Danni thinks of a number. She subtracts 2 then multiples the result by 8. The answer is the same as subtracting 5 from the number then multiplying by 16. What is the number did Danni think of?

Answer:

124.5°

Step-by-step explanation:

Let the smallest angle be x. Then, the sum of the angles is an arithmetic sequence with first term x, common difference 7, and 8 terms.

Using the sum of an arithmetic series formula,

[tex]\frac{8}{2}(2x+(8-1)(7))=1080 \\ \\ 4(2x+49)=1080 \\ \\ 2x+49=270 \\ \\ 2x=221 \\ \\ x=110.5[/tex]

So, the third angle is 110.5+14=124.5

Answer: C: 12-7x

Step-by-step explanation:

This expression is a good example of the difference of two squares, as 144 is the square of 12, while 49x² is the square of 7x.

Any difference of two squares [tex]a^2-b^2[/tex] can be factored into the sum of their square roots times the difference of their square roots [tex](a+b)(a-b)[/tex].

Let's factor our expression.

[tex]144-49x^2=(12+7x)(12-7x)[/tex]

Out of all the options given, only [tex]12-7x[/tex] is a factor. Hence, option C is correct.

Using proportions, it is found that due to the smaller division of the exchange rate by the cost, the souvenir would be less expensive in Egypt.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

The souvenir would be less expensive in the country in which the division of the exchange rate by the cost is smaller.

In Britain, the cost is of 17, with an exchange rate of 0.83, hence the cost in US dollars is:

c = 17/0.83 = $20.48.

In Egypt, the cost is of 288, with an exchange rate of 18, hence the cost in US dollars is:

c = 288/18 = $16.

16 < 20.48, hence the souvenir would be less expensive in Egypt.

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Answer:

a=–2, 3

Step-by-step explanation:

r(a)=20

a²–a+14=20===> a²–a–6=0===> (a–3)(a+2)

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textbf{Equation: }[/tex]

[tex]\large\textsf{(3x)(4x)}[/tex]

[tex]\large\textbf{Solving:}[/tex]

[tex]\large\textsf{(3x)(4x)}[/tex]

[tex]\large\textsf{= 3x} * \large\textsf{4x}[/tex]

[tex]\large\textbf{Combine the like terms:}[/tex]

[tex]\large\textsf{(3x * 4x)}[/tex]

[tex]\large\textsf{= 3x * 4x}[/tex]

[tex]\large\textsf{= 12x}^2[/tex]

[tex]\large\textbf{Therefore, your answer should be: }[/tex]

[tex]\huge\boxed{\frak{Option\ D. 12\mathsf{x}^2}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The dy/dx of equation  [tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex] is [tex](6xy-3x^{2} -2y^{2} )/(4xy-3x^{2})[/tex].

Given an equation [tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex].

We are required to find dy/dx of the equation.

Equation is like a relationship between two or more variables that are expressed in equal to form. Equations of two variables look like ax+by=c.

Differentiation is basically finding the change in variables.

It may be linear equation, quadratic equation,cubic equation or many more depending on the power of the variable present in the equation.

Equation:[tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex]

Differentiating with respect to x.

3[tex]x^{2}[/tex]-3([tex]x^{2}[/tex]*dy/dx+y*2x)+2(x*2y*dy/dx+[tex]y^{2}[/tex])=0

3[tex]x^{2} -3x^{2} dy/dx-6xy+4xy dy/dx+2y^{2}[/tex]=0

Taking dy/dx at one side and take the other part to other end.

[tex]-3x^{2} dy/dx+4xy dy/dx[/tex]=[tex]6xy-3x^{2} -2y^{2}[/tex]

dy/dx=[tex](6xy-3x^{2} -2y^{2})/(4xy-3x^{2} )[/tex]

Hence the dy/dx of equation  [tex]x^{3} -3x^{2} y+2xy^{2} =12[/tex] is [tex](6xy-3x^{2} -2y^{2} )/(4xy-3x^{2})[/tex].

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Answer:

17 +1^2=18

18+2^2=22

22+3^2=31

31+4^2=47

47+5^2=72

72+6^2=108

Step-by-step explanation:

Answer:

[tex]\frac{x^2}{9}+\frac{y^2}{4}=1[/tex]

Step-by-step explanation:

So an ellipse can be expressed in two different but very similar forms:

Horizontal Major Axis:

   [tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]

Vertical Major Axis:
   [tex]\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1[/tex]

In both equations the length of the major axis is "2a" and the length of the minor axis is "2b"

In the equation you provided, the major axis is horizontal, and the minor axis is vertical.

So looking at the horizontal length, you can see that it's 6, and since this ellipse has a horizontal major axis, that means 2a=6, which means a=3

Looking at the vertical length, you can see that it's 4, and since the ellipse has a vertical minor axis, that means 2b=4, which means b=2

The last thing to note is that the center of an ellipse is (h, k) in the equation, and since here the center is (0, 0) it's (x-0)^2 and (y-0)^2 in the denominator which is just x^2 and y^2

So let's plug in the values into the equation:

[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]

(h, k) = (0, 0)

a = 3

b = 2

[tex]\frac{x^2}{3^2}+\frac{y^2}{2^2}=1\\\\\frac{x^2}{9}+\frac{y^2}{4}=1[/tex]

Here we go ~

The given figure is of a horizontal ellipse with :

so, a = 3

hence, b = 2

And as it's shown in the figure, the ellipse has its centre at origin, so we can write it's equation as :

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {a}^{2} } + \cfrac{ {y}^{2} }{b {}^{2} } = 1[/tex]

[ now, plug in the values ]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {3}^{2} } + \cfrac{ {y}^{2} }{2 {}^{2} } = 1[/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {9}^{} } + \cfrac{ {y}^{2} }{4 {}^{} } = 1[/tex]

That's all, ask me if you have any questions ~

Answer:

Step-by-step explanation:

(1). A = π r²

A = 4 π

Area of shaded region is [tex]\frac{4\pi *260}{360}[/tex] = [tex]\frac{26}{9} \pi[/tex] or [tex]\frac{26\pi }{9}[/tex]

(2). C = 4 π

In this case, the length of the bigger arc and the area of shaded region happen to be the same.

The length of the arc ADB is  [tex]\frac{26}{9} \pi[/tex] or [tex]\frac{26\pi }{9}[/tex]

Answer:

35

Step-by-step explanation:

first, you look at 7x, from the previous equation, you know that x=3, so you take 7x3=21 then you evaluate -3y. as you did with x on the last one you will look at the equation for y and see that it's -4. A negative times a negative is a positive, so -4x(-3)= 12. Then you add them all together, since 12 is a positive, the equation would now look like 21+12+2. After adding all three numbers together, you get 12.

The lists of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 that are possible is; 256

We are told that the last digit has to be either a one (1) or nine (9), then are two (2) options (>,<) for the remaining eight digits, so there are 2⁸ = 256 arraignments where each digit is either greater than or less than the preceding digits. This can be confirmed as below;

Numbers beginning with 1 = 8C0 = 1

Numbers beginning with 2 = 8C1 = 8

Numbers beginning with 3 = 8C2 = 28

Numbers beginning with 4 = 8C3 = 56

Numbers beginning with 5 = 8C4 = 70

Numbers beginning with 6 = 8C5 = 56

Numbers beginning with 7 = 8C6 = 28

Numbers beginning with 8 = 8C7 = 8

Numbers beginning with 9 = 8C8 = 1

Total lists of numbers possible = 1 + 8 + 28 + 56 + 70 + 56 + 28 + 8 + 1 = 256

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The number exists 99, then 99 - 49 = 50

Therefore, the pair of two-digit numbers exist between 99 and 49.

In math, the word difference exists as the outcome of subtracting one number from another.

Let the first pair of two-digit numbers be xy and the second pair of numbers be yx.

we want a two-digit number, a two-digit number begins from 10 and ends with a two-digit number that exists 99.

Let the difference of 50 exists possible when we take the biggest two-digit number

Therefore, the number exists 99

99 - 49 = 50

Therefore, the pair of two-digit number exists 99 and 49.

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Answer:

150.8 in³

Step-by-step explanation:

The volume of the 5 inch ball is

[tex]\frac{4}{3}\pi (5/2)^{3}[/tex]

The volume of the 13 inch ball is

[tex]\frac{4}{3}\pi (13/2)^{3}[/tex]

Subtracting these volumes, we get about 150.8 in³.

The amount of space (volume) that is in the larger spherical ball than the smaller will be 1,084.8 in.³

To find the volume of a sphere, which is the amount of space the solid contains, the formula used is given as: 4/3 πr³,

where r is the radius of the sphere, which is half the measure of the diameter.

Diameter of the smaller spherical ball = 5 inches

Radius = 5/2 = 2.5 inches

Volume of the smaller spherical ball = 4/3 πr³ = 4/3 × π × 2.5³

Volume ≈ 65.5 in.³

Diameter of the larger spherical ball = 13 inches

Radius = 13/2 = 6.5 inches

Volume of the larger spherical ball = 4/3 πr³ = 4/3 × π × 6.5³

Volume of the larger spherical ball ≈ 1,150.3 in.³

The amount of space (volume) that is in the larger spherical ball than the smaller.

= 1,150.3  - 65.5

The amount of space (volume) that is in the larger spherical ball than the smaller will be 1,084.8 in.³

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Answer:

x = 15°

Step-by-step explanation:
165 and x are on a straight line which means they are supplementary.
Set up the equation and solve for x:

165 + x = 180

x = 180 - 165

x = 15

The area of the trapezoid is 140 square feet

The area of a shape is the amount of space on that shape

The dimensions of the trapezoid are given as:

Height = 10 feet

Parallel bases = 8 feet and 20 feet

The area of a trapezoid is calculated using

Area = 0.5 * (Sum of parallel bases) * Height

Substitute the known values in the above equation

Area = 0.5 * (8 + 20) * 10

Evaluate the equation

Area = 140

Hence, the area of the trapezoid is 140 square feet

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According to the direct inspection, we conclude that the best approximation of the two solutions to the system of quadratic equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the Cartesian plane.

According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two quadratic equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

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Answer:

9/25 or -1/11

Step-by-step explanation:

2 outcome

1; 7x-5=18x-4

2;-(7x-5)=18-4

Answer:

-13

Step-by-step explanation:

-2x6 = -12

-9+8= -1

-1+-12=-13

Hope this helps

Using it's concept, your percentage for the month was of 94.12%.

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

P = a/b x 100%

In this problem, your goal was of 85, with a grade of 80, hence the percentage is:

P = 80/85 x 100% = 94.12%.

Hence, your percentage for the month was of 94.12%.

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The point among the answer choices which is not in the solution set of the inequality is; (-1, 3).

It follows from the task content that the vertex of the two-variable inequality in discuss is; (1, 2).

On this note, it follows that; the two variable inequality described by a parabola opening upward can be written by means of its vertex as;

y >= (x - (1))² + 2

y >= (x-1)² + 2.

By testing points among the answer choices, the point which is not part of the solution set is; (-1,3).

This follows from the fact that; at x=-1;

The value of y is;

y >= (-1-1)² +2

y >= 6

Hence, since the value of y= 3 which is less than, 6, it follows that the point (-1,3) is not in the solution set.

Remarks: The answer choices in the complete question are as follows;

(–1, 3)

(0, 4)

(1, 5)

(2, 4)

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[tex]\stackrel{\stackrel{total~amount}{goal}}{481}~~ = ~~22(lawn)\implies \cfrac{481}{22}=lawn\implies \stackrel{rounded}{22}\approx lawn[/tex]

A. No, AB and BC are not congruent

B. No, AC and BD are not congruent

From the question, we are to determine if the given pairs of segments are congruent

To do this, we will determine the length of the line segments

Consider the given number line,

AB = -2 - (-5) = -2 + 5 = 3

BC = 0 - (-2) = 0 + 2 = 2

AC = 0 - (-5) = 0 + 5 = 5

BD = 5 - (-2) = 5 + 2 = 7

Now,

A. AB and BC

AB = 3 and BC =2

∴ AB and BC are not congruent.

Thus, No

A. AC and BD

AC = 5 and BD = 7

∴ AC and BD are not congruent.

Thus, No

Hence,

A. No, AB and BC are not congruent

B. No, AC and BD are not congruent

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The cross-section perpendicular to the base of a right rectangular prism is a rectangle.

A shape or a solid that has three dimensions that is length, width and height is called a 3D shape. 3D shapes have faces, edges, and vertices. Examples are cylinder, cone, prism, pyramid.

A shape that has two dimensions is called a 2D shape. 2D shapes have breadth and length.

The cross-section perpendicular to the base of a right rectangular prism is a rectangle.

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Answer:

x - 2, x - 3

Step-by-step explanation:

3x² - 5x + 2

x² - 5x + 6

(x - 3)(x - 2)

length = x - 2

width = x - 3

The total amount in the transaction account is

= $625.

The amount in the transaction account is

=75

Your salary and any other payments that you get may be deposited into an account known as a transaction account, which is an account that you utilize on a day-to-day basis. When connected to a Visa card, your transaction account may also be used to pay bills, go shopping, and make other types of payments that are commonplace. Balances in transaction accounts do not accrue any interest for the account holder.

b) Now if the reserve requirement changes to 5%, we need to reconstruct the balance sheet of the total banking system.

Calculate the initial total reserve using the new reserve requirement as follows:

= 4% x500

= 0.04×500

=20

Calculate the excess reserve as follows:

=30-20

= $10

Calculate the money multiplier as follows:

=1/4%

=1/0.04

=25

Calculate the increase in transaction account as follows:

=25x $5

= $125

Hence, the total amount in the transaction account is

$500+ $125

= $625.

c)

Therefore, the amount in the transaction account is

=600-525

=75

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Answer:

Step-by-step explanation:

Answer:

Option A

Here you go.

Hope this help!!

Good luck!!

Horizontal asymptote

The range is

Or

Option A

Answer:

120 students don't have social media accounts

Step-by-step explanation:

Whether the sample is representative:

Estimate: [tex]\frac{3}{75} (3000)=\frac{9000}{75} =120[/tex]

Hope this helps