Answer:
No, a quadrilateral with the given vertices is not an isosceles trapezoid.
Step-by-step explanation:
We are given that
A(3,3), B(5,3), C(8,1), D(1,1)
Slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Slope of AB=[tex]\frac{3-3}{5-3}=0[/tex]
Slope of BC=[tex]\frac{1-3}{8-5}=\frac{-2}{3}[/tex]
Slope of CD=[tex]\frac{1-1}{1-8}=0[/tex]
Slope of AD=[tex]\frac{1-3}{1-3}=1[/tex]
Slope of AB=Slope of CD
When slopes of two lines are equal then the lines are parallel.
Therefore, AB is parallel to CD.
When one pair of quadrilateral is parallel then the quadrilateral is trapezoid.
[tex]\implies [/tex]ABCD is a trapezoid.
Distance formula:
[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the formula
Length of BC=[tex]\sqrt{(8-5)^2+(1-3)^2}[/tex]
Length of BC=[tex]\sqrt{9+4}=\sqrt{13}[/tex] units
Length of AD=[tex]\sqrt{(1-3)^2+(1-3)^2}[/tex]
Length of AD=[tex]\sqrt{4+4}=2\sqrt{2}[/tex]
Length of AD is not equal to length of BC.
Hence, trapezoid is not an isosceles trapezoid.
write the equation of the line shown in the graph above in slope-intercept form
Which problem has a greater (bigger) answer? Solve both, choose the one that has the bigger answer and explain (1-2 sentences) how you found your
answer.
1) (2 + 3) (5 + 5)
2)2 + 3 x 5 + 5 =
I need so much helppppp pleaseeeee
Answer:
Problem 1 has a greater answer.
Step-by-step explanation:
Solve problem 1 using the order of operatiobs PEMDAS (Parentheses, Exponents, multiplication/division, and addition/subtraction):
Multiplication/division depends from left to right of the expression, the same goes to addition/subtraction.
(2 + 3) (5 + 5)
= (5)(10)
= 50
SOLVE problem 2 using PEMDAS:
2 + 3 x 5 + 5
= 2 + 15 + 5
= 17 + 5
= 22
Answer 1 (50) compared to Answer 2 (22):
50 > 22
HOPE THIS HELPS!
Suppose you choose a marble from a bag containing 3 red marbles, 5 white marbles, and 4 blue
marbles. You return the first marble to the bag and then choose again. Find P (red and blue).
Answer:
P(red and blue) = 1/12
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability of independent events:
If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each event happening, that is:
[tex]P(A \cap B) = P(A)P(B)[/tex]
P (red and blue).
Probability of choosing a red marble, then a blue marble. The marbles are replaced, so the trials are independent.
Probability of a red marble:
3 out of 3 + 5 + 4 = 12. So
[tex]P(A) = \frac{3}{12} = \frac{1}{4}[/tex]
Probability of a blue marble:
4 out of 12, so:
[tex]P(B) = \frac{4}{12} = \frac{1}{3}[/tex]
P (red and blue).
[tex]P(A \cap B) = P(A)P(B) = \frac{1}{4} \times \frac{1}{3} = \frac{1}{4*3} = \frac{1}{12}[/tex]
So
P(red and blue) = 1/12
Rearrange 2x = y/w to make w the subject
Find the mean or average of these savings accounts $215, $156,$318, $75, and $25
Answer:
157.8
Step-by-step explanation:
Add them all up to get 789 and divide them by 5 as there are five numbers to get the answer:)
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500. Is there sufficient evidence at the ?= 0.05 level to conclude that the mean cost has increased. Solve the question by traditional approach.
Answer:
The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.
Step-by-step explanation:
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.
At the null hypothesis, we test if the mean cost is still the same, that is:
[tex]H_0: \mu = 13252[/tex]
At the alternative hypothesis, we test if the mean cost has increased, that is:
[tex]H_1: \mu > 13252[/tex]
The test statistic is:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.
13252 is tested at the null hypothesis:
This means that [tex]\mu = 13252[/tex]
The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.
This means that [tex]n = 20, X = 15560, s = 3500[/tex]
Value of the test statistic:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}[/tex]
[tex]t = 2.95[/tex]
P-value of the test and decision:
The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.
The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.
A shopkeeper supplies 42 kg of vegetables to a school canteen in the morning and 58 kg of vegetables in the evening if cost of 1kg vegetable is 16 rupees how much money is due to the canteen per day?
Can someone please help?
Step-by-step explanation:
So, so, to attempt this, we need to use the formula :-
2 (l + b) × h ---> For Lateral surface area
2(30+30) h = 7200
2×60×h = 7200
120 × h = 7200
h = 7200/120
h = 60 cm
Now, volume = l×b×h
= 30×30×60
= 54000 cm³ is the required answer.
Hope it helps! :D
. a) In a group of 75 students, 20 liked football only, 30 liked cricket only and 18 did not like any of two games? (i) How many of them liked at least one game? (ii) Find the number of students who liked both the games. (iii) How many of them liked football? (iv) How many of them liked cricket? (v) Represent the result in a Venn diagram.
i)50
Steps
30+20=50
ii)7
Steps
75-(30+20)-18
=75-(50)-18
=7
iii)20
Steps
From the available data from the question
iv)30
Steps
From the available data from the questionl
v)From the attcged image file
30 POINTS
Help on Part B pleaseeee
In verse of B.g(x)=[tex]\frac{x+5}{4}[/tex] is:
4x-5
Answer:
Solution given:
B.g(x)=[tex]\frac{x+5}{4}[/tex]
let
g(x)=y
y=[tex]\frac{x+5}{4}[/tex]
Interchanging role of x and y
we get:
x=[tex]\frac{y+5}{4}[/tex]
doing crisscrossed multiplication
4x=y+5
y=4x-5
So
g-¹(x)=4x-5
Given that,
→ g(x) = x+5/4
Then g(x)=y,
→ y = x+5/4
Now we can interchange role of x and y,
→ x = y+5/4
Then use the cross multiplication,
→ 4x = y+5
→ y = 4x-5
Hence, g-¹(x) = 4x-5 is the solution.
Is the collection og rall " student in set ? why ? class7
Answer:
in secret
Step-by-step explanation:
correct answer is in a secret
evaluate the expression when b= -6 and c=3
-4c+b
Answer:
-18
Step-by-step explanation:
b = -6
c = 3
-4c + b = ?
Plug in the value of each variable into the equation
-4c + b = ?
= -4(3) + (-6)
= -12 - 6
= -18
The formula for velocity of an object is the equals d over t where he is a velocity of the object t is the distance traveled and t is a time in class well that distance is terrible if you had only this formula to work with what would your first step be to determine how long it takes for the light to return fitness center one additional information do you need to calculate this and solve the variable you're looking for
Answer:
[tex](a)\ t =\frac{d}{v}[/tex]
[tex](b)\ d = vt[/tex]
Step-by-step explanation:
The question is mixed up with details of another question. See comment for original question
Given
[tex]v = \frac{d}{t}[/tex]
[tex]v \to velocity[/tex]
[tex]d \to distance[/tex]
[tex]t \to time[/tex]
Solving (a): Solve for time
We have:
[tex]v = \frac{d}{t}[/tex]
Cross multiply
[tex]t * v = d[/tex]
Make t the subject
[tex]t =\frac{d}{v}[/tex]
Solving (b): Solve for distance
We have:
[tex]v = \frac{d}{t}[/tex]
Cross multiply
[tex]d = v * t[/tex]
[tex]d = vt[/tex]
Help me pls I am bad at math
Answer:
D is the correct answer.
Step-by-step explanation:
You can get every y value by multiplying the x value by 3/2. This value never changes and there are no extra limitations.
Researchers study the mean weight (in pounds) of adults between the ages of 30-40. The researchers form a SRS of adults and build a 90% confidence interval: [160, 180]. Which of the following statements are true about this confidence interval?
a. 90% of intervals built according to the method capture the true mean weight of adults between the ages of 30-40.
b. The intervals margin of error is 20.
c. There is a 90% chance that the mean weight of adults between the ages of 30- 40 is between 160 and 180 pounds.
d. The sample mean used to build this interval was 170 pounds.
Answer:
d. The sample mean used to build this interval was 170 pounds.
Step-by-step explanation:
Confidence interval concepts:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
The margin of error is the difference between the two bounds, divided by 2.
In this question:
Bounds 160 and 180, so the sample mean used was (160+180)/2 = 170, and thus the correct answer is given by option d.
al of
10. A square field has four sprinklers that spray
in the areas represented by the circles below. If
the shaded portion represents area that is not
reached by the sprinklers, find the total area that
is not reached by the sprinklers.
Using the areas of the sqaure and of the circle, it is found that the total area that is not reached by the sprinklers is of 343.36 ft².
What is the area of a square?The area of a square of side length l is given by:
A = l²
In this problem, we have that l = 40 ft, hence:
A = (40 ft)² = 1600 ft².
What is the area of a circle?The area of a circle of radius r is given by:
[tex]A = \pi r^2[/tex]
In this problem, we have four circles of radius r = 10 ft, hence it's combined area, in square feet, is given by:
[tex]A_c = 4\pi (10)^2 = 400\pi = 1256.64 \text{ft}^2[/tex]
The area not reached by the sprinklers is the subtraction of the area of the square by the area of the circle, hence:
1600 - 1256.64 = 343.36 ft².
More can be learned about the area of a rectangle at https://brainly.com/question/10489198
The sum of the first ten terms of an arithmetic progression consisting of
positive integer terms is equal to the sum of the 20th, 21st and 22nd term.
If the first term is less than 20, find how many terms are required to give
a sum of 960.
Answer: [tex]n=13[/tex]
Step-by-step explanation:
Given
Sum of the first 10 terms is equal to sum of 20, 21, and 22 term
[tex]\Rightarrow \dfrac{10}{2}[2a+(10-1)d]=[a+19d]+[a+20d]+[a+21d]\\\\\Rightarrow 5[2a+9d]=3a+60d\\\Rightarrow 10a+45d=3a+60d\\\Rightarrow 7a=15d[/tex]
No of terms to give a sum of 960
[tex]\Rightarrow 960=\dfrac{n}{2}[2a+(n-1)d]\\\\\Rightarrow 1920=n[2a+(n-1)\cdot \dfrac{7}{15}a]\\\\\Rightarrow 28,800=n[30a+7a(n-1)]\\\\\Rightarrow a=\dfrac{28,800}{n[30+7n-7]}\\\\\Rightarrow a=\dfrac{28,800}{n[23+7n]}[/tex]
Value of first term is less than 20
[tex]\therefore \dfrac{28,800}{n[23+7n]}<20\\\\\Rightarrow 28,800<20n[23+7n]\\\Rightarrow 0<460n+140n^2-28,800\\\Rightarrow 140n^2+460n-28,800>0\\\\\Rightarrow n>12.79\\\\\text{For integer value }\\\Rightarrow n=13[/tex]
Answer:
15
Step-by-step explanation:
In the previous answer halfway through they used the equation: 960 = (n÷2)×(2a+(n-1)×(7a÷15))
Using this equation we can substitute an number to replace n, the higher the number is the smaller a would be.
When we substitute 15 into a, then it leaves us with the answer to be a = 15 which is a positive integer and also is smaller than 20, this then let’s us know that 15 is how many terms can be summed up to make 960.
To double check this answer you can find that d = 7 by changing the a into 15 in the formula 7a/15 (found in the previous answer.
Then in the expression: (n÷2)×(2a+(n-1)×d)
substitute:
n = 14 (must be an even number for the equation to work)
a = 15
d = 7
This will give you an answer of 847, but this is only 14 terms as we changed n into 14. To add the final term you need to complete the following equation: 847+(a+(n-1)×d)
substituting:
n = 15
a = 15
d = 7
This will give you the answer of 960, again proving that it takes 15 terms to sum together to make the number 960.
I hope this has helped you.
P.S. Everything in the previous solution was right apart from the start of the last section and the answer
A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let Y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation.
p(x, y) y
0 1 2
x 0 0.10 0.03 0.01
1 0 08 0.20 0.06
2 0.05 0.14 0.33
(a) Given that X = 1, determine the conditional pmf of Y�i.e., pY|X(0|1), pY|X(1|1), pY|X(2|1).
(b) Given that two hoses are in use at the self-service island, what is the conditional pmf of the number of hoses in use on the full-service island?
(c) Use the result of part (b) to calculate the conditional probability P(Y ? 1 | X = 2).
(d) Given that two hoses are in use at the full-service island, what is the conditional pmf of the number in use at the self-service island?
Answer:
(a): The conditional pmf of Y when X = 1
[tex]p_{Y|X}(0|1) = 0.2353[/tex]
[tex]p_{Y|X}(1|1) = 0.5882[/tex]
[tex]p_{Y|X}(2|1) = 0.1765[/tex]
(b): The conditional pmf of Y when X = 2
[tex]p_{Y|X}(0|2) = 0.0962[/tex]
[tex]p_{Y|X}(1|2) = 0.2692[/tex]
[tex]p_{Y|X}(2|2) = 0.6346[/tex]
(c): From (b) calculate P(Y<=1 | X =2)
[tex]P(Y\le1 | X =2) = 0.3654[/tex]
(d): The conditional pmf of X when Y = 2
[tex]p_{X|Y}(0|2) = 0.025[/tex]
[tex]p_{X|Y}(1|2) = 0.150[/tex]
[tex]p_{X|Y}(2|2) = 0.825[/tex]
Step-by-step explanation:
Given
The above table
Solving (a): The conditional pmf of Y when X = 1
This implies that we calculate
[tex]p_{Y|X}(0|1), p_{Y|X}(1|1), p_{Y|X}(2|1)[/tex]
So, we have:
[tex]p_{Y|X}(0|1) = \frac{p(y = 0\ n\ x = 1)}{p(x = 1)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{Y|X}(0|1) = \frac{0.08}{0.08+0.20+0.06}[/tex]
[tex]p_{Y|X}(0|1) = \frac{0.08}{0.34}[/tex]
[tex]p_{Y|X}(0|1) = 0.2353[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{Y|X}(1|1) = \frac{0.20}{0.34}[/tex]
[tex]p_{Y|X}(1|1) = 0.5882[/tex]
[tex]p_{Y|X}(2|1) = \frac{0.06}{0.34}[/tex]
[tex]p_{Y|X}(2|1) = 0.1765[/tex]
Solving (b): The conditional pmf of Y when X = 2
This implies that we calculate
[tex]p_{Y|X}(0|2), p_{Y|X}(1|2), p_{Y|X}(2|2)[/tex]
So, we have:
[tex]p_{Y|X}(0|2) = \frac{p(y = 0\ n\ x = 2)}{p(x = 2)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{Y|X}(0|2) = \frac{0.05}{0.05+0.14+0.33}[/tex]
[tex]p_{Y|X}(0|2) = \frac{0.05}{0.52}[/tex]
[tex]p_{Y|X}(0|2) = 0.0962[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{Y|X}(1|2) = \frac{0.14}{0.52}[/tex]
[tex]p_{Y|X}(1|2) = 0.2692[/tex]
[tex]p_{Y|X}(2|2) = \frac{0.33}{0.52}[/tex]
[tex]p_{Y|X}(2|2) = 0.6346[/tex]
Solving (c): From (b) calculate P(Y<=1 | X =2)
To do this, where Y = 0 or 1
So, we have:
[tex]P(Y\le1 | X =2) = P_{Y|X}(0|2) + P_{Y|X}(1|2)[/tex]
[tex]P(Y\le1 | X =2) = 0.0962 + 0.2692[/tex]
[tex]P(Y\le1 | X =2) = 0.3654[/tex]
Solving (d): The conditional pmf of X when Y = 2
This implies that we calculate
[tex]p_{X|Y}(0|2), p_{X|Y}(1|2), p_{X|Y}(2|2)[/tex]
So, we have:
[tex]p_{X|Y}(0|2) = \frac{p(x = 0\ n\ y = 2)}{p(y = 2)}[/tex]
Reading the data from the given table, the equation becomes
[tex]p_{X|Y}(0|2) = \frac{0.01}{0.01+0.06+0.33}[/tex]
[tex]p_{X|Y}(0|2) = \frac{0.01}{0.40}[/tex]
[tex]p_{X|Y}(0|2) = 0.025[/tex]
Using the format of the above formula for the rest, we have:
[tex]p_{X|Y}(1|2) = \frac{0.06}{0.40}[/tex]
[tex]p_{X|Y}(1|2) = 0.150[/tex]
[tex]p_{X|Y}(2|2) = \frac{0.33}{0.40}[/tex]
[tex]p_{X|Y}(2|2) = 0.825[/tex]
Compute ????×????, where ????=????−2????+5????, ????=2????+????+3????. (Write your solution using the standard basis vectors ????, ????, and ????. Use symbolic notation and fractions where needed.)
Given: ????=????−2????+5????
and ????=2????+????+3????
To find: We need to find the value of ????×????
Solution: Here given,
????=????−2????+5????
and ????=2????+????+3????
Therefore, solving these two we have, ????=0
So,????×????=0
Barry and Robin walk to Dunkin' Donuts each Saturday to meet for coffee and donuts. Barry walks the 2 miles from his house in 30 minutes and Robin walks the 3 miles from his house in 36 minutes. Find the unit rate in minutes per mile for Barry. Find the unit rate in minutes per mile for Robin. Who walks faster, Barry or Robin
Answer : barry
12<15
Barry's unit rate is 15 minutes per mile and Robin's unit rate is 12 minutes per mile
The unit rates of Barry and RobinWe have:
Barry
Distance = 2 miles
Time = 30 minutes
Unit rate = Time/Distance
Unit rate = 30 minutes/2 miles
Unit rate = 15 minutes per mile
Robin
Distance = 3 miles
Time = 36 minutes
Unit rate = Time/Distance
Unit rate = 36 minutes/3 miles
Unit rate = 12 minutes per mile
Hence, Barry's unit rate is 15 minutes per mile and Robin's unit rate is 12 minutes per mile
Who walk faster?The unit rates mean that:
Barry covers 1 mile in 15 minutesRobin covers 1 mile in 12 minutesHence, Robin walks faster
Read more about unit rates at:https://brainly.com/question/19493296
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Multiply m and 6. Then, add 8.
Answer:
6m + 8 is the answer.
Step-by-step explanation:
( m x 6 ) + 8
= 6m + 8
f(x,y)=x10-3xy2then fz=
A. 10 x9 - 3y2
B. 20 x9 - 3y2
C. 2y2
D. 10x10 + xy2
which option is correct please
Given:
The function is:
[tex]f(x,y)=x^{10}-3xy^2[/tex]
To find:
The value of [tex]f_x[/tex].
Solution:
We need to find the value of [tex]f_x[/tex]. So, we have to find the first order partial derivative of the given function with respect to x.
We have,
[tex]f(x,y)=x^{10}-3xy^2[/tex]
Differentiate partially with respect to x.
[tex]f(x,y)=\dfrac{\partial}{\partial x}x^{10}-3y^2\dfrac{\partial}{\partial x}x[/tex]
[tex]f_x=10x^{10-1}-3y^2(1)[/tex]
[tex]f_x=10x^{9}-3y^2[/tex]
Therefore, the correct option is A.
Use cross products to identify the equation needed to solve this proportion:
5
x
=
2
9
Answer:
x=22.5
Step-by-step explanation:
We are given the proportion:
5/x=2/9
Cross multiply. Multiply the numerator (top number) of the first fraction by the denominator (bottom number) of the second. Then multiply the denominator of the first by the numerator of the second.
5*9=2*x
45=2x
2 and x are being multiplied. The opposite of multiplication is division. Divide both sides by 2. This will cancel out the 2 being multiplied by x, and leave x by itself.
45/2=2x/2
45/2=x
22.5=x
If we substitute 22.5 in for x, the final proportion will be:
5/22.5=2/9
I need help with this, please.
Answer:
it can not cleared clear but it can not cleared
A car originally costs $20,000. Its price went up by 20% and then by another $8,000. How much did the price go up as a percentage of the original price?
Answer:
60%
Step-by-step explanation:
20,000
we can move the decimal place one to the left to find 10 percent
2,000
multiply 10 x 2 to find twenty percent or 4,000
we add this to the original total. 24,000
then add the 8,000
32,000
we know find one percent of the original total
200
and find the difference between the two totals
32000-20000 = 12,000
12000 divided by 200 which is 6
multiply six by ten to get
60 percent
Given the functions below, find f(x)+g(x)
CHECK MY ANSWERS PLEASE
Answer:
It's the last one
Step-by-step explanation:
(3x-1)-(x²+4)
3x-1-x²-4
-x²+3x-5
After x hours, the distance between two trains traveling in opposite directions from the same station is 704 km. If one train travels 96 km/h and the other travels 80 km/h, find the number of hours they traveled if they left at the same time.
Answer:
4 hr
Step-by-step explanation:
96 x 4= 384
80 x 4=320
384+320=704
if you subtract 1/2 from a number and multiply the result by 1/2 you get 1/8. What is the no.
Step-by-step explanation:
1/6
1/6- 1/2 = 1/4
1/4*1/2= 1/8
Hattie had $3,000 to invest and wants to earn 10.6% interest per year. She will put some of the money into an account that earns 12% per year and the rest into an account that earns 10% per year. How much money should she put into each account?
Answer:
900 at 12%
2100 at 10%
Step-by-step explanation:
Let x= amount invested at 12%
let y= amount invested at 10%
with that being said we can write the two equation
Equation 1: x+y=3000
Equation 2: 3000*.106=.12x+.1y
isolte x from equation 1
x= 3000-y
plug this into equation 2
318=.12(3000-y)+.1y
318=360-.12y+.1y
-42= -.02y
y= 2100
Plug this into equation 1
x+2100=3000
x=900
she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.
How to determine How much money should she put into each accountLet's denote the amount of money Hattie invests at 12% as \(x\) dollars, and the amount she invests at 10% as \(\$3000 - x\) dollars.
The formula for calculating interest is: \(\text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time}\).
For the 12% account:
Interest_12% = \(x \times 0.12 \times 1\) (1 year)
For the 10% account:
Interest_10% = \((3000 - x) \times 0.10 \times 1\) (1 year)
Hattie wants to earn 10.6% interest on the total investment, so we can set up the equation:
\(\text{Total Interest} = \text{Interest}_12% + \text{Interest}_10%\)
\(3000 \times 0.106 = x \times 0.12 + (3000 - x) \times 0.10\)
Now, solve for \(x\):
\(318 = 0.12x + 300 - 0.10x\)
\(318 = 0.02x + 300\)
\(18 = 0.02x\)
\(x = 900\)
Hattie should invest $900 at 12% and \(3000 - 900 = 2100\) at 10%.
Therefore, she should invest $900 into the account earning 12% interest and $2100 into the account earning 10% interest.
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mrs cabrini needs 2 quarts of tomato sauce to make a large batch of her spaghetti sauce. she has 1 1/4 quarts of her own. she borrows 1/2 quart from the neighbor across the hall and 3/8 quart from the neighbor next door . how many quarts does she have in all of her own .
Answer:
Mrs. Cabrini has a total of 2 1/8 quarts of tomato sauce.
Step-by-step explanation:
Since Mrs. Cabrini needs 2 quarts of tomato sauce to make a large batch of her spaghetti sauce. she has 1 1/4 quarts of her own, and she borrows 1/2 quart from the neighbor across the hall and 3/8 quart from the neighbor next door, to determine how many quarts does she have in all of her own must perform the following calculation:
1/4 = 0.25
1/2 = 0.5
3/8 = 0.375
0.25 + 0.5 + 0.375 = X
1.125 = X
1 + 1,125 = 2,125
Therefore, Mrs. Cabrini has a total of 2 1/8 quarts of tomato sauce.
