draw a graph of the voltmeter reading versus ammeter readings.​

Answer:

Explanation:

The first question asks for the object's height. That is a y-dimension thing so we will use the one-dimensional formula:

[tex]v^2=v_0^2+2a[/tex]Δx and we are looking for delta x, which is the displacement of the object (here, the height since displacement in the y-dimension is height). Before we do that, though, we need to know the initial upwards velocity, which is found in:

[tex]v_{0y}=100sin(60)\\v_{0y}=90\frac{m}{s}[/tex]

And we also have to know from previous physics experience that the final velocity of an object at its max height is 0. Filling in:

[tex]0=(90)^2+2(-9.8)[/tex]Δx

[tex]0=8000-20[/tex]Δx and

-8000 = -20Δx so

Δx = 400 m

Now for the time it was in the air...we will use the simple equation

[tex]v=v_0+at\\0=90-9.8t\\-90=-9.8t\\t=9[/tex]

So the object is in the air for 9 seconds. Now we go to the other dimension, the x-dimension, to find out how far it goes horizontally. We will use the equation:

Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] but first we have to find the horizontal velocity, which is NOT the same as the upwards velocity.

[tex]v_{0x}=100cos(60)\\v_{0x}=50\frac{m}{s}[/tex]

And another thing we need to know prior to solving problems like this is that the acceleration in the x-dimension is ALWAYS 0. Filling in the equation:

Δx = [tex]50(9)+\frac{1}{2}(0)(9)^2[/tex]

Δx = 500 m

Answer:

B. Design tests to measure and compare the energy released by

earthquakes

Answer:

There must be a possibility to prove that the hypothesis is true. There must be a possibility to prove that the hypothesis is false. The results of the hypothesis must be reproducible.

Explanation:

Make sure your hypothesis is "testable." To prove or disprove your hypothesis, you need to be able to do an experiment and take measurements or make observations to see how two things (your variables) are related. You should also be able to repeat your experiment over and over again, if necessary

Answer:

It would be C.scale, because

A. is for liquid

B. is for measuring 2 things

and D. is for i don't know(lol)

but i think the scale would be the easiest way to measer an iPad

Answer:Y,X,Z,W

Explanation:

Answer:

A.

Explanation:

●Liquid

●Solid

As you gave no pic I took them on one lined

[tex]\\ \sf\longmapsto F_{net}=F_1+F_2\dots[/tex]

[tex]\\ \sf\longmapsto F_{net}=3+10+6+3\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto F_{net}=19+3(1.732)[/tex]

[tex]\\ \sf\longmapsto F_{net}=19+5.196[/tex]

[tex]\\ \sf\longmapsto F_{net}=24.196N[/tex]

Answer:

infrared light

Explanation:

infrared light

Answer:

Explanation:

E = IR

R = E/I

R = 9.0/0.549

R = 16.393 Ω

Answer:

uujjjjjctc7tox7txr9ll8rz8lr5xl8r6l8dl85x8rl5x8rl5x8rl5xrx8l58rk5xr8l5xr6l8xr68lc

Answer:

As per Coulomb's law we know that force between two charges is given as

F = \frac{kq_1q_2}{r^2}F=

r

2

kq

1

q

2

here we know that

q_1 = 2.5 \times 10^{-6} Cq

1

=2.5×10

−6

C

q_2 = -5.0 \times 10^{-6} Cq

2

=−5.0×10

−6

C

r = 0.0050 mr=0.0050m

now from above formula we will have

F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=

(0.0050)

2

(9×10

9

)(2.5×10

−6

)(5×10

−6

)

F = 4500 NF=4500N

so they will attract towards each other as they are opposite in nature with force F = 4500 N

Explanation:

a) Use the torque equation to solve for the amount of effort to lift the load:

[tex]\sum{\tau} = Lx_L - Ex_E = 0[/tex]

or

[tex]E = \dfrac{Lx_L}{x_E} = \dfrac{(100\:\text{N})(0.20\:\text{m})}{0.60\:\text{m}}[/tex]

[tex]\:\:\:\:\:=33.3\:\text{N}[/tex]

The mechanical advantage is

[tex]MA = \dfrac{0.60\:\text{m}}{0.20\:\text{m}} = 3[/tex]

The velocity ratio is the same as the MA:

[tex]VR = \dfrac{\text{effort arm}}{\text{load arm}} = MA = 3[/tex]

b) We can use the same equation in (a) to solve the problem:

[tex]\sum{\tau} = Ex_E - Lx_L = 0[/tex]

[tex]\Rightarrow x_L = \dfrac{Ex_E}{L} = \dfrac{(50\:\text {N})(90\:\text{cm})}{300\:\text{N}}[/tex]

[tex]\:\:\:\:\:=15\:\text{cm}[/tex]

c) We can write

[tex]W_RX_R = W_SX_S \Rightarrow X_R = \dfrac{W_SX_S}{W_R}[/tex]

[tex]\:\:\:\:\:= \dfrac{(400\:\text{N})(4\:\text{m})}{500\:\text{N}} = 3.2\:\text{m}[/tex]

d) We can solve the problem as follows:

[tex]\sum{\tau} = Ex_E - Lx_L = 0 \Rightarrow E = \dfrac{Lx_L}{x_E}[/tex]

or

[tex]E = \dfrac{(500\:\text{N})(0.50\:\text{m}}{1.0\:\text{m}} =250\:\text{N}[/tex]

The mechanical advantage MA is

[tex]MA = \dfrac{x_E}{x_L} = \dfrac{1.0\:\text{m}}{0.5\:\text{m}} = 2.0[/tex]

[tex]VR = MA = 2.0[/tex]

[tex]\%\text{eff} = \dfrac{Lx_L}{Ex_E}×100\%[/tex]

[tex]\:\:\:\:\:= \dfrac{(500\:\text{N})(0.5\:\text{m})}{(250\:\text{N})(1.0\:\text{m})}×100\%[/tex]

[tex]\:\:\:\:\:=100\%[/tex]

Answer:

981(46) ( 59)

45126(59)

2662434

Explanation:

Answer:

Explanation:

Area A = 4 pi R^2

lnA = ln(4 pi) + 2 ln R

dA/A = 2 dR/R = 2*(alpha)*dT

delta A = 2A*alpha*(delta T)

OR

A at T + deltaT

delta A = 4 pi (R + deltaR)^2 - A

= 4 pi R(1 + alpha*deltaT)^2 -A

= 4 pi R^2 *[1 + 2*alpha*deltaT +

(alpha*deltaT)^2] - A

= 2*A*alpha*deltaT + A*(alpha*deltaT)^2

(Ignore the second term in deltaT^2)

Answer:

(A)  inertia increases.

Explanation:

Inertia is the property of mass that resists change so the mass an object has the greater the inertia

Hello some data related to your question is missing attached below is the missing data

From the Table If Brown produces only Corn he will produce 50 but to produce some tobacco Brown will produce 40 Corn and 10 Tobacco to ensure the efficiency of production.

PPF ( production possibility frontier ) is a curve that shows/represent the production of various quantities of two(2) different commodities with the same limited amount of resource. In PPF the efficiency of production is not affected because the Increase in the production of a certain commodity will be balanced with a decrease in production of the other commodity. and The slope of PPF is the Marginal rate of transformation. and opportunity cost is kept constant.

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Answer:

An atom is the smallest unit of matter that retains all of the chemical properties of an element. Atoms combine to form molecules, which then interact to form solids, gases, or liquids. For example, water is composed of hydrogen and oxygen atoms that have combined to form water molecules. Many biological processes are devoted to breaking down molecules into their component atoms so they can be reassembled into a more useful molecule.

Atomic Particles

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged). Atoms have different properties based on the arrangement and number of their basic particles.

The hydrogen atom (H) contains only one proton, one electron, and no neutrons. This can be determined using the atomic number and the mass number of the element (see the concept on atomic numbers and mass numbers).

Acceleration = v^2 / r

Acceleration = 30^2/25

Acceleration = 900/25

Acceleration = 36 m/s^2

Answer:

Physics, or the study of matter, energy, and the interactions between them, helps us to understand the laws and rules that govern the physical world. Not every student will grow up and study physics on a deeper level, but everyone uses basic physics concepts to navigate everyday life.A

Physics is a natural science that involves the study of matter and its motion through space and time, along with related concepts such as energy and force. More broadly, it is the study of nature in an attempt to understand how the universe behaves.Physics helps you to understand the world around you, and satisfy your curiosity. Studying physics develops your critical thinking and problem-solving skills. Physicists are versatile, which opens a wide range of future careers.

C. It is answered by observation and evidence.

Good scientific explanations are defined, measurable and controllable. They can be answered by an experiment.

Yes. This is indeed the location of an object.

Answer:

wdym

Explanation:

not much information

Answer and Explanation:

If the ant was to crawl 50cm to the right, then come back 30 cm, then the total distance walked would be 80cm.

- Combine 50cm and 30cm to get 80 cm.

For displacement, the answer is 20 cm.

- When calculating displacement, you use the initial (starting) distance. and subtract that from the final distance, giving you the displacement, or the amount traveled from the starting point to the final point if you were to make a straight line from the starting point to end point. (0 to 50, then back 30 the same direction, so subtract 30 from 50 to get 20)

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

Distance = 80cm

Displacement = 20cm

Explanation:

Distance does not depend on direction, its the total amount traveled.

Displacement has a direction. Displacement is how far your stopping point is from the beginning point.

The ant could have walked 50cm to the east, stopped and turned around, walked 50cm to the west, walking a total distance of 100cm, but the displacement would be 0 because he ended up at the same spot that he started. It can get much more complicated than this, but this is a good start.

Answer:

tan theta = H / B        where H is height of triangle and B the length of base

H1 = 87 * tan 25 =  40.6 feet

H2 = 87 * tan 40 = 73 feet

H2 - H1 = 32.4 feet

Answer:

Time, t = 0.57 hours

Explanation:

It is given that,

Speed of the school bus, v = 35 mi/hr

Distance covered by the bus, d = 20 miles

We need to find the time taken by the bus to get to school. Time taken by the bus is given by :

t = 0.57 hours

So, the time taken by the bus to reach school is 0.57 hours. Hence, this is the required solution.

The heating element of an electric oven is designed to produce 3.9 kW of heat when connected to a 240-V source. Then the resistance of the element is 14.7Ω

When A 120-V hair dryer has two settings: 950 W and 1400 W then the resistance at 950 W is 15.15Ω and at 1400 W is 10.28Ω.

The pace at which electrical energy is transmitted by an electric circuit is referred to as its power. The watt is the SI unit of power, equal to one joule per second. Watts, like other SI units, have standard prefixes: thousands, millions, and billions of watts are referred to as kilowatts, megawatts, and gigawatts, respectively.

It is a popular misperception that electric power is purchased and sold, whereas electrical energy is. Electricity, for example, is sold to users in kilowatt-hours (kilowatts multiplied by hours), because energy is defined as power multiplied by time.

In this problem,

Given,

Power P = 3.9 KW

Voltage V = 240 V

P = V²/R

3.9 × 10³ = 240²/R

R = 240²/3.9 × 10³

R = 14.7Ω

For hair dryer,

given,

P = 950 W or 1400 W

V = 120 V

P = V²/R

950 = 120²/R

R = 120²/950

R = 15.15Ω

P = V²/R

1400= 120²/R

R = 120²/1400

R = 10.28Ω

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We have that the maximum induced emf,the maximum induced current, the induced emf and current as functions of time,The maximum torque must be applied to keep the coil turning are

a  )[tex]E_{max}=135.6v[/tex]

b)  [tex]I_max=11A[/tex]

c)  [tex]I_i=11A sin(376.9rad/s t)[/tex]

   [tex]E_i=135.6v sin(376.9rad/s )[/tex]

d)   [tex]T=4.07Nm[/tex]

From the Question we are told that

Area [tex]A =9.0x 10^{-2} m^2[/tex]

Total resistance of [tex]R=12.0 V.[/tex]

Magnetic field of [tex]B=0.500 T[/tex]

Constant frequency [tex]F=60.0 Hz[/tex]

Eight turns [tex]N=8N[/tex]

A)

Generally the equation for the maximum induced emf  is mathematically given as

[tex]E=NAB\omega[/tex]

Where

[tex]\omega=2\pi f[/tex]

[tex]\omega=2*3.142*60[/tex]

[tex]\omega=376.9rad/s[/tex]

[tex]E_max=8*(9.0x 10-2)*0.5*376.9[/tex]

[tex]E_{max}=135.6v[/tex]

B)

Generally the equation for the maximum induced Current is mathematically given as

[tex]I_m=\frac{E}{R}\\\\I_max=\frac{135.6}{12}\\\\I_max=11A[/tex]

C)

Generally for the induced emf and current as functions of time we Substitute [tex]E_{max}[/tex] and [tex]\omega[/tex] into

[tex]E_i=E_{max} sin\omega t[/tex]

[tex]E_i=135.6v sin(376.9rad/s t)[/tex]

And Same for induces Current

[tex]I_i=I_{max} sin\omega t[/tex]

[tex]I_i=11A sin(376.9rad/s t)[/tex]

D)

Generally the equation for the  maximum torque  is mathematically given as

[tex]T = rB sin θ[/tex]

Where

r= maximum magnetic moment

[tex]r=NIAr= 8*11.3*0.090r=8.14m^2[/tex]

Therefore

[tex]T = 8,14*0.500 sin 90[/tex]

[tex]T=4.07Nm[/tex]

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The image formed by the concave mirror is virtual, enlarged, and upright. The correct answer is option A.

A concave mirror is a type of spherical mirror that has a reflecting surface that curves inward, resembling the shape of the inner surface of a sphere. The inner surface of the mirror is reflective, while the outer surface is transparent.

Concave mirrors are also known as converging mirrors because they cause parallel incident light rays to converge or come together after reflection. These mirrors are commonly used in various optical devices, such as telescopes, makeup mirrors, and reflector headlights.

Option A states that the image formed by the concave mirror is virtual, enlarged, and upright. Let's break down what each of these terms means in the context of the image formation by a concave mirror:

1. Virtual: A virtual image is formed when the light rays appear to diverge from a point behind the mirror. It cannot be projected onto a screen since the light rays do not actually converge at the image position. In the case of a concave mirror, when the object is located between the mirror and the focal point, a virtual image is formed.

2. Enlarged: An enlarged image is one that appears larger than the object itself. In this case, since the image is virtual, it appears to be larger than the actual size of the object.

3. Upright: An upright image is one that has the same orientation as the object. In the case of a concave mirror, when the object is located between the mirror and the focal point, the image formed is upright.

Therefore, the correct option is A, the image formed by the concave mirror is virtual, enlarged (appears larger than the object), and upright (has the same orientation as the object).

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