The true statement about the series [tex]\sum\limits^{\infty}_{n=1} \frac{9}{n(n +3)}[/tex] is that (a) the series diverges
How to determine if the series diverges or converges?The series is given as:
[tex]\sum\limits^{\infty}_{n=1} \frac{9}{n(n +3)}[/tex]
Take the limit of the function to infinity
[tex]\lim_{n \to \infty} \frac{9}{n(n +3)}[/tex]
This gives
[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = \frac{9}{\infty * (\infty +3)}[/tex]
Evaluate the sum
[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = \frac{9}{\infty * \infty}[/tex]
Evaluate the product
[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = \frac{9}{\infty}[/tex]
Evaluate the quotient
[tex]\lim_{n \to \infty} \frac{9}{n(n +3)} = 0[/tex]
Since the limit is 0, then it means that the series diverges
Hence, the true statement about the series [tex]\sum\limits^{\infty}_{n=1} \frac{9}{n(n +3)}[/tex] is that (a) the series diverges
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Answer:
B. The series converges to [tex]\displaystyle{\frac{11}{2}}[/tex].
Step-by-step explanation:
Before evaluating the infinite series, the expression can be decomposed as the sum of two fractions (partial fraction decomposition) as follows.
Let [tex]\textit{A}[/tex] and [tex]\textit{B}[/tex] be constants such that
[tex]{\displaystyle{\frac{9}{n\left(n+3\right)}}}} \ \ = \ \ \displaystyle{\frac{A}{n} \ \ \ + \ \ \frac{B}{n+3}}[/tex]
Multiply both sides of the equation by the denominator of the left fraction,
[tex]n\left(n+3\right)[/tex], yielding
[tex]9 \ \ = \ \ A\left(n+3\right) \ \ + \ \ B \-\hspace{0.045cm} n[/tex]
Now, let [tex]n \ = \ 0[/tex], thus
[tex]\-\hspace{0.2cm} 9 \ \ = \ \ A\left(0 + 3\right) \ + \ B\left(0\right) \\ \\ 3 \-\hspace{0.035cm} A \ = \ \ 9 \\ \\ \-\hspace{0.11cm} A \ \ = \ \ 3[/tex].
Likewise, let [tex]n \ = \ -3[/tex], then
[tex]\-\hspace{0.5cm} 9 \ \ = \ \ A\left(-3 + 3\right) \ + \ B\left(-3\right) \\ \\ -3 \-\hspace{0.035cm} B \ = \ \ 9 \\ \\ \-\hspace{0.44cm} B \ \ = \ \ -3[/tex]
Hence,
[tex]\displaystyle{\sum_{n=1}^{\infty} {\frac{9}{n\left(n+3\right)}}} \ = \ \displaystyle\sum_{n=1}^{\infty} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right)[/tex].
First and foremost, write the nth partial sum (first nth terms) of the series,
[tex]\displaystyle\sum_{n=1}^{n} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right) \ \ = \ \-\hspace{0.33cm} \displaytstyle{\frac{3}{1} \ - \frac{3}{4} + \ \frac{3}{2} \ - \frac{3}{5} \ + \frac{3}{3} \ - \frac{3}{6} \ + \frac{3}{4} \ - \frac{3}{7}} \\ \\ \\ \-\hspace{3.58cm} + \ \displaystyle{\frac{3}{5} \ - \ \frac{3}{8} \ + \ \frac{3}{6} \ - \ \frac{3}{9} \ + \ \frac{3}{7} \ - \ \frac{3}{10}} \\ \\ \\ \-\hspace{3.58cm} + \ \ \dots[/tex]
[tex]+ \ \ \displaystyle{\frac{3}{n-3} \ - \ \frac{3}{n} \ + \ \frac{3}{n-2} \ - \ \frac{3}{n+1}} \\ \\ \\ \ + \ \frac{3}{n-1} \ - \ \frac{3}{n+2} \ + \ \frac{3}{n} - \ \frac{3}{n+3}}[/tex].
Notice that the expression forms a telescoping sum where subsequent terms cancel each other, leaving only
[tex]\displaystyle\sum_{n=1}^{n} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right) \ \ = \ \-\hspace{0.33cm} \displaytstyle{\frac{3}{1} \ + \ \frac{3}{2} \ + \frac{3}{3} \ - \ \frac{3}{n+1}} - \ \frac{3}{n+2} \ - \ \frac{3}{n+3}}}[/tex].
To determine if this infinite series converges or diverges, evaluate the limit of the nth partial sum as [tex]n \ \rightarrow \ \infty[/tex],
[tex]\displaystyle\sum_{n=1}^{\infty} \left(\frac{3}{n} \ - \ \frac{3}{n+3}\right) \ \ = \ \-\hspace{0.33cm} \lim_{n \to \infty} \left(\displaytstyle{\frac{11}{2} \ - \ \frac{3}{n+1} \ - \ \frac{3}{n+2} \ + \ - \ \frac{3}{n+3}\right) \\ \\ \\ \-\hspace{3.25cm} = \ \ \ \displaystyle{\frac{11}{2} \ - \ 0 \ - \ 0 \ - \ 0} \\ \\ \\ \-\hspace{3.25cm} = \ \ \ \displaystyle{\frac{11}{2}[/tex]
Which of the fallowing expressions represents the distance between -4 and 1
The answer is |-4 - 1|.
If you solve this absolute value, the answer would be 5 and if you look at the number line, the distance between the two dots is 5 units.
|-4 - 1| --> |-5| --> 5
in an absolute value, there are no negative numbers so the -5 becomes 5.
What is the direction and magnitude of the following correlation coefficients
a. -0.81
b. 0.40
c. 0.15
d. -0.08
e. 0.29
-0.81 has negative direction and o.81 is the magnitude, 0.40 has positive direction and 0.40 is the magnitude, 0.15 positive direction and 0.15 is the magnitude, -0.08 has negative direction and 0.08 is the magnitude and 0.29 has positive direction and 0.29 is the magnitude
What is Vector?A quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another.
-0.81
Minus zero point eight one has negative direction and o.81 is the magnitude
0.40
zero point four zero has positive direction and 0.40 is the magnitude
0.15
Zero point one five has positive direction and 0.15 is the magnitude
-0.08
Minus zero point zero eight has negative direction and 0.08 is the magnitude
0.29
Zero point two nine has positive direction and 0.29 is the magnitude
Hence -0.81 has negative negative direction and o.81 is the magnitude, 0.40 has positive direction and 0.40 is the magnitude, 0.15 positive direction and 0.15 is the magnitude, -0.08 has negative direction and 0.08 is the magnitude and 0.29 has positive direction and 0.29 is the magnitude
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I ordered a shoe a few days ago and the seller provided me with the tracking number for the hoodie but through Grailed but USPS has been stuck on "We are preparing your order for shipment" and "Delivery information will be available once the carrier has the updates." What does this mean? Also when I put my tracking number in USPS's Package Tracker, the number doesn't exist in its system. Does anyone know whats going on? Thanks!
Prove usin's Mathematical induction 2^n ≤(n+1)!, for n≥0
Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
Fertiliser is applied at the rate of a grams per square metre. It
takes b kilograms to cover a field of area c square metres. Find a
formula for b in terms of a and c.
Step-by-step explanation:
1 kilogram (kg) = 1000 grams (g)
as "kilo" means 1000.
b = a × c / 1000
it is simple : we have "c" square meters. as we need to apply "a" grams per square meter, we need to multiply both numbers to know how many grams we need for that many square meters. hence a × c.
and to get kg, we need to divide this number of grams by 1000.
that's it.
please help jajajajaja
Consider the curve C in the Cartesian plane described in polar coordinates by given:
See picture:
a. Determine a Cartesian equation that describes curve C. Hint: first multiply (c) by r.
b Describe this curve and use this description to obtain the area inside C.
c Use (c) to set up an integral that computes the area inside C that is also within the rst quadrant.
d Evaluate this integral to determine the area.
a. Recall that in polar coordinates, we can parameterize [tex]x=r\cos(\theta)[/tex] and [tex]y=r\sin(\theta)[/tex]. So, doing as the hint suggests, we have
[tex]r = 6\cos(\theta) + 8 \sin(\theta)[/tex]
[tex]\implies r^2 = 6r\cos(\theta) + 8r\sin(\theta)[/tex]
[tex]\implies \boxed{x^2 + y^2 = 6x + 8y}[/tex]
b. By completing the square, we get
[tex]x^2 + y^2 = 6x + 8y[/tex]
[tex]x^2 - 6x + y^2 - 8y = 0[/tex]
[tex]x^2 - 6x + 9 + y^2 - 8y + 16 = 25[/tex]
[tex](x-3)^2 + (y-4)^2 = 5^2[/tex]
which is the equation of the circle centered at (3, 4) with radius 5. Thus the area bounded by [tex]C[/tex] is [tex]\pi\cdot5^2 = \boxed{25\pi}[/tex].
c. This is made easier if you can consult a plot (attached). In the first quadrant, we have [tex]0\le\theta\le\frac\pi2[/tex], while the radial coordinate [tex]r[/tex] runs uninterrupted from the origin [tex]r=0[/tex] to the circle [tex]r=6\cos(\theta)+8\sin(\theta)[/tex]. So the area is
[tex]\displaystyle \int_0^{\pi/2} \int_0^{6\cos(\theta) + 8\sin(\theta)} r\,dr\,d\theta = \boxed{\frac12 \int_0^{\pi/2} \left(6\cos(\theta) + 8\sin(\theta)\right)^2 \, d\theta}[/tex]
d. Evaluate the integral.
[tex]\displaystyle \frac12 \int_0^{\pi/2} \left(36\cos^2(\theta) + 96\sin(\theta)\cos(\theta) + 64 \sin^2(\theta)\right) \, d\theta[/tex]
Simplify the integrand with the help of the identities
[tex]\cos^2(x) + \sin^2(x) = 1[/tex]
[tex]\sin(x)\cos(x) = \dfrac12 \sin(2x)[/tex]
[tex]\sin^2(x) = \dfrac{1 - \cos(2x)}2[/tex]
[tex]\displaystyle \frac12 \int_0^{\pi/2} \left(50 + 48\sin(2\theta) - 14 \cos(2\theta)\right) \, d\theta[/tex]
The rest is easy. You should end up with
[tex]\displaystyle \frac12 \int_0^{\pi/2} \left(6\cos(\theta) + 8\sin(\theta)\right)^2 \, d\theta = \boxed{24 + \frac{25\pi}2}[/tex]
a) The Cartesian equation that described curve C is x² + y² = 6 · x + 8 · y.
b) The area inside C is A = π · 5² = 25π square units.
c) The integral that computed the area inside curve C within the first quadrant is A = (1 / 2)∫ (6 · cos θ + 8 · sin θ)² dθ, for θ ∈ [0, 0.5π].
d) The integral evaluated at the given limits is equal to an area of 20.139π square units.
How to analyze a polar equation and find its area by geometric and calculus means
In this question we find a polar equation in explicit form. a) To find the equivalent form in rectangular coordinates, we must apply the following substitutions x = r · cos θ, y = r · sin θ:
r = 6 · cos θ + 8 · sin θ
r² = 6 · r · cos θ + 8 · r · sin θ
x² + y² = 6 · x + 8 · y (1)
The Cartesian equation that described curve C is x² + y² = 6 · x + 8 · y.
b) Perhaps the equation represents a conic section, possibly a circunference. To prove this assumption, we must apply algebraic handling until standard form is obtained:
x² - 6 · x + y² - 8 · y = 0
x² - 6 · x + 9 + y² - 8 · y + 16 = 25
(x - 3)² + (y - 4)² = 5² (1b)
Which indicates a circumference centered at point (h, k) = (3, 4) and with a radius of 5 units. By the area formula for a circle we find that the area inside C is A = π · 5² = 25π square units.
c) The polar form of the area integral is presented herein:
A = ∫ ∫ r dr dθ, for r ∈ [0, r(θ)] and θ ∈ [0, 0.5π]
A = (1 / 2)∫ [r(θ)]² dθ, for θ ∈ [0, 0.5π]
A = (1 / 2)∫ (6 · cos θ + 8 · sin θ)² dθ, for θ ∈ [0, 0.5π]
The integral that computed the area inside curve C within the first quadrant is A = (1 / 2)∫ (6 · cos θ + 8 · sin θ)² dθ, for θ ∈ [0, 0.5π].
d) By algebraic handling, trigonometric formulas and integral properties:
A = 25 ∫ dθ + 24 ∫ sin 2θ dθ - 14 ∫ cos 2θ dθ, for θ ∈ [0, 0.5π]
A = 25 · θ - 12 · cos 2θ - 7 · sin 2θ, for θ ∈ [0, 0.5π]
A = 20.139π
The integral evaluated at the given limits is equal to an area of 20.139π square units.
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Jasmine got a new puppy for her birthday. He's full of energy, so she takes him for a walk along a 1.2-mile loop in a nearby park. If they walked a total of 3.6 miles, how many loops did they do?
Answer: 3 loops
Step-by-step explanation: The loop is 1.2 miles, and the total walk is 3.6 miles. You want to find out how many laps are in the 3.6 miles. This can be found using division. 3.6/1.2= the number of 1.2 mile laps inside the 3.6 mile walk, which is 3 laps. hope this helped!
7
O x-3
O x-1
O x + 1
O x + 3
3
2-
What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?
3
N
3
I NEED HELP !!!!!
Answer:
x-1 gave ggs is it correct
Add the following polynomials, then place the answer in the proper location on the grid. Write your answer in descending powers of x.
x 4 -3x + 1, 4x 2 - 2x + 8, and x 3 - 9
The addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.
Polynomialx⁴ - 3x + 14x² - 2x + 8x³ - 9Adding the polynomial
(x⁴ - 3x + 1) + (4x² - 2x + 8) + (x³ - 9)
Open parenthesis= x⁴ - 3x + 1 + 4x² - 2x + 8 + x³ - 9
Collect like terms in descending powers= x⁴ + x³ + 4x² - 3x - 2x + 1 + 8 - 9
= x⁴ + x³ + 4x² - 5x
Therefore, the addition of the polynomials x⁴ - 3x + 1, 4x² - 2x + 8, x³ - 9 in descending powers of x is x⁴ + x³ + 4x² - 5x.
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Can segments with lengths of 6, 7, and 9 form a triangle? Why or why not
Answer:
Yes
Step-by-step explanation:
The sum of the lengths of any two sides of a triangle must be greater than the length of the third side or largest side. So, 7+6 = 13 which is greater than 9
Answer:
Yes, triangle with sides 6, 7 ,9 can be formed.
Step-by-step explanation:
The sum of any two sides of the triangle should be greater than the third side. If so, triangle can be formed.
6 + 7 = 13 > 9
7+ 9 = 16 > 6
6 +9 = 15 > 7
at the beginning of the week, a particular stock sold for 29 3/8 per share. at the end of the same week it sold for 31 2/8. what was the amount of increase per share ?
Answer:
2 1/8
Step-by-step explanation:
I counted from 29 to 31 and then saw that for 29 it was 3/8 and for 31 it was 2/8 so i knew that the answer would be 2 1/8
A projector enlarges an image in the ratio 20:1. What will be the size of an enlargement of a picture that is 8cm by 6cm?
Answer:
160 cm × 120 cm
Step-by-step explanation:
this means 1 cm turns into 20 cm.
so, 8 cm × 6 cm becomes
8×20 = 160 cm × 6×20 = 120 cm
Complete the square -3x^2+12x-7
Answer:
[tex]-3(x-2)^2+5[/tex]
Step-by-step explanation:
First we can factor a -3 from the [tex]x^2[/tex] term and the [tex]x[/tex] term to get [tex]-3(x^2-4x)-7[/tex].
Then we want the stuff in the parentheses to have the form of [tex](x+b)^2[/tex], or equivalently, [tex](x^2+2b+b^2)[/tex] . So we can let [tex]2b = -4[/tex]. By solving it, we get [tex]b = -4/2 = -2[/tex]. Then our [tex]b^2[/tex] term should be [tex]b^2 = (-2)^2 = 4[/tex].
In order to make our [tex]b^2[/tex] term appear in the parentheses, we need to add and subtract our [tex]b^2[/tex] term, so we get [tex]-3(x^2 - 4x + 4 - 4) -7[/tex].
What we to keep inside our parentheses is [tex](x^2 - 4x + 4)[/tex] , so we can factor the [tex]-4[/tex] out of parentheses to get [tex]-3(x^2-4x+4-4)-7 = -3(x^2-4x+4)+(-3)(-4) - 7 = -3(x^2 - 4x + 4) + 12 - 7 = -3(x^2 - 4x + 4) + 5[/tex]
Finally, plugging [tex]b = -2[/tex] that we computed earlier into the equation [tex](x^2+2b+b^2) = (x+b)^2[/tex], we get [tex](x^2 - 4x + 4) = (x-2)^2[/tex].
So we have [tex]-3(x^2-4x+4)+5 = -3(x-2)^2+5[/tex].
In summary, the procedure is
[tex]-3x^2+12x-7 \\= &-3(x^2-4x) -7 \\= &-3(x^2-4x+4-4)-7 \\= -3(x^2-4x+4) + (-3)(-4)-7\\=-3(x^2-4x+4)+12-7\\= -3(x^2-4x+4)+5 \\= -3(x-2)^2+5[/tex]
Calculating orthogonal trajectories?
The equation for the trajectories orthogonal to the family of functions of the form 5 · x² - 2 · y² = C is equal to (1 / 5) · ㏑ x + (1 / 2) · ㏑ y = C.
How to find the equation for the orthogonal trajectories of a given equation
In this problem we have a family of functions in implicit form, that is, a function of the form f(x, y, c) = 0. The equation of a orthogonal trajectory is always perpendicular to a particular form of a equation. First, we determine the first derivative of the given expression:
5 · x² - 2 · y² = C
10 · x - 4 · y · y' = 0
4 · y · y' = 10 · x
y' = (10 · x) / (4 · y)
y' = (5 · x) / (2 · y)
If f(x, y) = (5 · x) / (2 · y), then the differential equation for the orthogonal trajectories related to the family of functions is:
y' = - 1 / f(x, y)
y' = - (2 · y) / (5 · x)
dy / (2 · y) = - dx / (5 · x)
By indefinite integration we get the following solution to the ordinary differential equation:
(1 / 2) · ㏑ y = - (1 / 5) · ㏑ x + C
(1 / 5) · ㏑ x + (1 / 2) · ㏑ y = C
The equation for the trajectories orthogonal to the family of functions of the form 5 · x² - 2 · y² = C is equal to (1 / 5) · ㏑ x + (1 / 2) · ㏑ y = C.
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Two copies of the same Rational Function are shown below.
On the graph below draw the Horizontal Asymptote and write the equation for the horizontal asymptote underneath.
The equation for the horizontal asymptote will be y = -2.
How to illustrate the information?Since the degree of the numerator and denominator of f(x) is the same both being 1, therefore horizontal asymptote exists and is given by:
y = Leading coefficient of numerator of f(x) / Leading coefficient of denominator of f(x)
= y = -2/1
= y = -2
The vertical asymptote will be f(x) = -2x / (x + 3). To find the vertical asymptote we will equate the denominator of f(x) = 0
= x + 3 = 0
= x = -3
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Ivanna knit a scarf for each of her 9 friends. Altogether, the scarves had a total length of 41.4 ft. If each scarf was the same length, how long was each scarf? Write your answer in inches. Use the table of conversion facts as necessary, and do not round your answer. Conversion facts for length 12 inches (in) = 1 foot (ft) 3 feet (ft) = 1 yard (yd) 36 inches (in) = 1 yard (yd) 5280 feet (ft) = 1 mile (mi) 1760 yards (yd) = 1 mile (mi)
Answer: 55.2 in
Step-by-step explanation:
1ft = 12 in
41.4/9 = 4.6 ft
4.6 x 12 = 55.2 in
Help me with this math question :)
[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]
To prove two lines parallel, we need to check if the two angles involving the lines acts as some angle pair with defininte property.
In the given figure,
Angle 3 is congruent to Angle 19( by Alternate Exterior angle pair )
Hence, the two lines are parallel.
[tex] \qquad \large \sf {Conclusion} : [/tex]
Option C is correctThe next model of a sports car will cost 4.4% more than the current model. The current model costs $49,000. How much will the price increase in dollars? What will be the price of the next model?
Answer: $51156
Step-by-step explanation:
a = b x p%
how much will the price increase
a = 49,000 x 4.4%
= 49,000 x 0.044
= $2156
price of next model
49,000 + 2156 = $51156
A ball is launched into the sky at 54. 4 ft./s from a 268.8 m tall building. The equation for the ball’s height, h, at time t second’s is h= -3.2t^2 + 54.4t+ 268.8. When will the ball strike the ground?
Answer:
t = 21
Step-by-step explanation:
The ball strikes the groujd when h = 0.
[tex]-3.2t^2 + 54.4t+268.8=0 \\ \\ 32t^2 - 544t-2688=0 \\ \\ t^2 - 17t-84=0 \\ \\ (t-21)(t+4)=0 \\ \\ t=-4, 21[/tex]
Since time must be positive, t = 21.
Joey owns a small bakery and today Phoebe has ordered 100 cookies. If Joey boxes the cookies by the dozen, which of the following equations describes how many boxes of cookies Phoebe will have? Let b represent the number of boxes. (HINT: All of the cookie boxes are not necessarily full.)
Answer:
Joey needs 9 boxes.
Step-by-step explanation:
You will use the fact that a dozen is 12 cookies. You're trying to find how many dozen are in 100.
Something like:
12b = 100
or if you're studying inequalities:
12b >= 100
Divide by 12 to solve. See image. Interpret the results. See image.
Evaluate the expression if a=2,b=-3,C=-1, and D=4
-2(b^2-5c)
Answer:
Your answer is - 28
Step-by-step explanation:
Given,
a = 2
b = - 3
c = - 1
d = 4
Now,
- 2 ( b² - 5 c )
= - 2 ( -3² - 5 ( - 1 ) )
= - 2 ( 9 + 5 )
= - 2 × 14
= - 28 ans….
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How is a marketing -oriented firm different from a production-oriented firm or a sales-oriented firm?
Marketing-oriented firms focus more on what the market needs above every other aspects.
What is a Marketing-oriented Firm?Marketing-oriented firms can be described as firms that major in identifying the needs and wants of customers and then creating specific products that are designed to meet the wants of such customers. One of the important elements of marketing-oriented firms is to ensure there is a demand for whatever products or services they offer.
Some examples of marketing-oriented firms are:
AppleCoca-ColaAmazonWhat is a Product-oriented Firm or a Sales-oriented Firm?A product-oriented firm focus more resources on and focus on researching and developing quality products rather than focusing more on the market to discover the wants of customers.
Sales-oriented firm tend to focus more on developing its sales force that will promote their products and services.
How Marketing-Oriented Firms are Different from the Product-oriented or Sales-oriented Firms?Marketing-oriented firms stand out and are different from the other two types of firms because they focus more on what the market needs above every other aspects.
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y = -2(x + 5)(x + 1)
Set the factor (x + 5) = 0 and solve
Answer: [tex]x=-5[/tex]
Step-by-step explanation:
[tex]x+5=0 \implies x=-5[/tex]
1-cos(6x)=___?
A. 3sin(2x)
B. 2sin^2(3x)
C. 3cos(2x)
D. 2cos^2(3x)
The solution to 1 - cos(6x) is 2sin²(x).
Hence, option B) 2sin²(x) is the correct answer.
What is solution to 1 - cos(6x)?Given that; 1 - cos(6x) = ?
First, we rewrite using trig identity
1 - cos(2 × 3x)
Using the double angle identity, { cos2(x) = 1 - 2sin²(x) }
1 - ( 1 - 2sin²(x) )
Eliminate the parentheses
1 - 1 + 2sin²(x)
2sin²(x)
The solution to 1 - cos(6x) is 2sin²(x).
Hence, option B) 2sin²(x) is the correct answer.
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Multiply each of the following(2x - 3y) and (x + 5y)
Answer:
[tex]2 {x}^{2} + 7xy - 15 {y}^{2} [/tex]
Step-by-step explanation:
We can use the rainbow expansion method to find the expression.
[tex](2x - 3y)(x + 5y) \\ = 2 {x}^{2} + 10xy - 3xy - 15 {y}^{2} \\ = 2 {x}^{2} + 7xy - 15 {y}^{2} [/tex]
The relationship between voltage, E, current, I, and resistance, Z, is given by the equation E = IZ. If a circuit has a current I = 3 + 2i and a resistance Z = 2 – i, what is the voltage of the circuit?
4 – i
4 + i
8 + i
8 + 7i
The voltage of the circuit is 8 + i . Option C
How to determine the voltage
From the information given, we have that;
E = IZ
Where;
E is voltageI is currentZ is resistanceWe have that;
I = 3 + 2i
Z = 2 - i
Substitute into the formula
E = IZ
E = ( 3 + 2i) ( 2 - i)
Making the product of complex numbers we have:
E = ( 3 × 2 - i ) + ( 4i - 2i²)
E = ( 6 - 3i ) + ( 4i - 2 ( -1) )
E = ( 6 + 2) + ( 4 - 3 ) i
E = 8 + i
Thus, the voltage of the circuit is 8 + i . Option C
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Answer:
It's C
Step-by-step explanation:
. Find the perimeter of a regular pentagon with each side measuring 4.5 inches.
Answer: 22.5 inches
Step-by-step explanation:
the general formula for finding perimeter is [tex]p=s+s+s...[/tex]a pentagon contains 5 sides[tex]p=s+s+s+s+s[/tex]
note that this is a regular pentagon so it must contain 5 congruent sideseach side will be 4.5 inchesthe formula can be changed to [tex]5(s)[/tex] and solved:[tex]5(4.5 in)=p[/tex]
∴ 22.5 inches = perimeter of the pentagon
What is 500$ invested at 8% for 6 and a half years?
Answer:
$824.56
Step-by-step explanation:
Use the compound interest formula which is A = P(1+r/n)^nt
1st using the given information we are going to find out values:
P is our initial amount of $500
r is the annual rate of interest (expressed as a decimal) 8% becomes 0.08.
n is how many times interest is compounded per year, in this case since its not stated we are going to assume its annually, so n is 1
t is how long the money is deposited (in years) so t is 6.5
A is our final amount
2nd plug in our values into the equation
Plugging all these values we get A = 500 (1 +0.08/1)^(0.08)(6.5)
A = $824.56
Identify the lateral area and the surface area of a cube with edge length 15 in.
The Lateral area of the cube = 900 in.²
The Surface area of the cube = 1,350 in.².
What is the Lateral Area of a Cube?A cube's lateral area is the area covered by the lateral surfaces of the cube shape. The formula for the lateral area of a cube is given as: LA = 4a², where:
a = edge length of cube.
What is the Surface Area of a Cube?The surface area of a cube is the total area of all its 6 surfaces. The formula for finding the surface area of a cube is: 6a², where:
a = edge length of cube.
Edge length of cube (a) = 15 in.
Lateral area = 4a² = 4(15²)
Lateral area = 4(225)
Lateral area of the cube = 900 in.²
Surface area = 6a² = 6(15²)
Surface area = 6(225)
Surface area of the cube = 1,350 in.².
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