the chemical formula for nickel tetracarbonyl (a powerfully poisonous liquid used in nickel refining):
Ni(CO)4
A chemical engineer has determined by measurements that there are 93. moles of carbon in a sample of nickel tetracarbonyl. How many moles of oxygen are in
the sample?
Round your answer to 2 significant digits.
7 moles of oxygen are in the sample.
According to the chemical formula, each mole of nickel tetracarbonyl contains 4 moles of C atoms. Simply convert it into a fraction by putting the original solution in the denominator and the diluted solution in the numerator if you need to determine the concentration ratio between two solutions. The V/n ratio for each gas must be the same if the two gases are at the same temperature and pressure. The volume ratio of two gases at the same temperature and pressure is equal to their molar ratio. The mole ratio of C to O is 1 : 1
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The kb of hypochlorous acid is 3. 0×10^–8 at 26. 0 C. What is the percent of ionization of hypochlorous?
The acid dissociation constant (Ka) defines the difference between a weak and a strong acid. The % ionization of hypochlorous acid is 0.14%.
What is the acid dissociation constant?The acid dissociation constant is used to define the ionization constant of an acidic substance. It gives the quantitative measurement of the strength.
The ICE table is attached to the image below.
The acid dissociation constant (Ka) for the reaction is,
Ka = [H⁺][ClO⁻] ÷ [HClO]
= a² ÷ (0.015 - a)
= 3.0 x 10⁻⁸
Now, a² + 3.0 x 10⁻⁸ a - 4.5 × 10⁻¹⁰ = 0
So, a = 2.210 × 10⁻⁵
Solving further,
[H+] = a = 2.210 × 10⁻⁵ M
The percent ionization is calculated as,
[H+] ÷ [HClO] × 100
= 2.210 × 10⁻⁵ M ÷ 0.015 × 100
= 0.14 %
Therefore, 0.14 % is the percentage of hypochlorous ionization.
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Your question is incomplete, but most probably your full question was, The ka of hypochlorous acid (HClO) is 3.0 x 10⁻⁸ at 25.0°C. What is the % of ionization of hypochlorous acid in a 0.015 aqueous solution of HClO at 25.0C?
3. 2.71x1022 molecules of CO2 to atoms I NEED HELP
2.71 x 10²² molecules of CO2 is equivalent to 2.71 x 10²² atoms.
What is number of molecules?The number of molecules in an element is the combination of atoms in that element.
The number of molecules of an element can be calculated by multiplying the number of moles of that element by Avogadro's number, which is 6.02 × 10²³.
However, the number of molecules in a substance is equivalent to the number of atoms in that substance.
Therefore, 2.71 x 10²² molecules of CO2 is equivalent to 2.71 x 10²² atoms.
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A substance decays so that the amount a of the substance left at time t is given by: a = a0 ∙ (0.8)t where a0 is the original amount of the substance. what is the half-life (the amount of time that it takes to decay to half the original amount) of this substance rounded to the nearest tenth of a year?
The half-life of the substance is 3.106 years.
What is the formula for exponential decay?The exponential decline, which is a rapid reduction over time, can be calculated with the use of the exponential decay formula. The exponential decay formula is used to determine population decay, half-life, radioactivity decay, and other phenomena. The general form is F(x) = a.Here,
a = the initial amount of substance
1-r is the decay rate
x = time span
The equation is given in its correct form as follows:
a = [tex]a_{0}[/tex]×[tex](0.8)^{t}[/tex]
As this is an exponential decay of a first order reaction, t is an exponent of 0.8.
Now let's figure out the half life. Since the amount left is half of the initial amount at time t, that is when:
a = 0.5 a0
Substituting this into the equation:0.5[tex]a_{0}[/tex] = [tex]a_{0}[/tex]×[tex](0.8)^{t}[/tex]
0.5 = [tex](0.8)^{t}[/tex]
taking log on both sides
t log 0.8 = log 0.5
t = log 0.5/log 0.8
t = 3.106 years
The half-life of the substance is 3.106 years.
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I have a mixture of sand salt and water from the sea. Describe in detail how I separate these three substances and explain why each method works
Answer:
You can separate a mixture of sand, salt and water by decantation and evaporation. Decantation will separate sand from salt and water. Sand remains in the original vessel, whereas salt and water is transfered to new vessel. Evaporation will separate salt from water.
What can be said about this reaction when the concentration of 2-phosphoglycerate is 0.490 mm and the concentration of 3-phosphoglycerate is 2.90 mm at 25°c?
The reaction is at equilibrium. Option C
What is the equilibrium constant?The term equilibrium constant refers to a value that shows the extent to which reactants are converted into products in the reaction.
We know that;
∆G =∆G'° + RT In Keq
∆G'° = −4.40 kJ/mol
R = 8.314 J/K/mol
T = 25 + 273 = 298 K
Thus;
∆G = −4.40 * 10^3 + (8.314 * 298 * ln[2.90 * 10^-3/0.490 * 10^-3]
∆G = −4.40 * 10^3 + 4.40 * 10^3
∆G = 0
Hence, the reaction is at equilibrium.
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1) Consider the following metabolic reaction:
2-Phosphoglycerate ® 3-Phosphoglycerate DG°' = −4.40 kJ/mol
What can be said about this reaction when the concentration of 2-phosphoglycerate is 0.490 mM and the concentration of 3-phosphoglycerate is 2.90 mM at 25°C?
I. This reaction is endergonic under these conditions.
II. This reaction is exergonic under these conditions.
III. This reaction is at equilibrium under these conditions.
IV. This reaction is not favorable under standard conditions.
A) I, IV
B) II only
C) III only
D) IV only
E) None of the above
2) Consider the following metabolic reaction:
What process involves the addition of a hydrogen molecule to compounds containing multiple bonds?
The process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.
Unsaturated hydrocarbons are transformed into saturated hydrocarbons by the addition process when they interact with hydrogen gas and nickel. The term "hydrogenation reaction" is also employed to describe this process.
In the production of fats and oils, hydrogenation seems to be crucial for two reasons. It increases the oil's oxidative stability and turns liquid oils become semisolid or plastic fats for use in shortenings as well as margarine, among other things.
Therefore, the process which involves the addition of a hydrogen molecule to compounds containing multiple bonds will be known as hydrogenation reaction.
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In the following 2 questions, determine what is being oxidized and what is being reduced in each reaction. Identify the oxidizing and reducing agents in each :
a. 2Mg(s) + O2(g) → 2MgO(s)
b. Pb(NO3)2(aq) + Zn(s) → Zn(NO3)2(aq) +Pb(s)
a) Mg is oxidized and O2 is reduced
b) Zn is oxidized while Pb(NO3)2 is reduced.
Oxidation and reductionOxidation is defined as:
loss of electronsremoval of hydrogenaddition of oxygenincrease in oxidation numberremoval of electropositive elementsReduction is defined as:
gains of electronsaddition of hydrogenremoval of oxygendecrease in oxidation numberaddition of electropositive elementsLooking at the first reaction, the Mg atom gains oxygen to become MgO. This means that Mg is oxidized. The oxidizing agent is O2. At the same time, O2 is being reduced and the reducing agent is Mg.
For the second reaction, the oxidation number of Pb is reduced from +2 to 0. Thus, Pb has been reduced by Zn while Zn itself has been oxidized. The reducing agent here is Zn while the oxidizing agent is Pb(NO3)2.
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Write an equation to represent the following reaction:
Borax is heated with CoO
The equation of the reaction is; B2O3 + CoO -----> Co(BO2)2.
What is a reaction?The term chemical reaction has to do with the interaction between reactants in order to yield products. We know that when a chemical reaction occurs, the reactants are rearranged to form the products.
Now the first step in this reaction is that the Borax is heated to form boric anhydride (B2O3). Thus compound now reacts with cobalt II oxide as follows; B2O3 + CoO -----> Co(BO2)2.
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To prevent the system refrigerant from quickly dropping in temperature and pressure, refrigerant recovery should?
To prevent the system refrigerant from quickly dropping in temperature and pressure, refrigerant recovery should Begin with a liquid
In the refrigeration cycle of air conditioners and heat pumps, refrigerants are working fluids that typically go through numerous phase changes from a liquid to a gas and back again.
In the refrigeration cycle, which cools a place, a refrigerant is a material, frequently a fluid. Refrigerants use the thermodynamic phenomenon of phase transitions, in which a fluid transforms into a gas or vice versa, to absorb heat and then release it to another area.
At room temperature, it is often a gas. Ammonia, sulfur dioxide, and non-halogenated hydrocarbons like propane are further typical refrigerants that are employed in a variety of applications.
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If the decomposition of a sample of k c l o 3 kclox3 produces 3. 29 g of o 2 ox2 , what was the mass (g) of the original sample?
The mass (g) of the original sample after decomposition is 8.3983 g.
A decomposition reaction can be described as a chemical reaction wherein one reactant breaks down into or extra merchandise.
explanation:
Reaction 2KClO₃ ⇒ 2KCl + 3O₂
moles 2 2 3
molar mass 122.55 74.55 32
Given, Mass of O₂ = 3.29g ⇒ moles of O₂
= (3.29/32) = 0.1028
3 moles of O₂ produced by 2 moles of KClO₃
Therefore, 0.1028 moles of O₂ produced by (2*0.1028/3) = 0.06853 moles of Kclo₃
Mass of KClo₃ in original sample is = moles * molar mass
= 0.06853 * 122.55
= 8.3983 g
A decomposition response occurs whilst one reactant breaks down into or extra merchandise. this may be represented through the general equation: XY → X+ Y. Examples of decomposition reactions consist of the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.
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HELP PLS PLS PLS ILL MARK U BRAINLIEST!
Answer:
2 NaI ---> 2 Na + I₂
Explanation:
The only way the reactant NaI can decompose is by separating into 2 atoms, Na and I. However, you must take into account that iodine (I) exists as a diatomic molecule.
An equation is balanced when there is an equal amount of each element on both sides of the reaction. These amounts can be modified by adding coefficients in from of the molecules/atoms.
The unbalanced equation:
NaI -----> Na + I₂
Reactants: 1 sodium, 1 iodine
Products: 1 sodium, 2 iodine
The balanced equation:
2 NaI ---> 2 Na + I₂
Reactants: 2 sodium, 2 iodine
Products: 2 sodium, 2 iodine
Consider your results for the 0. 1-m znso4 solution. is the solution acidic or basic?
0. 1-m zinc sulfate - znso4 solution. is the solution acidic solution
Zinc sulfate is the inorganic compound with the formula ZnSO4 and historically known as "white vitriol". Zinc Sulfate is a prescription drug used to treat zinc deficiency. The body's healthy tissues grow and develop more quickly thanks to zinc sulfate.
Zinc sulfate inhalation can harm the respiratory system, bring on nausea, vomiting, stomach pain, disorientation, depression, and even death. Skin injury from exposure through skin contact can result in blisters, ulcers, and scars. In cases of mild to moderate acne, topical 5% zinc sulfate proved beneficial. In cases of moderate to severe acne, oral zinc gluconate and sulfate were helpful.
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What would the potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions? [h ]=0. 84 mh2=2. 2 atm=298 k
The potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions is - 0.029 V
Calculation ,
Formula used :
[tex]E_{cell}[/tex] = [tex]E_{cell}[/tex] ° - 0.059/n ㏒[tex]H_{2}[/tex]/ [tex][H^{+}]^{2}[/tex]
As we know that ,
[[tex]H^{+}[/tex]] = 0. 84 M
[tex]P_{H_{2}[/tex] = 2. 2 atm
Temperature ( T ) = 298 K
From reaction at electrode number of electrons involve ( n ) = 1
Standard electrode potential of standard hydrogen electrode [tex]E_{cell}[/tex] ° = 0
Putting the value of all data in equation ( i ) , we get
[tex]E_{cell}[/tex] = 0 - 0.059/1 ㏒2. 2 / [tex](0. 84)^{2}[/tex] = - 0.059 ㏒3.14 = - 0.059×0.497
[tex]E_{cell}[/tex] = - 0.029 V
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Alkali metals nitrates on heating give the corresponding __ and oxygen.
Alkali metals nitrates on heating give the corresponding nitrogen dioxide and oxygen.
What are alkali metals?These are the metals which forms alkali when dissolved in water. They are any of the soft, light, reactive metals of Group 1 of the periodic table.
Some examples of alkali metals are as follows:
LithiumSodiumPotassiumCesiumrubidiumfranciumA periodic table is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same column.
So therefore, alkali metals nitrates on heating give the corresponding nitrogen dioxide and oxygen.
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If the dehydration reaction of an alcohol is successful. What changes would be seen in the ir spectrum for the product compared to the starting material?
If the dehydration reaction of an alcohol is successful. The changes would be seen in the IR spectrum for the product compared to the starting material are as,
The O-H and C-O band is disappear from stating materialThe addition of a C-C double bond band in the product.In dehydration reaction of alcohol ( O-H and C-O bond ) contain , the water molecule ( [tex]H_{2}O[/tex] ) is release from the reactant and C-C double bond is form which is known as alkene in the product .
The reactant and product have different structure. To determine the structure of the compound IR spectroscopy is used. In IR spectrum the peak corresponds to 3400-3600 cm is missing in the product of dehydration reaction of an alcohol. It means O-H band is disappear from stating material.
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A bumblebee carries pollen from the male portion of a plant to the female portion of the similar plant. Fertilization occurs. Which statement is true about this type of reproduction?
Answer:
It’s sexual, and the offspring are genetically different from the parents
Explanation:
Since it is the same flower the bee is pollinating, the progeny will be genetically distinct if the bee were to transfer the pollen to the female part of the flower from the male part.
What non-metal has less than 4 valence electrons (Outmost cells electrons)?
Correct Answer: Boron family
In an sn2 reaction between bromomethane and hydroxide ion, the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles the rate of reaction?
The rate of reaction in SN2 reaction becomes four times when the the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles.
In SN2 reaction, the rate of reaction is depend on the concentration of both reactant.
For SN2 reaction,
r = k[bromoethane] [hydroxide ion]
r = k [CH3CH2Br] [OH]
When the concentration of bromoethane is doubled and the concentration of hydroxide ion doubles then,
r = k 2×[CH3CH2Br] × 2[OH]
r = 4k[CH3CH2Br] [OH]
Thus, we concluded that the rate of reaction in SN2 reaction becomes four times.
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If 0. 5371 g of zn was plated onto an electrode, how much charge (in coulombs) was used to reduce the zn2+ to zn(s)?
The amount of charge required to reduce Zn²⁺ to Zn is 1585.26 coulomb.
What is electrolysis?The process that has been equipped with the use of electric current to break the chemical compound and deposited at the constituent electrodes is termed as electrolysis.
The reaction of reduction of Zn can be given as:
Zn²⁺ + 2e⁻ → Zn (s)
Molar mass of Zn = 65.39 g
The equivalent of Zn²⁺ has been:
Equivalent = atomic mass/equivalent weight
Equivalent Zn²⁺ = 65.39/32.69
Equivalent Zn²⁺ = 2 mol
1 equivalent = 1 F charge used
2 mol equivalent = 2 F charge used
Charge in coulomb can be given as:
1 Faraday = 96500 coulomb
2 F = 96500 * 2 coulomb
2 F = 1,93,000 coulomb
The moles of Zn to be deposited is:
Moles = weight /molar weight
Moles = 0.5371 g/ 65.39 g/mol
Moles = 0.00821 mol
Therefore, the charge used for the deposition of 0.00821 mol is:
Charge = 0.00821 * 1,93,000 coulomb
Charge = 1585.26 coulomb
1585.26 coulomb charge was used to reduce the Zn²⁺ to Zn.
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In the laboratory, a student dilutes 18. 9 ml of a 10. 0 m perchloric acid solution to a total volume of 250. 0 ml. what is the concentration of the diluted solution? concentration = m submit answer
The concentration of diluted solution is 0.756M.
From the question given above, the following data were obtained:
Volume of stock solution (V1) = 18.9 mL
Molarity of stock solution (M1) = 10 M
Volume of diluted solution (V2) = 250 mL
Molarity of diluted solution (M2) =?
We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:
M1V1 = M2V2
10 × 18.9 = M2 ×250
189 = M2 × 250
Divide both side by 100
M2 = 189 / 250
M2 = 0.756 M
Therefore, the molarity of the diluted solution is 0.756 M.
Thus the concluded that concentration of the dilute acid is 0.756 M.
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The sp of pbbr2 is 6. 60×10−6. what is the molar solubility of pbbr2 in pure water?
Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.
Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.
Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.
Let the molar solubility be S upon dissociation.
PbBr₂ or Lead Bromide dissociates in pure water as follows:
PbBr₂ ----------> Pb⁺² + Br⁻
S 2S
Ksp = [Pb⁺²] [ Br⁻]
Ksp = (S) (2S)²
Ksp = 4S³
6.60 × 10⁻⁶ = 4S³
S = 0.0118M
Hence, the Molar solubility S is 0.0118M.
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Which spectroscopic tool would be best for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane?
1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
The preferred method for determining or validating the structure of organic molecules or those containing protons is H NMR. When compared to other nuclei, a solution-state proton spectrum may be obtained relatively quickly, and it contains a wealth of knowledge regarding a compound's structure.
It can be calculated by simply counting the number of unique hydrogens on one side of the symmetry plane will give you the count of signals individual molecules emit in a 1H NMR spectrum.
Therefore, 1-H NMR spectroscopy tool will be used for distinguishing a sample of 1,2,2-tribromopropane from 1,1,2-tribromopropane.
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Draw the lewis structure of scl₂ and then determine the hybridization of the central atom
The hybridization of the central atom in SCl₂ is sp³.
What is Lewis Structure ?Lewis structure is also known as Lewis dot structure which simply represent the valence electron of an atom.
What is Hybridization ?Hybridization is defined as the mixing of two atomic orbitals belongs to same atom but having entirely different shapes , energies which produces a new hybridized orbitals.
Now first write the electronic configuration of central atom.
The central atom in SCl₂ is S (Sulphur).
Electronic configuration of S: [Ne] 3s² 3p⁴
One 3s and three 3p undergo hybridization to form sp³ orbitals. Here each atom forms bond with one sp³ hybrid orbital.
Thus from the above conclusion we can say that The hybridization of the central atom in SCl₂ is sp³.
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A solution has a [h3o ] of 1 × 10−5 m. what is the [oh−] of the solution? 9 m 14 m 1 × 10−9 m 1 × 10−14 m
option (c) 1 × 10-9 m is the right answer.
The [oh−] of the solution having a [h3o ] of 1 × 10−5 m is 1 × 10-9 m.
What is [OH−] of the solution?The only component of water is H2O, and when the pH of the solution is 7, all of the ions have the same concentration, whereas during dissociation the water splits into H+ and OH- ions.
The concentration of OH- ions will be,
OH- = Kw {H3O+}
{H3O+} = 1 × 10−5 M.
Kw = 14
On substituting the value in the equation,
OH = 14 { 1 × 10−5 M.}
OH = 1 × 10−9 M
Consequently, the [H3O+] of the solution is 1 × 10-5 M.
Option (C) is the right choice because the [OH-] of the solution will be 1 × 10-9 M.
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Which are properties of all metals (except hg)? i. good conductors of heat and electricity ii. easily formed into sheets or wires iii. chemically unre
The properties of all metals are "good conductors of heat and electricity".
Metals are excellent heat or electricity conductors and were malleable, ductile materials that may be pulled into wire and pounded into sheets. Apart from mercury, which appears a liquid at ambient temperature, most metals have solids with a distinctive silvery shine.
Due to the metals' atoms' ability to create a matrix across which outside electrons could easily travel, metals make good electrical and thermal conductors. The positive nuclei of the connecting metal ions are surrounded by a sea of electrons rather than orbiting their individual atoms.
Therefore, the properties of all metals are "good conductors of heat and electricity".
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