Answer:
Explanation:fog
The temperature at which water leaves the boiler is?
Answer:
The average setting for a gas-powered hot water boiler is 180°F. This provides the appropriate level needed for most cold weather temperatures. If you can raise the temperature manually, do not set it any higher than 210°F (which is often the limit), and try to remain down at 190°F if you need the extra heat.
The pressure of a liquid is given by P = pgh. Calculate the pressure (in SI unit) if the
density of water, p is 1 g cm-, the acceleration due to gravity, g is 10 m s?, and the
height of water, h is 50 cm.
Answer:
5000 Pa
Explanation:
First collect the data you've been given already and make sure to convert into the right units;
Density = 1 g/cm³ ...... 1000 Kg/ m³
acceleration due to gravity = 10 m/s²
Height = 50 cm......0.5 m
after collecting the data, use the formula to solve
pressure = pgh
= 1000 × 10 × 0.5
= 5000 Pa
hope this helps
Which is an accurate statement about a magnetic field's direction?
The magnetic field goes from the north pole to the south pole.
The magnetic field goes from the south pole to the north pole.
The direction of the magnetic field depends on the strength of the field.
The magnetic field depends on if the magnet is man made or natural
The direction of a magnetic field can be accurately described as flowing from the north pole to the south pole,
What is a magnetic dipole?When considering the idea of a magnetic dipole, it involves having two magnetic poles that possess equal strength but differ in polarity. This particular configuration results in the creation of a magnetic field that flows from the north to south pole. The magnitude of this field is determined by the size of the magnetic dipole moment, which serves as a distinctive quality of the magnet.
Which is an accurate statement about a magnetic field's direction?The idea of a magnetic field pertains to a specific region in space that can exert magnetic force on either a magnet or a charged particle in motion. The orientation of the magnetic field lines indicates the direction of the force that would affect any magnetic object within the field. It's important to note that these lines always form closed loops, originating from the north pole of the magnet and extending through surrounding space before ultimately returning to enter at its south pole. This implies that without fail, magnetic field lines travel from north to south pole, with this directional flow being reliant on the magnet's magnetic dipole moment.
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can someone help me this question
Answer:
Volume of wood is 68-50 = 18 cm³
Explanation:
Hope it helps youHow many mm is 97.25cm?
Answer:
972.5 mm
Explanation:
Since there are 10 millimeters in one centimeter, we move the decimal place to the right once to convert from cm to mm.
Any two importance of measurement
Answer:
to sell and to buy
Explanation:
measurement is a comparison between unknown quantity with a known quantity
A car increases velocity from 25 m/s to 50 m/s in 5 seconds. What is the acceleration of the car?
Answer:
the acceleration of the car is 5m/s2
A train started its journey at 9:00. Its average speed between
9:00 and 13:00 was 80 km/h. It travelled 1/5 of its journey by
13:00. If the train was required to arrive at the destination at
21:00, what average speed must the train travel at for the rest
of the journey?
Answer:
Explanation:
In the four hours before 13:00 the train traveled 4(80) = 320 km.
It needs to travel another 4(320) = 1280 km in the next 21:00 - 13:00 = 8 hrs.
1280 / 8 = 160 km/hr
We can define average speed as:
s = (distance traveled)/(time it takes)
Using this, we will find that the average speed at which the train must travel the rest of the journey is 160km/h.
Here the given information is:
The train starts its journey at 9:00
The average speed between 9:00 and 13:00 was 80km/h, and it travels 1/5 of the journey by 13:00.
Then, if we define D as the total distance of the whole journey, in that lapse of 4 hours the train traveled 1/5 of D, or just D/5.
Then we can write the average speed as:
[tex]80km/h = \frac{(D/5)}{4h}[/tex]
[tex]80km/h*4h = D/5[/tex]
[tex]320km = D/5[/tex]
[tex]5*320km = D = 1,600km[/tex]
This means that the total distance of the journey is 1,600km
And at this time (13:00) the train already traveled 320km, so the distance left is:
[tex]d = 1,600km - 320km = 1,280km[/tex]
And we know that the train needs to finish the journey at 21:00
The time between 13:00 and 21:00 is 8 hours.
So the train needs to travel a distance of 1,280km in 8 hours, then the average speed that the train needs is:
[tex]s = (1,280km)/8h = 160 km/h[/tex]
s = 160km/h
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poopybutt pickle juice
Answer:
poopybutt pickle juice????? baa?
Explanation:
What is the displacement from 0 to 35.5 seconds
Answer:
12
cause the is no longer erra
The Kinetic Molecular Theory (KMT) is discussed in this lesson, and it helps us understand the behavior of gases. From what we learned, which of these statements are consistent with KMT?
A. Due to the large amount of empty space between gas molecules/atoms, the density of a gas is very low.
B. Gas molecules are in constant, random motion, so they take the shape and volume of whatever container they are in.
C. Since atoms are mostly empty space, gases can be compressed.
D. Gas molecules/atoms collide with each other and surfaces without losing energy. E. All of the above statements are consistent with KMT.
Answer:
Explanation:
for a.;
Kinetic molecular theory assumes the collision of particles with each other and walls of container as perfectly elastic, that is why no particle loses energy.
for b.;
Kinetic molecular theory assumes that particles are of very small size incomparison with the size of container and far apart from each other that is why their density is very low. because density is described as
Density = Mass/Volume
So, one can imagine that in a big container, entire mass of all gas particles is very low as compared to the volume of container. So the gas have very low density
For c.;
Gases assume shape of their container because they are freely moving with in a container
For d.;
For statement in "b", one can easily understand that because according to kinetic molecular theory, particles are very small and at great distances, so they are compressible against any external pressure applied
Grive reasons The units of force and pressure are called derived units. an
How ??
Force:-
We know
According to newtons second law
[tex]\boxed{\sf Force=Mass\times Acceleration}[/tex]
[tex]\\ \sf\longmapsto Force=kgm/s^2[/tex]
We don't use it
[tex]\\ \sf\longmapsto Force=Newton(N)[/tex]
Hence its a derived unit.
Pressure:-
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{N}{m^2}[/tex]
[tex]\\ \sf\longmapsto Pressure=Pascal(Pa)[/tex]
Hence its a derived unit
Write a formular to show force experienced by charge in magnetic field.
Answer:
[tex]{ \boxed{ \sf{F = Bev}}}[/tex]
Explanation:
F » Force
B » Magnetic flux density
e » magnitude of charge
v » voltage
Hey Mate A same question here answered by me with proper explanation.Kimdly visit the link below for your answer
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please help meeee its for physics....
Nothing accelerates a Projectile Horizontally during Motion...
Consequently
Horizontal Acceleration is Always Zero.
The Horizontal Velocity is always Constant too.
Only the vertical Velocity changes by -9.8ms-².
If this is so...
∆x = v'∆t + ½(0)(∆t)²
∆x = v't.
I'd go with Option D.
A particle initially located at the origin has an acceleration of a=3jm/s^2 and an initial velocity of Vi=5im/s.
(a)the vector position and velocity at any time t
Given the particle's acceleration is
[tex]\vec a(t) = \left(3\dfrac{\rm m}{\mathrm s^2}\right)\vec\jmath[/tex]
with initial velocity
[tex]\vec v(0) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath[/tex]
and starting at the origin, so that
[tex]\vec r(0) = \vec 0[/tex]
you can compute the velocity and position functions by applying the fundamental theorem of calculus:
[tex]\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u)\,\mathrm du[/tex]
[tex]\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u)\,\mathrm du[/tex]
We have
• velocity at time t :
[tex]\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \displaystyle \int_0^t \left(3\dfrac{\rm m}{\mathrm s^2}\right)\,\vec\jmath\,\mathrm du \\\\ \vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath \\\\ \boxed{\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath}[/tex]
• position at time t :
[tex]\vec r(t) = \displaystyle \int_0^t \left(\left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)u\,\vec\jmath\right) \,\mathrm du \\\\ \boxed{\vec r(t) = \left(5\dfrac{\rm m}{\rm s}\right)t\,\vec\imath + \frac12 \left(3\frac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath}[/tex]
How much is the velocity of a body when it travels 600m in a straight line in 5 min. Calculate in m/s unit.
[tex] \large \mathfrak{Answer : }[/tex]
Velocity of the body traveling 600 m in 5 min = 300 seconds is :
[tex] \dfrac{600}{300} [/tex][tex]2 \: \: m/s[/tex]Farah wants to move a 40.0kg rable. She applies a force of 520N. Under these conditions, the table initially moves with an acceleration of 4.50 m/s^2 Calculate the friction force on the table
Answer:
340 Newtons of friction force
Explanation:
4.50 m/s² = 520N of Fn - ?N of Ff ÷ 40 Kg or [tex]\frac{520-x}{40}[/tex] = 4.50
40* 520 - x/40 = 4.50 *40
520-x = 180
520-x/520 = 180/520
x=340 N of Ff
The length of a plate as measured with a ruler is 24.74 cm. The breadth as measured with a Vernier caliper is 6.78 cm. Calculate the are of the plate with exact significant figures.
The area of the plate is 167.78 centimeters.
The area of the plate can be calculated with the equation of the area of a rectangle:
[tex] A = l*w [/tex] (1)
Where:
l: is the length = 24.74 cm
w: is the width = 6.78 cm
By entering the above values into equation (1) we can find the area.
[tex] A = 24.74 cm*6.78 cm = 167.74 cm [/tex]
Therefore, the area of the plate is 167.78 centimeters.
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The following are dimensions of various physical parameters that will be discussed later on in the text. Here [L], [T], and [M] denote, respectively, dimensions of length, time, and mass.
Dimension Dimension
Distance (x) [L] Acceleration (a) [L]/[T]2
Time (t) [T] Force (F) [M][L]/[T]2
Mass (m) [M] Energy (E) [M][L]2/[T]2
Speed (v) [L]/[T]
Which of the following equations are dimensionally correct?
a. F = ma
b. x = 2 at2
c. E = 1/2 max
d. E = max
e. F = ?Fx/m
Dimentional analysis is very important in physics, because it allows finding errors in equations. We find that the following true equations
a) F= m a
b) x = 2 a t²
c) E = [tex]\frac{1}{2} }\ m \ a \ x[/tex]
d) E = m a x
The fundamental units in mechanics are;
the length [L] whose unit is the meter
The time [T] that has the second as a unit
The mass [M] with fundamental unit the kilogram (kg)
all other quantities are derived from these three fundamental units, for example velocity is
v = x / t
we replace the units
[v] = [L] / [T]
so the units of velocity are the distance between time.
This exercise uses the units of various quantities and asks to find if the equations are dimensionally correct.
Let's substitute the units in each expression
a) F = m a
[M] [L] / [[T] ² = [M] [L] / [T] ²
the two sides of the expression are equal therefore the equation is correct
b) x = 2 a t²
scalar quantities have no units
[L] = [L] / [T] ² [T] ²
[L] = [L]
the two sides are equal, therefore the equation is correct
c) E = ½ m a x
[M] [L] ² [T] ² = [M] [L] [T] ² [L]
[M] [L] ² [T] ² = [M] [L] ² [T] ²
the two sides are equal the equation is correct
d) E = m a x
since scalar quantities have no units, this expression is equivalent to the expression in part c, therefore it is correct
e) F = F x / m
[M] [L] / [T] ² = [M] [L] / [T] ² [L] / [M]
[M] [L] / [T] ² = [L] ² / [T] ²
the two sides are different so the equation is false
In the dimensional analysis we find that expressions are true a, b, c, d and we see that the expression e is false
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HELP PLS. the length of a wall in a class is measured by a class 6 student and his teacher using their hand span the readings obtained by the student is 52 hand spans the reading obtained by his teacher will be _______ (assume there are no errors in the measurement
Answer:
48
Explanation:
because teachers hand will be bigger than a student's hand. That's why teacher's hand acquire less surface area
two mass, m and 2m approach each along a Path a right angle to each Other after collision they Stick together and move off at 2m/s at angle 37degree to Original direction of the mass m What where the initial speed of the two Particles
Answer:
m1 v1 = x-component of momentum (towards origin)
m2 v2 = y-component of momentum (towards origin where they collide)
m3 V cos 37 = m1 v1
m3 V sin 37 = m2 v2 components of momentum after collision
sin 37 / cos 37 = 2 v2/ v1
v2/ v1 = 1/2 * tan 37 = 1/2 * .754 = .377 for the ratio of speeds
Using m3 V cos 37 = m1 v1
3 * 2 cos 37 = 1 * v1
v1 = 4.79 m/s
m3 V sin 37 = m2 v2
v2 = 6 * sin 37 / 2 = 1.81 m/2
v2 / v1 = 1.81 / 4.79 = .378 same as ratio found above
I dont know dont know dont know
Answer:
what you need help on exactly?
Explanation:
Define measurement What problems might me face it measurement systems were not established? (1+2=3)
Answer:
The process of comparing unknown quantities with known quantities is called measurement .If it measurement system were not established ,then there may create lots of problem such as: unequal measure ,anyone can get more ,or anyone can get less mass ,so on .
what’s the correct answer
According to 1st equation of motion :
[tex]\boxed{ \boxed{v = u + at}}[/tex]
where,
v = final velocityu = initial velocity a = acceleration t = timelet's solve for t
[tex] \hookrightarrow \: 17.63 = 0 + 2.13t[/tex]
[tex] \hookrightarrow \: t = \dfrac{17.63}{2.13} [/tex]
[tex] \hookrightarrow \: t = 8.276 \approx 8.28\: \: sec[/tex]
The diagram below represents the forces acting upon a rightward-moving object.
Each arrow represents a force; the length of the arrow represents the strength of
the force.
Answer:
Explanation:
The up and down arrows appear to me to be of the same length, therefore there is no up or down acceleration.
There are no right or left arrows, therefore there is no right or left acceleration.
The mass moves with constant velocity.
This could be the free body diagram of an ice puck sliding across a frictionless ice surface.
The down arrow is the puck weight. The up arrow is the normal force of the ice on the puck.
A friction force would be represented by a horizontal arrow to the left for the rightward moving mass. It's not there.
If something were increasing the rightward speed, like a bottle rocket attached to the puck, it would be represented as a right facing arrow.
3(8+2)
----------
4^2-1
Calculate the force applied if 200 Pascal pressure is exerted over the area of 0.2m². With explanation.
Force applied will be equal to 40 Newtons .
Answer:
F=40N
Explanation:
As
P=[tex]\frac{F}{A}[/tex] and
F=P*A
Putting the values
F=200*0.2
F=40N1. Escribe V, si la afirmación es verdadera o F, si es falsa. Justifica tu respuesta.
1)Un rayo de luz es una línea imaginaria que se traza en dirección perpendicular a la onda.
2)Una onda reflejada es aquella que viaja por el mismo medio de la onda incidente después de alcanzar la frontera entre dos medios.
3) La normal es una recta perpendicular a la línea que divide los dos medios.
4)En los espejos planos el ángulo de incidencia es igual al ángulo de reflexión.
5)En los espejos convexos la luz incide por la parte interna de la superficie esférica.
6)El foco está a una distancia equivalente al doble del radio de curvatura de un espejo esférico.
7)En un espejo esférico una imagen derecha es aquella que está por encima del eje óptico.
Las leyes de la óptica geométrica, permite encontrar los enunciados verdaderos son:
1. Un rayo es una línea perpendicular a los frentes de onda.
2. La onda incidente y reflejada van en el mismo medio
3. La normal es perpendicular a la superficie que divide el medio.
4. El espejo el ángulo de incidencia y refracción son iguales
Se le pide que diga si la afirmación es verdadera o falsa.
1) Un rayo de luz es una línea imaginaria que se dibuja perpendicular a la onda.
La luz está compuesta por infinitos frentes de onda, para simplificar la notación se dibuja un plano a través de todos los frentes de onda con la misma fase y la línea normal a esta se llama rayo; es el equivalente matemático de la norma definida para un plano
la declaración es verdadera
2) Una onda reflejada es aquella que viaja por el mismo medio que la onda incidente después de alcanzar el límite entre dos medios.
Cuando la onda interactúa con el medio a medida que se refleja o se transmite, la onda reflejada está en el mismo medio de incidencia.
la declaración es verdadera
3) La normal es una línea perpendicular a la línea que divide las dos medias.
En óptica es habitual describir los fenómenos con respecto a una línea perpendicular al plano de incidencia de la onda electromagnética, esta línea se denomina Normal.
La afirmación es verdadera
4) En espejos planos, el ángulo de incidencia es igual al ángulo de reflexión.
La ley de la reflexión establece que el ángulo de incidencia es igual al ángulo de reflexión. En los espejos cumplen esta ley
la declaración es verdadera
5) En los espejos convexos la luz incide en el interior de la superficie esférica.
En un espejo convexo, el radio de curvatura va hacia la parte interior de la esfera, los rayos incidentes comienzan en la parte exterior del espejo.
la afirmación es falsa
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
Donde f es la distancia focal, p y q son la distancia al objeto y la imagen, respectivamente
En este caso la distancia al objeto es infinita, por lo cual la distancia focal es igual a la distancia a la imagen
f = q
El foco está a una distancia igual al mitad radio de curvatura de un espejo esférico.
La distancia focal es la distancia donde se forma la imagen cuando el objeto está en el infinito, si usamos la ecuación del constructor
f = q = R / 2
donde la distancia focal es el radio de curvatura sobre dos
la afirmación es falsa
7) En un espejo esférico, una imagen derecha es aquella que está por encima del eje óptico.
En óptica, la imagen puede ser vertical o invertida. Por convención el objeto se dibuja hacia arriba con respecto al eje óptico, si la imagen también está hacia arriba se llama derecha y si está hacia abajo se llama invertida
En un espejo esférico es invertida
la afirmación es Falsa
Usando las leyes de la óptica geométrica podemos encontrar si los enunciados son verdaderos o no.
las afirmaciones verdaderas son: 1,2,3,4
las declaraciones falsas son: 4,6,7
Obtenga más información sobre la óptica geométrica aquí: brainly.com/question/15850239
if an equation is demensionally correct does this mean that the equation is true
Explanation:
If an equation is dimensionally correct, it does not mean that the equation must be true. On the other hand, when the equation is dimensionally correct, the equation cannot be true. Dimensional analysis is a technique used to check whether a relationship is correct
11. Approximatrly how many kelvins are equal to 60°F?
a. 439
b. 212
c. 902
d. 289
